find a1 for the geometric series with r=3 and s6=364

if no numbers can repeat then you have

1st digit = 10 numbers

2nd digit = 9 numbers

3rd digit = 8 numbers

 4th digit = 7 numbers

5th digit = 6 numbers

10 * 9 * 8 * 7 *6 =30,240 different combinations

There are 30,240 different ID cards that can be made with 5 digits where no digit can be repeated, calculated as a permutation of 10 choices taken 5 at a time without replacement.

The question asks us to determine how many different ID cards can be made with 5 digits where no digit can be repeated. This is a problem of permutations where the order of the digits matters. We have 10 possible digits (0-9), and we need to choose 5 of them without repetition.

For the first digit, we have 10 choices (0-9). Once we choose the first digit, we have 9 choices left for the second digit (since one digit is already used and can't be repeated). Continuing this pattern, we have 8 choices for the third digit, 7 choices for the fourth digit, and 6 choices for the fifth digit.

The total number of different ID cards is calculated by multiplying these choices:

The calculation is 10 x 9 x 8 x 7 x 6, which equals 30,240 different ID cards.

The probability that the train arrives on time, given that it leaves on time is 0.7

The question asks for the probability that the train arrives on time, given that it leaves on time. This is a conditional probability problem, and we can use the formula for conditional probability, which is P(A|B) = P(A and B)/P(B).

In this case, event A is the train arrives on time, event B is the train leaves on time. We know that P(A and B) = 0.28 (the probability that the train arrives on time and leaves on time) and P(B) = 0.4 (the probability that the train leaves on time).

By substituting these values into the formula, we get  P(A|B) = 0.28/0.4 = 0.7. So, the probability that the train arrives on time, given that it leaves on time is 0.7.

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Answer:

i have the image of the tunnel and here is my work

Part B: x=20 y=20  x=35 y=60  so {60-20}/{35-20}=40/15=2.6

hope this helps

south America = 2.2%

2.2% = 0.022

0.022 = 22/1000 which reduces to 11/500

False,

 the equation should be

x+ (x+2) +(x+4) = 45

The area of the kite will be equal to 14 sq. units

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the Kite in a two-dimensional plane is called the area of the kite.

The area of the kite can be found as follows;

Area    =   [area of XWY]   +     [areaYWZ]

Area XWY  =  1/2  x b  x  h

Area  XWY =   1/2  x  4  x   3   =   6 sq units

Area YWZ   =  1/2   x   b  x  h

Area YWZ   =  1/2   x   4  x  4  =  8 sq units

Hence the area of the kite will be:

Area  =   6  +  8   =   14 sq. units

Therefore the area of the kite will be equal to 14 sq. units

To know more about an area follow

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To receive $525.00 a week, a seamstress being paid $9.55 per pair of pants made would need to make approximately 55 pairs of pants.

Let’s denote the number of pairs of pants that need to be made as x.

The seamstress is paid $9.55 for every pair of pants.

We want to find the number of pairs of pants needed to earn $525.00, so we set up the equation:

[tex]9.55 \times x = 525.00[/tex]

Solve for x:

[tex]x = \frac{525.00}{9.55} \approx 54.97[/tex]

Since we can’t make a fraction of a pair, we round up to the nearest whole number:

The seamstress would need to make 55 pairs of pants (which means a total of 110 pants) to receive $525.00 a week.

x = land carriers = 1800x

y = air carries = 1500y

 as many as means up to that amount so <=150000 and <= 150

so equation is:

1800x + 1500y ≤ 150,000 x + y ≤ 150

The correct system of inequalities for this problem is: 1500x + 1800y ≤ 150,000 and x + y ≤ 150 - representing mail distribution limitations of a center.

In order for the mail distribution center to process the maximum amount of mail (150,000 pieces) with the available resources, the inequalities should be framed as follows:

This mathematical model sets the limitations of the mail distribution process and can be used to predict the optimal allocation of mail to air and land carriers.

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Since it is a parallelogram, NO = PQ

5 x + 12 = 7 x - 8

12 + 8 = 7 x - 5 x

20 = 2 x

x = 20 : 2

x = 10

NO = 5 * 10 + 12 = 50 + 12 = 62

Answer: 62

Hope this helps, have a BLESSED and wonderful day, as well as a safe one! Also, have a merry Christmas!  :-)

-Cutiepatutie

Answer:

180,000.

Step-by-step explanation:

Given  : 18 thousands times 10.

To find : Solve .

Solution : We have given

18 thousands times 10.

According to question :

18 thousand = 18000.

10 Times of 18 thousand .

18000 *10 .

180,000.

Number would be 180,000

Therefore, 180,000.

Final answer:

To find the positive integers less than 12 that are relatively prime to 12, we need to find the positive integers that do not share any common factors with 12 other than 1. The positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

Explanation:

Two positive integers are relatively prime if their greatest common divisor (GCD) is 1. To find the positive integers less than 12 that are relatively prime to 12, we need to find the positive integers that do not share any common factors with 12 other than 1.

The prime factors of 12 are 2 and 3. Therefore, any positive integer less than 12 that is not divisible by 2 or 3 will be relatively prime to 12.

Therefore, the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

The product of 18 and q is expressed as 18q in an algebraic expression, representing the multiplication of 18 by a variable, q. The value of the expression depends on what value q has.

The phrase 'the product of 18 and q' is a mathematical term used in algebra. It represents the multiplication of 18 and a variable 'q'. In algebraic expression, it can be written as 18q, where 18 is the constant multiplicand, and 'q' is the variable multiplier. The value of this product depends on the value of 'q'. For example, if q is 2, the product of 18 and q would be 36.

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Final answer:

To calculate the available farming land, 65% of the total 30 acres is determined, resulting in 19.5 acres available for farming.

Explanation:

To find out how many acres are available for farming, we need to calculate 65% of the total 30 acres of land the farmer owns.

The calculation is as follows:

Therefore, 19.5 acres of the farmer's land can be used for farming.

To find the critical z value for α = 0.08, we first divide α by 2 to get 0.04. This value corresponds to the tail regions in a two-tailed test. We then lookup or calculate the z value associated with a cumulative probability of 0.04, which gives us a z value of approximately 1.75.

The question is about finding the indicated critical z value. In statistics, critical values are used to make decisions about the null hypothesis in hypothesis testing. When α = 0.08, α/2 = 0.04 which refers to the tail regions in a two-tailed test.

First, we find the z value associated with α/2=0.04. This is found by looking at a standard z-table, or using a statistical calculator or a software tool that can calculate the inverse of the standard normal cumulative distribution function. For α/2=0.04, the z value is approximately 1.75.

Therefore, the critical z value (zα/2) is approximately 1.75.

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To sketch the graphs, square the y-values of sin(x) and cos(x) to get f^2(x) and g^2(x), respectively. Then, add the squared y-values of f(x) and g(x) to get f^2(x)+g^2(x). Plot the points obtained for each function and sketch the graphs.

a) To sketch the graph of f^2, we need to square every y-value of the function f(x)=sin(x). This means finding the square of the sine of each angle. For example, f^2(0)=sin^2(0)=0^2=0. By repeating this process for multiple angles, we can plot the points and sketch the graph.

b) Similarly, to sketch the graph of g^2, we need to square every y-value of the function g(x)=cos(x). This means finding the square of the cosine of each angle. For example, g^2(0)=cos^2(0)=1^2=1. By repeating this process for multiple angles, we can plot the points and sketch the graph.

c) To sketch the graph of f^2+g^2, we need to add the squared y-values of f(x) and g(x) at each angle. For example, f^2+g^2(0)=sin^2(0)+cos^2(0)=0^2+1^2=1. By repeating this process for multiple angles, we can plot the points and sketch the graph.

Using a t distribution table you can easily find the t critical value in a very easy way just look for the confidence level which is 95% or the 5% significance level and look for the degrees of freedom which is 28 (just to remind you degrees of freedom is always -1, so if you have 29 – 1 you will get 28 and it is the degrees of freedom), then the t distribution should give you 2.048 for your t critical value. When you use the significance level here you need to subtract the 100% by your confidence level of 95% you will get the 5% then you should divide it to 2, you will get the .025 if it only a two-tailed test you will use the significance level.

D/60 + D/50 = 2D/55 - 1/2

 find common denominator ( 3300)

3300/60 = 55

3300/50 = 66

3300/55=60

so then you get 55D +66D= 60(2D)-1650

121D=120D-1650

D=1650 miles

check

1650/60 =27.5, 1650/50 = 33,  27.5 + 33 = 60.5 hours total

1650/55 = 30, 30 x 2 = 60

60.5-60 = 0.5 longer

 so distance = 1650 miles