For some Gram-negative bacterial infections, antibiotic treatment can cause a more severe reaction than that caused by the base infection. This is often due to the release of endotoxin from the cell. Endotoxin, or LPS, is harmless in intact pathogens but can cause dangerously low blood pressure and high fever once released.

Which antibiotic here would you recommend against a bacterial pathogen that encodes LPS?

a) polymyxin, because it inserts into the cell membrane, disrupting homeostasis.

b) tetracycline, because it targets bacterial ribosomes.

c) vancomycin, because it disrupts cell wall formation.

d) ethambutol, because it interreupts arabinogalatcan.

Answers

Answer 1

Answer:

Polymyxin because, it inserts into the cell membrane and disrupts homeostasis.

Explanation:

Antimicrobial effect reacts with the cell membrane of the gram negative bacteria and causes disruption in their cell membrane by creating pores.

The cell membrane of bacteria release endotoxin for creating defense mechanism.

But the effect of certain antimicrobial peptide disrupt the effect of membrane by releasing electrostatic interaction and creates membrane pores.

The interaction between the microbial peptide and the cell membrane causes disruption of the cell.

Thus polymyxin is used to treat against the gram negative bacteria as they breaks the cell membrane of the bacteria.


Related Questions

what determines the type of soil that is created when it is formed?

A) The type of rock and minerals in the parent material

B) The types of organisms living in the soil

C) The altitude of the location of soil formation

D) The amount of time it takes to create the soil

Answers

Answer:

A.

Explanation:

The factors that affect soil formation are climate, rock type, slope, time, and biological activity. Differences in these factors will produce different types of soil. Soil type determines what can grow in a region. Humus, the decayed remains of living organisms, is essential for soils to be fertile.

The type of rock and minerals in the parent material determine the type of soil created. So the correct option is A.

What is the process of soil formation?

The soil is a very essential one of our natural resources. Soil is important for the growth of vegetation that we depend on for food. It provides the plants with stability and nutrition. Soil is also a habitat for many microorganisms. It is also important for earthworms, rats, and a lot of other subterranean species that are present on earth.

Parent material is the material from which soil is formed. The source of all soil minerals is the rocks. The parent material is weathered chemically or physically. It is then transported and then deposited for the formation of the layers of soil. The parent material is usually the bedrock. Soil can also get transported because of natural factors like wind and water.

Pedogenesis is the name of the process for the formation of soil. It is first initiated by the weathering of rocks. The variations are developed according to the weather conditions.

Therefore, the correct option is A.

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________ is the involuntary expulsion of the contents of the stomach and duodenum out the mouth

Answers

Answer:

Vomiting

Explanation:

Vomiting is the involuntary expulsion of the contents of the stomach and duodenum out the mouth

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For the numbered site below, select the option that places them in the correct order.
1)The ribosome binds to the m RNA and uses tRNAs to translate mRNA into the corresponding amino acid polypeptide sequence.
2)The spliceosome removes introns
3)The primary structure of the polypeptide chain undergoes hierarchical foldings to form the tertiary structure.
4)RNA polymerase binds to the promoter region of a gene and initiates transcription

Answers

Answer:

The correct order is:

4, 2, 1, 3

Explanation:

The list of options in this question depicts gene expression which involves transcription and translation processes.

Option 4 is simply describing the initial step of transcription where the enzyme RNA polymerase binds to the promoter region of a gene on the DNA and signals the initiation of transcription. RNA polymerase synthesizes a complementary strand of mRNA using the DNA it binds to as template.

Option 2 is a post-transcriptional process called SPLICING, which is the removal of the non-coding regions of a gene called INTRONS by enzymes called SPLICEOSOMES. This occurs in eukaryotic cell before the mRNA leaves the nucleus for the cytoplasm where translation will take place.

Option 1 signals the commencement of translation where a complex of ribosomal RNA and other proteins called RIBOSOME attaches to the mRNA molecule and uses the anticodons present in the tRNA to read the mRNA codons in order to carry the corresponding amino acid to the ribosome. The anticodons of the tRNA are complementary to the mRNA codon. At the end of translation, an amino acid sequence called polypeptide (future protein) will be released.

Option 3 tells us what happens after the translation process. The amino acids in the newly released protein are arranged in such a way that they make the protein a primary structure. The amino acids undergo certain modifications like folding that changesges the protein's structure from primary to tertiary.

Answer: 4213

The entire process is protein synthesis for gene expression.

The process  of  transcription  begins when the encoded protein information  from the DNA is transferred to the  mRNA.It begins when enzyme RNA polymerase bind with promoter region ( the point where the process of transcription begins) of a gene and initiates transcription.,the point where the process of transcription begins. The DNA double helix unwinds, the mRNA align and complementary paring of the bases occurs.

This is followed with the removal of noncoding part(introns) of the mRNA transcripts prior to translation  where;The spliceosome removes introns. This is essential because only the encoded part which contain the needed protein to be  transcribed is selected.

The mRNA is released, and leave the nucleus through the nuclear pore to the cytoplasm.In the cytoplasm the ribosomes with its two sub-units large and small  serve as templates for the mRNA with its anti codons and pairing  with the tRNA codons  in a complementary pairing for translation of amino acids to polypeptide sequence.

In the process of translation polypeptide chains of amino acids are formed as the complimentary  bases paired up to synthesize protein. Different levels of proteins are formed as the primary structure of the polypeptide chain undergoes hierarchical foldings to form the tertiary structure.

Explanation:

For a given gene in a population, there are two alleles, A and a. The frequency of the dominant homozygote, AA, is 0.50; the frequency of the heterozygote, Aa, is 0.20; and the frequency of the recessive homozygote, aa, is 0.30. What is the frequency of the recessive a allele?

Answers

Answer:0.548

Explanation:

In a population the genotype frequency =p2+2pq+q2=1

gene frequency =p+q=1

Where p is the homozygous allele(A)

q is the recessive allele(a)

Pq represent the heterozygote allele

Given that p2=0.50

2pq=0.20

q2=0.30

To get q=√0.30

q=0.548

The gene frequency for homozgous reccessive allele a is 0.548

At 5 pm, there were 20 bacterial cells in a test tube. Knowing that the generation time is 6 minutes, how many bacteria do you expect there will be in the test tube at 5:30 pm? Bacteria reproduce by binary fission, in which one bacterium becomes two bacteria.

Answers

The question is incomplete as it does not have the options which are:

120 Cells 640 Cells 1280 Cells 56 Cells.

Answer:

640 Cells

Explanation:

The bacterial cell divides by the process of binary fission which divides a parent bacterial cell into two daughter cells.

In the given condition, the generation time or the average time between the two generations is 6 minutes. When he analyzed the population at 5 pm, he found 20 bacterial cells.

At 5.30 pm, the bacterial cell will have 640 cells as

1. After every 6 minute the population doubles

2. The minute's difference between 5 pm to 5.30 pm is 30 minutes.

3. Since 1 generation time-6 min therefore 30 minutes will have = 30/ 6 = 5 generation.

4. The bacterial cell will be calculated using formula

[tex]2^{number of generations}[/tex] x an initial number of bacteria in a population, therefore, [tex]2^{5}[/tex] x 20 = 640 bacterial cells.

Thus, 640 Cells is the correct answer.

his geologic era is known as the age of aquatic plants and animals. a. Precambrian b. Mesozoic c. Cenozoic d. Paleozoi

Answers

Answer:d.Paleozoic Era

Explanation:

Paleozoic Era is hallmarked by climate, animals & plants.

This Era includes the Ordovician Period, Silurian Period and the Devonian Period.

The Silurian Period is one during this era where aquatic plants and animals evolved.

The spread of infectious diseases across borders ties into the social aspects of globalization. What percentage of people in Botswana have HIV? (Hint: one place you can find this answer is within Botswana's country profile on the Country Profile Tab/Tile. Drill into Society and Health).

Answers

Answer:

The percentage of people in Botswana that have HIV is 24. 83 percent .

Explanation:

Lesotho and Swaziland are the only country who is higher than Botswana in terms of terms of HIV prevalence rate in the world between adults aged from 15 to 49 years .

This condition has led to a major depletion in Botswana's workforce, because a good number of productive adults (18 to 50) developed AIDS and are unable to work .

These activities change heart rate by changing the balance of parasympathetic and sympathetic stimulation of the heart. Sort each of the activities according to whether it decreases or increases heart rate. Drag the appropriate items to their respective bins.

Answers

Question is incomplete i have added complete question in picture format see attachment.

Answer with Explanation:

Heart Rate Decreases in following conditions:

When we are Lying downWhen our stomach is Digesting a meal

Reason:

Decrease in heart rate results only when we are taking rest.

Heart Rate Increases in following conditions:

When we are Standing upWhen we are in Fright or AngerWhen we are doing Exercise

Reason:

Increase in heart rate results only when our body is in moving condition.

A transaction in which two or more organizations or people give and receive something of value is called ________.

Answers

Answer:

Exchange

Explanation:

A transaction in which two or more organizations or people give and receive something of value is called Exchange

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Coal is used to produce energy. The harmful gases produced by coal are cleaned up by a method which needs a large amount of limestone. Predict and explain the long term effect on the environment of obtaining and using limestone.

Answers

Wet Scrubbers use limestone to clean the large amount of gases produced by combustion of coal.

Explanation:

It is true that coal produces energy but combustion of coal leads to the production of harmful gases that affects the environment and also causes global warming. Wet scrubbers also known as flue gas desulfurization systems, removes sulfur dioxide, a significant cause of acid rain, by spraying flue gas with limestone and water.

The mixture reacts with the SO2 to form synthetic gypsum, a component of drywall. Long term use of Limestone can affect the conditions of ground water.

In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant gene R is present at one locus and at least one dominant gene P is present at a second locus (genotype R_P_). A rose comb is produced when at least one dominant gene is present at the first locus and two recessive genes are present at the second locus (genotype R_pp). A pea comb is produced when two recessive genes are present at the first locus and at least one dominant gene is present at the second (genotype rrP_). If two recessive genes are present at the first and the second locus (rrpp), a single comb is produced. Give genotypes for comb shape of the parents in the crosses listed below. a. Walnut crossed with single produces 1 walnut, 1 rose, 1 pea, and 1 single offspring. b. Rose crossed with pea produces 20 walnut offspring. c. Pea crossed with single produces 1 single offspring. d. Rose crossed with pea produces 2 walnut, 1 single, and 1 pea offspring. e. Rose crossed with single produces 31 rose offspring. f. Rose crossed with single produces 10 rose and 11 single offspring.

Answers

Answer and Explanation:

Available data:

Comb shape is determined by genes at two loci (R, r and P, p).The walnut comb genotype is R_P_. The rose comb genotype is R_pp. The pea comb genotype is rrP_. The single genotype is rrpp.

a. Walnut crossed with single produces 1 walnut, 1 rose, 1 pea, and 1 single offspring:

Parental)             RrPp       x          rrpp

Gametes)   RP   Rp   rP   rp     rp   rp   rp   rp

Punnet Square)      RP       Rp     rP        rp

                     rp   RrPp    Rrpp   rrPp   rrpp

                     rp    RrPp    Rrpp   rrPp   rrpp

                     rp    RrPp    Rrpp   rrPp   rrpp

                     rp    RrPp    Rrpp   rrPp   rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

b. Rose crossed with pea produces 20 walnut offspring.

Parental)              RRpp       x          rrPP

Gametes)   Rp   Rp   Rp   Rp     rP   rP   rP   rP

Punnet Square)      Rp       Rp     Rp        Rp

                     rP    RrPp    RrPp   RrPp   RrPp

                     rP    RrPp    RrPp   RrPp  RrPp

                    rP    RrPp    RrPp   RrPp   RrPp

                     rP    RrPp    RrPp   RrPp   RrPp

F1 phenotype: 100% walnut.

F1 genotype: 16/16 RrPp.

c. Pea crossed with single produces 1 single offspring.

This is not possible, because the pea genotype involves at least one dominant allele P. There are two possible crosses: rrPp x rrpp, which must produce half of the progeny pea and the other half single, or rrPP x rrpp which produce a whole pea progeny with no single offspring.  

Parental)              rrPp       x          rrpp

Gametes)   rP   rp   rP   rp     rp   rp   rp   rp

Punnet Square)     rP       rp       rP      rp

                     rp   rrPp    rrpp   rrPp   rrpp

                    rp    rrPp    rrpp   rrPp   rrpp

                     rp    rrPp    rrpp   rrPp   rrpp

                     rp    rrPp    rrpp   rrPp   rrpp

F1 phenotype: 50% pea, and 50% single.

F1 genotype: 8/16 rrPp, 8/16 rrpp.

d. Rose crossed with pea produces 2 walnut, 1 single, and 1 pea offspring.

This is not possible, because having one of the parents with a rose phenotype  involves at least one R allele, which means that there must be rose phenotype in the progeny.

Parental)             Rrpp       x          rrPp

Gametes)   Rp   Rp   rp   rp     rP   rP   rp   rp

Punnet Square)     Rp       Rp       rp      rp

                     rP   RrPp   RrPp   rrPp   rrPp

                     rP   RrPp    RrPp   rrPp   rrPp

                     rp    Rrpp    Rrpp   rrpp  rrpp

                     rp   Rrpp    Rrpp   rrpp   rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

e. Rose crossed with single produces 31 rose offspring.

Parental)              RRpp       x          rrpp

Gametes)   Rp   Rp   Rp   Rp     rp   rp   rp   rp

Punnet Square)     Rp       Rp       Rp      Rp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

F1 phenotype: 100% rose (31 individuals equal 100% of the progeny).

F1 genotype: 16/16 Rrpp.

f. Rose crossed with single produces 10 rose and 11 single offspring.

Parental)              Rrpp       x          rrpp

Gametes)   Rp   Rp   rp   rp     rP   rP   rp   rp

Punnet Square)      Rp       Rp       rp      rp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

F1 phenotype: 50% rose, 50% single.

F1 genotype: 8/16 Rrpp, 8/16 rrpp.

What was the term in the Gilded Age for a new emasculated condition that marked by depression,indigestion, hypochondria, and extreme nervousness?

Answers

Answer:

Neurasthenia

Explanation:

The gilded age refers to the last decades of the nineteenth century that is between the 1870s to about 1900.

The medical term which was used during the Gilded age to refer to the condition caused by the weakness of the nerves or nervous breakdown or nervous illness is Neurasthenia.

The Neurasthenia was marked by the symptoms of the depression, the fight or flight responses such as indigestion, the nervousness and the irritability.

Thus, Neurasthenia is the correct answer.

Programs at the ____________ level of the public health pyramid are aimed at changing the cultural competence of the workforce and the capacity of the workforce to address health disparities and cultural diversity.

Answers

Answer:

Direct health care services.

Explanation:

The health is one of the most important factor for all the individuals of the nation. The individual should be fit and healthy physically, mentally as well as socially.

The government has started the health care services to provide free health services or at low cost. These services includes the regular vaccination, health check up camps, address the health disparities and proper medication facility.

Thus, the answer is direct health care services.

The correct term to fill in the blank is organizational.

The public health pyramid, also known as the Spectrum of Prevention, is a framework that outlines various levels of intervention to improve public health outcomes. At the organizational level of the pyramid, programs are designed to change the cultural competence of the workforce and enhance their ability to address health disparities and cultural diversity. This level focuses on the policies, practices, and cultural norms within organizations that can influence health behaviors and outcomes. By implementing programs at this level, organizations can create supportive environments that promote health equity and effectively serve diverse populations. These programs might include cultural competency training, diversity and inclusion initiatives, and policy development that prioritize equity in healthcare deliver.

What other evidence could you use to analyze evolutionary relatedness among gibbons, monkeys, and humans?

Answers

Answer:

the amino acid sequences of other proteins from gibbons, monkeys, and humans

Explanation:

To analyze evolutionary relatedness among gibbons, monkeys, and humans, scientists use a variety of evidence beyond just genetic data. Here are some key pieces of evidence: Fossil Records, Comparative Anatomy, Behavioral Studies, Molecular Evidence, and Biogeography.

Fossil Records: The fossil record provides a rich source of information about ancient species and their evolutionary history. By examining the remains of primates from different time periods, scientists can establish links between extinct and modern species.

Comparative Anatomy: Comparing the physical structures of gibbons, monkeys, and humans can reveal evolutionary relationships. Homologous structures, such as the arrangement of bones in limbs or the structure of organs, can indicate shared ancestry.

Behavioral Studies: Ethology, the study of animal behavior, can offer insights into common behaviors or social structures among these species. Similarities in behavior can suggest shared evolutionary traits.

Molecular Evidence: In addition to genetics, other molecular evidence like protein sequencing and the study of non-coding DNA regions can reveal similarities and differences in the genomes of these species.

Biogeography: Analyzing the distribution of these primates across different continents can provide insights into their evolutionary history and past connections.

By integrating multiple sources of evidence, scientists can construct a more comprehensive understanding of the evolutionary relatedness among gibbons, monkeys, and humans, revealing their shared ancestry and the branching points in their evolutionary tree.

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