How do I multiply 8.354 by 11.81?
a car travels 150 miles at a certain speed if the speed had been 5 miles faster the trip would have been in one hour less time find the speed
what 87,628 divided by 931
all quadrilaterals are polygons
Your football team gained 4 yards on first down and 2 yards on second down during its last possession. Which number is the additive inverse of the yards gained?
A) −2
B) −6
C) 4
D) 6
Answer:
-6
Step-by-step explanation:
Because if you add up all of the events you'll get 6 . Then, after that it asks for the additive inverse so you put an negative sign behind the #6.a number is less than 200 and greater than 100 the ones digit is 5 less than 10.the tens digit is 2 more than the ones digit.what is the number
The correct number is between 100 and 200 would be 175.
Used the concept of number system which states that,
A writing system used to express numbers is known as a number system. It is the mathematical notation used to consistently express the numbers in a particular set using digits or other symbols.
Given that,
A number is less than 200 and greater than 100.
Here, the one's digit is 5 less than 10, and the tens digit is 2 more than the one digit.
Since the one's digit is 5 less than 10.
So, the number in one's place is,
10 - 5 = 5
And, the tens digit is 2 more than the one digit.
5 + 2 = 7
Since the number is between 100 and 200.
So, the possible value of a number with the value in one's place 5 and the value in tens place 7 would be,
175
Clearly, the number 175 is between 100 and 200.
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Jacob used 1/7 of a liter of water to fill 1/9 of the fish aquarium. How many liters r needed to fill the aquarium?
Since 1/7 L of water fills 1/9 of the aquarium, 9 times 1/7 will fill the aquarium:
9(1/7) = 9/7 = 1 2/7 L of water will fill the aquarium.
The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds. the probability of a player weighing more than 241.25 pounds is
To find the probability of a football player weighing more than 241.25 pounds, calculate the z-score and use the standard normal distribution table.
Explanation:To find the probability of a football player weighing more than 241.25 pounds, we need to calculate the z-score and then use the standard normal distribution table.
The formula for calculating the z-score is: z = (x - μ) / σ where x is the player's weight, μ is the mean weight, and σ is the standard deviation.
Plugging in the values, we get: z = (241.25 - 200) / 25 = 1.65
Using the standard normal distribution table, we can find that the probability of a value being greater than 1.65 is approximately 0.0495.
Which equation is equivalent to 1 5/6 - 2/6 = 1 3/6
Find the least common multiple (LCM) of 54 and 72. A) 9 B) 27 C) 108 D) 216
You have a photo that measures 1 in. wide by 3 in. tall. If you want to enlarge the photo so that the height is 18 in., what will the width of the photo be?
A. 98 in.
B. 4 in.
C. 6 in.
D. 108 in.
is 1 1/3 a unit rate
Jade spent 37.60 on groceries. 4/5 of that total was spent on vegetables. How much was spent on other items
We are conducting a test of the hypotheses h0: p = 0.2 ha: p ≠ 0.2 we find a test statistic of z = -1.11. what is the corresponding p-value? give your answer as a proportion between 0 and 1 to 4 decimal places.
The table below shows the typical hours worked by employees at a company. A salaried employee makes $67,000 per year. Hourly employees get paid $25 per hour, but get $37.50 per hour for each hour over 40 hours. Sun. Mon. Tues. Wed. Thurs. Fri. Sat. 0 10 8 8 7 6.5 4.5 Which of the payment options would you recommend to a new employee? a. Either one. Hourly and salaried employees earn the same amount per week. b. Hourly pay. Hourly employees make more per week than salaried employees. c. Salaried pay. Salaried employees make more per week than hourly employees. d. There is not enough information given to compare weekly earnings.
Answer:
C should be the correct option
Step-by-step explanation:
Tell me if im wrong :)
the sum of partial products is equal to the final product?
To graph the inequality t > 5, you would put an open circle on 5 and shade to the right. true or false
Computer upgrades have a nominal time of 80 minutes. samples of five observations each have been taken, and the results are as listed. sample 1 2 3 4 5 6 79.2 80.5 79.6 78.9 80.5 79.7 78.8 78.7 79.6 79.4 79.6 80.6 80.0 81.0 80.4 79.7 80.4 80.5 78.4 80.4 80.3 79.4 80.8 80.0 81.0 80.1 80.8 80.6 78.8 81.1 factors for three-sigma control limits for formula179.mml and r charts factors for r charts number of observations in subgroup, n factor for formula180.mml chart, a2 lower control limit, d3 upper control limit, d4 2 1.88 0 3.27 3 1.02 0 2.57 4 0.73 0 2.28 5 0.58 0 2.11 6 0.48 0 2.00 7 0.42 0.08 1.92 8 0.37 0.14 1.86 9 0.34 0.18 1.82 10 0.31 0.22 1.78 11 0.29 0.26 1.74 12 0.27 0.28 1.72 13 0.25 0.31 1.69 14 0.24 0.33 1.67 15 0.22 0.35 1.65 16 0.21 0.36 1.64 17 0.20 0.38 1.62 18 0.19 0.39 1.61 19 0.19 0.40 1.60 20 0.18 0.41 1.59
a. using factors from above table, determine upper and lower control limits for mean and range charts. (round your intermediate calculations and final answers to 2 decimal places. leave no cells blank - be certain to enter "0" wherever required.) mean chart range chart ucl 81.06 4.01 lcl 78.86 0.00 g
The UCL and LCL for the mean and range charts are calculated based on the average and range of the data sets. The table provided in the question provides respective factors for various subgroup sizes. For n=5, the factors are A2=0.58, D3=0 and D4=2.11. Using these we compute UCL and LCL for both charts. Round off to two decimal places and fill '0' in any empty cells.
Explanation:To find the Upper Control Limit (UCL) and Lower Control Limit (LCL) for the mean and range charts, we have to use the r and formula179.mml charts that are provided in your question. We will take the observations in groups of five as mentioned in the question.
Firstly, calculate the average (X-bar) for each of these groups and find the overall average (M) of these five averages.Please find the range (R) for each subgroup and then the average of these ranges (meanR).Referring to the table given in your question, for n=5, the factors are A2=0.58, D3=0 and D4=2.11.The UCL and LCL for the mean chart can be calculated using UCL=M+A2*meanR and LCL=M-A2*meanR, whereas, for the range chart, they are UCL=D4*meanR and LCL=D3*meanRUsing these steps, you can find the upper and lower control limits for both the mean and range charts. Always remember to round off your answers to two decimal places and also, to avoid leaving any cells blank in the excel sheet. If required, fill in '0' in those empty cells. This way, meaningful interpretation of the control charts can be made.
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The upper and lower control limits for the mean chart are 81.06 and 78.86, respectively, while the upper control limit for the range chart is 8.45 and the lower control limit is 0.
To determine the upper and lower control limits for the mean and range charts, we can use the factors provided in the table.
For the mean chart:
- The upper control limit (UCL) is calculated by adding the product of the factor for the mean chart (A2) and the average range (R-bar) to the overall average (X-double-bar). In this case, the A2 factor is 0.73 and the R-bar is 4.01, so the UCL for the mean chart is: 81.06 (rounded to 2 decimal places).
- The lower control limit (LCL) is calculated by subtracting the product of the factor for the mean chart (A2) and the average range (R-bar) from the overall average (X-double-bar). Using the same values, the LCL for the mean chart is: 78.86 (rounded to 2 decimal places).
For the range chart:
- The UCL for the range chart is calculated by multiplying the factor for the range chart (D4) by the average range (R-bar). In this case, the D4 factor is 2.11 and the R-bar is 4.01, so the UCL for the range chart is: 8.45 (rounded to 2 decimal places).
- The LCL for the range chart is always 0 since range values cannot be negative.
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solve the equation for x.
ax+bx=c
Answer: x = c/a + b
Step-by-step explanation: I have put the variable x in purple in the image that I have made so you can see it better.
Notice that the variable we are solving for in
this problem appears in 2 separate terms.
In this situation, we must factor the x out
of both terms to get x(a + b) = c.
Think about it as the reverse of the distributive property.
In other words, if we take our second step and distribute the x
through the parentheses, we end up back at our first step.
The beauty of factoring is that the two x's in this problem
have now been combined into one x and we can get x
by itself by dividing both sides by a + b.
This gives us x = c/a + b.
Suppose 4 mg of a drug is injected into a person's bloodstream. As the drug is metabolized, the quantity diminishes at the continuous rate of 3% per hour?
a box of cereal contains 23.4 ounces. It cost $5.49. What is the cost,to the nearest cent, of the cereal per ounce.
Write this in Interval Notation:
4x - 6 ≥ 6x - 20
12.917 rounded to the nearest ones
Your mid-morning break begins at 10:30 A.M. and lasts for 15 minutes. You work 2 hours and 50 minutes until your lunch break. What time does your lunch break begin?
Final answer:
The lunch break begins at 1:20 P.M. after working for 2 hours and 50 minutes from the mid-morning break at 10:30 A.M.
Explanation:
The mid-morning break begins at 10:30 A.M. and lasts for 15 minutes.
You work 2 hours and 50 minutes from 10:30 A.M.
To find the start time of your lunch break, add 2 hours and 50 minutes to 10:30 A.M.
Lunch break begins at 1:20 P.M.
Solve for Z. Z−4/9−1/3=5/9 Enter your answer in the box. Z=
NEED HELP FAST WILL GIVE BRAINLIEST 15 POINTS
Answer:
The answer correct answer is, 4/3
Step-by-step explanation:
I am reveiwing this quiz right now!
Discuss the differences between parametric and non-parametric tests?
Vail Ski Shop received a $1,201 invoice dated July 8 with 2/10, 1/15, n/60 terms. On July 22, Vail sent a $485 partial payment. (If more than one discount, assume date of last discount)
a. What credit should Vail receive?
b. What is Vail’s outstanding balance?
Vail Ski Shop won't receive any credit because the payment did exceed the discount period. Vail's outstanding balance is $716, calculated by subtracting the partial payment from the original invoice.
Explanation:The $1,201 invoice dated July 8 with 2/10, 1/15, n/60 terms means that Vail Ski Shop receives a discount if paid within certain time periods, specifically a 2% discount if paid within 10 days, a 1% discount if paid within 15 days, and full payment is required within 60 days. However, since Vail made a partial payment of $485 on July 22, the days had already exceeded both the 10 and 15-day discount periods. This implies that Vail should not receive any credit.
To calculate Vail's outstanding balance, we would subtract the amount Vail has paid partially from the original invoice. So, the calculation would be $1,201 - $485 which equals $716. Therefore, Vail's outstanding balance would be $716.
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Amanda, Bryce, and Corey enter a race in which they have to run, swim, and cycle over a marked course. Their average speeds are given in the table. Corey finishes first with a total time of 2 hr 32 min. Amanda comes in second with a time of 3 hr 33 min. Bryce finishes last with a time of 4 hr 14 min. Find the distance (in mi) for each part of the race.
Jim Abbott purchased a $58,000 recreational vehicle (RV) with a 45 percent markup on selling price. a. What was the amount of the dealer’s markup? Markup amount $ b. What was the dealer’s original cost? Original cost $
The dealer's markup amount is $26,100 and the original cost of the RV is $31,900.
Explanation:To determine the dealer's markup, we need to find 45% of the selling price of the RV. We can set up the following equation:
Markup amount = Selling price × Markup percentage
Let's plug in the given values: $58,000 × 45% = $26,100
The dealer's original cost can be found by subtracting the markup amount from the selling price:
Original cost = Selling price - Markup amount
Let's calculate it: $58,000 - $26,100 = $31,900
You have 3/8 of a cake. You divide the remaining cake into six equal pieces. What fraction of the original cake is each piece?