Enter the slope-intercept equation of the line shown below.

The coordinates of the vertices of the triangle are A ( 2 , 2 ) , B ( 6 , 2 ) and C ( 2 , -1 )

A triangle is a plane figure or polygon with three sides and three angles.

A Triangle has three vertices and the sum of the interior angles add up to 180°

Let the Triangle be ΔABC , such that

∠A + ∠B + ∠C = 180°

The area of the triangle = ( 1/2 ) x Length x Base

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

if a² + b² = c² , it is a right triangle

if a² + b² < c² , it is an obtuse triangle

if a² + b² > c² , it is an acute triangle

Given data ,

Let the triangle be represented as ΔABC

Now , the coordinates of the triangle are

A ( 2 , 2 ) , B ( 6 , 2 ) and C ( 2 , -1 )

And , length of AB is given by the distance formula .

Distance D = √ ( x₂ - x₁ )² + ( y₂ - y₁ )²

AB = √ ( 16 + 0 ) = 4 units

BC = √ ( 16 + 9 ) = 5 units

Hence , the lengths of AB and BC are 4 and 5 units respectively

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marathon = 26.2

hill is at least 10

26.2-10=16.2

X=  miles left

X<=16.2

The correct answer is: B. 10111

To convert the number [tex]\(212_{\text{three}}\)[/tex] to base-two (binary) form, we need to first convert it to base-ten and then convert the base-ten number to base-two.

[tex]\(212_{\text{three}}\)[/tex] in base-ten:

[tex]\[ 212_{\text{three}} = 2 \cdot 3^2 + 1 \cdot 3^1 + 2 \cdot 3^0 = 18 + 3 + 2 = 23_{10} \][/tex]

Now, we convert [tex]\(23_{10}\)[/tex] to base-two:

[tex]\[ 23_{10} = 16 + 4 + 2 + 1 = 2^4 + 2^2 + 2^1 + 2^0 = 10111_{2} \][/tex]

Final answer:

The number 212 in base three (212three) converts to 17 in decimal, which is represented as 10001 in binary notation (base-two).

Explanation:

The number 212 in base three (2123) needs to be converted into base-two form (binary). Converting from base three to base two requires understanding each digit's place value in base three and then converting that to binary. Starting from the rightmost digit to the left, we have:

So, we have:

2123 = (1 × 32) + (2 × 31) + (2 × 30)

2123 = (1 × 9) + (2 × 3) + (2 × 1)

2123 = 9 + 6 + 2 = 17 in decimal.

Now we need to find the binary representation of 17:

So, the binary equivalent is 1(24)0(23)0(22)0(21)1(20), which is 100012.

The solution is, the growth factor b is, 1.02

In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.

Using the formula:

P = P0(1+r)^t

where

P0 is the initial population

r is the rate in decimal

b = 1+r is the growth factor

t is the time in years.

As per the statement:

the bear population increases at a rate of 2% each year there are 1573 bears this year,

⇒P0 = 1573,

r = 2% = 0.02

then;

solving using the formula,

we get,

⇒ b = 1.02

Therefore, the growth factor b is, 1.02.

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Answer:

The battery was charged at a rate of 2.2 % per minute.

It took 35 minutes to fully charge the battery

Step-by-step explanation:

Initial amount of charge = 23%

Charge after 30 minutes = 89%

Percentage of charge gained in 30 minutes = 89-23

                                                                         = 66 %

Charging speed of battery = [tex]\frac{percentage\hspace{3}of\hspace{3}charge\hspace{3}gained}{time\hspace{3}taken\hspace{3}in\hspace{3}minutes}[/tex]

= [tex]\frac{66}{30}[/tex]

= 2.2 % per minute

2.2% charge takes 1 minutes

1% charge takes [tex]\frac{1}{2.2}[/tex] minutes

Initially it was 23% charged so it needs 77% more charge to be fully charged.

So, 77% charge takes [tex]\frac{1}{2.2}*77[/tex] minutes    

                         =  [tex]\frac{100}{2.2}[/tex] minutes

                         = 35 minutes

To answer this problem, we use the binomial distribution formula for probability:

P (x) = [n! / (n-x)! x!] p^x q^(n-x)

Where,

n = the total number of test questions = 10

x = the total number of test questions to pass =   >6

p = probability of success = 0.5

q = probability of failure = 0.5

Given the formula, let us calculate for the probabilities that the student will get at least 6 correct questions by guessing.

P (6) = [10! / (4)! 6!] (0.5)^6 0.5^(4) = 0.205078

P (7) = [10! / (3)! 7!] (0.5)^7 0.5^(3) = 0.117188

P (8) = [10! / (2)! 8!] (0.5)^8 0.5^(2) = 0.043945

P (9) = [10! / (1)! 9!] (0.5)^9 0.5^(1) = 0.009766

P (10) = [10! / (0)! 10!] (0.5)^10 0.5^(0) = 0.000977

Total Probability = 0.376953 = 0.38 = 38%

There is a 38% chance the student will pass.

Answer:

[tex](-2,-2)[/tex].

Step-by-step explanation:

Let us assume that coordinates of other endpoint are [tex](x_1,y_1)[/tex]

We have been given that the midpoint of a segment is (4,3) and one endpoint is (10,8). We are asked to find the coordinates of the other endpoint.  

We will use midpoint formula to solve our given problem.

[tex]x\text{-coordinate of midpoint}=\frac{x_1+x_2}{2}[/tex]

[tex]y\text{-coordinate of midpoint}=\frac{y_1+y_2}{2}[/tex]

Upon using our given information, we will get:

[tex]4=\frac{x_1+10}{2}[/tex]

[tex]4\cdot 2=\frac{x_1+10}{2}\cdot 2[/tex]

[tex]8=x_1+10[/tex]

[tex]8-10=x_1+10-10[/tex]

[tex]x_1=-2[/tex]

Similarly, we will find y-coordinate.

[tex]3=\frac{y_1+8}{2}[/tex]

[tex]3\cdot 2=\frac{y_1+8}{2}\cdot 2[/tex]

[tex]6=y_1+8[/tex]

[tex]6-8=y_1+8-8[/tex]

[tex]y_1=-2[/tex]

Therefore, the coordinates of other endpoint would be [tex](-2,-2)[/tex].

To solve this problem, we must assume that the man undergoes constant acceleration as he goes down the river (therefore no other forces must act on him except gravity). Therefore we can use the formula below to calculate for the duration of his fall:

y = y0 + v0 t + 0.5 a t^2

where y is the distance and y0 = 0 since we set the reference point at the bridge, v0 is the initial velocity and is also equal to v0 = 0 since the man started from rest, therefore the equation becomes:

y = 0 + 0 t + 0.5 a t^2

y = 0.5 a t^2

Rewriting in terms of t:

t^2 = 2 y / a

t = sqrt (2y / a)

a is acceleration due to gravity = 9.8 m/s^2

t = sqrt [2 * 23 / 9.8]

t = 2.17 s

Therefore the jump last only about 2.17 seconds.

The digit 2 in the number 258,364 stands for two hundred thousand, occupying the hundred thousands place in the place value system.

The value of the 2 in the number 258,364 represents two hundred thousand. In place value terms, this means the 2 is in the hundred thousands place. To understand this concept clearer, consider the alignment of digits in each place value when written in a column:

2 is in the hundred thousands place (200,000)

5 is in the ten thousands place (50,000)

8 is in the thousands place (8,000)

3 is in the hundreds place (300)

6 is in the tens place (60)

4 is in the ones place (4)

Therefore, the digit 2 represents 200,000.

Answer:

In the number 258,364, the 2 is in the hundred thousand's place. So, its place value is 2 * 100,000 = 200,000.

Explanation:

In the number 258,364, each digit's place value is determined by its position relative to the decimal point. The 2 is in the hundred thousand's place, representing 200,000. In whole numbers, the place values increase from right to left, with each place being 10 times the value of the place to its right. So, the hundred thousand's place has a value of 100,000. Thus, the digit 2 in this position contributes 200,000 to the total value of the number 258,364, indicating that there are 200,000 hundred thousands in it.

Question:

What is the place value of the 2 in 258,364?

This question involves the concept of binomial probability in statistics. The scenarios involve calculating the probability of a certain number of successes (cashew preference) among a set number of trials (12 adults). It's recommended to use a calculator or software tool to perform the calculations.

The subject of the query is known as binomial probability which is part of statistics in mathematics. Here, we need to find the probability of 'success' (in this case, the preference of cashews) exactly a set number of times when conducting a set number of trials (12 adults).

It's also important to note, the results in these examples would be more accurate if you use a calculator or software like Excel to handle the computations.

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The probability of exactly 3 cashews in a random sample of 12 adults is approximately 19.4%.

The probability of at least 4 cashews is approximately 15.0%.

The probability of at most 2 cashews is approximately 72.0%.

These probabilities were calculated using the binomial probability formula and considering the complementary event for cases with "at least" or "at most" conditions. Technology like calculators or statistical software can be helpful in performing these calculations efficiently.

Determining the Probability of Nut Preference in a Random Sample

In this scenario, we're analyzing the probability of specific outcomes when randomly selecting 12 adults and inquiring about their favorite nut, knowing that 43% prefer cashews. Here's a breakdown of the requested probabilities:

(a) Exactly Three Cashew Preferences:

Imagine having 12 slots to fill with "cashew" or "other." We need 3 "cashew" slots and 9 "other" slots. Using the binomial probability formula, the probability of this specific arrangement is:

P(3 cashews in 12 trials) = (12 choose 3) * (0.43)^3 * (0.57)^9 ≈ 0.194

(b) At Least Four Cashew Preferences:

This includes scenarios with 4, 5, 6, 7, 8, 9, 10, 11, or all 12 adults preferring cashews. We can calculate the probability for each case and sum them up, but a simpler approach is to find the probability of the opposite event (fewer than 4 cashews) and subtract it from 1:

P(at least 4 cashews) = 1 - P(fewer than 4 cashews)

P(at least 4 cashews) ≈ 1 - (0.194 + 0.237 + 0.184 + 0.115 + 0.063 + 0.034 + 0.015 + 0.006 + 0.002) ≈ 0.150

(c) At Most Two Cashew Preferences:

This includes scenarios with 0, 1, or 2 adults preferring cashews. Similar to (b), we can calculate the probability for each case and sum them up:

P(at most 2 cashews) = P(0 cashews) + P(1 cashew) + P(2 cashews)

P(at most 2 cashews) ≈ 0.237 + 0.299 + 0.184 ≈ 0.720

In standard fantasy football, each team incorporates a variety of positions including a Quarterback, Running Backs, Wide Receivers, a Tight End, a Flex, Defense/Special Teams, a Kicker and bench spots.

In standard fantasy football, each team is composed of a variety of positions: 1 Quarterback (QB), 2 Running Backs (RB), 2 Wide Receivers (WR), 1 Tight End (TE), 1 Flex (which can be a RB, WR, or TE), 1 Defense/Special Teams (DST), and 1 Kicker (K). In most cases, you also have bench spots for subs or injured players, usually 6-7. These numbers can vary depending on the rules of your fantasy league.

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Final answer:

If one root of a quadratic equation with rational coefficients is rational, the other root must be rational too because the sum and product of the roots are related to the coefficients, which are also rational.

Explanation:

To prove that if one solution for a quadratic equation of the form x^2 + bx + c = 0 is rational, then the other solution is also rational, we can use the quadratic formula and properties of rational numbers. If the quadratic equation has rational coefficients and one rational solution, then the sum and product of the roots must also be rational. This is because a quadratic equation with roots r and s can be factored as (x - r)(x - s) = 0, which expands to x^2 - (r + s)x + rs = 0. Matching coefficients, we see that - (r + s) = b and rs = c. Since b and c are rational, r + s and rs must be rational as well.

Given that we have one rational root, let's say r, the sum of the roots r + s is rational, so s must also be rational because the difference of two rational numbers is rational. Hence, if one root of a quadratic equation with rational coefficients is rational, the other root must be rational as well.

Final answer:

The trapezoid forms a right-angled triangle with one additional rectangle. Its area is found to be 48m^2, and its approximate perimeter is 36.944m, by adding the lengths of all its sides together.

Explanation:

To find the perimeter and area of a trapezoid with two right angles and bases of 16m and 8m, we must first visualize the trapezoid. This trapezoid appears like a right-angled triangle with an additional rectangle attached to its hypotenuse.

We are given the hypotenuse of the altitude's right triangle is 4√5m, thanks to Pythagoras' theorem, we can find the two legs (which are the altitude h and the difference in bases). Let's call the altitude h and the difference in bases 'd'. Now, we know that the length of the longer leg of the right triangle is 16m - 8m = 8m.

Using the Pythagorean theorem where hypotenuse2 = altitude2 + difference in bases2, we have (4√5)2 = h2 + 82. Solving for 'h', we have h = √(80 - 64) = √16 = 4m. The area of a trapezoid is given by the formula A = (1/2) × (sum of the bases) × (height), which in this case is A = (1/2) × (16m + 8m) × 4m = 48m2.

For the perimeter, it can be calculated by adding the lengths of all sides. So, perimeter = 16m + 8m + 4m + 4√5m = 28m + 4√5m. To find the approximate value of 4√5m, we can calculate 4 × 2.236 (since √5 = 2.236), which gives us approximately 8.944m. Adding this to 28m gives us a perimeter of approximately 36.944m.

The mathematics problem set with cookies deals with basic addition: if you have 1 cookie and you take another from a friend, you have a sum of 2 cookies.

The subject here is basic arithmetic, a branch of mathematics.

If you start with 1 cookie (your own), and then you take || 'steal' || another cookie from your friend, you are basically adding that 1 cookie to the 1 cookie you already have. So, 1 cookie (yours) + 1 cookie (your friend's) = 2 cookies. Hence, you would have 2 cookies.

Remember, in real life, it's not nice to steal. This is just a math problem to help you understand the concept of addition.

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Answer:            ≈ 75,779

Step-by-step explanation:

area of a circle = pi r^2

radius = 18

 so R62 = 18^2 = 324

 since you want the answer in pi it would be 324PI

 so the answer is 324

B is (-3,2) E is (4,-2)

4-(-3) = 4+3 =47

-2 -2 = -4

7^2 = 49

-4^2 = 16

Sqrt( 49+16)

Sqrt(65) = 8.062

 Round off to 8

the value of a is

[tex]\( a = \frac{9845}{x - 10} \)[/tex].

To find a, we can use polynomial long division or synthetic division to divide [tex]\( x^5 - 105 \)[/tex] by [tex]\( x - 10 \)[/tex]. The remainder should be zero if [tex]\( x - 10 \)[/tex] is a factor of [tex]\( x^5 - 105 \)[/tex].

Let's perform polynomial long division:

         ____________________________

x - 10  |  x^5 + 0x^4 + 0x^3 + 0x^2 + 0x - 105

           - (x^5 - 10x^4)

           ____________________________

                       10x^4 + 0x^3 + 0x^2 + 0x - 105

                       - (10x^4 - 100x^3)

                       ____________________________

                                    100x^3 + 0x^2 + 0x - 105

                                    - (100x^3 - 1000x^2)

                                    ___________________________

                                                 1000x^2 + 0x - 105

                                                 - (1000x^2 - 10000x)

                                                 ___________________________

                                                              995x - 105

                                                              - (995x - 9950)

                                                              ___________________________

                                                                          9845

```

Since the remainder is a constant term, it's clear that [tex]\( x - 10 \)[/tex] is a factor of [tex]\( x^5 - 105 \)[/tex]. So, [tex]\( a = \frac{9845}{x - 10} \)[/tex].

Therefore, [tex]\( a = \frac{9845}{x - 10} \)[/tex].