f(x) = 4x+8
g(x) = x+3,
Find f(x)*g(x)

Answer:

[tex]6 \frac{5}{9} [/tex]

is greater than

[tex]6 \frac{15}{28} [/tex]

Answer:6 5/9 is greater than 6 15/28

Step-by-step explanation: positive proper fractions: 15/28, 5/9;

1 positive integer number: 6; Any positive proper fraction is smaller than

any positive integer number Sort the positive proper fractions:

15/28 and 5/9 15/28 already reduced to the lowest terms;

the numerator and the denominator have no common prime factors:

15 = 3 × 5;

28 = 22 × 7;

5/9 already reduced to the lowest terms;

the numerator and the denominator have no common prime factors:

5 is a prime number;

9 = 32; 15 = 3 × 5;

5 is a prime number;

Multiply all the unique prime factors, by the largest exponents:

LCM (15, 5) = 3 × 5 = 15 Divide LCM by the numerator of each fraction:

For fraction: 15/28 is 15 ÷ 15 = (3 × 5) ÷ (3 × 5) = 1;

For fraction: 5/9 is 15 ÷ 5 = (3 × 5) ÷ 5 = 3;  Build up all the fractions to the same numerator (which is LCM).

Multiply the numerators and the denominators by their expanding number:

15/28 = (1 × 15)/(1 × 28) = 15/28;

5/9 = (3 × 5)/(3 × 9) = 15/27;

Answer:

They are not equal? I don't get what you're trying to ask.

Answer:

[tex]\displaystyle 2x - 3y = 6\:OR\:y = \frac{2}{3}x - 2 \\ \\ 3x - 2y = 40\:OR\:y = \frac{3}{2}x - 20[/tex]

Step-by-step explanation:

2 = ⅔[6] + b

4

[tex]\displaystyle -2 = b \\ \\ y = \frac{2}{3}x - 2[/tex]

If you want it in Standard Form:

y = ⅔x - 2

- ⅔x - ⅔x

_________

−⅔x + y = −2 [We do not want fractions in our standard equation, so multiply by the denominator to get rid it.]

−3[−⅔x + y = −2]

[tex]\displaystyle 2x - 3y = 6[/tex]

_______________________________________________

−5 = 3⁄2[10] + b

15

[tex]\displaystyle -20 = b \\ \\ y = \frac{3}{2}x - 20[/tex]

If you want it in Standard Form:

y = 3⁄2x - 20

- 3⁄2x - 3⁄2x

__________

−3⁄2x + y = −20 [We do not want fractions in our standard equation, so multiply by the denominator to get rid of it.]

−2[−3⁄2x + y = −20]

[tex]\displaystyle 3x - 2y = 40[/tex]

* Parallel Lines have SIMILAR RATE OF CHANGES [SLOPES], so ⅔ and 3⁄2 remain the way they are.

I am joyous to assist you anytime.

Answer:

AY = 10 cm.

Step-by-step explanation:

Given that, ΔABC is similar to ΔAXY

and [tex]\frac{AB}{AX }  = \frac{5}{3}[/tex]

⇒  [tex]\frac{AC}{AY }  =  [tex]\frac{BC}{XY } = \frac{5}{3}[/tex]

⇒ BC = XY× \frac{5}{3}[/tex] =  \frac{20}{3}[/tex] (as XY = 4 cm given)

Now, check the attached figure,

given, BY bisects ∠XYC

let ∠XYB = ∠BYC = x

⇒ ∠AYX = 180-2x (angle on a straight line)

and also ∠AYX = ACB (similar triangle properties)

⇒ ∠ACB = 180-2x

Now, sum of angles in ΔBYC = 180°

⇒ ∠YBC = x

⇒ BC = YC (as two sides of equal angles are equal in a triangle)

⇒ YC =  \frac{20}{3}[/tex]

And also [tex]\frac{AC}{AY }  = \frac{5}{3}[/tex]

AC = AY + YC

⇒ [tex]\frac{AY+YC}{AY }  = \frac{5}{3}[/tex]

⇒ [tex]\frac{AY+\frac{20}{3}[/tex]}{AY }  = \frac{5}{3}[/tex]

⇒ 5AY = 3AY + 20

⇒ AY = 10 cm

The slope is -4/5

Step-by-step explanation:

We have to observe the graph to find two points to find slope.

The graph has two points

(-5,0) and (0, -4)

The formula for slope is given by:

[tex]m = \frac{y_2-y_1}{x_2-x_1}\\[/tex]

Here

(x1,y1) = (-5,0)

(x2,y2) = (0,-4)

Putting the values

[tex]m = \frac{-4-0}{0+5}\\=-\frac{4}{5}[/tex]

Hence,

The slope is -4/5

Keywords: slope, steepness

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Answer:

The width of the sandbox is 4 feet

Step-by-step explanation:

Area = Length x Width

Fill in known values

26 sq ft = 6.5 ft x w

Divide by 6.5 on both sides

4 ft = w

Width = 4 ft

:)

Answer:

Step-by-step explanation:

The probability of drawing the 8 of spades from a deck of cards is 1/52, or approximately 0.0192, which can also be expressed as 1.92%.

The probability of drawing the 8 of spades from a deck of cards is calculated as the number of favorable outcomes divided by the total number of possible outcomes. In this case, there is only 1 8 of spades card in the deck, and there are a total of 52 cards. Therefore, the probability is 1/52, or approximately 0.0192, which can also be expressed as 1.92%.

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Answer:

Very bottom graph

Step-by-step explanation:

Go .75 units right (positive x) then go 1.5 units down (negative y)

Answer:

Your answer will be D.

Step-by-step explanation:

Coordinate grid shown from negative 2 to positive 2 on the x-axis and negative 2 to positive 2 on the y-axis in increments of 1 over 4. Only the whole numbers are labeled. A point A is shown at the intersection of 3 grid lines to the right of the y-axis and 6 grid lines below the x-axis.

Answer:

m=7

Step-by-step explanation:

2m-(-3m)+(-15)=20

2m+3m-15=20

5m-15=20

5m=20+15

5m=35

m=35/5

m=7

Answer:

1.997 x 10²

Step-by-step explanation:

The number with the highest exponent is the greatest value.

10² is bigger than 10⁻⁶ and 10⁻⁸, so 1.997 x 10² is your answer.

Answer:

Length of the base = 8

Step-by-step explanation:

Area of a triangle = 1/2(h*b)

h = height

b = base

52 = 1/2 (13 * b)

Rearrange the equation to get b on it's own

52 * 2 = 13 * b

104 = 13 * b

104/13 = b

b = 8

A = 1/2(bh)

in this case, b = 2a/h. plug in the values:

steps

b = 2a/h

b = 2(52)/13

b = 104/13

b = 8 meters

Answer:

26.4 ft^2 (1 d.p.)

Step-by-step explanation:

[tex]area \: of \: circle = \pi {r}^{2} [/tex]

Since it is given that r, the radius of the circle, is 2.9 ft,

area of circle= π(2.9)^2= 8.41π= 26.4 ft^2 (1 d.p.)

Answer: x = 12

Step-by-step explanation:

[tex]\frac{6}{x}[/tex] = [tex]\frac{4}{8}[/tex]

cross multiply

4x = 6 × 8

4x = 48

divide through by 4

x = 12

Answer:

x-intercept

= 7/6

= 1.16667

Answer:

2/25

Step-by-step explanation:

Answer:

0.08

Step-by-step explanation:

(gof)(0) cannot be evaluated

Solution:

Given that,

[tex]f(x) = \frac{1}{x}\\\\g(x) = x - 4[/tex]

A composite function is denoted by (g o f) (x) = g (f(x)).

The notation g o f is read as “g of f”

Therefore, let us find whether (gof)(0) can be evaluated or not

To find (gof)(0):

(g o f) (x) = g (f(x))

Now substitute the given value of f(x)

[tex](g o f) (x) = g(\frac{1}{x})[/tex]

[tex]\text{ Substitute } x = \frac{1}{x} \text{ in } g(x) = x - 4[/tex]

[tex](g o f) (x) = \frac{1}{x} - 4[/tex]

Now to find (gof)(0), substitute x = 0

[tex](g o f) (x) = \frac{1}{0} - 4[/tex]

Since 1 divided by 0 is undefined, because any number divided by 0 is undefined

(gof)(0) cannot be evaluated

Answer:

You must evaluate the function f first.

Division by 0 is undefined.

The composition cannot be evaluated.

Step-by-step explanation:

Answer:

B. 28 degrees

Step-by-step explanation:

ok so,

the starting temperature is 35 degrees then the temperature dropped 4 degrees. making the temp 31 degrees. next the temperature rose 2 degrees, making it 33 degrees. lastly, the temperature dropped another 5 degrees making it 28 degrees out on wednesday.  

so the number line showing this would be B.

Final answer:

After a cold front caused the temperature to drop by 40 degrees from the initial 35 degrees Fahrenheit, the resulting temperature would be -5 degrees Fahrenheit on the number line for Wednesday morning at 8:00am.

Explanation:

The student originally observed a temperature of 35 degrees Fahrenheit on Sunday morning. If we suppose a cold front blows in and drops the temperature by 40.0 Fahrenheit degrees, the temperature change can be calculated by subtracting 40 from the initial temperature:

35 °F - 40 °F = -5 °F

Therefore, the number line that shows the temperature on Wednesday morning at 8:00am should have a point at -5 degrees Fahrenheit, representing the new temperature after the cold front.

Answer:

Step-by-step explanation:

X=-1/2

Hope this helps mark me as brainiest pls

Yes, -1/2 will be the x-coordinate for the solution. We can also find the y-coordinate by subbing in -1/2 for x in the equation y=4x+7.

y=4(-1/2)+7

y=-2+7

y=5

The intersection point would be (-1/2,5).

Answer:

OPTION A: [tex]$ \frac{12}{1 + 8x} $[/tex], where [tex]$ x \ne - \frac{1}{8} $[/tex].

Step-by-step explanation:

Given: [tex]$ \frac{- 12x^4}{x^4 + 8x^5} $[/tex]

Taking [tex]$ x^4 $[/tex] common outside in the denominator, we get:

[tex]$ = \frac{-12x^4}{(x^4)(1 + 8x)} $[/tex]

[tex]$ x^4 $[/tex] will get cancelled on the numerator and denominator, we get:

[tex]$ = \frac{-12}{1 + 8x} $[/tex]

we know that the denominator can not be zero.

That means, 1 + 8x [tex]$ \ne $[/tex] 0.

[tex]$ \implies 8x \ne -1 $[/tex]

[tex]$ \implies x \ne \frac{-1}{8} $[/tex]

So, the answer is: [tex]$ \frac{-12}{1 + 8x} $[/tex], where [tex]$ x \ne \frac{-1}{8} $[/tex].

Answer:

Jamal  is correct.

Step-by-step explanation:

3:4 is equivalent to 9:12, not 18:12.

We can see that for 3:4, the left side is less than the right, but for 18:12, left side is greater than the right, which immediately tells us the ratios are not equivalent.

Jamal is correct. 18:12 and 3:4 are not equivalent ratios.

To determine if two ratios are equivalent, you can simplify them to their simplest form or find a common factor that divides both terms. In this case:

18:12 can be simplified by dividing both terms by their greatest common factor, which is 6:

18 ÷ 6 = 3

12 ÷ 6 = 2

So, 18:12 simplifies to 3:2.

Now, compare it to 3:4. Since they have different values (3:2 vs. 3:4), Jamal's statement is incorrect, and Margie is right; they are not equivalent ratios.

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Answer:

y = 3

Step-by-step explanation:

Answer:

6^h=126

Step-by-step explanation:

6 to the power of h is just 6^h

Plug it into an equation with =126

Boom you have the equation 6^h=126

Answer:

k=2

Step-by-step explanation:

3k-k+5k-7=7

2k+5k=7+7

7k=14

k=14/7

k=2

Answer:

[tex] \: \: \: \: \: \: \: \: 3k - k + 5k - 7 = 7 \\ = > 8k - k = 7 + 7 \\ = > 7k = 14 \\ = > k = \frac{14}{7} \\ = > k = 2[/tex]

Complete Question:

As you may have unintentionally forgotten to add the answer choices in your question, but I was able to find the complete the question and answering your question based on this as it may surely clear your concepts. Here is the complete question.

In which of the following functions would it be appropriate to use only positive integers for the domain? Select all that apply.

The function c(p) represents The cost for P people to attend the movies. The function m(t) represents the miles driven over T hours. The function t(m) represents the average high temperature for a given number of months. The function p(w) represents the prophet of a farmer who sells whole watermelons. The function h(n) represents the number of person-hours it takes to assemble n engines in a factory.

Answer Explanation:

Domain is termed as all the input values on a certain interval that define the function.

Here are the appropriate function scenarios where it is appropriate to use only positive integers.

The function c(p) represents The cost for P people to attend the movies.

As the function c(p) contains people. And People are not counted as negative, although they can be zero. So, only positive integers should be appropriate to use in this scenario.

The function m(t) represents the miles driven over T hours

As the function m(t) contains miles. And miles are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function t(m) represents the average high temperature for a given number of months.

As the function t(m) contains months. And months are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function p(w) represents the prophet of a farmer who sells whole watermelons.

As the function p(w) contains the number of watermelons. And watermelons are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function h(n) represents the number of person-hours it takes to assemble n engines in a factory.

As the function h(n) contains the number of engines. And engines are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

Keywords: domain, function, positive integer

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Answer:

The x-axis, it would be between quadrant 2 and quadrant 3

Answer:

[tex]\angle a=35^o[/tex]

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

An isosceles triangle has two equal sides and two equal interior angles

The angles opposite to the equal sides of an isosceles triangle are equal.

[tex]\angle b=\angle c[/tex]

we have

[tex]\angle c=55^o[/tex] -----> given problem

so

[tex]\angle b=55^o[/tex]

Remember that

The sum of the interior angles in any triangle must be equal to 180 degrees

[tex]\angle b+\angle c+2\angle a=180^o[/tex]

substitute the given values

[tex]55^o+55^o+2\angle a=180^o[/tex]

[tex]110^o+2\angle a=180^o[/tex]

[tex]2\angle a=180^o-110^o[/tex]

[tex]2\angle a=70^o[/tex]

[tex]\angle a=35^o[/tex]

Answer:

The numbers are 165 and 113

Step-by-step explanation:

Let

x ----> one number

y ----> the other number

we know that

[tex]x+y=278[/tex] ----> equation A

[tex]x=y+52[/tex] ----> equation B

substitute equation B in equation A

[tex](y+52)+y=278[/tex]

solve for y

[tex]2y=278-52[/tex]

[tex]2y=226[/tex]

[tex]y=113[/tex]

Find the value of x

[tex]x=y+52[/tex]

[tex]x=113+52=165[/tex]

therefore

The numbers are 165 and 113