Mathematics College

Erika worked 14 hours last week and 20 hours this week. If she earns $9 per hour, how much did she earn during these two weeks? 4 of 60

Answers

Answer 1

309 Dollars were earned by Erika for both weeks

Answer 2

we know that

Erika earns [tex]\$9[/tex] per hour

By proportion

Find how much she earn during the total hours of two weeks

The total hours of two weeks is equal to

[tex]14+20=34\ hours[/tex]

[tex]\frac{9}{1} \frac{\$}{hour} =\frac{x}{34} \frac{\$}{hours} \\ \\x=34*9 \\ \\x=\$306[/tex]

therefore

the answer is

[tex]\$306[/tex]

Related Questions

Can someone please help me solve this triangle problem, picture is shown.

Answers

(4t + 4t + 4t) (addition form)

3(4t) (multiplication form)

these are two forms you can use to get your answer

answer: 12t

hope this helps

perimeter = 4t + 4t + 4t

and

perimeter = 4t * 3

6x2=(3×2)×___=___

6×4=2×(6×___)=___

2×(6×4)=____×8=____

Answers

Let me try.

6×2 = (3×2)×2 = 12

6×4 = 2×(6×2) = 24

2×(6×4) = 6×8 = 48

a local charity held a crafts fair selling donated,handmade items. Total proceeds from the sale were $1,875. A total of 95 items were sold,some at $15 each and the rest at $25 each. Let x be the number of $15 items and y the number of $25 items. How many items sold at $25?

Answers

15x+25y=1875
Let
y=95-x
15x+25 (95-x)=1875
Solve for x
15x+2375-25x=1875
15x-25x=1875-2375
-10x=-500
X=500/10
X=50 the number of $15 items

Y=95-50=45 the number of $25 items

Answer:

It’s 30

Step-by-step explanation:

Information about movie ticket sales was printed in a movie magazine. in a sample of of fifty pg-rated movies, 36% had ticket sales in excess of $30,000,000. in a sample of thirty-five r-rated movies, 23% grossed over $30,000,000. suppose that this data is used to test the claim that the proportion of movies with ticket sales in excess of $30,000,000 is the same for pg movies as it is for r-rated movies. what would be the test statistic for this test? z = 1.29 z = 2.07 z = 4.005 z = 2.58

Answers

Let us say that the samples for fifty movies is 1 and samples for thirty five is 2. To solve the test statistic z, we can use the formula:

z = (p1 – p2) / sqrt [p (1 – p) (1 / n1 + 1 / n2)]

Where,

p1 = is the proportion for sample 1 = 0.36

p2 = is the proportion for sample 2 = 0.23

n1 = number of samples = 50

n2 = number of samples = 35

while p can be calculated using the formula:

p = [p1 * n1 / (n1 + n2)] + [p2 * n2 / (n1 + n2)]

p = [0.36 * 50 / (50 + 35)] + [0.23 * 35 / (50 + 35)]

p = 0.211764705 + 0.094705882

p = 0.306470587

Going back for the calculation of z:

z = (0.36 – 0.23) / sqrt [0.306 (1 – 0.306) (1 / 50 + 1 / 35)]

z = 1.279

Therefore the nearest answer is:

z = 1.29

A geometry class has a total of 34 students. The number of males is 14 more than the number of females. How many males and how many females are in the class?

Answers

m=14+f, m+f=34. Solve for the equations simultaneously.

one way is to substitute teh first into the second to get, 14+2f=34, or 7+f=17, or f=10. Since f is 10 and m+f=34, m=34-10=24.

Good luck!

Write an equation for the function. Tells what each variable you use represents. A plant's height is 1.6 times its age in months.

Answers

Y=1.6x+b (B can be anything or you won't need to add it into the equation)

This is function can be defined as a linear equation, in the standard form of y = mx + b. X is the independent variable, y is the dependent variable, m is the slope (rate of change/growth), and b is the constant (starting point).

Since the growth rate of height for the plant is 1.6 times the independent variable and there is no starting point (so assume 0), our equation should look like this:

y = 1.6x

The plant's height is y and its age in months is x.

Hope my answer helped clear things up a bit.

A taxi cab charges $0.55 per mile in addition to a $1.75 flat rate fee. Susie has $10 to spend on a taxi cab ride. The taxi driver will not give anyone a ride unless they are going somewhere that is more than 2 miles away. Model Susie’s situation with a system of inequalities.

Answers

The taxi driver doesn't give anyone a ride unless it's 2 miles away, as such you need to add at least $0.55x2 in addition to the $1.75 at the start
1.75+(0.55x2)=2.85
As Susie only has 10 dollars to spend, she can't exceed that. So Susie must spend more than $2.85(minimum from the taxi) and less than $10(her money)
so,
$2.85<Susie<$10

You have a 20-foot ladder that you are using as you paint your house. You place the ladder so that it forms an angle of 30 at the point of contact between the ladder and the ground. How high will the top of the ladder be above the ground

Answers

First draw out the picture it will help. Then you can see that you want the opposite segment of the angle, which leads you to use a sine. So you have 20sin30 or 20(1/2) or 10ft.

Answer:

The Ladder is 10 ft high.

Step-by-step explanation

According to the question we have a 20 ft ladder inclined against a wall at a 30° angle, and are asked to find how high the top of the ladder is from the ground. I have added a visual representation to help you better understand the situation. As you can see we need to solve for x. Since we are given one angle and the hypotenuse we can solve for x using the SIN operator.

[tex]sin(a) = \frac{opposite}{hypotenuse}[/tex]

Since we have the angle (a) and the hypotenuse we can just plug the information into the sin equation and solve for the opposite (x).

[tex]sin(30) = \frac{x}{20ft}[/tex]

[tex]sin(30)*20ft = x[/tex]

[tex]0.5*20ft = x[/tex]

[tex]10ft = x[/tex]

So now we can see that the height of the top of the ladder to the ground is 10 ft

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

find two consecutive even integers such that the smaller added to five times the larger give you a sum of 46.

Answers

First consecutive integer: n
Second consecutive integer: n + 2 (next even integer)
n + 5(n + 2) = 46
n + 5n + 10 = 46

6n + 10 = 46
6n = 36
n = 6
n + 2 = 8
Your answer is 6 and 8

A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in 30 minutes. How much faster does she have to work to grade the remaining papers in the allotted time?

Answers

At first, she was grading papers at 10 papers per hour. To meet her time limit, she would have to begin grading them at 12 papers per hour, or 20% faster than her previous rate

so, she has 3hrs to grade all papers, for 35 students.. alrite.

the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6

now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.

now if we take 1/6 as the 100%, what is 1/5 in percentage then?

[tex]\bf \begin{array}{ccllll} rate&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \frac{1}{6}&100\\\\ \frac{1}{5}&x \end{array}\implies \cfrac{\frac{1}{6}}{\frac{1}{5}}=\cfrac{100}{x}\implies \cfrac{1}{6}\cdot \cfrac{5}{1}=\cfrac{100}{x}\implies \cfrac{5}{6}=\cfrac{100}{x} \\\\\\ x=\cfrac{6\cdot 100}{5}\implies x=120[/tex]

so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.

105,159 rounded to the nearest ten thousand

Answers

110,000 is your answer

hope this helps

110,000. it is that number because 5 is over 0,1,2,3,and 4 why end in 4 because to make it fair that have to make both 5numbera and 0 counts as a number so 5,6,7,8,and 9 are the other 5 why not 10 because 10 is the 0 in the other line so 5 is over the count and that means change the 5 to 0 and all the numbers following it to 0 and in the ten thousands place change 0 to 1. that was a lot to type.

EASY 5 POINTS!! Which expression gives the correct volume of the figure?

Answers

The correct answer is:
(3×2×1)+(3×1×1)

Answer:

(3×2×1)+(3×1×1)

Step-by-step explanation:

AS you can se ein the figure, the figure is not a solid full rectangula prism, it is made out of two prisms the first one is the 3x2x1 rectangular prism, and the second is the 3x1x1 square prism, so by adding the volume of those two you can figure out the volume of the whole figure that is why the answer to the problem is (3×2×1)+(3×1×1)

Pediatric asthma survey, n = 50. suppose that asthma affects 1 in 20 children in a population. you take an srs of 50 children from this population. can the normal approximation to the binomial be applied under these conditions? if not, what probability model can be used to describe the sampling variability of the number of asthmatics?

Answers

In this situation,
n=50, p=1/20, q=(1-p)=19/20, and npq=19/8=2.4

We would like np and npq to be a large number, at least greater than 10.
The normal approximation can always be applied, but the result will be very approximate, depending on the values of np and npq.

Situations are favourable for the normal approximation when p is around 0.5, say between 0.3 and 0.7, and n>30.

"Normal approximation" is using normal probability distribution to approximate the binomial distribution, when n is large (greater than 70) or exceeds the capacity of most hand-held calculators. The binomial distribution can be used if the following conditions are met:
1. Bernoulli trials, i.e. exactly two possible outcomes.2. Number of trials is known before and constant throughout the experiment, i.e. independent of outcomes.3. All trials are independent of each other.4. Probability of success is known, and remain constant throughout trials.
If all criteria are satisfied, we can model with binomial distribution, where the probability of x successes out of N trials each with probability of success p is given byP(x)=C(N,x)(p^x)(1-p)^(N-x)and,C(N,x) is number of combinations of selecting x objects out of N.
The mean is np, and variance is npq.

For the given situation, np=2.5, npq=2.375, so standard deviation=sqrt(2.375)=1.54.

n=50, p=1/20, q=(1-p)=19/20, and npq=19/eight=2.4

We would like np and npq to be a huge range, at least extra than 10.

The ordinary approximation can usually be carried out, but the result might be very approximate, relying on the values of np and npq.

conditions are favorable for the normal approximation when p is around 0.5, say among 0.3 and 0.7, and n>30.

For the given scenario, np=2.five, npq=2.375, so widespread deviation=sqrt(2.375)=1.54.

underneath what conditions binomial distribution tends to be everyday distribution?

the theory states that any distribution becomes normally allotted whilst the variety of variables is satisfactorily massive. for example, the binomial distribution has a tendency to alternate into the regular distribution with suggest and variance.

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Which expression is equivalent to (7^3)−2
A- 1 over 7 times 7 times 7 times 7 times 7 times 7
B- 7
C- 1 over 7
D-negative 1 over 7 times 7 times 7 times 7 times 7 times 7

Answers

[tex]\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\ a^{-{ n}} \implies \cfrac{1}{a^{ n}} \qquad \qquad \cfrac{1}{a^{ n}}\implies a^{-{ n}} \qquad \qquad a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}} \\\\ -------------------------------\\\\ (7^3)^{-2}\implies 7^{-2\cdot 3}\implies 7^{-6}\implies \cfrac{1}{7^6}\implies \cfrac{1}{7\cdot 7\cdot 7\cdot 7\cdot 7\cdot 7}[/tex]

What is the value of -2 (7-15) over 4

Answers

The answer to the question is: 4

A ship traveled for 4 hours heading east and for 3 hours heading north. If the total distance traveled was 149 miles, and the ship traveled 3 miles per hour faster heading north, at what speed was the ship traveling east?

Answers

just like the previous one

if the ship travelled a total of 149 miles, then let's say it travelled East "d" miles and thus it travelled North the slack of 149 and "d", thus " 149 - d".

now, if the rate travelling East is say "r", then the faster rate going North is " r + 3".

[tex]\bf \begin{array}{lccclll} &distance&rate&time\\ &-----&-----&-----\\ East&d&r&4\\ North&149-d&r+3&3 \end{array} \\\\\\ \begin{cases} \boxed{d}=4r\\ 149-d=(r+3)3\\ ----------\\ 149-\boxed{4r}=3(r+3) \end{cases}[/tex]

solve for "r".

James deposits $600 in an account that pays 4% simple interest, and $1200 in a second account which has a higher interest rate but is more risky. What interest rate must he get on the second account in order to earn at least $132 in interest for the year?

Answers

1) $600 deposited at 4% simple interest for one year generates:

$600 * 4% = $600 * 0040 = $24

2) If he wants to earn $132 in interest for the year, he yet needs to generate $132 - $24 = $108 (additional)

3) The interest rate to generate $108 on a deposit of $1200 in a year, at simple interest is:

$1200 * (r) = $108 => r = 108 / 1200 = 0.09 = 9/100 = 9%

Answer: 9%

What is the value of k in the equation below? 5k - 2k = 12? 1 1/5, 1 5/7, 3, 4

Answers

Hi there!

5k - 2k = 12
Solve for K
3k = 12
Divide both sides by 3
3k/3 = 12/3
k = 4
The correct answer is : 4

I hope that helps!
Brainliest answer :)

Answer:4

Step-by-step explanation:

value for X^2 left for 95% confidence interval when n=18

Answers

Given that n = 18, then the degree of freedom is n - 1 = 17.

From the table of Chi Square [tex](X^2)[/tex]

The value of [tex](X^2)[/tex] to the left for 95% confidence interval given a degree of freedom of 17 is 8.672

The graph of a limacon curve is given. Without using your graphing calculator, determine which equation is correct for the graph.[-5, 5] by [-5, 5] (1 point)

Answers

The general form for this curve is:
[tex]r = Acos \theta + B[/tex]
Now find A,B given 2 points:
[tex]r(0) = 5, r(\pi) = 1[/tex]
[tex]A +B = 5 \\ \\ -A+B = 1[/tex]
Solving this system yields:
[tex]A = 2, B = 3 \\ \\ r = 2cos \theta + 3[/tex]

Answer:

r = 2 - 3 cos θ

Step-by-step explanation:

This is the best I could come up with.

What is the sum of the arithmetic series? ∑[i=1,15,Fn=5i-1]

Answers

[tex]\bf \sum\limits_{i=1}^{15}\ 5i-1\implies 5\sum\limits_{i=1}^{15}\ i-\sum\limits_{i=1}^{15}\ 1\implies 5\left[ \cfrac{15(15+1)}{2} \right]-(15\cdot 1) \\\\\\ 5\cdot (15\cdot 8)-15\implies 585[/tex]

Each figure is filled with unit cubes. Drag 22 figures whose combined volume is equal to 45 unit cubes.

Answers

To solve this problem, what we have to do first is to calculate for the volumes of each figure. Let us start from the figure on the left going to the right. Let us call the figures 1 to 4. Formula for volume is:

V = l * w * h

Figure 1:

V1 = 4 * 3 * 1 = 12 unit cubes

Figure 2:

V2 = 3 * 2 * 3 = 18 unit cubes

Figure 3:

V3 = 2 * 2 * 4 = 16 unit cubes

Figure 4:

V4 = 3 * 3 * 3 = 27 unit cubes

The two combinations that would result in 45 total unit cubes would be:

V = V2 + V4 = 18 unit cubes + 27 unit cubes = 45 unit cubes

So the answers are:

Figure 2 and Figure 4

100 meter long Christmas train needs 30 seconds to cross a 400nmetrr long bridge assuming the train goes at a steady speed how fast is it

Answers

Since it's 100m long, to cross the front needs to go 500m. 500/30= (16+2/3)meters per second

The coordinates of △ABC△ABC are A(12,8), B(10,18), C(4,16)A(12,8), B(10,18), C(4,16). After a dilation, the coordinates are A'(6,4), B'(5,9), C'(2,8)A′(6,4), B′(5,9), C′(2,8). Find the scale factor.

Answers

The scale factor is 1/2 because when you multiply the x and y-coordinates of each point by 1/2, you will get the coordinates of the new dilated points.

Answer: [tex]\dfrac{1}{2}[/tex]

Step-by-step explanation:

The dilation is a transformation which makes similar shapes.

We know that In two similar geometric figures, the ratio of their corresponding corresponding x-coordinate is known as the scale factor.

For the given situation, the x-coordinate of A in pre-image = 12

The x-coordinate of A' in image = 6

Then , the scale factor for the dilation is given by :-

[tex]k=\dfrac{6}{12}=\dfrac{1}{2}[/tex]

Hence, the scale factor = [tex]\dfrac{1}{2}[/tex]

simplify the expression below. show your work. -(-7y+12)

Answers

[tex]-(-7y+12) = 7y -12[/tex]

5 times the difference of 29 and a number is 215. Which equation below can be used to find the unknown number?

Answers

Is it multiple choice? If not I would say 215=5(x)-29

Answer:

The required equation is [tex]5(29-n)=215[/tex]

Step-by-step explanation:

Given : 5 times the difference of 29 and a number is 215.

To find : Which equation can be used to find the unknown number?

Solution :

Let the number be 'n'.

The difference of 29 and a number i.e. [tex]29-n[/tex]

5 times the difference of 29 and a number i.e. [tex]5(29-n)[/tex]

5 times the difference of 29 and a number is 215 i.e. [tex]5(29-n)=215[/tex]

Therefore, the required equation is [tex]5(29-n)=215[/tex]

Can the polynomial below be factored into a perfect square? If not, select the answer that best describes why not.
64x^2+49x+8
A.

The x^2 coefficient does not permit the factoring.

B.

The x^2 coefficient does permit the factoring, but the x coefficient does not permit the factoring.

C.

The constant value does not permit the factoring.

D.

The polynomial may be factored into a perfect square.

Answers

Option B;
A suitable x-coefficient for a quadratic function that factors into a perfect square has to be even.

Answer:

Option B is correct.

Step-by-step explanation:

We will work with the formula : [tex](a+b)^{2}[/tex]

= [tex]a^{2}+2ab+b^{2}[/tex]

Given polynomial is :

[tex]64x^{2} +49x+8[/tex]

here a = [tex]\sqrt{64x^{2} } =8x[/tex]

b = [tex]\sqrt{8}= 2\sqrt{2}[/tex]

2ab = [tex]2*8x*2\sqrt{2} =32\sqrt{2}x[/tex]

Now, we can see that the middle term should be [tex]32\sqrt{2} x[/tex] but in the question, it is given 49x

So, option B is true that - The x^2 coefficient does permit the factoring, but the x coefficient does not permit the factoring.

Steve can complete the 100m dash in 10 seconds while Paul can run it in 12 seconds. How does Steve's time compare to Paul's?

Answers

Steve is faster than Paul by 2 seconds after 100m

Which figure has the correct lines of symmetry drawn in?

Answers

The figure which has the correct lines of symmetry drawn is figure D.

What is line of symmetry?

A line of symmetry refers to the line that divides a shape or an object into two equal and symmetrical parts.

The figure given is a five sided shape referred to as a pentagon.

A pentagon has five lines of symmetry.

Therefore, the correct line of symmetry is 5 lines drawn from each angle respectively.

Answers

A. 999 numbers under 1000, so prob of picking one is 999/6296 = 0.1587
B. 6 numbers divisible by 1000, so prob 6/6296 = 0.000953
C. (6296 - 6)/6296 = 1 - 0.000953 = 0.999047

Final answer:

The probability of selecting a number divisible by 1000 from the range of 1 to 6857 is approximately 0.0008763. The probability of selecting a number that is not divisible by 1000 is approximately 0.9991237.

Explanation:

To find the probability of selecting a number divisible by 1000, we need to determine the total number of possible outcomes and the number of favorable outcomes. There are a total of 6857 possible outcomes since the company selects employee numbers ranging from 1 to 6857. For a number to be divisible by 1000, it must end with three zeros, so we need to find how many numbers satisfy this condition between 1 and 6857.

Since 1000 is the smallest number divisible by 1000, we can calculate the number of favorable outcomes by finding the largest integer that satisfies the condition. In this case, it is 6000. Therefore, there are 6 favorable outcomes.

The probability of selecting a number divisible by 1000 is calculated by dividing the number of favorable outcomes by the total number of possible outcomes:

Probability = Favorable outcomes / Total outcomes = 6 / 6857 ≈ 0.0008763.

The probability of selecting a number that is not divisible by 1000 can be calculated as the complement of the probability of selecting a number divisible by 1000:

Probability(not divisible by 1000) = 1 - Probability(divisible by 1000) ≈ 1 - 0.0008763 ≈ 0.9991237.

Learn more about Probability here:

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