graph the equation by plotting three points. if all three are correct, the line will appear.
-3y=5x-7

Graph The Equation By Plotting Three Points. If All Three Are Correct, The Line Will Appear. -3y=5x-7

Answers

Answer 1

Answer:

(x, y) = (-1, 4), (2, -1), (5, -6)

Step-by-step explanation:

You can choose any value you like for either x or y, then solve for the other value. I like to plot points with integer coefficients, so I would look for sets of those.

The nature of this equation is that it will have integer solutions with x-values spaced 3 apart and y-values spaced 5 apart. (The spacing of each corresponds to the coefficient of the other.) So, the trick is to find an x-value that gives an integer solution for y. (You will need to try at most 3 consecutive integers.)

Solving the equation for y, we get ...

y = -5/3x +7/3

Right away, we know that x=0 will not give an integer solution for y. Nor does x=1. The third consecutive integer that is easy to try is x = -1, so ...

y = (-5/3)(-1) +7/3 = (5+7)/3 = 4 . . . . an integer value for y

Our first point is then (x, y) = (-1, 4).

Since the slope is negative, we know that increasing x will decrease y. Thus we can simply add (3, -5) to any point to get another point on the line.

Two more points on the line are ...

(-1, 4) +(3, -5) = (2, -1)

(2, -1) +(3, -5) = (5, -6)

Three integer-valued points on this line are (-1, 4), (2, -1), (5, -6).

Graph The Equation By Plotting Three Points. If All Three Are Correct, The Line Will Appear. -3y=5x-7

Related Questions

Please please help me out

Answers

Answer:

The measure of angle y is [tex]m\angle y=54\°[/tex]

Step-by-step explanation:

we know that

The inscribed angle is half that of the arc it comprises.

[tex]m\angle y=\frac{1}{2}(108\°)=54\°[/tex]

HELP PLEASE!!
Question 1 (2 points)
Generalize the pattern by finding the nth term.
6, 10, 14, 18, 22,
A. 4n
B. 4n + 2
C. 4n + 10
D. 6n + 4

Answers

Answer:

B. 4n+2

Step-by-step explanation:

You are given the pattern 6, 10, 14, 18, 22

Rewrite it as

[tex]a_1=6\\ \\a_2=10\\ \\a_3=14\\ \\a_4=18\\ \\a_5=22[/tex]

Note that

[tex]a_2-a_1=a_3-a_2=a_4-a_3=a_5-a_4=4[/tex]

This means that given pattern is a part of arithmetic sequence with

[tex]a_1=6\\ \\d=4[/tex]

So, the nth term of this arithmetic sequence is

[tex]a_n=a_1+(n-1)d\\ \\a_n=6+4(n-1)\\ \\a_n=6+4n-4\\ \\a_n=4n+2[/tex]

A bag contains 26 tiles showing a different letter from A to Z. Each player draws a letter tile at random. Player 1 wins if the letter is in his or her name. Player 2 wins if the letter is in his or her name. If the letter is in both their names then no one wins. Nathan and Katie play the game. Is this a fair game? If not, who has the advantage?

Answers

Answer:

no

Step-by-step explanation:

 Nathan has 6 letters in his name so he has a higher chance of winning

No, Katie has the advantage.

Katie has 5 distinct letters.

Nathan has 4 distinct letters.

They have one overlap (a).

Katie can expect to win 4 out of 26 games.

Nathan can expect to win 3 out of 26 games.

Since Katie has more distinct letters, she has the advantage, so it is not a fair game.

Hotdogs and corndogs were sold at last night’s football game. Use the information below to write equations to help you determine how many corndogs were sold.
The number of hotdogs sold was three fewer than twice the number of corndogs sold. Write an equation relating the number of hotdogs and corndogs. Let h represent the number of hotdogs and c represent the number of corndogs. A hotdog costs $3 and a corndog costs $1.50. If $201 was collected, write an equation to represent this information. How many corndogs were sold? Show how you calculated your answer.

Answers

Answer:

28

Step-by-step explanation:

If we set up our equation using the unknown number of hot dogs and corn dogs with their individual prices attached to them, we can set the sum of them equal to $201.  We know that a hot dog costs $3, so we can represent hot dogs monetarily by attaching the cost of a single hot dog to the h.  For example, if a hot dog costs $3, and we represent the expression as 3h, with h being the number of hot dogs sold, if we sell 4 hot dogs at $3 apiece, we make $12.  If we sell 6 hot dogs we will make $18.  The same goes for the corn dogs.  We don't know how many corn dogs or hot dogs we sold, but we do know that the sales of both made $201.  So our expression for that is

3h + 1.50c = 201

That's great, but we have too many unknowns, and that's a problem.  So let's look back up to where we are told that the number of hot dogs is 3 less than 2 times the number of corn dogs.  "3 less than" is -3 algebraically.  "Twice the number" is 2times  and the words "is" and "was" represent the = sign.  So putting those words into an algebraic equation looks like this:

h = 2c - 3

That says "the number of hot dogs was twice the number of corn dogs less 3".  Now that we have an expression for hot dogs we can sub it into our money equation in place of h:

3h + 1.5c = 201 becomes 3(2c - 3) + 1.5c = 201

Now we have an equation with only c's in it.  

Distribute through the parenthesis to get

6c - 9 + 1.5c = 201

Simplify to 7.5c = 210

Now divide by 7.5 to get that c = 28.

Now that we know that, we go back with that number and sub it in for c in

h = 2c - 3 -->  h = 2(28) - 3 gives us that the number of hot dogs sold was 53

The total number of corn dogs sold is 28 corn dogs and number of hotdogs is 53

let

h = number of hotdogs

c = number of corndogs.

cost of hotdog = $3

corn dog = $1.50

The equation:

3h + 1.50c = 201 (1)

h = 2c - 3 (2)

substitute (2) into (1)

3(2c - 3) + 1.50c = 201

6c - 9 + 1.50c = 201

7.50c - 9 = 201

7.50c = 201 + 9

7.50c = 210

c = 210/7.50

c = 28

Therefore,

h = 2c - 3

= 2(28) - 3

= 56 - 3

= 53

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this is a geometry I question please explain your answer ty

Answers

Answer:

B. <Q = <R

Step-by-step explanation:

Angles are related to their intercepted arcs. An intercepted arc is found by finding the arc segment on a circle whose endpoints connect with the segments that make up an angle.

In this case, TQ and SQ make up <Q, so TS is the intercepted arc of <Q. However, TR and SR make up angle <R as well, making TS the intercepted arc of <R as well.

This means that because the angles share an intercepted arc, they are congruent.

How many vertices does a dodecahedron have

Answers

Answer:

20

Step-by-step explanation:

A dodecahedron is a three-dimensional figure made out of 12 regular pentagons.  It resembles a soccer ball, just more rough on the edges.

So, it has 12 faces made out of regular pentagons.  Each summit/vertex is a meeting point for 3 different pentagons.

So, you can easily calculate the number of vertices:

How many pentagon vertices in total?

12 pentagons with 5 vertices / pentagon = 60 vertices in total

But each vertex meets with two others... so you have to divide the number of total vertices by 3... so 60 / 3 = 20.

Answer:

12 faces

Step-by-step explanation:

~apex

(10.02)

The point (−3, 1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of θ? Make sure to show all work.


Answers

Answer:

Part 1) [tex]sin(\theta)=\frac{\sqrt{10}}{10}[/tex]

Part 2) [tex]cos(\theta)=-3\frac{\sqrt{10}}{10}[/tex]

Part 3) [tex]tan(\theta)=-1/3[/tex]

Step-by-step explanation:

we know that

The angle is in the second quadrant  so the sine is positive, the cosine is negative and the tangent is negative

step 1

Find the radius r applying the Pythagoras theorem

[tex]r^{2}=x^{2} +y^{2}[/tex]

substitute the given values

[tex]r^{2}=(-3)^{2} +(1)^{2}[/tex]

[tex]r^{2}=10[/tex]

[tex]r=\sqrt{10}\ units[/tex]

step 2

Find the value of [tex]sin(\theta)[/tex]

[tex]sin(\theta)=y/r[/tex]

substitute values

[tex]sin(\theta)=1/\sqrt{10}[/tex]

Simplify

[tex]sin(\theta)=\frac{\sqrt{10}}{10}[/tex]

step 3

Find the value of [tex]cos(\theta)[/tex]

[tex]cos(\theta)=x/r[/tex]

substitute values

[tex]cos(\theta)=-3/\sqrt{10}[/tex]

Simplify

[tex]cos(\theta)=-3\frac{\sqrt{10}}{10}[/tex]

step 4

Find the value of [tex]tan(\theta)[/tex]

[tex]tan(\theta)=y/x[/tex]

substitute values

[tex]tan(\theta)=-1/3[/tex]

Which members are in the sample

Answers

Answer:

20, 26, 35, 18

Step-by-step explanation:

So starting at row 129, we look at the sequence two-digits at a time without overlapping.  If that number is between 01 and 43, then they get selected.

The first two digits are 20.  That fits between 01 and 43, so that member gets selected.

Next, we have 26.  That also fits.

After that we have 64.  Nope, too high.

98 and 44 are also too high.

35 fits though.  So does 18.

So the members that get selected are 20, 26, 35, 18.

Drag each tile to the correct box. Arrange the equations in order from least to greatest bed on their solution. Equation A: 5( x-6)+3x=3/4(2x-8) Equation B: 2.7(5.1x+4.9)=3.2+28.9 Equation C: 5(11x-18)=3(2x+7)

Answers

Answer:

B

C

A

Step-by-step explanation:

Find the value of x in each equation then compare the solutions from the least to the greatest

In A

5( x-6)+3x=3/4(2x-8) ------------Open brackets

5x-30+3x=3/2x-6

5x+3x-30=3/2x-6

8x-3/2x=-6+30---------------collect like terms

16x-3x=48

13x=48-----------------dived both sides by 13

x=48/13 = 3.7

In B

2.7(5.1x+4.9)=3.2+28.9-------------open bracket

13.77x+13.23=32.1

13.77x=32.1-13.23---------------collect like terms

13.77x=18.87

x=18.87/13.77----------------------divide both sides by 13.77

x=1.37

In C

5(11x-18)=3(2x+7)--------------------open brackets

55x-90=6x+21

55x-6x=21+90-----------------------collect like terms

49x=111----------------------------------divide both sides by 49 to get x

x=111/49 = 2.27

From the solutions, the least value of x is in B, then C ,and finally A

Equation B:[tex]\(x \approx 1.371\)[/tex]

Equation C:[tex]\(x \approx 2.2653\)[/tex]

Equation A: [tex]\(x = \frac{48}{13}\)[/tex]

Order from least to greatest: B, C, A.

To solve each equation, let's start by simplifying each side of the equation step by step.

Equation A:[tex]\(5(x-6) + 3x = \frac{3}{4}(2x - 8)\)[/tex]

Step 1: Distribute the numbers:

[tex]\(5x - 30 + 3x = \frac{3}{4}(2x) - \frac{3}{4}(8)\)[/tex]

Step 2: Combine like terms:

[tex]\(8x - 30 = \frac{3}{2}x - 6\)[/tex]

Step 3: To get rid of the fraction, multiply both sides by 2:

(16x - 60 = 3x - 12)

Step 4: Move all (x) terms to one side by subtracting (3x) from both sides:

(16x - 3x - 60 = -12)

Step 5: Combine like terms:

(13x - 60 = -12)

Step 6: Add 60 to both sides to isolate (x):

13x = 48

Step 7: Divide both sides by 13 to solve for (x):

[tex]\(x = \frac{48}{13}\)[/tex]

Equation B: 2.7(5.1x + 4.9) = 3.2 + 28.9

Step 1: Distribute the number:

13.77x + 13.23 = 32.1

Step 2: Move the constant to the other side by subtracting 13.23 from both sides:

13.77x = 18.87

Step 3: Divide both sides by 13.77 to solve for (x):

x ≈ 1.371

Equation C: (5(11x - 18) = 3(2x + 7)

Step 1: Distribute the numbers:

55x - 90 = 6x + 21

Step 2: Move all (x) terms to one side by subtracting (6x) from both sides:

55x - 6x - 90 = 21

Step 3: Combine like terms:

49x - 90 = 21

Step 4: Add 90 to both sides to isolate (x):

49x = 111

Step 5: Divide both sides by 49 to solve for (x):

x ≈ 2.2653

Now, let's order these solutions from least to greatest:

[tex]\(x= 1.371\)[/tex] (from Equation B)

[tex]\(x = 2.2653\)[/tex] (from Equation C)

[tex]\(x = \frac{48}{13}\)[/tex] (from Equation A)

So, the order from least to greatest based on their solutions is Equation B, Equation C, and then Equation A.

Express in scientific notation 1,789

Answers

Answer:

[tex]1.789*10^{3}[/tex]

Answer: 1.789 × 10 to the third power

Step-by-step explanation: the answer would be 1.789 x 10 to the third power because the A term has to be between 1 and 10

PLEASE HELP ME SOLVE THIS QUESTION!!
***quickest and shortest way***

Answers

Answer:

1/4 bag for each batch.

Step-by-step explanation:

Start with 4 bags. If the cake requires 1/4 bag, then 3 3/4 bags of flour are left over for the cookies.  That's rather a nice number when you are dealing with 15 batches of cookies.

Start by changing the 3 3/4 into a decimal.

3 3/4 = 3.75

Now divide 3.75 by 15

3.75 / 15 = 0.25 bags which is 1/4 bag. You only have to come up with one value so this one will do.

through (-1,2) parallel to y=-4x+3

Answers

Answer:

y = -4x - 2

Step-by-step explanation:

Parallel has same slope

so

y - 2 = -4(x + 1)

y - 2 = -4x - 4

y = -4x - 2

Equation

y = -4x - 2

Anyone know the answer to this?

Answers

Answer:

[tex]2^{n-1}[/tex]

Step-by-step explanation:

Square 1 has 2^0 pennies.

Square 2 has 2^1 pennies.

Square 3 has 2^2 pennies.

Square 4 has 2^3 pennies. The exponent of 2 is 1 less than the square number, so ...

Square n has 2^(n-1) pennies.

A copy machine depreciates at the rate of 15% each year. If the original cost of the copy machine was $20,000, what is the approximate value of the machine at the end of 3 years?

Answers

$12,282.5 (20000x0.85x0.85x0.85)

Final answer:

The value of the copy machine depreciates at a rate of 15% each year. After calculating the depreciated value for 3 consecutive years, the copy machine that initially cost $20,000 is worth approximately $12,282.50 after 3 years.

Explanation:

The original cost of the copy machine is $20,000. Given that the copy machine depreciates, or loses value, at a rate of 15% each year, we need to calculate the value of the copy machine each year for 3 years by subtracting 15% of its current value.

In the first year, the value of the copy machine would be $20,000 - (15% of $20,000) = $20,000 - $3,000 = $17,000. In the second year, we will take 15% off $17,000, so the value will be $17,000 - (15% of $17,000) = $17,000 - $2,550 = $14,450. Finally, in the third year, we will take 15% off $14,450, so the final value is $14,450 - (15% of $14,450) = $14,450 - $2,167.50 = $12,282.50. So, the approximate value of the machine at the end of 3 years is $12,282.50.

Learn more about Depreciation here:

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A candle manufacturer sells cylindrical candles in sets of three. Each candle in the set is a different size. The smallest candle has a radius of 0.5 inches and a height of 3 inches. The other two candles are scaled versions of the smallest, with scale factors of 2 and 3. How much wax is needed to create one set of candles? A. 27 π cubic inches B. 36 π cubic inches C. 53 π cubic inches D. 86 π cubic inches E. 98 π cubic inches

Answers

Answer:

A. 27 π cubic inches

Step-by-step explanation:

The volume of a cylinder is calculated using the formula;

[tex]Volume=\pi r^2h[/tex]

From the given information, the smallest candle has a radius of 0.5 inches and a height of 3 inches.

We substitute [tex]r=0.5[/tex] and [tex]h=3[/tex] into the given formula.

The vlume of the smallest candle is

[tex]Volume=\pi \times0.5^2\times 3[/tex]

[tex]Volume=\frac{3}{4}\pi in^3[/tex]

from the given information, the other two candles are scaled versions of the smallest, with scale factors of 2 and 3.

The volume of the other two candles will be [tex]2^3\times \frac{3}{4}\pi=6\pi in^3[/tex] and [tex]3^3\times \frac{3}{4}\pi=\frac{81}{4}\pi in^3[/tex]

The wax needed to create one set of candle is

[tex]\frac{3}{4}\pi+6\pi+\frac{81}{4}\pi=27\pi\: in^3[/tex]

The correct answer is A

Answer:

27 pi in³

Step-by-step explanation:

I just took a test on Plato/Edmentum with this question and this was the right answer

~Please mark me as brainliest :)

Solve for x.
1/10(x - 3) = -40
A) -403
B) -397
C) -7
D) -1

Answers

Answer:

-397

Step-by-step explanation:

This may look daunting, but let us approach it step by step.

Step 1: Remove the Parentheses

multiply 1/10 by x - 3

0.1x - 0.3 = -40

Step 2: Add 0.3

In algebra, the goal is always to undo all the operations and get back to the original problem so that the mystery value can be determined. In this case since 0.3 was removed, we must add it back.

0.1x = -39.7

Step 3. Divide by 0.1

0.1x/0.1 = x

39.7/0.1 = -397

Step 4. Preliminary Answer

Answer seems to be B. -397, but we should still check it.

Step 5: Check

0.1(-397) - 0.3 = -40

-39.7 - 0.3 = -40

-40 = -40 Correct

If the answer was incorrect, this would show that there had been a flaw in our calculations. But everything checks out, so we are done!

Step 6: Final Answer

Our final answer is B. -397.

PLEASE MARK BRAINLIEST

Answer:

The answer is -397

Step-by-step explanation:

At Eagle Rock High School, the probability that a student takes theatre and choir is 0.078. The probability that a student takes choir is 0.26. What is the probability that a student takes theatre given that the student is taking choir?

Answers

Final answer:

The probability that a student takes theatre given that the student is taking choir is found using conditional probability and is calculated to be 0.3, or 30%.

Explanation:

To find the probability that a student takes theatre given that the student is taking choir, we use the definition of conditional probability. In this scenario, the probability of a student taking theatre and choir (joint probability) is given as 0.078, and the probability of a student taking choir (marginal probability) is 0.26.

The formula for conditional probability is:

P(A | B) = P(A and B) / P(B)

Let A represent the event of a student taking theatre, and B represent the event of a student taking choir. Substituting the given values into the formula yields:

P(A | B) = 0.078 / 0.26

Performing the division gives us:

P(A | B) = 0.3

Therefore, the probability that a student takes theatre given that the student is taking choir is 0.3, or 30%.

What should the balance be in Diane's register?

Will give BRAINLIEST

Answers

Answer:

The balance of Dianne's register should be $359.41

Step-by-step explanation:

We can begin at the ending balance on the bank statement at $578.30

Then a check is written for $219.25, so a debit

Next a deposit is made for $140.36, so a credit

Then a withdrawal is made for $140.00, so a debit

This means we can make the equation

[tex]578.30-219.25+140.36-140.00=359.41[/tex]

A manufacturer makes closed cubic containers from sheet metal. How many square centimeters of sheet metal will a 27,000 cm 3 container need?

Answers

let's recall that a cube is just a rectangular prism with all equal sides, check picture below.

[tex]\bf \textit{volume of a cube}\\\\ V=s^3~~ \begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} V=&27000 \end{cases}\implies 27000=s^3\implies \sqrt[3]{27000}=s\implies 30=s \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a cube}\\\\ SA=6s~~\begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} s=&30 \end{cases}\implies SA=6(30)\implies SA=180[/tex]

Find the volume of the square pyramid below

Answers

Answer:

A

Step-by-step explanation:

The volume (V) of a pyramid is

V = [tex]\frac{1}{3}[/tex] area of base × perpendicular height (h)

area of square base = 4² = 16 and h = 4, hence

V = [tex]\frac{1}{3}[/tex] × 16 × 4 = [tex]\frac{64}{3}[/tex] = 21 [tex]\frac{1}{3}[/tex] ft³

What is the product?

8(–1)

Answers

8(-1) = -8

When a positive and a negative number is being multiplied the product is always negative, but when a negative and a negative number is being multiplied the product is positive

Hope this helped!

~Just a girl in love with Shawn Mendes

The answer is -8 because a positive X negative equals a negative

Use this formula to find the value of a house with appreciation: A = V (1+r)Y
When Henry bought his house for $135,700, he was told that it would appreciate at a rate of five percent per year. If this remains true, how much will his house be worth in four years?

Answers

Answer:

[tex]A=\$164,944.20[/tex]

Step-by-step explanation:

we know that

[tex]A=V(1+r)^{Y}[/tex]

In this problem we have

[tex]r=5\%=0.05[/tex]

[tex]V=\$135,700[/tex]

[tex]Y=4\ years[/tex]

substitute in the formula and solve for A

[tex]A=\$135,700(1+0.05)^{4}=\$164,944.20[/tex]

If you have 14 1/2 dozen boxes of envelopes, and you order 3 1/4 dozen more, how many dozen boxes will you have in all?

Answers

The answere is 213 boxes

If you add 3 dozens to 14 dozens of boxes of envilopes , then you get 17 dozens of boxes of envilopes.Then of you sum up the 1/2 (2/4 ) with the 1/4.You get 3/4. Finally, you add 17 dozens to 3/4 of a dozen you get 17 3/4 dozens( wich is 213 boxes )

Jimmy is trying to dive down and touch the bottom of the pool. On his first try he makes it 1/3 of the way to the bottom. On his second try he makes it 3/5 of the way to the bottom. Jimmys second dive was deeper than his first dive by what fraction of the pool?

Answers

Answer:

Jimmy's second dive was [tex]\frac{4}{15}[/tex] of the pool deeper than the first one

Explanation:

We are given that:

First dive was [tex]\frac{1}{3}[/tex] of the way to the bottom

Second dive was [tex]\frac{3}{5}[/tex] of the way to the bottom

We know that the second dive was deeper than the first one since [tex]\frac{3}{5} > \frac{1}{3}[/tex]

To know how much deeper the second dive was compared to the first one, we will simply subtract the depth of the first dive from that of the second one

Therefore:

The second dive was [tex]\frac{3}{5} - \frac{1}{3} = \frac{9}{15} - \frac{5}{15} = \frac{4}{15}[/tex] of the pool deeper than the first one

Hope this helps :)

Final answer:

Jimmy's second dive was 4/15 of the pool deeper than his first dive, calculated by finding a common denominator and subtracting the fractions representing the depth of each dive.

Explanation:

Jimmy's second dive was 3/5 of the way to the bottom of the pool, which is deeper than his first dive at 1/3 of the way. To find out how much deeper the second dive was compared to the first, we subtract the two fractions:

Second dive - First dive = 3/5 - 1/3

To subtract fractions, they must have a common denominator. Multiplying top and bottom of 3/5 by 3 and 1/3 by 5 gives us:

9/15 - 5/15 = 4/15

Therefore, Jimmy's second dive was 4/15 of the pool deeper than his first dive.



The City Zoo collected $100 in one morning. An adult ticket is $5 each, and a child's ticket is $3. How many different combinations of adult and children's tickets would have totaled $100?
5
6
7
8

Answers

Final answer:

To calculate the number of different combinations of adult and children's tickets that would total $100, we can set up an equation: 5x + 3y = 100. We can find possible values of 'x' and 'y' that satisfy the equation. There are 6 different combinations of adult and children's tickets that would have totaled $100.

Explanation:

To calculate the number of different combinations of adult and children's tickets that would total $100, we can set up an equation:

5x + 3y = 100

Where 'x' represents the number of adult tickets and 'y' represents the number of children's tickets. We need to find whole number solutions for 'x' and 'y'.

We can start by finding the possible values of 'x' and 'y' that satisfy the equation and add up to $100. The possible combinations are:

x = 0, y = 33

x = 5, y = 31

x = 10, y = 29

x = 15, y = 27

x = 20, y = 25

x = 25, y = 23

Therefore, there are a total of 6 different combinations of adult and children's tickets that would have totaled $100.

John owns an engine which receives heat input from a reservoir at 600 K and loses heat to a sink at 300 K. What is the maximum possible efficiency of this engine?

A.
25 percent

B.
50 percent

C.
75 percent

D.
100 percent

Answers

Answer:

D. 100 percent

Step-by-step explanation:

it is 100 percent because the reservoir is putting out 600k, but loses 300k, which would be easy to think it would be 50 percent because 300k is half of 600k, but however its peek outage is putting out 600k, therefore 600k = 600k, 100%.

B. 50 %

Formula : Output / Input. X 100%

: 300/600. X 100

= 50%

Please please help me

Answers

Answer:

(a)

Step-by-step explanation:

The line y = x + 1 has a solid circle at x = 2 indicating that x is valid for this value, thus

y = x + 1 for x ≤ 2

The line y = x + 2 has an open circle at x = 2 indicating that x = 2 is not part of the solution but that values greater than 2 are valid, that is

y = x + 2 for x > 2

The definition for the function is (a)

These are the means and standard deviations for samples of prices from two different brands of shoes. Brand A Brand B Mean: $50 Mean: $40 Standard deviation: $5 Standard deviation: $8 Select the two true statements.

Answers

(a) The average price of brand A is higher than average price of brand B

(b) The price of brand B is more spread out than the price of brand A.

Mean of the distributions

The mean of the distributions for the individual samples is given as;

Mean of Brand A = $50

Mean of Brand B = $40

Standard deviation of the samples

Standard deviation of Brand A = $5

Standard deviation of Brand B = $8

From the mean and standard deviation of the samples we can conclude the following;

The average price of brand A is higher than average price of brand B.The price of brand B is more spread out than the price of brand A.

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Final answer:

The two true statements are that Brand A's prices are less spread out than brand B's prices (C), reflected in the smaller standard deviation, and that Brand A has a higher average price than brand B (D), as indicated by their respective means.

Explanation:

The question involves comparing means and standard deviations for samples of prices from two different brands of shoes, Brand A and Brand B. To select the two true statements among the given options, we consider the provided statistics for each brand:

Brand A: Mean = $50, Standard deviation = $5Brand B: Mean = $40, Standard deviation = $8

Now let's analyze the statements:

A. Brand A has a lower average price than brand B - This statement is false because the mean of Brand A ($50) is higher than the mean of Brand B ($40).B. Brand A's prices are more spread out than brand B's prices - This statement is false as well because Brand A has a smaller standard deviation ($5) compared to Brand B ($8), indicating less spread.C. Brand A's prices are less spread out than brand B's prices - This statement is true, reflecting the smaller standard deviation for Brand A.D. Brand A has a higher average price than brand B - This statement is true as explained earlier.

Therefore, the two true statements are C and D: Brand A's prices are less spread out than brand B's prices, and Brand A has a higher average price than brand B.

Information about the recycling drive at school is shown in the table. Let A be the event that the item pulled out of the recycling bin is a plastic bottle, and let B be the event that a tenth grader recycled that item. Which statement is true about whether A and B are independent events? A and B are independent events because P(A∣B) = P(A). A and B are independent events because P(A∣B) = P(B). A and B are not independent events because P(A∣B) ≠ P(A). A and B are not independent events because P(A∣B) ≠ P(B).

Answers

Answer:

the answer is c

Step-by-step explanation:

The events are illustrations of probability, and the events A and B are not independent events because P(A∣B) ≠ P(A)

How to determine the true statement?

From the complete table, we have the following parameter:

P(A∣B) ≠ P(A)

Two events A and B are independent if

P(A∣B) = P(A)

Given that:

P(A∣B) ≠ P(A)

It means that the events are not independent.

Hence, the events A and B are not independent events because P(A∣B) ≠ P(A)

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Suppose that a coin is tossed 5 times. how many different outcomes include at least two heads

Answers

26 different outcomes include at least two heads.

There are [tex]26[/tex] different outcomes that include at least two heads when a coin is tossed [tex]5[/tex] times.

The total number of outcomes when a coin is tossed [tex]5[/tex] times is [tex]\(2^5 = 32\)[/tex], since each toss has [tex]2[/tex] possible outcomes (heads or tails).

To find the number of outcomes with at least two heads, we can find the total number of outcomes with exactly one head and no heads, and subtract that from the total number of outcomes.

1. Number of outcomes with no heads: There is only [tex]1[/tex] outcome with no heads ([tex]5[/tex] tails).

2. Number of outcomes with exactly one head: This can be calculated using combinations. There are [tex]5[/tex] ways to choose which toss will be heads, and for each of these, the remaining [tex]4[/tex] tosses must be tails. So, there are [tex]\(5 \times 1 = 5\)[/tex]outcomes with exactly one head.

Therefore, the number of outcomes with at least two heads is:

[tex]\[ 32 - 1 - 5 = 26 \][/tex]

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