Convert 0.0000001 to a power of 10.

107
10−7
106
10−6

x+y=12

x-y=4

x=y-4

y-4+y=12

2y-4=12

2y=16

y=8

x=8-4=8

8+4=12

 the 2 numbers are 8 & 4

Mike will use 1 1/2 pounds of pork for his meatloaf recipe, which calls for a 3 to 1 ratio of beef to pork and a total of 6 pounds of meat.

Mike's meatloaf recipe has a total of 6 pounds of meat and uses a 3 to 1 ratio of beef to pork. To find out how much pork he will use, we can express the total amount of meat as the sum of beef and pork parts.

First, we know that there are 3 + 1 = 4 parts in total because of the given ratio. Since the ratio is 3 to 1, for every 4 parts of meat, 1 part is pork. Therefore, we calculate the weight of each part by dividing the total weight by the number of parts:

6 pounds ÷ 4 parts = 1.5 pounds per part

Since one part is pork, Mike will use 1.5 pounds of pork for his meatloaf. Expressed as a mixed number, that's 1 1/2 pounds of pork in simplest terms.

Answer:

[tex]2x+\frac{1}{3}+\frac{1}{x}=Base[/tex]

Step-by-step explanation:

Given: The area of the parallelogram is [tex]6x^2+x+3[/tex] and the height is 3x.

To find: The base of the given parallelogram.

Solution: It is given that The area of the parallelogram is [tex]6x^2+x+3[/tex] and the height is 3x.

Now, area of parallelogram is given as:

[tex]A=b{\times}h[/tex] where b is the base and h is the height of teh gievn parallelogram.

Substituting the given values, we have

[tex]6x^2+x+3=b{\times}3x[/tex]

⇒[tex]\frac{6x^2+x+3}{3x}=Base[/tex]

⇒[tex]\frac{6x^2}{3x}+\frac{x}{3x}+\frac{3}{3x}=Base[/tex]

⇒[tex]2x+\frac{1}{3}+\frac{1}{x}=Base[/tex]

which is the required expression for the base of the given parallelogram.

Rounded to the nearest hundredth, they are:

[tex]\[x_1 \approx -0.63 + 1.35i\][/tex]

[tex]\[x_2 \approx -0.63 - 1.35i\][/tex]

To solve the quadratic equation [tex]\(2x^2 + 5x + 5 = 0\)[/tex], we can use the quadratic formula:

[tex]\[x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}\][/tex]

where [tex]\(a = 2\), \(b = 5\)[/tex], and [tex]\(c = 5\)[/tex].

Substituting the values into the quadratic formula:

[tex]\[x = \frac{{-5 \pm \sqrt{{5^2 - 4 \cdot 2 \cdot 5}}}}{{2 \cdot 2}}\][/tex]

[tex]\[x = \frac{{-5 \pm \sqrt{{25 - 40}}}}{{4}}\][/tex]

[tex]\[x = \frac{{-5 \pm \sqrt{{-15}}}}{{4}}\][/tex]

Since the discriminant [tex](\(b^2 - 4ac\))[/tex] is negative, the solutions will involve imaginary numbers.

Using the imaginary unit [tex]\(i\)[/tex], where [tex]\(i^2 = -1\),[/tex] we can rewrite [tex]\(\sqrt{{-15}}\)[/tex] as [tex]\(i\sqrt{{15}}\):[/tex]

[tex]\[x = \frac{{-5 \pm i\sqrt{{15}}}}{{4}}\][/tex]

So, the solutions to the equation [tex]\(2x^2 + 5x + 5 = 0\)[/tex] are complex numbers. Rounded to the nearest hundredth, they are:

[tex]\[x_1 \approx -0.63 + 1.35i\][/tex]

[tex]\[x_2 \approx -0.63 - 1.35i\][/tex]

These solutions represent the points where the graph of the quadratic equation intersects the x-axis. They lie on the complex plane.

Answer:

$180,997.50.

Step-by-step explanation:

1. On TABLE 14-1 Future Value of $1.00 Ordinary Annuity, select the periods row corresponding to the number of interest periods.

2. Select the rate-per-period column corresponding to the period interest rate.

3. Locate the value in the cell where the periods row intersects the rate-per-period column.

4. Multiply the annuity payment by the table value from step 3.

Future value = annuity payment × table value

FV = $7500.00 * 24.133 = $180,997.50

The solution is: the following expression factored completely,

6x^2-13x=5 is: c  (3x-1)(2x-5)

An expression is any mathematical statement which consists of numbers, variables and an arithmetic operation between them. In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Here, we have,  

we have,

6x² - 13x  = +5

6x² - 13x  - 5 = 0

6x² - 15x + 2x - 5 =0

so, we get,

(3x-1)(2x-5) = 0

The sign of the constant term is the product of the signs of the constants in the binomial factors: (+1)·(+5). We want a positive sign for the constant, so both binomial factor constants must have the same sign.

When the signs of the binomial factor constants are the same, the x-term constant will match them. Thus, for a positive x-term constant, both binomial factor constants must be positive.

The signs of the x-term and the constant term are both positive, so the signs of the constants in the binomial factors must be the same and must both be positive. The only offering that meets that requirement is

... C (3x-1)(2x-5)

Hence, The solution is: the following expression factored completely, 6x^2-13x=5 is: c  (3x-1)(2x-5)

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area = pi x r^2

615.75 = 3.14 x r^2

r^2 = 615.75/3.14 =196.0987 round to 196.1

r = sqrt(196.1) = 14.00357 round to 14

radius = 14 kilometers

Answer:

512/2500

Step-by-step explanation:

gpe = 1/2 of the unit measures

 since 9 is a whole number the gpe would be 1/2 g

The solution of the given equation is -1 or 5

An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values.

For example, 3x + 5 = 15.

Given is an equation, x²-4x = 5,

we need to transform it into a perfect square,

The equation is =

x²-4x = 5

Add 4 to each side,

x²-4x+4 = 5+4

x²-4x+4 = 9

(x-2)² = 9

Solving for x,

x-2 = √9

x-2 = ±3

x = -1 or x = 5

Hence, the solution of the given equation is -1 or 5

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As per quadratic equation, all values of 't' for which the ball's height is 15 feet are 33.25 and (- 31.813).

"Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax² + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x)."

Given, [tex]h = 15[/tex] feet.

Therefore, the quadratic equation for [tex]h = 15[/tex] will be:

A ball is thrown from an initial height of 7 feet with an initial upward velocity of 23 feet per second.

The ball's height h (in feet) after t seconds is:

[tex]h = 7+23t-16t^{2}[/tex]

[tex]15 = 7+23t-16t^{2}[/tex]

⇒ [tex]15-7-23t+16t^{2} = 0[/tex]

⇒ [tex]16t^{2} -23t - 8 = 0[/tex]

⇒ [tex]t = [- (-23)[/tex] ± [tex]\sqrt{(23)^{2} - 4(16)(- 8)}[/tex] ]/(2 × 16)

⇒ [tex]t =[/tex] [23 ± 1041]/32

⇒ [tex]t =[/tex] [23 + 1041]/32, [23 - 1041]/32

⇒ [tex]t =[/tex] 33.25, - 31.813

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The equivalent expression to the given expression is [tex]8x^12y^3[/tex].

We have given that,

The  expression (2x^4y)^3

We have to determine the,

Which expression is equivalent to (2x^4y)^3

Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value(s) for the variable(s).

The answer is D.

2^3 is 8.

(x^4)^3 is x^12 and y^3 is simply y^3.

Put them together to get the final answer.

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In the given diagram, we are given two triangles, triangle ABC and triangle DEF.

And we are given a line or reflection l.

Triangle DEF is the mirror image of triangle ABC.

Therefore, all sides of the triangle ABC would be congruent to sides of triangle DEF.

AB = DF

AC = DE and

BC = EF.

We can see than BC is the smallest side of triangle ABC and EF is the smallest side of triangle DEF.

Answer:

H = .2L; H = .4

Step-by-step explanation: