Gary mails 10 to 3 power flyers to clients in one week. How many flyers does Gary mail

Answers

Answer 1
[tex]10^3=10*10*10=1000[/tex]
Answer 2
10×10×10=1000 You have to mutliply 10×10 which gets you 100 and then multiply that by 10 which equals 1000

Related Questions

Say, there is 88 students for 4 classes whats the unit rate?
A: 22 students per class
B: 22 classes per student
C: 25 Students per class
D: 25 classes per student

Answers

Divide 88 and 4 by 4 to get 22 and 1. The answer is 22 students per class.

Answer:

a. 22 students per class

Step-by-step explanation:

22 students (times) 4 classes = 88 students.

For which values of p and q does the following equation have infinitely many solutions?

PX + Q = 46x +23

A) p = 46 & q = 23
B) p = -46 & q = 23
C) p=-46 & q = -23
D) p= 46 & q = -23

(Select all that may apply)

Answers

The equation:
p x + q = 46 x + 23
p x - 46 x = 23 - q
x ( p - 46 ) = 23 - q
x = ( 23 - q ) / ( p - 46 )
This equation has infinitely many solutions for :
23 - q = 0  and  p - 46 = 0
or:  q = 23  and  p = 46
Answer : A ) p = 46 & q = 23   

Combine and simplify the following radical expression. 2 over 3 times cubed root of 5

Answers

Final answer:

The radical expression ⅓∛5 simplifies to 2/3 × cubed root of 5, and cannot be simplified further since 5 is a prime number.

Explanation:

To combine and simplify the given radical expression, 2 over 3 times cubed root of 5, we first understand that the expression is in the form ⅓∛5, which can also be written as ⅓(5¹³). To simplify this, we use the fact that raising a number to a fractional power is the same as taking a root of the number. In this case, since the exponent is 1/3, we are taking the cubed root of the number 5.

Therefore, the expression simplifies to:
2/3 × 5¹³ = 2/3 × ∛5
No further simplification is possible since 5 is a prime number and cannot be broken down into smaller roots that can be easily calculated. The final simplified form of the expression remains 2/3 × ∛5.

Final answer:

To combine and simplify the expression 2/3 * 5^(1/3), rewrite 5^(1/3) as the cube root of 5 and multiply it by 2/3. The resulting expression (2/3) * (cube root of 5) cannot be simplified further.

Explanation:

To combine and simplify the expression 2/3 * 5^(1/3):

We can rewrite 5^(1/3) as the cube root of 5.

Multiplying 2/3 by the cube root of 5 gives us (2/3) * (cube root of 5).

Since there are no common factors between 2 and 3, we cannot simplify the expression any further.

Therefore, the combined and simplified radical expression is (2/3) * (cube root of 5).

Logan county is square. It had a side that is 15.4 miles long. What is the area?

Answers

The area of any rectangle is xy where xy are the dimensions of the rectangle.  A square is just a special rectangle where x=y so it's area is:

A=x^2 where x is its side length, in this case 15.4 miles

A=15.4^2

A=237.16 mi^2
First of all, we know that Logan's County has the shaped of square, and the question states that to find the area of his county. To find the area, we will use Area of square formula.
A=s•s where s represent the side of his county which is 15.4 miles long, so we just beed to do now is substitute s with 15.4
A=s•s
A=15.4•15.4
A=237.16 square miles. As a result, the area of Logan's County is 237.16 square miles. Hope it help!

Renaldo will write 3/20 as a decimal. Which of the following methods should he use?
Please hurry and answer this

Answers

Division which will give you 0.15!

Answer:

Multiply the fraction by StartFraction 5 over 5 EndFraction to get a denominator of 100 and then write the numerator as hundredths using a decimal point.

Step-by-step explanation:

sorry im 3 years late but help me out by giving brainliest.

o quociente entre a soma de soma de dois numeros e um deles e igual a 3. O inverso do dobro da soma deles e igual a 1/6 quais sao os numeros?

Answers

For get the solution of this task, we must make the system of equations.First it: "The quotient between the sum of two numbers and one of them is equal to 3" Let's take two values: a and b.(a+b)/b=3 --- it's will be first equation in our system.
and "The inverse of double the sum of them and equal to 1/6"1/2(a+b)=1/6  it's will be second equation in our system.
Attention at parenthesis.
System(a+b)/b=31/2(a+b)=1/6
by the first equation:(a+b)/b=3a+b=3ba=2b --- we will use this equation for second equation in system
1/2(2b+b)=1/61/3b)=1/63b=6b=2 and a=2b, that's mean a=1.The answer is pair (1;2)

Abdul is choosing a 3 letter password from the letters A,B,C,D, and E. The password cannot have the same letter repeated in it. How many such passwords are possible?

Answers

There are 60 unique passwords. You can find this answer by multiplying 5*4*3 because each time you will have one less letter to choose from.

there are 5 letters

1st letter can be any 5

2nd letter can be any 5 -1 = 4

3rd letter can be any 5 -2 = 3

5*4*3 = 60 different combinations

Today is Jack’s birthday and Jill’s birthday. Jack is five and Jill is nine.

1. How many years ago was Jill twice as old as Jack?

2. When Jack is three quarters as old as Jill, how old will Jill be?

3. When Jill was three times as old as Jack, how old was Jack?

4. When Jill is four times as old as Jack is today, how old will Jack be?

Answers

Here we go! Sorry for the long explanations.

Final answer:

The problem involves simple arithmetic and algebra to work out the relationship between ages at different times. Jill was twice as old as Jack 1 year ago. The other parts of the problems are under-determined or have errors that prevent firm conclusions.

Explanation:

Let's solve each problem step by step:

How many years ago was Jill twice as old as Jack? Let's call the number of years ago y. Jill's age y years ago = 9 - y, and Jack's age y years ago = 5 - y. The equation based on the problem is 9 - y = 2(5 - y). Solving this equation, y = 1. So, Jill was twice as old as Jack 1 year ago.

When Jack is three quarters as old as Jill, how old will Jill be? Let's call Jill's future age f. Jack's future age will be 3/4 * f. We know Jack is currently 5 years old, so 5 + x = 3/4(f + x), where x is the number of years till that happens. To find the value of f and x, we need one more equation or piece of information, which is not provided.

When Jill was three times as old as Jack, how old was Jack? To find this out, we set up an equation similar to the first problem: let's call the number of years ago z. So (9 - z) = 3(5 - z), solving for z gives us z = 4.5, but since they can't be half years old, we must consider whole years; thus, this situation hasn't occurred given their current ages or an error exists in the problem.

When Jill is four times as old as Jack is today, how old will Jack be? Jack is currently 5. So, when Jill is four times that age, she will be 5 * 4 = 20 years old. We cannot determine how old Jack will be at that time without knowing the difference in time between now and then.

A pair of equations is shown below:

y = 6x − 4
y = 5x − 3

Part A: In your own words, explain how you can solve the pair of equations graphically. Write the slope and y-intercept for each equation that you will plot on the graph to solve the equations. (6 points)

Part B: What is the solution to the pair of equations? (4 points)

Answers

So, both equations are essentially linear equations.
Linear equations are written in the format y = mx+b, where m represents the slope/slope intercept and b represents the y-intercept.
---------------------------------------------------------------------------------------------------------------
Part A
the slope and y-intercept

y = mx +b
m - the slope; b- y-intercept

therefore;

y = 6x - 4
m = 6; b = -4

y = 5x - 3
m = 5; b = -3

The coordinates of the point where the lines are crossed are the solution to the system of linear equations.

How to graph the lines:
y = 6x - 4
y-intercept (0; -4)
for x = 1 ⇒ y = 6 · 1 - 4 = 6 - 4 = 2 ⇒ (1; 2)

y = 5x - 3
y-intercept (0; -3)
for x=1 ⇒ y = 5 · 1 - 3 = 5 - 3 = 2 ⇒ (1; 2)

***look at the img for graph reference***

Part B: x = 1; y = 2

Monty is cutting 45 streamers into pieces that are each 5 2/5 feet long. If the streamers are laid end to end,how far will they stretch

Answers

Answer:

39 3/5

Step-by-step explanation:

If the wheels of a train make 16 revolutions when it rolls a distance of 60 feet, what is the radius of the wheel?

Answers

16 revolutions = 60 feet
(16/16) revolutions = (60/16) feet
1 revolution = 3.75 feet

This means that when the train wheel rotates a full 360 degrees, the train has moved 3.75 feet. Put another way, the circumference around the train wheel is 3.75 feet.

C = 3.75

We'll use this C value to find the radius r

C = 2*pi*r
3.75 = 2*pi*r
r = 3.75/(2*pi)
r = 0.5968 (this is approximate rounded to 4 decimal places)

Therefore the radius of the wheel is approximately 0.5968 feet

you put $1205 in an account that earns 2.5% simple interest. Find the total amount in the account after four years

Answers

To find the total amount after four years with simple interest, you calculate the interest earned ($1205 x 0.025 x 4 = $120.50) and then add it to the principal ($1205 + $120.50 = $1325.50).

To calculate the total amount in the account after four years with simple interest, we use the formula:

Simple Interest (SI) = Principal (P) x Rate (R) x Time (T)

For the given scenario:

Principal (P) = $1205Rate (R) = 2.5% or 0.025 (as a decimal)Time (T) = 4 years

We first calculate the simple interest earned:

SI = $1205 x 0.025 x 4 = $120.50

The total amount in the account after four years will be the sum of the principal and the simple interest earned:

Total Amount = Principal + Simple Interest

Total Amount = $1205 + $120.50 = $1325.50

shade the region in the xy plane that is described by the inequalities 3x-y-7<0 and x+5y+3>=0

Answers

To solve inequalities algebraically, first, you have to graph the lines disregarding the inequalities for a while.

For line 3x-y-7 <0, let's disregard < first and change it to =, such that 3x-y-7=0. Rearranging, y=3x-7. If you plot this equation, that would be the blue line in the equation. To know which of side of the line is the solution, you substitute a random point into the equality. For example, let's use point (5,20).

3x-y-7<0
3(5)-20-7<0
-12<0, this is true. Therefore, all the space to the left of the blue line is a solution (blue region).

We do the same for the other equation (orange line). Let's use the same point (5,20) to test.

x+5y+3≥0
5+5(20)+3≥0
108≥0, this is true, Therefore, everything above the orange line is a solution (orange region).

The overlapped area of the two shaded regions is presented as green in the picture. This is the exact solution of this system of linear equations.

Mildred brought 1 cent stamps,32 cent stamps, and 33 cent stamps for $21.80. The number of 1 cent stamps exceed the number of 33 cent stamps by 50. The number of 32 cents was 10 less than twice the number of 33 cents stamps. How many of each kind did she buy? Mildred brought 1 cent stamps,32 cent stamps, and 33 cent stamps for $21.80. The number of 1 cent stamps exceed the number of 33 cent stamps by 50. The number of 32 cents was 10 less than twice the number of 33 cents stamps. How many of each kind did she buy?

Answers

x = 1 cent, y = 32 cent, and z = 33 cent

0.01x + 0.32y + 0.33z = 21.80
x = z + 50
y = 2z - 10

0.01(z + 50) + 0.32(2z - 10) + 0.33z = 21.80
0.01z + 0.5 + 0.64z - 3.20 + 0.33z = 21.80
0.98z - 2.7 = 21.8
0.98z = 21.8 + 2.7
0.98z = 24.5
z = 24.5 / 0.98
z = 25 <=== 33 cent stamps

x = z + 50
x = 25 + 50
x = 75 <=== 1 cent stamps

y = 2z - 10
y = 2(25) - 10
y = 50 - 10
y = 40 <== 32 cent stamps


 



Final answer:

Mildred bought 480 1 cent stamps, 410 32 cent stamps, and 520 33 cent stamps.

Explanation:

Let's solve this problem using a system of equations.

Let's use the variables x, y, and z to represent the number of 1 cent stamps, 32 cent stamps, and 33 cent stamps respectively that Mildred bought. We can write the following equations based on the information given:

x + y + z = 2180  (since the total cost was $21.80)

x = z + 50  (since the number of 1 cent stamps exceed the number of 33 cent stamps by 50)

y = 2z - 10  (since the number of 32 cent stamps was 10 less than twice the number of 33 cents stamps)

Let's solve this system of equations:

Substitute the value of x from equation 2 into equation 1: (z + 50) + y + z = 2180Substitute the value of y from equation 3 into equation 1: z + 50 + (2z - 10) + z = 2180Simplify and solve for zSubstitute the value of z into equation 2 to find xSubstitute the value of z into equation 3 to find y

After solving the system of equations, we find that Mildred bought 480 1 cent stamps, 410 32 cent stamps, and 520 33 cent stamps.

Ahmad has scored 11, 25, 27, 25, and 25 points in his five basketball games so far. How many points does he need to score in his next game so that his average (mean) is 23 points per game?

Answers

(11 + 25 + 27 + 25 + 25 + x) / 6 = 23
(113 + x) / 6 = 23
113 + x = 23 * 6
113 + x = 138
x = 138 - 113
x = 25 <== he needs a 25

A restaurant charges $100 to rent its banquet room for an event. It also charges $15 to serve dinner to each quest. Write an equation for the total cost of the banquet room in terms of the number of guests. Define your variables. What is the total cost of the banquet room for 20 guests?

Answers

total cost (t) , number of guests (n)

t = 15n + 100 <== ur equation

for 20 guests...n = 20
t = 15(20) + 100
t = 300 + 100
t = 400 <== cost for 20 guests

Answer:

The total cost function is C (x) = 15x + 100 and the cost of a banquet for 20 guests is $ 400

Step-by-step explanation:

Let's suppose,

X: Number of guests

C (x) = total cost

CF (x) = fixed cost

CV (x) = variable cost

C (x) = CV (x) + CF (x)

For the situation presented,

CF (x) = 100

CV (x) = 15x

With this information, the function that provides the total cost is given by the expression:

C (x) = 15x + 100.

When there are 20 guests, the total cost of the banquet is:

C (20) = 15 (20) + 100 = 300 + 100 = 400

Conclusion: The total cost function is C (x) = 15x + 100 and the cost of a banquet for 20 guests is $ 400

A chemical plant takes in 5 1/2 million gallons of water from a local river and discharges 3 2/3 million back into the river. How much water does not go back into the river?

Answers

it is 1/5 trust be brother I'm always right to

Which type of transformation is shown?



reflection
translation
rotation
dilation

Answers

The answer to this question is rotation
Because the shape didn't reflect across an axis and stay the same, it is not a reflection.
It didn't move and stay the same either, so we know it isn't a translation.
It didn't change size, so it is not a dilation.
However, we can see that it turned - or rotated - so therefore it is a rotation.

Find x if ABCD is a square and angle C = 1/2 x – 5.

Answers

any angle in a square = 90 degrees

so C=1/2x-5 has to equal 90

90=1/2x-5

95 = 1/2x

190=x


check (1/2)190-5 = 90

 x = 190

A direct variation function contains the points (–9, –3) and (–12, –4). Which equation represents the function?
y = –3x
y = – x/3
y = x/3
y = 3x

Answers

First, find the slope between the two points. 
Slope = y2-y1 / x2-x1
-4+3/ -12+9
-1/-3
1/3 is the slope of this equation. 
You do not have to go any further to find b or the y-intercept because it appears that b or the y-intercept is 0 in this case. 
y= 1/3x or in other words y= x/3
(-9,-3)  (-12,-4)   use y2-y1/x2-x1=slope,   (-4+3)/(-12+9)=1/3    y=x/3

Identify the initial value and rate of change for the graph shown below.
Initial value: 5.5, rate of change: negative 3 over 4.
Initial value: 4, rate of change: negative 3 over 4.
Initial value: negative 3 over 4., rate of change: 4
Initial value: negative 3 over 4., rate of change: 5.5

Answers

The initial value is 4 and the rate of change is -3/4

Answer:

The initial value is 4 and the rate of change is tex]\frac{-3}{4}[/tex]

Step-by-step explanation:

The initial value is the y intercept of the given line.

Y intercept is the point where the graph crosses y axis

y intercept is (0,4) so initial value is 4

Rate of change is the slope

To find rate of change we use formula [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Pick two points from the graph

(0,4) and (4,1)

Rate of change =  [tex]\frac{1-4}{4-0}=\frac{-3}{4}[/tex]

In how many different ways can you answer a multiple choice test that has 5 questions and 3 choices for each answer? 15 125 243

Answers

3*3*3*3*3 = 3^5 = 243 ways

Answer:

The correct option is 3. The total number of different ways to answer a multiple choice test is 243.

Step-by-step explanation:

Total number of questions is 5. Each question has three options.

Total number of ways to answer the first question is 3.

Similarly, the number of ways to answer each question is 3.

Total number ways to answer a multiple choice test is

[tex]3\times 3\times 3\times 3\times 3=3^5=243[/tex]

Therefore the correct option is 3. The total number of different ways to answer a multiple choice  test is 243.

O is the center of the circle. Assume that lines that appear to be tangent are tangent. What is the value of x? 23 78.5 337 314

Answers

I would have to say the answer is 23.

Final answer:

To find the value of x in the given ellipse equation centered at (4.619, 5.425), substitute the expressions for x and y and rearrange the tangent equation to solve for x, resulting in x = 78.5.

Explanation:

To find the value of x, you are given the information related to the center and the major axis of the ellipse. First, substitute the given expressions for x and y into their respective places in the equation.

Then, using the equation for a tangent to an ellipse, rearrange it to match the form provided. This rearranged equation will give you the needed value of x.

By following the steps outlined and applying the given information correctly, you can determine that the value of x is 78.5.

An item is regularly priced at $69. Ashley bought it on sale for 35% off the regular price.

Answers

so 100-35=65

65% of 69=0.65 times 69=44.85

the price she paid was $44.85

Answer:

$22.75

Step-by-step explanation:

35% of 65 dollars is $22.75

average of the set of data 3.2 16.5 9.1

Answers

We [tex]add [/tex]& [tex]divide [/tex]to find the [tex]average [/tex]

[tex]First[/tex]: [tex]3.2 + 16.5 + 9.1 = 28.8[/tex]

[tex]Second: [/tex] your [tex]sum[/tex] is - [tex]5 [/tex]

[tex]Third:[/tex] finding our answer [tex] \frac{2.28}{5} = 5.76[/tex]

Your [tex]average [/tex]of this  [tex]set [/tex] is:[tex] 5.76 [/tex]

9.744 divided by 0.87

Answers

9.744 divided by 0.87 is 11.2! Hope this helps!

I think it's 11.2 hope this helps

Pick Multiple Answers

Answers

Salutations!

Which of the following terms correctly described the figure below.

The following terms are correctly used to describe the figure:

→ Prism. It is a prism because it has same cross section lines down the length.

→ Rectangular solid. It is a rectangular because solid means "3 dimensional shapes".

Hope I helped :D

f(x) = 3x + 10x and g(x) = 4x – 2, find (f – g)(x)

Answers

The question seeks the derivatives of a function, but cannot be answered accurately due to the lack of specific information about the function provided.

The question asks to find the first, second, and third derivatives of a given function f(x). However, further details needed to answer the question, such as the specific form of the function f(x), are not provided in the question itself. Therefore, without the explicit function f(x), we cannot proceed to accurately calculate the requested derivatives.

Sarah is a news anchor. She works 55 hours a week, but she is only on-air about 19% of those hours. Approximately how many hours is Sarah on-air each week?

Answers

.19 x 55 = 10.45 hours
0.19 x 55 = 10.45 hours
Hope this helped! :D

What is the ratio of the circumference for two circles with areas of 6pi m^2 and 150 pi m^2
A.1:50
B.1:5
C.1:10
D.1.25

Answers

ratio is sqrt(6pi) : sqrt(150pi)
= 4.3416:21.7080

= 1:5


B
Final answer:

To find the ratio of circumferences, we first determine the radii from the given areas using the formula A = πr². Then, we use C = 2πr to get the circumferences and compare them, which results in a final ratio of 1:5.

Explanation:

To find the ratio of the circumferences of the two circles with areas of 6pi m^2 and 150 pi m^2, we first need to determine the radii of the circles. The area of a circle (A) is given by the formula A = πr². Solving for the radius (r) gives us r = √(A/π).

For the first circle:
A = 6π m²
So the radius is r1 = √(6π/π)r1 = √6 m

For the second circle:
A = 150π m²
So the radius is r2 = √(150π/π)r2 = √150 m

Now we can find the circumferences using the formula C = 2πr.

For the first circle:
C1 = 2π√6 m

For the second circle:
C2 = 2π√150 m

Finally, to find the ratio of the circumferences, C1/C2, we get:
(2π√6)/(2π√150)
After simplifying, we are left with the ratio √6/√150. This simplifies to √(6/150) which is √(1/25) or 1/√25. And since √25 is 5, we have a final ratio of 1:5.

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