Create a factorable polynomial with a GCF of 2y. Rewrite that polynomial in two other equivalent forms. Explain how each form was created.

Hello!

First of all, let the number be y.

"twice a number" means you should multiply that number by 2:

2y

Now, "fifteen less" means you should subtract 15:

2y-15

Now, this whole expression is less than or equal to -23:

2y-15≤-23

[tex]\rule{150}{1}~\rule{150}{2}[/tex]

Solve the inequality:

2y≤23+15

2y≤38

Divide both sides by 2

y≤19

Hope everything is clear.

Let me know if you have any questions!

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[tex]\boxed{An~Emotional~Helper}[/tex]

39) 6 *15 = 90 in deposits

40) 5 + 10 + 15 = 30 withdrew

41) 35 +90 = 125 - 30 = 95 in the account

The number of senior tickets is 375 and the adult tickets is 375 if All 500 seats to the Friday Night Seniors' Play were sold, and a total of $3312.50 was collected.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

All 500 seats to the Friday Night Seniors' Play were sold, and a total of $3312.50 was collected.

From the question:

A + S = 500

7.5A + 4S = 3312.50

-3.5S = - 437.50

S = -437.50/-3.5

S = 125

A = 500 - S

A = 375

Thus, the number of senior tickets is 375 and the adult tickets is 375 if All 500 seats to the Friday Night Seniors' Play were sold, and a total of $3312.50 was collected.

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Answer:

[tex]3\frac{5}{8}[/tex] pizzas were there at the start of the party.

Step-by-step explanation:

At the party let number of pizzas were = x

Aisha and her friends ate [tex]2\frac{1}{2}[/tex] pizzas after which [tex]1\frac{1}{8}[/tex] pizzas were left.

Therefore the equation formed will be

[tex]x-2\frac{1}{2}=1\frac{1}{8}[/tex]

x - (5/2) = 9/8

x = 9/8 + 5/2

x = 29/8 = [tex]3\frac{5}{8}[/tex]

Therefore [tex]3\frac{5}{8}[/tex] pizzas were there at the start of the party.

The approximate length of the leg of a right triangle is 17.

Use the concept of a triangle defined as:

A triangle is a three-sided polygon, which has three vertices and three angles which has a sum of 180 degrees.

And the Pythagoras theorem for a right-angled triangle:

(Hypotenuse)²= (Perpendicular)² + (Base)²

Given that,

One leg = 8 say it is the base of a triangle.

Hypotenuse = 19

Applying the Pythagorean theorem,

(19)²= (Perpendicular)² + (8)²

(Perpendicular)² = 297

Taking square root on both sides,

Perpendicular ≈ 17.2

Hence,

The required length of leg is approximately 17.

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Answer:

m= 6/5, n= √2

Step-by-step explanation:

This is just a simple version of the answer.

Answer:

Answer is A

Step-by-step explanation:

[tex]\displaystyle \boxed{y = \frac{6}{25}cos\:(1\frac{1}{2}\pi{x} - \frac{\pi}{2})} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{1}{3}} \hookrightarrow \frac{\frac{\pi}{2}}{1\frac{1}{2}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}} \hookrightarrow \frac{2}{1\frac{1}{2}\pi}\pi \\ Amplitude \hookrightarrow \frac{6}{25}[/tex]

OR

[tex]\displaystyle \boxed{y = \frac{6}{25}sin\:1\frac{1}{2}\pi{x}} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}} \hookrightarrow \frac{2}{1\frac{1}{2}\pi}\pi \\ Amplitude \hookrightarrow \frac{6}{25}[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = \frac{6}{25}cos\:1\frac{1}{2}\pi{x},[/tex] in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is approximately shifted [tex]\displaystyle \frac{1}{3}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{1}{3}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{1}{3}} = \frac{\frac{\pi}{2}}{1\frac{1}{2}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = \frac{6}{25}cos\:(1\frac{1}{2}\pi{x} - \frac{\pi}{2}).[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-2\frac{2}{3}, 0],[/tex]from there to [tex]\displaystyle [-1\frac{1}{3}, 0],[/tex]they are obviously [tex]\displaystyle 1\frac{1}{3}\:unit[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 1\frac{1}{3}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex]in which each crest is extended six-twenty-fifths unit beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

**Now, it really does not matter which function you use because the result will always be the same, but IF the system only wants one function as an answer, then it would be the sine function sinse it intersects the origin. Other than that, it does not matter which one is chosen.

I am delighted to assist you at any time.

The additive inverse of the expression -2.5 - 1.5 is 4. This is determined by first resolving the expression to -4 and then flipping the sign of this result to its opposite, yielding 4.

In mathematics, the additive inverse of a number is the number that when added to the original number results in zero. To find the additive inverse of the expression -2.5 - 1.5, follow these steps:

This is applicable similarily like in vector subtraction we add the first vector to the negative of the vector that needs to be subtracted. This is analogous to the subtraction of scalars.

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Answer:

13

Step-by-step explanation:

Answer: A. Matt is correct. Though two lines with equal slopes are often parallel, if they have the same y intercept, they are the same line and have infinitely many solutions.

Step-by-step explanation: Apex Answer

Answer:

[tex]\frac{r^{15}}{512}[/tex]

Step-by-step explanation:

(8r^-5)^ -3

[tex](8r^{-5})^{-3)[/tex]

Apply exponential property

(ab^m) ^n = a^m b^mn

Multiply the outside exponent with the exponents insde

[tex](8r^{-5})^{-3)= 8^{-3}r^{-5*-3}=8^{-3}r^{15}[/tex]

Appy property a^-m = 1/a^m to make the exponent positive

[tex]8^{-3}r^{15}= \frac{r^{15}}{8^3} =\frac{r^{15}}{512}[/tex]

Answer:

7+8+4-9+3=13                        

Step-by-step explanation:

We have given the statements and we have to figure out the answer.

Think of the number seven i.e. 7

Now add eight to it i.e. 7+8

Now add four more i.e. 7+8+4

Now subtract nine i.e. 7+8+4-9

Now add three i.e. 7+8+4-9+3

Simplification of expression  7+8+4-9+3

Add the terms,

7+8+4-9+3=22-9

Subtract the terms,

7+8+4-9+3=13

Therefore, The answer is 13.

Answer:

i)  y = 2x + 3

ii) y = 3x + 3

iii) y = 5x + 5

iv) y = 5x + 2

Step-by-step explanation:

i) The first graph has the slope (m) = 2 and the y-intercept(b) = 3

Therefore, the equation of the line is y = 2x + 3

ii) The second graph has the slope (m) = 3 and the y-intercept (b) = 3

Therefore, the equation of the line is y = 3x + 3

iii) The third graph has the slope (m) = 5 and the y-intercept (b) = 5.

Therefore, the equation of the line is y = 5x + 5

iv) The fourth graph has the slope (m) = 5 and the y-intercept (b) = 2

Therefore, the equation of the line is y = 5x + 2

3x-5 =10

 add 5 to both sides

3x=15

 divide both sides by 3

x=5

check:

3(5)-5 = 15-5 = 10

Using the Pythagorean theorem, we find that the sum of the squares of the two shorter sides of the triangle (6 cm and 10 cm) is less than the square of the longest side (12 cm). Hence, the triangle is obtuse because 6² + 10² < 12².

To classify a triangle whose sides measure 6 cm, 10 cm, and 12 cm, we can use the Pythagorean theorem which relates the lengths of a right triangle's legs (a and b) to its hypotenuse (c), by the formula a² + b² = c². In our case, we need to check if the squares of the two shorter sides add up to the square of the longest side. We calculate:

Since 136 is less than 144, 62 + 102 < 122 is true, and the triangle is obtuse because the sum of the squares of the lengths of the two shorter sides is less than the square of the length of the longest side.

Answer:

24

Step-by-step explanation:

edge 2022

area = 1/2 b*h

1/2 *10 *015 =

1/2 * 150 =75

 area = 75 square feet

Final answer:

The weight of the solids in the fruit remains constant at 10 kg. When the water content changes to 80%, the total weight of the fruit is 50 kg, since the solids make up 20% of the fruit's weight.

Explanation:

Initially, we have 100 kg of fruit with 90% water content. This means that there are 90 kg of water and 10 kg of solids (since water plus solids equals the total weight of the fruit).

After some time, the fruit dehydrates to where it now contains 80% water. However, the amount of solids in the fruit has not changed; it remains constant at 10 kg. To find the new total weight of the fruit with 80% water, we can set up the equation where 80% of the new weight is equal to the weight of the solids subtracted from the new total weight (since solids comprise the remaining 20% of the weight).

Let's denote the new total weight of the fruit as 'x'. According to the given information, 20% of x is the weight of the solids, which is 10 kg. Therefore, the equation is:

0.20x = 10 kg

Now we solve for 'x':

x = 10 kg / 0.20 x = 50 kg

The result is that there are 50 kg of the fruit with 80% water content now.