Answers
7x4 = 28
5 x z = 28
z = 28/5 = 5.6
Related Questions
How can you eliminate the fraction from each side of the equation to make finding the
solution easier?
The equation is 1/2(x - 4) = 1/3x + 2
Answers
1/2(x - 4) = 1/3x + 2
multiply by : 6
3(x-4) = 2x +4
solution easier:
3x -12 = 2x +4
3x - 2x = 12+4
x = 16
Find the surface area of the cone to the nearest tenth.
A. 203 cm2
B. 1341.5 cm2
C. 747.7 cm2
D. 213.5 cm2
Answers
soooo like this is what you gone do....
(pi) * 7^2+ (pi) *7 *27
=747.6990.....
hope this helps
THE STRUGGLE IS REAL
The surface area of the given cone is 747.32.
What is area of a cone?"The total surface area of a cone is defined as the total area of the cone occupied in a three-dimensional area. It is equal to the sum of the curved surface and the base of the cone. "
Surface area of the cone is [tex]\pi*r(l+r )[/tex]
[tex](22/7)*7*(27+7)[/tex]
= 747.32
The surface area of the cone is 747.32
Hence, option C is correct.
To know more about surface area here
https://brainly.com/question/10026601
#SPJ2
800x200 I know the answer is 160000 but I want to see how quick you guys answer...
Answers
8×2 = 16
and : four zero : 0000
you have : 160000
write an equation for a line perpendicular to the x-axis that passes through the point (5,1)
Answers
x=k, since it must pass through (5,1) that vertical line is:
x=5
The equation of a line perpendicular to the x-axis passing through the point (5,1) is x = 5. This is because a vertical line crossing the x-axis at a specific point will have the same x-coordinate for all its points.
Explanation:In mathematics, a line perpendicular to the x-axis is a vertical line that crosses the x-axis at a specific point. All points on this line will share the same x-coordinate. Therefore, a line that is perpendicular to the x-axis, and passes through the point (5,1) will have the equation x = 5. This equation represents a line that is vertical and intercepts the x-axis at the point where x equals 5. This is because in each point on the line, x remains constant, which is the characteristic of a vertical line in a Cartesian Coordinate System.
Learn more about Equation of a Line here:https://brainly.com/question/33578579
SOMEONE PLEASE HELP ME WITH MATH! WILL GIVE BRAINLIEST TO FIRST PERSON WHO ANSWERS!!
Solve each system by substitution.
1. -5x-8y=9
y= -3.
2. y= -3x
-6x-2y=3
3. 6x+5y=10
y=-8x+2
4.6x+2y= -6
y= -3x -3
Thank you!
Answers
-5x+24=9
-5x=-15
x=3
(3,-3)
2. -6x-2(-3x)=3
-6x+6x=3
0=3
No solution
3. 6x+5(-8x+2)=10
6x-40x+10=10
-34x+10=10
-34x=0
x=0
y=-8(0)+2
y=2
(0,2)
4. 6x+2(-3x-3)=-6
6x-6x-6=-6
-6=-6
Infinitely many solutions
Use the functions h(x) = 2x + 5 and t(x) = 7x − 6 to complete the function operations listed below.
Part A: Find (h + t)(x). Show your work. (3 points)
Part B: Find (h ⋅ t)(x). Show your work. (3 points)
Part C: Find h[t(x)]. Show your work. (4 points)
Answers
h ( x ) = 2 x + 5 and t ( x ) = 7 x - 6
Part A:
( h + t ) ( x ) = ( 2 x + 5 ) + ( 7 x - 6 ) = 9 x - 1
Part B :
( h · t ) ( x ) = ( 2 x + 5 ) · ( 7 x - 6 ) = 14 x² - 12 x + 35 x - 30 =
= 14 x² + 23 x - 30
Part C :
h [ t ( x ) ] = h ( 7 x - 6 ) = 2 · ( 7 x - 6 ) + 5 = 14 x - 12 + 5 =
= 14 x - 7
Suppose there are 10,000 civilizations in the milky way galaxy. if the civilizations were randomly distributed throughout the disk of the galaxy, about how far (on average) would it be to the nearest civilization? (hint: start by finding the area of the milky way's disk, assuming that it is circular and 100,000 light-years in diameter. then find the average area per civilization, and use the distance across this area to estimate the distance between civilizations.)
Answers
so the radius is 50, 000 lights year, thus
Area of the galaxy is [tex]A(galaxy)= \pi r^{2}= \pi (50,000)^{2}=25*10^{8} \pi [/tex] (lights year square)
The area per civilisation is [tex] \frac{25*10^{8} \pi }{10,000}=25*10^{4} \pi[/tex]
from this result we can assume as a circle of Radius=[tex]25*10^{2}=2500[/tex] lights year.
and assume that each civilisation lives in a planet at the center of these smaller circles.
Check the figure attached.
Planet A, and B are closest in distance. They are each at the center of a circle with radius 2500, and they are tangent. So the distance of A to B is 2500+2500=5000 (light years).
Answer: 5000 light years
a farmer needs to enclose a section of land in the shape of a parallelogram by using one side of a barn for one side the barn in the side opposite of the barn will be 10 ft long one of the other sides will be 6 feet long what is the length of the last side?
A) 6 feet
B) 16 feet
C) 4 feet
D) 10 feet
Answers
Thus, for this problem:
The first two opposite sides will be 10 ft long and they are also parallel
The third side is 6 ft long
This means that the fourth side will definitely be equal to the third one and parallel to it.
The answer is : A) 6 ft
Answer: C:6
Step-by-step explanation:
I just got it right on the quiz
whats the normal arm span for these heights? : 4'10,4'11,5'0,5'4,5'5,5,'7,5'8,5'9,5'10,5'11,6'0
Answers
In adults, the arm span is approximately 5 cm greater than the height in adult males and 1.2 cm in adult females. To calculate the arm span for the heights given, we add 5cm to their height. The following are the results:
Height Arm Span Length (in cm)
4’10 152.32
4’11 154.86
5’0 157.4
5’4 167.56
5’5 170.10
5’7 175.18
5’8 177.72
5’9 180.26
5’10 182.80
5’11 185.34
6’0 187.88
To add, the total measurement of the length from the furthermost part of an individual's arms to the other end when raised equidistant to the ground at shoulder height at a 90º angle is called the arm span or wingspan.
Which system is the only inconsistent system?
Select one:
a.
y
y
=
=
x+4
2x+4
y=x+4y=2x+4
b.
y
y
=
=
x
−x
y=xy=−x
c.
y
y
=4
=
x−3
4x+3
y=4x−3y=4x+3
d.
y
2y
=2
=
x−3
4x−6
y=2x−32y=4x−6
Answers
Option (c) represents an inconsistent system of equations, as the constant terms are not proportional, while the coefficients of x are. This system (y=4x-3, y=4x+3) has no solutions.
Explanation:In mathematics, specifically in algebra, an inconsistent system is a system of equations that has no solutions. To check which system is inconsistent from the options you've given, we need to compare the coefficients of each equation within a system. An inconsistent system will have proportional coefficients of x and y between the two equations, but the constant terms will not be proportional.
Looking at each option:
Option (a): y=x+4 and y=2x+4
Option (b): y=x and y=−x
Option (c): y=4x−3 and y=4x+3
Option (d): y=2x−3 and 2y=4x−6
From here, we can see that option (c): y=4x-3, y=4x+3 is inconsistent. In this system, the coefficients of x are proportional (4), but the constant terms (-3 and +3) are not proportional.
Learn more about Inconsistent Systems here:https://brainly.com/question/35587704
#SPJ12
Factor this expression. With work please!
Answers
[tex]\bf x^6-9x^4-81x^2+729\qquad \begin{cases} x^6=x^{2\cdot 3}\\ \qquad (x^2)^3\\ 729=9\cdot 9\cdot 9\\ \qquad 9^3\\ 81=9\cdot 9\\ \qquad 9^2 \end{cases}\\\\ -------------------------------\\\\[/tex]
[tex]\bf (x^6+729)-(9x^4+81x^2)\implies [(x^2)^3+9^3]-(9x^2x^2+9^2x^2) \\\\\\\ [\underline{(x^2+9)}(x^4-9x^2+9^2)]\ -\ [9x^2\underline{(x^2+9)}]\impliedby \begin{array}{llll} notice\ the\\ \textit{\underline{common factor}} \end{array} \\\\\\ (x^2+9)\ [(x^4\underline{-9x^2}+9^2)\underline{-9x^2}]\impliedby \textit{now we add \underline{these two}} \\\\\\[/tex]
[tex]\bf (x^2+9)\ [x^4-18x^2+9^2]\impliedby \begin{cases} \sqrt{x^4}=x^2\\ \sqrt{9^2}=9\\ 18x^2=2(x^2)(9)\\ thus\ a\\ \textit{perfect square trinomial} \end{cases} \\\\\\ (x^2+9)\ [(x^2)^2-18x^2+9^2] \\\\\\ (x^2+9)(x^2-9)^2\implies (x^2+9)(x^2-3^2)^2 \\\\\\ (x^2+9)\ [(x-3)(x+3)]^2\implies \boxed{(x^2+9)(x-3)^2(x+3)^2} \\\\\\ \textit{and I guess you could be redundant and use} \\\\\\ (x^2+9)(x-3)(x-3)(x+3)(x+3)[/tex]
Angles θ and Φ are supplementary, and theta equals 3pi/7 find the measure of theta
Answers
Φ + 3π/7 = π
Φ = π - 3π/7
Φ =4π/7
From Plato: Φ =7π/7 or π.
Walter bought a square plot of land. the perimeter is 544 feet. how wide is the property?
Answers
perimeter of a square = is side times 4
so divide 544 by 4
544/4 = 136
the property is 136 feet wide
The coordinates of the midpoint of GH¯¯¯¯¯¯¯¯are M(−2, 5) and the coordinates of one endpoint are H(−3, 7) .
The coordinates of the other endpoint are ( __ , __ )
Answers
(-3 + x) / 2 = -2
-3 + x = -4
x = -4 + 3
x = -1
(7 + y) / 2 = 5
7 + y = 10
y = 10 - 7
y = 3
so the other endpoint is (-1,3)
The coordinate point of the other endpoint, G is (-1, 3)
The given parameters;
the midpoint = M(-2, 5)
one end point = H(-3,7)
To find:
the coordinate point of the other endpoint, GLet the coordinate point of the other endpoint = G(x, y)
The coordinate point of the other endpoint, G will be calculated using midpoint formula.
[tex]M(-2, 5) =( \frac{x + (-3)}{2} , \frac{y + 7}{2} )\\\\-2 = \frac{x - 3}{2} \ \ \ and \ \ 5 = \frac{y+ 7}{2} \\\\x-3 = 2(-2)\\\\x - 3 = -4\\\\x = -4 + 3\\\\x = -1\\\\y+ 7 = 2(5)\\\\y + 7 = 10\\\\y = 10 -7\\\\y = 3\\\\G= (-1, 3)[/tex]
Thus, the coordinate point of the other endpoint, G is (-1, 3)
Learn more here: https://brainly.com/question/10812174
Find the exact solution to the equation. Show your work for credit. (1 point) four to the power of quantity twelve minus four x equals two hundred and fifty six.
Answers
4^(12-4x)=4^4 taking the natural log of both sides
(12-4x)ln4=4ln4 dividing both sides by ln4
12-4x=4 subtract 12 from both sides
-4x=-8 divide both sides by -4
x=2
The exact solution to the equation [tex]4^{(12 - 4x)[/tex] = 256 is x = 2. By recognizing that 256 is 4 raised to the fourth power, we equate the exponents and solve for x.
To solve this problem, we need to recognize that 256 is a power of 4. 4⁴ = 256. With this insight, the equation can be rewritten as:
[tex]4^{(12 - 4x)[/tex] = 4⁴
Since the bases are the same, we can equate the exponents:
12 - 4x = 4
Now, we'll isolate the variable x:
Subtract 12 from both sides: -4x = 4 - 12
-4x = -8
Divide both sides by -4: x = 2
Thus, the exact solution to the given equation is x = 2.
how close are a meter and a yard? convert 1 meter into yards by using the fact
that there are 100 centimeters in a meter, 2.53 centimeters in a inch, 12 inches in a foot, and 3 feet in a yard.
Answers
2.53cm=1 inch
12 inches= 1 foot
3 feet= 1 yard
2.53*12*3=91.08
1 yard=91.08cm
1 meter=100cm
1 meter is 8.92cm longer than 1 yard
I hope this helps, if you need more elaboration, just ask
5 radians is the same as _____.
Answers
5rad(360°/2π rad)=900/π degrees
That is approximately:
286.48° (to nearest hundredth of a degree) or
286°28'44" (to nearest second)
Answer:
286°28'44
Step-by-step explanation:
Let $f$ be a function such that $f(x+y) = x + f(y)$ for any two real numbers $x$ and $y$. if $f(0) = 2$, then what is $f(2012)?$
Answers
Given:
f(0) = 2
So first of all, we let x = 2012, y = 0:
Then, F(2012) = 2012 + f(0)
Since f(0) = 2, then f(2012) = 2012 + 2 = 2014.
To add, the process that relates an input to an output is called a
function.
There are always three main parts of a
function, namely:
Input
The Relationship
The Output
The classic way of writing a function is "f(x) = ... ".
What goes into the function is put inside parentheses () after the name of the function: So, f(x) shows us the function is called "f", and "x" goes in.
What a function does with the input can be usually seen as:
f(x) = x2 reveals to us that function "f" takes "x" and squares it.
Juanita’s boss told her that once she has worked with the company for 10 years, her salary will be increased to 3 times what she makes now plus $2,000. If s represents her original salary, which expression represents what her salary will be after 10 years at the company?
Answers
A=3s+2000
Answer:3s+2,000
Step-by-step explanation:
Miss broom invested $10,000 into an account with an interest rate of 6% compounded annually which equation models the time it will take for his money to double?
A- logbase2 1.06= T
B- log2 =T
C-log1.06 =T
D= logbase1.06 2=t
Answers
D= logbase1.06 2=t
If you compute it, you will will get 11.89 years which rounded to 12 years
if 6a-8b=0 and c=12b, the ratio of a to c is equivalent to the ratio of one to what number?
Answers
3a=4b
c=3*(4b)=3*3a=9a
c=9a
Evaluate P(6,2).
A.) 12
B.) 30
C.) 360
Answers
[tex]6P2=\frac{6!}{(6-2)!}=\frac{4!\cdot 5 \cdot 6}{4!}=5 \cdot 6=30[/tex]
The value of the [tex]\rm ^6p_2[/tex] is 30.
We have to determineThe value of P(6,2).
According to the question
The value of the [tex]\rm ^6p_2[/tex] is determined by using permutation.
The probability of selecting an ordered set of 'r' objects from a group of 'n' number of objects.
The order of objects matters in the case of permutation.
The formula to find [tex]\rm ^np_r[/tex] is given by:
[tex]\rm ^np_r = \dfrac{n!}{(n-r)!}[/tex]
Substitute n = 6 and r = 2 in the formula;
[tex]\rm ^np_r = \dfrac{n!}{(n-r)!}\\ \\ \rm ^6p_2 = \dfrac{6!}{(6-2)!}\\ \\ \rm ^6p_2= \dfrac{6 \times 5\times 4 \times 3\times2 \times 1}{4!}\\ \\ ^6p_2= \dfrac{6 \times 5\times 4 \times 3\times2 \times 1}{4\times 3 \times2 \times 1}\\ \\ ^6p_2= 6 \times 5}\\ \\ ^6p_2= 30[/tex]
Hence, The value of the [tex]\rm ^6p_2[/tex] is 30.
To know more about Permutation click the link given below.
https://brainly.com/question/10148445
What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term of 2?
an = 5 − 2(n − 1); all integers where n ≥ 1
an = 5 − 2(n − 1); all integers where n ≥ 0
an = 5 − 3(n − 1); all integers where n ≥ 1
an = 5 − 3(n − 1); all integers where n ≥ 0
Answers
The easiest way to answer this is to try all choices, plug in values for the 1st term and 2nd term then check if the answer matches with 5 and 2. (n = 1 and n = 2)
We know that n starts with 1 because that is our 1st term, we do not have 0th term, therefore that leaves us with 2 choices.
Choice 1: an = 5 − 2(n − 1); all integers where n ≥ 1
n = 1
a1 = 5 – 2 (1 – 1) = 5 – 2 (0)
a1 = 5
n = 2
a2 = 5 – 2 (2 – 1) = 5 – 2 (1)
a2 = 3 (FALSE!)
Choice 2: an = 5 − 3(n − 1); all integers where n ≥ 1
n = 1
a1 = 5 – 3 (1 – 1) = 5 – 3 (0)
a1 = 5
n = 2
a2 = 5 – 3 (2 – 1) = 5 – 3 (1)
a2 = 2 (TRUE)
Therefore the correct answer is:
an = 5 − 3(n − 1); all integers where n ≥ 1
Answer:
A is INCORRECT
Step-by-step explanation:
Just finished the FLVS test
Which of the following is a factor of 6x2 + 2x − 21?
4x − 3
2x + 7
6x − 3
None of the above
Answers
None of the above
EXPLANATION
The quadratic expression given to us is
[tex]6 {x}^{2} + 2x - 21[/tex]
If the discriminant of this quadratic expression is a perfect square, then it has rational factors,
If we compare the above expression to the general quadratic expression,
[tex]a {x}^{2} + bx + c[/tex]
We have,
[tex]a=6,b=2,c=-21[/tex]
The discriminant is given by,
[tex] D = {b}^{2} - 4ac[/tex]
Thus
[tex] D = {2}^{2} - 4(6)( - 21)[/tex]
[tex] D = 4 + 504 = 508[/tex]
Since 508 is not a perfect square, the expression
[tex]6 {x}^{2} + 2x - 21[/tex]
has no rational factors.
Therefore D is the correct answer.
How can the average rate of change be found using a discrete graph?
Answers
The average rate of change can be found using a discrete graph by calculating the slope between two points on the graph. This provides insight into how the dependent variable changes as the independent variable varies.
Explanation:The average rate of change can be found using a discrete graph by calculating the difference in the y-values of two points and dividing it by the difference in the x-values of those same points. This will give you the slope of the line connecting the two points, which represents the average rate of change between those two points. For example, if you have two points (x1, y1) and (x2, y2), the average rate of change can be calculated as:
(y2 - y1) / (x2 - x1)
By finding the average rate of change at different intervals on the graph, you can analyze how the dependent variable changes in relation to the independent variable.
if f (x) =-14x-2, then f^-1 (x) =
Answers
Switch up the variables:
y = -14x - 2.
x = -14y - 2.
Add 2 to both sides.
x + 2 = -14y - 2 + 2.
x + 2 = -14y.
Divide by -14 on both sides.
(x + 2) / -14 = -14y / -14.
(x + 2) / -14 = y.
Change the y to f^-1(x).
f^-1(x) = (x + 2) / -14.
Hopefully, this helps! =)
A right triangle has legs that are 10.1in and 12.2 in long. What is the approximate length of the hypotenuse?
Answers
10.1^2 + 12.2^2 = c^2
102.01 + 148.84 = c^2
250.85 = c^2
sqrt 250.85 = c
15.838 = c <== ur hypotenuse
The measure of ∠B is (3x – 4 )° and the measure of ∠D is (2x – 6)°. What are the measures of angles B and D?
Answers
The measures of angles B and D are 110° and 70° respectively.
What is cyclic quadrilateral?The rule of cyclic quadrilateral states that, the sum of the opposite is supplementary i.e 180°
Therefore, applying this rule, Angle B and D are supplementary
Then, B+D=180°
Given that, B=3x-4 and D= 2x-6
Thus, (3x-4)+(2x-6)=180°
3x-4+2x-6=180°
3x+2x-4-6=180°
5x-10=180°
5x=180°+10
5x=190°
Then, x =190/5
x=38°
Then solving for B and D;
B=3x-4
B=3(38)-4
B=114-4
B=110°
Also, D=2x-6
D=2(38)-6
D=76-6
D=70°
Learn more about cyclic quadrilateral ;
https://brainly.com/question/14928650
#SPJ5
Simplify:
6( [tex]4/3 \f[/tex] ( 14 ÷ [tex] \frac{1}{7} [/tex] ) ) ÷ [tex] \frac{13}{10} [/tex]
-
I got 603 [tex] \frac{1}{12} [/tex] , but i'm not completely sure it's correct..
Answers
33.
In quadrilateral PQRS, the coordinates are P(0, 0), Q(a + c, 0), R(2a + c, b), and S(a, b). How can you use coordinate geometry to show that the diagonals are perpendicular?
Apply the Distance Formula to show that opposite sides to show they are congruent.
Find the slopes of their product is 1.
Apply the Distance Formula to show that opposite sides to show sides are congruent.
Find the slopes and show that their product is -1.
Answers
A technique that can help you to know if two straight lines are perpendicular is is you find their slopes. Let's say the slope of line 1 is m1 and the slope of line 2 is m2. If m1*m2 yields a product of -1, then the lines are perpendicular. This is because if m1 is the negative reciprocal of m2, the lines are perpendicular. But if m1=m2, the lines are parallel, meaning they don't intersect at all.
Therefore, the answer is: Find the slopes and show that their product is -1.
Answer: The answer is (d) Find the slopes and show that their product is -1.
Step-by-step explanation: Given in the question and shown in the attached figure that the vertices of the quadrilateral PQRS are P(0, 0), Q(a + c, 0), R(2a + c, b), and S(a, b). We are asked to use geometry to show that the diagonals PR and QS are perpendicular to each other.
We know that the two lines are perpendicular if the product of their slopes is --1.
So, first we will find the slopes of PR and QS, multiply them, and check the value.If the value is -1, then the diagonals are perpendicular to each other.
That is, if 'm' and 'p' are the slopes of the diagonals PR and QS, and if m × p = -1, then the two diagonals are perpendicular.
Thus, the correct answer is (d).