Force per unit area defines which of the following?

gravity

pressure

force

temperature

Answers

Answer 1
Pressure can be defined as the amount of force applied to a square unit area

Answer 2

The Answer is Pressure hope it helps


Related Questions

What is the longest wavelength of radiation that possesses the necessary energy to break the bond 941?

Answers

Energy is calculated by molecule dividing energy by mole by Avogadro's number (6.022*10^23) 941kJ=9.41*10^5 J so energy by molecule E= 9.41*10^5/6.022*10^23=1.563*10^-18 J Wavelength (w) given by E=hc/w where, E = energy h = planks constant (6.6262 x 10-34 J·s) c = speed of light (3 x 10^8 m/s ) So, w= hc/E = (6.6262*10^-34)*(3*10^8) /1.563*10^-18 = 127.2 Nm Longest wavelength of radiation =127.2 Nm

Using the periodic table of the elements, how many valence electrons would helium have?
A. 0
B. 1
C. 2
D. 8

Answers

Helium only has 2 electrons. So the answer is C. 2

Explain how the position of the moon relates to the occurrence of high tides and low tides?

Answers

The closer the moon is to earth, the greater the moon’s gravity pulls on earth causing high tides. Low tides occur between two high tides.

There are 2 high tides and 2 low tides on most days. 

A high tide occurs near the point directly "under" the moon AND at the point on the opposite side of the earth.. 

Low tide occurs near the time when the moon is near the horizon. 


A more detailed answer:

The high and low tide are caused by the gravitational forces between the earth and the moon. However, the source of the real effect takes some explaining to grasp. The incorrect way of thinking is that the moon attracts all the water to itself, therefore causing a high tide on the side of earth close to the moon, and a low tide on the side far from the moon. However, if this was the case, there would be a high tide once per day. But there are TWO high tides a day. The reason is, the part of the earth both AWAY from the moon, and CLOSE to the moon BOTH get high tides... 

This is because the earth and the moon rotate around each other, each pulling the other towards itself. The moon attracts every piece of matter on earth. Since gravity is inversely proportional to the square of the distance, this force is greater on the side of the earth closer to the moon, and lesser on the side of the earth further from the moon. Since the earth is quite a rigid object, this difference in forces fails to deform the earth (much). However, it succeeds quite well in deforming the oceans -- which are not as rigid. Since the waters on the moon side are attracted more strongly than average, they tend to bulge TOWARDS the moon, hence causing a high tide. The waters on the opposite side of the moon, since they are attracted less strongly than average, tend to 'lag behind' the rigid earth, and bulge AWAY from the moon, which in this case, is also AWAY from the earth, again, causing a high tide. Low tide occurs at about right angles to the moon, where the force on the waters match the average pull of the moon on the earth closely. 

1) mechanical
2) electrical
3) thermal
4) light
5) chemical

In the system, __________ energy from the sunlight causes the solar panel to create __________ energy which flows into the incandescent light bulb. In the light bulb, the ________ energy is transformed into two different types of energy: _________ energy and _________ energy.

Answers

I am pretty sure about these answers.Thermal goes in the 4th blank.
Mechanical goes in the 2nd blank.
Electrical goes in the 3rd blank.
I think chemical goes in the 1st blank and light goes in the 5th blank
Hope this helps
Final answer:

The solar panel absorbs light energy and converts it into electrical energy. When this electrical energy reaches the incandescent light bulb, it is then transformed into thermal energy and light energy.

Explanation:

In the system, light energy from the sunlight causes the solar panel to create electrical energy which flows into the incandescent light bulb. In the light bulb, the electrical energy is transformed into two different types of energy: thermal energy and light energy.

Firstly, the solar panel absorbs light energy, also known as solar energy, and through a process called photovoltaic effect, it transforms this energy into electrical energy. This electrical energy then travels into the incandescent light bulb. Within the bulb, this electric energy is converted into thermal (heat) energy - this is the reason why light bulbs can get very hot. The heat then produces light energy, which is what we ultimately see and perceive as the functioning of a light bulb.

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Calculate the kinetic energy in joules of a 1500 kg automobile moving at 19 m/s

Answers

using
KE = ½mv² = ½×1500×19×19 = 270750 joules

A man weighs 1190 n on earth. what would he weigh on jupiter, where the free-fall acceleration is 25.9 m/s 2 ? the acceleration of gravity is 9.8 m/s 2 . answer in units of n.

Answers

The weight on Jupiter of a man if man weighs 1190 N on earth. Where the free-fall acceleration is 25.9 m / s² is 3144.26 N.

What is acceleration?

Acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration of all other motions.

Given:

The weight of the man, F = 1190 N,

The acceleration, a = 25.9 m / s²,

Calculate the mass of the man by the formula given below,

[tex]F = ma[/tex]

1190 = m × 9.8 m / s²

m = 121.4 kg

Calculate the weight of a man on Jupiter by the formula given below,

[tex]F = ma[/tex]

F = 121.4 × 25.9

F = 3144.26 N

Therefore, the weight on Jupiter of a man if man weighs 1190 n on earth. Where the free-fall acceleration is 25.9 m / s² is 3144.26 N.

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If weight is a measure of an object's force due to gravity, what is the weight of a student who has a mass of 65 kg? (assume that the acceleration due to gravity equals 9.8 m/s2.)

Answers

The weight will be around 637N

F=mg

The weight of the object with mass 65kg and acceleration due to gravity 9.8 m/s² is 637N.

What is Weight?

The weight (w) of an object is the product of its mass (m) in kilograms and the acceleration due to gravity, g in meters per second square. The weight of an object in physics is the force which is acting on the object due to the gravity of the planet. The SI unit of weight is newton (N).

The weight of the object is:

W = m × g

where, W = weight of the object,

m = mass of the object,

g = acceleration due to gravity,

m = 65 kg,

g = 9.8m/s²

W = 65 × 9.8

W = 637N

Therefore, the weight of the object is 637N.

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The height of an average adult person is closest to

Answers

6 foot I hope I helped

The global average height for an adult male is 171 centimeters (5 feet 7 inches) and the average height for an adult female is 159 centimeters (5 feet 2 inches).

What is the average height?

It is important to note that these are just averages and there will be a range of heights within each country. For example, in the United States, the shortest 10% of men are less than 163 cm (5 ft 4 in) tall and the tallest 10% of men are more than 185 cm (6 ft 1 in) tall. The same is true for women.

The average height of an adult person has been increasing over time due to a number of factors, including improved nutrition and better healthcare.

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A ball is tossed straight up with an initial velocity of 13.6 m/s. A) how high will it go? B) how long is the ball in the air?

Answers

A: 9.4248 m B: 2.773 s A ball tossed in to the air at 13.6m/s will experience a constant acceleration due to gravity of 9.81m/s^2. It will reach a 0 velocity at 13.6m/s^2 / 9.81m/s^2 = 1.386 s from the time it was thrown. It will fall to the ground another 1.386 seconds giving a total time in the air of 2*13.6m/s^2 / 9.81m/s^2 = 2.773 s To calculate the maximum height of the ball we use the fact that acceleration is constant. Between being thrown and reaching the maximum height the velocity constantly accelerates from 13.6m/s to 0 which gives an average velocity of 13.6m/s / 2 = 6.8m/s Now that we know average velocity and the time, the distance can be calculated. 1.386s * 6.8m/s = 9.4248m

If the 37.0-n force continues, the box accelerates at 0.52 m/s2 . what is the coefficient of kinetic friction?

Answers

Final answer:

The coefficient of kinetic friction is approximately 0.176.

Explanation:

To calculate the coefficient of kinetic friction, we need to use the formula:

frictional force = coefficient of kinetic friction × normal force

We also know that the frictional force is equal to the product of mass and acceleration:

frictional force = mass × acceleration

By equating the two expressions for frictional force, we can solve for the coefficient of kinetic friction:

coefficient of kinetic friction = (mass × acceleration) / (mass × gravity)

Plugging in the given values, we have:

coefficient of kinetic friction = (30 kg × 0.52 m/s²) / (30 kg × 9.8 m/s²)

coefficient of kinetic friction ≈ 0.176

Final answer:

The coefficient of kinetic friction is approximately 0.176. To determine this, we can use the formula: frictional force = coefficient of kinetic friction × normal force.

Explanation:

To calculate the coefficient of kinetic friction, we need to use the formula:

Frictional force = coefficient of kinetic friction × normal force

We also know that the frictional force is equal to the product of mass and acceleration:

Frictional force = mass × acceleration

By equating the two expressions for frictional force, we can solve for the coefficient of kinetic friction:

Coefficient of kinetic friction = (mass × acceleration) / (mass × gravity)

Plugging in the given values, we have:

Coefficient of kinetic friction = (30 kg × 0.52 m/s²) / (30 kg × 9.8 m/s²)

Coefficient of kinetic friction ≈ 0.176

Bob is pulling a 30 kg filing cabinet with a force of 200 n, but the filing cabinet refuses to move. the coefficient of static friction between the filing cabinet and the floor is 0.80. what is the magnitude of the friction force on the filing cabinet?

Answers

Final answer:

The magnitude of the friction force opposing the filing cabinet is 200 N, equal to the applied force, since it does not exceed the maximum static frictional force of 235.2 N calculated using the coefficient of static friction and the normal force.

Explanation:

The magnitude of the friction force on the filing cabinet can be determined by using the coefficient of static friction and the normal force acting on the cabinet. Since the cabinet is not moving, the static frictional force will be equal to the force applied until it reaches its maximum value, which can be calculated as μs N, where μs is the coefficient of static friction and N is the normal force. The normal force is equal to the weight of the cabinet (mass times the acceleration due to gravity, g). For a 30 kg filing cabinet, the normal force N is equal to 30 kg × 9.8 m/s², which equals 294 N. Hence, the maximum static frictional force is 0.80 × 294 N = 235.2 N. Since the cabinet does not move when a 200 N force is applied, the frictional force opposing it is also 200 N, which is less than the maximum static friction of 235.2 N.

Final answer:

The friction force on the filing cabinet is 200 N, which is the same as the applied force and within the maximum static friction value given by the coefficient of static friction multiplied by the normal force.

Explanation:

The magnitude of the friction force on the filing cabinet can be found by using the coefficient of static friction and the normal force. The normal force is equal to the weight of the cabinet, which is the mass (30 kg) multiplied by the acceleration due to gravity (9.8 m/s²). This gives a normal force of (30 kg)(9.8 m/s²) = 294 N. The maximum static friction force can be calculated with the formula fs(max) = μs N, where μs is the coefficient of static friction and N is the normal force. Since the cabinet doesn't move, the static friction force must equal the applied force up to its maximum value, which is determined by the coefficient of static friction (0.80).

Therefore, the maximum static friction force that can act on the filing cabinet is fs(max) = (0.80)(294 N) = 235.2 N. Since 200 N is being applied to move the cabinet, and it does not move, the friction force acting on the cabinet is 200 N, which is the same as the applied force and less than the maximum static friction force.

Which wind system helped early sailors navigate earth's oceans?

Answers

The wind system that had helped early sailors to navigate the earth oceans are trade winds. It is blowing toward the equator from the northern hemisphere or the southern hemisphere. Trade winds are found in the tropics. It strengthens during winter when the Arctic oscillation, is in its warm phase. It has been used by captains of sailing ships to cross the oceans around the world for centuries now. It also acts as the steering flow for tropical storms that form over the major oceans in the world. If the trade winds are weak, then the more rainfall can be expected in the neighboring landmasses.     

A student throws a set of keys vertically upward to his fraternity brother, who is in a window 4.00 m above. the brother’s outstretched hand catches the keys 1.50 s later. (a) with what initial velocity were the keys thrown? (b) what was the velocity of the keys just before they were caught?

Answers

a) 10.0 m/s b) -4.7 m/s The formula for distance under constant acceleration is d = 0.5AT^2 The formula for distance with a specified velocity is d = VT So the distance the keys travel with an initial velocity and under constant acceleration by gravity is d = VT - 0.5AT^2 The acceleration due to gravity is 9.8 m/s^2 and the time T is 1.50 s, and finally, the distance traveled is 4.00 m. So substitute those values into the equation and solve for V d = VT - 0.5AT^2 4.00m = 1.50s * V - 0.5 * 9.8 m/s^2 * (1.5s)^2 Do the multiplications 4.00m = 1.50s * V - 4.9m/s^2 * 2.25 s^2 Cancel the s^2 terms 4.00m = 1.50s * V - 4.9m * 2.25 Do the multiplication 4.00m = 1.50s * V - 11.025m Add 11.025m to both sides 15.025m = 1.50s * V Divide both sides by 1.50s 10.01667 m/s = V Since we have 3 significant figures in the data, round results to 3 significant figures. V = 10.0 m/s So the keys were initially thrown upwards with a velocity of 10.0 m/s Since it took 1.50 seconds from launch to catch, the velocity of the keys will decrease by 9.8 m/s^2 times the time. So V = 10.0 m/s - 1.50s * 9.8 m/s^2 V = 10.0 m/s - 14.7 m/s V = -4.7 m/s So at the time the keys were caught, they were moving downward at a velocity of 4.7 m/s

What is the least possible initial kinetic energy in the oxygen atom could have and still excite the cesium atom?

Answers

Final answer:

The minimum kinetic energy needed to excite a cesium atom by a collision with an oxygen atom can be calculated using the conservation of energy principle.

Explanation:

The minimum amount of kinetic energy a particle must have to excite another particle can be calculated using the conservation of energy principle and the equation for kinetic energy. In this case, we are considering the collision between an oxygen atom (O) and a cesium atom (Cs). The formula for calculating the minimum kinetic energy is:

K.E. = (2 * activation energy) + ionization energy

The activation energy is the minimum energy required to initiate the reaction, and the ionization energy is the energy required to remove an electron from an atom. To calculate the specific values for this equation, we need to know the activation energy and the ionization energy of the cesium atom.

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HELP ASAP!! DUE TOMORROW!! WILL MARK AS BRAINLIEST IF ANSWERED NOW!!

Answers

Sorry, I’m only completely sure about 3 and 5.

3.) D. All of the above
5.) Blood type, though only class evidence, can help to lower the list of suspects as not everyone has the same blood type.
1 - B
2 - A 
i think they may be right
but sorry this is all i could do hope this helped

A car drives horizontally off the edge of a cliff that is 40.8 m high. the police at the scene of the accident note that the point of impact is 121 m from the base of the cliff. how fast was the car traveling when it drove off the cliff?

Answers

Fall time machine:
t = √ (2*H/g) = √ (2*40.8 / 9,8) ≈ 2.9 s
Horizontal movement:
S = V₀*t
Speed:
V₀ = S / t = 121 / 2.9 ≈ 41.7 m/s         or  150 km/h

Final answer:

To calculate the speed of the car when it drove off the cliff, we used projectile motion equations to solve for the time it took to hit the ground and then found the horizontal velocity with this time and the given horizontal distance.

Explanation:

To determine the speed at which the car was traveling when it went off the cliff, we can use the kinematic equations for projectile motion. Given that the car falls from a height of 40.8 m and lands 121 m away from the base of the cliff, we can first calculate the time it took for the car to hit the ground using the equation for vertical motion under constant acceleration due to gravity (g = 9.8 m/s²). The vertical motion is independent of the horizontal motion, so:

y = ½ gt², where y is the vertical displacement and t is the time.

Using this equation, we solve for t:

40.8 m = ½ (9.8 m/s²) t²

t = √((2 * 40.8 m) / 9.8 m/s²)

After calculating the time, t, we can then use the horizontal distance travelled and the time of flight to find the horizontal velocity (v):

x = v * t, where x is the horizontal displacement.

Now we substitute the previously calculated time t in the equation to find the horizontal velocity (which is also the initial velocity since there is no horizontal acceleration):

v = x / t

v = 121 m / t

This gives us the car's speed as it left the cliff.

what is the difference between ram express and tradesman

Answers

Differences appear to be largely cosmetic. The Tradesman is a basic model, while the Express is slightly more “tricked out” on the interior.

You run 100 meters in 15 seconds. What is your speed in m/s?

Answers

To find meters per second, just do 100 divided by 15. Your speed would be 6.67 meters per second.

How to find the acceleration of a 20 kg block, going down and to the left (Ф= 37°)
connected, by a pulley, to a 10 kg block accelerating up ?

Theres no friction at all and the pulley is light

Answers

You need to start by considering what forces are on the 20kg block. The 20kg block will have a tension force as well as a gravitational force that are antiparallel to each other. There is also a normal force, but we will not need to consider this since friction is negligible. The equation will be: [tex]m_1a_1 = T - m_1g\cos\phi[/tex], where [tex]m_1 = 20kg[/tex]. From this equation, you can find the expression for acceleration ([tex]a_1[/tex]) by dividing by the mass.

The base unit for mass in the SI system is the?
gram
kilogram
slug

Answers

The right answer is Kilogram.
I hope can help you.

What is the wavelength of an infrared wave with a frequency of 4.2 x1014 Hz?

Answers

using
π = c/f
where c = velocity of EM waves in vacuum = 3×10^8 ms-¹
f = 4.2×10^14
π = 3/4.2 ×10^(8-14)
π = 0.714 ×10 ^-6
π = 7.14×10^-5 m

The wavelength of an infrared wave with a given frequency is 7.14 x 10⁻⁵ m.

What is frequency?

Frequency is the number of cycles per second moved by the wave.

The frequency and wavelength is related as

λ = c/f

where c = velocity of sound wave in vacuum = 3×10⁸ m/s

Given is the frequency of the infrared wave f = 4.2×10^14, then wavelength will be

λ = 3 x10⁸ / 4.2 x 1

λ = 7.14 x 10⁻⁵ m

Thus, the wavelength  of an infrared wave with a given frequency is 7.14 x 10⁻⁵ m

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How did advances in technology open the way for world exploration?

Answers

they took advantage of innovations in sailing technolgy that allowed ships such as the caravel to sail against the wind.

Which force puts an object into free fall?

Answers

Answer:

Gravity

Explanation:

When we say that object is in free fall then it always means that the object will move under the influence of gravitational force only

So here we can say that

under free fall condition the force on the object is given as

[tex]F = mg[/tex]

so the acceleration of free fall is always constant and given as

[tex]a = \frac{F}{m}[/tex]

[tex]a = \frac{mg}{m}[/tex]

[tex]a = g[/tex]

so correct answer is

Gravity

An object with mass m is located halfway between an object of mass m and an object of mass 3m that are separated by a distance
d. what is the magnitude of the force on the object with mass m?

Answers

The resultant force would be 2*(Gm^2/R^2)

R=distance between massses in this case d/2.
G=gravitational constant.


60 POINTS ANSWER CORRECTLY
Which statement best describes charge A and charge B in this diagram?

A ) The signs on charges A and B are opposite. The amount of charge on A is greater than that on B.

B ) The signs on charges A and B are opposite. The amount of charge on A is less than that on B.

C ) The signs on charges A and B are the same. The amount of charge on A is greater than that on B.

D ) The signs on charges A and B are the same. The amount of charge on A is less than that on B.

Answers

Your answer will be A The signs on charges A and B are opposite. The amount of charge on A is greater than that on B.

The answer is A The amount of charge on A is greater than that on B.

A negatively charged rubber rod can pick up small, neutrally charged pieces of paper by a process called

Answers

Final answer:

A negatively charged rubber rod can pick up small, neutrally charged pieces of paper through polarization, causing a redistribution of charges within the paper. This induces a dipole moment, leading to attraction despite the paper's overall neutral charge.

Explanation:

A negatively charged rubber rod can pick up small, neutrally charged pieces of paper by a process called polarization. This phenomenon occurs because the negatively charged rod causes a redistribution of charges within the neutral paper, inducing a dipole moment. The paper, though overall neutral, has its charges slightly shifted: the side closer to the rod becomes positively charged due to the attraction of electrons towards the rod, and the far side becomes more negatively charged. The closer, positively charged side of the paper is then attracted more strongly to the negatively charged rod than the repulsion experienced by the more distant, negatively charged side, resulting in the net attraction of the paper to the rod. This effect is not limited to rubber rods and paper; it can be demonstrated with various insulators and small objects. The key to this attraction is the electrostatic force and the principle that opposite charges attract. The rubber rod, after being charged (usually by friction with another material like fur), exhibits this charge inducing behavior due to the presence of excess electrons. Some molecules, like water, are naturally polar and show greater polarization effects than molecules with naturally uniform charge distributions when in the presence of charged objects. Thus, the same principle applies to the attraction of neutrally charged objects that have polar molecules.

A jogger runs the first 1000 meters of a race in 250 seconds. What is the joggers speed

Answers

4 meters per second. hope this helped

Answer:

The speed of the joggers is 4 m/s.

Explanation:

Given that,

Distance covered by the joggers, d = 1000 meters

Time taken by the joggers, t = 250 seconds

We need to find the joggers speed. It is given by :

[tex]v=\dfrac{d}{t}[/tex]

[tex]v=\dfrac{1000\ m}{250\ s}[/tex]

v = 4 m/s

So, the joggers speed is 4 m/s. Hence, this is the required solution.

An airplane accelerates down a run-way at 3.20 m/s 2 for 32.8 s until is finally lifts off the ground. determine the distance traveled before take-off.

Answers

Distance = 1/2 (a) (t^2)

= 1/2 (3.2) (32.8)^2

= (1.6) x (1,075.84)

= 1,721 meters (rounded)


Which of the following is an organic compound?

Answers

The answer is D if im correct

Answer:

D

Explanation:

In order to be classified as an organic compound, the compound must contain carbon. Of the options available, only option D includes a sample that contains carbon.

Organic compounds often contain C, H, and O atoms, such as ethanol, CH₃OH.

The mass of an object is independent of its location
a. True
b. False

Answers

True...
the mass of an object is constant,
but it's the weight that varies
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