The net force is 2.2 N at 80.9 degrees south of east
Explanation:
In order to find the net force, we have to resolve each force along the x-y direction, and then add the components in each direction.
Taking east as positive x-direction and north as positive y-direction, we have:
- First force:
[tex]F_{1x} = -3.0 N\\F_{1y} = 0[/tex]
- Second force:
[tex]F_{2x} = (4.0)(cos (-33^{\circ})=3.35 N\\F_{2y} = (4.0)(sin (-33^{\circ})=-2.18 N[/tex]
Therefore, the components of the net force are
[tex]F_x = F_{1x}+F_{2x}=-3.0+3.35=+0.35 N\\F_y = F_{1y}+F_{2y}=0+(-2.18)=-2.18 N[/tex]
And so, the magnitude of the net force is
[tex]F=\sqrt{F_x^2+F_y^2}=\sqrt{(0.35)^2+(-2.18)^2}=2.2 N[/tex]
And the direction is
[tex]\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{-2.18}{0.35})=-80.9^{\circ}[/tex]
which means 80.9 degrees south of east.
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8. In what family would each of these elements be classified?
Radium -
Tin -
Iodine -
Cesium -
Answer: Radium is a member of the alkaline metals group.
Tin is classified in the 'Other Metals' section which can be located in groups 13, 14, and 15 of the Periodic Table.
Iodine is classified as a halogen — a subset of very chemically reactive elements (Group 17 on the periodic table) that exist in the environment as compounds rather than as pure elements. The other halogens include fluorine (F), chlorine (Cl), bromine (Br) and astatine (At).
Cesium is classified as an "Alkali Metal" and located in Group 1 elements of the Periodic Table. An Element classified as an Alkali Metal is a very reactive metal that does not occur freely in nature. Alkali metals are soft, malleable, ductile, and are good conductors of heat and electricity.
Radium belongs to Alkaline Earth Metals, Tin to Post-transition Metals, Iodine to Halogens, and Cesium to Alkali Metals.
Explanation:The elements in question belong to different families on the Periodic Table.
Radium belongs to the Alkaline Earth Metals family. Tin belongs to the Post-transition Metals family. Iodine belongs to the Halogens family. Cesium belongs to the Alkali Metals family.
The elements Radium, Tin, Iodine, and Cesium belong to different families in the Periodic Table of Elements. Radium is classified in the Alkaline Earth Metals family, Tin is classified in the Carbon Group family, Iodine is classified in the Halogens family, and Cesium is classified in the Alkali Metals family.
Each family is grouped together because of similarities in chemical properties, as well as their shared valence electron structure.
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Describe the medium that electromagnetic waves use to travel
Answer:
Electromagnetic waves do not require a medium to propagate means they can travel through air and solid material and the vacuum of space too.
they move the fastest through gases mostly because particles in gases are spread out more than the particles in solids or in liquids so they move quickly through gases.
Explanation:
Define self-actualization.
Answer:the realization or fulfillment of one's talents and potentialities, especially considered as a drive or need present in everyone.
Explanation:
your welcome
Answer:
the realization or fulfillment of one's talents and potentialities, especially considered as a drive or need present in everyone.
Explanation:
In other words, for our purposes, self-actualization can be thought of as the full realization of one’s creative, intellectual, or social potential.
Which structure is the arrow pointing to?
What is the function of this organelle?
Answer:
The arrow is pointing to the "nucleus."
Explanation:
A cell is the smallest unit in an organism. It mainly functions to provide structure to the human body, thus it is call "the building blocks of life."
There are 6 organelles in a cell and these are: Nucleus, Ribosomes, Endoplasmic Reticulum, Golgi Aparatus, Chloroplasts and Mitochondria.
The arrow is pointing to the cell's nucleus in the image above. This is an organelle that is enclosed in a membrane. It is where you can find the deoxyribonucleic acid or the DNA, which is essential for hereditary function. It also coordinates activities in the cell, such as metabolism, synthesis of proteins, cell division, etc.
Remember, not all cells have nucleus. Only eukaryotic cells have a nucleus. This cells are considered as more advanced.
the arrow is pointing to nucleus
the function of this organelle that it controls the activities of the cells
What is the relationship between the strength of an
electromagnet and the number of turns in the coil?
As the number of turns in the coil increases, the strength
of the electromagnet increases.
The number of turns in the coil has no impact on the
strength of the electromagnet.
As the number of turns in the coil decreases, the
strength of the electromagnet increases.
Answer:
As the number of turns in the coil increases, the strength of the electromagnet increases.
Explanation:
When current flows through a coil the coil behaves as an electromagnet. The strength of electromagnet depend the amount of current, no of turns of coil and the core of coil.
B=μ₀ N I
μ₀ = permeability of the core
N = Number of turns of the coil
I = Current flowing through the coil
Increasing the current and number of coils increase the strength of electromagnet.
50. As a pendulum swings back and forth,
A) potential energy is transformed into kinetic energy
B) kinetic energy is transformed into potential energy
C) at the lowest part of the swing the potential energy is the lowest
D) all of the above are true
Answer:
D
Explanation:
All the options A, B, and C are true for a swinging pendulum. As it swings, potential energy is converted to kinetic energy and vice versa, and the lowest potential energy occurs at the lowest point of the swing.
During the swing of the pendulum, energy is continuously being transformed between kinetic and potential forms.
At the highest points of the swing, the pendulum has the most potential energy because it is the furthest away from the point of equilibrium, and as it starts falling, this potential energy is converted into kinetic energy. Conversely, as it swings upwards, the kinetic energy is transformed into potential energy.
At the lowest point of the swing, the pendulum has its maximum kinetic energy and minimum potential energy, thereby making all the provided statements true.
Forces always act in pairs? True or false
Answer:
True
Explanation:
Just as Isaac Newton says, "For every action, there is an equal and opposite reaction."
What do I have to do to figure out " What % of an object’s mass is above the water line if the object’s density is 0.82g/ml " with just that information?
Answer:
18%
Explanation:
There are two equal and opposite forces on a floating object: weight and buoyancy.
W = B
The weight of an object is its mass times gravity: W = mg
Buoyancy is the weight of the displaced fluid: W = mf g
Plugging in:
mg = mf g
m = mf
Mass is density times volume:
ρV = ρf Vf
Solving for the ratio of Vf / V:
Vf / V = ρ / ρf
Given that ρ = 0.82 g/mL and ρf = 1.00 g/mL:
Vf / V = 0.82
That means 82% of the object's volume (and therefore, 82% of its mass, assuming uniform density) is submerged. Which means that 18% is above the water line.
A horizontal string tied at both ends is vibrating in its fundamental mode. The traveling waves have speed v, frequency v, amplitude A, and wavelength λ. Calculate the maximum transverse velocity and maximum transverse acceleration of points located at (i) x= λ /2, (ii) x= λ /4 and (iii) x= λ /8 from the left-hand end of the string.
Answer:
1) both velocity and acceleration at x = λ /2 are 0
2)maximum velocity at x=λ /4 is -2Aω
maximum acceleration at x=λ /4 is Aω²
3)maximum velocity at x=λ /8 is √2Aω
maximum acceleration at x=λ /8 is (-Aω²/√2)
Explanation:
When a string is tied at both ends and vibrated, we get standing waves.
The general form of standing wave is,
y(x,t) = 2A×sin(kx)×cos(ωt) (displacement of string at x and at time t)
where, A = amplitude of wave
ω = 2πv , v = frequency of the wave
k = 2π/λ ; λ = wavelength of wave
Speed V = ω/k.
Now, differentiating y(x,t) by once with t gives velocity
⇒V(x,t) = -2Aω×sin(kx)×sin(ωt)
And differentiating once again gives acceleration
a(x,t) = -Aω²×sin(kx)×cos(ωt)
1) x= λ/2
⇒V(x,t) = -2Aω×sin(k(λ /2))×sin(ωt)
= -2Aω×sin(π)×sin(ωt)
= 0
a(x,t) = -Aω²×sin(kx)×cos(ωt)
⇒ a(x,t) = -Aω²×sin(k(λ /2))×cos(ωt)
= -Aω²×sin(π)×cos(ωt)
= 0
2) x= λ /4
⇒V(x,t) = -2Aω×sin(kx)×sin(ωt)
= -2Aω×sin(k(λ /4))×sin(ωt)
= -2Aω×sin(π/2)×sin(ωt)
= -2Aω sin(ωt)
⇒ maximum velocity at x=λ /4 is -2Aω (minimum sin value is -1)
a(x,t) = -Aω²×sin(kx)×cos(ωt)
= -Aω²×cos(ωt)
⇒ maximum acceleration at x=λ /4 is Aω² (minimum cos value is -1)
3) x= λ /8
⇒V(x,t) = -2Aω×sin(kx)×sin(ωt)
= -√2Aω×sin(ωt)
⇒ maximum velocity at x=λ /8 is √2Aω (minimum sin value is -1)
a(x,t) = -Aω²×sin(kx)×cos(ωt)
= (-Aω²/√2) × cos(ωt)
⇒ maximum acceleration at x=λ /8 is (-Aω²/√2) (minimum cos value is -1)
The velocity perpendicular to the radius vector is called the transverse velocity. The transverse acceleration is the acceleration produced by an inertial force acting across the body. The expression for the maximum transverse velocity and acceleration has been obtained for given values of x.
Given information-A horizontal string tied at both ends is vibrating in its fundamental mode.
Transverse velocityVelocity perpendicular to the radius vector is called the transverse velocity.
The formula for the maximum transverse velocity can be given as,
[tex]V_m=-2A\omega\sin(kx)\times \sin(\omega t)[/tex]
Transverse accelerationTransverse acceleration is the acceleration produced by an inertial force acting across the body.
[tex]a_m=-A\omega^2 \sin(kx)\times \cos(\omega t)[/tex]
1) Maximum transverse velocity and maximum transverse acceleration when x is equal to the [tex]\lambda/2 [/tex] -[tex]V_m=-2A\omega\sin(k\dfrac{\lambda}{y} )\times \sin(\omega t)\\ V_m=-2A\omega\sin(\pi )\times \sin(\omega t)\\ V_m=0[/tex]
[tex]a_m=-A\omega^2 \sin(k\dfrac{\lambda}{2} )\times \cos(\omega t)\\ a_m=-A\omega^2 \sin(\pi )\times \cos(\omega t)\\ a_m=0[/tex]
2) Maximum transverse velocity and maximum transverse acceleration when x is equal to the [tex]\lambda/4 [/tex] -[tex]V_m=-2A\omega\sin(k\dfrac{\lambda}{4} )\times \sin(\omega t)\\ V_m=-2A\omega\sin(\dfrac{\pi}{2} )\times \sin(\omega t)\\ V_m=-2A\omega \times \sin(\omega t)\\ [/tex]
[tex]a_m=-A\omega^2 \sin(k\dfrac{\lambda}{4} )\times \cos(\omega t)\\ a_m=-A\omega^2 \sin(\dfrac{\pi}{2} )\times \cos(\omega t)\\ a_m=-A\omega^2 \times \cos(\omega t)\\[/tex]
3) Maximum transverse velocity and maximum transverse acceleration when x is equal to the [tex]\lambda/3 [/tex] -[tex]V_m=-2A\omega\sin(k\dfrac{\lambda}{8} )\times \sin(\omega t)\\ V_m=-{\sqrt{2} }{A\omega\times \sin(\omega t)} \\ [/tex]
[tex]a_m=-A\omega^2 \sin(k\dfrac{\lambda}{4} )\times \cos(\omega t)\\ a_m=\dfrac{-A\omega^2\times \cos(\omega t)}{\sqrt{2} } \\ [/tex]
Thus the maximum transverse velocity and maximum transverse acceleration at given points has been obtained.
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Starting from rest, Christina experiences 24.5 m/s2 of acceleration to take off from an aircraft carrier for 5 seconds. How long does the runway need to be? Round to the nearest meter.
Answer:
The length of the runway to the nearest meter is 306 m.
Explanation:
Given:
Initial velocity of Christina is, [tex]u=0\ m/s(Rest)[/tex]
Time taken is, [tex]t=5\ s[/tex]
Acceleration experienced by Christina is, [tex]a=24.5\ m/s^2[/tex]
The length of the runway is, [tex]d=?[/tex]
Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.
So, we have the following equation of motion:
[tex]d=ut+\frac{1}{2}at^2[/tex]
Plug in all the given values and solve for 'd'. This gives,
[tex]d=0+\frac{1}{2}\times 24.5\times 5^2\\\\d=\frac{1\times 24.5\times 25}{2}\\\\d=\frac{612.5}{2}\\\\d=306.25\approx 306\ m(\textrm{Rounding to nearest meter})[/tex]
Therefore, the length of the runway to the nearest meter is 306 m.
The motion of roller coasters depends upon the conversion of potential and kinetic energy. A 100-kg car starts from rest at the top of a hill with a height of 50 m. Which of the following is this car's kinetic energy at the bottom of the hill? 150 J 5000 J 49,000 J 98,000 J
Answer:
The kinetic energy will be 49000[J]
Explanation:
This problem is the common use of energy conservation when the body is at the top at the point where its elevation is the highest (usually the lowest point is taken as the reference level) at that point the body will have the highest potential energy, then as the body descends its potential energy decreases but its kinetic energy begins to increase. By the time the body reaches the lowest point or reference point, its potential energy will be zero, but its maximum kinetic energy, as all potential energy has become kinetic energy.
Therefore:
[tex]Ep=m*g*h\\where\\m =100 [kg]\\g= 9.81 [m/s^2] gravity\\h = 50 [m]\\\\Ep= 100*9.81*50\\Ep=49000 [J][/tex]
This energy will be transformed into kinetic energy at the bottom of the hill.
The kinetic energy of the roller coaster car at the bottom of the hill is 49,000 J, which equals the potential energy at the top of the hill assuming no energy loss to friction.
The motion of roller coasters relies on the conversion between potential and kinetic energy.
At the top of a hill, a roller coaster car has maximum gravitational potential energy, which is given by the equation:
PE = mgh,where
m is the mass (100 kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height (50 m)Thus,
PE = 100 kg * 9.8 m/s² * 50 m PE = 49,000 J.Assuming no energy loss due to friction, this potential energy is entirely converted to kinetic energy at the bottom of the hill.
Hence, the kinetic energy of the car at the bottom is: 49,000 J.
find the angle between the vectors |A+B|=|A-B|
Answer:
90 degrees
Explanation:
In the attached image we can see, the condition where this condition (|A+B|=|A-B|) is true.
vector A is pointing horizontally to the right, vector B (positive), points up vertically.
Now analyzing the subtraction of vectors A and B = A - B, we have that vector A continues to point to the right (positive) and vector B points down (negative). In this way the magnitudes of both operations sum and subtraction of vectors is equal.
But the angle between the two vectors (A and B) will remain the same and will be 90°.
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Drift nets are huge nets that fishing boats use to catch fish. Drift nets can be several kilometers long and catch many more fish than do smaller, more traditional nets. How does the widespread use of drift nets affect the ocean ecosystem? A. It reduces pollution in the ocean. B. It increases the biodiversity of the ocean. C. It increases the populations of marine mammals that feed on fish. D. It reduces populations of fish and other marine organisms.
Answer:
Its D these nets have long been destroying the ecosystem
Answer: D.) It reduces populations of fish and other marine organisms.
Explanation: It was on study Island
an electrical iron box having power 400w is operated in 10hours. what will be the energy consumed by the device in commercial unit?
Answer:
4 kWh or 4 units
Explanation:
energy = power × time
= 400 W× 10 h
= 4000 Wh
=( 4000/ 1000 ) kWh
= 4 kWh
= 4 commercial units
If you decrease the wavelength of a wave, the frequency should
Answer:
The frequency should increase.
Explanation:
The wavelength of a wave varies inversely to frequency of the wave.
The relation between the frequency and wavelength of a wave is given as:
[tex]f\lambda=v[/tex]
Here, [tex]f\to frequency\\\lambda\to wavelength\\v\to velocity\ of\ wave[/tex]
Therefore, as the wavelength increases then the frequency will decrease.
Similarly, as the wavelength of the wave decreases, then the frequency will increase.
So, the frequency should increase if you decrease the wavelength of a wave.
A bat hits a 0.150 kg baseball for
0.0930 s. The ball's velocity
changes from 47.0 m/s left to
32.0 m/s right. What impulse was
given to the ball?
(Unit = kg*m/s)
Remember: right is +, left is -
Answer:
11.85 kg m/s
Explanation:
impulse = mass ( change in velocity )
= mass ( final velocity - initial velocity )
= 0.150 ( 32.0 - (-47.0))
= 0.150 ( 32.0 +47.0)
= 0.150 (79)
= 11.85 kg m/s
Answer:
11.85
Explanation:
its correct
In your own words, what was the purpose of the field study?
Procedure
Write a short summary of how you completed your field study and how you classified the organisms.
Data
Use the following key to help you complete the field study.
New Fabula Creatures Taxonomic Key
Step Physical Feature Classification
1 Smooth skin Go to 2
Fur Go to 3
2 One eye Go to 4
Two eyes Go to 5
3 One eye Go to 7
Two eyes Go to 8
4 Arms and legs Silkus monowrestle
Legs only Silkus monosquirmus
5 Arms and legs Go to 6
Legs only Silkus duosquirmus
6 Tail Silkus tallyhas
No tail Silkus stretchilus
7 Tail Fuzzus tallywag
No tail Fuzzus feelzalot
8 Two teeth Go to 9
More than two teeth Fuzzus chompilus
9 Pointy Fuzzus pointilus
Square Fuzzus squarilus
Fill in the chart with each creature's scientific name based on your field study observations.
Creature Scientific Name
1
2
3
4
5
6
7
8
9
10
Conclusion
Now that you have classified the organisms on planet Fabula, answer the following questions:
1. How many different species are there?
2. How many different genus groups are there? List them.
3. Do you think all of these creatures would belong in the same Kingdom? Why or why not?
4. Explain in your own words the order in which the creature's traits may have evolved, starting from the first likely trait. (Hint: Which trait is most common across the creatures?)
Answer:
Hi there! I have only the procedure and the scientific names of the creatures. Hope this helps!
Procedure
I studied the physical features of ten creatures and classified them using the key. I completed each section below and recorded the creature's scientific name in the data section.
The Creatures Scientific Names:
1
Fuzzus tallywag
2
Fuzzus pointilus
3
Silkus duosquirmus
4
Fuzzus chompilus
5
Silkus stretchilus
6
Silkus tallyhas
7
Fuzzus feelzalot
8
Silkus monosquirmus
9
Fuzzus squarilus
10
Silkus monowrestle
Have a thrilling Thursday!
~Lola
Answer:
Creature
Scientific Name
1.
Fuzzus tallywag
2.
Fuzzus pointilis
3.
Silkus duosquirmus
4.
Fuzzus chompilus
5.
Silkus stretchilus
6.
Silkus tallyhas
7.
Fuzzus feelzalot
8.
Silkus monosquirmus
9.
Fuzzus squarilus
10.
Silkus monowrestle
Conclusion (10 points)
Now that you have classified the organisms on planet Fabula answer the following questions:
Skilled Scientist level from Rubric: Student used critical thinking skills and evidence to establish a possible relationship among organisms and a possible evolutionary history of traits.
How many different species are there?
THere are 10 different species.
How many different genus groups are there?
There are 10 different genus groups.
List the different genus groups:
Fuzzus Tallywag
Fuzzus pointilus
Silkus duosquirmus
Fuzzus chompilus
Silkus stretchilus
Silkus tallyhas
Fuzzus feelzalot
Silkus monosquirmu
Fuzzus squarilus
Silkus monowrestle
Do you think all of these creatures would be long to the same Kingdom? Why or why not?
Yes, because they all look the same, but also look different. It's kind of like cats and lions or dogs and wolves.
Explanation:
How do i figure this out?
explanation not just a answer
Answer:
You now this question state why a person standing at point Y hears an echo
Explanation:
Density is mass divided by volume. For example, Block A:
ρ = m / V
ρ = 60 g / 125 cm³
ρ = 0.48 g/cm³
I assume each block is a cube, so the length of block underwater divided by the side length of the block is the percent underwater.
% = 1.8 / 3.9
% = 46%
Repeat for Blocks B through E.
When are tides lowest? What causes these tides to be lowest?
Tides are lowest when:
Tides are lowest when the earth, sun and moon come’s in a right angle. It occurs when the greatest pint in the wave or can called the crest arrives at the coast, the coast can feel the high tide, but when the smallest point i.e. trough arrives at the coast feels the low tide. The tidal force present makes the earth also the water to swell out of side which is often nearer to moon and the side farthest to that of moon, when no swelling can be seen low tides occurs.
Neap tides, which are the lowest tides, occur when the Sun and Moon's gravitational forces are at right angles to each other, typically during the first and third quarter moon phases.
Explanation:The lowest tides, known as neap tides, occur approximately twice a month when the Sun is at a 90° angle to the Earth-Moon alignment. During these periods, the gravitational forces of the Sun and the Moon act at right angles to each other, which reduces the overall tidal effect. Neap tides happen during the first and third quarters of the Moon’s phase, also referred to as the half-moon. Conversely, the highest tides, called spring tides, happen when the Earth, the Moon, and the Sun are aligned, typically during a new or full moon when their gravitational forces combine to create stronger tides.
A Jeep is stuck in the mud. The driver has a winch that can pull on its cable with a force of 35,000 N. The driver loops the cable through a pulley attached to a tree, then attaches the end of the cable to his Jeep, as shown in figure 1. What is the magnitude of the maximum force that can be exerted on the Jeep by this cable arrangement? Express your answer with appropriate units.
The pulley system has a cable attached to either side of the front end of the jeep which connects to a pulley attached to a tree.
Answer:
70,000 N
Explanation:
Draw a free body diagram of the Jeep. There are two tension forces, both pulling the Jeep towards the tree.
The net force is:
ΣF = 2T
ΣF = 2 (35,000 N)
ΣF = 70,000 N
The maximum force that can be exerted on the Jeep due to the cable arrangement is 70000N.
Force, Tesnion = 35000N F = mass × accelerationThe net force, ΣF ; can be calculated thus :
Net force = 2 times the TensionΣF = 2 × Tension
Net force = 2 × 35000
Net force = 70,000 N
Therefore, the net force that is exerted on the Jeep is 70,000N.
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The phosphorus cycle is important to ecosystems. Choose all of these statements that are true concerning the phosphorus cycle.
The largest reservoir of phosphorous is sedimentary rock.
Most of the phosphorous cycle occurs in the atmosphere.
Phosphoric acid is the major acid found in acid rain.
Major sources of phosphorous to aquatic ecosystems are fertilizer runoff, sewage leaks, and industrial wastes.
Eccess phosphorous can lead to eutrophication.
Answer:
The largest reservoir of phosphorous is sedimentary rock.
Major sources of phosphorous to aquatic ecosystems are fertilizer runoff, sewage leaks, and industrial wastes.
Eccess phosphorous can lead to eutrophication
Explanation:
Phosphorus come from different sources such as aquatic ecosystems and fertilizers used for plants. When these substances containing phosphorus and those from industrial wastes find their way into water bodies, they tend to cause eutrophication, which is the natural enrichment of water bodies.
Also, it is known that a very small portion of phosphoric acid contribute to acid rain in the atmosphere.
Answer:
The statements that are true are:
-The largest reservoir of phosphorous is sedimentary rock
- Major sources of phosphorous to aquatic ecosystems are fertilizer runoff, sewage leaks, and industrial wastes.
- Excess phosphorous can lead to eutrophication.
Explanation:
In nature, phosphorous is found in form of phosphate ions PO₄⁻³, which are forming part of sedimentary rocks. Upon the action of wind and rain, phosphorous is washed into the soil (it dissolves and its passes into the soil in form of phosphate compounds). So, the largest reservoir of phosphorous is sedimentary rock.
Phosporous in the soil is absorbed by animal and plants and it is transformed in biological components (like nucleic acids, phospholipids, etc), and when animal and plants die, phosphorous return to the soil. So, the most of the phosphorous cycle occurs in the Earth (soil, water, living beings). In fact, phosphorous does not circulate through atmosphere.
Human activities such as farming and industry impact in phosphorous cycle. Fertilizers, wastes from human activities and phosphorous-containing products are poured in oceans and they feed the cycle.
But the excess of phosphorous often leads to an overgrowth of algae, which causes a lack of oxygen in water and consequenty the death of aquatic organisms. This fenomena is called eutrophication.
Finally, the major acid found in acid rain is sulphuric acid (it is not phosphoric acid).
A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically drops that distance before the track curves forward. If the velocity at the bottom of the drop is 10.0 m/s and the mass of the cart and passengers is 3.5 x 104 kg, how much potential energy was converted into thermal energy (heat)?
3.7 x 107 J
4.2 x 107 J
4.5 x 107 J
8.0 x 107 J
Answer:
Potential energy converted = 4.2*10^7 [J]
Explanation:
This problem has to be analysed under the principle of energy conservation. For this case potential energy that is transformed into kinetic energy, but however not all potential energy is transformed into kinetic energy, as we are told that some of this energy dissipates in the form of heat. We must first find the potential energy.
Potential energy
[tex]E_{p} =m*g*h\\where:\\m = mass =3.5*10^4[kg]\\g = gravity = 9.81[m/s^2]\\h = elevation = 126.5 [m]\\therefore\\E_{k} = 3.5*10^4*9.81*126.5\\E_{k} = 43433775 [J][/tex]
Kinetic Energy
[tex]E_{k}=\frac{1}{2} * m*v^{2}\\ where:\\v = velocity = 10[m/s]\\therefore:\\E_{k}=\frac{1}{2} * 3.5*10^4*10^{2}\\\\E_{k}=1750000[J][/tex]
As we can see, not all potential energy has been transformed into kinetic energy. That is, part of this energy dissipates as thermal energy, so this difference of energies will be equal to the loss of energy represented as dissipated energy.
[tex]Thermal Energy\\T_{e} = 43433775-1750000\\T_{e} =41683775[J][/tex]
The previous value can be approximated to 4.2 * 10^7 [J]
Answer:
4.2 x 10^7
I hope this helps!
In an analogy between water and electric current, water would correspond to charge. What would correspond to current, I?
In an analogy between water and electric current, the flow of water would correspond to the electric current. Electric current is defined as the rate at which charge flows, and can be envisioned as similar to the flow of water moving past a given section in a pipe. The direction of the current is the direction the positive charge would flow, although it's driven by the movement of negatively charged electrons.
Explanation:In an analogy between water and electric current, if water corresponds to charge, the flow of water would correspond to the electric current. This is because electric current is defined as the rate at which charge flows. Specifically, 1 Ampere (A) is equal to 1 Coulomb per second (1C/s), meaning it represents one coulomb of charge passing through a given area per second, similar to how we might measure the number of water molecules flowing past a specific point in a pipe per second.
Just as water flows from high to low elevation, electric current flows from high to low electrical potential. For example, in a battery, electrons (which carry the charge) will move from the low-potential terminal (negative end) through to the high-potential terminal (positive end). It should be noted that the direction of conventional current is defined as the direction positive charge would flow, even though, in reality, it is the negatively charged electrons that are moving.
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For an object that is speeding up at a constant rate in the positive direction,
what does the velocity vs. time graph look like?
A. A horizontal line, not on the x-axis.
B. A line angled upward
C. A graph curving upward
D. A horizontal line on the x-axis
Answer:
B. A line angled upward
Explanation:
velocity is plotted along y- axis and time is plotted along x- axis so we get a line angled upward
a fan sitting in the stands behind centerfield sees the batter hit the ball before he hears the
ack of the bat. Which of the following best describes the behavior of the waves?
P A. Reflected light that shows you what is
happening travels to your eyes faster than
sound travels to your ears.
B. Reflection off the field helps you to see
because light bounces off to make colors, but
sound waves do not reflect.
C. The air in the stadium carries the light
waves better than it carries the sound waves.
D. Light moves through one medium, like air,
at the same speed, but sound changes its
speed.
Answer:A
Explanation:just took the test
11. Which has more mass, a 2 kg fluffy pillow or a 3 kg small piece of iron? More volume? Why are your
answers different?
A 2 kg fluffy pillow has more volume, while a 3 kg small piece of iron has more mass due to their differences in density.
Explanation:A 2 kg fluffy pillow has more volume, while a 3 kg small piece of iron has more mass.
The volume of an object is the amount of space it occupies. The fluffy pillow, being soft and compressible, takes up more space than its mass would suggest.
The mass of an object, on the other hand, is the amount of matter in it. The small piece of iron, though heavier, occupies less space and has a higher density than the fluffy pillow.
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A 3 kg piece of iron has more mass than a 2 kg pillow, but the pillow likely has a greater volume due to lower density. The difference in density affects the volume that the same mass of two different materials occupies.
The 3 kg small piece of iron has more mass than the 2 kg fluffy pillow because 3 kg is greater than 2 kg. However, the fluffy pillow likely has more volume because it is less dense than the iron. This difference occurs because density is defined as mass divided by volume. The iron has a higher density which means it has more mass in a given volume compared to the pillow's material. For instance, a kilogram of feathers has the same mass as a kilogram of iron, but the feathers occupy a much larger volume because they are less dense.
Let's consider the weight in Newtons as an example. The weight of an object on Earth can be calculated by multiplying its mass in kilograms by the acceleration due to gravity (9.8 m/s2). So, the weight of a 3 kg textbook is approximately 29.4 Newtons (3 kg × 9.8 m/s2).
Finally, comparing materials of the same weight, a pound of gold has the same mass as a pound of iron on Earth’s surface, but their volumes and thus their densitiess Will differ. The density is the critical factor determining volume for the same mass of two different substances.
Consider a golf club hitting a golf ball that results in the following graph of force versus time on a 45 gram golf ball. If the final velocity of the ball has a magnitude of 41 m/s, determine the value of Fmax
The question is missing the graph. So, the graph is attached below.
Answer:
The value of [tex]F_{max}[/tex] is 7380 N.
Explanation:
Given:
Mass of the ball is, [tex]m=45\ g=0.045\ kg[/tex]
Initial velocity of the ball is, [tex]u=0\ m/s(Assuming)[/tex]
Final velocity of the ball is, [tex]v=41\ m/s[/tex]
From the graph,
Time interval for which the force acts, [tex]\Delta t=0.5\ ms=0.5\times 10^{-3}\ s[/tex]
Height of the triangle is equal to the maximum force acting on the ball = [tex]F_{max}[/tex]
Now, we know that, impulse acting on the ball is equal to the area under the curve of force and time graph.
So, impulse is equal to the area of the triangle and is given as:
Impulse = [tex]\frac{1}{2}\times base\times height[/tex]
Here, base is time interval [tex]\Delta t[/tex] and height is [tex]F_{max}[/tex].
Impulse = [tex]\frac{1}{2}\times (0.5\times 10^{-3})\times F_{max}[/tex]
Impulse = [tex]0.25\times 10^{-3}F_{max}[/tex]
Now, we also know that, impulse is equal to the change in momentum of a body.
Therefore, change in momentum (Δp) is given as:
[tex]\Delta p=m(v-u)\\\Delta p = 0.045(41-0)=1.845\ kgms^{-1}[/tex]
Now, change in momentum is equal to impulse acting on the ball. Thus,
[tex]0.25\times 10^{-3}F_{max}=1.845\\\\F_{max}=\frac{1.845}{0.25\times 10^{-3}}\\\\F_{max}=7380\ N[/tex]
Therefore, the value of [tex]F_{max}[/tex] is 7380 N.
A worker lifts a load of 200 N with the help of a lever by applying an effort of 50 N. The load is
kept at a distance of 20 cm and the effort is applied at a distance of im from the fulcram. Find the
mechanical advantage, velocity ratio, and efficiency of the lever used.
a) The mechanical advantage is 4
b) The velocity ratio is 5
c) The efficiency is 80%
Explanation:
a)
The mechanical advantage of a lever (or any other machine) is given by
[tex]MA=\frac{Load}{Effort}[/tex]
Where
[tex]Eff[/tex] is the effort (the force applied in input)
[tex]Load[/tex] is the load (the force in output to the lever)
For the lever in this problem, we have:
[tex]Eff = 50 N[/tex]
[tex]Load = 200 N[/tex]
Substituting into the equation, we find the mechanical advantage of the lever:
[tex]MA=\frac{200}{50}=4[/tex]
b)
The velocity ratio of a lever (or any other machine) is given by the equation
[tex]vr=\frac{d_{res}}{d_{eff}}[/tex]
where
[tex]d_{res}[/tex] is the length of the resistance arm
[tex]d_{eff}[/tex] is the length of the effort arm
For the lever in this problem, we have
[tex]d_{res} = 20 cm[/tex]
[tex]d_{eff}=1 m = 100 cm[/tex]
Therefore, the velocity ratio is
[tex]vr=\frac{100}{20}=5[/tex]
The velocity ratio represents the ideal mechanical advantage of the machine, i.e. the mechanical advantage in absence of friction, or the maximum theoretical mechanical advantage.
c)
The efficiency of the lever is given by the following ratio:
[tex]\eta = \frac{MA}{vr}[/tex]
where
MA is the mechanical advantage
vr is the velocity ratio
For the lever in this problem, we have
MA = 4 (calculated in part a)
vr = 5 (calculated in part b)
Therefore, the efficiency of the lever is
[tex]\eta = \frac{4}{5}=0.80[/tex]
Which means an efficiency of 80%.
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An area where the water table is at, near, or above the land surface long enough during the year to support adapted plant growth is called a(n)
An area where the water table is at, near, or above the land surface long enough during the year to support adapted plant growth is called a wetland.
Explanation:
Wetland is a private water body, which gets fed permanently or seasonally. Wetland is not purely a water body, because it allows some aquatic plants to grow which have adapted to its hydric soil. They have their place in almost every continent. They have some types too, namely swamp, marsh, bog, etc.
Mangrove forests are also a type of wetlands because the roots of the mangrove trees store a huge amount of water, which can be used for different purposes. And also, the wetland is at sea-level, which means it is near to the water table also. Its spatial flow is identical to that of the flow of groundwater.
what is meant by the statement that the linear expansivity of copper is 0.000017/k?
help me
oh, and uhmm;
steel bars each of length 3m at 29°c are to be used for constructing a rail line. if the linear expansivity of steel is 1.0×10⁻⁵/k. calculate the safety gap that must be kept between successive bars, if the highest temperature expected is 40°c
a) It means that the relative change of length of the copper, [tex]\Delta L/L[/tex], increases by 0.000017 for each increase in temperature of 1 degrees
b) The safety gap must be 0.33 mm
Explanation:
a)
The linear expansivity of a material is a measure of how much the length of a sample of that material expands per unit increase of temperature.
Mathematically, the linear expansivity can be written as
[tex]\alpha = \frac{\Delta L/L}{\Delta T}[/tex]
where
[tex]\Delta L[/tex] is the change in length of the sample
L is the original length of the sample
[tex]\Delta T[/tex] is the change in temperature of the sample
For instance, in this problem, we are told that the linear expansivity of copper is
[tex]\alpha = 0.000017/K[/tex]
Which means that the relative change of length of the copper, [tex]\Delta L/L[/tex], increases by 0.000017 for each increase in temperature of 1 degrees.
b)
We can re-write the formula written in part a as
[tex]\Delta L = \alpha L \Delta T[/tex]
where, applied to this problem, each variable means:
[tex]L[/tex] is the length of the steel bar
[tex]\alpha[/tex] is the linear expansivity of steel
[tex]\Delta L[/tex] is the change in length of the steel bar when the temperature increases by [tex]\Delta T[/tex]
In this problem, we have:
L = 3 m
[tex]\alpha = 1.0\cdot 10^{-5}/K[/tex]
[tex]\Delta T = 40^{\circ}C-29^{\circ}C=11^{\circ}C[/tex]
Therefore, the change in length of a steel bar is
[tex]\Delta L = (1.0\cdot 10^{-5})(3)(11)=0.00033 m = 0.33 mm[/tex]
Which means that the safety gap between two successive bars must be 0.33 mm.
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