do we lose taste buds as we age?

Answer: The Atom would have:  

9 protons

19 electrons (since atoms are electrically neutral and have the same number of electrons as protons)

20 neutrons

Explanation: Hope this Helps.

The distinction between a strong acid (HClO₄) and a weak acid (HClO₂) lies in the extent of ionization in the solution. Strong acids ionize fully, while weak acids only partially ionize.

A strong acid is one that completely ionizes in water, while a weak acid only partially ionizes. The extent to which a substance is ionized in solution is determined by its dissociation constant (Ka).

HClO₄ is considered a strong acid because it fully dissociates into its ions when dissolved in water.

HClO₂ (chlorous acid),  is a weak acid. It only partially ionizes in water, meaning that only a fraction of the HClO₂ molecules dissociate into H+ and ClO⁻² ions. As a result, the concentration of H+ ions in the solution is lower compared to a strong acid like HClO₄, resulting in a weaker acidity.

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To calculate the empirical formula from percent compositions, convert the percent composition of each element to grams, then to moles, and finally, divide the moles by the smallest number of moles obtained. In this case, the empirical formula is C5H7N.

The empirical formula can be calculated by finding the moles of each element in the compound using their percent compositions. In this case, we have 82% nitrogen, which corresponds to 82 grams, and 18% hydrogen, which corresponds to 18 grams. Next, we convert the grams to moles using the molar mass of each element. The molar mass of nitrogen (N) is 14 grams/mol, and the molar mass of hydrogen (H) is 1 gram/mol. Dividing the moles by the smallest number of moles obtained gives us the empirical formula. For this compound, the empirical formula is C5H7N.

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Answer:

Opinion

Explanation:

This is an opinion, actually. A Hypothesis has an "if/then" statement, for example, "IF I do not tie a knot at the end of a balloon THEN it will deflate". A scientific law states a fact that can be proven, such as Newtons Laws. A problem is the question you ask without making an educated guess.

Hope I helped! :)

Answer:

112g + 64g = 176g

Explanation:

Just pretty much put the things together or add them

The heat of reaction is -79.2 kJ/mol.

The equation of the reaction is;

CaO(s) + 2H2O(l) ------> Ca(OH)2(aq) + H2(g)

Number of moles of CaO =  6.50 g/56 g/mol = 0.12 moles

Number of moles of H2O =  99.70 g/18 g/mol = 5.53 moles

Temperature rise =  43.1 °C -  21.7 °C = 21.4  °C

Total mass of solution = 99.70 g + 6.50 g = 106.2 g

We must obtain the limiting reactant as follows;

1 mole of CaO reacts with 2 moles of H2O

0.12 mole of CaO reacts with 0.12 mole × 2 moles/1 mole = 0.24 moles

We can see that CaO is the limiting reactant.

Heat absorbed = 106.2 g ×  4.18 J/g-1K-1 × 21.4  °C = 9.5 kJ

Heat of reaction = -(9.5 kJ/0.12 moles) = -79.2 kJ/mol

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Answer: The density of cone is [tex]0.115g/cm^3[/tex]

Explanation:

The equation used to calculate the volume of cone is:

[tex]V=\frac{1}{3}\pi r^2h[/tex]

where,

V = volume of cone

r = radius of the cone = 5 cm

h = height of the cone = 2 cm

Putting values in above equation, we get:

[tex]V=\frac{1}{3}\times (3.14)\times (5)^2\times 2\\\\V=52.33cm^3[/tex]

To calculate volume of a substance, we use the equation:

[tex]\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}[/tex]

We are given:

Mass of cone = 6 g

Volume of cone = [tex]52.33cm^3[/tex]

Putting values in above equation, we get:

[tex]\text{Density of cone}=\frac{6g}{52.33cm^3}\\\\\text{Density of cone}=0.115g/cm^3[/tex]

Hence, the density of cone is [tex]0.115g/cm^3[/tex]

Answer: mass = 19 grams

Explanation: Density is directly proportional to mass and indirectly proportional to the volume. So, the density formula is:

[tex]density=\frac{mass}{volume}[/tex]

density and volume are given and the question asks to calculate the mass. So, the formula could be rearranged as:

mass = density x volume

Given density is [tex]\frac{5.2g}{cm^3}[/tex] and the volume is [tex]3.7cm^3[/tex] .

Let's plug in the values in the formula to calculate the mass:

mass = [tex]\frac{5.2g}{cm^3}*3.7cm^3[/tex]

mass = 19.24 grams

Both the density and volume have two sig figs, so if the answer is round off to correct number of sig figs then the mass will be 19 grams.

Answer: Option (d) is the correct answer.

Explanation:

A hypothesis is referred to as an idea which might be a possible explanation for a particular experiment or situation but it is not necessarily correct.

So, in order to form a hypothesis, a scientist has to theoretically look into the problem so that he can provide or suggest a possible explanation for the same.

This is because when the scientist looks theoretically into a problem then he will check all the steps in detail and its possible outcomes or results. This will lead to a possibility that the suggested hypothesis will be correct.

Answer:

The object is not traveling fast enough to match Earth’s curvature.

Explanation:

c on edge

Final answer:

To calculate the grams of oxygen that reacted, subtract the mass of copper (254.2 grams) from the mass of the copper oxide product (286.2 grams) to get 32.0 grams of oxygen.

Explanation:

To find out how many grams of oxygen reacted with copper to form copper oxide, perform a mass difference calculation from the given data. The law of conservation of mass states that mass is neither created nor destroyed in a chemical reaction. Therefore, the mass of products formed in a reaction equals the mass of reactants.

The initial mass of copper is given as 254.2 grams, and the final mass of the copper oxide product is 286.2 grams. To find the mass of oxygen that has combined with the copper, subtract the mass of copper from the mass of the copper oxide product:

Mass of oxygen = Mass of copper oxide – Mass of copper

Mass of oxygen = 286.2 grams – 254.2 grams

Mass of oxygen = 32.0 grams

Therefore, 32.0 grams of oxygen must have reacted with the copper.

A hypertonic solution has a higher osmolarity than a cell's cytoplasm, leading to water exiting the cell, known as crenation in red blood cells and plasmolysis in plant cells.

A hypertonic solution is one where the extracellular fluid has a higher osmolarity than the cytoplasm of a cell, causing water to move out of the cell. In such a solution, cells will lose water and shrink, which can be observed in red blood cells as crenation. Additionally, in plant cells, this phenomenon can result in the cell membrane detaching from the cell wall, known as plasmolysis.

To determine which flask holds which sucrose solution, you can use a method called titration. This involves adding a known solution that does not contain sucrose to each flask and noting when the indicator solution changes color. By comparing the volumes of the known solution required for each flask, you can determine the relative concentrations of the sucrose solutions.

In order to determine which flask holds which solution, we can use a method called titration. Here's how it works:

For us to accurately determine what compound this is, additional info must be given. However I can suggest two compounds which have molecular mass of about 30.07 g/mol.

1. It could be NO or nitric oxide.

The molecular mass is 16 + 14= 30 g/mol

But if we search the exact weight, it is 30.01 g/mol

2. It could also be (CH3)2  or ethane.

The molecular mass is 2*12+ 6*1= 30 g/mol

But if we search the exact weight, it is 30.07 g/mol.

So we could say it more likely to to be (CH3)2 

Answer:

C2H6

Explanation:

There is no central carbon atom therefore you can put subscripts on both atoms.

Final answer:

Molarity is a quantitative measure for the concentration of a solution, defined as the number of moles of solute per liter of solution, and is calculated by dividing moles of solute by liters of solution.

Explanation:

The concentration of a solution can be quantitatively expressed using molarity, which is one of the most frequently used methods by chemists. Molarity is defined as the number of moles of solute per liter of solution. To calculate the molarity of a solution, you must first determine the amount of solute in moles and then measure the total volume of the solution in liters. For example, if you have 1.5 moles of NaCl dissolved in 0.500 liters of solution, the molarity (M) of the solution is calculated by dividing the number of moles of solute by the number of liters of solution, resulting in a 3 molar (3 M) solution of NaCl.

The volume of a 75-gram sample of gold at STP is approximately 3.886 cubic centimeters, calculated using the formula V = m/d, where m is the mass and d is the density of gold.

To determine the volume of a 75-gram sample of gold at standard temperature and pressure (STP), we must use the formula that relates mass (m), density (d), and volume (V), which is m = dV. Since the density (d) of gold is 19.3 g/cm³, we can rearrange the formula to solve for volume: V = m/d.

By plugging in the mass of the gold sample and the given density, we get:

V = 75 g / 19.3 g/cm³ = 3.886 cm³

Therefore, the volume of a 75-gram sample of gold at STP is approximately 3.886 cubic centimeters.

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Final answer:

The scientist is conducting descriptive research, documenting soil composition changes in a forest over time without manipulating the environment.

Explanation:

The scientist performing an investigation by collecting soil composition data in a forest after a wildfire and analyzing it for trends over ten years is conducting descriptive research. This type of investigation involves documenting and describing changes in the environment without manipulating any variables. Descriptive research aims to accurately portray the characteristics of a particular individual, situation, or group over time and is foundational in natural sciences, including soil science and ecology.

In contrast to experimental research, which involves creating a controlled environment to test specific hypotheses, descriptive research documents real-world phenomena as they naturally occur. Moreover, this type of research is crucial for understanding ecological succession, how ecosystems recover after disturbances, and for guiding conservation and management practices.