How do i write 0.624 in expanded form?

Answers

Answer 1
6(1/10)+2(1/100)+4(1/1000)

btw not rrly so sure wut expanded form is.
Answer 2
0.624 in expanded form is 0+0.6+0.02+0.004, the expanded form is like a word form but when you say it you write it as a number form.

Related Questions

Catherine walks her dog 3/4 mile everyday. how far does she walk each day?

Answers

 3/4 mile            
If she were to walk her dog for a week then 5 1/4 miles.

Find two values of b that will make 9 x 2 + b x + 9 a perfect square trinomial.

Answers

You want 9x^2 + bx + 9a to be a perfect square trinomial.  Note that 9 x 2 is incorrect and should be written as 9x^2, where "^" represents "exponentiation."

What about a?  Are we supposed to find a also?

One way in which to do this problem is to factor 9 out of the trinomial:

9 (x^2 + (b/9)x + a )

Concentrate now on making x^2 + (b/9)x + a into a perfect square trinomial.

x^2 + (b/9)x                            + a

Take half of the coefficient (b/9) and square the result:  [(b/9)/2]^2 = b^2/81.  

Then, x^2 + (b/9)x + b^2/81 - b^2/81 + a.

          The above quadratic expression can be re-written as

             (x + b/9)^2  - b^2/81 + a.  This is a perfect square trinomial if

                                 -b^2/81 + a = 0.  Solve for b:  b^2/81 = a,
                                                             b/9 = sqrt(a)
                                                              b = 9 sqrt a


What is a coplanar. You will earn good point.

Answers

Think about the prefix co-

cooperation
cosign
co-president

It's typically used to describe things that are shared or mutual. We say that two points are coplanar when they share the same plane.

A students received a score of 50 on his history test. The test had a mean of 69 and a standard deviation of 10. Find the z score and assess whether his score is considered unusual.

Answers

[tex]z = \frac{x - mean}{stdev} \\ \\ z = \frac{50 - 69}{10} = -1.9[/tex]

The general rule is that 68% of all scores are within 1 z-score of the mean.
95% are within 2 z-scores of the mean.
99% are within 3 z-scores of the mean.

1.9 is pretty close to 2, so this means approximately only 5% of all scores are more unusual than this students' score.

i need to know what t is but i don't understand how to get it

Answers

[tex]\bf \cfrac{7+3t}{4}=-\cfrac{t}{8}\impliedby \textit{first off cross-multiply} \\\\\\ 8(7+3t)=4(-t)\implies 56+24t=-4t\implies 24t+4t=-56 \\\\\\ 28t=-56\implies t=-\cfrac{56}{28}\implies t=-2[/tex]

What is the reason for each step in the solution of the equation?

3+4xâ’3x=4

Drag and drop the reasons into the boxes to correctly complete the table.

3+x=43+x=4

x=1

Distributive property
Subtraction property of equality
Combine like terms
Division property of equality
Given

Answers

Could you rewrite this please? It is fairly difficult to read. 

If sale price of a shirt after giving 8% is RS.161,then find the written price? (By the written price means cost price)

Answers


you can do it, man
I believe in you

To find the original cost price of a shirt on which an 8% discount was given, resulting in a sale price of Rs.161, the formula CP = Sale Price / (1 - (Discount Percent / 100)) is used, calculating the cost price as Rs.175.

If the sale price of a shirt after giving an 8% discount is Rs.161, to find the written price, or the cost price before the discount, we can use the formula for discount calculation. Let CP represent the cost price. The formula for calculating the sale price after discount is:

Sale Price = CP - (Discount Percent * CP) / 100

Here, the sale price is given as Rs.161, and the discount percent is 8%. Therefore, we can rearrange the formula to solve for CP:

CP = Sale Price / (1 - (Discount Percent / 100))

Plugging in the values gives us:

CP = 161 / (1 - (8 / 100)) = 161 / 0.92 = Rs.175

Therefore, the written price or the cost price of the shirt before the discount was applied is Rs.175.

Jorge says there are 198 inches in 5.5 yards. Is he correct?

Answers

yess Jorge is correct
36 inches in 1 yard so
5 times 36=180
1/2 of 36( to get the.5) = 18
180+18= 198
so he is right

Classify the following triangle. Check all that apply

Answers

It is an acute triangle and a scalene triangle. It is acute because the angles are less than 90 degrees and it is scalene because all of the sides are not equal.

The manufacturers of m&m's claim that 20% of the milk chocolate m&m candies are orange. find the mean and standard deviation of the sampling distribution of the sample proportion of orange m&m's for samples of size 100. use two decimal places.

Answers

The mean of a sampling distribution of a sample with proportion, p and sample size, n is given by [tex]\mu=np[/tex].

The standard deviation of a sampling distribution of a sample with proportion, p and sample size, n is given by [tex]\sigma= \sqrt{np(1-p)} [/tex]

Given that the manufacturers of m&m's claim that 20% of the milk chocolate m&m candies are orange. The proportion is p = 0.2

The mean of the sampling distribution of the sample proportion of orange m&m's for samples of size 100 is given by [tex]\mu=100(0.2)=20[/tex]

The standard deviation of the sampling distribution of the sample proportion of orange m&m's for samples of size 100 is given by [tex]\sigma= \sqrt{100(0.2)(1-0.2)} = \sqrt{16} =4[/tex]

How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 35% antifreeze?

To obtain a 35% antifreeze solution, □ gallon(s) of water should be added
(Simplify your answer.)

Answers

Final answer:

To obtain a 35% antifreeze solution, you need to add approximately 1.857 gallons of water to 1 gallon of pure antifreeze.

Explanation:

To obtain a 35% antifreeze solution, you need to add a certain amount of water to 1 gallon of pure antifreeze. Let's assume that x gallons of water should be added. In a 35% antifreeze solution, the amount of antifreeze is 35% of the total solution. So, we can set up the following equation:

1 gallon of antifreeze = (35/100) * (1 + x) gallons of solution

Simplifying this equation, we get:

1 = 0.35 * (1 + x)

Now, let's solve for x:

Divide both sides of the equation by 0.35:

1/0.35 = 1 + x

2.857 = 1 + x

Subtract 1 from both sides of the equation:

2.857 - 1 = x

x = 1.857 gallons of water

Therefore, you need to add approximately 1.857 gallons of water to 1 gallon of pure antifreeze to obtain a 35% antifreeze solution.

Final answer:

To obtain a 35% antifreeze solution from 1 gallon of pure antifreeze, approximately 1.857 gallons of water needs to be added. This calculation is based on a simple concentration equation, resulting in the given ratio.

Explanation:

To calculate the amount of water to be added to 1 gallon of pure antifreeze to obtain a solution that is 35% antifreeze, we need to perform a simple concentration calculation.

We are starting with pure antifreeze, so it's 100% antifreeze. We want to end with a solution that is 35% antifreeze. Let's denote the amount of water added as x gallons. Because we are diluting the antifreeze, the total volume of the solution after adding water will be 1 gallon (the initial volume of the antifreeze) plus x gallons (the volume of water added).

The concentration of antifreeze after adding water is the volume of antifreeze divided by the total volume of the solution:

Concentration of antifreeze = Volume of antifreeze / Total volume of solution

Thus, 0.35 = 1 / (1 + x)

Multiplying both sides by (1 + x) and then by 0.35 we get:

1 = 0.35 * (1 + x)

Dividing by 0.35 and then subtracting 1:

x = 1 / 0.35 - 1

After calculating:

x ≈ 1.857 gallons

To obtain a 35% antifreeze solution, approximately 1.857 gallons of water should be added.

If a 30 -meter pine tree casts a shadow of 30 meters, how far is the tip of the shadow from the top of the tree?

Answers

From the information given, this scenario creates a 45-45-90 triangle, allowing us to use the Pythagorean Theorem. 30^2+30^2=x^2. 30^2 is 900, so now you have 900+900=x^2. Add to make 1800=x^2. Now take the square root of both sides. It should come out to be about 42.43 meters.

The distance from the tip of the shadow to the top of the tree is 42.426 meters.

What is Pythagoras' theorem?

Pythagoras theorem is a relation between sides of a right-angle triangle.

It states that for a right-angle triangle the square root of Hypotenuse is equal to the sum of the individual base and perpendicular square.

So,

Hyp² = Base² + Perp²

Given the situation is making a right angle triangle with base and perpendicular as 30 meters.

By Pythagoras theorem,

Hyp² = Base² + Perp²

Hyp² = 30² + 30²

Hyp² = 1800

Hyp = 42.426 meter.

Hence "The distance from the tip of the shadow to the top of the tree is 42.426 meters".

To learn more about Pythagoras' theorem,

https://brainly.com/question/21926466

#SPJ2

If a line of one billion people standing shoulder to shoulder stretches 346,439 miles long, what is the average shoulder width, in feet, of the people in the line?

Answers

the answer in scientific form is 1.829198 • 10^9 but not in scientific form would just be 346,439 times 5280

Answer: [tex]1.83\text{ feet}[/tex]

Step-by-step explanation:

Given : If a line of one billion people standing shoulder to shoulder stretches 346,439 miles long.

We know that 1 mile =5280 feet

Then, the length of line=[tex]346439\times5280=1829197920[/tex] feet

We know that 1 billion can be written as :

[tex]1,000,000,000=10^9[/tex]

Now, the average shoulder width of the people in the line :-

[tex]\dfrac{1829197920}{1000000000}=1.8291979\approx1.83\text{ feet}[/tex]

Hence, the average shoulder width of the people in the line is about [tex]1.83\text{ feet}[/tex]

there are 28 tables in the cafeteria.each table has 12 students sitting at it.fourth graders sit at 13 of the yables.fifth graders sit at the rest of the tables.how many fifth graders are there?

Answers

Hope this helps!

28 - 13 = 15
15 x 12 = 180 Fifth graders

A nail is 0.1875 inch thick. What is it’s thickness as a fraction? Is 0.1875 inch closer to 1/8 inch or 1/4 inch on a number line?

Answers

It is the same distance apart. .1875-.125 is .0625
1/4 is .25-.1875 is .0625

The LCD for the fractions 1/3, 3/4, 5/32, and 8/9 is

Answers

In order to find the least common denominator we need to find the common multiple between the denominators of 3, 4, 32, and 9 and once we get that we have our answer.

Answer: LCD is 288.
Hello There!

Factor them by their prime factors:
3  =  3
4 = 2 x 2 or 2²
32 = 2 x 2 x 2 x 2 x 2 or [tex] 2^{5} [/tex]
9 = 3 x 3 or 3²

Since you can divide 32 by 4 and 9 by 3, you only need to use 32 and 9.

LCD = 2 x 2 x 2 x 2 x 2 x 3 x 3
LCD = [tex] 2^{5} [/tex] x [tex] 3^{2} [/tex]
LCD = 288

Hope This Helps You!
Good Luck :) 

- Hannah ❤

What is the scale factor of triangle ABC to triangle DEF

Answers

[tex]\bf side:side\qquad \cfrac{side}{side}\implies \cfrac{5}{5}\implies \cfrac{1}{1}\implies 1:1\impliedby \textit{scale factor}[/tex]

Answer:

The correct option is:  1

Step-by-step explanation:

Scale factor is the ratio of corresponding side lengths of two triangles.

Here....

[tex]\frac{DE}{AB}=\frac{5}{5}=1\\ \\ \frac{DF}{AC}=\frac{5}{5}=1\\ \\ \frac{EF}{BC}=\frac{5}{5}=1[/tex]

So, the scale factor of [tex]\triangle ABC[/tex] to [tex]\triangle DEF[/tex] is 1.

problem solving choose the correct answer that follows each sequence
3 4 6 9 13 18 24
.29
.31
.32
.33

Answers

31
it goes by 1 hen 2 then 3 then 4 then 5 then 6 then 7
you add each of the numbers to the last number

hat is the solution set of the following equation? -8x + x + 15 = -7x + 12 Ø {} {all reals}

Answers

-8x + x + 15  = -7x + 12
-7x + 15 = -7x + 12

First of all, we need to put the variables apart and the numbers apart. So we add 7x on both sides:
-7x + 7x + 15 = -7x + 7x + 12
0x + 15 = 0x + 12
15 = 12

This answer is impossible since 15 can never be equal to 12. So there are no values of x that can make the equation true.

Hope this helps! :)

What is the estimate 323 +151

Answers

There are multiple ways of doing this.  I would round off 323 to 300 and round off 151 to 150.  Then 323 + 151 is approx. equal to  300 + 150 = 450.

You could also find the estimate 320 + 150 = 470.

What is the area of trapezoid ABCD ? (Enter your answer as a decimal or whole number)

Answers

check the picture below.

bear in mind that, the "bases" are the two parallel sides, and the height is the distance between them.

[tex]\bf \textit{area of this trapezoid}\\\\ A=\cfrac{AB(BC+AD)}{2}\\\\ -------------------------------\\\\ \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ -1}}\quad ,&{{ 5}})\quad % (c,d B&({{ 3}}\quad ,&{{ 2}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ AB=\sqrt{[3-(-1)]^2+[2-5]^2}\implies AB=\sqrt{(3+1)^2+(2-5)^2} \\\\\\ AB=\sqrt{16+9}\implies AB=\sqrt{25}\implies \boxed{AB=5}[/tex]

[tex]\bf -------------------------------\\\\ \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) B&({{ 3}}\quad ,&{{ 2}})\quad % (c,d C&({{ 0}}\quad ,&{{ -2}}) \end{array} \\\\\\ BC=\sqrt{(0-3)^2+(-2-2)^2}\implies BC=\sqrt{9+16} \\\\\\ BC=\sqrt{25}\implies \boxed{BC=5}[/tex]

[tex]\bf -------------------------------\\\\ \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ -1}}\quad ,&{{ 5}})\quad % (c,d D&({{ -13}}\quad ,&{{ -11}}) \end{array} \\\\\\ AD=\sqrt{[-13-(-1)]^2+[-11-5]^2} \\\\\\ AD=\sqrt{(-13+1)^2+(-16)^2}\implies AD=\sqrt{144+256} \\\\\\ AD=\sqrt{400}\implies \boxed{AD=\sqrt{20}}[/tex]

so, the area for this trapezoid is then

[tex]\bf A=\cfrac{5(5+20)}{2}\implies A=\cfrac{125}{2}\implies A=62\frac{1}{2}[/tex]

Area of the trapezoid ABCD is

[tex]62\frac{1}{2}[/tex]

Given :

The diagram of a trapezoid ABCD

Area of trapezoid is [tex]\frac{base1+base2}{2} \cdot height[/tex]

Lets find the length of base 1  and base 2 using distance formula

Base 1 is AD. find the distance AD

[tex]AD=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\AD=\sqrt{\left(-13-\left(-1\right)\right)^2+\left(-11-5\right)^2}\\AD=20[/tex]

Now we find out BD that is base 2

[tex]BD=\sqrt{\left(0-3\right)^2+\left(-2-2\right)^2}\\BD=5[/tex]

Now find out height  AB

A is (-1,5) and B(3,2)

[tex]AB=\sqrt{\left(-1-3\right)^2+\left(5-2\right)^2}\\AB=5\\[/tex]

[tex]Area =\frac{AD+BC}{2} \cdot AB\\Area=\frac{20+5}{2} \cdot 5\\Area=\frac{125}{2}\\Area=62\frac{1}{2}[/tex]

Area of the trapezoid ABCD is

[tex]62\frac{1}{2}[/tex]

Learn more : brainly.com/question/11150764

How can I find the exact distance between the points(√7,-√2)and (4√7,5√2)

Answers

[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ \sqrt{7}}}\quad ,&{{ -\sqrt{2}}})\quad % (c,d) &({{4\sqrt{7}}}\quad ,&{{ 5\sqrt{2}}}) \end{array}~~~ % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ [/tex]

[tex]\bf d=\sqrt{[4\sqrt{7}-\sqrt{7}]^2~+~[5\sqrt{2}-(-\sqrt{2})]^2} \\\\\\ d=\sqrt{(4\sqrt{7}-\sqrt{7})^2~+~(5\sqrt{2}+\sqrt{2})^2}\implies d=\sqrt{(3\sqrt{7})^2~+~(6\sqrt{2})^2} \\\\\\ d=\sqrt{3^2\cdot 7~~+~~6^2\cdot 2}\implies d=\sqrt{63+72}\implies d=\sqrt{135} \\\\\\ \begin{cases} 135=5\cdot 3\cdot 3\cdot 3\\ \qquad 5\cdot 3^2\cdot 3\\ \qquad 15\cdot 3^2 \end{cases}\implies d=\sqrt{15\cdot 3^2}\implies d=3\sqrt{15}[/tex]

How do you write 960,060 in expanded form

Answers

900,000 + 60,000 + 60

hope this helps

Answer:

[tex]900000 + 60000+60[/tex]

Step-by-step explanation:

write 960,060 in expanded form

In 960,060, from left to right

0 is in ones place is 0

6 is in tens place is 6 times 10 = 60

6 is in ten thousands place is 6 times 10000= 60000

9 is in hundred thousands place 9 times 100000= 900000

So the expanded form of the given number is

[tex]900000 + 60000+60[/tex]

three adults and four children must pay $107. two adults and three children must pay $76. find the price of the adult ticks and the price of a childs ticket

Answers

assigning "a" as cost of adult tickets and "c" the cost of children's tickets.

3a + 4c = 107
2a + 3c = 76

elimination method
2(3a + 4c = 107)
-3(2a + 3c = 76)

6a + 8c = 214
-6a - 9c = -228
----------------------
0 - c = - 14
c = 14

Then 2a + 3(14) = 76
2a = 76 - 42
2a = 34
a = 34/2
a = 17


Translate the phrase into a math expression. 
 
the quotient of twenty divided by four more than one



 
A.
(20 ÷ 4) + 1


 
B.
1 + (4 ÷ 20)


 
C.
(1 + 4) ÷ 20


 
D.
20 ÷ (1 + 4)

Answers

its d 20 / (1+4)...........................................................................



Jasmine exchanges $100 for Yen before going to Japan if each US dollar is worth 87.747 Yen how many yen should Jasmine receive

Answers

100 * 87.747 = 8774.7

Evaluate -(4/5) over 8/15

Answers

See picture for the answer.

The slope of a line is -1/3, and the y-intercept is 10/3. What is the equation of the line written in general form?
10x + 3y - 1 = 0
x + 3y + 10 = 0
x + 3y - 10 = 0

Answers

The answer is:  [B]:  " x  + 3y + 10 = 0 " .
______________________________________________________
Explanation:
______________________________________________________
Note the equation for a line; in 'slope-intercept form':  "y = mx + b" ;
 
   in which "y" is isolated alone, as a single variable, on the left-hand side of the equation;
                "m" = the slope of the line; and is the co-efficient of "x" ;
                                  b = the "y-intercept"; (or the "y-coordinate of the point of                                                                          the "y-intercept"). 
______________________________________________________
So, given the information in this very question/problem:
______________________________________________________
slope = m = (-1/3) ; 
b = y-intercept = (10/3) ; 
______________________________________________________
And we can write the equation of the line; in "slope-intercept form"; that is:
______________________________________________________
  " y = mx + b " ;  as:
______________________________________________________

   " y = (-1/3)x + (10/3) " ;
______________________________________________________
Now, the problem asks for the equation of this line; in "general form";  or "standard format";  which is:
________________________________________
   "Ax + By + C = 0 " ; 
________________________________________
So; given: 
____________________________________
 " y = (-1/3)x + (10/3) " ;
____________________________________
  We can multiply the ENTIRE EQUATION (both sides) by "3" ; to get rid of the "fractions" ;

  →  3* { y = (-1/3)x + (10/3) } ;

  →  3y = -1x + 10 ; 

        ↔  -1x + 10 = 3y ; 

Subtract "(3y)" from each side of the equation:
____________________________________
            -1x + 10 − 3y = 3y − 3y ;

to get: 

-1x + 10 − 3y = 0 ; 

↔  -1x − 3y − 10 = 0 ;  

→ This is not one of the "3 (THREE) answer choices given" ;

→ So, multiply the ENTIRE EQUATION (both sides); by "-1" ; as follows:

     -1 * {-1x − 3y − 10 = 0} ; 

to get:
______________________________________________________
   →   " x + 3y + 10 = 0 " ;  which is:  "Answer choice:  [B] ."
______________________________________________________
Note that is equation is in the "standard format" ;
     " Ax + By + C = 0 " .
______________________________________________________

The slope of a line is -1/3, and the y-intercept is 10/3. What is the equation of the line written in general form?

Answer:

x + 3y - 10 = 0

What is the place value relationships of 8's in 6,588

Answers

The rightmost 8 is in the ones place and the 8 to the left of that is in the tens place.
Ones and tens
EXAMPLE
9-ones 
97- tens
987-hundreds and so on

The area of a regular octagon is 35 cm^2. What is the area of a regular octagon with sides five times as long?
A. 625 cm^2
B. 875 cm^2
C. 175 cm^2
D. 245 cm^2

I'm not very good at this kind of stuff :/

Answers

so... let's say the smaller regular octagon has sides of "x" long, then the larger octagon will have sides of 5x.

[tex]\bf \qquad \qquad \textit{ratio relations} \\\\ \begin{array}{ccccllll} &Sides&Area&Volume\\ &-----&-----&-----\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array} \\\\ -----------------------------\\\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\ -------------------------------\\\\[/tex]

[tex]\bf \cfrac{small}{large}\quad \stackrel{area~ratio}{\cfrac{s^2}{s^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{(5x)^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{5^2x^2}}\implies \stackrel{area~ratio}{\cfrac{\underline{x^2}}{25\underline{x^2}}}=\stackrel{area~ratio}{\cfrac{35}{a}} \\\\\\ \cfrac{1}{25}=\cfrac{35}{a}\implies a=\cfrac{25\cdot 35}{1}[/tex]
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