How do you recognize if a binomial is a difference of perfect squares and how is the pattern used to factor the binomial?

Answer

3/7 - three sevenths

Step-by-step explanation:

Multiply both numerators and both denominators

4*3=12 and 7*4=28

first one is your numerator

second one is your denominator

12/28

Then simplify

12/4=3 and 28/4=7

3/7

Answer:

8 square units

Step-by-step explanation:

Base area= Length* width

Base area= 4* 2

Base area= 8 square units

Answer:

8 square units

Step-by-step explanation:

Base area= Length* width

Base area= 4* 2

Base area= 8 square units

[tex]\heartsuit[/tex]  If x = 4 is the Only Solution of the Equation x² + bx + 16 = 0

[tex]\heartsuit[/tex]  Then the Value x = 4 should satisfy the Given Equation

⇒ (4)² + b(4) + 16 = 0

⇒ 16 + 4b + 16 = 0

⇒ 4b + 32 = 0

⇒ 4b = -32

⇒ b = -8

[tex]7x+10=\dfrac{1}{3}(12x-3)+14x\qquad\text{use distributive property}\\\\7x+10=\dfrac{1}{3}\cdot12x-\dfrac{1}{3}\cdot3+14x\\\\7x+10=4x-1+14x\\\\7x+10=18x-1\qquad\text{substitute 10 from both sides}\\\\7x=18x-11\qquad\text{subtract 18x from both sides}\\\\-11x=-11\qquad\text{divide both sides by (-11)}\\\\\boxed{x=1}[/tex]

Answer:

I believe the correct awnser is x=1 I took the test

Answer:

x = 5

Step-by-step explanation:

in ΔABC , AB = BC , hence triangle is isosceles, thus

∠A = ∠C = 73° ( base angles are equal )

the sum of the 3 angles in a triangle = 180°

subtract the sum of the base angles from 180 for ∠B

∠B = 180° - (73 + 73)° = 34°

⇒ 6x + 4 = 34 ( subtract 4 from both sides )

6x = 30 ( divide both sides by 6 )

x = 5

Answer:

(B) ASA

Step-by-step explanation:

we will verify each options

option-A:

we can see that there is no consecutive two angles

so, this postulates can not be true

so, this is FALSE

option-B:

We can see that

one angle and then side and another angle are equivalents

so, this is TRUE

option-C:

We can see that

one side and two angles are equivalents

so, this is FALSE

option-D:

we can see that

one side and two angles are equivalents

so, this is FALSE

Answer:

B

Step-by-step explanation:

Answer:

Money  club have after the show is  $358 .

Step-by-step explanation:

As given

The art club at a school raised $248 at a car wash.

They spent $206 to set up an art show, and raised $316 at the art show by selling artwork the members had made.

Than

Money club have after the show =  school raised money at a car wash +  Raised money at the art show  -  spent money to set up an art show.

Money club have after the show =  248 +  316 - 206

Money club have after the show =  564 - 206

Money club have after the show =  $358

Therefore  money  club have after the show is  $358 .

Answer:

It is 358.

Step-by-step explanation:

The club started with $248, and then spent $206.

248−206=42

The club had $42, left after they spent for the art show.

Then, they raised another $316, at the show.

42 + 316 = 358

Answer: 358

6+4x=y or y=4x+6

Plug in to second equation: -5x-(4x+6)=21

-9x-6=21

-9x=27

x=-3

Plugging in, you get that y=-12+6 or -6.

Therefore, the solution is (-3,-6)

Answer:

(D)68

Step-by-step explanation:

If 1 litre =4.23 cups

and 1 cup = 8 ounces

Therefore: 1 litre = 4.23 X 8 Ounces = 33.84 Ounces

2 litres = 2 x 33.84 Ounces

           =67.68 Ounces

           =68 Ounces (To the nearest whole number)

The number of ounces in 2 liters will be 68 ounces. Thus, the correct option is D.

Given that:

1 liter = 4.23 cups

1 cup = 8 ounces

Unit modification is the process of converting the measurement of a given amount between various units, often by multiplicative constants that alter the value of the calculated quantity without altering its impacts.

The number of cups in 2 liters is calculated as,

⇒ 2 x 4.23

⇒ 8.46 cups

The number of ounces in 8.46 cups is calculated as,

⇒ 8.46 x 8

⇒ 67.68 or 68 ounces

Thus, the correct option is D.

More about the conversion link is given below.

https://brainly.com/question/9414705

#SPJ6

Answer:

A) 1/2QP=UT

D) SU II RP

Step-by-step explanation:

A & D ARE THE ANSWERS

The correct statements are 1/2QP=UT and SU||RP.

In this question, we are given that points S, U, and T are the midpoints of the sides of triangle PQR. We need to determine which statements are correct.

So firstly, we need to find how much the entire trip will cost. To do this, add the product of 16 and 35 (since tickets are 35 per student, and there are 16 students) with 960:

[tex](35*16)+960\\560+960\\\\\$ 1520[/tex]

The total cost of the trip is $1520. Next, we know that the sweatshirts will be making a profit of $19 per article sold so divide 1520 by 19:

[tex]1520\div 19=80[/tex]

The students need to sell 80 sweatshirts total to get enough money for the trip. Now, to know how many sweatshirts each student needs to sell individually, divide 80 by 16 (since there are 16 students):

[tex]80\div 16=5[/tex]

In short, each student must sell 5 sweatshirts to pay for the entire trip.

The least common multiple of 7 and 3 is 21, so both the football and volleyball teams will have games on the same day again in 21 days.

The question requires us to determine when the football and volleyball teams will have games on the same day again. Since the football team plays every 7 days and the volleyball team plays every 3 days, we are looking for the least common multiple (LCM) of 7 and 3, which represents the number of days until both teams will have games on the same day again.

To find the LCM of 7 and 3, we can list the multiples of each number until we find a common multiple:

Multiples of 7: 7, 14, 21, 28, ...

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, ...

The first common multiple we encounter is 21. Therefore, both teams will have games on the same day again in 21 days.

Billy wants tickets huh okay.....

Alright so first off what information do we have?

We know that 4 adult tickets are 15 Euros each

2 child tickets are 10 Euros each

Ok simple calculations here

4*15 = 60

2*10 = 20

Total is 80 Euros charge

10% booking fee

so 10% of 80 is 8 (Add this onto the total bill) = 88

3% of 88 is (well 1% is 0.88 3% is 0.88 * 3 = 2.64)

Total bill now is 90.64 (Might aswell add taxes now poor billy spending a 100)

By the way your answer is 90.64

First question:

By definition of sine and cosine, we have

[tex]\sin30^\circ=\dfrac h{\sqrt5}\implies h=\dfrac{\sqrt5}2[/tex]

[tex]\cos30^\circ=\dfrac g{\sqrt5}\implies g=\dfrac{\sqrt{15}}2[/tex]

Second question:

By definition of tangent, we have

[tex]\tan60^\circ=\dfrac{5\sqrt2}x\implies x=\dfrac{5\sqrt2}{\sqrt3}=\dfrac{5\sqrt6}3[/tex]

Then by Pythagoras' theorem,

[tex](5\sqrt2)^2+x^2=y^2\implies y=\sqrt{(5\sqrt2)^2+\left(\dfrac{5\sqrt6}3\right)^2}=\sqrt{50+\dfrac{50}3}=\sqrt{\dfrac{200}3}=\dfrac{10\sqrt6}3[/tex]

Answer:

d. 40

Step-by-step explanation:

x/4 - 7=3

Add 7 to both sides

x/4 - 7+7=3+7

x/4 = 10

Multiply by 4 on each side

x/4*4 = 10*4

x = 40

Answer:The Answer of this probelm is D 40.

Step-by-step explanation:

x/4 - 7=3

First you need to add 7 to both sides

x/4 - 7+7=3+7

x/4 = 10

second you need to multiply by 4 on each side

x/4*4 = 10*4

Once you finish this should be your final answer right here x = 40

Hope this helps

Answer:

[tex]A.\ a_n=n^2+1[/tex]

Step-by-step explanation:

[tex]Check:[/tex]

[tex]a_n=n^2+1\\\\a_1=1^2+1=1+1=2\qquad CORRECT\\\\a_2=2^2+1=4+1=5\qquad CORRECT\\\\a_3=3^2+1=9+1=10\qquad CORRECT\\\\a_4=4^2+1=16+1=17\qquad CORRECT\\\\a_5=5^2+1=25+1=26\qquad CORRECT[/tex]

Used PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

First Power, next Addition

Answer: A.

Step-by-step explanation:

2, 5, 10, 17, 26

First, check the difference between each term:

2 → 5 = +3

5 → 10 = +5

10 → 17 = +7

17 → 26 = +9

Since the difference (d) is not the same, this is not an arithmetic sequence.

Now, check the second tier {3, 5, 7, 9}

3 → 5 = 2

5 → 7 = 2

7 → 9 = 2

The difference (d) of the second tier is the same, so it is an exponential sequence.

--> the only option that is an exponential sequence is option A.

[tex]7x+10=13(12x-3)+14x\qquad\text{use distributive property}\\\\7x+10=(13)(12x)+(13)(-3)+14x\\\\7x+10=156x-39+14x\\\\7x+10=170x-39\qquad\text{subtract 10 from both sides}\\\\7x=170x-49\qquad\text{subtract 170x from both sides}\\\\-163x=-49\qquad\text{divide both sides by (-163)}\\\\\boxed{x=\dfrac{49}{163}}[/tex]

Answer:

b^2-4ac >0  the roots are real

Step-by-step explanation:

b^2-4ac >0  the roots are real

b^2-4ac = 0 there is 1 root

b^2 -4ac <0 the root are complex

Let the Distance traveled by the tourist by walking be : D miles

Given : Tourist walks at a rate of 4 Miles per Hour

[tex]\mathsf{\implies Tourist\;travels\;D\;Miles\;in : \frac{D}{4}\;Hours}[/tex]

Given : The Total Distance of Mountain Path = 31 Miles

Distance traveled by the tourist by hiring a Taxi is : (31 - D) Miles

Given : The Taxi travels at a constant speed of 50 miles per hour

[tex]\mathsf{\implies Tourist\;travels\;(31 - D)\;Miles\;in : (\frac{31 - D}{50})\;Hours}[/tex]

Given : The Tourist reaches the destination 2 Hours after he started

Time taken by Walking + Time Taken by travelling in Taxi = 2 Hours

[tex]\mathsf{\implies \frac{D}{4} + \frac{31 - D}{50} = 2}[/tex]

[tex]\mathsf{\implies \frac{D}{2} + \frac{31 - D}{25} = 4}[/tex]

[tex]\mathsf{\implies (\frac{25D + 2(31 - D)}{50}) = 4}[/tex]

[tex]\mathsf{\implies (\frac{25D + 62 - 2D}{50}) = 4}[/tex]

[tex]\mathsf{\implies ({23D + 62}) = 200}[/tex]

[tex]\mathsf{\implies 23D = 200 - 62}[/tex]

[tex]\mathsf{\implies 23D = 138}[/tex]

[tex]\mathsf{\implies D = 6}[/tex]

⇒ Distance traveled by the tourist by walking = 6 Miles

⇒ Distance traveled by the tourist by hiring a taxi = (31 - 6) = 25 Miles

⇒ The Distance for which tourist has to pay for cab driver is 25 Miles

The distance traveled by taxi = 25 miles

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration

• At constant velocity motion:

the speed of vo = v = constant

acceleration = a = 0

An equation of constant velocity motion

[tex]\large {\boxed {\bold {x = v \times \: t}}}[/tex]

x = distance = m

v = speed = m / s

t = time = seconds

x1, x2 = distance traveled

t1, t2 = travel time

1 = tourist, 2 = taxi

[tex]\rm x1=v1.t1=4t1\\\\x2=v2.t2=50.t2\\\\t1+t2=2~hours\\\\t1=2-t2[/tex]

Total distance = x1 + x2

[tex]\rm 31~miles=4t1+50t2\\\\31=4(2-t2)+50t2\\\\31=8-4t2+50t2\\\\23=46t2\\\\t2=0.5[/tex]

then:

[tex]\rm x2=v2.t2\\\\x2=50\times 0.5\\\\x2=\boxed{\bold{25~miles}}[/tex]

The distance of the elevator

brainly.com/question/8729508

resultant velocity

brainly.com/question/4945130

the average velocity

brainly.com/question/5248528

Answer:

Short-response question = 20.

Step-by-step explanation:

Let x be number of short response questions and y be the number of essay questions.

We have been given that there are 22 questions that are worth 100 points in total. Each short-response question is worth 4 points, and each essay question is worth 10 points. Using our given information we can form a system of equations as:

[tex]x+y=22...(1)[/tex]  

[tex]4x+10y=100...(2)[/tex]

Now we will solve our system of equations using substitution method.

From equation 1 we will get,

[tex]y=22-x[/tex]

Upon substituting [tex]y=22-x[/tex] in equation 2 we will get,

[tex]4x+10(22-x)=100[/tex]

[tex]4x+220-10x=100[/tex]

[tex]4x-10x=100-220[/tex]

[tex]-6x=-120[/tex]

[tex]x=\frac{-120}{-6}[/tex]    

[tex]x=20[/tex]  

Therefore, there are 20 short-response questions on the exam.

Answer:

D. 20

Step-by-step explanation:

I got it right on prepworks

Answer:

239 ft³

Step-by-step explanation:

Multiply the squared radius by π:

2*2*3.14=12.56 ft².

Multiplying the height:

12.56*19≅239 ft³.

Answer:

200

Step-by-step explanation:

150/3=50 so she sorts 50 items per minute, then 50*4=200

Answer:

Number of recyclable items sort in 4 minutes by Faye = 200

Step-by-step explanation:

Given that Faye can sort 150 recyclable items in 3 minutes.

   Number of recyclable items sort in 3 minutes = 150

   [tex]\texttt{ Number of recyclable items sort in 1 minute =}\frac{150}{3}=50[/tex]

Number of recyclable items sort in 4 minutes = 4 x Number of recyclable items sort in 1 minute

Number of recyclable items sort in 4 minutes = 4 x 50 = 200

Number of recyclable items sort in 4 minutes by Faye = 200

Answer:

total earning is  $64.80

Step-by-step explanation:

Price of one work = $18.00

Payment  by owner = 1/4 of $18.00

                                 = 18/4

                                  = $4.50

Earning by tip =  20% of $18.00 =  20/100 x18 = 3.60

Total earning from one work   =   $4.50+$3.60

                                                = $ 8.10

Earning from 8 tips =  8x8.10

                                = $64.80

Answer: [tex]\bold{[\dfrac{\pi}{4},\dfrac{5\pi}{4}]}[/tex]

Step-by-step explanation:

Step 1: Create a table

x    |   5sinx + 5cosx = y

0    |       0    +     5     =   5

[tex]\frac{\pi}{2}[/tex]   |        5    +     0    =   5

π    |        0    +    -5    =  -5

[tex]\frac{3\pi}{2}[/tex]    |       -5    +     0    =  -5

2π |        0    +      5    =   5

Notice that y = 5 at 0 and [tex]\frac{\pi}{2}[/tex] , so there will be a vertex at their midpoint.  Similarly at y = -5.

Midpoint of 0 and [tex]\frac{\pi}{2}[/tex]  is [tex]\dfrac{\pi}{4}[/tex] . Midpoint of π and [tex]\frac{3\pi}{2}[/tex] is [tex]\dfrac{5\pi}{4}[/tex]

(graph is attached to confirm interval)

Answer:

[(x+3)(x+2)] /[(2x+3)(x-3)]  

Step-by-step explanation:

 [(2x²+x-6)/(x²-x-6)]/[(4x²-9)/(x²+5x+6)]

= (2x²+x-6)/(x²-x-6) × (x²+5x+6) /(4x²-9)                           Factor

= [(2x-3)(x+2)]/[(x-3)(x+2] × [(x+3)(x+2)] /[(2x+3)(2x-3)]     Cancel terms

= (2x-3)/(x-3) × [(x+3)(x+2)] /[(2x+3)(2x-3)]                        Cancel terms

= [(x+3)(x+2)] /[(2x+3)(x-3)]

[tex]\dfrac{\frac{2x^2+x-6}{x^2-x-6}}{\frac{4x^2-9}{x^2+5x+6}}=(*)\\---------------------\\2x^2+x-6=2x^2+4x-3x-6=2x(x+2)-3(x+2)=(x+2)(2x-3)\\-----------\\x^2-x-6=x^2+2x-3x-6=x(x+2)-3(x+2)=(x+2)(x-3)\\-----------\\x^2+5x+6=x^2+2x+3x+6=x(x+2)+3(x+2)=(x+2)(x+3)\\-----------\\4x^2-9=(2x)^2-3^2=(2x-3)(2x+3)\\----------------------[/tex]

[tex](*)=\dfrac{(x+2)(2x-3)}{(x+2)(x-3)}\cdot\dfrac{(x+2)(x+3)}{(2x-3)(2x+3)}=(**)\\----------------------\\(x+2)-canceled\\(2x-3)-canceled\\----------------------\\(**)=\dfrac{(x+2)(x+3)}{(x-3)(2x+3)}\\\\Answer:\ \boxed{\boxed{\dfrac{(x+2)(x+3)}{(2x+3)(x-3)}}}[/tex]

Answers: -4, 5

Step-by-step explanation:

[tex]e^{x^{2}}=e^{x}*e^{20}[/tex]

[tex]e^{x^{2}}=e^{x+20}[/tex]

x² = x + 20

x² - x - 20 = 0

(x + 4)(x - 5) = 0

x + 4 = 0      x - 5 = 0

 x = -4            x = 5

**************************************************

Answers:

Step-by-step explanation:

domain: there are no restrictions on the x-value so x = All Real Numbers

range: since the new graph has a reflection then y < 0

y-intercept is when x = 0:

horizontal asymptote: y ≠ 0 so the H.A. is y = 0

graph:  The parent graph is: y = 2ˣ

The new graph of y = -2ˣ⁻³ has the following transformations:

***************************************************************************

graph: see attachment

(0, 0) and (-1/3, 1)

(-1, ∞)

x = -1

Answer:

Correct choices are A and D.

Step-by-step explanation:

According to the table for the given function [tex]h(x),[/tex] you can write the same table for the inverse function [tex]h^{-1}(x).[/tex] With this aim change [tex]x[/tex] into [tex]h^{-1}(x)[/tex] and [tex]h(x)[/tex] into x:

[tex]\begin{array}{ccccccc}x&2&5&8&11&14&17\\h^{-1}(x)&0&1&2&3&4&5\end{array}[/tex]

Then you can see that points (5,1) and (2,0) are on the graph of the inverse function.