Answer:
Radiation is the correct answer for this question.
Explanation:
Have you ever chewed on a wintergreen mint in front of a mirror in the dark? If you have, you may have noticed some sparks of light coming out of your mouth as you chewed on the candy; and, without knowing it, you have experienced a physical phenomenon called triboluminescence. In this problem you will analyze some of the key elements of triboluminescence in wintergreen candies. When you break a sugar crystal with your teeth, energetic electrons, released by the broken chemical bonds, collide with nitrogen molecules in the air. As a result of these collisions, the electrons in the nitrogen molecules jump to a state of higher energy; when they decay to their ground state, radiation is emitted. Part A Imagine that an electron in an excited state in a nitrogen molecule decays to its ground state, emitting a photon with a frequency of 8.88×1014 Hz . What is the change in energy, ΔE, that the electron undergoes to decay to its ground state?
Answer:
[tex]\Delta E = -5.89\cdot 10^{-19} J[/tex]
Explanation:
The change in energy of the electron that undergoes the decay is equal to the energy of the photon, which is given by:
[tex]\Delta E=hf[/tex]
where
h is the Planck constant
f is the frequency of the Photon
Here we have
[tex]f=8.88\cdot 10^{14}Hz[/tex]
Substituting into the formula, we find
[tex]\Delta E=(6.63\cdot 10^{-34} Js)(8.88\cdot 10^{14}Hz)=5.89\cdot 10^{-19} J[/tex]
and since the electron decays from a higher energy level to the ground state, its change in energy will be negative:
[tex]\Delta E = -5.89\cdot 10^{-19} J[/tex]
The change in energy ΔE, that an electron undergoes when it decays to its ground state during triboluminescence can be calculated using the energy of a photon formula E=hf. By substituting the given values, we get E=(6.63 x 10^-34 JS) x (8.88 x 10^14 Hz), which results in E=5.89 x 10^-19 Joules.
Explanation:In the phenomenon of triboluminescence, the change in energy denoted by ΔE that an electron undergoes to decay to its ground state can be found using the formula for the energy of a photon: E = hf, where h is Planck's constant (6.63 x 10^-34 Joule seconds) and f is the frequency of the photon. Given that the frequency of the photon emitted when the decay occurs is 8.88 x 10^14 Hz, we multiply this frequency by Planck's constant to find the change in energy.
E = hf = (6.63 x 10^-34 JS) x (8.88 x 10^14 Hz) = 5.89 x 10^-19 Joules. This value is the change in energy that the electron undergoes as it decays to its ground state, a phenomenon evidenced by the sparks observed when wintergreen candies are chewed.
Triboluminescence, while intriguing and visible in the dark, is the result of energetic electrons reacting with nitrogen molecules and releasing energy in the form of visible light. This physical phenomenon can be explained and calculated using basic principles of photon energy.
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How can natural events such as floods hurricanes and tornadoes be predicted
Answer:
Predicting the size, location, and timing of natural hazards is virtually impossible, but now, earth scientists are able to forecast hurricanes, floods, earthquakes, volcanic eruptions, wildfires, and landslides using fractals.
Explanation:
Planet that is one astronomical unit from the sun
Answer:
Earth
Explanation:
"Light travels at a speed of 299,792 kilometers per second; 186,287 miles per second. It takes 499.0 seconds for light to travel from the Sun to the Earth, a distance called 1 Astronomical Unit."
Source : https://image.gsfc.nasa.gov/poetry/venus/q89.html
How far do tectonic plates move in a year
Answer:
About 4-10cm/yr
Explanation:
Plates have different motion due to the tectonic settings and the properties of the plates.
Tectonic plates typically move very slowly over the weak asthenosphere in the mantle. This accounts for the wide range of about 4-10cm/yr. Some plates moves slower than this. It is difficult to perceive plate movement using our observational senses.
Scientists use GPS units and satellites to monitor the rate of movement of plates in a year to as to forecast a whole lot of environmental event that might result from that.
What derived unit is used to measure the slope of the line in this graph?
Answer:
C. g/cm³
Explanation:
The slope is measured by calculating the variation of the Y values over the X values between two points on a line.
So, the formula is: Slope = Δy/Δx
That means that we also take the units.
In this case, the Y-axis unit is in g, while the X-axis unit is in cm³.
Dividing a Y-variation over an X-variation will give you g/cm³.
In this case, let's assume the line passes through (10,100) (not exactly, but close enough for the example), and it passes through (0,0)
So the slope would be: (100-0) g / (10-0) cm³ = 10 g/cm³
Compressions and rarefactions are characteristic of
Answer:
Of longitudinal waves
Explanation:
Depending on the direction of the oscillation, there are two types of waves:
- Transverse waves: in a transverse wave, the oscillations occur perpendicularly to the direction of propagation of the wave. Examples are electromagnetic waves.
- Longitudinal waves: in a longitudinal wave, the oscillations occur parallel to the direction of propagation of the wave. In such a wave, the oscillations are produced by alternating regions of higher density of particles, called compressions, and regions of lower density of particles, called rarefactions. Examples of longitudinal waves are sound waves.
Compressions and rarefactions are characteristic of sound waves, which are longitudinal waves. Compressions are regions of high pressure, while rarefactions are regions of low pressure, both created by the vibrating motion of the sound source.
Explanation:Compressions and rarefactions are characteristic features of a sound wave, which is a type of longitudinal wave. When a sound source vibrates, it causes fluctuations in the pressure of the medium through which it travels, typically air. These fluctuations manifest as alternating regions of higher pressure, known as compressions, and lower pressure, known as rarefactions. Sound waves consist of these repeating patterns of compressions and rarefactions, moving away from the source of the sound in the form of a wave.
During compression, air molecules are pushed closer together, leading to a higher pressure region. Conversely, during rarefaction, air molecules are spread out, creating a lower pressure region. For example, when a speaker cone moves forward, it compresses the air in front of it, and when it moves backward, it creates a rarefaction. These disturbances travel through the air, causing our eardrums to vibrate and enabling us to perceive sound.
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A capacitor is connected across an AC source. Suppose the frequency of the source is doubled. What happens to the capacitive reactant of the inductor?
The capacitive reactants is doubled.
The capacitive reactants is traduced by a factor of 4.
The capacitive reactants remains constant.
The capacitive reactants is quadrupled.
The capacitive reactants is reduced by a factor of 2.
Final answer:
Doubling the frequency of an AC source connected to a capacitor halves the capacitive reactance due to the inverse relationship between frequency and capacitive reactance.
Explanation:
The question seems to contain a slight error in terminology, implying a mix-up between capacitive and inductive components. However, addressing the core intent, if a capacitor is connected across an AC source and the frequency of the source is doubled, the capacitive reactance is reduced by a factor of 2. This outcome is based on the principle that capacitive reactance (XC) is inversely proportional to both the frequency of the AC source (f) and the capacitance (C). The formula for capacitive reactance is XC = 1/ (2πfC), indicating that as the frequency (f) increases, XC decreases. Therefore, doubling the frequency results in the halving of the capacitive reactance, making the correct answer 'The capacitive reactance is reduced by a factor of 2'.
What is the energy of an electron in the 2s orbital of a hydrogen atom?
Answer:
-3.4 eV ([tex]-5.4\cdot 10^{-19} J[/tex])
Explanation:
In a hydrogen atom, the energy of an electron is given by:
[tex]E_n = - 13.6 eV \frac{1}{n^2}[/tex]
where
n is the principal quantum number
For an electron in the 2s orbital,
n = 2
So substituting this value into the formula, we find
[tex]E_2 = -13.6 eV \frac{1}{2^2}=-3.4 eV[/tex]
And converting this into Joules, we have
[tex]E_2 = -3.4 eV \cdot 1.6\cdot 10^{-19} J/eV=-5.4\cdot 10^{-19} J[/tex]
What is the equivalent resistance if you connect three 10.0 Ω resistors in series?
Req = 30.0Ω.
When two or more resistors are in series, the intensity of current that passes through each of them is the same. Therefore, if you notice, you can observe that the three previous series resistors are equivalent to a single resistance whose value is the sum of each one.
Req = R1 + R2 + R3 = 10.0Ω + 10.0Ω + 10.0Ω = 30.0Ω
The equivalent resistance if you connect three 10.0 Ω resistors in series will be 30 ohms.
What is series circuit?In the series circuit, the amount of current flowing through any component in a series circuit is the same and the sum of the individual resistances equals the overall resistance of any series circuit.
The voltage in a series circuit, the supply voltage, is equal to the total of the individual voltage drops.
[tex]\rm R_{eq}= R_1+R_2+R_3 \\\\ R_{eq}=10+10+10 \\\\ R_{eq}=30 \ ohms[/tex]
Hence, the equivalent resistance will be 30 ohms.
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whats the diffrence between health insurance and insurance ?
Answer:
Insurance is for items like cars and things health insurance is for injuries. Hope this helps!
Explanation:
A diverging lens has a focal length of magnitude 22.8 cm. (a) Locate the images for each of the following object distances. 45.6 cm distance 22.8 cm distance 11.4 cm distance
(a) -15.2 cm
We can solve the problem by using the lens equation:
[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]
where
f = -22.8 cm is the focal length of the lens (negative because it is a diverging lens)
p = 45.6 cm is the distance of the object from the lens
q is the distance of the image from the lens
Solving the equation for q, we find the position of the image:
[tex]\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-22.8 cm}-\frac{1}{45.6 cm}=-0.066 cm^{-1}[/tex]
[tex]q=\frac{1}{-0.066 cm^{-1}}=-15.2 cm[/tex]
and the negative sign means that the image is virtual.
(b) -11.4 cm
In this case, the distance of the object from the lens is
p = 22.8 cm
Substituting into the lens equation, we can find the new image distance, q:
[tex]\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-22.8 cm}-\frac{1}{22.8 cm}=-\frac{2}{22.8 cm}[/tex]
[tex]q=\frac{-22.8 cm}{2}=-11.4 cm[/tex]
and the negative sign means that the image is virtual.
(c) -7.6 cm
In this case, the distance of the object from the lens is
p = 11.4 cm
Substituting into the lens equation, we can find the new image distance, q:
[tex]\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-22.8 cm}-\frac{1}{11.4 cm}=-0.132 cm^{-1}[/tex]
[tex]q=\frac{1}{0.132 cm^{-1}}=-7.6 cm[/tex]
and again, the negative sign means that the image is virtual.
Final answer:
To locate the images for a diverging lens with a focal length of -22.8 cm, the lens formula is used, yielding image distances of approximately -45.6 cm for an object 45.6 cm away, undefined (at infinity) for an object 22.8 cm away, and -15.2 cm for an object 11.4 cm away.
Explanation:
To locate the images formed by a diverging lens with a negative focal length, we use the lens formula:
[tex]\( \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \)[/tex]
Where f is the focal length, [tex]\( d_o \)[/tex] is the object distance, and [tex]\( d_i \)[/tex] is the image distance. Since the lens is diverging, f is negative.
Given a focal length (f) of -22.8 cm for the diverging lens, we can solve for the image distance [tex](\( d_i \))[/tex] for the following object distances [tex](\( d_o \))[/tex] :
For an object distance of 45.6 cm: [tex]\(d_i = \frac{1}{\frac{1}{-22.8} - \frac{1}{45.6}} \approx -45.6\text{ cm}\)[/tex]For an object distance of 22.8 cm: [tex]\(d_i = \frac{1}{\frac{1}{-22.8} - \frac{1}{22.8}} \)[/tex] is undefined, indicating the image is formed at infinity.For an object distance of 11.4 cm: [tex]\(d_i = \frac{1}{\frac{1}{-22.8} - \frac{1}{11.4}} \approx -15.2 \text{ cm}\)[/tex]The negative sign for [tex]\( d_i \)[/tex] means that the image is virtual and located on the same side as the object.
Two particles with oppositely signed charges are held a fixed distance apart. The charges are equal in magnitude and they exert a force on each other. Half of one of the charges is transferred to the other charge and the distance between them is unchanged. What happens to the force exerted on one charge by the other charge?
When half of one of the charges of equal magnitude is transferred to the other, the electric force between them reduces to 75% of the original force while maintaining the same distance.
Explanation:In this scenario, you're dealing with the concept of electric forces between charged particles. The force between two charges is given by Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. This can be represented by the equation F = k * Q1 * Q2 / r^2
Initially, we have two charges both of magnitude Q, the force is F_initial = k * Q * Q / r^2. Half of one of the charges is transferred to the other, the charges become 1.5Q and 0.5Q. The new force is F_final = k * 1.5Q * 0.5Q / r^2 = 0.75 k * Q * Q / r^2.
So, the force between the charges reduces to 75% of the original force when half of one of the charges is transferred to the other while the distance remains the same.
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Help please!
A ray of light is incident upon a strange material at an angle of 27 deg from the normal.
Its angle of refraction in the material is 11 deg.
Based on the table below, how would we identify this material?
Clue: the index of refraction in air is 1
A) diamond
B) glass, flint
C) plexiglass
D) zircon
Explanation:
This described situation is known as Refraction, a phenomenon in which the light bends or changes it direction when passing through a medium with a index of refraction different from the other medium.
In this context, the index of refraction is a number that describes how fast light propagates through a medium or material.
According to Snell’s Law:
[tex]n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})[/tex] (1)
Where:
[tex]n_{1}=1[/tex] is the first medium index of refraction (air)
[tex]n_{2}[/tex] is the second medium index of refraction (the value we want to know)
[tex]\theta_{1}=27\°[/tex] is the angle of the incident ray
[tex]\theta_{2}=11\°[/tex] is the angle of the refracted ray
Now, let's find [tex]n_{2}[/tex] from (1):
[tex]n_{2}=n_{1}\frac{sin(\theta_{1}}{sin(\theta_{2}}[/tex] (2)
Substituting the known values:
[tex]n_{2}=(1)\frac{sin(27\°)}{sin(11\°)}}[/tex]
Finally:
[tex]n_{2}=2.379\approx 2.4[/tex]
If we compare this result with the given table, the index of refraction value that is close to this number is diamond's index of refraction.
Therefore, the correct option is A: the material is diamond.
Vertical columns on the periodic table are called
Alkali metals alkaline earth metals and halogens and noble gases. I’m pretty sure
Answer: Alkali metals alkaline earth metals and halogens and noble gases. I’m pretty sure
A driver driving along a highway at a steady 45 mph (66 ft/sec) sees an accident ahead and slams on the brakes. What constant deceleration is required to stop the car in 242 ft? To find out, carry out the following steps. (1) Solve the following initial value problem. StartFraction d squared s Over dt squared EndFraction equals negative k (k constant), with StartFraction ds Over dt EndFraction equals66 and sequals0 when tequals0 (2) Find the value of t that makes StartFraction ds Over dt EndFraction equals0. (The answer will involve k.) (3) Find the value of k that makes sequals242 for the value of t found in the step (2).
Answer:
9 ft/s²
Explanation:
1)
d²s/dt² = -k
Integrate once:
ds/dt = -kt + C
At t=0, ds/dt = 66:
66 = -k(0) + C
C = 66
ds/dt = -kt + 66
Integrate again:
s = -½ kt² + 66t + D
At t=0, s = 0:
0 = -½ k (0)² + 66 (0) + D
D = 0
s = -½ kt² + 66t
2)
Setting ds/dt = 0:
0 = -kt + 66
t = 66/k
3)
Setting s = 242:
242 = -½ kt² + 66t
242 = -½ k (66/k)² + 66 (66/k)
242 = -2178/k + 4356/k
242 = 2178/k
k = 9
The driver must decelerate at 9 ft/s².
What do electric forces between charges depend on
Answer:
On the magnitude of the charges, on their separation and on the sign of the charges
Explanation:
The magnitude of the electric force between two charges is given by
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where
k is the Coulomb's constant
q1, q2 are the magnitudes of the two charges
r is the separation between the charges
From the formula, we see that the magnitude of the force depends on the following factors:
- magnitude of the two charges
- separation between the charges
Moreover, the direction of the force depends on the sign of the two charges. In fact:
- if the two charges have same sign, the force is repulsive
- if the two charges have opposite signs, the force is attractive
Fission is the process of creating energy by
The nuclear fission consists of dividing a heavy nucleus into two or more lighter or smaller nuclei, by means of the bombardment with neutrons to make it unstable.
Then, with this division a great release of energy occurs and the emission of two or three neutrons, other particles and gamma rays.
It should be noted that in the process, the emitted neutrons can interact with new fissionable nuclei that will emit new neutrons and so on. Effect better known as chain reaction.
Nuclear fission is the process of splitting heavy atomic nuclei into smaller ones, releasing energy due to the mass difference. It can produce a chain reaction that is critical for nuclear power plants and nuclear weapons.
Explanation:Nuclear fission is the process of creating energy by splitting heavy atomic nuclei into smaller, medium-mass nuclei. This occurs when a neutron collides with a nucleus causing it to split into two isotopes. The mass of the products is less than the mass of the reactants, and the difference in mass is released as a tremendous amount of energy. A notable characteristic of fission is the release of additional neutrons, which can induce further fissions, leading to a chain reaction. This principle is harnessed in both nuclear power plants and nuclear weapons. To sustain a chain reaction, a certain amount, known as the critical mass, is required. The reaction can be represented as: n+AX → FF₁ + FF2 + xn, where FF₁ and FF₂ are the fission fragments, and x is the number of neutrons produced.
What happens to the potential energy of an object when it is falls from a height? A. Its is lost. B. It is converted into another form, mainly thermal energy. C. It is converted into another form, mainly kinetic energy. D. It stays in the object.
Answer:
C. It is converted into another form, mainly kinetic energy
Explanation:
Potential energy is energy available to be used in an object that isn't currently moving. When an object begins moving, potential energy becomes kinetic energy.
Answer:
The answer is: C. It becomes another form, mainly kinetic energy.
Explanation:
Potential energy is that which has a body due to the height at which it is.
For example, a pot placed in a window at a certain height has potential energy.
When a body falls from a certain height, and if we despise friction with the air, what happens is that its potential energy is transformed into kinetic energy.
The answer is: C. It becomes another form, mainly kinetic energy.
The diagram below shows four coastline locations on Earth with respect to the moon at a given time.
In this current position, which coastline(s) are experiencing a daily low tide?
1) Only A
2) Only B
3) Both A and C
4) Both B and D
4)Both B and D.This happens becaus3 at the ceryain time, A experiences a flood tide causing the waters to come near it.And since B and D are the closest coastlines they are affected the most.
Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz and the speed of sound in water is 1.45 x 103 m/s, what is the wavelength of the sonar signal?
0.20 m
0.01 m
5.03 m
0.50 m
Answer:
5.03 m
Explanation:
The wavelength of a wave is given by
[tex]\lambda=\frac{v}{f}[/tex]
where
v is the speed of the wave
f is the frequency of the wave
For the sonar signal in this problem,
[tex]f=288 Hz[/tex]
[tex]v=1.45\cdot 10^3 m/s[/tex]
Substituting into the equation, we find the wavelength:
[tex]\lambda=\frac{1.45\cdot 10^3 m/s}{288 Hz}=5.03 m[/tex]
Taking into account the definition of wavelength, frecuency and propagation speed, the correct answer is the third option: The wavelength of the sonar signal is 5.03 m.
WavelenghtIn first place, wavelength (λ) is one of the parameters used to physically define a wave. This parameter can be defined for any periodic wave, that is, for the type of wave that repeats itself with exactly the same shape every given interval of time.
In a periodic wave the wavelength is the physical distance between two points from which the wave repeats itself. It is expressed in units of length (m).
FrequencyOn the other side, frequency (f) is the number of vibrations that occur in a unit of time, that is, a measure of the number of cycles or repetitions of the wave per unit of time. Its unit is s⁻¹ or hertz (Hz).
Propagation speedFinally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave's disturbance propagates along its displacement.
Relate the wavelength and the frequency inversely proportional using the following equation:
v = f × λ
This caseIn this case, you know:
v= 1.45×10³ m/sf= 288 Hzλ= ?Replacing:
1.45×10³ m/s= 288 Hz× λ
Solving:
λ= 1.45×10³ m/s÷ 288 Hz
λ= 5.03 m
Finally, the correct answer is the third option: The wavelength of the sonar signal is 5.03 m.
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brainly.com/question/2232652?referrer=searchResultsbrainly.com/question/7321084?referrer=searchResultsbrainly.com/question/14946166?referrer=searchResultsplease help on this one?
Answer:
B
Explanation:
E = hf
E = (6.626×10⁻³⁴ Js) (8.0×10¹⁵ 1/s)
E = 5.3×10⁻¹⁸ J
Answer is B.
Answer:
yes answer is B
Explanation:
Mercury length of time for one revolution around the sun
Answer:
► 88 Earth Days
Explanation:
It takes Mercury about 88 Earth days to complete an orbit around the sun. It also takes Mercury 59 Earth days to do one full spin on its axis. The length of one full day on Mercury would take 176 Earth days.
Mordancy.
Final answer:
Mercury's orbital period is 88 Earth days, while its rotation period is 59 days, leading to a 3:2 spin-orbit resonance. A day on Mercury lasts 176 Earth days, and the planet exhibits unique solar movement patterns due to its strange rotation.
Explanation:
Mercury's orbital period, or the length of time for one revolution around the sun, is 88 Earth days. This orbital period is known as a Mercury year. In contrast to its revolution, Mercury's spin or period of rotation is 59 Earth days. This difference in timescales leads to an interesting dynamic where a day on Mercury (defined as the Sun returning to the same position in the sky) lasts 176 Earth days. This is because Mercury has a unique 3:2 spin-orbit resonance, rotating three times on its axis for every two revolutions it completes around the Sun.
Visual studies initially suggested that Mercury had a synchronous rotation with the Sun, akin to how the Moon rotates with Earth, leading to the belief that one side was perpetually hot and the other perpetually cold. However, this was proved incorrect when it was found that Mercury's rotation and orbit are in a stable 2:3 ratio. Mercury's Strange Rotation results in extremely long days relative to the years and unusual solar movement patterns in the sky for hypothetical observers on the surface.
A technician fills a tank with a liquid to a height of 0.20 m. The tank is cylindrical with radius 0.10 m. The mass of the liquid is 1.0 kg. What is the density of the liquid in 160 kg/m3?
160
120
1100
180
50
Answer:
[tex]160 kg/m^3[/tex]
Explanation:
The density of the liquid is given by:
[tex]d=\frac{m}{V}[/tex]
where
m is the mass of the liquid
V is its volume
The mass of the liquid is
m = 1.0 kg
while the volume is the volume of a cylinder with height h=0.20 m and radius r=0.10 m:
[tex]V=\pi r^2 h = \pi (0.10 m)^2 (0.20 m)=6.28\cdot 10^{-3} m^3[/tex]
So, the density is
[tex]d=\frac{1.0 kg}{6.28\cdot 10^{-3} m^3}=159.2 kg/m^3 \sim 160 kg/m^3[/tex]
Examine the lightbulbs in the circuit below. Write a sentence explaining what would happen if lightbulb A burned out. Repeat this for lightbulbs B, C, and D.
If the lightbulb A in the circuit shown in the image burned out, the path for the current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.
If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.
In a series circuit, if one bulb burns out, it interrupts the flow of electricity, causing all other bulbs in the circuit to not light up.
Explanation:Assuming the lightbulbs are in a series circuit, if lightbulb A burned out, the circuit would be interrupted and thus the other bulbs (B, C, and D) would also not light up as there would be no continuous pathway for current to flow. Similarly, if lightbulb B, C, or D burned out, it would act like a break in the circuit and just like the previous scenario, none of the other bulbs will light. The fundamental aspect of a series circuit is that the current is the same through all components, so if one pathway is interrupted (one bulb burns out), the entire circuit is affected.
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A string attached to an oscillator at one end forms 5 nodes (counting the two ends) and produces a frequency of ν = 1.5 kHz. The string is L = 1.2 m long and is under a tension of T = 276 N.
What is the linear density of the string, in kilograms per meter?
Answer:
[tex]3.4\cdot 10^{-4} kg/m[/tex]
Explanation:
The order of the harmonics for standing waves in a string is equal to the number of nodes minus 1, so
n = 5 - 1 = 4
In this case, the frequency of the 4th-harmonic is
[tex]f_4=1.5 kHz = 1500 Hz[/tex]
We also know the relationship between the frequency of the nth-harmonic and the fundamental frequency:
[tex]f_4 = 4 f_1[/tex]
so we find the fundamental frequency:
[tex]f_1 = \frac{f_4}{4}=\frac{1500 Hz}{4}=375 Hz[/tex]
The fundamental frequency is given by
[tex]f_1 = \frac{1}{2L}\sqrt{\frac{T}{\mu}}[/tex]
where
L = 1.2 m is the length of the string
T = 276 N is the tension in the string
[tex]\mu[/tex] is the linear density
Solving the equation for [tex]\mu[/tex], we find
[tex]\mu = \frac{T}{4L^2 f_1^2}=\frac{276 N}{4(1.2 m)^2(375 Hz)^2}=3.4\cdot 10^{-4} kg/m[/tex]
Electrons do not move unless they are attracted to an electromagnet
True or false
The answer is false , because they move without an electromagnetic
Answer: False
Explanation:
please help on this one?
Answer:
B
Explanation:
Judging from the shape of the lens, you already know that the lenses are concave rather than convex. This eliminates C and D. Concave lens produce a smaller and virtual image at any specified distance.
Hope this helped!
Two friends, Joe and Sam, go to the gym together to strength train. They decide to start off with an exercise called flat bench press. Lying flat on a bench with his arms in an extended position, each friend slowly lowers (to his chest) and then raises a barbell back to the starting position. They start off by using a 31.5 kg barbell. Joe is taller than Sam, which means Joe's arms are 70.0 cm long whereas Sam's are 59.0 cm . Calculate the work done by Joe ????Joe when he raises the barbell to finish one repetition. The acceleration due to gravity is 9.81 m/s2 .
Answer:
216.31 (the work done by gravity is -216.31) positive for going up.
Explanation:
We look at this question first by getting the right equation for work.
Which should be... W = F x D.
From this, we can do everything, we need the Force (F) first - the question tells us that Joe is lying on his back and moves his arms upward to raise the barbell. This means that he is countering the force of graving on the object.
What is the formula for the force of gravity on an object near the earth?
Right here --- [tex]F_{grav}[/tex] = mg
m = the mass and...
g = the acceleration due to gravity which is 9.81 m/s2
Before we plug things in though, we need to convert everything to SI units,
the weight is in kg - so we're good to go there, but the length of Joe's arms are in "cm" we need m or meters. Converting 70 cm to m = .7 m.
Now, we just put it all together - (31.5kg)(9.81m/s2)(.7m) = 216.31 J or 216.31 N m.
During convection of air currents,
a. all air rises.
b. cool air sinks.
c. warm air sinks.
d. air is cooled by a heat source.
During convection of air currents, cool air sinks. (b)
Answer:
Cool air sinks
Explanation:
In this type of heat transfer, warm air rises and cool air sinks, making a current. Which is convection
if it takes 4J work to stretch a hooke's law spring 10 cm from its equilibrium length, determine the extra work required to stretch it an additional 10 cm
Answer:
12 J
Explanation:
The amount of energy stored in a spring stretched by a distance x is:
E = 1/2 k x², where k is the stiffness of the spring.
So the spring has 4J of energy when it is stretched 10 cm:
4 J = 1/2 k (0.10 m)²
k = 800 N/m
When the stretched to 20 cm, the amount of energy is:
E = 1/2 (800 N/m) (0.20 m)²
E = 16 J
So it takes an additional 12 J to stretch the spring an additional 10 cm.