find the probability that a randomly selected automobile tire has a tread life between 42000 and 46000 miles

Answers

Answer 1
Given that in a national highway Traffic Safety Administration (NHTSA) report, data provided to the NHTSA by Goodyear stated that the mean tread life of a properly inflated automobile tires is 45,000 miles. Suppose that the current distribution of tread life of properly inflated automobile tires is normally distributed with mean of 45,000 miles and a standard deviation of 2360 miles.

Part A:

Find the probability that randomly selected automobile tire has a tread life between 42,000 and 46,000 miles.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is between two numbers, a and b is given by:
[tex]P(a \ \textless \ X \ \textless \ b) = P(X \ \textless \ b) - P(X \ \textless \ a) \\ \\ P\left(z\ \textless \ \frac{b-\mu}{\sigma} \right)-P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles a standard deviation of 2360 miles.
The probability that randomly selected automobile tire has a tread life between 42,000 and 46,000 miles is given by:
[tex]P(42,000 \ \textless \ X \ \textless \ 46,000) = P(X \ \textless \ 46,000) - P(X \ \textless \ 42,000) \\ \\ P\left(z\ \textless \ \frac{46,000-45,000}{2,360} \right)-P\left(z\ \textless \ \frac{42,000-45,000}{2,360} \right) \\ \\ =P(0.4237)-P(-1.271)=0.66412-0.10183=\bold{0.5623}[/tex]


b. Find the probability that randomly selected automobile tire has a tread life of more than 50,000 miles.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is greater than a numbers, a, is given by:
[tex]P(X \ \textgreater \ a) = 1-P(X \ \textless \ a) \\ \\ =1-P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles a standard deviation of 2360 miles.
The probability that randomly selected automobile tire has a tread life of more than 50,000 miles is given by:
[tex]P(X \ \textgreater \ 50,000) = 1 - P(X \ \textless \ 50,000) \\ \\ =1-P\left(z\ \textless \ \frac{50,000-45,000}{2,360} \right)=1-P(z\ \textless \ 2.1186) \\ \\ =1-0.98294=\bold{0.0171}[/tex]


Part C:

Find the probability that randomly selected automobile tire has a tread life of less than 38,000 miles.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is less than a numbers, a, is given by:
[tex]P(X \ \textless \ a) =P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles a standard deviation of 2360 miles.
The probability that randomly selected automobile tire has a tread life of less than 38,000 miles is given by:
[tex]P(X \ \textless \ 38,000) = P\left(z\ \textless \ \frac{38,000-45,000}{2,360} \right) \\ \\ =P(z\ \textless \ -2.966)=\bold{0.0015}[/tex]


d. Suppose that 6% of all automobile tires with the longest tread life have tread life of at least x miles. Find the value of x.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is greater than a numbers, x, is given by:
[tex]P(X \ \textgreater \ x) = 1-P(X \ \textless \ a) \\ \\ =1-P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles and a standard deviation of 2360 miles and that the probability that all automobile tires with the longest tread life have tread life of at least x miles is 6%.

Thus:
[tex]P(X \ \textgreater \ x) =0.06 \\ \\ \Rightarrow1 - P(X \ \textless \ x)=0.06 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=1-0.06=0.94 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=P(z\ \textless \ 1.555) \\ \\ \Rightarrow \frac{x-45,000}{2,360}=1.555 \\ \\ \Rightarrow x-45,000=2,360(1.555)=3,669.8 \\ \\ \Rightarrow x=3,669.8+45,000=48,669.8[/tex]
Therefore, the value of x is 48,669.8


e. Suppose that 2% of all automobile tires with the shortest tread life have tread life of at most x miles. Find the value of x.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is less than a numbers, x, is given by:
[tex]P(X \ \textless \ x) =P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles and a standard deviation of 2360 miles and that the probability that all automobile tires with the longest tread life have tread life of at most x miles is 2%.

Thus:
[tex]P(X \ \textless \ x)=0.02 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=1-0.02=0.98 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=P(z\ \textless \ 2.054) \\ \\ \Rightarrow \frac{x-45,000}{-2,360}=2.054 \\ \\ \Rightarrow x-45,000=-2,360(2.054)=-4,847.44 \\ \\ \Rightarrow x=-4,847.44+45,000=40,152.56[/tex]
Therefore, the value of x is 40,152.56

Related Questions

Results for 'Tanisha's office is on the ninth floor of an office building.she products your car in the underground parking garage for floors below ground level but how many floors are between Tanisha's Office and her car? '

Answers

there are 9 floors between her office and her car

A client is instructed to take
1 1/2 teaspoons of a cough syrup 3 times a day. How many teaspoons of cough syrup will the client take each day?

Answers

It would be 3/2 x 3/1 which would = 4 1/2
  1.5 * 3 = 4.5 tsp.  ;  or, write as:  " 4[tex] \frac{1}{2}[/tex]  tsp.".
___________________________________________________

A train leaves Los Angeles at 2 p.m. heading north at 50 mph. If the next train leaves three hours later and also heads north at 60 mph, at what time will the second train catch up with the first?

Answers

The Second train will catch up with the first train after 15 hours which is 8a.m the following morning.

First train :

Departure time = 2 pm

Speed = 50 mph

Second train :

Departure time = 2 pm + 3 hours = 5 pm

Speed = 60 mph

Distance = speed × time

Distance already covered by first train before the departure of the second = 50 mph × 3 hpird = 150 miles

The number of hours needed for second train to catch up will be h;

(60 × h) = (50 × h) + 150

60h = 50h + 150

60h - 50h = 150

10h = 150

h = 150/ 10

h = 15

Second train will catch up after 15 hours :

Hence, time will be : (5pm + 15 hours) = 8 a.m the following morning.

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Answer: 8:00 am

Step-by-step explanation:

(5pm + 15 hours) = 8 a.m the following morning.

60h = 50h + 150

60h - 50h = 150

10h = 150

h = 150/ 10

h = 15

In the diagram, polygon ABCD is flipped over a line of reflection to form a polygon with its vertices at A′, B′, C′, and D′. Points A′, B′, and D′ are shown, but the line of reflection and point C′ are not. The line of reflection is , and the coordinates of C′ are . NextReset

Answers

Here is what I found

1.Parallelogram ACFD is split in two parts so that ABED and FEBC are congruent isosceles trapezoids. What are the measures of all the angles of trapezoid FEBC if angle D is 48°?

I know that Angle C is 48 degrees
I know that Angle F is 132 degrees
What is < CBE equal to and why?
What is < FEB equal to and why?

Answers

Refer to the diagram shown below.

Because ACFD is a parallelogram, its opposite angles are equal. Therefore
x = m∠ACF = m∠BCF = 48°  
Similarly,
y = m∠CAD = m∠CFD 

The sum of the angles inside a parallelogram is 360°. Therefore
48° + x + y + y = 360°
Because x = 48°,
48° + 48° + 2y = 360°
2y = 360° - 96° = 264°
y = 132°

Because ABED and FEBC are congruent, therefore
y = m∠DAB = m∠CFE = 132°
x = m∠ADE = m∠FCB = 48°

Because FEBC is a parallelogram, the opposite angles are equal. Therefore
m∠CBE = m∠CFE = y = 132°
m∠BCF = m∠BEF = x = 48°

Answer:
The measures of all angles of trapezoid FEBC are
m∠BCF = 48°
m∠BEF = 48°
m∠CBE = 132°
m∠CFE = 132°

A diver begins at 150 feet below sea level, descends at a steady rate of 5 feet per minute for 3.5 minutes, and then ascends 122.2 feet. What is the diver’s current depth? Explain how to write a numerical expression to find the answer.

Answers

Sent a picture of the solution to the problem (s).

You diver begin at -150 feet and then descend at 5 feet/minute for 3.5 minutes, which could be represented by (-5)(3.5). you then go up 122.2 feet. The expression is -150 + (-5)(3.5) + 122.2. You then get that the diver’s depth is 45.3 feet below sea level, or -45.3.


what is the 13th term in the arithmetic sequence described by this explicit formula an=84+(n-1)(-6)

Answers

Just replace n with 13 in the formula:  an=84+(n-1)(-6)

Thus, a(13)=84+(13-1)(-6) = 84 - 72 = 12 (answer)

Answer:

12


Step-by-step explanation:

The formula given is [tex]a_n=84+(n-1)(-6)[/tex]

Where [tex]a_n[/tex] gives the nth term


Since we want 13th term, we can say we want [tex]a_{13}[/tex] and we plug in 13 in [tex]n[/tex] into the formula. So we get:

[tex]a_n=84+(n-1)(-6)\\a_{13}=84+(13-1)(-6)\\a_{13}=84+(12)(-6)\\a_{13}=84-72\\a_{13}=12[/tex]


So, the 13th term of the sequence is 12

select the function that represents a geometric sequence?

Answers

Answer:

The correct option is A.

Step-by-step explanation:

A geometric sequence is defined as

[tex]A(n)=ar^{n-1}[/tex]

Where, a is the first term of the sequence, r is the common ratio and n is number of term. So, n can not be negative or zero.

In option A, the given sequence is

[tex]A(n)=P(1+i)^{n-1}[/tex]

Where, n is positive integers.

Here the first term is P and (1+i) is the common ratio. So, this sequence is geometric sequence.

Therefore the correct option is A.

Answer:

A is correct just took the test

Step-by-step explanation:

Express each ratio as a unit rate. 325.4 miles on 17.3 gallons



having trouble :/

Answers

Hello! I can help you with this question! To find the unit rate, we’ll have to divide total by number of units. Or in this case, miles/gallons. 325.4/17.3 is 18.809 and other numbers, or 18.81 when rounded to the nearest hundredth. If you’re looking for the answer to the nearest hundredth, the answer is 18.81 mpg. Or, if you’re looking for the answer to the nearest whole number, the answer is 19 mpg.
Final answer:

To express the given ratio as a unit rate, divide the miles by the gallons to obtain 18.8 miles per gallon.

Explanation:

To express the given ratio as a unit rate, divide the miles by the gallons. So, the unit rate would be:

325.4 miles ÷ 17.3 gallons = 18.8 miles per gallon

Therefore, the unit rate for the given ratio is 18.8 miles per gallon.

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What are the values of the 7 in the number 17,372

Answers

I'm pretty sure you meant place value. 
7 is the thousandth place, and it is also in the tenth place.

If you asked for a face value, 
70070 would be the answer for place values.
7 ( In front of the 2)- represent tens

7 ( In front of the 3)- represents thousands

Please vote my answer brainliest. thanks!

Kathy runs a 26.2- mile marathon at an average pace of 6.2 minutes per mile how long will it take her to finish

Answers

Around 2:45:34 
hope this helps

Kathy will complete the 26.2-mile marathon in approximately 2 hours and 42 minutes by multiplying the marathon distance by her average pace and converting the result from minutes to hours and minutes.

To calculate the time it will take for Kathy to finish a 26.2-mile marathon at an average pace of 6.2 minutes per mile, we simply multiply the distance of the marathon by her average pace per mile. This is a basic mathematics problem involving multiplication to determine the total time.

Here is the calculation:

Total marathon distance = 26.2 miles

Average pace = 6.2 minutes per mile

Total time = Total marathon distance x Average pace

Total time = 26.2 miles x 6.2 minutes per mile = 162.44 minutes

To convert minutes into hours and minutes, we know that there are 60 minutes in an hour. Therefore:

Hours = Total time / 60

Hours = 162.44 minutes / 60 ≈ 2.707 hours

Since we want hours and the remaining minutes, we can take the decimal part and multiply it by 60:

Remaining minutes = 0.707 x 60 ≈ 42.42 minutes

Hence, Kathy will complete the marathon in approximately 2 hours and 42 minutes.

A runner can jog at a rate of 4 miles per hour uphill. Downhill, he can run 3 miles in the same time it takes him to run 2 miles uphill. How long would it take to run 2 miles uphill and then 3 miles downhill?
what is the most important variable?

Answers

The most important variable is 4 miles per hour up hill. Down hill he can run 3 miles in the same time it takes time to run uphill.  up hill 4 miles  1 hour  so 2 miles up hill is 1/2 hour.  Down hill he can run 3 miles in the same time it takes time to run up hill..  2 miles up hill - 1/2 hour.  So 1/2 hr up and 1/2 hr down = 1 hour. 

To calculate the total time it takes to run 2 miles uphill at 4 mph and then 3 miles downhill at a speed that takes the same time as running 2 miles uphill, we find that the time for each is 0.5 hours, or 30 minutes, totaling 1 hour

The main question asks how long it would take for the runner to run 2 miles uphill and then 3 miles downhill, knowing that he jogs at a rate of 4 miles per hour uphill, and he can run 3 miles downhill in the same time it takes to run 2 miles uphill

First, let's find the time it takes to run 2 miles uphill. Since he runs at 4 miles per hour uphill, the time for 2 miles uphill is 2 miles divided by 4 miles per hour, which equals 0.5 hours or 30 minutes. Now, since it takes the same time to run 3 miles downhill, we know the downhill time is also 30 minutes

The total time taken for 2 miles uphill and 3 miles downhill is the sum of both, which is 30 minutes + 30 minutes = 60 minutes, or 1 hour. Thus, the answer to the student's question is 1 hour

The amount left when you subtract last month's payment from last month's balance on a credit card statement is the

A. APR.

B. unpaid balance.

C new balance.

D. minimum payment.

The percentage charged each month on purchases charged to the credit card account is called the

A. periodic rate

B. new balance

C. unpaid balance

D. minimum payment

Answers

I believe that the first one is B) Unpaid Balance.
Dont quote me though if its wrong haha. 

Answer:

Question 1)

Option: B

( unpaid balance)

Question 2)

Option: D

( Minimum payment )

Step-by-step explanation:

Question 1)

UNPAID BALANCE:

unpaid balance is the remaining balance of a loan, cash advance or credit that has not been paid.

Hence, The amount left when you subtract last month's payment from last month's balance on a credit card statement is the:

unpaid balance.

Question 2)

Minimum payments are typically calculated as percentage of your outstanding balance plus any fees that have been added to your balance.

Hence, The percentage charged each month on purchases charged to the credit card account is called the:

Minimum payment.

A basket contains 12 apples, of which two are rotten. a sample of three apples is selected at random. in how many ways can two rotten apples be chosen

Answers

Final answer:

Using the concept of combinations, there are 10 ways to choose three apples from a basket, where two are rotten and one is not.

Explanation:

The question is asking about the number of ways two rotten apples can be chosen from a basket, given the total apples and the number of rotten ones. This is a problem based on probability and combinations.

The total number of apples in the basket is 12, two of them are rotten. The number of ways of choosing 2 rotten apples from 2 is simply 1 way, because there are only 2 and you're choosing each one of them.

But, the student is asked to select three apples, so the last apple would be one of the other 10 (remaining good ones). The number of ways you can choose that is 10 C 1.

From combinations rules, we know nCr=n!/[r!(n-r)!], where n is the total items, r is the number chosen, and '!' refers to factorial.

So to find the number of ways to choose 1 apple from 10, we find 10! / [1!(10-1)!]. This calculates as 10! / [1!9!] = 10. So, there are 10 ways to choose three apples with two of them being rotten.

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There are 10 different ways to choose a sample of three apples from the basket such that exactly two of them are rotten.

To determine the number of ways to choose two rotten apples from a basket containing 12 apples (2 of which are rotten) when a sample of three apples is selected.

We can use combinatorics.

Step-by-Step Solution:

1. Identify the total number of apples and the rotten apples:

Total apples: [tex]\( 12 \)[/tex]

Rotten apples: [tex]\( 2 \)[/tex]

2. Determine the possible cases for choosing two rotten apples in the sample of three:

We need to choose 2 out of the 2 rotten apples.

We need to choose the remaining 1 out of the 10 good apples.

3. Calculate the number of ways to choose 2 rotten apples out of 2:

[tex]\[ \binom{2}{2} = 1 \][/tex]

4. Calculate the number of ways to choose 1 good apple out of 10:

[tex]\[ \binom{10}{1} = 10 \][/tex]

5. Multiply the results from the above steps to get the total number of ways to choose two rotten apples and one good apple:

[tex]\[ \text{Total ways} = \binom{2}{2} \times \binom{10}{1} = 1 \times 10 = 10 \][/tex].

What is the value of the underlined digit 5,678.321

Answers

none of the digits r underlined but here is some help
the number 5 is in the thousands
6 is in hundreds
7 in tens
8 in ones
.3 is tenths
2 is hundredths
1 is thousandths

The value of the underlined digit is 600.

What is the place value strategy?

The place value strategies are defined as math strategies that use to assist you in resolving your elementary math problems, use your places values, such as tens and hundreds. It is possible to employ enlarged notation or compensation. Using regrouping techniques, you can make the problem easier by compensating for addition.

We must determine the values of each integer in order to calculate the value of the underlined digit (6) in the equation.

In 5,678.321, the first digit, 5, is 1,000 in the thousands of places.

The second digit, 6, is in the hundreds (100) place.

So the value is 600.

Hence, the value of the underlined digit is 600.

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Your question is incomplete, probably the complete question is:

What is the value of the underlined digit 5,678.321, the underlined digit (6)

There are 10 less trumpet and saxophone players number of saxophone players three times the number of trumpet players how many trumpet players are there?

Answers

Let a be the number of trumpet players
Let b be the number of saxophone players
---------------------
(1) a = b-10
(2) b =3a
----------------
Substitute
(2) into (1)
(1) a =3a-10
(1) 2a =10 

 (1) a = 5and
(2) b = 3(5)(2)
b =  15
------------------
There are 5 trumpet players and 15 saxophone player

There are 3 trumpet players.

We have,

Let's assume the number of trumpet players is represented by "x".

According to the given information, the number of saxophone players is three times the number of trumpet players, so the number of saxophone players would be 3x.

It is also stated that there are 10 less saxophone players than the total number of trumpet and saxophone players.

So, the number of saxophone players would be (x + 3x) - 10, which simplifies to 4x - 10.

Since the number of saxophone players is equal to 4x - 10, we can set up an expression to solve for x:

4x - 10 = x

To isolate x, subtract x from both sides of the expression:

4x - x - 10 = x - x

This simplifies to:

3x - 10 = 0

Next, add 10 to both sides:

3x - 10 + 10 = 0 + 10

This yields:

3x = 10

Finally, divide both sides by 3:

(3x) / 3 = 10 / 3

The solution is:

x = 10/3 or approximately 3.33

Therefore,

There are approximately 3.33 trumpet players.

Since you cannot have a fraction of a player, we can conclude that there are 3 trumpet players.

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What is the thickness t of the thin film of diamond? express your answer in nanometers using three significant figures?

Answers

Final answer:

The thickness of a thin film of diamond can be calculated using the formula t = (m * λ) / (2 * n), where m is the number of fringes, λ is the wavelength of light used, and n is the refractive index of diamond.

Explanation:

The thickness of a thin film of diamond can be determined using the formula:

t = (m * λ) / (2 * n)

where t is the thickness, m is the number of fringes, λ is the wavelength of light used, and n is the refractive index of diamond.

In this case, the number of fringes is given as 14 per centimeter, which can be converted to 140 per meter. The wavelength of the light used is not provided, so we cannot determine the thickness without that information.

how many 1/4 cup servings of oatmeal are in 3/5 of a cup of oatmeal?

Answers

nice question, here we gonna employ our understanding in fraction.
3/5÷1/4= 3/5×4/1
final answer is 12/4=3
Meaning 3 cups of 1/4 serving oatmeal are in 3/5 oatmeal.

A rectangle is divided into 8 equal parts. Two parts are shaded. Which fraction is equivalent to the shaded area of the rectangle?

Answers

If the shaded area is 2 out of the 8 equal parts, the fraction is 2/8, which simplifies to 1/4.
2/8 or 1/4 of the rectangle is shaded

F(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (1, 2) to (2, 8) (a) find a function f such that f = ∇f.

Answers

[tex]\mathbf F(x,y)=x^2\,\mathbf i+y^2\,\mathbf j[/tex]

If a scalar function [tex]f(x,y)[/tex] exists for which [tex]\nabla f(x,y)=\mathbf F(x,y)[/tex], then we'd have

[tex]\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)[/tex]
[tex]\implies\dfrac{\partial f}{\partial y}=y^2=g'(y)\implies g(y)=\dfrac{y^3}3+C[/tex]

so the scalar function would be given by

[tex]f(x,y)=\dfrac{x^3+y^3}3+C[/tex]

where [tex]C[/tex] is an arbitrary constant.

Presumably, this question is being asked in the context of the line integral of [tex]\mathbf F(x,y)[/tex] along the given contour [tex]C[/tex]. Since [tex]\mathbf F(x,y)[/tex] is conservative - and consequently a scalar potential function [tex]f(x,y)[/tex] exists - we can simply use the gradient theorem to evaluate the line integral. We would get

[tex]\displaystyle\int_C\mathbf F\cdot\mathrm d\mathbf r=f(2,8)-f(1,2)=\dfrac{511}3[/tex]

(and we get the same answer by parameterizing [tex]C[/tex] and computing the integral as we usually would)

Suppose Q and R are independent events. Find P(Q and R) if P(Q) = 0.27 and P(R) = 0.03.

Answers

Your answer would be 0.0081!

Answer:

Value of  [tex]P(Q \cap R)[/tex] is, 0.0081

Step-by-step explanation:

For an independent events A and B is given by:

[tex]P(A \cap B) =P(A) \cdot P(B)[/tex]

As per the statement:

Suppose Q and R are independent events.

P(Q) = 0.27 and P(R) = 0.03.

We have to find [tex]P(Q \cap R)[/tex]

By definition we have;

[tex]P(Q \cap R) =P(Q) \cdot P(R)[/tex]

Substitute the given values we have;

[tex]P(Q \cap R) =0.27 \cdot 0.03[/tex]

⇒[tex]P(Q \cap R)=0.0081[/tex]

therefore, the value of  [tex]P(Q \cap R)[/tex] is, 0.0081

Fuaad solved an absolute value inequality and expressed the solution as -12

Answers

well -4 times 3 is -12 that would be your answer hope this helps

Can you plz solve 336.752 divided by 31 in long division form. This would help a whole bunch:)

Answers

that would be 10.862
hope this helps.

Quadrilateral ABCD is the result of a translation of quadrilateral EFGH. Segment EF is parallel to segment HG in the pre-image.

Select from the drop-down menus to correctly complete the statement.
Segment EF is parallel to segment HG in the pre-image.

The corresponding segments are what

Answers

Answer: Segment BC of image is parallel to  segment AD of image.

Step-by-step explanation:

Given: Quadrilateral ABCD is the result of a translation of quadrilateral EFGH.

Segment EF is parallel to segment HG in the pre-image.

Since translation is a rigid transformation which preserves the side-lengths and angles of the original figures.

Therefore, all the segments of the image figure are parallel to correspondent segments of the original figure.

Segment AD of image is parallel to segment HG  in the pre-image.

Segment BC of image is parallel to  segment  EF in the pre-image.

Hence, if Segment EF is parallel to segment HG in the pre-image.

⇒ Segment BC of image is parallel to segment AD in image.

Solve the equation

5(-3x - 2) - (x - 3) = -4(4x + 5) + 13

Answers

First we reduce brackets
next we expand the equation
next we subtract -15x - 10 - x + 3 so it can be -16x - 7
and then we subtract -16x - 20 + 13 to get our answer, and since its -16x - 7, both sides of it are equal.

Answer: Infinitely many answers.

A sea lion dove from the water's surface at sea level to an altitude of −216.12 meters in 2.4 minutes. What is the average change in the sea lion's altitude per minute? Enter the your answer in the box as a decimal.

Answers

2.4 minutes is 144 seconds. divide -216.12 by it to get altitude per second. This is 1.5 meters per second. Multiply this by 60 to get the rate per minute, totaling 90.05 meters per minute. Sorry if this explanation was long that was how I remember.

Sasha donated 9/100 of her class’s entire can collection for the food drive. What decimal is equivalent to 9/100?

Answers

The decimal that is equivalent to 9/100 is 0.09.

Hope this helps!
Listen up:

To find the decimal equivalent of any fraction, simply divide the numerator(top) by the denominator(bottom).

In his case, divide 9 by 100

ANSWER .09

Also some place value lessons:

.1 is in the tenths place
.01 is in the hundredths
.001 is in the thousandths

Hope this helps!

what is five divided by 2835

Answers

2835 divided by 5 equals 567.
2835/5=567, good luck.

order 56.2 56.32 56.321 from greatest you least

Answers

Here it is listed from greatest to least:
56.32, 56.321, 56.2
From greatest to least:

56.321
56.32(0)
56.2(0)

The "(0)"s indicate understood 0s, which are there just not visible

what is the quotient a-3/7÷3-a/21

Answers

I wish you were using parentheses here.  I must assume (without knowing for sure) that y ou mean

a - 3/7
----------
3 - a/21

The LCD here is 21, since 7 divides into 21 without a remainder. 

Thus, multiply numerator and denominator by 21:


21a - 9
-----------
63 - a

You could leave this result as is, or you could factor out 3:
    
     7a-3
3 ---------
    63-a

The quotient of the expression [tex]\(\frac{a-3}{7} \div \frac{3-a}{21}\)[/tex] is -3.

To find the quotient of the expression [tex]\(\frac{a-3}{7} \div \frac{3-a}{21}\)[/tex], we follow the rules of division for fractions, which involves multiplying the first fraction by the reciprocal of the second fraction.

The expression can be rewritten as:

[tex]\[\frac{a-3}{7} \times \frac{21}{3-a}\][/tex]

Now, we can simplify the expression by canceling out common factors. Notice that [tex]\(a-3\)[/tex] and [tex]\(3-a\)[/tex] are negatives of each other, and [tex]\(7\)[/tex] is a factor of [tex]\(21\)[/tex].

First, we can cancel [tex]\(a-3\)[/tex] with [tex]\(3-a\)[/tex], keeping in mind that a negative sign will be introduced since [tex]\(a-3 = -(3-a)\)[/tex]:

[tex]\[\frac{-1}{7} \times \frac{21}{-1}\][/tex]

Next, we simplify [tex]\(21\)[/tex] divided by [tex]\(7\)[/tex], which is [tex]\(3\)[/tex]:

[tex]\[-1 \times 3\] = -3[/tex]

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