disadvantages of biodegradable plastics

Answer:

Mass of Ag₂S which is produced, 2.29 g

Mass of reactant in excess (S₈) which is left unreacted, 1.70g

Explanation:

The balanced reaction is this:

16 Ag (s)  +  S₈ (s)   →    8Ag₂S (s)

Molar mass of sulfur: 2g / 256.48 g/m = 0.00779 moles

Molar mass of silver: 2 g / 107.87 g/m = 0.0185 moles

For 16 moles of silver, I need 1 mol of S

For 0.0185 moles of Ag, I will need ( 0.0185 / 16) = 0.00116 moles

If I need 0.00116 moles of S, and I have 0.00779 moles it means, that S is my reactant in excess so the limiting reagent is the Ag.

Let's verify:

1 mol of S are needed to make react 16 moles of Ag

0.00779 moles of S, will need ( 0.00779 .16 ) = 0.124 moles of Ag

(I only have 0.0185 moles of Ag)

So the Ag is the limiting reactant, now we can calculate the mass of formed product:

16 moles of Ag, produce 8 moles of Ag₂S

0.0185 moles of Ag will produce (0.0185  .8)/ 16 = 0.00925 moles of Ag₂S

To find out the mass, let's multiply moles . molar mass

0.00925 m . 247.8 g/m = 2.29 g

Mass of the excess, which is left unreacted:

0.00779 m - 0.00116m = 0.00667 moles

0.00667m . 256.48 g/m = 1.70 g

Final answer:

To find the mass of Ag2S produced, determine the limiting reactant using mole ratios and convert the masses of Ag and S8 to moles. Then use the molar ratios in the balanced equation to calculate the mass of Ag2S produced. The mass of the unreacted reactant can be found by subtracting the mass of Ag2S produced from the initial mass of the reactant.

Explanation:

To determine the mass of Ag2S produced, we need to find the limiting reactant first. The balanced equation shows that the molar ratio of Ag to Ag2S is 16:8. Using the given masses of Ag and S8, we can convert them to moles, and based on the molar ratios, find the amount of Ag2S produced. Using the molar masses of Ag and S, which are 107.87 g/mol and 256.52 g/mol respectively, we calculate:

a. Mass of Ag2S = moles of Ag * (8 moles of Ag2S / 16 moles of Ag) * molar mass of Ag2S
b. The mass of the unreacted reactant can be calculated by subtracting the mass of Ag2S produced from the initial mass of the reactant.

Final answer:

To find the mole fraction of methanol in the solution, calculate the moles of methanol and water in the mixture. The mole fraction of methanol is 0.4.

Explanation:

To find the mole fraction of methanol in the solution, we need to calculate the moles of methanol and water in the mixture. The formula for mole fraction (X) is the moles of the component divided by the total moles in the solution.

First, we calculate the moles of methanol by dividing the mass of methanol by its molar mass:

Moles of methanol = 128 g / 32.04 g/mol = 4 mol

Next, we calculate the moles of water by dividing the mass of water by its molar mass:

Moles of water = 108 g / 18.02 g/mol = 6 mol

The total moles in the solution is the sum of the moles of methanol and water:

Total moles = 4 mol + 6 mol = 10 mol

Finally, we can calculate the mole fraction of methanol:

Mole fraction of methanol = Moles of methanol / Total moles = 4 mol / 10 mol = 0.4

The mole fraction of methanol in the solution is 0.4.

Answer:

the answer is 79.875

Explanation:

355/22.5*100

The amount of alcohol in the bottle of mouthwash is equal to 79.88 ml.

The volume percent is the concentration of a solution which is determined by the volume of a solute divided by the volume of a solution and multiplied by 100.

Volume Percentage = (Volume of Solute/Volume of Solution) × 100

Because a solution is made of both a solute and a solvent, the volume of a solution is equal to the sum of the volumes of the solute as well as the volume of the solvent present in it. All of the volumes must be expressed in milliliters.

Given, the percentage of alcohol in the mouthwash = 22.5 %

If we consider that the volume of the bottle of mouthwash is 100ml.

Then the amount of alcohol present in it = 22.5 ml

If 100ml of a bottle of mouthwash contains alcohol = 22.5 ml

Then the 355 ml of a bottle of mouthwash will contain alcohol is

= (22.5/100) × 355

= 79.88 ml

Therefore, 79.88 ml of alcohol present in 355 ml of mouthwash.

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Answer: option A) adequacy

Explanation:

Definitely, ACK has an healthy diet missing ADEQUACY of energy provision. This is seen in the shortfall of 1200 kilocalories of energy (2800 - 1600 = 1200).

Note that Ack feed on varieties of food, thus he gets balanced diet, and a variety diet. However, he is short of 1200 kilocalories, thus making him miss ADEQUACY

Answer:

True

Explanation:

The wind speed to be considered a tornado is 40 to 72 mph

Answer:

40% of the hurricane that occur in the United states hit Florida . the difference between a tropical storm and a

hurricane is wind speed – tropical strom usually bring wind of 36 to 47 mph where as hurricane winds speed are at least 74 mph

Answer:

A) True/True

Explanation:

Non spontaneous exothermic reactions need to reach the activation energy to get started (like all non spontaneous reactions), usually this energy is given in the form of heat.  So you can say the second statement is True

The first one is also True, if you don't give some energy (heat) to a non spontaneous reaction it won't start. Never the less, exothermic reaction's conversion of equilibrium is decreased when heat is addeed to the system.

Answer:

a. The reaction it catalyzes during glycolysis is reversible under intracellular conditions.

Explanation:

Hexokinase is an enzyme utilized in the phosphorylation of six carbon sugars during glycolysis or glycogen synthesis. The enzyme has the capacity to transfer phosphate group from ATP to six carbon sugar substrates.

Hexokinases are proteinous and there are four different types in human including hexokinase I, II, III, and IV.

Phosphorylation of hexoses by hexokinase under intracellular condition constitutes the first step of glycolytic pathway and it is irreversible.

The correct option is a.

Answer: norfenefrine [tex](C_8H_{11}NO_2)[/tex]

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=T_f^0-T_f=(-114.6-(-115.5)^0C=0.9^0C[/tex] = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

[tex]K_f[/tex] = freezing point constant = [tex]1.99^0C/m[/tex]

m= molality

[tex]\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}[/tex]

Weight of solvent (ethanol)= [tex]density\times volume=0.789g/cm^3\times 1.50cm^3=1.18g=1.18\times 10^{-3}kg[/tex]

Molar mass of unknown non electrolyte = M g/mol

Mass of unknown non electrolyte added = 82 mg = 0.082 g (1g=1000mg)

[tex]0.9=1\times 1.99\times \frac{0.082g}{M g/mol\times 1.18\times 10^{-3}}kg}[/tex]

[tex]M=154g/mol[/tex]

The molecular mass of norfenefrine [tex](C_8H_{11}NO_2)[/tex] is near to 154 and thus the identity of the white powder is norfenefrine .

Explanation:

Very little to no formation of silver sulfate, as the silver sulfate Ksp( solubility product) is very large compared to the yellow precipitate Ksp.

By adding sodium sulfate to the silver / yellow precipitate mix, this question asks us to find a potential result and justification for the outcome. This implies that we will have to select the right answer that has a valid result and an adequate explanation for it. A substance's Ksp, or solubility product, is defined as the product of the dissolved ion concentration of each substance elevated to the power of its stoichiometric coefficient.

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When sodium sulfate is added to a mixture with silver ions and a yellow precipitate, the likely result is an increase in silver sulfate precipitate as more sulfate ions are available to react with silver ions.

Explanation:

If sodium sulfate was added to the mixture containing silver ions and the yellow precipitate, the most likely observation after a significant amount of time would be an increase in the amount of precipitate. This is because adding sodium sulfate adds more sulfate ions to the mixture, which can react with the silver ions to form silver sulfate, a slightly soluble compound. As the reaction reaches a new equilibrium, more silver sulfate precipitate can form.

For example, the reaction represented by Ag+ (aq) + SO₄²- (aq) → Ag²SO₄ (s) shows the formation of silver sulfate precipitate upon the combination of silver ions and sulfate ions.

It's also important to mention that, depending on the original yellow precipitate mentioned (e.g., if it was due to a sulfide such as tin(II) sulfide, SnS, forming in the presence of H₂S), the sulfate ions from the sodium sulfate would not react directly with this other precipitate but could possibly shift the equilibrium of any concurrent reactions involving silver ions.

Final answer:

Using the Henderson-Hasselbalch equation and given the pKa of acetic acid as 4.75, for solution A (acid greater than base), the pH is 3.74; for B (base greater than acid), the pH is 5.74; and for C (equal concentrations), the pH is 4.74.

Explanation:

The problem involves the use of the Henderson-Hasselbalch equation to determine the pH of various buffer solutions containing acetic acid and its conjugate base, acetate. Given that the pKa of acetic acid is 4.75, we can match the pH levels to the solutions A, B, and C based on the ratios of acetic acid to acetate in each.

For solution A where [acetic acid] is ten times greater than [acetate], the pH will be 4.75 - 1 = 3.74.

For solution B where [acetate] is ten times greater than [acetic acid], the pH will be 4.75 + 1 = 5.74.

For solution C where [acetate] = [acetic acid], the pH will be equal to the pKa, which is 4.74.

Therefore, the pH levels will be matched to the following solutions:

Solution A: pH = 3.74

Solution B: pH = 5.74

Solution C: pH = 4.74

Answer:

1013.32 J/kg.K

Explanation:

The heat transferred by a changing in temperature without phase change can be calculated by:

Q = m*c*ΔT

Where m is the mass, c is the specific heat, and ΔT is the change in temperature (final - initial).

The values of c for water and copper can e found in thermodynamics tables:

cwater = 4.19x10³ J/kg.K

ccopper = 0.39x10³ J/kg.k

By the conservation of energy:

Qwater + Qcopper + Qmaterial = 0

0.200*4.19x10³*(26.1 - 19.0) + 0.150*0.39x10³*(26.1 - 19.0) + 0.085*c*(26.1 - 100) = 0

5949.8 + 415.35 - 6.2815c = 0

6.2815c = 6365.15

c = 1013.32 J/kg.K

The specific heat capacity of the unknown material is 1013.32 J/kg°C.

A calorimeter is used to measure the specific heat capacity of an unknown material. The calorimeter contains 0.200 kg of water and 0.150 kg of copper. A 0.085-kg sample of the unknown material is dropped into the calorimeter, and the temperature of the calorimeter increases from 19.0°C to 26.1°C. The specific heat capacities of water and copper are 4186 J/kg°C and 385 J/kg°C, respectively.

Heat transfer equation: Q = m * c * ΔT

Values of c for water and copper:

c_water = 4.19e3 J/kg°C

c_copper = 0.39e3 J/kg°C

Conservation of energy: Q_water + Q_copper + Q_material = 0

Calculations:

0.200 * 4.19e3 * (26.1 - 19.0) + 0.150 * 0.39e3 * (26.1 - 19.0) + 0.085 * c_material * (26.1 - 100) = 0

5949.8 + 415.35 - 6.2815c = 0

6.2815c = 6365.15

c_material = 1013.32 J/kg°C

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The question probable may be;

The complete question is: A laboratory technician drops a 0.0850-kg sample of unknown solid material, at 100.0∘C, into a calorimeter. The calorimeter can, initially at 19.0∘C, is made of 0.150 kg of copper and contains 0.200 kg of water. The final temperature of the calorimeter can and contents is 26.1∘C. Compute the specific heat of the sample.

Answer:

Explanation:

As the problem states that we have STP, these conditions are 1 atm of pressure and 273 K of temperature.

Now, the equation we must use to solve this:

PV = nRT

Solving for V:

V = nRT/P

Where:

V: Volume in Liters

n: moles of the tin block

T: temperature in K

P: Pressure in atm

R: gas constant which is 0.082 L atm / K mol

But also the problem is giving us the density data for all elements. In the case of Tin it is 7.31 g/cm³ or 7.31 g/mL, so, with the formula of density:

d = m/V  ----> V = m/d

From the above formula, we can calculate the volume of tin so:

V = 95.04 / 7.31

V = 13 mL

This would be the volume of the tin block, but, we have this block at STP so we need to calculate the volume with the ideal gas equation above. We need the molecular mass of Tin which is 118.71 g/mol, so let's calculate the moles:

n = m/MM

n = 95.04 / 118.71 = 0.8 moles

Now, solving for V:

V = 0.8 * 0.082 * 273 / 1

V = 17.91 L

And this would be the volume of the tin block at STP conditions.

Answer:

Alloy

Explanation:

Alloy: An alloy is a substance prepared by adding one or more element to a base or parent metal to obtain desirable products. The added element are usually metals or carbon. An alloy can be considered as a uniform mixture.

Examples of Alloy:

⇒ Brass is an alloy that contains 60 - 80% of copper and 20- 40% of zinc.

⇒Bronze is an alloy that contains 90% of copper and 10% of tin.

⇒ Steel is an alloy that contains  99.8% of iron and 0.2% of carbon.

Uses of Alloys:

⇒ They are used for making coins and medals

⇒ They are used in the construction of aircraft, ships and cars.

⇒They are used for making electromagnet.

The balanced chemical equations for heating copper sulfides such as covellite and chalcocite with oxygen to form copper oxides and sulfur dioxide gas.

Copper sulfides, such as CuS (covellite) or Cu2S (chalcocite), are often heated with oxygen to change them to copper oxides. This reaction also forms sulfur dioxide gas. The balanced chemical equation for this reaction with covellite is:

2 CuS + 3 O2 → 2 CuO + 2 SO2

And for chalcocite:

2 Cu2S + 3 O2 → 2 Cu2O + 2 SO2

Answer:

3

Explanation:

Firstly, we need to define the phenomenon know as isomerism. It is a phenomena in which 2 or more organic compounds have the same molecular formula but different structural arrangements.

In this special case of pentane, we are looking at other compounds whose molecular formulas are also C5H12 but have a different structure from that of pentane. It must be noted that two isomers might belong to the same homologous series or belong to a different homologous series entirely.

The first isomer is 2-methylbutane also known trivially as isopentane. It has the same molecular formula as said earlier with a methyl group substituted for a hydrogen atom on the second carbon of the principal chain of the molecule.

The second one is n-pentane itself. This is the normal straight chain pentane in its linear form.

The third one is 2-ethylpropane or dimethylpropane trivially knows as neopentane.

Pentane (C₅H₁₂) has three structural isomers: pentane, isopentane, and neopentane. These isomers differ in their carbon chain arrangement and have distinct properties, including boiling points. This brings the total number of structural isomers to three.

Pentane (C₅H₁₂) is a straight-chain hydrocarbon with a molecular formula that allows for three structural isomers. These isomers are:

Therefore, besides the straight-chain version (pentane), there are two additional structural isomers for pentane, bringing the total number of isomers to three. Each of these isomers possesses unique properties, such as different boiling points: pentane (36.1°C), isopentane (27.7°C), and neopentane (9.5°C).

Answer : The number of electrons transferred are, 10

Explanation :

Rules for the balanced chemical equation in acidic solution are :

First we have to write into the two half-reactions.

Now balance the main atoms in the reaction.

Now balance the hydrogen and oxygen atoms on both the sides of the reaction.

If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the less number of oxygen are present.

If the hydrogen atoms are not balanced on both the sides then adding hydrogen ion [tex](H^+)[/tex] at that side where the less number of hydrogen are present.

Now balance the charge.

The given balanced redox reaction is,

[tex]2MnO_4^-(aq)+10Br^-{aq)+16H^+(aq)\rightarrow 2Mn^{2+}(aq)+5Br_2(aq)+8H_2O(l)[/tex]

Step 1: Separate the skeleton equation into two half-reactions.

Oxidation : [tex]Br^-\rightarrow Br_2[/tex]

Reduction : [tex]MnO_4^-\rightarrow Mn^{2+}[/tex]

Step 2: Balance all atoms other than H and O.

Oxidation : [tex]2Br^-\rightarrow Br_2[/tex]

Reduction : [tex]MnO_4^-\rightarrow Mn^{2+}[/tex]

Step 3: Balance O.

Oxidation : [tex]2Br^-\rightarrow Br_2[/tex]

Reduction : [tex]MnO_4^-\rightarrow Mn^{2+}+4H_2O[/tex]

Step 4: Balance H.

Oxidation : [tex]2Br^-\rightarrow Br_2[/tex]

Reduction : [tex]MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2O[/tex]

Step 5: Balance the charge.

Oxidation : [tex]2Br^-\rightarrow Br_2+2e^-[/tex]

Reduction : [tex]MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O[/tex]

Step 6: Equalize electrons transferred.

Oxidation : [tex]2Br^-\rightarrow Br_2+2e^-[/tex]    × 5

Reduction : [tex]MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O[/tex]   × 2

and,

Oxidation : [tex]10Br^-\rightarrow 5Br_2+10e^-[/tex]

Reduction : [tex]2MnO_4^-+16H^++10e^-\rightarrow 2Mn^{2+}+8H_2O[/tex]

Step 7: Add the two half-reactions.

[tex]2MnO_4^-(aq)+16H^+(aq)+10Br^-(aq)\rightarrow 2Mn^{2+}(aq)+8H_2O(l)+5Br_2(aq)[/tex]

In this reaction, there are 10 number of electrons transferred.

Hence, the number of electrons transferred are, 10

The total number of electrons transferred in the reaction is 10.

The number of electrons transferred can be given by half reactions:

Oxidation reaction: [tex]\rm Br^-\rightarrow\;Br_2[/tex]

Reduction reaction : [tex]\rm MnO_4^-\;\rightarrow\;Mn^2^+[/tex]

The transfer of electrons can be balanced with the addition of a water molecule to the reaction. If the hydrogen atoms are not balanced on both sides then add hydrogen ion at that side where the less number of hydrogen is present. The electron transfer will be:

Oxidation reaction : [tex]\rm 2\;Br^-\;\rightarrow\;Br_2\;+\;2\;e^-[/tex]

Reduction reaction : [tex]\rm MnO_4^-\;+\;H^+\;+\;5\;e^-\;\rightarrow\;Mn^2^+\;+\;2\;H_2O[/tex].

By balancing the equation and electron transfer:

[tex]\rm 2\;MnO_4^-\;+\;16\;H^+\;10\;Br^-\;\rightarrow\;2\;Mn^2^+\;8\;H_2O\;+\;5\;Br_2[/tex]

The total number of electrons transferred in the reaction is 10.

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Final answer:

Sulfuric acid is used in automobile batteries and it acts as an electrolyte to allow the flow of electrons. In our bodies, acids and bases maintain pH balance and facilitate biochemical reactions. Acid rain can cause damage to buildings, vegetation, and ecosystems. Water is a substance that is neither an acid nor a base. The pH scale measures the concentration of hydrogen ions in a solution. Litmus paper is used to determine if a compound is an acid or base.

Explanation:

The acid used in automobile batteries is sulfuric acid (H2SO4). The sulfuric acid acts as an electrolyte, which allows the flow of electrons between the battery's positive and negative terminals. When the battery discharges, chemical reactions occur that convert the sulfuric acid into lead sulfate and water.

In our bodies, acids and bases play important roles in maintaining pH balance and facilitating various biochemical reactions. For example, the stomach produces hydrochloric acid (HCl) to help digest food, while bicarbonate ions (HCO3-) act as a base to neutralize excess acid in the blood.

Acid rain is harmful because it contains high levels of sulfuric acid (H2SO4) and nitric acid (HNO3). These acids can damage buildings, vegetation, and aquatic ecosystems.

A substance that is neither an acid nor a base is water (H2O). Water is considered neutral because it has an equal number of hydrogen ions (H+) and hydroxide ions (OH-).

The pH scale measures the concentration of hydrogen ions (H+) in a solution. The scale ranges from 0 to 14, with 7 being neutral. The lower the pH, the higher the hydrogen ion concentration and the more acidic the solution.

Litmus paper is a pH indicator used to determine if a compound is an acid or base. It changes color depending on the pH of the solution. If the strip turns red, it indicates an acid. If it turns blue, it indicates a base.

In addition to litmus paper, other devices that can determine an accurate measurement of pH include pH meters and pH strips that provide a more precise numerical value for the pH of a solution.

Answer:

-0.129V

Explanation:

The change in free energy is obtained from the given parameters after which the value is now applied to obtain the cell potential in volts from the formukar shown in the solution below.

Answer:

There is 89.9 kJ of heat evolved in the combustion

Explanation:

Step 1: Data given

Mole fraction of CH4 = 0.830

Mole fraction of C2H6 = 0.112

Mole fraction of C3H8 = 0.058

Volume = 2.15 L

Temperature = 24.5 °C = 297.65 Kelvin

744 mmHg is burned

The combustion of methane (CH4) releases 891 kJ of energy

The combustion of ethane (C2H6) releases 1561 kJ of energy

The combustion of propane (C3H8) releases 2220 kJ of energy

Step 2: Calculate number of moles of

p*V= n*R*T

⇒ p = The pressure = 744 mmHg = 744/760 = 0.979 atm

⇒ V = the volume = 2.15 L

⇒ n= The number of moles = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L*atm/k*mol

⇒ T = The temperature = 24.5 °C = 297.65 Kelvin

n(total) = PV / RT = (0.979 *2.15 ) /  (0.08206 * 297.65 )

n(total) = 0.0862 moles

Step 3: Calculate energy for combustion of each gas

CH4: 0.0862 moles * 0.830 * 891 kJ/mol =  63.7 kJ

C2H6: 0.0862 moles * 0.112 * 1561 kJ/mol = 15.07 kJ

C3H8: 0.0862 moles * 0.0580 * 2220 kJ/mol = 11.1 kJ

Step 4: Calculate tot heat for the combustion

63.7 kJ + 15.07 kJ  + 11.1 kJ = 89.9 kJ total

There is 89.9 kJ of heat evolved in the combustion

Answer:

Magnet with a positive and a negative pole

Explanation:

A great analogy to demonstrate what a polar molecule looks like is to imagine a magnet. A magnet has one positively charged end and one negatively charged end, two poles, that is.

Imagine that we have a magnet of a shape of a prism (water molecule has a bent shape). The two base vertices of the face of the triangle are positively charged, that's because hydrogen is less electronegative than oxygen and, hence, the two hydrogen atoms are partially positively charged in a water molecule.

Oxygen is more electronegative than hydrogen meaning it has a greater electron-withdrawing force, so electrons are closer to oxygen within the O-H bonds. Oxygen, as a result, becomes partially negatively charged, so it's our negative pole of the magnet.

Final answer:

Water is a polar molecule with a partial negative charge on the oxygen atom and partial positive charges on the hydrogen atoms. An analogy that can be used to compare this is a magnet, where opposite poles attract each other. This polarity in water molecules allows for the formation of hydrogen bonds.

Explanation:

Water is a polar molecule due to the unequal sharing of electrons between the oxygen and hydrogen atoms. The oxygen atom attracts the shared electrons more strongly, resulting in a partial negative charge on the oxygen atom and partial positive charges on the hydrogen atoms. This creates a dipole in the molecule, with the oxygen end being slightly negative and the hydrogen end being slightly positive.

One analogy that can be used to compare this is a magnet. In a magnet, the north pole attracts the south pole, and vice versa. Similarly, the partial negative oxygen end of water attracts the partial positive hydrogen ends of nearby water molecules, forming hydrogen bonds. These hydrogen bonds are stronger than conventional dipole-dipole forces and contribute to some of the unique properties of water, such as its high boiling point and ability to dissolve many substances.

Answer:

0.78 M

Explanation:

First, we need to know which is the value of Kc of this reaction. In order to know this, we should take the innitial values of N2, O2 and NO and write the equilibrium constant expression according to the reaction. Doing this we have the following:

N2(g) + O2(g) <------> 2NO(g)   Kc = ?

Writting Kc:

Kc = [NO]² / [N2] * [O2]

Replacing the given values we have then:

Kc = (0.6)² / (0.2)*(0.2)

Kc = 9

Now that we have the Kc, let's see what happens next.

We add more NO, until it's concentration is 0.9 M, this means that we are actually altering the reaction to get more reactants than product, which means that the equilibrium is being affected. If this is true, in the reaction when is re established the equilibrium, we'll see a loss in the concentration of NO and a gaining in concentrations of the reactants. This can be easily watched by doing an ICE chart:

      N2(g) + O2(g) <------> 2NO(g)

I:      0.2        0.2                 0.9

C:     +x         +x                   -2x

E:    0.2+x    0.2+x             0.9-2x

Replacing in the Kc expression we have:

Kc =  [NO]² / [N2] * [O2]

9 = (0.9-2x)² / (0.2+x)*(0.2+x)   ----> (this can be expressed as 0.2+x)²

Here, we solve for x:

9 = (0.9-2x)² / (0.2+x)²

√9 = (0.9-2x) / (0.2+x)

3(0.2+x) = 0.9-2x

0.6 + 3x = 0.9 - 2x

3x + 2x = 0.9 - 0.6

5x = 0.3

x = 0.06 M

This means that the final concentration of NO will be:

[NO] = 0.9 - (2*0.06)

[NO] = 0.78 M

Answer:

The larger person will have to get a larger parachute. The answer is D

Explanation:

If the smaller person does nothing, the larger person subsequently accelerate for more time and with larger terminal velocity. In this case the person needs to do something so as to reduce the terminal velocity and can also effectively raise the air resistance. For this reason the person should get a bigger parachute. The air resistance in the opened parachute overwhelms the downward force of the gravity. Whereas the net force as well as the acceleration of the person is upward. The bigger parachute has the ability to grab the greater force. If the parachute, dragging force works in the opposite to that of the force of the gravity, hence the drag force slows the parachute decrease as they fall.

Answer:

The needed electrons, N = 4 for silicon (Si)

and N = 1 for chlorine (Cl).

Explanation:

Si has atomic number 14 and belongs to group 14  and 3 period.

The electronic configuration of Si is 1s²2s²2p⁶3s²3p².

so, there are 4 electrons in valence shell i.e) third shell (n=3)

so, according to Lewis it needs 4 more electrons to get stability via octet configuration.

Cl has atomic number 17 and belongs to group 17 and 3 period.

The electronic configuration of Cl is 1s²2s²2p⁶3s²3p⁵.

so, there are 7 electrons in valence shell i.e) third shell (n=3)

so, according to Lewis it needs 1 more electrons to get stability via octet configuration.

So, in order to get stability 4 Cl atoms form 4 covalent bonds with 1 Si atom

In a Covalent bond, electrons are shared. so, now both Si and Cl have octet configuration.

Answer:

1. Amplitude 2. Wavelength 3.Pressure

Explanation:

I just did the quiz

A loud sound has a large amplitude. Wavelength is the distance between two peaks or crests. Sound waves are a type of radiation  wave.

Sound is defined in physics as a vibration that travels as just an acoustic wave through with a data transmission like a gas, liquid, or solid. Sound is the receipt of such waves as well as their perception even by brain in human physiology as well as psychology.

A loud sound has a large amplitude. Wavelength is the distance between two peaks or crests. Sound waves are a type of radiation  wave.

Therefore, a loud sound has a large amplitude. Wavelength is the distance between two peaks or crests. Sound waves are a type of radiation  wave.

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Answer:

38.8 mL

Explanation:

2CO(g) + O₂(g)⟶2CO₂(g)

Because pressure and temperature remain constant, we can think of the moles ratios as volume ratios. This means that 2mL of CO react with 1 mL of O₂ to produce 2 mL of CO₂.

Because the problem asks us to calculate the amount of oxygen gas unreacted, then CO is the limiting reactant. We calculate the amount of O₂ that reacted, from the available amount of CO:

82.4 mL CO * [tex]\frac{1mLO_{2}}{2mLCO}[/tex] = 41.2 mL O₂

Thus, the oxygen gas remaining is:

80.0 mL - 41.2 mL = 38.8 mL O₂

The volume of oxygen gas, O₂, remaining in the reaction vessel when 82.4 mL of carbon monoxide gas reacts with 80.0 mL of oxygen gas is 38.8 mL

From the question given above, we can conclude that CO is the limiting reactant since the question is asking for the volume of O₂ remaining.

Now, we shall obtain the volume of O₂ that reacted. This can be obtained as follow:

2CO(g) + O₂(g) —> 2CO₂(g)

From the balanced equation above,

2 mL of CO reacted with 1 mL of O₂.

Therefore,

82.4 mL of CO will react with = [tex]\frac{82.4}{2}\\\\[/tex] = 41.4 mL of O₂.

Finally, we shall determine the volume of O₂ remaining. This can be obtained as follow:

Volume of O₂ given = 80 ml

Volume of O₂ that reacted = 41.4 mL

Volume of O₂ remaining = (Volume of O₂ given) – (Volume of O₂ that reacted)

Volume of O₂ remaining = 80 – 41.2

Thus, the volume of O₂ remaining in the reaction vessel is 38.8 mL

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Answer:

The hydrolysis rate is significantly low because the energy of the transition state for hydrolysis is significantly high

Explanation:

In the given problem,  It was stated that the peptide bond is not stable thermodynamically. Peptide bonds are typically formed between molecules with carboxyl groups and molecules with amino groups. Therefore, it can be inferred that the hydrolysis rate is significantly low because the energy of the transition state for hydrolysis is significantly high.

Answer:

Paris climate agreement of 2015

Explanation:

In the year 2015, global leaders seeking to join forces to combat the ever increasing emissions of green house gases which is having a bad influence on our prevailing world climate met in Paris in 2015, although the treaty became effective in the year 2016.

There are 195 signatories to the treaty. The Paris Agreement's long-term temperature goal is to keep the increase in global average temperature to well below 2 °C above pre-industrial levels; and to pursue efforts to limit the increase to 1.5 °C, recognizing that this would substantially reduce the risks and impacts of climate change.

Answer : The correct option is, (e) eg = trigonal planar, mg = trigonal planar

Explanation :

Formula used  :

[tex]\text{Number of electron pair}=\frac{1}{2}[V+N-C+A][/tex]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

The given molecule is, [tex]CH_3^+[/tex]

[tex]\text{Number of electron pair}=\frac{1}{2}\times [4+3-1]=3[/tex]

That means,

Bond pair = 3

Lone pair = 0

The number of electron pair are 3 that means the hybridization will be [tex]sp^2[/tex] and the electronic geometry of the molecule will be trigonal planar.

Hence, the electron geometry (eg) and molecular geometry (mg) of [tex]CH_3^+[/tex]  is, trigonal planar and trigonal planar respectively.

Final answer:

The electron geometry of CH3+ is tetrahedral, and the molecular geometry is trigonal planar, due to there being three regions of electron density around the central carbon atom with no lone pairs.

Explanation:

The electron geometry (eg) of CH3+ is determined by the number of regions of electron density around the central carbon atom, which in this case is three bonded groups and no lone pairs. This corresponds to tetrahedral electron-pair geometry. However, since one of the positions is not occupied by electrons due to the positive charge, the molecular geometry (mg) is trigonal planar.

Therefore, the correct answer for the electron geometry and molecular geometry of CH3+ is:

eg = tetrahedral

mg = trigonal planar

Answer:

C. Atoms lose energy as a gas changes to a solid

Explanation: