During the World Series the host city wide hotel occupancy rose 21% over the prior busiest night. If the busiest night had been 76% occupany, what was the new record? (use % symbol in answer)

Answer:

91.96%.

Step-by-step explanation:

We have been given that during the World Series the host city wide hotel occupancy rose 21% over the prior busiest night. The busiest night had been 76% occupancy.

[tex]\text{New record}=\text{Old record+ Increase in old record}[/tex]

To find the new record of occupancy, we will find 21% of 76% and add it to 76%.

[tex]\text{The new record}=76\%+({21\%\text{ of } 76\%)[/tex]

[tex]\text{The new record}=\frac{76}{100}+({\frac{21}{100}\times\frac{76}{100})[/tex]

[tex]\text{The new record}=0.76+({0.21\times 0.76)[/tex]

[tex]\text{The new record}=0.76+0.1596[/tex]

[tex]\text{The new record}=0.9196[/tex]

Now let us convert our answer in percentage by multiplying our answer by 100.

[tex]\text{The new record}=0.9196\times 100=91.96\%[/tex]

Therefore, the new record of occupancy was 91.96%.

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