A rectangle has an area of k2 + 19k + 60 square inches. If the value of k and the dimensions of the rectangle are all natural numbers, which statement about the rectangle could be true?
Find all solutions in the interval [0, 2pi): sin5x+sinx=sin3x
Simplify 10x - 3x + (-5x).
-2x
2x
18x
-18x
Use these values to solve this problem. X=2,y=3,z=4. 21xy/x+z
solve for x in the diagram (right triangle smallest side 9,bottom side 12,longest x)
Name a pair of supplementary angles.
A. angle A E B and angle C E D
B. angle A E B and angle B E D
C. angle A E C and angle B E D
D. angle B E A and angle C E B
Answer:
B.angle AEB and angle BED.
Step-by-step explanation:
We are given that a diagram .
We have to find a pair of supplementary angles.
Supplementary angles:The pair of angles whose sum is 180 degrees is called supplementary angles.
From given diagram
[tex]\angle AEB+\angle BED=180^{\circ}[/tex]
[tex]\angle AEC+\angle CED=180^{\circ}[/tex]
Hence, option B is true.
Answer:B.angle AEB and angle BED.
(05.02 LC)
Which equation does the graph below represent?
y = fraction 1 over 4x
y = 4x y
fraction negative 1 over 4x
y = −4x
Answer:
y=-4x
Step-by-step explanation:
WE need to write the equation for the given graph
In the graph y intercept is (0,0)
The equation of linear graph is y=mx+b
where m is the slope and b is the y intercept
From the given graph y intercept is 0 so b=0
to find slope pick two points from the graph
(0,0) and (1, -4)
slope = [tex]\frac{y_2-y_1}{x_2-x_1} = \frac{-4-0}{1-0} = -4[/tex]
m=-4 and b=0
So the equation becomes
y= -4x+0
y= -4x
A triangle has one leg measuring 10 inches and the hypotenuse measuring 20 inches. the other leg measures 10\sqrt[]{3} 10 3 inches. what type of triangle is represented here?
If y = 4x + 3 were changed to y = -4x + 3, how would the graph of the new function compare with the original?
Answer:
The graph of y=-4x+3 will be as a reflexion in a mirror of y=4x+3
Step-by-step explanation:
y=4x+3 y=-4x+3
. .
. .
. .
Tiffany put a $1550 item on layaway by making a 20% down payment and agreeing to pay $120 a month. How many months sooner would she pay off the item if she increased her monthly payment to $180?
A. 18 months sooner
B. 11 months sooner
C. 4 months sooner
D 7 months sooner
1550*0.8=1240
1240/120 = approximately 11 months to pay off
1240/180=approximately 7 months to pay off
11-7 =4
so it would be paid off 4 months sooner, so C is the answer
Option: C is the correct answer.
C. 4 months sooner.
Step-by-step explanation:Total amount of the item is: $ 1550
Also, Tiffany paid 20% of the amount by down payment.
Hence, the amount left to pay after the down payment is:80% of total amount.
i.e. 0.80 of total amount.
= 0.80×1550
= $ 1240
Now the number of month it will take if she pay $ 120 a month is:
[tex]=\dfrac{1240}{120}=10.3333[/tex]
which is approximately equal to 11 months.
Similarly, the number of month it will take if she pay $ 180 a month is:
[tex]=\dfrac{1240}{180}=6.8889[/tex]
which is approximately equal to 7 months.
Hence, the number of months sooner she will pay off is:
11-7=4 months.
A bond payable is similar to which of the following?
A Bond payable is are likely similar to note payable. They are similar because they have both written premises to pay the interest and the principal amount on a specific futures dates. They are both liability and also the interest is accrued in current liability.
The answer to your question is "Notes Payable."
Which function represents g(x), a reflection of f(x) = 6(1/3)^x across the y-axis?
Answer:
its b
Step-by-step explanation:
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Determine which ordered pair is NOT a solution of y=3x-8.
a.
(8, 16)
b.
(3, 4)
c.
(–6, –26)
d.
(–10, –38)
A group of hikers are 675 ft from the base of Guadalupe Peak, which is 8,749 ft tall. What is the angle of elevation when they look at the top of the Peak? Round to the nearest hundredth.
What are the amplitude, period, and midline of f(x) = −7 sin(4x − π) + 2?
This is an example of a sine wave function. A given sine wave function has a standard form of:
y = A sin [B (x + C)] + D
Where,
A = absolute value of amplitude
2 π / B = the period of the sine wave
D = is the midline of y
C = phase of the sine wave
Rewriting the given equation into this form will yield:
f (x) = -7 sin[4 (x – π / 4)] + 2
Therefore from this form, we can get the answers:
Amplitude = 7
Period = 2π / 4 = π / 2
Midline = 2
If there is a 0.3% chance of something happening one day, what is the possibility of it happening throughout twenty days?
Find three consecutive odd integers with the sum of 51.
Find the equation of the tangent line of f^-1(x) at the point where it intersects the x-axis
How many three-letter "words" can be made from 5 letters "fghij" if repetition of letters (a) is allowed?
If a rope 36 feet long is cut into two pieces in such a way that one piece is twice as long as the other piece, how long must the long piece be
rope = 36 feet
first piece = x
2nd piece = 2x ( twice as long as the first piece)
3x=36
x=12
first piece = 12 feet
2nd piece = 2 x 12 = 24 feet
What is the simplified expression for ?
What is the sum of the arithmetic sequence 3, 9, 15..., if there are 26 terms?
9 - 3 = 6, 15-9 = 6 the difference is 6, So d = 6
First term: a1 = 3
Sn = n*(a1 + an)/2
Sn = n*(a1 + a1 + (n-1)*d)/2
Sn = n*(2*a1 + (n-1)*d)/2
substitute 26 for n
S26 = 26*(2*a1 + (26-1)*d)/2
substitute 3 for a1
S26 = 26*(2*3 + (26-1)*d)/2
substitute 6 for d
S26 = 26*(2*3 + (26-1)*6)/2
S26 = 2,028
Solve |x| + 7 < 4.
........................
Write the equation in logarithmic form.
25 = 32
A. log32 = 5 • 2
B. log232 = 5
C. log32 = 5
D. log532 = 2
The equation in logarithmic form is B.log₂32 = 2.
To convert the equation 2⁵ = 32 into logarithmic form, you need to identify the base, the exponent, and the result. The given equation can be interpreted as 2 raised to the power of 5 equals 32.
The general form of a logarithmic equation is: log_base (result) = exponent
In this specific case, we have:
base = 2
result = 32
exponent = 5
Putting it into the logarithmic form, we get: log₂32 = 5
So, the correct option is: B.log₂32 = 2
For Jane's Uber business, she charges $5 initial fee and $0.10 a mile. Joe's Uber business charges $4 initial fee and $0.20 per mile.
1. Write a function for jane's Uber buisiness
2. write a function for joe's Uber business
The linear equations to calculate the earning by Jane and Joe's Uber business per ride, given the initial fee and charge per mile:
Jane: y = 5 + 0.1x
Joe: y = 4 + 0.2x
What is a linear equation ?A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation.
For Jane's Uber business, she charges $5 initial fee and $0.10 a mile.
Let Jane's earning from a ride be $y.
Let the number of miles she drove in that ride be x miles.
Linear equation to calculate the earning from a ride given the number of miles rode: y = 5 + 0.1x
For Joe's Uber business, he charges $4 initial fee and $0.20 a mile.
Let Joe's earning from a ride be $y.
Let the number of miles he drove in that ride be x miles.
Linear equation to calculate the earning from a ride given the number of miles rode: y = 4 + 0.2x
Learn more about linear equation here
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Student identification codes at a high school are 4-digit randomly generated codes beginning with 1 letter and ending with 3 numbers. there are 26,000 possible codes. what is the probability that you will be assigned the code a123?
Line EF has an equation of a line y = −2x + 7. Which of the following could be an equation for a line that is perpendicular to line EF?
y = 2x − 3
y = 1 over 2x − 3
y = −2x − 3
y = −1 over 2x − 3
Answer:
[tex]y=\frac{1}{2} x-3[/tex]
Step-by-step explanation:
Step 1
Find the slope of the line EF
we have
[tex]y=-2x+7[/tex]
The slope of the line EF is equal to
[tex]m=-2[/tex]
Step 2
Find the slope of the line perpendicular to the line EF
we know that
If two lines are perpendicular, then the product of its slopes is equal to minus one
so
[tex]m1*m2=-1[/tex]
we have
[tex]m1=-2[/tex] -----> slope of the line EF
Find the value of m2
substitute
[tex](-2)*m2=-1[/tex]
[tex]m2=1/2[/tex]
therefore
the equation [tex]y=\frac{1}{2} x-3[/tex] could be an equation for a line that is perpendicular to line EF
Assume that adults have iq scores that are normally distributed with a mean of 100100 and a standard deviation of 15. find the third quartile upper q 3q3, which is the iq score separating the top 25% from the others.
Final answer:
The third quartile (Q3) of IQ scores, which separates the top 25% of scores, is approximately 110.125 for a normal distribution with a mean of 100 and a standard deviation of 15.
Explanation:
To find the third quartile (Q3) of IQ scores, which is the value that separates the top 25% from the others in a normally distributed data set, we use the properties of the normal distribution. The mean IQ score is 100 and the standard deviation is 15. Q3 corresponds to the 75th percentile in a normal distribution.
To find the third quartile (Q3), we often refer to the z-score table or use a statistical software or calculator that can handle normal distribution calculations. The z-score corresponding to the 75th percentile is approximately 0.675. We can then use the formula for z-scores:
Q3 = mean + z*(standard deviation)
Q3 = 100 + 0.675*15
Q3 = 100 + 10.125
Q3 = 110.125
Thus, the third quartile IQ score, separating the top 25% of scores from the rest, is approximately 110.125.
To find Q3 for IQ scores (mean 100, SD 15), calculate 75th percentile: [tex]\( Q3 = 100 + 0.674 \times 15 = 110.11 \).[/tex]
To find the third quartile (upper Q3) of IQ scores, we need to determine the IQ score that separates the top 25% from the rest. Given that IQ scores are normally distributed with a mean of 100 and a standard deviation of 15, we can use the properties of the normal distribution to find this value.
1. Identify the z-score corresponding to the third quartile (Q3):
- The third quartile (Q3) corresponds to the 75th percentile of the normal distribution.
- Using the standard normal distribution table or a calculator, the z-score for the 75th percentile is approximately 0.674.
2. Convert the z-score to an IQ score:
- Use the formula for converting a z-score to a value in a normal distribution:
[tex]\[ X = \mu + z \sigma \][/tex]
where:
- [tex]\( \mu \)[/tex] is the mean (100)
- [tex]\( \sigma \)[/tex] is the standard deviation (15)
- [tex]\( z \)[/tex] is the z-score (0.674)
3. Calculate the IQ score:
[tex]\[ Q3 = 100 + (0.674 \times 15) = 100 + 10.11 = 110.11 \][/tex]
Therefore, the third quartile (Q3) IQ score, which separates the top 25% from the others, is approximately 110.
How much money should be deposited today in an account that earns 6% compounded monthly so that it will accumulate to $9000 in three years?
Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p. n equals 123n=123, p equals 0.85
The mean of the binomial distribution is [tex]\( 104.55 \)[/tex], the variance is [tex]\( 15.6825 \)[/tex], and the standard deviation is approximately .
To find the mean, variance, and standard deviation of a binomial distribution with given values of [tex]\( n \)[/tex] and [tex]\( p \)[/tex], we use the following formulas:
Mean [tex](\( \mu \)) = \( n \times p \)[/tex]
Variance [tex](\( \sigma^2 \)) = \( n \times p \times (1 - p) \)[/tex]
Standard Deviation [tex](\( \sigma \)) = \( \sqrt{\text{Variance}} \)[/tex]
Given:
[tex]\( n = 123 \)[/tex]
[tex]\( p = 0.85 \)[/tex]
Let's calculate each of these:
Mean [tex](\( \mu \))[/tex]:
[tex]\( \mu = n \times p \)[/tex]
[tex]\( \mu = 123 \times 0.85 \)[/tex]
[tex]\( \mu = 104.55 \)[/tex]
Variance [tex](\( \sigma^2 \))[/tex]:
[tex]\( \sigma^2 = n \times p \times (1 - p) \)[/tex]
[tex]\( \sigma^2 = 123 \times 0.85 \times (1 - 0.85) \)[/tex]
[tex]\( \sigma^2 = 123 \times 0.85 \times 0.15 \)[/tex]
[tex]\( \sigma^2 = 104.55 \times 0.15 \)[/tex]
[tex]\( \sigma^2 = 15.6825 \)[/tex]
Standard Deviation [tex](\( \sigma \))[/tex]:
[tex]\( \sigma = \sqrt{\sigma^2} \)[/tex]
[tex]\( \sigma = \sqrt{15.6825} \)[/tex]
[tex]\( \sigma \approx 3.9599 \)[/tex]
Therefore, the mean of the binomial distribution is [tex]\( 104.55 \)[/tex], the variance is [tex]\( 15.6825 \)[/tex], and the standard deviation is approximately .