Colorblindness is an X-linked recessive condition. If a woman with normal vision whose father was colorblind has a son with a man with normal vision, what is the probability that he will be colorblind?

Answers

Answer 1

Answer: 0.25 or 25%

Step-by-step explanation:Women have two chromosomes XX and men have two also XY.

From the question, it can be seen that colorblindness is an X-linked recessive condition.

Let the X-linked recessive gene be specified as [tex]X^{-}[/tex] and the dominant gene which is not colorblind linked as [tex]X^{+}[/tex].

The question says the woman has a father who is colourblind which means her father possesses the X-linked recessive gene [tex]X^{-}[/tex] which means he has chromosomes [tex]X^{-}Y[/tex] and therefore must have given his daughter the recessive gene

For her husband who has normal vision his chromosomes will be [tex]X^{+} Y[/tex].

So, the probability that their son will be colourblind will be;

Chromosomes [tex]X^{+}[/tex] Y

[tex]X^{+}[/tex] [tex]X^{+} X^{+}[/tex] [tex]X^{+}Y[/tex].

[tex]X^{-}[/tex] [tex]X^{-} X^{+}[/tex]. [tex]X^{-}Y[/tex].

Therefore, the probability that their son will be color blind = ¼ or 0.25 or 25%

Colorblindness Is An X-linked Recessive Condition. If A Woman With Normal Vision Whose Father Was Colorblind

Related Questions

Two dice are thrown. Let E be the event that the sum of the dice is
even, let F be the event that at least one of the dice lands on 6 and
let G be the event that the numbers on the two dice are equal. Find
P(E), P(F), P(G), P(EF), P(F G), P(EG).

Answers

Answer:

P(E) = 1/2P(F) = 11/32P(G) = 1/6P(EF) = 5/52P(FG) = 1/32P(EG) = 1/6

Step-by-step explanation:

For the sum to be even, both dice can be odd, or both even. The probability of a dice being odd is 1/2 and the same is for it to be even. Since the result of the dices are independent, we have that

P(E) = (1/2)² + (1/2)² = 1/2

Out of the 36 possible outcomes for the dice (assuming that you can distinguish between first and second dice), there are 11 cases in which one dice is a 6 (if you fix 1 dice as 6, there are 6 possibilities for the other, but you are counting double 6 twice, so you substract one and you get 6+6-1 = 11). Since all configurations for the dices have equal probability, we get that

P(F) = 11/32

The probability for the second dice to be equal to the first one is 1/6 (it has to match the same number the first dice got). Hence

P(G) = 1/6

for EF, you need one six and the other dice even. For each dice fixed as 6 we have 3 possibilities for the other. Removing the repeated double six this gives us 5 possibilities out of 32 total ones, thus

P(EF) = 5/32

If one dice is 6 and both dices are equal, then we have double six, as a result there is only one combination possible out of 32, therefore

P(FG) = 1/32

If both dices are equal, in particular the sum will be even, this means that G= EG, and as a consecuence

P(EG) = P(G) = 1/6

Final answer:

The probabilities are P(E) = 1/2, P(F) = 11/36, P(G) = 1/6, P(EF) = 1/6, P(FG) = 1/12, and P(EG) = 1/4.

Explanation:

To find the probabilities, we need to use the concept of counting outcomes.

P(E):

There are 36 equally likely outcomes when two dice are thrown. Out of these, 18 outcomes result in an even sum. So, P(E) = 18/36 = 1/2.

P(F):

There are 11 outcomes where at least one die lands on 6 out of the 36 total outcomes. So, P(F) = 11/36.

P(G):

There are 6 outcomes where both dice show the same number, out of the 36 possible outcomes. So, P(G) = 6/36 = 1/6.

P(EF):

There are 6 outcomes where at least one die shows 6 and the sum is even. So, P(EF) = 6/36 = 1/6.

P(FG):

There are 3 outcomes where both dice show 6 and at least one of them shows 6. So, P(FG) = 3/36 = 1/12.

P(EG):

Out of the 36 outcomes, 9 outcomes result in both dice being the same and the sum being even. So, P(EG) = 9/36 = 1/4.

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Write y= -3/4 x-6 in standard form using integers.

Answers

Answer:

3x + 4y = -24.

Step-by-step explanation:

y= -3/4 x-6

Multiply through by 4:

4y = -3x - 24

3x + 4y = -24.

An airplane flying into a headwind travels the 1800-mile flying distance between New York City and Albuquerque, New Mexico in 3 hours and 36 minutes. On the return flight, the same distance is traveled in 3 hours and 20 minutes. Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.

airspeed of the plane mph
speed of the wind mph

Answers

Answer:

plane speed = 520 mph

wind speed = 20 mph

Step-by-step explanation:

let the speed of the wind be w mph and the speed of the plane be p mph

flying from NY to NM,

time taken = 3 hr 36 min = 3.6 hr

average ground speed = total distance / time taken

= 1800 / 3.6 = 500 mph

since it is a headwind, the plane speed will be slowed down by the head wind, resulting in a lower ground speed.

we can write the following equation:

ground speed = plane speed - wind speed

500 = p - w ------(eq1)

flying from NY to NM (return flight),

time taken = 3 hr 20 min = 3.333 hr

average ground speed = total distance / time taken

= 1800 / 3.333 = 540 mph

on the return trip, the headwind becomes a tailwind, hence the total ground speed would be faster than the plane's air speed , we can write the following equation:

ground speed = plane speed + wind speed

540 = p +  w ------(eq2)

with these 2 systems of equations, we can solve for p & w using either substitution of elimination method.

eventually you will end up with

plane speed = 520 mph

wind speed = 20 mph

   Speed of airplane is 520 miles per hour and speed of the wind is 20 miles per hour.

    Let the speed of an airplane = x miles per minute

And the speed of the wind = y miles per minute

Distance between New York City and Albuquerque = 1800 miles

Airplane covers the distance between New York City and Albuquerque in 3 hours 36 minutes Or 3.6 hours.

In return journey, airplane covers this journey in 3 hours 20 minutes Or 3.33 hours.

Since, airplane takes more time from New York City to Albuquerque,

Therefore, airplane covered this distance against the wind,

And the speed of the airplane against the wind = (x - y) miles per hour

Expression for the speed,

Speed = [tex]\frac{\text{Distance}}{\text{Time}}[/tex]

(x - y) = [tex]\frac{1800}{3.6}[/tex]

x - y = 500 ------- (1)

Speed of airplane in return journey = (x + y) miles per hour

And the equation will be,

x + y = [tex]\frac{1800}{3.33}[/tex]

x + y = 540 ------- (2)

By adding equation (1) and (2),

(x - y) + (x + y) = 500 + 540

2x = 1040

x = 520 miles per hour

From equation (1),

520 - y = 500

y = 20 miles per hour

       Therefore, speed of airplane is 520 miles per hour and the speed of wind is 20 miles per hour.

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she has 6 cherry candies, 3 grape candies, and 3 lime candies. If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry? Round to the nearest hundredth.

Answers

Answer:     [tex]\dfrac{1}{2}[/tex]

Step-by-step explanation:

We know that probability for any event = [tex]\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}[/tex]

Given : Charlotte has 6 cherry candies, 3 grape candies, and 3 lime candies.

I..e Total pieces of candies she has = 6+3+3=  12

Now , If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry is given by :-

[tex]\text{P(cherry)}=\dfrac{\text{Number of cherries}}{\text{Total candies}}\\\\=\dfrac{6}{12}\\\\=\dfrac{1}{2}[/tex]

Hence, the  probability that it will be cherry is [tex]\dfrac{1}{2}[/tex] .

The probability that Charlotte will pull a cherry candy out of the bag is 0.50 or 50%.

To determine the probability that Charlotte will randomly pull a cherry candy from the bag, we need to use the basic probability formula:

Probability = (Number of favourable outcomes) / (Total number of possible outcomes)

Step-by-Step Solution

Count the number of cherry candies: Charlotte has 6 cherry candies.Count the total number of candies: She has a total of 6 (cherry) + 3 (grape) + 3 (lime) = 12 candies.Calculate the probability: The probability of drawing a cherry candy is 6 (favourable outcomes) / 12 (total outcomes) = 0.5.Round to the nearest hundredth: Since 0.5 is already a decimal to the nearest hundredth, the final probability is 0.50.

Therefore, the probability that Charlotte will pull a cherry candy out of the bag is 0.50 (or 50%).

. Patrick, by himself, can paint four rooms in 10 hours. If he hires April to help, they can do the same hob together in 6 hours. If he lets April work alone, how long will it take her to paint four rooms?

Answers

Answer:  15 hours

Step-by-step explanation:

Given : Patrick, by himself, can paint four rooms in 10 hours.

i..e Time taken by Patrick to paint the 4 walls =  10 hours.

Since rate of work = [tex]\dfrac{Work}{Time}[/tex]

We consider the entire job as 1.

Then, the rate of work done by Patrick = [tex]\dfrac{1}{10}[/tex]

If he hires April to help, they can do the same hob together in 6 hours.

i.e.  the rate of work done by Patrick and April together = [tex]\dfrac{1}{6}[/tex]

Then, the rate of work done by April = rate of work done by Patrick and April together - rate of work done by Patrick

[tex]\dfrac{1}{t}=\dfrac{1}{6}-\dfrac{1}{10}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{10-6}{60}=\dfrac{4}{60}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{1}{15}\\\\\Rightarrow\ t=15[/tex]

Hence,it will take 15 hours April to paint four rooms .

At the baseball game, Adam bought 3 hot dogs and 2 sodas for $11. Four innings later, he purchased 2 hot dogs and 3 sodas for $10.25. Wat was the cost of a soda

Answers

Answer: the cost of one Soda was $1.75

Step-by-step explanation:

Let x represent the cost of one hot dog.

Let y represent the cost of one Soda.

At the baseball game, Adam bought 3 hot dogs and 2 sodas for $11. It means that

3x + 2y = 11 - - - - - - - - - - 1

In a later time, he purchased 2 hot dogs and 3 sodas for $10.25. It means that

2x + 3y = 10.25 - - - - - - - - -2

Multiplying equation 1 by 2 and equation 2 by 3, it becomes

6x + 4y = 22

6x + 9y = 30.75

Subtracting, it becomes

- 5y = - 8.75

y = - 8.75/- 5

y = 1.75

Substituting y = 1.75 into equation 1, it becomes

3x + 2 × 1.75 = 11

3x + 3.5 = 11

3x = 11 - 3.5 = 7.5

x = 7.5/3 = 2.5

A uranium mining town reported population declines of 3.2%, 5.2%, and 4.7% for the three successive five-year periods 1985–89, 1990–94, and 1995–99. If the population at the end of 1999 was 9,320:

Answers

Answer:

Step-by-step explanation:

Heres the complete question:

A uranium mining town reported population declines of 3.2%, 5.2%, and 4.7% for the three successive five-year periods 1985–89, 1990–94, and 1995–99. If the population at the end of 1999 was 9,320:

How many people lived in the town at the beginning of 1985? (Round your answer to the nearest whole number.)

solution:

Let the population of the town at the beginning of 1985 be P. Then, given that in the first five-year period the population declined by 3.2%, i.e., 0.032, the population of the town at the end of 1989 would be

(1 – 0.032)P = 0.968P.

Again, given that in the second five-year period the population declined by 5.2%, i.e., 0.052, the population of the town at the end of 1994 would be

(1 – 0.052)(0.968P) = 0.948 x 0.968P = 0.917664P.

Finally, given that in the third five-year period the population declined by 4.7%, i.e., 0.047, the population of the town at the end of 1999 would be

(1 – 0.047)(0.917664P) = 0.874533792P.

We are given, 0.874533792P = 9320 or

P = 9320/0.874533792 = 10657.11.

Thus, 10657 people lived in the town at the beginning of 1985

Final answer:

This is a mathematics question requiring the computation of past populations based on given percentage declines and the population at the end of 1999.

Explanation:

The question involves calculating the population of a uranium mining town at a prior date based on given percentage declines over successive five-year periods and the known population at the end of 1999. Since the population at the end of 1999 was 9,320, we work backward using the given percentage declines for each five-year period to estimate the population at the beginning of 1985. The calculation takes into account a 3.2% decline for 1985-89, a 5.2% decline for 1990-94, and a 4.7% decline for 1995-99. By applying these percentage changes in reverse, we can determine the population at the start of 1985.

There are 1200 elephants in a herd. Some have pink and green stripes, some are all pink and some are all blue. One third are pure pink. Is it true that 400 elephants are definitely blue?Why?

Answers

Answer: Yes.

The remaining 2/3 elephants left could be a mix of blue and green shared equally.

Step-by-step explanation:

Total number of elephants= 1200

Number of possible colours=3 (blue,green and pink)

Number of pink elephants =1/3 of 1200

Number of pink elephants =1/3×1200

Pink elephants are 400

The remaining fraction will b 1-1/3=2/3

Total number of elephants - number of pink elephants = remaining number of elephants => 1200-400=800

It is true that 400 elephants are definitely blue because the number of elephants remaining is twice 400

Given:

Total number of elephants = 1200

Colours available:

Blue

Pink

Pink & green

Pure Pink = 1/3 of 1200

= 1/3 × 1200

= 1200/3

Pure Pink = 400

Elephants remaining = Total number of elephants - Pure Pink

= 1200 - 400

= 800

Therefore, it is true that 400 elephants are definitely blue because the number of elephants remaining is twice 400

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Assigned Media Question Help Determine whether the following probability experiment represents a binomial experiment and explain the reason for your answer. An experimental drug is administered to 180180 randomly selected​ individuals, with the number of individuals responding favorably recorded.

Answers

Answer:

Yes ,it represents a binomial experiment.

Step-by-step explanation:

In order for a probability experiment to represent a binomial experiment ,there are three conditions.

1) There should be a fixed number of trials.

2) Trials should be independent.

3)Each trial can result in two outcomes.

In this experiment ,there is a fixed number of trial ,since it is administered to 180180 individuals.

Outcome on an individual does not affect the outcome of others.

Individuals respond as favorably or not ,so it can be reduced to two outcomes.

All conditions are met, so it can be considered as binomial experiment.

Jane wants to pick out an outfit for the school dance she can choose from 3 pairs of pants 5shirts and 2 pairs of shoes how many differnt outfits does jane have to choose from

Answers

Answer:

30

Step-by-step explanation:

we multiply each number. There are 3 pairs of pants 5 shirts and 2 pairs of shoes, so we multiply 3x5x2 to get 30

The number of different outfits that Jane has to choose from is 30

What is the rule of product in combinatorics?

If a work A can be done in p ways, and another work B can be done in q ways, then both A and B can be done in p×q ways.

Remember that this count doesn't differentiate between order of doing A first or B first then doing other work after the first work.

Thus, doing A then B is considered same as doing B then A

It is given that:

There are 3 pairs of pants,  5 shirts to choose from and 2 pairs of shoes to choose from.

One outfit would include one-one of these 3 things.

Pants can be chosen in 3 waysShirts can be chosen in 5 waysShoes can be chosen in 2 ways.

Thus, they all together can be chosen in 3 × 5 × 2 = 30 ways.

So there are 30 different outfit that Jane has to choose from.

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Using the graph, find the value of y when x = 7. (image down below)

a.
y = 7
c.
y = 2.71
b.
y = 6.1
d.
y = 4.42

Answers

Y=4.42, you just look at the graph when x is 7

Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards. If the actual width of a neighborhood park is 62 yards, how wide is the park in drawing?

Answers

Answer:

The park is 31 inches wide in the drawing.

Step-by-step explanation:

Given:

Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards.

The actual width of a neighborhood park is 62 yards.

Now, to find the width of park in drawing.

Let the width of park in drawing be [tex]x.[/tex]

The scale drawing of the city is 1 inch : 2 yards.

So, 1 inch is equivalent to 2 yards.

Thus, [tex]x[/tex] is equivalent to 62 yards.

Now, to get the width of park in drawing by using cross multiplication method:

[tex]\frac{1}{2} =\frac{x}{62}[/tex]

By cross multiplying we get:

[tex]62=2x[/tex]

Dividing both sides by 2 we get:

[tex]31=x[/tex]

[tex]x=31\ inches.[/tex]

Therefore, the park is 31 inches wide in the drawing.

Answer:

Answer:

31 inches

Step-by-step explanation:

62 yds divided by 2 equals 31 in

Step-by-step explanation:

Find the coordinates of the x- and y-intercepts for an ellipse with the equation (x+1)^2/9 + (y-2)^2/8 = 1

Answers

Answer:

x-intercepts: -1±√4.5y-intercepts: 2±8/3

Step-by-step explanation:

The x-intercepts are where y = 0.

  (x +1)^2/9 +(0 -2)^2/8 = 1

  (x +1)^2/9 +1/2 = 1 . . . . . simplify a bit

  (x +1)^2 = 9/2 . . . . . . . . .subtract 1/2, multiply by 9; next: square root, add -1

  x = -1 ±√4.5 . . . . . x-intercepts

__

The y-intercepts are where x=0.

  (0+1)^2/9 +(y-2)^2/8 = 1

  1/9 + (y -2)^2/8 = 1 . . . . . simplify a bit

  (y -2)^2 = 64/9 . . . . . . . . subtract 1/9, multiply by 8,

  y = 2 ±8/3 . . . . . . take the square root, add 2 . . . . y-intercepts

HELP!! 13 PTS!!!

Write a function of the form f(x) = a/x-h + k

With vertical asymptote is x=-2, horizontal asymptote is y=-5. The graph expands vertically by a factor of 2 and reflects across the x-axis.

Answers

Answer:

Step-by-step explanation:

VA= -2

HA= -5

F(x)= 2(x+5)/-(x+2)

If the square root of p2 is an integer greater than 1, which of the following must be true? I. p2 has an odd number of positive factors II. p2 can be expressed as the product of an even number of positive prime factors III. p has an even number of positive factors?

Answers

Answer:

Option | and Option || is True

Step-by-step explanation:

Given:

If the square root of [tex]p^{2}[/tex] is an integer greater than 1,

Lets p = 2, 3, 4, 5, 6, 7..........

Solution:

Now we check all option for [tex]p^{2}[/tex]

Option |.

[tex]p^{2}[/tex] has an odd number of positive factors.

Let [tex]p=2[/tex]

The positive factor of [tex]2^{2}=4=1,2,4[/tex]

Number of factor is 3

Let [tex]p=3[/tex]

The positive factor of [tex]3^{2}=9=1,3,9[/tex]

Number of factor is 3

So, [tex]p^{2}[/tex] has an odd number of positive factors.

Therefore, 1st option is true.

Option ||.

[tex]p^{2}[/tex] can be expressed as the product of an even number of positive prime factors

Let [tex]p=2[/tex]

The positive factor of [tex]2^{2}=4=1,2,4[/tex]

[tex]4=2\times 2[/tex]

Let [tex]p=3[/tex]

The positive factor of [tex]3^{2}=9=1,3,9[/tex]

[tex]9=3\times 3[/tex]

So, it is expressed as the product of an even number of positive prime factors,

Therefore, 2nd option is true.

Option |||.

p has an even number of positive factors

Let [tex]p=2[/tex]

Positive factor of [tex]2=1,2[/tex]

Number of factor is 2.

Let [tex]p=4[/tex]

Positive factor of [tex]4=1,2,4[/tex]

Number of factor is 3 that is odd

So, p has also odd number of positive factor.

Therefore, it is false.

Therefore, Option | and Option || is True.

Option ||| is false.

Your brother has $2000 saved fo a vacation. His airplane ticket is $637. Write and solve an inequality to find out how much he can spend for everything else.

Answers

The amount he can spend for everything else is less than or equal to 1363

The inequality is : [tex]s\leq 1363[/tex]

Solution:

Let "s" represent the brother's money to spend

Your brother has $2000 saved for a vacation

His airplane ticket is $637

Write an expression for the total money spent by adding "s" and the price of plane ticket $ 637

We can frame a inequality as:

[tex]s+637\leq 2000[/tex]

Here we have used "less than or equal to" symbol, because he can spent only up to 2000

Solve the inequality for "s"

[tex]s+637\leq 2000\\\\\text{Add -637 on both sides of inequality }\\\\s+637-637\leq 2000-637\\\\s\leq 1363[/tex]

Thus the amount he can spend for everything else is less than or equal to 1363

This is timed. Please Help me.
Which is the function g(x) for a restricted domain? g(x) = Negative RootIndex 3 StartRoot x minus 4 EndRoot; x greater-than-or-equal-to –4 g(x) = Negative RootIndex 3 StartRoot x 4 EndRoot + 4; x greater-than-or-equal-to 0 g(x) = Negative RootIndex 3 StartRoot x + 4 EndRoot; x greater-than-or-equal-to –4 g(x) = Negative RootIndex 3 StartRoot x EndRoot minus 4; x greater-than-or-equal-to 0

Answers

Answer:

the answer is 2x=9-0

Step-by-step explanation:

put it in the cAC  PAPER

Answer:

Its C

Step-by-step explanation:

Correct on ed genuity

g(x) + 3 x+4; x  greater or equal to -4

What is the weight per cm? ​

Answers

Answer:

  2/5 g/cm

Step-by-step explanation:

When you want to know "A per B", divide the given quantity of A by the corresponding quantity of B. ("Per" essentially means "divided by".)

It can be convenient to choose table values that make the division easy:

  12 g/(30 cm) = 4/10 g/cm = 0.4 g/cm

  20 g/(50 cm) = 2/5 g/cm . . . . . . . . . . . . . same as 0.4 g/cm

Your answer will be 2/5 g/cm it is correct ✨

Given that lines a and b are parallel, what angles formed on line a when cut by the transversal are congruent with ∠7?

Answers

Answer:

∠2 and ∠3

Step-by-step explanation:

Given:

lines a and line b are parallel and cut by transversal.

We need to find the which angles from line a are congruent to ∠7

Solution:

Now we know that;

line a║line b , So by corresponding angle postulate which states that;

"When two parallel lines are cut by a transversal , the resulting corresponding angles are congruent."

so  we can say that;

∠2 ≅ ∠6

Also by Vertical angle theorem which states that;

"If two angles are  vertical angles, then they are congruent ."

so  we can say that;

∠2 ≅ ∠3    and  ∠6 ≅ ∠7

So by Transitive Property of Congruence which states that;

When [tex]a \cong b\ \ \ and \ \ \ b\cong c \ \ \ so \ \ \ a\cong c[/tex]

so  we can say that;

∠2 ≅ ∠3 ≅ ∠6 ≅ ∠7

Hence measure ∠2 and ∠3 are congruent to measure ∠7.

Answer: it’s C

Step-by-step explanation:

Determine whether the underlined value is a parameter or a statistic. A study of 6076 adults in public rest rooms found that 23% did not wash their hands before exiting. Is the value a parameter or a statistic?

A. The value is a parameter because the 6,076 adults in public rest rooms are a sample
B. The value is a parameter because the 6,076 adults in public rest rooms are a population.
C. The value is a statistic because the 6076 adults in public restrooms are a sample
D. The value is a statistic because the 6,076 adults in public rest rooms are a population

Answers

Answer:

C

Step-by-step explaination:

A statistic is a data obtained by sampling a population

A sample is a part of a population studied for the purpose of testing of an hypothesis

6076 is a statistical value because it represents a part (sample) of the whole population

Final answer:

The value of 23% is a statistic calculated from a sample of 6076 adults in public restrooms.

Explanation:

In this question, the value of 23% represents the proportion of adults in public restrooms who did not wash their hands before exiting. Since this value is calculated from a sample of 6076 adults, it is considered a statistic. A statistic is a number that represents a property of a sample. On the other hand, a parameter is a numerical characteristic of the entire population. In this case, if we had data for all adults in public restrooms, the proportion would be a parameter.

Find the measure of the exterior angle​

Answers

Answer:

The answer to your question is a ) 127°    b) 80°

Step-by-step explanation:

a) We have to consider that the sum of the interior angles in a triangle equals 180°.

Then,

          89 + (5x - 7) + [180 - (14x + 1)] = 180

Simplification

          89 + 5x - 7 + 180 - 14x - 1 = 180

          5x - 14x = 180 - 89 + 7 - 180 + 1

                 - 9x = -81

                     x = -81 / -9

                     x = 9

Exterior angle = 14(9) + 1

                       = 127°  

b) The process is the same that the previous problem

          30 + (4x + 2) + [180 - (8 + 6x)] = 180

Simplification

          30 + 4x + 2 + 180 - 8 - 6x = 180

          4x - 6x = 180' - 30 - 2 + 8 - 180

               -2x = -24

                  x = -24/-2

                  x = 12

The measure of the external angle is = 8 + 6(12)

                                                              = 8 + 72

                                                              = 80°

Can someone please help me with my algebra fraction homework Page's 8,9 and 10. Thank You!

Answers

Answer:

8. A

9. C

10. A

In the sales comparison approach, using comparables that are five and 15 years old when appraising a subject that is 10 years old is an example of what?

Answers

Final answer:

In the sales comparison approach, using comparables of different ages requires adjustments for age or vintage to estimate the accurate value of the subject property considering physical and economic differences.

Explanation:

In the sales comparison approach, the use of comparables that vary significantly in age compared to the subject property is an example of adjusting for age or vintage. When appraising a subject property that is 10 years old, by using comparables that are five and 15 years old, an appraiser is attempting to account for differences in physical deterioration, functional obsolescence, and external obsolescence that may exist. A key part of this approach is applying adjustments to the comparables to reflect these differences, thereby arriving at a more accurate value for the subject property.

It is important to ensure that the base year used for comparison is consistent, and adjustments are made for any significant differences in market conditions or property features. The age adjustment is just one of many adjustments that might be made, including location, size, and condition. This process requires careful consideration and professional judgment to ensure that the end value is reflective of the current market.

Select the graph of the solution set that would represent the following expression.

3(x - 2) = 5 (x + 1)

Answers

Answer:

The solution for the expression is:

[tex]x=-\frac{11}{2}[/tex]

Step-by-step explanation:

Given expression:

[tex]3(x-2)=5(x+1)[/tex]

To graph the solution set.

Solution:

We will first solve for [tex]x[/tex] to find the solution for the expression.

We have:

[tex]3(x-2)=5(x+1)[/tex]

Using distribution:

[tex]3x-6=5x+5[/tex]

Adding 6 both sides.

[tex]3x-6+6=5x+5+6[/tex]

[tex]3x=5x+11[/tex]

Subtracting both sides by [tex]5x[/tex].

[tex]3x-5x=5x-5x+11[/tex]

[tex]-2x=11[/tex]

Dividing both sides by 2.

[tex]\frac{-2x}{-2}=\frac{11}{-2}[/tex]

∴ [tex]x=-\frac{11}{2}[/tex]

The correct graph that represents the solution is given below.

I don’t understand how to do this

Answers

Step-by-step explanation:

θ is in quadrant IV, so:

sin θ < 0

cos θ > 0

tan θ = sin θ / cos θ < 0

csc θ = 1 / sin θ < 0

sec θ = 1 / cos θ > 0

Without doing any calculations, we can see only the third option fits (in the second option, sin θ / cos θ = -9/18, not -18/9.  In the fourth option, csc θ and sec θ are switched).

Let's go ahead and calculate the values.  There are several ways to solve this.  One way is to use Pythagorean identities (ex., 1 + cot²θ = csc²θ).  Another way is to simply draw a triangle in the fourth quadrant.

cot θ = 1 / tan θ, and tan θ = opposite / adjacent.  So cot θ = adjacent / opposite.  If we draw a triangle with angle θ, where the adjacent side is 9 and the opposite side is -18, then we can use Pythagorean theorem to find the hypotenuse:

c² = a² + b²

c² = (9)² + (-18)²

c = √405

Therefore:

sin θ = -18 / √405

cos θ = 9 / √405

csc θ = √405 / 18

sec θ = √405 / 9

tan θ = -18/9

The median is:

a. the second quartile
b. the 50th percentile
c. the observation with half of the data on either side of it
d. all of the above

Answers

d all of the above because it fits all those descriptions
Final answer:

The median is all of the above: the second quartile, the 50th percentile, and the observation with half of the data on either side. It represents the central point of a data set where 50% of the values are below and 50% are above it.

Explanation:

The question asks to identify what the median represents in statistical terms. The median is:

a. the second quartile b. the 50th percentile c. the observation with half of the data on either side of it d. all of the above

The correct answer is d. all of the above. The median or second quartile (Q₂) is the value that divides the ordered dataset in half. It is also known as the 50th percentile since it implies that 50% of the data lies below this point and 50% lies above it. For example, in a dataset 1, 1, 2, 2, 4, 6, 6.8, 7.2, 8, 8.3, 9, 10, 10, 11.5, the median is 7, meaning that half of the values are smaller than 7 and half of the values are larger than 7.

A 16 inch candle is lit and burns at a constant rate of 1.1 inches per hour. Let t represent the never of hours that have elapsed since the candle was lit.

a) write an expression in terms of t that represents the number of incrhs that have burned from the candle since it was lit.
b) write an expression in terms of t that represents the remaining length of the candle (in inches).

Answers

Answer:

(a) Number of inches that have burned from the candle since it was lit is (1.1t) inches

(b) The remaining length of the candle is (16 - 1.1t) inches

Step-by-step explanation:

(a). Length of candle before it was lit = 16 inches

Constant rate at which at which candle burns = 1.1 inches per hour

Let t represent the number of hours that have elapsed since the candle was lit

In 1 hour, 1.1 inches of the candle burned

Therefore, in t hours, (1.1t) inches of the candle would have burned since the candle was lit

(b) Remaining length of candle = length of candle before it was lit - length of candle that have burned = 16 inches - 1.1t inches = (16 - 1.1t) inches

Working together, Melissa and Jing can mow a lawn in 5 hours. It would take Melissa 8 hours to do the job alone. What is the value of r, the part of the lawn that Jing could complete in 1 hour?A. 0.075.
B. 0.125.
C. 0.375.
D. 0.625.

Answers

Answer:

The amount of work completed by Jing in 1 hour is 0.075 which is option A

Step-by-step explanation:

Melissa & Jing can complete the work in 5 hours

This means that the amount of work completed by Melissa & Jing working together in 1 hour is (1÷5) = 0.2

Melissa will do the job in 8 hours, which means that the amount of job completed by Melissa working alone in 1 hour is (1÷8) = 0.125

The amount of work completed by Jing when he works alone in 1 hour will be the difference of amount of work completed by both of them in 1 hour with the amount completed by only Melissa in 1 hour.

There Amount of work completed by Jing in an hour = 0.2 - 0.125 = 0.075

Answer: option A

Step-by-step explanation:

Ms.Franks drives a maximum of 150 miles per week to and from work. She works 5 days per week. Write an inequality that shows m the number of mies she drives per day

Answers

Answer:

Step-by-step explanation:

Let m represent the number of miles that she drives per day.

She works 5 days per week. This means that the total number of miles that she drives in a week would be

5 × m = 5m

Ms.Franks drives a maximum of 150 miles per week to and from work. Therefore, the inequality that shows m the number of miles she drives per day would be

5m ≤ 150

m ≤ 150/5

m ≤ 30

The length of a rectangle is 4 meters less than twice the width. If the area of the rectangle is 240 square​ meters, find the dimensions.How many meters is the length? How many meters is the width?

Answers

Length is 12 meter and width is 20 meter.

Step-by-step explanation:

Let L be the length and W be the width.

The length of a rectangle is 4 meters less than twice the width.

That is

            L = 2W - 4

The area of the rectangle is 240 square​ meters

That is

        L x W = 240

        (2W - 4) x W = 240

         2W² - 4W = 240

         W² - 2W - 120 = 0

          (W -12 ) (W+10) = 0

         W = 12 m or W = -10 m

So width of rectangle is 12 meter

Length = 2 x 12 - 4 = 20 m

Length is 12 meter and width is 20 meter.

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