can someone explain the diffrence between first class, second class, and third class levers?

Answers

Answer 1

The answer you're looking for is that, 1rt class levers is that, the fulcrum is in the middle and force is being applied to one side of the lever, and the resistance on the other side for example think of a seesaw. A second class lever has load between the effort and the fulcrum. Like a wheelbarrow. The wheel's axels is the fulcrum and the handles are the effort. The load is between these two. Finally, a third class lever is when the input force is between the output force, such as a baseball bat. The handle of the bat is like a fulcrum. You input the force onto the bat, causing the output force to be pushed against the ball as it hits. Hoped this help you :@)

Answer 2

Final answer:

Levers are classified based on the positions of the fulcrum, input force, and output force. First-class levers have the fulcrum in the middle, second-class levers have the load in the middle, and third-class levers have the effort in the middle. The Mechanical Advantage of a lever indicates how much the lever amplifies the input force.

Explanation:

The three classes of levers are differentiated by the positions of the fulcrum, input force, and output force. A first-class lever has the fulcrum placed between the input force and the output force. Examples would include a seesaw and a crowbar. A second-class lever has the output force between the input force and the fulcrum, with examples being a wheelbarrow and a nutcracker. Lastly, a third-class lever has the input force between the output force and the fulcrum, as seen in a pair of tweezers or a human arm when lifting a weight.

The Mechanical Advantage (MA) is a calculation that shows how much a lever amplifies the input force. It is given by the ratio of the distance from the fulcrum to the input force (effort arm) and the distance from the fulcrum to the output force (resistance arm). Levers are simple machines that utilize torque and the physical distances from their pivot point to achieve an output force that is greater or faster or travels a further distance than the input force.

Related Questions

how to factor 6x^2+5x+1

Answers

Here you go, explains how to do it and your answer.

Is the number of fish caught during a fishing tournamentnumber of fish caught during a fishing tournament discrete or continuous?

Answers

Final answer:

The number of fish caught in a fishing tournament is a discrete variable, as it can only take specific or separate values which are whole numbers, not fractions or decimals.

Explanation:

The number of fish caught during a fishing tournament would be considered a discrete variable in mathematics. This is because discrete variables are variables that can only take specific or separate values.

In this case, you can't catch half a fish or 2.3 fish in a tournament, you can only catch whole fish. This makes the number of fish caught a discrete variable because the count can only be in whole numbers. This is different from a continuous variable, such as the amount of time spent fishing or the weight of the fish caught, which could take on any value within a given range.

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solve for y. 8x+y=15

Answers

8x + y = 15

y = 15 - 8x

8x + y + -1y = 15 + -1y

8x = 15 + -1y

x = 1.875 + -0.125y

x = 1.875 + -0.125y

B is the midpoint of AC, D is the midpoint of CE. BD=10, and AE =2x. Find the length of CE if CD =3x

Answers

There is a theorem that states that the line joining two midpoints in a triangle is always parallel to the third side and its length is half the length of the third side.

Since B is midpoint of AC and D is midpoint of CE, therefore, BD is parallel to AE and BD = 0.5 AE
AE = 2 BD = 2 x 10 = 2x
Therefore, x= 10

D is the midpoint of CE and CD = 3x, therefore CE = 6x where x = 10
Based on this, CE = 6 x 10 = 60 units of length

the lines shown below are perpendicular. if the green line has a slope of 3/4, what is the slope of the red line
a)4/3
b)-3/4
c)-4/3
d) 3/4

Answers

perpendicular slope is opposite and reciprocal

the green line has a slope of 3/4
so the slope of the red line is -4/3

answer
c)-4/3

The slope of the red line is -4/3. Therefore, option C is the correct answer.

Given that, the green line has a slope of 3/4.

We need to find the slope of the red line.

What is the formula to find the slope of the perpendicular line?

The formula for the slope of perpendicular lines is m1.m2 = -1. The product of the slopes of perpendicular lines is equal to -1.

Since, m1=3/4.

Now, 3/4.m2 = -1

⇒m2 =-4/3

The slope of the red line is -4/3. Therefore, option C is the correct answer.

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What is the value of n in the equation –(2n + 4) + 6 = –9 + 4(2n + 1)?

Answers

Final answer:

The value of n in the equation –(2n + 4) + 6 = –9 + 4(2n + 1) is -2. This is determined by simplifying and solving the given expression for n.

Explanation:

To find the value of n in the equation –(2n + 4) + 6 = –9 + 4(2n + 1), we need to simplify and solve for n. First, we distribute the negative sign and the 4 into the parentheses and then combine like terms:

-2n - 4 + 6 = -9 + 8n + 4

Now, we combine the constants:

-2n + 2 = -5 + 8n

To isolate n, we move all the terms involving n to one side and the constants to the other:

-2n - 8n = -5 - 2

-10n = -7

Finally, we divide by -10 to solve for n:

n = ⅔

Thus, the value of n is -2.

In the triangle below, what is the side opposite the 30 degree angle

Answers

[tex]tan(30^o)= \frac{opposite }{adjacent} \ \ \ \ \to \\ \\ opposite = adjacent*tan(30^o)=3* \frac{ \sqrt{3} }{3} = \sqrt{3} [/tex]

Write the equation of a circle with center (-2,3) and a radius of 4. Show all work to receive credit.

Answers

The equation of the circle is given by:
(x-a)^2+(y-b)^2=r^2
where:
(a,b) is the center of the circle
given that the center of our circle is (-2,3) with the radius of 4, the equation will be:
(x+2)^2+(y-3)^2=4^2
expanding the above we get:
x^2+4x+4+y^2-6y+9=16
this can be simplified to be:
x^2+4x+y^2-6y=16-13
x^2+y^2+4x-6y=3

Simplify 15 to the 18th power over 15 to the 3rd power.

Answers

(15^18) / (15^3)

If the exponents you're dividing have the same base, you subtract them.
18 - 3 = 15

15^15

[tex] \cfrac{15^{18}}{15^3} = 15^{18-3}=15^{15}[/tex]

A regular pyramid has a height of 12 centimeters and a square base. if the volume of the pyramid is 256 cubic centimeters, how many centimeters are in the length of one side of its base

Answers

Let the length of one side of the base square be a cm.

The Volume of a pyramid is [tex] \frac{1}{3}*area_b_a_s_e *height[/tex]

the area of the base is a^2,

we apply the formula

[tex]256= \frac{1}{3}*a^{2}*12 [/tex]

[tex]256= 4a^{2} [/tex]

[tex]256= (2a)^{2} [/tex]

[tex]2a= \sqrt{256}=16[/tex]

a=8 (cm)

Answer: 8 cm

In how many ways can 50 cards be chosen from a standard deck of 52 cards?

Answers

The answer must take into account that the order is irrelevant, that is that it is the same J, Q, K that Q, K, J, and K, J, Q and all the variations of those the three cards.

The number of ways you can draw 50 cards from 52 is 52*51*50*49*48*47*...4*3 (it ends in 3).
,
But the number of ways that those 50 cards form the same set repeats is 50! = 50*49*49*47*....3*2*1

So, the answer is (52*51*50*49*48*....*3) / (50*49*48*...*3*2*1) = (52*51) / 2 = 1,326.

Note that you obtain that same result when you use the formula for combinations of 50 cards taken from a set of 52 cards:

C(52,50) = 52! / [(50)! (52-50)!] = (52*51*50!) / [50! * 2!] = (52*51) / (2) = 1,326.

Answer: 1,326

any ideas friends? cant seem to figure this out

Answers

I = 7.6*10^(-4) is the given intensity of the sound
Io = 10^(-12), which is a constant usually shown in a table or in your book

Plug in those values to get
B = 10*log(I/Io)
B = 10*log((7.6*10^(-4))/(10^(-12)))
B = 88.808135922808
B = 88.81

Answer: Approximately 88.81 decibels

Find three positive numbers x, y, and z that satisfy the given conditions. the sum is 180 and the product is maximum.

Answers

I don't know of any algebraic way to answer this, but 59,60,61 add up to 180, and 60^3 would be the greatest product of 3 numbers, so 59,60,61 yield the greatest product.

Bruce had an EKG to measure his heartbeat rate. After conversion, the function produced could be modeled by a cosine function, and the wave produced a maximum of 4, minimum of −2, and period of pi over 2. Which of the following functions could represent Bruce's EKG read-out?
f(x) = 4 cos pi over 2x − 2
f(x) = 3 cos 4x + 1
f(x) = 3 cos pi over 2x + 1
f(x) = 4 cos 4x − 2

Answers

y= a.cos (bx) + midline

a = Amplitude = |4+2}/2 = |3|

Period = 2π/b = (2π) / (π/2) = 4

midline = (4-2)/2 = 1

Then the equation is:

y=3.cos(4x) + 1

Answer:

Option B.

Step-by-step explanation:

Bruce had an EKG to measure his heartbeat rate. After conversion, the function produced was modeled by a cosine function.

Now we will form this function.

Function will be in the form of f(x) = a cos(Bx) + d

Amplitude [tex]a=\frac{Maximum-minimum}{2}[/tex]

[tex]a=\frac{4+2}{2}=3[/tex]

Period = π/2

And [tex]Period=\frac{2\pi }{B}[/tex]

⇒[tex]\frac{\pi }{2}=\frac{2\pi }{B}[/tex]

⇒ B = 4

Since minimum is (-2) and maximum is (4), means cosine graph was shifted upwards.

Mid line of the graph is [tex]x=\frac{4+2}{2}=3[/tex] which shows graph is shifted by one unit above the x-axis.

Now the function we get is f(x) = 3 cos4x + 1

Therefore option B is the answer.

Bob is driving along a straight and level road toward a mountain. At some point on his trip, he measures the angle of elevation to the top of the mountain and finds it to be 21°44'. Find the height of the mountain to the nearest foot if Bob is 13,428.7 feet from the center of the mountain at the base.
A. 5453 ft
B. 5353 ft
C. 53,534 ft
D. 535,342 ft

Answers

tan 21 44 = h / 13428.7
h = 13428.7 * tan 21 44

Height = 5353 feet

Answer:

Option B is the correct answer.

Step-by-step explanation:

The arrangement is given in the below figure.

We have height of the mountain = x

We also have

[tex]tan(21^044')=\frac{x}{13428.7}\\x=5352.98ft[/tex]

Height of the mountain to the nearest foot = 5353 ft

Option B is the correct answer.

Help with geometry...

Answers

so... doing the distances from ABC to GHI

[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ 1}}\quad ,&{{ 2}})\quad % (c,d) G&({{ -4}}\quad ,&{{ 2}})\\ B&({{ 2}}\quad ,&{{ 3}})\quad % (c,d) H&({{ -3}}\quad ,&{{ 3}})\\ C&({{ 3}}\quad ,&{{ 1}})\quad % (c,d) G&({{ -2}}\quad ,&{{ 1}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\[/tex]

[tex]\bf -------------------------------\\\\ AG=\sqrt{(-4-1)^2+(2-2)^2} \\\\\\ BH=\sqrt{(-3-2)^2+(3-3)^2} \\\\\\ CG=\sqrt{(-2-3)^2+(1-1)^2}[/tex]

and doing the distances from ABC to DEF

[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ 1}}\quad ,&{{ 2}})\quad % (c,d) D&({{ 1}}\quad ,&{{ -1}})\\ B&({{ 2}}\quad ,&{{ 3}})\quad % (c,d) E&({{ 2}}\quad ,&{{ 0}})\\ C&({{ 3}}\quad ,&{{ 1}})\quad % (c,d) F&({{ 3}}\quad ,&{{ -2}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}[/tex]

[tex]\bf -------------------------------\\\\ AD=\sqrt{(1-1)^2+(-1-2)^2} \\\\\\ BE=\sqrt{(2-2)^2+(0-3)^2} \\\\\\ CF=\sqrt{(3-3)^2+(-2-1)^2}[/tex]

now... the ABC to JKL... surely you'd know how to do... the same way, just use the distance formula

If the telescope is 1 m deep and 8 m wide, how far is the focus from the vertex?
1
2
4
16
Find the vertex, focus, directrix, and focal width of the parabola.

negative 1 divided by 12 times x squared = y

Answers

First, let me introduce the general equation of the parabola:

(x-h)^2 = +/- 4a(y-k) or (y-k)^2=+/- 4a(x-h), where

(h,k) are the coordinates of the vertex
a is the distance of the vertex to the focus
4a = length of lactus rectum or the focal width

If the equation contains (x-h)^2, then the parabola passes the x-axis twice. Similarly, (y-k)^2 passes the y-axis twice. If the sign is (-), it opens to the left(if y-axis) or downward (if x-axis). If the sign is (+), it opens to the right(if y-axis) or upward (if x-axis).

The equation of the parabola is -1/12 x^2 = y. Rearranging to the general form:

x^2 = -12y
Therefore,

-4a = -12
4a = 12
a = 3, and the parabola is facing downwards.

The vertex is (0,0) at the origin.
The focus is (0,-3). Since it is negative, the focus is situated downwards, hence -3.
The directrix is the mirror image of the focus. Hence, it is a line passing +3 on the y-axis. y=3
Focal width is 4a which is equal to 12 units.

Dr. Black is standing 15 feet from the streetlamp. The lamp is making his shadow 8 feet long. He estimates that the angle of elevation from the tip of his shadow to the top of the streetlamp is 50°. To the nearest foot, the streetlamp is about _______

Answers

use tangent because tangent is opposite over adjacent ( to remember sin cos and tan use the phrase "Oscar Has A Hairy Old Asss")
the angle is from his shadow so use (15+8) as the adjacent side
so tan(50)=x/23
so tan(50)(23)=x
so x=about 27 feet

Write the sum using summation notation, assuming the suggested pattern continues. -9 - 3 + 3 + 9 + ... + 81

Answers

-9 -3 +3 +9 +15 +....+81=15+21+...+81=(23*66)/2=759

Honestly I believe this is correct:

∑ 15 at the top, n =0 (-9+6n)

(07.03 LC)

The steps below show the incomplete solution to find the value of p for the equation 4p − 2p + 4 = −1 + 21:

Step 1: 4p − 2p + 4 = −1 + 21
Step 2: 4p − 2p + 4 = 20
Step 3: 2p + 4 = 20

Which of these is most likely the next step?
2p = 5
2p = 8
2p = 16
2p = 24

Answers

Step 1: 4p − 2p + 4 = −1 + 21
First they combined like terms on one side.

Step 2: 4p − 2p + 4 = 20
Then they combined like terms on the other side.

Step 3: 2p + 4 = 20
Now you have to subtract 4 from both sides.

Step 4: 2p = 16

So the answer is C. 2p = 16

It's 2p = 16. You subtract 4 from both sides.
2p+4=20
-4=-4
2p = 16

The volume of a cube is found using the formula l3, where l is the side length. What is the volume of a cube, in cubic feet that is 3/5 of a foot long

Answers

The volume of a cube is defined by the formula l^3, as stated in the problem. The length of the cube given to us is 3/5 of a foot, meaning that the value of l is 3/5. So if we plug this into the equation, we get that (3/5)^3 = (3)^3/(5)^3 = 27/125. The units will also match up to be in cubic feet, so the answer is that the volume will be 27/125 cubic feet.

A hypothesis is only tentative: to make sure it's valid, you have to ___________.

Answers

a hypothesis is only tentative: to make sure it's valid, you have to test it.

Mario and Luigi want to purchase some extra controllers for their friends.each controller costs 29.99. Use an algebraic expression to describe how much they spend in total,before sales tax,based on purchasing the console(299.00)the number of games(59.99 each) and the number of extra controllers

Answers

How many controllers do they need

i cant answer this question because it doesnt say how many friends they have

In physics, if a moving object has a starting position at s 0, an initial velocity of v 0, and a constant acceleration a, then the position S at any time t > 0 is given by:

S = at 2 + v 0 t + s 0.

Solve for the acceleration, a, in terms of the other variables. For this assessment item, you can use ^ to show exponents and type your answer in the answer box, or you may choose to write your answer on paper and upload it.

Answers

Actually the position function with respect to time under constant acceleration is:

a=g

v=⌠g dt

v=gt+vi

s=⌠v

s=gt^2/2+vit+si

So if vi and si are zero then you just have:

s=gt^2/2

Notice that it is not gt^2 but (g/2) t^2

So the first term in any quadratic is half of the acceleration times time squared because of how the integration works out...

Anyway....

sf=(a/2)t^2+vit+si

(sf-si)-vit=a(t^2)/2

2(sf-si)-2vit=at^2

a=(2(sf-si)-2vit)/t^2 and if si and vi equal zero

a=(2s)/t^2

Step-by-step explanation:

The equation of a moving object in physics is given by :

[tex]s=at^2+v_ot+s_o[/tex]...........(1)

Where

s₀ is the starting position of an object

a is the acceleration of the object

v₀ is the initial velocity of the object

t is the time taken

We need to find the value of acceleration by rearranging equation (1). Subtract [tex](v_ot+s_o)[/tex] on both sides of equation (1) as :

[tex]s-v_ot-s_o=at^2[/tex]

Divide both sides of above equation by t² as :

[tex]a=\dfrac{s-v_ot-s_o}{t^2}[/tex]

So, the value of acceleration is [tex]\dfrac{s-v_ot-s_o}{t^2}[/tex]. Hence, this is the required solution.

Solve log 1/100 = log(10^x+2)

A.) x= 0

B.) x= -2

C.) x= -4

D.) x= 4

Answers

i believe the answer is C: x= -4

Jan is twice as old as her sister betty, but half of joe's age. betty just got married. how old is joe most likely to be?

Answers

For this algebraic problem, you have to assign variables so you can formulate equations to help you solve the problem. Let x be the age of Jan, y be the age of Betty and z be the age of Joe. You are to find the value of z. The equations would be:

x = 2y and x = 0.5z

Equating this two yields 2y = 0.5z. There are two variables but only one equation. Therefore, you have to specify one of the variables to be able to solve this problem. It was mentioned that Betty just got married. Let's assume that Betty's age was around 30 years old. Then, it follows that y=30. Substituting this to the final equation,

2(30) = 0.5z
z = 120 years old

This is impossible. Betty must have been married at an early age. Let's assume that Betty is 18 years old, then

2(18) = 0.5z
z = 72 years old

If Betty was 18 years old, then Joe is 72 years old. This is only an illustration to the problem. You must have introduced Betty's age to know the exact answer for Joe's age.

He sum of three consecutive odd integers is −375. find the three integers.

Answers

-375/3 = -125

-125-2 =-127

-125+2 = -123

-123 + -125 + -127 = -375

x = first integer
x+2 = second integer
x+4 = third integer

x + x+2 + x+4 = -375
3x = -375 - 6
3x = -381
x = -381/3 = -127 ← first integer

second integer = -127 + 2 = -125

third integer = -127 + 4 = -123

Answer: -127, -125 and -123

Write the function in vertex form, and identify its vertex. g(x) = 5x2 - 50x + 128

Answers

hello :
g(x) = 5x² - 50x + 128
= 5(x²-10x +128/5)
= 5 (x²-10x+5²-5² +128/5)
= 5 ((x-5)² +128/5 -125/5)
y = 5 ((x-5)² - 3/5)
y= 5(x-5)² +3.....vertex form
the vertex is : (5,3)

how would you prove two circles are similar

Answers

Is this a real question lol? but anyways i think that it's by shape.
GOOD LUCK!

Answer:

it is by similarity transformations

Step-by-step explanation:

so like it would be a rigid transformation then a dilation

EX- A translation then a dilation of R/r

Simplify: 6/3-y -2/y

Answers

Since 6/3=2, we could make it 2-y-2/y. If we wanted everything over y, we could make it (2y-y^2-2)/y by multiplying both 2 and y with y. This is not factorable due to that nothing multiplies to -2 and adds up to 2.

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