To calculate the sum of 12x² + 9x², add the coefficients (12 and 9) to get 21 and then multiply by x², resulting in a sum of 21x².
To find the sum of the expression 12x² + 9x², you simply add the like terms. Both terms have an x² component, so they can be combined.
Here's how you do it:
First, identify the coefficients of the x² terms, which are 12 and 9.
Next, add these two coefficients together: 12 + 9 = 21.
Finally, multiply the sum of the coefficients by x2 to get the final answer: 21x².
Therefore, the sum of 12x² + 9x² is 21x².
Simplify.
(-5.12) - (-4.7) + (7.021)
6.79
6.601
-2.799
A street that is 270m long is covered in snow. city workers are using a snowplow to clear the street. a tire on the snowplow has to turn 45 times in traveling the length of the street. what is the diameter of the tire?
What is 55 x 10 to the power of 4 in scientific notation
Solve an equation to answer the question
Jose bought 2 movie tickets and a box of popcorn. The popcorn cost $6, and he spent a total of $24. How much did each ticket cost? Use m to represent the cost of each movie ticket.
A. 6m+2=24 m=3 ; each ticket cost $3.
B. 2m+6=24 m=9 ; each ticket cost $9.
C. 2m+6=24 m=15 ; each ticket cost $15.
D. 6m+2=24 m=4 ; each ticket cost $4.
Answer:
B) 2m+6=24 m=9 ; each ticket cost $9.
Step-by-step explanation:
Given: Jose bought 2 movie tickets and a box of popcorn. The popcorn cost $6, and he spent a total of $24.
Here "m" represents the cost of each movie ticket.
Now let's form an equation.
2m + box of popcorn = $24
Box of popcorn cost $6
So,
2m + 6 = 24
Now, we have to solve for m.
Subtract 6 from both sides, we get
2m + 6 - 6 = 24 - 6
2m = 18
Dividing both sides by 2, we get
2m/2 = 18/2
m = 9
So, the cost of movie ticket is $9 each.
Therefore, the answer is B) 2m+6=24 m=9 ; each ticket cost $9.
Which of the following statements is true?
All trapezoids are parallelograms.
All parallelograms are trapezoids.
All rectangles are squares.
All rhombuses are rectangles.
Answer:
The answer is B. All parallelograms are trapezoids.
Step-by-step explanation:
The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure. That makes the opposite of facing sides are parallel to each other. The the definition of trapezoid is a convex quadrilateral with at least one pair of parallel sides. Therefore, all parallelograms are trapezoids.
The true statement among the given options is, B. All parallelograms are trapezoids.
A trapezoid is a quadrilateral with at least one pair of parallel sides, but it doesn't require all sides to be parallel. Therefore, not all trapezoids are parallelograms. (Statement A is false)
A parallelogram is a quadrilateral with both pairs of opposite sides parallel. Every trapezoid has at least one pair of parallel sides, so it can be considered a special case of a parallelogram. Therefore, all trapezoids are parallelograms. (Statement B is true)
A rectangle is a quadrilateral with all four angles equal to 90 degrees. It has opposite sides that are parallel and equal in length. A square is a special type of rectangle with all sides of equal length. However, not all rectangles have all sides of equal length, so statement C is false.
A rhombus is a quadrilateral with all four sides of equal length. It has opposite sides that are parallel, making it a parallelogram. Since a rectangle is a parallelogram with right angles, and a rhombus is a parallelogram with equal sides. Therefore, statement D is also false.
Learn more about quadrilaterals here:
https://brainly.com/question/3113772
#SPj6
What are the steps for using a compass and straightedge to construct a square? Drag and drop the steps in order from start to finish.
Use the straightedge to draw FD ¯ ¯ ¯ ¯ ¯ and FE ¯ ¯ ¯ ¯ ¯ .
Keeping the same compass width, place the compass on point E and draw an arc in the interior of ∠DBE to intersect the previously drawn arc. Label the point of intersection as point F.
Use a straightedge to draw line t and label a point on the line as point B.
Without changing the compass width, place the compass point on point D and draw an arc in the interior of ∠DBE .
With the compass open to the desired side length of the square, place the compass point on point B and draw an arc on line t and an arc on BC ← → . Label the points of intersection as points D and E.
Construct a line perpendicular to line t through point B. Label a point on this line as point C.
Answer:
See explanation below.
Step-by-step explanation:
To construct a square using only a compass and a straightedge first we need to:
Use a straightedge to draw a line (we will name the line t) and label a point on the line as point B.Then, you will draw a perpendicular line to the segment that passes through point B ( To remember how to draw a perpendicular line through a segment see the note at the end of the explanation), label a point on this line as point C.With the compass open to the desired side length of the square (meaning the measure of the side of the square you need), place the compass point on point B and draw an arc on line t and an arc on BC. Label the points of intersection as points D and E.Without changing the compass width, place the compass point on point D and draw an arc in the interior of ∠DBE .Keeping the same compass width, place the compass on point E and draw an arc in the interior of ∠DBE to intersect the previously drawn arc. Label the point of intersection as point F.Finally, use the straightedge to draw FD and FE (the other two sides of the square are DB and DE)*Note: To draw a perpendicular line through a segment follow the next steps:
Place the compass point at point B Draw an arc of ANY size that crosses line t twice (one to the left of point B and one to the right)Stretch the compass larger than you first did and place the point at one of the points where the previous arc crossed the line. Draw an arc above the line.Using the same width you used on step 3, place the compass point at the other point in the line.From there draw an arc above the line that crosses the other arc from step 4.Using your straightedge draw a line from the intersection of both arcs and point B and this line will be perpendicular to the line and it will pass through point B.There is an average of 3.5×10−2 kilograms of dissolved salt in each liter of seawater. The Pacific Ocean contains approximately 6.6×1020 liters of seawater. About how many kilograms of dissolved salt are in the Pacific Ocean? Enter your answer, in scientific notation, in the boxes. ×× 10 kg
Quick Answer:
2.31 x 10^19 kg
Change each fraction to a decimal. If the division doesn’t end, round your answer to the nearest hundredth. a. 3⁄4 b. 7⁄16 d. 3⁄5 e. 7⁄40 f. 51⁄20
Answer:
the other person forgot to answer c
Step-by-step explanation:
a 0.75
b 0.44
c 0.6
d 0.6
e 0.18
Which of the following is an example of gameplay in a video game
A: the art of a game
B: the player interacting with the game world and game mechanics
C: the personalities of all the characters
D:all of the above
Answer:
B: the player interacting with the game world and game mechanics
Step-by-step explanation:
explain quantum physics and math
Final answer:
Quantum physics is the branch of physics that deals with small objects and the quantization of various entities, including energy and angular momentum. Mathematics plays a crucial role in explaining quantum physics. It has various applications and impacts our understanding of the universe and technology.
Explanation:
Quantum physics is the branch of physics that deals with small objects and the quantization of various entities, including energy and angular momentum. It focuses on understanding the behavior of subatomic particles and the strange submicroscopic world they inhabit. Quantum mechanics, a part of quantum physics, describes the motion of objects that are atomic or subatomic in size and demonstrates wave-particle duality.
Mathematics plays a crucial role in explaining quantum physics. The mathematics of probability is used to describe the behavior of complex quantum systems. Additionally, equations and mathematical models are used to calculate and predict the behavior of subatomic particles.
Quantum physics has many applications and impacts our understanding of the universe and technology. It helps explain phenomena such as why some materials conduct electricity while others do not. It is also vital in areas such as atomic and nuclear physics, where it is used to study and manipulate the behavior of particles and systems at the quantum level.
According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function? f(x) = 4x5 – 3x
It really is five roots in e2020
Solve for x.
89(54x−36)+2=−34(−40+16x)+90x
Ariel was told the x intercept and the y intercept of a line with a positive slope. Yet, it was impossible for Ariel to find the slope of the line. What can you conclude about this line?
A line has the following standard equation form:
y = m x + b
where m is the slope and b is the y intercept
So if Ariel cannot find the slope, then this would only mean that m = 0, there is no slope. And hence the line is either a straight vertical line or straight horizontal line.
Answer:
There is no slope
Given only the information that a line has x and y intercepts and a positive slope, Ariel cannot directly calculate the slope without knowing the exact values of the intercepts. Knowledge of two distinct points on the line is necessary for calculating the slope.
Explanation:Ariel was told the x intercept and the y intercept of a line with a positive slope. Yet, it was impossible for Ariel to find the slope of the line. What can you conclude about this line? If given only the x and y intercepts without the exact numeric values or additional points, determining the slope directly is challenging because the slope formula, Δy/Δx (change in y over change in x), requires knowledge of at least two distinct points on the line (other than the intercepts without their exact values). However, knowing that a line has both an x and a y-intercept implicitly indicates it is neither vertical nor horizontal, and stating it has a positive slope provides a general direction of the line's angle relative to the axes.
To find the slope, you generally need the coordinates of two distinct points on the line. For instance, if the y-intercept is given as (0, b) and the x-intercept as (a, 0), the slope m can be found by the difference in y values divided by the difference in x values, or (0 - b) / (a - 0) = -b/a. But without knowing a and b's exact values, Ariel cannot calculate the numeric value of the slope. This indicates a limitation in calculating slope with incomplete information about the intercepts' exact numerical values but not an inherent impossibility of the line to have a determinable slope if such values were known.
Which ordered pairs are solutions to the inequality 2y−x≤−6 ?
Select each correct answer.
(0, −3)
(2, −2)
(1, −4)
(6, 1)
(−3, 0)
we have
[tex]2y-x\leq -6[/tex]
we know that
if a ordered pair is a solution of the inequality
then
the ordered pair must satisfy the inequality
we will proceed to verify each case to determine the solution of the problem
case A) [tex](0,-3)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(-3)-0\leq -6[/tex]
[tex]-6\leq -6[/tex] -------> Is True
therefore
the ordered pair [tex](0,-3)[/tex] is a solution of the inequality
case B) [tex](2,-2)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(-2)-2\leq -6[/tex]
[tex]-6\leq -6[/tex] -------> Is True
therefore
the ordered pair [tex](2,-2)[/tex] is a solution of the inequality
case C) [tex](1,-4)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(-4)-1\leq -6[/tex]
[tex]-9\leq -6[/tex] -------> Is True
therefore
the ordered pair [tex](1,-4)[/tex] is a solution of the inequality
case D) [tex](6,1)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(1)-6\leq -6[/tex]
[tex]-4\leq -6[/tex] -------> Is False
therefore
the ordered pair [tex](6,1)[/tex] is not a solution of the inequality
case E) [tex](-3,0)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(0)-(-3)\leq -6[/tex]
[tex]3\leq -6[/tex] -------> Is False
therefore
the ordered pair [tex](-3,0)[/tex] is not a solution of the inequality
therefore
the answer is
[tex](0,-3)[/tex]
[tex](2,-2)[/tex]
[tex](1,-4)[/tex]
At the beginning of an experiment, there are 400 grams of contaminants. Each hour, three-fourths of the contaminants are filtered out.
A. Formulate a recursive sequence modeling the number of grams after "n" hours.
B. Use the model to calculate the amount of contaminants after the third hour of the experiment.
The recursive sequence is:[tex]T_n = \frac 14T_{n-1}[/tex] and there are 25 contaminants left after the third hour of the experiment
The recursive sequenceThe initial number of contaminant is 400.
If 3/4 contaminants are filtered out, there are 1/4 contaminants left.
So, the recursive sequence is:
[tex]T_n = \frac 14T_{n-1}[/tex]
Where T1 = 400
The number of contaminants after the third hourThis means that n = 3.
So, we have:
[tex]T_3 = \frac 14 * T_2[/tex]
[tex]T_2 = \frac 14 * T_1[/tex]
Substitute [tex]T_2 = \frac 14 * T_1[/tex] in [tex]T_3 = \frac 14 * T_2[/tex]
[tex]T_3 = \frac 14 * \frac 14 * T_1[/tex]
Substitute 400 for T1
[tex]T_3 = \frac 14 * \frac 14 * 400[/tex]
Evaluate
[tex]T_3 = 25[/tex]
Hence, there are 25 contaminants left after the third hour of the experiment
Read more about recursive sequence at:
https://brainly.com/question/1275192
#SPJ2
Final answer:
A recursive sequence can be formulated to model the number of grams of contaminants after "n" hours. After plugging in the values, the amount of contaminants after the third hour is 168.75 grams.
Explanation:
A. To formulate a recursive sequence modeling the number of grams after "n" hours, we can start with the initial amount of contaminants of 400 grams and then multiply it by three-fourths each hour. This can be represented by the formula: an = (3/4) * an-1. This formula tells us that to find the amount of contaminants after "n" hours, we multiply the amount after the previous hour by three-fourths.
B. To calculate the amount of contaminants after the third hour of the experiment, we can use the recursive formula. Let's plug in the values: a0 = 400 grams, a1 = (3/4) * a0 = (3/4) * 400 = 300 grams, a2 = (3/4) * a1 = (3/4) * 300 = 225 grams, a3 = (3/4) * a2 = (3/4) * 225 = 168.75 grams.
Therefore, the amount of contaminants after the third hour of the experiment is 168.75 grams.
Which is an equivalent equation solved for y ?
Answer:
4th Option is correct.
Step-by-step explanation:
Given:
x and y are the half length of the largest and smallest diameter of the ellipse.
Area of the Ellipse , a = πxy
To find: Equivalent Equation for y.
Consider,
a = πxy
πxy = a
(πx)y = a
transpose πx to RHS,
[tex]y=\frac{a}{\pi x}[/tex]
y = a ÷ ( πx )
Therefore, 4th Option is correct.
Front-row tickets for a concert cost $60. After every 5 rows, the ticket price goes down by $5. What is the total amount of money generated by a full house? Info: There are 20 rows that increase by 3 seats each time starting with 18.
Hiram sells kites to various corporations. To maintain his business, he must sell an average of 50 kites per month. After 5 months, Hiram has sold 30, 42, 77, 90, and 52 kites in each of the 5 months. How many kites would Hiram have to sell in the 6th month for him to meet his average of 50 kites?
Rajan climbed to a height of 10 ft from the bottom of a climbing wall. He then climbed up an additional 5 ft. What must he do to return to the bottom of the climbing wall?
Select from the drop-down menus to correctly complete the statement.
Rajan must climb _____ _____ ft to return to the bottom of the climbing wall.
1. Rajan must climb up, down, left, right? (Which way is it)
2. 5 ft, 10 ft, 15 ft, 20 ft
Answer:
Rajan must climb down 15 feet to return to the bottom of the climbing wall.
Step-by-step explanation:
Rajan climbed to a height of 10 ft from the bottom of a climbing wall.
He then climbed up an additional 5 ft.
So, in total he climbed [tex]10+5=15[/tex] feet
If Rajan wants to return to the bottom, he must climb down 15 feet.
Answer:
Rajan must climb down 15 feet to return to the bottom of the climbing wall.
Leanne is trying to choose between two party dresses that originally cost $120 one dress is on 1/4 off and the $40 what is the price of less expensive dress
$8 euros were worth $9 and $24 euros were worth $27 write an equation of the form y=kx to show the relationship between the number of euros and the value in dollars.
Jack purchases 12 gallons of gas on Monday. He uses 2/3 of the amount purchased commuting to and from work during the week and an additional 2 gallons running errands. How many gallons of gas does john use from work and errands?
Answer: Using operations with fractions, John uses 10 gallons from work and errands.
Solution:
Jack purchases 12 gallons of gas on Monday.
He uses 2/3 of the amount purchased commuting to and from work during the week:
(2/3)(12)=(2/3)(12/1)=(2*12)/(3*1)=24/3=8
Then John uses 8 gallons commuting to and from work during the week.
And an additional 2 gallons running errands.
John uses in total from work and errands= 8 gallons+2 gallons
John uses in total from work and errands= 10 gallons
Put the numbers in order from smallest to largest.
5.0
4.5
3.1
4.9
3.6
4.2
HEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Drag an answer to each box to complete this paragraph proof.
Given: ∠PQR and ∠RQS are supplementary angles and m∠PQR=115°
Prove: ∠RQS is an acute angle.
It is given that ∠PQR and ∠RQS are supplementary angles. So, m∠PQR+m∠RQS=180° using the ________ . It is also given that m∠PQR=115° . Using the substitution property of equality, ________ + m∠RQS=180° . Using the subtraction property of equality, m∠PQR=65° . Therefore, ∠RQS is an acute angle by ________ .
A. definition of complementary angles
B. definition of supplementary angles
C. definition of acute angle
D. definition of obtuse angle
E. 180°
F. 115°
Image uploaded below:
V V V
Answer: The correct options for blank 1,2 and 3 are B, F and C respectively.
Explanation:
It is given that the ∠PQR and ∠RQS are supplementary angles and ∠PQR=115°.
The two angles are called supplementary angles if they are lies on the same arc of a straight line and their sum is 180 degree.
Since it is given that ∠PQR and ∠RQS are supplementary angles, so by the definition of supplementary angles we can say that their sum is 180 degree.
[tex]\angle PQR+\angle RQS=180^{\circ}[/tex] .... (1)
Therefore, the correct option for first blank is option B.
It is given that ∠PQR=115°.
Using the substitution property of equality, the equation (1) can be written as,
[tex]115^{\circ}+\angle RQS=180^{\circ}[/tex]
Therefore, the correct option for second blank is option F.
Using the subtraction property of equality, ∠PQR=65° .
An angle less that 90 degree is called an acute angle and the an angle more than 90 degree but not more that 180 degree is called an obtuse angle.
Since 65 is less than 90, so by the definition of acute angle the ∠RQS is an acute angle.
Therefore, the correct option for third blank is option C.
Which table shows a linear function?
Thank you!
Nine friends will equally share 12 glasses of punch how many glasses of punch will each friend get A.3/4 B.1/3 C.4/3 D.3
Match the following items.
1. 2x + x + 4 = -17
subtraction
2. 3x + 4 =-17
division
3. 3x =- 21
combine like terms
4. x = -7 Given
Answer and explanation:
To find : Match the following items.
Solution :
We arrange all steps by steps,
Step 1 - Given
[tex]2x + x + 4 = -17[/tex]
Step 2 - Combine like terms,
[tex]3x+ 4 = -17[/tex]
Step 3 - Subtract 4 both side,
[tex]3x=-21[/tex]
Step 4 - Divide by 3 both side,
[tex]x=-7[/tex]
An equation is a mathematical statement that is made up of two expressions connected by an equal sign.
The following are matched:
1. 2x + x + 4 = -17 ------------ ( Given )
2. 3x + 4 =-17 ----------(combine like terms)
3. 3x =- 21 -----------( subtraction )
4. x = -7 -------------( division )
What is an equation?An equation is a mathematical statement that is made up of two expressions connected by an equal sign.
We have,
Given,
2x + x + 4 = -17
We will combine the like terms.
3x + 4 = -17
We will subtract 4 on both sides.
3x = -17 - 4
3x = -21
Divide both sides by 3.
x = -21/3
x = -7
Thus,
1. 2x + x + 4 = -17 ------------ ( Given )
2. 3x + 4 =-17 ----------(combine like terms)
3. 3x =- 21 -----------( subtraction )
4. x = -7 -------------( division )
Learn more about equations here:
https://brainly.com/question/27996921
#SPJ2
NEED ASAP!!!!
In quadrilateral ABCD, diagonals AC and BD bisect one another:
What statement is used to prove that quadrilateral ABCD is a parallelogram?
Angles ABC and BCD are congruent.
Sides AB and BC are congruent.
Triangles BPA and DPC are congruent.
Triangles BCP and CDP are congruent.
Answer:Triangles BPA and DPC are congruent is used to prove that ABCD is a parallelogram.
Explanation:Here, we have given a quadrilateral ABCD in which diagonals AC and BD bisect each other.
If P is a an intersection point of these diagonals
Then we can say that, AP=PC and BP=PD ( by the property of bisecting)
So, In quadrilateral ABCD,
Let us take two triangles, [tex]\triangle BPA[/tex] and [tex]\triangle DPC[/tex].
Here, AP=PC
BP=PD,
[tex]\angle APB=\angle DPC[/tex] ( vertically opposite angles.)
So, By SAS postulate,[tex]\triangle BPA\cong \triangle DPC[/tex]
Thus AB=CD ( CPCT).
Similarly, we can prove, [tex]\triangle APD\cong \triangle BPC[/tex]
Thus, AD=BC (CPCT).
Similarly, we can get the pair of congruent opposite angle for this quadrilateral ABCD.
Therefore, quadrilateral ABCD is a parallelogram.
Note: With help of other options we can not prove quadrilateral ABCD is a parallelogram.
The congruence of triangles BPA and DPC, proven through the Side-Angle-Side postulate or other congruency postulates, can be used to prove that quadrilateral ABCD is a parallelogram when diagonals AC and BD bisect one another.
The statement used to prove that quadrilateral ABCD is a parallelogram when diagonals AC and BD bisect one another is that triangles BPA and DPC are congruent. The congruence of these triangles can be shown through the Side-Angle-Side (SAS) postulate or other congruency postulates depending on a given figure, and this property that diagonals bisect each other is a defining trait of a parallelogram. Therefore, by showing the congruence of triangles BPA and DPC, we can deduce that ABCD is a parallelogram.
what are the domain range and asymptote of h(x)=(1.4)^x+5
domain: {x | x is a real number}; range: {y | y > 5}; asymptote: y = 5
A crew of ten workers was hired to complete a job in 8 days. After working for two days, there was a new request to complete this job in two days. How many more workers need to be hired to finish this job in 2 days?
Answer:
29 more workers are needed.
Step-by-step explanation:
Let us assume that the 10 workers, working at their normal rate would finish the job in exactly 8 days.
The rate of working for 1 worker is:
[ 1/10 of the job ] / [ 8 days ] = [ 1 job ] / [ 80 days ]
This is also [ 1/80 of the job ] / [ 1 day ]
In 2 days, the fraction of the job that gets done is:
[tex]2\times \frac{1}{80}=\frac{1}{40}[/tex]
Job left = [tex]1-\frac{1}{40} =\frac{39}{40}[/tex]
Now the rate has to be :
[tex]\frac{\frac{39}{40} }{2} =\frac{39}{80}[/tex]
Now, let w be the additional number of workers needed.
We get:
[tex]\frac{10+w}{80}=\frac{39}{80}[/tex]
Solving for w;
[tex]10+w=39[/tex]
[tex]w=39-10[/tex]
w = 29
Therefore, 29 more workers are needed.
-------------------------------------------------------------------------------------
There can be another approach as well.
Fraction of the job done by 10 workers in 2 days = 1/4
Remaining fraction = 1-1/4 = 3/4
Lets say W workers are needed more.
So, we can say that 3/4 of the work is to be done by 10+W workers.
Hence, it will take a total of 30 workers to complete the job.
Making it additional 20 workers.