Can you please help me with #9?

During a collision, two cars experience equal and opposite forces according to Newton's Third Law of Motion, but their accelerations differ due to Newton's Second Law as a less massive car will experience a greater change in velocity.

When one car is twice the mass of the other during a collision, the two cars do indeed experience equal and opposite forces according to Newton's Third Law of Motion. This law states that for every action, there is an equal and opposite reaction. Therefore, no matter the disparity in mass, the forces exerted on each other during a collision are equal in magnitude but opposite in direction. Although the forces are equal, the effect of these forces will differ due to Newton's Second Law of Motion, which links the net force acting on an object to its mass and acceleration (F = ma). A less massive car will experience a greater acceleration (or deceleration) than a more massive car under the same force. This concept is crucial in understanding the dynamics of collisions.

Answer:

d is the answer

Explanation:

A closed container is filled with oxygen. the pressure in the container is 335 k-pa . The pressure in mili meters of mercury 2,513 millimetres of mercury.

The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. In comparison to the surrounding pressure, gauge pressure is the pressure. Pressure is expressed using a variety of units.

Conversion factor is

1 mm of Hg = 133.322 pascals,

So,  335 kpa the pressure in millimeters of mercury is  2,513 millimetres of mercury.

The pressure in mili meters of mercury 2,513 millimetres of mercury.

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Volcanoes come in different shapes, depending on the type of eruption. Shield volcanoes have shallow, sloping sides and are formed by very hot, runny lava that spreads over a wide area. The majority of the volcanoes that happen occur along the cracks in the lithosphere that mark the edges of the tectonic plates.

Answer:

Explanation:

Inertia is the property of any object which always resist any change in the object.

Inertia is measured by the mass of the object.

More be the mass of the object, more be the inertia.

Galileo's law of inertia state that, if a body is at rest it always remains at rest and if a body is in motion it remains in motion, until and unless an external force is not applied on the body.

It is also called Newton's first law of motion.

Looking at the position A, we can actually see that velocity vectors connecting position A and its adjacent positions appear to have similar magnitude and in similar direction. Hence the acceleration is zero and similarly, the net force is also zero.

Answer:

Net force is zero

The net force acting on the object at position A is zero, option 5 is correct.

In physics, an object's motion is determined by the net force acting upon it. When multiple forces act on an object, they can either cancel each other out or add together to create a resultant force. At position A, if the forces acting on the object are balanced in such a way that the magnitudes and directions of all forces cancel each other out, the net force is zero.

This means that there is no overall acceleration or change in motion, and the object remains in a state of equilibrium. In other words, the forces pushing or pulling in various directions at position A are perfectly balanced, resulting in a net force of zero, option 5 is correct.

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The complete question is:

What is the direction of the net force acting on the object at position A?

1. upward

2. downward

3. to the left

4. to the right

5. The net force is zero.

a. The mechanical work output of the engine during one cycle is 2600 Joules.

b. The thermal efficiency of the engine is equal to 28.89%.

Given the following data:

a. To determine the mechanical work output of the engine during one cycle:

Mathematically, the mechanical work output of an engine during one cycle is given by the formula:

[tex]Work = H_{in}- H_{out}\\\\Work = 9000-6400[/tex]

Work output = 2600 Joules

b. To determine the thermal efficiency of the engine:

[tex]Th_{E} =\frac{Work}{H_{in}} \times 100\\\\Th_{E} =\frac{2600}{9000} \times 100\\\\Th_{E} =0.2889 \times 100[/tex]

Thermal efficiency = 28.89%

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Newton's law of gravitation says that the magnitude f of the force exerted by a body of mass m on a body of mass m is f = Gmm/r² where G is the gravitational constant and r is the distance between the bodies. Then df/dr = Gmm(-2/r³).

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.

f = Gmm/r²

df/dr = Gmm(-2/r³).

Newton's law of gravitation says that the magnitude f of the force exerted by a body of mass m on a body of mass m is f = Gmm/r² where G is the gravitational constant and r is the distance between the bodies. Then df/dr = Gmm(-2/r³).

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the correct answer is a discovery

The initial 'launch' speed of a basketball rebounder with a vertical leap of 120 cm is approximately 4.9 m/s. They are in the air for about 1 second, given the symmetry of the jump's ascent and descent.

The best rebounders in basketball who have a vertical leap of 120 cm possess a certain initial launch speed and time in the air. These can be determined using the equations of motion in physics. The equation for the height h in terms of initial speed v, time t, and acceleration due to gravity g (about 9.8 m/s²) is: h = vt - 0.5gt².

(a) Setting h to 1.2 meters (or 120 cm) and t to the time of the peak of the jump (which is when the velocity v becomes 0), we get h = 0.5gt, or v = gt. Plugging in g, we get an initial launch speed off the ground of roughly 4.9 m/s.

(b) To find out how long they are in the air, we recognise that the time to reach the peak and the time to fall back down should be the same, given symmetry. Therefore the total time in air would be 2t, which is also equal to 2v/g. Plugging in the values, we get the athlete is in the air for roughly 1 second.

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One disadvantage of using a survey to gather data for psychological purposes is the fact that it can be subject to response bias.

Social Desirability Bias: Respondents may provide answers that they believe are socially acceptable or desirable rather than their true feelings or behaviors. They may want to present themselves in a positive light, which can lead to inaccurate responses.

Acquiescence Bias: Some individuals have a tendency to agree with statements or questions, regardless of their true beliefs.

Extreme Response Bias: On the other hand, some respondents may consistently choose the most extreme response options (e.g., always selecting "strongly agree" or "strongly disagree") without considering the nuances of the questions.

Non-Response Bias: Not all individuals approached to participate in a survey actually respond. Those who choose not to respond may have different characteristics or perspectives from those who do respond, leading to potential bias in the sample.

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Answer: A

Explanation:

To solve this we must be knowing each and every concept related to work and its calculation. Therefore, 439,805 Joules is the work done on the car in this time interval.

Work in physics is the energy delivered to or out of an item by applying force across a displacement. It is frequently expressed in its most basic form as the combination of displacement and force.

When a force is applied, it is said to produce positive work if it has a proportion in the orientation of the movement of a site of application. Work done is positive when the direction of force acting on the object and displacement of the object both are in the same direction.  

Mathematically,    

acceleration=(V-Vo)/t

                   = (12.4-0)/3.77

                  = 3.29 m/s^2

d = 0.5×3.29×(3.77)² = 23.37 m

Work = F×d

         = (m×g) ×d

         =(1920*9.8)23.37

          = 439,805 Joules.

Therefore, 439,805 Joules is the work done on the car in this time interval.

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Answer:

Explanation:

It’s a SESMOGRAPH

Answer:

Waves interact with  

⇒ objects and other  

⇒ waves.

Explanation:

Transverse Waves: Displacement of the medium is perpendicular to the direction of propagation of the wave.

To understand this it is good to think of a rope being held still by person B and being moved up and down by person A. The direction of propagation is from person A to B, so you will see the waves move along this way. But the displacement will be up and down.

Can travel in solids, but not in liquids and gas.

Electromagnetic radiation

Transverse Waves: Displacement of the medium is perpendicular to the direction of propagation of the wave.

To understand this it is good to think of a rope being held still by person B and being moved up and down by person A. The direction of propagation is from person A to B, so you will see the waves move along this way. But the displacement will be up and down.

Can travel in solids, but not in liquids and gas.

eg. Electromagnetic radiation

Longitudinal Waves: Displacement of the medium is parallel to the direction of propagation of the wave.

A good example for this is a slinky being pushed along the table, the propagation will be along the table and so will the displacement of all the 'rings'.

Can travel through all states of matter.

Sound waves

The measure that gives the intensity of precipitation from the weather radar is the  rate of dispersion of the microwave energy pulses returning back to the radar .

There are three main ways of measuring intensity of precipitation and they are

For the purpose of your question the weather radar been discussed is the ground based weather radar.

A weather radar is an equipment used for the predetermination of precipitation in a region. it performs this function by sending out microwave energy pulses via tube transmitter into the atmosphere( air ) to detect the possibility of precipitation.

Hence The important measure of the weather radar that helps determine the intensity of the precipitation is; rate of dispersion of the microwave energy pulses sent out to the atmosphere.

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I'm actually going ahead in the book (DC Circuits) so this isn't really homework but I figured the tag was appropriate....the name of the chapter is Ohm's Law and Watt's Law.

The next question is what I'm not sure about:

Question: What is the power in the circuit (a) above if the voltage is doubled? (Hint: Consider the effect on current).

What I did initially was: P = IV = (100mA)(2V) = 2 W

But then I looked at the answer and it said 4 W, then I looked at the Hint again. Then I remembered in the book early on it said "If the voltage increases across a resistor, current will increase."

So question is: When solving problems I have to increase (or decrease) current (I) every time voltage (V) is increased (decreased) in a problem, right? How about the other way around, when increasing current (I), you need to increase voltage (V). I'm pretty sure that's how they got 4 W, but want to make sure before I head to the next section of the book.

P = IV = (200mA)(2V) = 4 W

According to Ohm's law, if the voltage across a constant resistance is doubled, the current will also double. This relationship holds true as long as the resistance remains unchanged. The key concept here is the direct proportionality of voltage and current, as described by I = V/R.

According to Ohm's law, the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor. The mathematical equation that describes this relationship is I = V/R.

When the voltage across a fixed resistance is doubled, Ohm's law dictates the relationship between voltage and current. If the voltage is increased two-fold while the resistance remains constant, the current will also double. This is because, in the equation I = V/R, if V is multiplied by two, and R remains the same, then I must also be multiplied by two.

Therefore, if a student is faced with the decision to either double the voltage or the resistance with the voltage remaining constant, the best choice to maintain the current flow would be to option (b) double the current, which aligns with Ohm's law. Doubling the resistance would actually halve the current based on the formula.

If the voltage across a circuit is increased four times, the current would also increase four times, assuming the resistance stays the same. Additionally, if the resistance of a circuit is halved, for a fixed amount of voltage such as the 110 V provided by an electric company, this means the current would double, leading to twice as much power dissipation.