Find the missing factor B that makes the equality true. 21y^4= (B) (7y^3)​

Answer:

Step-by-step explanation:

Because angle FGH and angle HGE are congruent, that angle bisector, namely GH, separates this largr triangle into one that shares sides in proportion to each other.  

That means that [tex]\frac{x}{13.5} =\frac{68}{54}[/tex]

Cross multiply to get

54x = 918 and

x = 17

Choice A.

Answer:

Cross out Ab

Step-by-step explanation:

Answer: AD; 6

Step-by-step explanation:

using the shortest route algorithm. The next shortest route to AD would be AD; 6.

Answer:

C) 9

Step-by-step explanation:

The response is very low

Answer: 950, option D

Step-by-step explanation:

Adequate response rate from participants prevents non response bias.

Non-response bias can be said to occur when response rates from participants is below 60%.

Meanwhile, all other options are less than or equals 20% respond rate, while 950 implies 100% response rate.

The degree of the radian angle 0.11 is [tex]6.3^{\circ}[/tex]

Explanation:

It is given that the radian angle is 0.11

We need to determine the degrees of the radian angle.

To convert the radian into degrees, let us multiply the radian with [tex]\left(\frac{180}{\pi}\right)[/tex]

Thus, we have,

[tex]0.11\times\left(\frac{180}{\pi}\right)=\frac{19.8}{\pi}[/tex]

It is given that [tex]\pi=3.14[/tex]

Substituting [tex]\pi=3.14[/tex] in the above expression, we have,

[tex]\frac{19.8}{3.14} =6.303...[/tex]

Rounding off to the nearest tenth, we have,

[tex]6.3^{\circ}[/tex]

Thus, the degree of the radian angle 0.11 is [tex]6.3^{\circ}[/tex]

Step-by-step explanation:

a. The first four terms are:

-4 (⅓)¹⁻¹ = -4

-4 (⅓)²⁻¹ = -4/3

-4 (⅓)³⁻¹ = -4/9

-4 (⅓)⁴⁻¹ = -4/27

b. This is a geometric series.  Since the absolute value of the common ratio is less than 1 (|⅓| < 1), the series converges.

c. The series converges to the sum of:

S = a₁ / (1 − r)

S = -4 / (1 − ⅓)

S = -6

Answer:

cos(25)

Step-by-step explanation:

cosAcosB + sinAsinB = cos(A-B)

cos(20)cos(45) + sin(20)sin(45)

= cos(20-45) = cos(-25)

= cos(25) or 0.906

Answer:

The afrmer had 480 chickens at first

Step-by-step explanation:

We make an assumption here, that the initial number of chickens that the farmer has, is C.

Chickens sold by the farmer is (20% of C) + 240 chickens

Number of chickens left after selling in the morning and afternoon is 30% of C

So, the first number of chickens = Number of chickens sold + Number of chickens left

This gives us an equation that will be solved to obtain C.

C = ([tex]\frac{20}{100}[/tex] × C) + 240 chickens + ([tex]\frac{30}{100}[/tex] × C) = 0.2C + 240 chickens + 0.3C

C = 0.5C + 240 chickens

C - 0.5C = 240 chickens

0.5C = 240 chickens

C = [tex]\frac{240 chickens}{0.5}[/tex]

C = 480 Chickens

Answer: the answer is C = 480

Step-by-step explanation:

Answer:

Again, A.

Step-by-step explanation:

Just graph the equation, but you can tell just by looking at it that (0,11) is the y-intercept meaning that it's one of the answer choices.

Answer: 16

Step-by-step explanation:

law of cosines says that c^2 = a^2 + b^2 -2abcosC

so c^2 = 3^2 +15^2 - 2*2*15*cos108

c^2 = 234 -  (-27.8115294937 )

c^2 = 261.811529494

c = 16.18 rounds to 16

Answer:

16

Step-by-step explanation:

c² = a² + b² - 2(a)(b)cos(C)

c² = 3² + 15² - 2(3)(15)cos(108)

c² = 261.8115295

c = 16.18059114

Answer: the area of the garden is 493 ft²

Step-by-step explanation:

Let L represent the length of the rectangular garden.

Let W represent the width of the rectangular garden.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

If he has 92 feet of fencing, it means that

2(L + W) = 92

Dividing through by 2, it becomes

L + W = 46 - - - - - - - - - - - -1

He wants the length of the garden to be five feet less than twice its width. This means that

L = 2W - 5

Substituting L = 2W - 5 into equation 1, it becomes

2W - 5 + W = 46

2W + W = 46 + 5

3W = 51

W = 51/3

W = 17 feet

L = 2W - 5 = 2 × 17 - 5

L = 29 feet

The area of the garden is

LW = 29 × 17 = 493 ft²

We want

[tex]2x<6\cdot 2=12[/tex]

So, if we divide both sides by 2, we have

[tex]x<6[/tex]

So, we can accept all values for [tex]x[/tex], as long as they are less than 6 (excluded)

Answer:

a) 2x < 6(2)

x < 6

x can take any real value less than 6

b) divide both sides by 2;

Or multiply both sides by ½

Answer: the length of the cable is 10000 feet.

Step-by-step explanation:

A right angle triangle is formed. The length of the cable represents the hypotenuse of the right angle triangle. The height of the mountain represents the opposite side of the right angle triangle. To determine the length of the cable, L, we would apply the Sine trigonometric ratio.

Sin θ = opposite side/hypotenuse. Therefore,

Sin 30 = 5000/L

L = 5000/Sin 30 = 5000/0.5

L = 10000 ft

Answer:

3:7 or .4285

Step-by-step explanation:

the odds against are 4:7 so the odds with must be 7-4=3

which will be written in 3:7 form

Answer:

i = 351, j = 0

Step-by-step explanation:

The while loop runs 5 times as indicated by the variable, count.

The variable, i, has an initial value of 10. The first line of the loop code doubles the value of i while the second increments it by 1. This is done 5 times. We have

Iteration 1: i = 10 + 10 + 1 = 21

Iteration 1: i = 21 + 21 + 1 = 43

Iteration 1: i = 43 + 43 + 1 = 87

Iteration 1: i = 87 + 87 + 1 = 175

Iteration 1: i = 175 + 175 + 1 = 351

The third line of the loop code decrements j by 1. However, the fourth line sets j = 0 by subtracting it from itself. Hence, j is always 0 at the end of the loop, no matter its initial value or the number of iterations.

Thus, at the end of the code snippet, i = 351 and j = 0.

Answer:

3 books per box, 3 left over.

Step-by-step explanation:

Brian has 18 books, and he is packing them into 5 boxes. 18 is only divisible by 1, 3, 9, and 18.

1 x 5 = 5 books =  13 left over. Still enough to pack more books.

3 x 5 = 15 books = 3 left over. This is the answer, but let's check the others as well.

9 x 5 = 45 books. He doesn't have that many! He can't put 9 books in each box because it would only take 2 boxes he's using all 5.

18 x 5 = 90 books. We can clearly see this isn't the answer. He would only be able to put all 18 books in 1 box but he wants to use all 5 boxes.

There are 3 books in each box with 3 left over.

Brian has 3 books in each of the 4 boxes, with 3 books remaining as leftovers after packing them equally.

Brian is moving his 18 books and has packed an equal number of books into each of the 5 empty boxes. To find out how many books are in each box, we divide the total number of books by the number of boxes, which is = 18 books ÷ 5 boxes = 3 books per box with 3 books left over. Therefore, there will be 3 full boxes and one box with 3 leftover books.

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Answer:

5

Step-by-step explanation:

(4+20+x)/3 = (y+16)/2

2(24+x) = 3(y+16)

48 + 2x = 3y + 48

2x = 3y

Since x and y are positive integers, they can't be 0. To satisfy 2x = 3y

We'll have to use LCM of 2 and 3, which is 6 (or a multiple of 6)

For the least value, we use 6

To make both sides 6,

x = 3 and y = 2

Hence x + y = 5

Answer:

Yes

Step-by-step explanation:

A chi-square test (y) examine whether it is good enough to fit, and associates a detected dispersal of Categorical data to the theorized dispersal shown in one-way table demonstrations distribution. If we get an empty hypothesis of the Chi test, it means no relationship exists between the categorial variables in the population, and they are not dependent on each other.

Answer:

undefined or 1

Step-by-step explanation:

(-3g^2)^0

Where g=0. (given)

now,

[tex](-3g^2)^0 \\ ( - 3(0) {}^{2} ) {}^{0} \\

[/tex]

undefined or 1

[tex]\text{Solve by plugging in 0 to g}\\\\(-3\left(0\right)^2)^0\\\\\text{Solve:0}\\\\(-3\left(0\right)^2)^0\\\\(-3(0))^0\\\\(0)^0=1\\[/tex]

The concluding part of the question as obtained from the textbook;

The number on the 20 beach balls that come up in the simulated sample:

42, 1701, 638, 397, 113, 1243, 912, 380, 769, 1312, 76, 547, 721, 56, 4, 1411, 1766, 677, 201, 1840

A) Based on this sample, how many

defective beach balls might the

manufacturer expect in the next

shipment?

B) What is the difference between the

number of defective beach balls in the

actual shipment and the number

predicted in the next shipment?

Answer:

A) 500 defective beach balls.

B) Difference between the

number of defective beach balls in the

actual shipment and the number

predicted in the next shipment = 350

Step-by-step explanation:

The beach balls are labelled 1 to 2000 with the 150 defective ones labelled 1 to 150.

Then a random sample of 20 beach balls is picked, and the numbers are presented as

42, 1701, 638, 397, 113, 1243, 912, 380, 769, 1312, 76, 547, 721, 56, 4, 1411, 1766, 677, 201, 1840

Note that only the defective beach balls have numbers 1 to 150.

A) The number of beach balls with numbers from 1 to 150 in the sample is 5 (numbers 42, 113, 76, 56, 4). This is the number of defective beach balls in the sample.

Probability of getting a defective ball in the next shipment = (5/20) = 0.25

If every shipment contains 2000 beach balls, then there will be (0.25 × 2000) defective beach balls in the next sample; 500 defective beach balls.

B) Number of defective beach balls in actual shipmemt = 150

Number of predicted defective beach balls in the next shipment = 500

difference = 500 - 150 = 350.

Hope this Helps!!!

Answer:

C.) 500

Step-by-step explanation:

In a shipment of 2,000 beach balls, 150 are defective. The manufacturer generates a random sample to simulate 20 beach balls to inspect in the next shipment. The integers 1 to 150 represent defective beach balls.

   42         1701         638         397          113  

1243          912         380          769       1312

   76           547         721            56              4

1411         1766        677          201       1840

12. Based on this sample, how many defective beach balls might the manufacturer expect in the next shipment?

Group of answer choices

A.) 100

B.) 200

C.) 500

D.) 1000

Answer:

Step-by-step explanation:

Let the speed of cyclist be C and bus be B.

Using the concept of relative speed:-

For incoming bus,speed = B + C

For overtaking bus,speed = B - C

Now,distance travelled b/w 2 incoming bus = (B + C)*4

Now,distance travelled b/w 2 overtaking bus = (B - C)*12

so,

(B + C)*4 = (B - C)*12

or, B=2C

Hence,distance b/w two buses in same direction,d=4*(3/2)B=6 B

Therefore, time gap=d/B=6 minutes

Time interval between consecutive buses is 6 minutes, determined using relative speeds and given overtaking and meeting intervals.

To solve this problem, let's denote the following:

- [tex]\( v_c \)[/tex] is the speed of the cyclist.

- [tex]\( v_b \)[/tex] is the speed of the buses.

- [tex]\( t \)[/tex] is the time interval between consecutive buses.

Step-by-Step Solution:

1. Relative Speed in the Same Direction:

  When a bus overtakes the cyclist, it means the bus is catching up to the cyclist from behind. The relative speed of the bus with respect to the cyclist is:

  [tex]\[ v_b - v_c \][/tex]

  According to the problem, a bus overtakes the cyclist every 12 minutes:

  [tex]\[ v_b - v_c = \frac{d}{12} \][/tex]

  where [tex]\( d \)[/tex] is the distance between consecutive buses.

2. Relative Speed in the Opposite Direction:

  When the cyclist meets an oncoming bus, they are moving towards each other. The relative speed is:

  [tex]\[ v_b + v_c \][/tex]

  According to the problem, the cyclist meets an oncoming bus every 4 minutes:

  [tex]\[ v_b + v_c = \frac{d}{4} \][/tex]

3. Setting Up Equations:

  From the given information, we have two equations:

  [tex]\[ v_b - v_c = \frac{d}{12} \][/tex]

  [tex]\[ v_b + v_c = \frac{d}{4} \][/tex]

4. Solving for [tex]\( d \)[/tex] and [tex]\( t \)[/tex]  :

  Let's add these two equations to eliminate [tex]\( v_c \)[/tex]:

  [tex]\[ (v_b - v_c) + (v_b + v_c) = \frac{d}{12} + \frac{d}{4} \][/tex]

  [tex]\[ 2v_b = \frac{d}{12} + \frac{d}{4} \][/tex]

  [tex]\[ 2v_b = \frac{d}{12} + \frac{3d}{12} \][/tex]

  [tex]\[ 2v_b = \frac{4d}{12} \][/tex]

  [tex]\[ 2v_b = \frac{d}{3} \][/tex]

  Multiply both sides by 3:

  [tex]\[ 6v_b = d \][/tex]

  Now, substitute [tex]\( d = 6v_b \)[/tex] back into either equation, let's use [tex]\( v_b + v_c = \frac{d}{4} \)[/tex]:

  [tex]\[ v_b + v_c = \frac{6v_b}{4} \][/tex]

  [tex]\[ v_b + v_c = 1.5v_b \][/tex]

  [tex]\[ v_c = 0.5v_b \][/tex]

5. Finding the Time Interval [tex]\( t \)[/tex]:

  We already established that the distance between consecutive buses is [tex]\( d = 6v_b \)[/tex].

  The time interval [tex]\( t \)[/tex] between consecutive buses can be found using the speed of the buses:

  [tex]\[ t = \frac{d}{v_b} \][/tex]

 [tex]\[ t = \frac{6v_b}{v_b} \][/tex]

  [tex]\[ t = 6 \text{ minutes} \][/tex]

So, the time interval between consecutive buses is 6 minutes.

Answer: y = 6

y = -3x - 12

y = 3x + 24

Use elimination method to get 2y = 12 so y = 6.

Answer: the last option is the correct answer.

Step-by-step explanation:

The given system of equations is expressed as

y = - 3x - 12- - - - - - - - - - - - -1

y = 3x + 24- - - - - - - -- - - - - - -2

We would apply the method of elimination. Since x has the same coefficient and the sign is opposite, we would eliminate x by adding equation 1 to equation 2. It becomes

y + y = - 3x + 3x - 12 + 24

2y = 12

Dividing the left hand side and the right hand side of the equation by 2, it becomes

2y/2 = 12/2

y = 6

Step-by-step explanation:

[tex] \frac{y - y1}{x - x1} = \frac{y2 - y1}{x2 - x1} [/tex]

[tex] \frac{y - 0}{x - ( - 1)} = \frac{3 - 0}{1 - ( - 1)} [/tex]

[tex] \frac{y}{x + 1} = \frac{3}{1 + 1} [/tex]

[tex] \frac{y}{x + 1} = \frac{3}{2} [/tex]

[tex]y = \frac{3}{2} (x + 1)[/tex]

[tex]y = \frac{3}{2} x + \frac{3}{2} [/tex]

option B

Answer:

95%

Step-by-step explanation:

Three tests worth 100 points each = 3 X 100 = 300 points

Three quizzes worth 50 points each = 3 X 50 =150 points

Final exam worth 200 points

Total Obtainable Points=300+150+200=650

Total of test grades obtained (91, 82, and 88)=91+82+88=261

Total of quiz grades (50, 42, and 42) obtained = 50+42+42=134

Let x be the exam score for the student to obtain 90%

Therefore:

[tex]\frac{261+134+x}{650} X 100 \geq 90\\\frac{100(395+x)}{650} \geq 90\\39500+100x \geq 90X650\\39500+100x \geq 58500\\100x \geq 58500-39500\\100x \geq19000\\x \geq190\\[/tex]

The lowest score a student can score is 190.

Expressed as a percentage of 200,

[tex]\frac{190}{200}X100=95[/tex] per cent

The student must score a minimum of 95% in order to make an A.

Answer:

Part 1) The volume of the object is [tex]32\pi\ cm^{3}[/tex]  or [tex]100.48\ cm^{3}[/tex]

Part 2) see the procedure

Step-by-step explanation:

The picture of the question in the attached figure

Part 1)  What is the volume, in cubic centimeters, of the object?

we know that

The volume of the object is equal to the volume of the cylinder plus the volume of the cone

Find the volume of the cone

The volume of the cone is equal to

[tex]V=\frac{1}{3}\pi r^{2} h[/tex]

we have

[tex]r=4/2=2\ cm[/tex] -----> the radius is half the diameter

[tex]h=3\ cm[/tex]

substitute the values

[tex]V=\frac{1}{3}\pi (2^{2})(3)=4\pi\ cm^{3}[/tex]

Find the volume of the cylinder

The volume of the cylinder is equal to

[tex]V=\pi r^{2} h[/tex]

we have

[tex]r=4/2=2\ cm[/tex] -----> the radius is half the diameter

[tex]h=(10-3)=7\ cm[/tex]

substitute the values

[tex]V=\pi (2^{2})(7)=28\pi\ cm^{3}[/tex]

Part 2) Then explain how you found the volume of the total shape

The volume of the total shape is equal to the volume of the cylinder plus the volume of the cone

[tex]4\pi\ cm^{3}+28\pi\ cm^{3}=32\pi\ cm^{3}[/tex] ------> exact value

Find the approximate value of the volume

assume

[tex]\pi=3.14[/tex]

[tex]32(3.14)=100.48\ cm^{3}[/tex]

Answer:

Step-by-step explanation:

After 6 years the number of subscribers are 16500.

percentage, a relative value indicating hundredth parts of any quantity.

Given that Subscriptions to a fashion magazine have gone down by a consistent 5% each year.

The magazine currently has 25,000 subscribers.

We need to find the number of subscribers after 6 years.

[tex]A=Pe^{rt}[/tex]

where r is rate of interest

t is the time

p is the initial subscribers

[tex]A=25000e^{0.05(6)}[/tex]

[tex]A=25000e^{0.3}[/tex]

A=25000(1.34)

A=33500

As it is going down so we need to subtract 33500-25000

8500

So from initial subscribers 8500 are left.

250000-8500

16500

Hence, after 6 years the number of subscribers are 16500.

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Answer:

Neither the ranges nor the interquartile ranges for the data sets are the same.

Step-by-step explanation:

In a visual display, the boxplot presents five sample statistics: the minimum, the lower quartile, the median, the upper quartile and the maximum, and the box length gives an indication of the sample variability and the line across the box shows where the sample is centred, with an end at each quartile. The length of the box is thus the interquartile range of the sample and, whether the sample is symmetric or skewed, either to the right or left, the "shape" of the sample, and by implication, the shape of the population from which it was drawn, considering appropriate analyses of the data.

The question is incomplete! The complete question along with answer and explanation is provided below.  

Question:  

Which statement is true about the box plots? (attached in the image)

A Both the ranges and the interquartile ranges for the data sets are the same.

B. Neither the ranges nor the interquartile ranges for the data sets are the same.

C. The interquartile ranges for the box plots are the same, but their ranges are different.

D. The ranges for the box plots are the same, but their interquartile ranges are different.

Answer:

D. The range of both box-pots is same (9) but the interquartile range of box-plots is different (6 and 5)

Step-by-step explanation:

To answer this question, first we have to understand what a box plot is!

A box plot is a type of graph which shows 5 statistical characteristics of a data set.

1. Maximum and 2. Minimum values of data

3. Upper Interquartile and 4. Lower interquartile of data

5. Median of the data

Now lets analyze the attached box-plot so that we can conclude what is true about them and what is not!

We have two box-plots for two teacher's classes Marc and Sue and they show the number of incorrect questions in exam.

For Sue's class: (on the bottom)

As you can see the maximum and minimum values are

Maximum = 12 and Minimum = 3

So the Range becomes = 12 - 3 = 9

The upper quartile Q3 is 10 and lower quartile Q1 is 5

So the Interquartile Range becomes = 10 - 5 = 5

This Interquartile Range represents the 25 to 75 percentile of the data

There is little vertical line skewed to the right represents the Median = 9

So to summarize Sue's class

Range = 9

Interquartile Range = 5

Median = 9

For Marc's class: (on the top)

As you can see the maximum and minimum values are

Maximum = 10 and Minimum = 1

So the Range becomes = 10 - 1 = 9

The upper quartile Q3 is 9 and lower quartile Q1 is 3

So the Interquartile Range becomes = 9 - 3 = 6

This Interquartile Range represents the 25 to 75 percentile of the data

There is little vertical line skewed to the left represents the Median = 5

So to summarize Marc's class

Range = 9

Interquartile Range = 6

Median = 5

Conclusion:

The range of both box-pots is same (9) but the interquartile range of box-plots is different (6 and 5).

Therefore, we can confidently conclude that option D is the correct answer.

Answer:

x = −2.4

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

Exact Form: x = −12/5

Decimal Form: x = −2.4

Complete Question:

Which of the following is true of qualitative research methods?

A. Qualitative data may be analyzed qualitatively or quantitatively.

B. Qualitative researchers must be able to translate numerical data into meaningful narrative information.

C. Qualitative researchers seek to fit their answers into predetermined categories rather than to understand research participants.

D. Qualitative research is less superior for studying topics that involve complex psychological motivations.

E. Qualitative researchers emphasize their samples are made up of representative rather than relevant consumers.

Answer:

A. Qualitative data may be analyzed qualitatively or quantitatively.

Step-by-step explanation:

Qualitative data research is a way or method to gather or collect non-numerical information either by observation or by asking crucial questions. It is a scientific method.

Qualitative data research involves the gathering accurate data and one of the way to do this is by carrying out surveys.

Qualitative data research determines WHY a particular action is carried out.

There are various methods of Qualitative data research. They are:

a. Direct Observation

b. In-depth interviews

c. Focus groups

d. Open end surveys

e. Oral History

f. Ethnographic observation

Qualitative data may be analysed qualitatively or quantitatively.

Qualitative research methods involve the collection and analysis of non-numerical data to understand subjective experiences and behaviors.

Qualitative research methods involve the collection and analysis of non-numerical data to understand subjective experiences and behaviors. It emphasizes open-ended questions, in-depth interviews, and observations to gain insights into complex psychological motivations. Qualitative researchers do not seek to fit their answers into predetermined categories but rather aim to understand research participants and their experiences.

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