HELP PLEASE!!!!!

Kajan repeatedly rolled a die and he was getting frustrated that he could not roll his favourite number, which is three. What is the probability that the first three occurred on the tenth roll?
0.0323 0.0269 0.323 mc009-1.jpg

Answers

Answer 1
The number of trials = 10
Probability of success (getting a 3) is p = 1/6
Probability of failure (not getting a 3) is q = 1 - 1/6 = 5/6

The probability of one success after 10 trials is given by the binomial distribution as
₁₀C₁ p¹ q⁽¹⁰⁻¹⁾ = 10*(1/6)*(5/6)⁹ = 0.323

Answer: 0.323

Related Questions

Find the length of the diameter of a sphere with a surface area of 452.39^2 ft.

Answers

surface area = 4*pi*r^2

using 3.14 for pi

452.39 = 4*3.14*r^2=

452.39=12.56* r^2

r^2 = 452.39/12.56 = 36.0


sqrt(36) = 6= r

diameter = 2r = 6*2= 12

 diameter = 12 feet

Meike earned $1565 in tips while working a summer job at a coffee shop. She wants to use this money to take a trip to Europe next summer. If she places the money in an account which pays 6.5% compounded continuously, how much money will she have in nine months?

Answers

your answer would be $1,643.18

Which of the following triangles are right triangles? Check all that apply
A triangle with side lengths 4, 5, 6
A triangle with side lengths 6 inches, 8 inches, 10 inches
A triangle with side lengths 8, 15, 17
A triangle with side lengths 5, 12, 13

Answers

If they are right triangles, they'll satisfy Pythagoras theorem:

a^2 = b^2  +c^2, with the longest side:

No: 6^2 = 4^2 + 5^2
Yes: 10^2 = 6^2 + 8^2
Yes: 17^2=15^2+8^2
Yes: 13^2 = 12^2 + 5^2

All but the first are right triangles. Check the 2nd,  3rd and 4th!

In this exercise we have to apply the Pythagorean theorem to know that it is possible to form a certain triangle, so we have:

A) No
B) Yes
C) Yes
D) Yes

Knowing that the Pythagorean theorem is given by:

[tex]a^2 = b^2 +c^2[/tex]

They are putting the values ​​informed we have:

A) [tex]6^2 = 4^2 + 5^2[/tex]

B) [tex]10^2 = 6^2 + 8^2[/tex]

C) [tex]17^2=15^2+8^2[/tex]

D) [tex]13^2 = 12^2 + 5^2[/tex]

See more about triangles at brainly.com/question/25813512

if ∠1 and ∠2 are complementary and m∠1= 17°, what is m∠2?



173 degrees
90 degrees
73 degrees
77 degrees

Answers

Complementary angles add up to 90*. Therefore, the logical answer would be 
D, 77.

Identify the value of y

Answers

24^2 = 18 * (18 +y)

576 = 324+18y

252 =18y

y = 252/18 =14

 y = 14

The value of y is 14.

What is a circle?

'A circle is a shape consisting of all points in a plane that are at a given distance from a given point, the center. Equivalently, it is the curve traced out by a point that moves in a plane so that its distance from a given point is constant'

According to the given problem,

We know,

⇒ 18 ( 18 + y ) = 24²

⇒ 324 + 18y = 576

⇒ 18y = 576 - 324

⇒ 18y = 252

⇒ y = 252/18

⇒ y = 14

Hence, we can conclude, the value of y is 14.

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The area of the right triangle shown is 24 square feet. Which equations can be used to find the lengths of the legs of the triangle? Check all that apply.

0.5(x)(x + 2) = 24

x(x + 2) = 24

x2 + 2x – 24 = 0

x2 + 2x – 48 = 0

x2 + (x + 2)2 = 24

x2 + (x + 2)2 = 100

Please help me quickly, I really need the help. I'll even mark brainiest if you do it correctly. I really need this and I need whoever does this to pay attention to the whole "Check all that apply". I'm adding the picture below.

Answers

Given : A  = 24 sq feet

A = 0.5 base x height

base = x , height = x+2

A = 0.5 x(x+2)  = 24 sq feet

1) 0.5 x(x+2) = 24 (A) 

2) x^2 + 2x - 48 = 0 (D)

To check the rest un-wrap the bracket:

x^2 + (x+2)^2 = 24

x^2 + x^2 + 4 + 4x = 24

2x^2 + 4x - 20 = 0

x^2 + 2x - 10= 0 (NO)

Likewise:

x^2 + (x+2)^2 = 100

x^2 + x^2  +4 + 4x = 100

2x^2 + 4x + 4 = 100

2x^2 + 4x - 96 = 0

3) x^2 + 2x - 48 = 0 (F)


To sum up: that's what apply:

1) 0.5 x(x+2) = 24 (A) 

2) x^2 + 2x - 48 = 0 (D)

3) x^2 + 2x - 48 = 0 (F)

The equation that can be used to find the lengths of the legs of the triangle is [tex]\rm 0.5(x)(x + 2) = 24[/tex]

Given that

The area of the right triangle shown is 24 square feet.

We have to determine

Which equations can be used to find the lengths of the legs of the triangle?

According to the question

From the given figure the base of the triangle is x.

And the height of the triangle is (x+2).

What is the area of a triangle?

The area of the triangle is given by half the product of the height and base.

[tex]\rm Area = \dfrac{1}{2} \times base \times height\\ [/tex]

Substitute all the values in the formula;

[tex]\rm Area \ of \ right \ triangle= \dfrac{1}{2} \times base \times height\\ \\ \rm 24= \dfrac{1}{2} \times x \times (x+2)\\\\ \rm 0.5(x)(x + 2) = 24[/tex]

The equation can be used to find the lengths of the legs of the triangle is [tex]\rm 0.5(x)(x + 2) = 24[/tex].

Hence, the equation can be used to find the lengths of the legs of the triangle is [tex]\rm 0.5(x)(x + 2) = 24[/tex].

To know more about the Area of the Triangle click the link given below.

https://brainly.com/question/15442893


Julio paid 1.3 times his normal hourly rate for each he works over 31 hours in a week. Last week he worked 35 hours and earned $448.88. What is julios normal hourly rate ?

Answers

Hi, Globabypatricia! :)

All the time worked past 31 hours gets paid 1.3 times.
He worked 4 hours at such a rate.

31+4(1.3)
31+5.2
=36.2
Paid as if he worked 36.2 at a normal rate. 

To find his normal wage, divide 448.88 by 36.2
448.88/36.2
=12.40

His normal wage is $12.40.

To check:
12.40*31=384.40
12.40*1.3=16.12
16.12*4=64.48

384.40+64.48
=$448.88

Hope this helps.
-Benjamin
Good question


Let his hourly rate is x

then:

31x + (35-31)*1.3x = 448.88

solve for x:

31 x + 5.2x = 448.88

36.2 x =448.88

x = 12.4$

not fair hourly rate by the way ;)

Three times the difference of a number x and seven is twenty-three minus the sum of three times a number x and two. what is the value of x?

Answers

3(x - 7) = 23 - (3x + 2) =
3x - 21 = 23 - 3x - 2 =
3x - 21 = -3x + 21
3x + 3x = 21 + 21
6x = 42
x = 42/6
x = 7 <==

The required value of x is 7.

What are linear equation?

A linear equation only has one or two variables. No variables in a linear equation is raised to power greater than 1 or used as denominator of a fraction.

Now the given statement is,

Three times the difference of a number x and seven is twenty-three minus the sum of three times a number x and two.

So converting them into numerical form,

the difference of a number x and seven = x - 7

Three times the difference of a number x and seven = 3(x - 7)

Similarly,

the sum of three times a number x and two = 3x + 2

∴ Twenty-three minus the sum of three times a number x = 23 - (3x + 2)

Therefore, the required equation is,

3(x - 7) = 23 - (3x + 2)

Expanding the brackets we get,

3x - 21 = 23 - 3x - 2

or, 3x - 21 = 21 - 3x

Taking alike terms together,

3x + 3x = 21 + 21

or, 6x = 42

Dividing both side by 6 we get,

x = 7

which is the required value of x.

Thus, The required value of x is 7.

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A new machine can make 10,000 aluminum cans three times faster than an older machine. with both machines working, 10,000 cans can be made in 9 hours. how long would it take the new machine, working alone, to make the 10,000 cans?

Answers

it takes at least 12 hours for the newer machine to make 10,000 cans

Since the new machine is three times faster, it takes (12 hours) / 3 = 4 hours for the new machine to make 10,000 cans alone.

Let's denote the time it takes the older machine to make 10,000 cans as "t" hours.

The new machine can make 10,000 cans three times faster than the older machine, which means it takes "t/3" hours for the new machine to make 10,000 cans.

When both machines are working together, they can make 10,000 cans in 9 hours.

Now, we can set up an equation based on the work rates of the two machines:

Work rate of the older machine + Work rate of the new machine = Combined work rate

The work rate is the amount of work (number of cans made) per unit of time (hours).

For the older machine:

Work rate of the older machine = 10,000 cans / t hours

For the new machine:

Work rate of the new machine = 10,000 cans / (t/3) hours

Combined work rate when both machines work together:

Combined work rate = 10,000 cans / 9 hours

Now, the equation becomes:

10,000 cans / t hours + 10,000 cans / (t/3) hours = 10,000 cans / 9 hours

To solve for "t," we can start by finding a common denominator for the fractions on the left side of the equation:

t/3 is the same as (1/3)t. So the equation becomes:

10,000 cans / t hours + 10,000 cans / (1/3)t hours = 10,000 cans / 9 hours

Now, to combine the fractions, we find the common denominator, which is 3t:

(3t * 10,000 cans) / (3t * t hours) + (t * 10,000 cans) / (3t * t hours) = 10,000 cans / 9 hours

(30,000t + 10,000t) / (3t^2 hours) = 10,000 cans / 9 hours

Combine the terms on the left side of the equation:

40,000t / (3t^2 hours) = 10,000 cans / 9 hours

Now, cross-multiply to solve for "t":

40,000t * 9 hours = 10,000 cans * 3t^2 hours

360,000t hours = 30,000t^2 hours

Now, rearrange the equation:

30,000t^2 - 360,000t hours = 0

Divide by 30,000t to simplify the equation:

t - 12 = 0

Now, solve for "t":

t = 12 hours

Therefore, it takes the older machine 12 hours to make 10,000 cans.

To know more about machine:

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5v + 7f =28.70 if f is 2.85

Answers

5v+7(2.85)=28.70

5v+19.95 = 28.70

5v = 8.75

v = 1.75

Hey!

First, let's write the problem.
[tex]5v+7\left(2.85\right)=28.7[/tex]
Multiply [tex]7[/tex] with [tex]2.85[/tex].
[tex]5v+19.95=28.7[/tex]
Subtract [tex]19.95[/tex] from both sides.
[tex]5v+19.95-19.95=28.7-19.95[/tex]
[tex]5v=8.75[/tex]
Divide both sides by [tex]5[/tex].
[tex]\frac{5v}{5}=\frac{8.75}{5}[/tex]
[tex]v=1.75[/tex]

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish

The city of Lakeside has a population of 22,000 people and is decreasing at a rate of 1.5% The population in 3 years would be

A)Approximately 21,000 people
B)None of the choices are correct
C)Approximately 20,000 people
D)Approximately 25,000 people
E)Approximately 19,000 people

Answers

The formula is
P=Ae^rt
P ?
A 22000
R -0.015
T 3years

P=22,000×e^(−0.015×3)
p=21,032

So the answer is
A) Approximately 21,000 people

Which rate is the lowest price?
$6.30 for 9
$5.50 for 5
$4.20 for 7
$0.80 each

Answers

Answer: $4.20 for 7
This problem can be solved by dividing the pay by the number of items.

$6.30 / 9 = $0.70
$5.50 / 5 = $1.10
$4.20 / 7 = $0.60
$0.80 / 1 = $0.80

This shows that for the third option, $4.20 for 7, the rate per item is the lowest.

Why might algebra tiles not be a good tool to use to factor x2 + 18x + 80? Explain.

Answers

Algebra tiles would not be a good tool to use to factor the trinomial because you would need to drag an x-squared tile, 18 x-tiles, and 80 plus tiles. That is a total of 99 tiles. It would take a lot of time to drag that many tiles on the board and there might not be enough space to hold all of them. You would also need to determine how to arrange all those tiles to make a rectangle. Since 80 is a multiple of 10, you might recognize that 10 and 8 are the factors that add to 18, which would give you the values to use in the X method.

Algebra tiles are used to factorize a polynomial. The factorization of the given trinomial will be very difficult to perform using the algebra tiles due to the large number of tiles used.

The given quadratic polynomial or trinomial is [tex]x^2 + 18x + 80[/tex].

The algebra tiles required to solve the given trinomial are,

1 x-squared tile.18 x-tiles.80 unit tiles.

So, the total number of times required will be 1+18+80 or 99 tiles.

Now, it will be very difficult to drag or arrange so many tiles on the board. Also, the space could be a problem in this case.

Therefore, the factorization of the given trinomial will be very difficult to perform using the algebra tiles due to a large number of tiles used.

For more details, refer to the link:

https://brainly.com/question/16865029

Apply the distributive property to factor out the greatest common factor. 45+75=

Answers

15 * 3 = 45
15 * 5 = 75
15( 3 + 5)

(02.05 MC)

Triangle ABC is transformed to obtain triangle A′B′C′:

Which statement is correct for Triangle ABC. and Triangle A prime B prime C prime.?

Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 6. and then rotating it about the origin by 90 degrees

Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 3. and then rotating it about the origin by 180 degrees

Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 3. and then rotating it about the origin by 90 degrees

Triangle ABC is similar to triangle A prime B prime C prime. because triangle A prime B prime C prime. is obtained by dilating Triangle ABC.by a scale factor of 1 over 4. and then rotating it about the origin by 180 degrees

Answers

Triangle ABC is similar to triangle A prime B prime C prime. because triangle A prime B prime C prime. is obtained by dilating Triangle ABC.by a scale factor of 1 over 4. and then rotating it about the origin by 180 degrees
The answer is the last choice. It says the triangle is dilated by a scale factor of [tex]\frac{1}{4}[/tex]. To check this we can just look at the side lengths if the triangles. [tex]AB[/tex] has a length of 8 by looking at the graph, and [tex]A'B'[/tex] has a length of 2 from the graph too. So when we put those lengths[tex]\frac{2}{8}[/tex] into a fraction, it simplifies to [tex]\frac{1}{4}[/tex]. The only answer that says this is the last answer choice.

The function f(x) = –x2 + 16x – 60 models the daily profit, in dollars, a shop makes for selling candles, where x is the number of candles sold, and f(x) is the amount of profit.

Part A: Determine the vertex. What does this calculation mean in the context of the problem? (5 points)

Part B: Determine the x-intercepts. What do these values mean in the context of the problem? (5 points

please help

Answers

A.

f is a quadratic function, which means it's graph is a parabola.

Notice that the coefficient of [tex] x^{2} [/tex] is negative, so the parabola opens downwards.

the x-coordinate of a parabola is always determined by the formula: [tex] -\frac{b}{2a} [/tex]

where a is coefficient of the [tex] x^{2} [/tex] term, and b is the coefficient of the x term.

Thus, x-coordinate of the vertex of the graph of f is :

[tex]-\frac{b}{2a}=-\frac{16}{2(-1)}=8[/tex]

the y-coordinate of the vertex is f(8)=-8*8+16*8-60=4.

The vertex is (8, 4).

This means that the maximum daily profit is when exactly 8 candles are sold.

B.

The x-intercepts are the values of x such that f(x)=0,

so to find these values we solve:

[tex]- x^{2} +16x-60=0[/tex]


[tex]x^{2}-16x+60=0[/tex]

complete the square:

[tex]x^{2}-2*8x+64-64+60=0[/tex]

[tex](x-8)^{2}-4=0[/tex]

[tex](x-8)^{2}= 2^{2} [/tex]

so x-8=2      or x-8=-2

the roots are x=10 and  x=6, are the roots.

This means that when the shop sells exactly 6 or 10 candles, it makes no profit.



Final answer:

The vertex of the profit function f(x) = -x^2 + 16x - 60 is (8, 4), meaning the maximum profit is $4 when 8 candles are sold. The x-intercepts are (6,0) and (10,0), indicating zero profit when either 6 or 10 candles are sold.

Explanation:

The function given is a quadratic equation of the form f(x) = ax2 + bx + c, where the constants are a = -1, b = 16, and c = -60. To find the vertex of the parabola, we can use the formula -b/(2a) for the x-coordinate of the vertex.

Calculate the x-coordinate of the vertex: x = -b/(2a) = -16/(2 * -1) = 8.

Substitute x = 8 into the original function to find the y-coordinate: f(8) = -(8)2 + 16(8) - 60 = -64 + 128 - 60 = 4.

The vertex is at the point (8, 4). In the context of the problem, this point represents the maximum daily profit of $4, which occurs when 8 candles are sold.

To determine the x-intercepts, we set f(x) to zero and solve for x, which represents the number of candles sold when the profit is zero.

Set the function equal to zero and solve for x: 0 = -x2 + 16x - 60.

Apply the quadratic formula x = [-b ± sqrt(b2 - 4ac)]/(2a) to find the x-intercepts. In this case, a = -1, b = 16, and c = -60.

Calculate the discriminant, sqrt(162 - 4(-1)(-60)) = sqrt(256 - 240) = sqrt(16) = 4.

Find the two x-intercepts: x = [16 ± 4]/(2 * -1) which yields x = 6 and x = 10.

The x-intercepts (6,0) and (10,0) indicate the number of candles sold at which the profit would be zero, specifically at 6 and at 10 candles sold.

Martin is asked to find the probability of getting one head and three tails on for coin tosses this is a simple event

Answers

The possible outcomes for 1 HEAD and 3 TAILS are

HTTT
THTT
TTHT
TTTH

Assuming the coin is a fair coin, we have:
Probability of tossing head is 0.5
Probability of tossing tail is 0.5

Probability of tossing the coin four times for each outcome combination listed above is

HTTT = 0.5×0.5×0.5×0.5 = 0.0625
THTT = 0.5×0.5×0.5×0.5 = 0.0625
TTHT = 0.5×0.5×0.5×0.5 = 0.0625
TTTH = 0.5×0.5×0.5×0.5 = 0.0625

Hence, probability of getting three tails and one head from 4 tossing is 
4×0.0625 = 0.25

Answer: False

Martin is asked to find the probability of getting one head and three tails on for coin tosses this is a simple event.

A. True

B. False

Solve the equation: 2.6 = -0.2t

Answers

2.6 = -0.2t...divide both sides by -0.2
2.6 / -0.2 = t
-13 = t <==
2.6=-0.2t
T=2.6/-0.2=-13

T= -13

Hope this helps!

I don't understand this and would appreciate an explanation as well :)
Solve for the variable in the equations below.
Round your answers to the nearest hundredth.
Do not round any intermediate computations.

e^x = 6

4^(y+3) = 3

[tex]e^x = 6[/tex]
[tex]4^y^+^3 = 3 [/tex]

Answers

We want to solve the two equations
[tex]e^{x}=6[/tex]
and
[tex]4^{y+3}=3[/tex]

First equation.
Take natural log of each side.
[tex]ln(e^{x})=ln(6)\\xln(e)=ln(6)\\ x=ln(6)=1.7918[/tex]
Note that ln(e) = 1 by definition.
Answer: x = 1.79 (nearest hundredth)

Second equation.
Take natural log of each side.
[tex]ln(4^{y+3})=ln(3)\\ (y+3)ln(4)=ln(3)\\ y+3= \frac{ln(3)}{ln(4)} =0.7925\\y=0.7925-3=-2.2075[/tex]
Answer: y = -2.21 (nearest hundredth)

(02.03 MC)

The figure shows two triangles on a coordinate grid:


What set of transformations is performed on triangle ABC to form triangle A'B'C'?
A.. A 180-degree counterclockwise rotation about the origin, followed by a translation 5 units down
B. A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin
C. A 270-degree counterclockwise rotation about the origin, followed by a translation 5 units to the right
D. A translation 5 units to the right, followed by a 270-degree counterclockwise rotation about the origin

Answers

pretty sure it is b

i know for sure it isnt C or D

A store's cost for a stereo was $27. The markup was 75%. A customer purchased it on sale at 40% off the markup price. What was the purchase price of the stereo

Answers

so the stereo costs $27, so to include a price for profit and other expenses, it gets ballooned to 75% extra, or the new price is 175%, how much is that?

if we take 27 to be the 100%, what's 175% of that?

[tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 27&100\\ x&175 \end{array}\implies \cfrac{27}{x}=\cfrac{100}{175}\implies \cfrac{27\cdot 175}{100}=x\implies \boxed{47.25=x}[/tex]

alrite, then a customer showed up and found it on sale, 40% off that price, so if you take out 40% from the 100%, the price the customer found it at is the 60%, 100-40,  of the current price of 47.25

so, if 47.25 is the 100%, what's 60% of that?

[tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 47.25&100\\ x&60 \end{array}\implies \cfrac{47.25}{x}=\cfrac{100}{60}[/tex]

solve for "x".

I need to find the answer to these questions in about 10 minutes or I'm screwed. please help me out.

Answers

For the first figure, the geometric figure used in the construction that is shown is the intersection of the angle bisectors of the triangle is the center of the inscribed circle.

For the second figure, the construction of the above figure in the circle represents how to find the intersection of the perpendicular bisectors of triangle ABC.

For the third figure, the statement that is demonstrated in the in line P intersecting line m perpendicularly is the set of points equidistant from the endpoints of  a line segment  is the perpendicular bisector of the segment.

True or False...

P^2+2pq+q^2= 1

Answers

f stands for false my friend  

Answer:

defiantly a false!!

Step-by-step explanation:

In how many ways can 2 singers be selected from 4 who came to an audition?

A. 6
B. 2
C. 12
D. 4

In a batch of 280 water purifiers, 12 were found to be defective. What is the probability that a water purifier chosen at random will be defective? Write the probability as a percent. Round to the nearest tenth of a percent if necessary.

A. 4.3%
B. 5.6%
C. 95.7%
D. 71.8%

Answers

First part  its 4C2  = 4*3 / 2 = 6

Second part
12 * 100
----------    =   4.3 %
   280

Answer: A. 6

A. 4.3%

Step-by-step explanation:

The total number of singers = 4

To choose singers = 2

The number of ways to choose 2 singers from 4= [tex]^4C_2=\frac{4!}{2!(4-2)!}=3\times2=6[/tex]

Hence, A is the right option.

The total number of water purifiers  T= 280

The number of defective purifiers D= 12

The probability that a water purifier chosen at random will be defective (in percent)=[tex]\frac{\text{T}}{\text{D}}\times100[/tex]

[tex]=\frac{12}{280}\times100\\=0.042857\times100\\=4.2857\%\approx4.3\%[/tex]

Hence, A is the right option.

PLEASE HELP ASAP!!! A talent competition on television had five elimination rounds. After each elimination, only one-third of the contestants were sent to the next round. The table below shows the number of contestants in each round of the competition: x 1 2 3 4 5 f(x) 243 81 27 9 3 Compute the average rate of change of f(x) from x = 1 to x = 4 and describe what it represents.

A) −78 contestants per round, and it represents the number of contestants who will reach the final round

B)−234 contestants per round, and it represents the number of contestants who will reach the final round

C)−234 contestants per round, and it represents the average rate at which the number of contestants changed from the first round to the fourth round

D) −78 contestants per round, and it represents the average rate at which the number of contestants changed from the first round to the fourth round

Answers


(9-243)/(4-1)=-78
D)−78 contestants per round, and it represents the average rate at which the number of contestants changed from the first round to the fourth roundReport · 14/12/2015

Answer:

D

Step-by-step explanation:

Given the following data  

x  1   2  3  4  5  

f(x)  243  81  27  9  3

The rate of change between the second and the first points is computed as  

(f(x2) - f(x1))/(x2 -x1) =  (81 - 243)/(2-1) = -162

Analogously, between 3rd and 2nd points and between  4th and 3rd points:

27 - 81 = -54

9 - 27 = -18

Therefore, the average rate of change is (-162 -54 -18)/3 = -78 contestants per round, and it represents the average rate at which the number of contestants changed from the first round to the fourth round .

Suppose i pick a jelly bean at random from a box containing two red and ten blue ones. i record the color and put the jelly bean back in the box. if i do this three times, what is the probability of getting a blue jelly bean each time? (round your answer to three decimal places.)

Answers

The probability of picking a blue jelly bean is 10/12=0.833, since there are 10 blue and 12 jelly beans in total.

Each time the probability of picking blue is the same, since put back in the box whatever jelly bean we pick

P(blue, blue, blue) = P(blue) × P(blue) × P(blue) = 0.833×0.833×0.833=0.579


Answer: 0.579

Which represents a quadratic function? f(x) = −8x3 − 16x2 − 4x f (x) = x 2 + 2x − 5 f(x) = + 1 f(x) = 0x2 − 9x + 7

Answers

The answer is f(x)=x^2+2x-5
A quadratic formula must have at least one square (x^2) and cannot have higher exponents.
The reason 0x^2 doesn't count is because that will always equal zero no matter the value of x, which makes that term a constant.

Answer: The correct answer is [tex]f(x)=x^2+2x-5[/tex]

Step-by-step explanation:

A Quadratic equation is defined as the equation in which the highest power of the variable is 2. The general form of this equation represents:

[tex]ax^2+bx+c=0[/tex]

where, [tex]a\neq 0[/tex]

From the given options:

1. [tex]f(x)=-8x^3-16x^2-4x[/tex]: Here, the highest power of the variable is 3. Therefore, it is not a quadratic equation.

2. [tex]f(x)=x^2+2x-5[/tex]: Here, the highest power of the variable is 2. Therefore, it is a quadratic equation.

3. [tex]f(x)=+1[/tex]: Here, the highest power of the variable is 0. Therefore, it is not a quadratic equation.

4. [tex]f(x)=0x^2-9x+7[/tex]: Here, the highest power of the variable is 1. Therefore, it is not a quadratic equation.

Hence, the correct answer is [tex]f(x)=x^2+2x-5[/tex]

What is 5 plus 5 minus 5 divided by 5 and then multiplied by 5?

Answers

With the order of operations first, you multiply and divide from left to right:

So you have 5+5-5/5(5)

We will divide first:
5+5-1(5)

Then multiply:
5+5-5

Then add and subtract from left to right:
10-5=5

Hope that helps.

Answer:

45

Step-by-step explanation:

[tex](5+5-5:5)\cdot5\\\\\text{Use PEMDAS}\\\\\text{P Parentheses first}\\\text{E Exponents}\\\text{MD Multiplication and Division (left-to-right)}\\\text{AS Addition and Subtraction (left-to-right)}\\\\=(5+5-1)\cdot5\\\\=(10-1)\cdot5\\\\=9\cdot5\\\\=45[/tex]

16% of what number is 17 ?

Answers

16% x 17 =

(16 / 100) x 17 =

(16 x 17) / 100 =

272 / 100 =

The answer : 2.72
x = 106.25

Step-by-step explanation:

To find out what 16% of 17 is, we create a cross multiply equation

16/100=17/x

Cross multiply

(16 * x  = 16x)

(100 * 17 = 1700)

16x = 1700

1700/16 = 106.25

A school director must randomly select 6 teachers to participate in a training session. There are 34 teachers at the school. In how many different ways can these teachers be selected, if the order of selection does not matter?

Answers

The selection of r object out of n, is carried out in C(n, r) many ways, 

where [tex]C(n, r)= \frac{n!}{r!(n-r!)} [/tex]

n! meaning 1*2*3*....*(n-1)*n


According to this, the selection of 6 teachers out of 34, can be carried out in C(34, 6) many different ways.

[tex]C(34, 6)= \frac{34!}{6!(34-6!)}=\frac{34!}{6!(28!)}= \frac{34*33*32*31*30*29*28!}{6!28!}= \frac{34*33*32*31*30*29}{6!}[/tex]

[tex]=\frac{34*33*32*31*30*29}{6*5*4*3*2*1}= 34*11*4*31*29=1,344,904[/tex]
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