Choose the equation and the inequality needed to answer this question.

Trevor tutors French for $15 and hour and scoops ice cream for $10 an hour. He is going to work 15 hours this week. At least how many hours does he need to tutor to make more than $180? Let x equal the number of hours he tutors and y be the number of hours he scoops ice cream.

Options (you can pick more than one):

x + y = 15
x + y > 15
x + y < 15
15x + 10y = 180
15x + 10y > 180
15x + 10y < 180


So far all I have it the fourth option (15x + 10y = 180).

Answers

Answer 1

Answer:

Actually, what you said you have so far is not correct.  The 2 correct answers are the 1st one (x + y = 15) and the 5th one (15x + 10y > 180)

Step-by-step explanation:

If tutoring French is x hours and scooping ice cream is y hours and he is going to work 15 hours for sure doing both, then we can add them together to get that x hours + y hours = 15 hours, or put simply:  x + y = 15.

Now we are going to throw in the added fun of the money he makes doing each.  The thing to realize here is that we can only add like terms.  So looking at the equation above, we have x hours of tutoring and y hours of scooping, so if we want to add them, we will add those number of hours together to get the total number of hours he worked, which we know to be 15.  The same goes for money.  If we add money earned from tutoring to money earned from scooping, we need that to be greater than the money he wants to earn which is 180 at least.  Because he wants to earn MORE than $180. we use the ">" sign.  Since he earns $15 an hour tutoring, that expression is $15x; since he earns $10 an hour scooping, that expression is $10y.  Now add them together (and you CAN because they are both expressions relating dollars to dollars) and set the sum > $180:

$15x + $10y > $180.  That's why your answer is not correct.  Use mine (with the understanding that you care about why yours is wrong and mine is correct) and you'll be fine.


Related Questions

Use substitution to solve each system of equations. y = 4x + 22 4x – 6y = –32

(–5, 2)

(2, –5)

(–8, 1)

(4, 7)

Answers

Answer:

(-5,2)

Step-by-step explanation:

The given system is

1st equation: y = 4x + 22

2nd equation:  4x – 6y = –32

We plug in the first equation into the second equation to obtain:

4x – 6(4x + 22) = –32

We expand the parenthesis to obtain:

4x – 24x -132= –32

Group similar terms;

4x – 24x = –32+132

Combine similar terms

-20x =100

Divide both sides by -20

x =-5

Put x=-5 into the 1st equation

y = 4(-5) + 22

y=-20+22

y=2

The solution is:

(-5,2)

Which expression is equivalent to sec2xcot2x?

A.
sin2x

B.
csc2x

C.
`(1)/(cos^2x)`

D.
`(1)/(tan^2x)`

Answers

Answer:

Option B is correct answer.

Step-by-step explanation:

We need to solve the expression sec2xcot2x.

We know sec x = 1/ cos x and cot x = 1/ tan x and tan x = sin x/cos x and 1/tanx = cosx /sinx

Since in question we 2x instead of x so, replacing x with 2x and Putting values:

[tex]sec2x\,\, cot2x\\=\frac{1}{cos 2x} * \frac{1}{tan 2x} \\=\frac{1}{cos 2x} * \frac{cos2x}{sin2x}\\=\frac{1}{sin 2x}\\=csc2x[/tex]

So, Option B is correct answer.

Answer:

b

Step-by-step explanation:

please help me asap

afraid to fail

Answers

Answer: 311.25

Step-by-step explanation: Take 52.50 and multiply by 4.5. Then add the $75 service fee.

Answer:

$311.25

Step-by-step explanation:

This is your correct answer because 52.50 x 4.5 plus 75 equals 311.25.

What is the average rate of change of the function over the interval x = 0 to x = 5?
f(x) = 2x^2 - 1
Enter your answer, as a fraction, in the box.​

Answers

[tex]\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)= 2x^2-1\qquad \begin{cases} x_1=0\\ x_2=5 \end{cases}\implies \cfrac{f(5)-f(0)}{5-0} \\\\\\ \cfrac{[2(5)^2-1]~~-~~[2(0)^2-1]}{5}\implies \cfrac{50-(-1)}{5}\implies \cfrac{50+1}{5}\implies \cfrac{51}{5}\implies 10\frac{1}{5}[/tex]

Consider the following factor and indicate whether it increases or decreases the equilibrium price of gasoline and the equilibrium quantity of gasoline sold. In this problem, assume that gasoline is a normal good.

When the number of sellers decreases, the


Choose one:
A. supply curve shifts to the right.
B. demand curve shifts to the right.
C. demand curve shifts to the left.
D. supply curve shifts to the left.


As a result,


Choose one:
A. price decreases and quantity decreases.
B. price decreases and quantity increases.
C. price increases and quantity decreases.
D. price increases and quantity increases.

Answers

The answer for your question is A,D.

Answer:

D. supply curve shifts to the left

C. price increases and quantity decreases

Step-by-step explanation:

Since the number of sellers decreases, the quantity available at the same price decreases. This shifts the supply curve to the left.

When the supply curve shifts to the left, the equilibrium point shifts to the left (and up the demand curve). Hence the price increases and the quantity decreases.

A number is increased by 54. The sumos then divided by 9. The result is 21. Write an equation to represent the discription, use n for the number

Answers

Answer:

  (n+54)/9 = 21

Step-by-step explanation:

A number: n

Is increased by 54: n+54

The sum is divided by 9: (n +54)/9

and the result is 21:

  (n +54)/9 = 21

Which of the following equations is represented by the given graph?

Answers

Answer:

A

Step-by-step explanation:

What is the value of the expression |a + b| + |c| when a = –3, b = –7, and c = –15?

Answers

Answer:

Step-by-step explanation:

Formula

abs(a + b) + abs(c)

Givens

a = - 3

b = - 7

c = - 15

Solution

abs(-3 - 7) + abs(-15)

abs(-10) + abs(-15)

10 + 15

25

Write the equation 9y = 12x + 0.2 in standard form. Identify A, B, and C.
Question 19 options:

45x – 60y = 1 where A = 45, B = –60, and C = –1

45x – 1y = 1 where A = 45, B = –60, and C = 1

60x + 45y = –1 where A = 60, B = 45, and C = 1

60x – 45y = –1 where A = 60, B = –45, and C = –1

Answers

Answer: D) 60x-45y = - 1 where A = 60 , B = -45 , and c = - 1

Step-by-step explanation: Clear it : 45y=60x+1

Step 2: Isolate the constant on one side: ( -1 = -45y +60x)

step 3: A= 60 , B= - 45 , C= - 1

Answer:

60x-45y = - 1 where A = 60 , B = -45 , and c = - 1

Step-by-step explanation:

1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is the surface area of the parametric surface given by r2(u,v)=5r1(u,v) with −4≤u≤4,−4≤v≤4?

Answers

Surface area of [tex]\(r_2(u,v)\)[/tex]  is [tex]\(25\)[/tex] times the area of parameter domain[tex]\(D\),[/tex] yielding [tex]\(1600\)[/tex] if [tex]\(D\)[/tex] is [tex]\(8 \times 8\).[/tex]

Let's break it down step by step:

step:-1. **Define the parametric surfaces**: We have two parametric surfaces: [tex]\( r_1(u,v) = f(u,v)i + g(u,v)j + h(u,v)k \)[/tex] and [tex]\( r_2(u,v) = 5r_1(u,v) \).[/tex]

step:-2. **Calculate the partial derivatives**: Compute the partial derivatives of [tex]\( r_1 \)[/tex]  with respect to [tex]\( u \)[/tex]  and [tex]\( v \)[/tex] denoted by [tex]\( r_{1u} \)[/tex] and [tex]\( r_{1v} \).[/tex]

step:-3. **Multiply by 5**: Since[tex]\( r_2(u,v) = 5r_1(u,v) \),[/tex]  the partial derivatives of [tex]\( r_2 \)[/tex] with respect to [tex]\( u \)[/tex] and [tex]\( v \)[/tex] will be 5 times the corresponding partial derivatives of [tex]\( r_1 \)[/tex], denoted by [tex]\( r_{2u} \)[/tex] and [tex]\( r_{2v} \).[/tex]

step:-4. **Calculate the cross product**: Compute the cross product of [tex]\( r_{2u} \)[/tex] and[tex]\( r_{2v} \),[/tex] denoted by [tex]\( \| r_{2u} \times r_{2v} \| \)[/tex]. This will be 25 times the magnitude of the cross product of [tex]\( r_{1u} \)[/tex] and [tex]\( r_{1v} \),[/tex] as the cross product is linear with respect to the vectors involved.

step:-5. **Surface area integral**: Use the formula for the surface area integral: [tex]\( A = \iint_D \| r_u \times r_v \| \, dA \),[/tex] where [tex]\( \| r_{2u} \times r_{2v} \| \)[/tex] replaces [tex]\( \| r_{u} \times r_{v} \| \).[/tex]

step:-6. **Calculate the integral**: Integrate[tex]\( \| r_{2u} \times r_{2v} \| \)[/tex] over the parameter domain [tex]\( D \)[/tex]. Since [tex]\( \| r_{2u} \times r_{2v} \| \)[/tex] is constant and equal to 25 times the magnitude of the cross product of [tex]\( r_{1u} \)[/tex] and [tex]\( r_{1v} \)[/tex], the integral becomes [tex]\( 25 \times \text{Area of } D \).[/tex]

step:-7. **Determine the area of the parameter domain**: If the parameter domain [tex]\( D \)[/tex] is a rectangle with sides of length 8 in both directions, its area is [tex]\( 8 \times 8 = 64 \).[/tex]

step:-8. **Final calculation**: Multiply the area of [tex]\( D \)[/tex] by 25 to get the surface area of[tex]\( r_2(u,v) \)[/tex], which is[tex]\( 25 \times 64 = 1600 \).[/tex]

So, the surface area of the parametric surface given by [tex]\( r_2(u,v) = 5r_1(u,v) \)[/tex] is 1600.

The surface area of the parametric surface [tex]\( \mathf{r}_2(u, v) \)[/tex] is 25.

To find the surface area of the parametric surface given by [tex]\( \mathf{r}_2(u, v) = 5 \mathf{r}_1(u, v) \)[/tex] where [tex]\( -4 \leq u \leq 4 \)[/tex] and [tex]\( -4 \leq v \leq 4 \)[/tex], given that the surface area of [tex]\( \mathf{r}_1(u, v) \)[/tex] over the same parameter range is 1, follow these steps:

Surface Area of [tex]\( \mathf{r}_1(u, v) \)[/tex]

  The surface area of [tex]\( \mathf{r}_1(u, v) \)[/tex] is given to be 1.

Relationship Between [tex]\( \mathf{r}_1 \) and \( \mathf{r}_2 \)[/tex]

 [tex]\[ \mathf{r}_2(u, v) = 5 \mathf{r}_1(u, v) \][/tex]

Effect of Scaling on Surface Area

  When a surface is scaled by a factor k, the surface area is scaled by a factor of k². This is because surface area is a two-dimensional measure, and scaling each dimension by k multiplies the area by k².

Calculation for [tex]\( \mathf{r}_2(u, v) \)[/tex]

  In this problem, the scaling factor k is 5. Therefore, the surface area of [tex]\( \mathf{r}_2(u, v) \)[/tex] will be [tex]\( 5^2 \)[/tex] times the surface area of [tex]\( \mathf{r}_1(u, v) \)[/tex].

[tex]\[\text{Surface area of } \mathf{r}_2(u, v) = 5^2 \times \text{Surface area of } \mathf{r}_1(u, v)\][/tex]

Substitute the Given Surface Area

  The surface area of [tex]\( \mathf{r}_1(u, v) \)[/tex] is 1.

[tex]\[\text{Surface area of } \mathf{r}_2(u, v) = 5^2 \times 1 = 25\][/tex]

Find a parametric representation for the surface. The part of the sphere x2 + y2 + z2 = 16 that lies between the planes z = −2 and z = 2. (Enter your answer as a comma-separated list of equations. Let x, y, and z be in terms of θ and/or ϕ.)

Answers

To  answer this question, we should make use of spherical coordinates.

Solution is:

S = (  4×cosθ ×sinΦ , 4 ×sinθ× sinΦ, 4 × cosΦ)

0 ≤ θ ≤ 2×π     ;  π/2  ≤ Ф ≤ (3/2)×π

In Analitic Geometry we have different way of determine, and identify  the position of objects, we have rectangular coordinates, cylindrical coordinates and spherical coordinates. The use of each of these system depends on de geometry of the problem.

In this particular case and according to the problem statement we should use spherical coordinates

x = ρ×cosθ ×sinΦ           y = ρ ×sinθ× sinΦ         z = ρ× cosΦ

In our particular case

ρ = 4   then   x = 4×cosθ ×sinΦ     y = 4 ×sinθ× sinΦ   z = 4 × cosΦ

0 ≤ θ ≤ 2×π     ;   π/2  ≤ Ф ≤ ( 3/2)×π

So the solution in terms of θ and/or  Φ

S = (  4×cosθ ×sinΦ , 4 ×sinθ× sinΦ, 4 × cosΦ)

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Final answer:

To find a parametric representation for the surface of the part of the sphere x² + y² + z² = 16 between the planes z = -2 and z = 2, use spherical coordinates with r = 4, θ ranging from 0 to π, and ϕ ranging from 0 to 2π.

Explanation:

To find a parametric representation for the surface of the part of the sphere x² + y² + z² = 16 that lies between the planes z = -2 and z = 2, we can use spherical coordinates.

Letting x = r sinθ cosϕ, y = r sinθ sinϕ, and z = r cosθ, where r is the radius of the sphere, θ is the polar angle, and ϕ is the azimuthal angle, we can rewrite the equation of the sphere as r² = 16.

Simplifying, we have r = 4.

Now we can write the parametric equations as x = 4 sinθ cosϕ, y = 4 sinθ sinϕ, and z = 4 cosθ, where θ ranges from 0 to π, and ϕ ranges from 0 to 2π.

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f(x)=4x2+8x-9 find and simplify f(2+x)

a. 23+x

b. 4x^2+8x-11

c. 4x^2+2x+23

d. 4x^2+24x+23

Answers

Answer:

d. 4x^2 +24x +23

Step-by-step explanation:

Evaluating polynomials is sometimes easier when they are written in Horner form:

f(x) = (4x +8)x -9

Substituting (x+2) for x, we have ...

f(x+2) = (4(x+2)+8)(x+2) -9

= (4x +16)(x +2) -9

= 4x^2 +24x +32 -9

= 4x^2 +24x +23 . . . . . matches choice D

_____

Alternative method

You can observe that the answer choices differ in the coefficient of the x-term. So, to make the correct selection, you only need to find the coefficient of the x-term. That will be the sum of coefficients of the x-terms in 4(x+2)^2 and 8(x+2). Those x-terms are 4·4x and 8x, so have a sum of (16+8)x = 24x. This matches choice D.

Willie has 4 baseball caps. Two of the caps are blue. One of the caps is red and one is green. What fraction of the caps is blue?

Answers

Answer:

2/4

when simplified = 1/2

Your answer is 1/2

Step-by-step explanation:

Amt. of Baseball caps = 4

Blue caps = 2

which can be written as 2/4

when simplified 2/4 ÷ 2/2 = 1/2

Final answer:

Willie has 4 baseball caps, of which 2 are blue. To find the fraction of caps that are blue, divide the number of blue caps (2) by the total number of caps (4), resulting in a fraction of 1/2.

Explanation:

Willie has 4 baseball caps in total, and 2 of those caps are blue. To determine what fraction of the caps is blue, you divide the number of blue caps by the total number of caps.

So, the calculation would be:

Number of blue caps = 2Total number of caps = 4Fraction of caps that are blue = Number of blue caps ÷ Total number of caps = 2 ÷ 4 = 1/2

Therefore, the fraction of Willie's caps that are blue is 1/2, which means half of the caps are blue.

Please help me last question

Answers

As you can see there are two triangles but it can be done calculating just for one. First we must understand how formula for area of triangle works.

[tex]A=\frac{1}{2}bh[/tex]

Where [tex]b[/tex] represents base (hypotenuse) and [tex]h[/tex] as height of the triangle.

We know that:

[tex]

b=13cm \\

h=4cm

[/tex]

Using this data we fill the formula.

[tex]A=\frac{1}{2}\cdot13\cdot4=\frac{13\cdot4}{2}=13\cdot2=\boxed{26cm^2}[/tex]

Hope this helps.

r3t40

Answer:

Area of the triangle = 26 cm²

Step-by-step explanation:

The given triangle has the measure of height h = 4 cm

and base of the triangle = 13 cm

We know the formula of the area of a triangle = [tex]\frac{1}{2}(Base)(height)[/tex]

By putting the values in the formula

Area of the triangle = [tex]\frac{1}{2}(4)(13)[/tex]

                                = 2×13

                                = 26 cm²

Therefore, area of the given triangle is 26 cm².

Can someone help me with this math question?

Answers

Answer:

  see attachment

Step-by-step explanation:

It is convenient to use a spreadsheet for this purpose.

The first row of numbers is constant at $45, as there is no daily charge associated with that payment method.

The second row of numbers uses the formula ...

  cost = $12 + $4×(number of days)

The third row of numbers uses the formula ...

  cost = $6×(number of days)

___

Of course, you can use these formulas to fill in the numbers by hand. For example, for 15 days, the charges are ...

Early Pay: $45 (no calculation necessary)Deposit Plus: $12 + $4×15 = $12 +60 = $72Daily Pay: $6×15 = $90

Can someone please help me with this problem
30 points!!!!

Answers

Answer:

29.4

Step-by-step explanation:

29.4444 rounded to the nearest tenth is 29.4

the other answerer forgot to round to the tenths place

A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 220 feet of fencing and does not fence the side along the street, what is the largest area that can be enclosed?

Answers

Answer:

* The largest area can be enclosed is 6050 feet²

Step-by-step explanation:

* Lets explain the situation to solve the problem

- There is a rectangular parking

- The parking will surrounded by fencing from three sides only

- The length of fencing is 220 feet

- Lets consider the width of the rectangle is x and the length of it is y

- The side along the street will not fence

* Lets put all of these data in equation

∵ The width of the parking is x

∵ The length of the parking is y

- He will not fence the side along the street

∴ The perimeter of the parking = x + y + x

∴ The perimeter of the parking = 2x + y

- The length of the fencing = the perimeter of the park

∵ The length of the fencing = 220 feet

∵ The perimeter of the parking = 2x + y

2x + y = 220 ⇒ (1)

- Lets find the area of the parking

∵ The area of any rectangle is length × width

∵ The width of the rectangle is x

∵ The length of the rectangle is y

∴ The area of the parking (A) = x × y

∴ The area of the parking = xy ⇒ (2)

- Lets find the value of y from equation (1) and substitute this value

 in equation (2)

∵ 2x + y = 220 ⇒ subtract 2x from both sides

∴ y = 220 - 2x

- Substitute this value in equation (2)

∵ A = xy

∴ A = x(220 - 2x) ⇒ open the bracket

∴ A = 220x - 2x²

- To find the largest area differentiate the area with respect to x

  and equate the result by 0 to find x which gives the largest area

A = 220x - 2x²

- Lets remember the differentiation rules

# If y = a x^n, where a is the coefficient of x then dy/dx = (an) x^(n-1)

# If y = ax, then dy/dx = a

# If y = a, where a is constant then dy/dx = 0

∴ dA/dx = 220 - 2(2) x^(2-1)

∴ dA/dx = 220 - 4x

- Put dA/dx = 0 ⇒ for largest area

∵ dA/dx = 0

∴ 220 - 4x = 0 ⇒ add 4x to both sides

∴ 220 = 4x ⇒ divide both sides by 4

∴ 55 = x

* The width of the parking is 55 feet

- Substitute this value of x in the equation of the area to find the

 largest area

∵ A = 220x - 2x²

∵ x = 55

∴ A = 220(55) - 2(55)² = 12100 - 6050 = 6050 feet²

* The largest area can be enclosed is 6050 feet²

Final answer:

To find the largest area that can be enclosed by the given amount of fencing, we can use the concept of optimization and solve for a rectangular lot's dimensions that maximize the area. The largest area that can be enclosed is 6050 square feet.

Explanation:

To find the largest area that can be enclosed, we can use the concept of optimization. Let's assume the length of the rectangular lot is x feet. The remaining length, which is not fenced, will be 220 - 2x feet. The width of the lot will be y feet. So we have 2x + y = 220. To find the largest area, we need to express the area in terms of a single variable. A = xy, substitute y = 220 - 2x. So A = x(220 - 2x) = 220x - 2x^2. To find the maximum value of A, we can find the vertex of the parabola, which corresponds to the maximum. The x-coordinate of the vertex is -b/2a. In this case, a = -2, b = 220, so x = -220/(-2*2) = 55.Plug this value of x into the equation y = 220 - 2x. y = 220 - 2(55) = 110. So the dimensions of the lot that will enclose the largest area are 55 feet by 110 feet. Substituting these values into the area formula A = xy, we get A = 55 * 110 = 6050 square feet.

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If f = {(4, 2), (6, 1), (8, 4), (10, 2), (12, 5)}, what is the range

Answers

Answer:

Range = {2,1,4,5}

Step-by-step explanation:

When a function is given in the form if a relation. i.e. ordered pairs.

When the function is given in the form of ordered pairs then the set of first elements i.e. x-coordinates of all ordered pairs forms domain while the set of second elements i.e. y-coordinate of all ordered pair is called range.

So in the given function:

Range = {2,1,4,5}

The repeating values are only written once..

Find the value of x.

log 3 x=4

Answers

Answer:

The correct answer option is D. 81.

Step-by-step explanation:

We are given the following expression and we are to find the value of x:

[tex] log _ 3 x = 4 [/tex]

We can inverse [tex] log _ 3 x [/tex] and re-write it as [tex]3^x[/tex].

Doing that, we will raise both the sides of the equation to the power of 3 to get:

[tex] 3 ^ { log 3 x } = 3 ^ 4 [/tex]

x = 81

Eric deposited $9,033.00 into a new savings account that earns interest compounded monthly. After 11 months, the balance in the account was $10,230.00. What was the interest rate on the account?
Round your answer to the nearest tenth of a percent.

Answers

Dang that’s tuff I feel bad

A sample of 64 observations is selected from a normal population. The sample mean is 215, and the population standard deviation is 15. Conduct the following test of hypothesis using the 0.025 significance level. H0: μ ≥ 220 H1: μ < 220 Is this a one- or two-tailed test? One-tailed test Two-tailed test What is the decision rule? (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.) What is the value of the test statistic? (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) What is your decision regarding H0? Reject Do not reject What is the p-value? (Round your answer to 4 decimal places.) rev: 10_28_2017_QC_CS-107404 Next Visit question mapQuestion 2 of 4 Total 2 of 4 Prev

Answers

Answer:

15 million

Step-by-step explanation:

Final answer:

This is a one-tailed test with a significance level of 0.025. The test statistic is -1.83, and we reject the null hypothesis. The p-value is approximately 0.0344.

Explanation:

This is a one-tailed test because the alternative hypothesis (H1) is specifying a less than condition (<) for the population mean.

The decision rule for a one-tailed test with a significance level of 0.025 is to reject the null hypothesis (H0) if the test statistic is less than the critical value.

The test statistic is calculated by subtracting the hypothesized population mean from the sample mean and dividing by the standard deviation divided by the square root of the sample size. In this case, the test statistic is [(215 - 220) / (15 / sqrt(64))] = -1.83 (rounded to 3 decimal places).

In order to make a decision regarding H0, we compare the test statistic with the critical value. If the test statistic is less than the critical value, we reject H0. Otherwise, if the test statistic is greater than or equal to the critical value, we fail to reject H0. In this case, -1.83 is less than the critical value, so we reject H0.

The p-value is the probability of obtaining a test statistic as extreme as the one observed, assuming that the null hypothesis is true. To find the p-value, we look up the test statistic in the standard normal distribution table. In this case, the p-value is approximately 0.0344 (rounded to 4 decimal places).

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In a class of 30 students 15 know Italian, 10 know French, and 3 know both languages. The rest of the students learn Spanish. How many students learn Spanish?

Answers

8 students know Spanish since 12 students know French and 7 students know Italian

Answer:

8 students learn Spanish.

Step-by-step explanation:

In a class total number of students are 30.

Students who know Italian = 15

Students who know French = 10

Students who know both = 3

Rest all students know Spanish.

By Venn diagram attached number of students who know Spanish

= [ 30 - (12 + 3 + 7 )]

= 30 - (22)

= 8 students.

8 students learn Spanish.

Solve for x. x2 - 2x - 24 = 0 A. -4, -6 B. -4, 6 C. 2, -6 D. 4, 6 Reset Next

Answers

Answer:

B. -4, 6

Step-by-step explanation:

Given the quadratic equation;

x^2 - 2x - 24 = 0

we can determine the solution by first factoring the expression on the left hand side. We determine two numbers whose product is -24 and sum -2. By trial and error the two numbers are found to be;

-6 and 4

We replace the middle term, -2x, with these two values;

x^2 + 4x -6x -24 = 0

x(x+4) -6(x+4) = 0

(x-6)(x+4) = 0

x-6 = 0 or

x + 4 = 0

x = 6 or x = -4

Answer: the answer is B

Step-by-step explanation: -4 & 6 are both zeros of the function .

A foam material has a density of 175 g/l. what is its density in units of lb/ft3? How do you get 1 gram/liter = 0.06242796 pound/cubic foot?

Answers

Answer:

Given: 175 g/L

1 gram/liter  =  0.06242796 pound/cubic foot

175 g/L * 0.06242796 pound/cubic foot= 10.924893 lb/ft3

So, a foam material has a density of 10.924893 lb/ft3 in units of lb/ft3

Step-by-step explanation:

Please help on puzzle #2

Answers

Answer:

  (2 +4i)(5 -6i) . . . or . . . (4 -2i)(6 +5i)

Step-by-step explanation:

The product of two complex numbers is ...

  (a +bi)(c +di) = (ac -bd) +(bc +ad)i

So, we're looking for pairs of numbers that can be combined in different ways to give 34 and 8. The numbers we found (by trial and error) are ...

  2, 4, 5, 6

where 4*6 +2*5 = 34 and 4*5 -2*6 = 8. Because of the effect if i^2 on the sign, we need to have the imaginary parts have opposite signs.

Each of the solutions shown above is representative of 4 solutions. For example, for the first one, you could have ...

  (2 +4i)(5 -6i) = (2·5 +4·6) + (4·5 +2(-6))i = 34 +8i

  (5 -6i)(2 +4i) = (5·2 +6·4) + (-6·2 +5·4) = 34 +8i . . . . . order of factors swapped

  (-2 -4i)(-5 +6i) = ((-2)(-5) -(-4)(6)) + ((-4)(-5) +(-2)(6))i = 34 +8i . . . . both factors in the first solution negated

  (-5 +6i)(-2 -4i) = ((-5)(-2) -(6)(-4)) +(6(-2) +(-5)(-4))i = 34 +8i . . . . factors swapped and negated

___

Likewise, the second shown solution above is representative of 4 solutions.

Possible solutions are ...

(2 +4i)(5 -6i)(4 -2i)(6 +5i)

with sign and order variations.

_____

Comment on trial and error

Actually, we did an exhaustive search of the 441 products of single-digit numbers [-9, 9] to see which pairs of them differed by 34. Then, among those, we looked for product pairs that added to 8. In the end, we found the 8 solutions described above.

Solve for x. Geometry plz help

Answers

- The solution/answer is 10.

The two angles are Supplementary angles and need to eaual 1980 degrees.

x-2 + 5x +2 = 180

Simplify:

6x = 180

Divide both sides by 6:

x = 180 /6

x = 30

Last answer choice is 4,2

Help

Answers

Use the midpoint formula:

(-7,-4) (-1,8)

(-7 + -1) /2 ,  (-4 +8) /2

-8/2 , 4/2

Midpoint = (-4,2)

In rhombus JKLM, if m<KLJ = 38°, find m<JIVIL.

Answers

Answer:

∠JML = 104°

Step-by-step explanation:

JL bisects angle KLM, so ...

∠KLM = 2·∠KLJ = 2·38° = 76°

Adjacent angles in any parallelogram are supplementary, so ...

∠JML = 180° -∠KLM = 180° -76°

∠JML = 104°

You find an old bathroom scale at a garage sale on your way home from getting a physical exam from your doctor. You step on the scale, and it reads 135 lb. You step off and step back on, and it reads 134 lb. You do this three more times and get readings of 135 lb, 136 lb, and 135 lb. a. What is the precision of this old bathroom scale? Would you consider this adequate precision for the type of measurement you are making? b. The much more carefully constructed and better-maintained scale at the doctor's office reads 126 lb. Assuming that you are wearing the same clothes that you wore when the doctor weighed you, do you think the accuracy of the old bathroom scale is high or low?

Answers

the scale has a persicion of 2 and it reads high.

1. 2 is the precision of this old bathroom scale.
2. Since 135 lbs of the old scale is higher than 126 lbs of a better-maintained scale at the doctor's office.

Given that,
An old bathroom scale,
You step on the scale, and it reads 135 lb. You step off and step back on, and it reads 134 lb. You do this three more times and get readings of 135 lb, 136 lb, and 135 lb.

What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements.

Here,
a). What is the precision of this old bathroom scale,
= higher reading - the lower reading
= 136 - 134
= 2

b. The much more carefully constructed and better-maintained scale at the doctor's office reads 126 lb.
Since measured weight by the old scale is 135 lbs which is higher than 126 lbs measured by the scale at the doctor's office.

Thus,
1. 2 is the precision of this old bathroom scale.
2. Since 135 lbs of the old scale is higher than 126 lbs of a better-maintained scale at the doctor's office.

Learn more about arithmetic here:

brainly.com/question/14753192

#SPJ2



Mike wants to redesign a box. Currently, it’s length is 20 cm, it’s width is 30 cm and it’s height is 40cm. he wants to keep the volume and the length unchanged and increase the height by 25 percent. What will be the new width of the box?

Answers

Answer:

  24 cm

Step-by-step explanation:

The product of height and width will remain the same, so the new width (w) will be given by ...

  w·(new height) = (old width)·(old height)

  w·(1.25·40 cm) = (30 cm)(40 cm)

  w = (30 cm)/1.25 = 24 cm . . . . . . . divide by 1.25·40 cm and simplify

_____

This derives from the fact that volume and length are unchanged. The formula for the volume in terms of length, width, and height is ...

  V = LWH

Then the product of W and H is the constant ...

  V/L = WH . . . . . divide by L

For our purpose, we only need to know that V and L are unchanged, so the product WH is unchanged. We don't need to know their values.

Of course, increasing the height by 25% is equivalent to multiplying it by 1.25:

  H + 25/100·H = H·(1 + 0.25) = 1.25H

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