Ella and Margaret were at a carnival. They each got a ticket to the Ferris wheel. Ella got a snow cone, and Margaret got a cotton candy. Ella had a certificate for $6 off the cost. Margaret paid the rest, which came to $12.75. Each Ferris wheel ticket is $5. And a snow cone is $3.50. What was the cost of the cotton candy? A.$5.00 B.$5.25 C.$2.50 D.$7.25

Answer:

[tex]-1.5[/tex]

Step-by-step explanation:

We have been given that Beth's score is 3/4 of Trevon's score.

[tex]\text{Beth's score}=-8\times \frac{3}{4}[/tex]

[tex]\text{Beth's score}=-2*3[/tex]

[tex]\text{Beth's score}=-6[/tex]

We are also told that Leah’s score was 1/4 of Beth’s score.

[tex]\text{Leah's score}=-6\times \frac{1}{4}[/tex]

[tex]\text{Leah's score}=-\frac{3}{2}[/tex]

[tex]\text{Leah's score}=-1.5[/tex]

Therefore, Leah score was [tex]-1.5[/tex].

1 kilogram = 100 grams

3500 / 1000 = 3.5 kilograms

65.5 - 3.5 = 62

she weighs 62 kilograms

Final answer:

Tom was able to cut 7.5 pieces of ribbon that were 1/12 yard long from a total length of 5/8 yard, which normally rounds down to 7 full pieces.

Explanation:

Tom cut his 5/8 yard ribbon into pieces that were 1/12 yard long. To find out how many such pieces Tom could cut, you divide the total length of ribbon by the length of each piece:

Calculate how many 1/12 yard pieces are in one yard by dividing 1 by 1/12. This equals 12, which means there are 12 pieces of 1/12 yard in one yard.

Multiply 5/8 by 12 to find out how many 1/12 yard pieces are in 5/8 of a yard. (5/8) * 12 = 7.5

Therefore, Tom was able to cut 7.5 pieces of ribbon, each measuring 1/12 yard. Since you can't have half a piece of ribbon, we would round down to 7 pieces (the question remains if the leftover could form a full piece, but based on the initial information, it's assumed to not be a full piece).

Answer: Richard has 5 7/12 rolls left.

Step-by-step explanation:

Hi to answer this question, first, we have to sum the amount of rolls Richard bought for the bbq:

4 1/4 + 5 2/3 = 4 3/12 + 5 8/12 = 9 11/12

Finally we have to subtract the amount of rolls eaten at the bbq to the previous number.

9 11/12 - 4 1/3 = 9 11/12 - 4 4/12= 5 7/12  

So, Richard has 5 7/12 rolls left.

Feel free to ask for more if needed or if you did not understand something.

Answer:

7

Step-by-step explanation:

Answer:

240 divided by 3 = c

Step-by-step explanation:

Tricky...it is $240 for all 3 nights....not $240 per night.  So it is division NOT multiplication.

To divide 2 and 5/14 by (2 and 5/8 times 1 and 3/7), convert the mixed numbers to improper fractions, multiply the fractions in the denominator and numerator separately, and then divide by multiplying by the reciprocal of the second fraction. The final answer is 44/5.

To divide 2 and 5/14 by (2 and 5/8 times 1 and 3/7), we first need to convert the mixed numbers into improper fractions. 2 and 5/14 can be written as 33/14, 2 and 5/8 can be written as 21/8, and 1 and 3/7 can be written as 10/7. Next, we can multiply the fractions in the denominator and the fractions in the numerator separately. So (2 and 5/8 times 1 and 3/7) becomes (21/8 times 10/7). This can be simplified to (105/8 times 10/7). We then multiply the numerators (105 * 10) and the denominators (8 * 7) resulting in 1050/56.

Now we can divide 33/14 by 1050/56. Division is the same as multiplying by the reciprocal of the second fraction. So 33/14 divided by 1050/56 is the same as 33/14 times 56/1050. We can simplify this by canceling common factors. After canceling, we are left with (33 * 8) / (2 * 15), which becomes 264/30. Finally, we can reduce this fraction to its simplest form by dividing the numerator and denominator by their greatest common factor, which is 6. So the final answer is 44/5.

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Final answer:

To solve for x in the equation X + 6y = 29, subtract 6y from both sides to isolate x, resulting in x = 29 - 6y. The solution for [tex]\( x \)[/tex] in the first equation is [tex]\( x = \frac{19}{2} \).[/tex]

Explanation:

To solve for [tex]\( x \)[/tex] in the first equation [tex]\( x + 6y = 29 \)[/tex], we can isolate [tex]\( x \)[/tex] by subtracting [tex]\( 6y \)[/tex] from both sides of the equation:

[tex]\[ x + 6y - 6y = 29 - 6y \][/tex]

[tex]\[ x = 29 - 6y \][/tex]

Now, we can substitute this expression for [tex]\( x \)[/tex] into the second equation [tex]\( 2x - 4y = -6 \):[/tex]

[tex]\[ 2(29 - 6y) - 4y = -6 \][/tex]

First, distribute the 2:

[tex]\[ 58 - 12y - 4y = -6 \][/tex]

Combine like terms:

[tex]\[ 58 - 16y = -6 \][/tex]

Next, isolate the term with [tex]\( y \)[/tex] by adding [tex]\( 16y \)[/tex] to both sides:

[tex]\[ 58 - 16y + 16y = -6 + 16y \][/tex]

[tex]\[ 58 = -6 + 16y \][/tex]

Now, isolate [tex]\( y \)[/tex]by subtracting 6 from both sides:

[tex]\[ 58 - 6 = 16y \][/tex]

[tex]\[ 52 = 16y \][/tex]

Finally, solve for [tex]\( y \)[/tex] by dividing both sides by 16:

[tex]\[ \frac{52}{16} = y \][/tex]

[tex]\[ y = \frac{13}{4} \][/tex]

Now that we have found the value of [tex]\( y \)[/tex], we can substitute it back into the expression we found for[tex]\( x \)[/tex]:

[tex]\[ x = 29 - 6\left(\frac{13}{4}\right) \][/tex]

[tex]\[ x = 29 - \frac{39}{2} \][/tex]

[tex]\[ x = \frac{58}{2} - \frac{39}{2} \][/tex]

[tex]\[ x = \frac{19}{2} \][/tex]

Therefore, the solution for [tex]\( x \)[/tex] in the first equation is [tex]\( x = \frac{19}{2} \).[/tex]