The statement about pointwise convergence follows because C is a complete metric space. If fn → f uniformly on S, then |fn(z) − fm(z)| ≤ |fn(z) − f(z)| + |f(z) − fm(z)|, hence {fn} is uniformly Cauchy. Conversely, if {fn} is uniformly Cauchy, it is pointwise Cauchy and therefore converges pointwise to a limit function f. If |fn(z)−fm(z)| ≤ ε for all n,m ≥ N and all z ∈ S, let m → ∞ to show that |fn(z)−f(z)|≤εforn≥N andallz∈S. Thusfn →f uniformlyonS.
2. This is immediate from (2.2.7).
3. We have f′(x) = (2/x3)e−1/x2 for x ̸= 0, and f′(0) = limh→0(1/h)e−1/h2 = 0. Since f(n)(x) is of the form pn(1/x)e−1/x2 for x ̸= 0, where pn is a polynomial, an induction argument shows that f(n)(0) = 0 for all n. If g is analytic on D(0,r) and g = f on (−r,r), then by (2.2.16), g(z) =
List five examples from daily life in which you see periodic motion caused by a spring or cord.
car suspension
guitar string
clips for hanging clothes
keyboards buttons
elevators
The five examples from daily life in which you see periodic motion caused by a spring or cord are car suspension, guitar string, clips for hanging clothes, keyboards buttons and elevators.
What is periodic motion?The motion which repeats itself after a fixed time period is called the periodic motion.
In daily life, every machine or simple machine we use is operated from a mechanism. The mechanism which involves the use of spring or cord for giving motion is elevator. The other examples are car suspension, guitar string, clips for hanging clothes and keyboards button.
Thus, the examples which shows periodic motion are listed above.
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Which statement best describes how today’s scientific community views light?
Light behaves only like waves.
Light behaves only like particles
Light behaves like both waves and particles.
Light behaves like both waves and particles.
The correct answer is C) Light behaves like both waves and particles.
The statement that best describes how today’s scientific community views light is "Light behaves like both waves and particles."
Light comes from the Sun. Light travels at 186 miles per second. The distance between the Sun and the Earth is 93 million miles. So energy travels in waves of light scientists called electromagnetic energy, that is vibrating patterns of electricity and magnetism. It was Isaac Newton that said that light was a particle, but Christian Huygens said that it was a wave. But today’s scientific community views light is that light behaves like both waves and particles.
A student is performing a double-slit experiment to determine the wavelength of a light source. She has measured the distance between dark bands and the distance between the slits and the screen. She still needs to measure:
Question 10 options:
A)
the speed of the light
B)
the width of each slit
C)
the distance between the slits
D)
the angle between the right bisector and the first minima
E)
the distance between the centre of the slits and the first minima
Answer:
lights need elewctricity
Explanation:
She still needs to measure the distance between the slits.
To determine the correct option among all the options, we need to know about fringe width in young's double slits experiment.
What is fringe width in young's double slits experiment?In young's double slits experiment, a fringe pattern is found on the screen. The separation between the consecutive bright and dark spot is known as the fringe width.How can we calculate fringe width?Fringe width can be found from the formula(Wavelength × separation between screen and slits)/separation between the slits.
The above formula also gives a relation between the wavelength and fringe width. I.e. if we know the fringe width, separation between the screen and slits and the separation between the slits, we can determine the wavelength.Thus, we can conclude that she needs the distance between the slits to determine the wavelength of light.
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A student throws a baseball upwards at an angle of 60 degrees to the horizontal. The initial horizontal and vertical components are 12.5 m/s and 21.7 m/s, respectively.
Given data
ball throws upwards at an angle 60°
Horizontal component (Vh) = 12.5 m/s,
Vertical component (Vv) = 21.7 m/s ,
The magnitude of throw/resultant velocity (V) = ?
The resultant velocity /the velocity with which ball is throws is determined by the following equation
V = √[(Vh)² + (Vv)²]
= √[(12.5)² + (21.7)²]
= 25.04 m/s
The resultant velocity or the velocity with which the ball is thrown is 25 m/s
Answer:
d
Explanation:
The acceleration stays the same. Velocity is the one that changes.
How do two objects at different temperatures attain thermal equilibrium?
A.As the two objects touch, thermal energy flows from the colder block to the warmer block until both blocks have the same amount of heat energy and kinetic energy.
B.As the two objects touch, thermal energy flows as heat from surrounding air until particles in both blocks become stationary and reach the same temperature.
C.As the two objects touch, thermal energy flows as heat from the warmer block to the colder block until particles in both blocks move at the same rate and reach the same temperature.
D.As the two objects touch, kinetic energy flows as heat from the warmer block to the colder block until both blocks reach the same temperature and have the same thermal energy.
Answer:
C.As the two objects touch, thermal energy flows as heat from the warmer block to the colder block until particles in both blocks move at the same rate and reach the same temperature.
Explanation:
Heat is the transfer of thermal energy from an object at higher temperature to an object at colder temperature.
The temperature of an object is a measure of how fast the particles in the object move: the higher its temperature, the faster the particles move, the higher the average kinetic energy of the particles in the object. As a result, the particles of the object at higher temperature tend to transfer more energy (called thermal energy) to the particles of the object at colder temperature by colliding with them: this process continues until the particles of the colder object reach the same average kinetic energy as the particles of the warmer object, and this means that the two objects have reached the same temperature.
A motor having a maximum power rating of 8.1 x 104 watts is used to operate an elevator with a weight of 1.8 x 104 newtons. What is the maximum weight this motor can lift at an average speed of 3.0 meters per second?
If the power rating of the motor is 8x10^4 Watts and our equation for Power is:
[tex]Power=\frac{Energy}{time}=\frac{Work}{time}=\frac{Force \times Displacement}{time}\\\\P=Force \times Velocity[/tex]
Note that:
[tex]F=ma=mg[/tex]
where g is the average gravity on Earth which is approximately 9.8 m/s^2.
And so:
[tex]P=F \times V\\P=m \times g \times V\\\\\ m=\frac{P}{gv} \\\\[/tex]
[tex]m=\frac{8.1 \times 10^4 }{9.8 \times 3} =2755.1kg[/tex]
In terms of force:
[tex]F=mg=2755.1kg \times 9.8 \frac{m}{s^2}=27000N[/tex]
The maximum weight of motor that can lifted at the given speed is of 27000 N.
Given data:
The maximum power rating of the motor is, [tex]P = 8.1 \times 10^{4} \;\rm W[/tex].
The weight of elevator is, [tex]W = 1.8 \times 10^{4} \;\rm N[/tex].
The speed of motor is, v = 3.0 m/s.
Since, the power rating of motor is obtained due to the force experienced on the elevator. Then,
[tex]P = F \times v[/tex]
Solving as,
[tex]8.1 \times 10^{4} = F \times 3.0 \\F = 27000 \;\rm N[/tex]
Now, the force experienced on the elevator is due to the weight of motor. Then,
Force (F) = Weight of motor (W')
[tex]27000 = W' \\\\W' = 27000 \;\rm N[/tex]
Thus, we can conclude that the maximum weight of motor that can lifted at the given speed is of 27000 N.
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PLEASE HELP!!!!
1. A motorcycle with a mass of 200 kg can accelerate from 0 to 30 m/s in 3 seconds.
A. Assuming all of the force generated by the engine goes into acceleration of the motorcycle, how much force is the engine producing? Show your work.
B. What would happen if the coefficient of friction between the tire and the pavement increased greatly? Explain what would happen, including whether the acceleration of the motorcycle would stay the same, increase, or decrease, and tell why you think this is.
Answer:
a. 2000 N
b. acceleration of the motorcycle would decrease
Explanation:
a. acceleration = (final speed - initial speed)/time
a = (30 - 0)/3 = 10 m/(s^2)
Force = mass * acceleration
F = 200 * 10 = 2000 N
b. If the the coefficient of friction between the tire and the pavement increased greatly, part of the force generated by the engine would go to overcome this friction, then the force that goes into acceleration of the motorcycle would be less than case a, as a consequence, its acceleration would decrease (mass remains the same).
Pyrite is called "fool's gold" because it's looks a lot like gold. Which properties can be used to tell gold and pyrite apart?
Answer:
On the basis of physical and chemical properties, pyrite can be differentiated from real gold.
Explanation:
Some properties which can be used to differentiate pyrite from real gold are given below:
i) Real gold is made of same kind of atoms while pyrite is made of combinations of atoms like Iron and Sulphur.
ii) Pyrite is lighter in color than real gold.
iii) When we heat pyrite and real gold, both show different colors at higher temperatures.
iv) Pyrite is less dense and harder than real gold.
v) Real gold has weight 1.5 times than that of pyrite.
The students in a class had the following scores on a test:
76, 79, 81, 83, 85, 86, 89, 91, 93
The teacher wants to make a box-and-whisker plot of these data. Which value should he use for Q3?
A. 90
B. 93
C. 91
D. 85
Answer:
He should use 90 for Q3 ⇒ answer A
Explanation:
Lets explain the meaning of Q3
Q1 is the "middle" value in the first half of the data set
Q2 is the median value in the set
Q3 is the "middle" value in the second half of the data set
The data are
76 , 79 , 81 , 83 , 85 , 86 , 89 , 91 , 93
The set has nine numbers, then Q2 is the fifth one
Q2 = 85
The first half of the data are:
76 , 79 , 81 , 83
The second half of the data are:
86 , 89 , 91 , 93
They are four numbers, then the middle one is the average of the
second and the third numbers
Q3 = [tex]\frac{89+91}{2}=90[/tex]
He should use 90 for Q3
Answer: The answer to this question is A
Explanation:
A student performs a reaction twice. In the second trial, she raises the temperature by 20¨¬C and notices that the reaction takes place more quickly. She concludes that the reaction must be endothermic. Explain why the student is incorrect.
Answer: She is incorrect to conclude that the reaction is endothermic.
As in the second trial, the temperature has increased by 20 °C , that means the heat has been released and energy is released in exothermic reactions.
Exothermic reactions: The reactions in which the energy of the products is less than the energy of the reactants, and the excess energy is released as heat.
Endothermic reactions: The reactions in which the energy of the products is more than the energy of the reactants, and the excess energy is absorbed as heat.
Explanation:
An endothermic reaction is a reaction in which the reactants absorb energy and the energy of products is more than that of reactants.
Whereas an exothermic reaction is a reaction in which the reactants have more energy as compared to products. Hence, there will be release of energy.
Therefore, when temperature is increased by [tex]20^{o}C[/tex] then it means we are providing more energy to the reactants. As a result, there will be release of energy. Hence, the reaction will be exothermic in nature and not endothermic.
Thus, we can conclude that the student is incorrect because the reaction is exothermic and not endothermic.
Blaine steps onto a ski slope with an angle of 25°. There is a coefficient of kinetic friction of 0.15 between him and the ground. He has a mass of 65 kg.
Draw the free-body diagram showing the forces acting on Blaine.
θ = angle of the incline surface from the horizontal surface = 25⁰
μ = Coefficient of friction = 0.15
m = mass of the person = 65 kg
[tex]f_{k}[/tex] = kinetic frictional force acting on the person as he slides down
mg = weight of the person acting in down direction
[tex]F_{n}[/tex] = normal force by the incline surface on the person
the free body diagram showing the forces acting on the person is given as
A 10-N force is applied horizontally on a box to move it 10 m across a frictionless surface. How much work was done to move the box?
Work done to move the box is 100Joules.
What is work done?The work done by any object is equal to the product of force applied and the distance moved by the object.
W =F.s
Given is the Force F =10N and distance moved s =10m
Then , the work done will be
W =10N x 10m
W =100J
Thus, the work done is 100J
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Which of the following describes an object in static equilibrium?
A.A platypus lies motionless on the sand.
B.A tuna speeds up from 2 m/s to 3 m/s
C.A dolphin jumps out of the water
D.A zebra shark swims at a constant speed of 8 m/s
A is the answer. If an object is at rest and is in a state of equilibrium, then we would say that the object is at static equilibrium. Static means stationary or at rest. A common physics lab is to hang an object by two or more strings and to measure the forces that are exerted at angles upon the object to support its weight.
Answer:
A). A platypus lies motionless on the sand.
Explanation:
As we know that equilibrium is defined as the system in the state of ZERO net force or zero acceleration condition.
So equilibrium is of two types
1) Static equilibrium : Here object will remain at rest and do not have any type of motion.
2) Dynamic equilibrium : Here object may move with constant speed in same direction so it will not have any acceleration.
So here
B.A tuna speeds up from 2 m/s to 3 m/s
C.A dolphin jumps out of the water
Not in equilibrium as speed is changing so acceleration is not zero
D.A zebra shark swims at a constant speed of 8 m/s
It is in dynamic equilibrium case where speed is constant
so correct answer will be
A.A platypus lies motionless on the sand.
you slide across home plate during baseball game. If you have a mass of 82 kg, and the coefficient of kinetic friction between you and the ground is 0.45, what is the force of friction acting on you?
m = mass of the person = 82 kg
g = acceleration due to gravity acting on the person = 9.8 m/s²
F = normal force by the surface on the person
f = kinetic frictional force acting on the person by the surface
μ = Coefficient of kinetic friction = 0.45
The normal force by the surface in upward direction balances the weight of the person in down direction , hence
F = mg eq-1
kinetic frictional force on the person acting is given as
f = μ F
using eq-1
f = μ mg
inserting the values
f = (0.45) (82) (9.8)
f = 361.6 N
Answer:
362 rounded, a p e x users
Explanation:
Ball a of mass 5.0 kilograms moving at 20 meters per second collides with ball b of unknown mass moving at 10 meters per second in the same direction. after the collision, ball a moves at 10 meters per second and ball b at 15 meters per second, both still in the same direction. what is the mass of ball b? * 1 point your answer
Answer:
10.0 kg
Explanation:
The problem can be solved by applying the law of conservation of momentum - the total momentum before the collision must be equal to the total momentum after the collision:
[tex]p_i = p_f\\m_A u_A + m_B u_B = m_A v_A + m_B v_B[/tex]
where:
[tex]m_A = 5.0 kg[/tex] is the mass of ball A
[tex]u_A = +20 m/s[/tex] is the velocity of ball A before the collision
[tex]m_B = ?[/tex] is the mass of ball B
[tex]u_B = +10 m/s[/tex] is the velocity of ball B before the collision (same sign of uA, since they are moving in same direction)
[tex]v_A = +10 m/s[/tex] is the velocity of ball A after collision
[tex]v_B = +15 m/s[/tex] is the velocity of ball B after collision
Re-arranging the equation, we can solve to find mB, the mass of ball B:
[tex]m_B u_B - m_B v_B = m_A v_A - m_A u_A\\m_B = \frac{m_A (v_A -u_A)}{u_B -v_B}=\frac{(5.0 kg)(10 m/s-20 m/s)}{10 m/s-15 m/s}=10.0 kg[/tex]
Suppose you want to separate the leaves, acorns, and twigs from a pile of soil. Filtration and distillation are two processes of separating mixtures. Explain which process you would use and why.
Have only 30 minutes to answer!!!!!
I will mark brainliest!
Mark him brainliest! XD
(your welcome btw)
The curved section of a horizontal highway is a circular unbanked arc of radius 740m. If the coefficient of static friction between this roadway and typical tires is .40, what would be the maximum safe driving speed for this horizontal curved section of highway
The maximum speed at which the car makes the turn without slipping is [tex]\boxed{54\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}}[/tex].
Further Explanation:
Given:
The coefficient of static fiction between the road and tyres is [tex]0.40[/tex].
The radius of curvature of the road is [tex]740\,{\text{m}}[/tex].
Concept:
As the car turn around the curved road, the centripetal force acting on the car should be balanced by the friction force acting on the car to avoid the slipping of the car on the road.
Write the force balancing equation for the forces acting on the car.
[tex]{F_{centripetal}} = {F_{frcition}}[/tex] …… (I)
The centripetal force acting on the car is given by.
[tex]{F_{centripetal}} = \dfrac{{m{v^2}}}{r}[/tex]
Here, [tex]m[/tex] is the mass of the car, [tex]v[/tex] is the velocity of the car and [tex]r[/tex] is the radius of the curvature of path.
The friction force acting on the car is given by.
[tex]{F_{fricton}} = \mu mg[/tex]
Here, [tex]\mu[/tex] is the static friction coefficient and [tex]g[/tex] is the acceleration due to gravity.
Substitute [tex]\dfrac{{m{v^2}}}{r}[/tex] for [tex]{F_{centripetal}}[/tex] and [tex]\mu mg[/tex] for [tex]{F_{friction}}[/tex] in equation (I).
[tex]\begin{aligned}\frac{{m{v^2}}}{r} &= \mu mg\\ v&= \sqrt {\mu rg}\\\end{aligned}[/tex]
Substitute the values in the above expression.
[tex]\begin{aligned}v&= \sqrt {0.40 \times 740 \times 9.8}\\ &= \sqrt {2900.8}\\ &= 53.85\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}\\&\approx 54\,{{\text{m}}\mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}\\\end{aligned}[/tex]
Thus, the maximum speed at which the car makes the turn without slipping is [tex]\boxed{54\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}}[/tex].
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Answer Details:
Grade: High School
Chapter: Circular motion
Subject: Physics
Keywords: Curved section, circular, unbanked road, static friction, maximum safe driving, radius 740m, without slipping, centripetal force, friction force.
*Physical Science* *E2020* *Unit Test*
Four students were loading boxes of food collected during a food drive. The force that each student exerted while lifting and the distance each box was lifted are listed in the table.
| Student | Force(N) | Distance(m) |
|-------------------|--------------------------|--------------------------|
| Chet | 50 | 1.0 |
|-------------------|--------------------------|--------------------------|
| Mika | 40 | 2.0 |
|-------------------|--------------------------|--------------------------|
| Sara | 30 | 1.5 |
|-------------------|--------------------------|--------------------------|
| Bill | 60 | 0.5 |
|__________|______________|_____________ |
Which lists the students in order from the greatest amount of work done to the least? (Work: W = Fd)
A. Bill, Sara, Chet, Mika
B. Mika, Chet, Sara, Bill
C. Bill, Chet, Mika, Sara
D. Mika, Sara, Chet, Bill
i think its b
hope this helps
Answer:The correct answer is option B.
Explanation:
Work done is defined product of force applied on an object and the displacement of an object on applying of force.It is measured in Joules.
[tex]W=Force\times Displacement[/tex]
1. Chet
Work done = [tex]50 N\times 1.0 m= 50.0 Joules[/tex]
2. Mika
Work done = [tex]40 N\times 2.0 m= 80.0 Joules[/tex]
3. Sara
Work done = [tex]30 N\times 1.5 m= 45.0 Joules[/tex]
4.Bill
Work done = [tex]60 N\times 0.5 m= 30.0 Joules[/tex]
The greatest work was done by Mika and least work was done by BIll. The order from the greatest amount of work done to the least.
Mika>Chet>Sara>Bill.
Hence ,the correct answer is option B.
If an atom has two electrons outside of its nucleus, what number of protons and neutrons must be contained in the nucleus to result in a neutral atom
A neutral atom must contain an equal number of protons and electrons. To have a neutral charge with two electrons, an atom would need two protons — as such, it is likely a helium atom. The number of neutrons doesn't affect the charge and can vary.
Explanation:Your question involves understanding the structure of an atom, particularly relating to its protons, neutrons, and electrons. An atom is made up of two sections: the nucleus, which consists of protons and neutrons, and a surrounding region that contains electrons. The number of both protons and electrons in an atom determines its atomic number, and this in turn identifies the element.
For an atom to be neutral, it should have an equal number of protons (positively charged particles) and electrons (negatively charged particles). So if an atom has two electrons outside its nucleus, it must contain two protons in its nucleus to be neutral. This corresponds with the element helium. The number of neutrons can vary without affecting the charge, so while the most common isotope of helium contains two neutrons, alternatives with one or no neutrons exist.
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The number of slices of pepperoni needed by a pizza restaurant is given by the equation p = 14n. In this equation, n is the number of pizzas the restaurant will make. How many slices of pepperoni are needed to make 40 pizzas?
A. 14
B. 560
C. 54
D. 40
If N is the number of pizza’s the restraunt will make and the equation tells us that the restraunt will make 40 pizza’s, I believe this turns the equation into p=14(40).
Answer:
The slices of pepperoni are 560.
Explanation:
The equation is given by
[tex]p=14 n[/tex]
We need to calculate the slices of pepperoni are needed to make 40 pizzas
Using given equation
[tex]p=14n[/tex]
Where, p = number of slices
n = number of pizza
Put the value of n in the equation
[tex]p = 14\times40[/tex]
[tex]p=560[/tex]
Hence, The slices of pepperoni are 560.
Which of the following is an abiotic limiting factor for a plant population in an ecosystem?
Invasive weed species
Seed dispersal by wind
Availability of soil minerals
Disease-causing fungal spores
Correct answer is Availability of soil minerals.
There are two types of limiting factors that affect plant population in a ecosystem. They are:
BioticAbioticBiotic factors includes food, diseases etc. Such as Invasive weed species, seed dispersal by wind, disease-causing fungal spores are examples of biotic limiting factor.
Abiotic factors include sunlight, temperature and chemical environment. The availability of soil mineral is an example of abiotic limiting factor. Growth of plant population depends on availability of soil minerals.
In the context of an ecosystem, an abiotic limiting factor refers to non-living elements that may limit a plant's survival or growth. Among the options provided, 'Availability of soil minerals' serves as an abiotic limiting factor.
Explanation:The question asks for an abiotic limiting factor, which refers to non-living aspects of an ecosystem that could limit a plant's growth or survival. In this case, the correct answer would be 'Availability of soil minerals.' Soil minerals are considered abiotic because they are non-living elements of the environment. They can limit plant growth if they are in short supply, as plants require specific minerals to carry out various biological functions. For example, nitrogen is a critical soil mineral that plants use to produce proteins and DNA.
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A long distance running is running the 10000 m race. He runs the first 2000 m in 5 minutes, the next 5000 m in 14 minutes and the final 3000 meters in 7 minutes. What was the runner’s average speed?
A long distance runner is running the 10000 m race. He runs the first 2000 m in 5 minutes, the next 5000 m in 14 minutes and the final 3000 meters in 7 minutes so the runner’s average speed is 6.41 m/sec.
What is average speed?The average speed is the total distance travelled by the object in a particular time interval. The average speed is a scalar quantity. It is represented by the magnitude and does not have direction.
Divide the whole distance by the total time required for him to go from the starting point to the finishing point to solve this type of problem. The entire distance in this instance is ten thousand meters, and the total time is the sum of the timings that were stated (which is 26 minutes, or 1560 seconds). By dividing these two figures, the following is the average speed,
average speed = 1000÷1560
average speed = 6.41 m/sec
The runner’s average speed is 6.41 m/sec.
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Which statement describes the vector plotted below?
A. The vector goes from (4,0) to (3-2)
B. The vector goes from (0,4) to (-2, 3)
C. The vector goes from (4,0) to (3,2)
D. The vector goes from (0,4) to (2,3)
A. The vector goes from (4,0) to (3-2)
(x,y)
The motion of an orbiting satellite can be described by the same motion characteristic of any object in uniform circular motion. The centripetal force acting toward the center of the circle, in this case, is supplied by
Gravity. That's the only force between the two objects.
the atomic number is consider a unique atom and element identifier. Describe the associated subatomic particle, and how it can be used to identify the atom.
The atomic number is unique to each element and represents the number of protons in the nucleus of that atom. Therefore, it can be used to identify which element an atom belongs to.
The atomic number of an atom signifies the number of protons in the nucleus of that atom.
This number is unique to each element, making it a reliable identifier.
For example, Hydrogen has an atomic number of 1, which means it has 1 proton, while Helium has an atomic number of 2, indicating it has 2 protons.
No two elements share the same atomic number, hence, the atomic number can be used to identify an atom and determine which element it belongs to.
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A forensic odontologist examines the teeth of a skull and finds no baby teeth, no wisdom teeth, deep roots in the maxillary cupsids, and substantial tooth degeneration. Which skull fits that data?
A) male, age 50
B) male, age 15
C) female, age 30
D) female, age 20
Answer:A Male,age 50
Explanation:
From forensic odontology description of a Male at age 50 to have a skull characteristic of no milk teeth, deep rooted maxillary due to change in structure of the canine teeth and no wisdom tooth.
The skull fits that data, if the data is A forensic deontologist examines the teeth of a skull and finds no baby teeth, no wisdom teeth, deep roots in the maxillary cuspids, and substantial tooth degeneration to a male of age 50, so option A is correct.
What is a skull?The skull's supporting bones. The skull is made up of facial bones and cranial bones, which surround and protect the brain (bones that form the eye sockets, nose, cheeks, jaw, and other parts of the face). The spinal cord and brain are joined by a gap at the base of the skull. Similar to the cranium.
According to forensic ontology, a male with a skull characteristic of age 50 had no milk teeth, a deep-rooted maxilla due to a change in the structure of the canines, and no wisdom teeth.
Therefore, the skull fits that data, if the data is A forensic deontologist examines the teeth of a skull and finds no baby teeth, no wisdom teeth, deep roots in the maxillary cuspids, and substantial tooth degeneration to a male of age 50.
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A student measured the specific heat of water to be 4.89 J/g · °C. The literature value of the specific heat of water is 4.18 J/g · °C. What was the student's percent error? %
4.89-4.18/4.18x100 = 0.71/4.18x100~1/6x100~16.7%
Answer:
16.98%
Explanation:
Given:
True value of specific heat of water = 4.18 J/g°C
Measured value of specific heat of water = 4.89 J/g°C
Percentage error can be calculated as follows:
[tex]error\% = \frac{|\text{True value-measured value}|}{\text{True value}}\times 100\% \\ e = \frac{|4.18-4.89|}{4.18}\times 100\% = 16.98\%[/tex]
A crane uses a block and tackle to lift a 2200N flagstone to a height of 25m
a. How much work is done on the flagstone? I calculated this to be 55000J
c. What is the potential energy of the flagstone when it is 25m above the ground?
The second question I did not get. I need help on the formula and how to solve.
Remember the headline: ENERGY IS NEVER CREATED OR DESTROYED
The amount of energy before and after are always equal. All we ever do with energy is move it around from one place to another.
a). A crane can't create energy. Lifting the same rock in 20 different ways always takes the same amount of work. It doesn't matter whether one person picks the rock straight up, or 50 people get around it and lift it, or roll it up a ramp, or lift it with 16 pulleys and a mile of rope, or use a giant steam crane.
You want to lift a 2200N weight up 25m, you're going to have to supply
(2200N) x (25m) = 55,000 Joules of work.
c). YOU put out 55,000 Joules of energy. It had to GO someplace. Where is it now ? ===> It's the potential energy the rock has now, from being 25m higher than it was before. That 55,000 Joules is NOW the potential energy of the rock.
No energy was created or destroyed. It just got moved around.
55,000 Joules of energy began as nuclear energy in the core of the sun. Solar radiation carried it to the Earth. Plants absorbed it, and stored it as chemical energy. You ... or a cow that you ate later ... ate the plants and took the chemical energy. One way or the other, the chemical energy got stored in your blood and fat. When you needed to put it out somewhere, you moved it into your muscles, and they converted it into mechanical energy. Then you used the mechanical energy to exert forces. Today, you used the original 55,000 joules to lift the flagstone, and NOW that energy is in the flagstone, 25 meters up off the ground !
The potential energy of the flagstone when it is 25m above the ground is 55000J.
The question concerns two aspects of physics: calculating the work done on an object and understanding the concept of potential energy. First, you correctly calculated the work done on the flagstone as 55000J. Now, for the potential energy of the flagstone when it is 25m above the ground, we use the formula for gravitational potential energy, which is P.E = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m/s2 on the surface of the Earth), and h is the height in meters.
To find the mass (m) of the flagstone, we use the relationship F = ma where F is the force (weight in this case, which is 2200N) and a is the acceleration due to gravity. This gives m = F/g. Substituting the values, we get the mass of the flagstone which allows us to calculate its potential energy at a height of 25m, using P.E = mgh.
It's important to understand that the potential energy of an object is directly related to its height above the ground and represents the energy stored within the object due to its position. In this case, assuming the flagstone is lifted vertically and no energy is lost, the potential energy at 25 meters would be equal to the work done to lift it, which is 55000J.
5. A truck left a diner at 1:00 p.M. And drove 360 km to Jersey City. The truck arrived at 2:00 p.M. And drove to Jersey City at an average 7:00 p.M. A car left the same dinner speed of 80 km/h. A. How fast did the truck travel?
Answer:
360 km/h
Explanation:
The truck left the diner at 1.00 pm and arrived at Jersey City at 2.00 pm - This means that the total time of the trip was 1 hour:
[tex]t = 1 h[/tex]
The distance covered between the diner and Jersey City was 360 km:
[tex]S=360 km[/tex]
So, the average speed of the truck is given by the distance covered divided by the time taken:
[tex]v=\frac{S}{t}=\frac{360 km}{1 h}=360 km/h[/tex]
Answer:
average speed of the truck will be 60 km/h
Explanation:
Truck started his Journey from diner at 1:00 PM
It reached to the Jersey City at 7:00 PM
so here we have total time interval of journey for the truck motion is given as
[tex]t = 7 - 1 = 6 hour[/tex]
total distance = 360 km
so here we know that average speed is defined as
[tex]v_{avg} = \frac{distance}{time}[/tex]
[tex]v_{avg} = \frac{360 km}{6 h}[/tex]
[tex]v_{avg} = 60 km/h[/tex]
so average speed of the truck will be 60 km/h
Which sound characteristic is not affected by the relative motion of an object
Answer: Quality is one of the characteristic of the sound which is not affected by the relative motion of an object.
Explanation: There are three characteristics of the sound which are pitch, loudness and quality.
Pitch depends on the frequency of the sound. The frequency varies in the case of the relative motion of the object.
Loudness depends on the amplitudes of the vibration. The amplitude also varies in the case of the relative motion of the object.
Quality is described by the word timber. The different sounds are produced by different sources. Therefore, It is not affected by the relative motion of the object.
Answer:
the answer is intensity on gradpoint
Explanation: