Chords AC and BD intersect at the center of circle ABCD. If the length of CP = 8, which is the length of PB?

This problem is a combination problem since it did not indicate that there is a specified order of songs to be played. The type of combination problem is without repetition. Thus the working equation would be n!/r!(n-r)! wherein n is the total number of songs to choose from and r is the number of songs you can choose at a given time. The answer would be 125970. 

Answer: 125970

Step-by-step explanation:

The number of combinations of n things taken r at a time is given by :-

[tex]^nC_r=\dfrac{n!}{r!(n-r)!}[/tex]

Similarly , the  number of combinations of 20 songs taken 8 at a time is given by :-

[tex]^{20}C_8=\dfrac{20!}{8!(20-8)!}\\\\=\dfrac{20\times19\times18\times17\times16\times15\times14\times13\times12!}{8\times7\times6\times5\times4\times3\times2\timews12!}\\\\=125970[/tex]

Hence, the number of different playlists are possible= 125970

Answer:  The required value of A² is 9.

Step-by-step explanation:  We are given the following value of a variable A :

[tex]A=-3.[/tex]

We are to find the value of [tex]A^2.[/tex]

To evaluate [tex]A^2,[/tex] we need to multiply A and A.

Therefore, the evaluation is as follows :

[tex]A^2=A\times A=(-3)\times(-3)=9.[/tex]

Thus, the required value of A² is 9.

Neptune's distance from the Sun is about 78 times farther than that of Mercury. This result is computed by dividing Neptune's average distance from the Sun by Mercury's average distance from the Sun.

The subject here is to determine how many times Neptune is farther from the Sun than Mercury. We have the average distance from the Sun to Neptune as 4.503 × 109 km and the average distance from the Sun to Mercury as 5.791 × 107 km. To find out how many times Neptune is farther from the Sun than Mercury, we divide the distance of Neptune by the distance of Mercury: (4.503/5.791) x 109-7 which equates to 0.77782 times 102 or 7.7782 × 101. Therefore, Neptune is approximately 78 (7.8 × 101 when rounded to the nearest ten-thousandths) times farther from the Sun than Mercury.

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Final answer:

The midsegment of a triangle is a line segment connecting the midpoints of two sides of the triangle, parallel to the third side and half its length.

Explanation:

In geometry, the midsegment of a triangle is a line segment that connects the midpoints of two sides of the triangle. By definition, this segment is parallel to the third side of the triangle, and its length is half that of the third side. When we think about a triangle, we must consider it as a three-sided figure on a plane, with three angles adding up to 180 degrees. Within this triangle, the midsegment represents a special relationship between its sides and angles.

An example of a midsegment would be if you have a triangle ABC with points D and E being the midpoints of AB and AC, respectively. The midsegment DE would connect these midpoints and have properties that relate to side BC, the side of the triangle to which it is parallel.

The concept of the midsegment is useful in various geometric proofs and problems because it establishes proportional relationships within the triangle. It aids in solving problems by applying these inherent ratios and proportions.

Answer:

259001 x 10^4 is the answer

The calculated value of z in the equation 17 = z - (-9) is 8

How to determine the value of z in the equation

From the question, we have the following parameters that can be used in our computation:

17 = z - (-9)

When the bracket is evaluated, we have

17 = z + 9

So, we have

z = 17 - 9

Evaluate

z = 8

Hence, the value of z in the equation is 8

The associative property is not used when solving the given equation.

The property that is NOT used when solving the equation 15=2x-1 is the associative property.

The associative property states that the grouping of numbers does not affect the result of addition or multiplication. However, in this equation, there is no need to group the numbers in a different way.

Thus, the answer to the equation is:
15 = 2x - 1

Solving for x:
15 + 1 = 2x

16 = 2x

Divide both sides by 2:
16/2 = x

8 = x

To ascertain points of discontinuity, evaluate where functions are undefined or have limits that do not exist, often due to division by zero or undefined behavior in their basic components. For example, f(x) = 1/ sin x is discontinuous where sin x equals zero.

To find out where a function is discontinuous, we must examine points where the function is not defined or its limit does not exist. For a function defined by building blocks of continuous functions, it will generally remain continuous except at points where it involves division by zero or at points where its simpler components are not continuous.

For example, the function f(x) = 1/ sin x can be seen as the composition of the functions g(x) = 1/x and h(x) = sin x. We know that for a sine function, namely h(x), it is continuous everywhere, but the function g(x) is discontinuous at 0. Hence, f(x) will be discontinuous at points where sin x = 0, which occur at integer multiples of π.

More generally, to check continuity, ask yourself these questions about the function:

If you answer 'no' to any of these, the function might be discontinuous at some points, and hence, it would also be nondifferentiable at those points.