How long is the arc subtended by an angle of 7π/5 radians on a circle of radius 25 cm?

Answer:

Answer is

[tex]x^3-7x^2+17x-20 \\ [/tex]

Step-by-step explanation:

We need to find

[tex](x-4)(x^2-3x+5) \\ [/tex]

Using distribution rule.

[tex](x-4)(x^2-3x+5)=x^3-4x^2-3x^2+12x+5x-20\\\\(x-4)(x^2-3x+5)=x^3-7x^2+17x-20 \\ [/tex]

So the answer is

[tex]x^3-7x^2+17x-20 \\ [/tex]

Within a specific stretch spanning 5 miles, the roadway inclines approximately 0.53 miles or 2771.64 feet, rounded to the nearest hundredth of a mile.

Trigonometric principles aid in determining the elevation gained by the highway over this distance.

Given:

An angle of ascent (θ) of 6 degrees and a horizontal distance (adjacent side) of 5 miles, our objective is to ascertain the vertical distance (opposite side).

Utilizing the tangent function in trigonometry:

[tex]\[ \tan(\theta) = \frac{{\text{{opposite}}}}{{\text{{adjacent}}}} \][/tex]

[tex]\[ \tan(6^\circ) = \frac{{\text{{height}}}}{{5}} \][/tex]

The calculation for the height is:

height = 5 × tan(6°)

Plugging in the values:

height ≈ 5 × 0.1051

height ≈ 0.5255 miles

To convert this to feet (1 mile = 5280 feet):

height ≈ 0.5255 × 5280  

height ≈ 2771.64 feet

Thus, within this 5-mile segment, the roadway ascends approximately 0.53 miles or 2771.64 feet, rounded to the nearest hundredth of a mile.

Answer:

Option 1,3 and 4 are correct.

Step-by-step explanation:

Given is a quadratic equation

[tex]x^2-10x+25=0[/tex]

Marcus used quadratic formula to solve this

The correct use of formula is

[tex]\frac{-b+/\sqrt{b^2-4ac} }{2a}[/tex]

for the quadratic equation [tex]ax^2+bx+c=0[/tex]

Comparing we have a =1, b =-10: c=25

The student should have substituted -10 for b but he wrong did only 10

II option is wrong since 2 is substituted correctly

III option is right -4ac i.e. the product x 4 must have been subtracted

IV option is right since repeated root is there so only one solution

The converse of the statement 'If two lines are parallel, they do not intersect' is 'If two lines do not intersect, they are parallel', which is false. A counterexample to this converse is skew lines that do not intersect but are not parallel. Thus, we can't write both statements as a biconditional

The subject of your question is regarding conditional statements and their converses in mathematics. A conditional statement is often expressed in the form: 'If p, then q', where p is a hypothesis and q is a conclusion. The converse of a conditional statement switches the hypothesis and the conclusion, i.e., 'If q, then p'.

In the context of your question, the conditional statement given is 'If two lines are parallel, they do not intersect'. The converse of this statement is 'If two lines do not intersect, they are parallel'. However, this converse is not true. A counterexample can be two lines that do not intersect but are not parallel because they are skew lines, which exist in three dimensions and do not lie in the same plane. Thus, the statements can't be written as a biconditional as one is not a valid conditional.

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Final answer:

Erica will have 1 1/6 yards of fabric left after using 2/3 of the 3 1/2 yards she purchased to make a curtain.

Explanation:

The student's question is about how much fabric Erica will have left after using 2/3 of the 3 1/2 yards she bought to make a curtain. To solve this problem, we first need to convert the mixed number of yards of fabric to an improper fraction. We start by multiplying the whole number, 3, by the denominator of the fraction, 2, and then adding the numerator, 1. This gives us (3 × 2) + 1 equals 7, so Erica has 7/2 yards of fabric.

Next, we determine how much fabric she uses by multiplying 7/2 yards by 2/3. Doing the multiplication, (7/2) × (2/3), we can cancel out the common factor of 2 to simplify the calculation. The result is 7/3 yards of fabric used for the curtain.

To find out how much fabric is left, we subtract the used fabric from the total amount Erica originally had, which is 7/2 yards. So, we calculate 7/2 - 7/3 yards. To subtract these fractions, they need to have a common denominator. Multiplying 7/2 by 3/3 and 7/3 by 2/2 gives us equivalent fractions with a common denominator of 6. We now have (21/6) - (14/6) yards, and subtracting these gives us 7/6 yards of fabric remaining. This can also be represented as 1 1/6 yards, which is how much Erica will have left after making the curtain.

Answer with explanation:

The given equation which represents a circle having center at, (2,0) and radius =8 is,

 [tex](x - 2)^2 + y^2 = 64\\\\y^2=64 - (x-2)^2\\\\y^2=64 - (x^2-4 x +4)\\\\ y^2=64 -x^2+4 x-4\\\\y^2=60+4 x-x^2[/tex]

Result  of isolating y² in the equation below, gives

   Option A

            [tex]y^2=60+4 x-x^2[/tex]

If the repair took 5 hours, the total cost would be $250.

To find the total cost if the repair took 5 hours, we need to evaluate the function[tex]\(C(x)\) at \(x = 5\).[/tex]

Given that [tex]\(C(x) = 35x + 75\),[/tex] we substitute [tex]\(x = 5\)[/tex] into the function:

[tex]\[C(5) = 35 \times 5 + 75\]\[C(5) = 175 + 75\]\[C(5) = 250\][/tex]

So, if the repair took 5 hours, the total cost would be $250.

Complete correct question:

The function C(x) = 35x + 75 represents the labor cost (in dollars) for Bob's Auto Repair to replace our alternator, where x is the number of hours of labor. What would be the total cost if the repair took 5 hours?

Answer:

The pressure of the gas 0°C is about 699.

Step-by-step explanation:

The given table of values is

Temperature      Pressure

     10                      723

     25                     763

     40                     800

     55                     845

     80                      900

The general form of a trend line is

[tex]y=a+bx[/tex]

where, b is slope and a is y-intercept.

[tex]b=\frac{\sum_{i=1}^nx_iy_i-n\overline{x}\overline{y}}{\sum_{i=1}^nx_i^2-n\overline{x}^2}[/tex]

[tex]a=\overline{y}-b\overline{x}[/tex]

Using graphing calculator, we get

[tex]a=699.006826[/tex]

[tex]b=2.552218[/tex]

The equation of line of best bit is

[tex]y = 2.552218x + 699.006826[/tex]

where, y is pressure at x°C.

We need to find the pressure of the gas at 0°C.

Substitute x=0 in the above equation.

[tex]y = 2.552218(0) + 699.006826[/tex]

[tex]y =699.006826[/tex]

[tex]y \approx 699[/tex]

Therefore the pressure of the gas 0°C is about 699.

Answer:

Option a is correct

200 cartons is the sample size

Step-by-step explanation:

As per the statement:

For ten shipments of 1000 cartons of eggs, she examines every 50th carton to see how many cartons contain cracked eggs.

First examine how many cartons are examined per shipment.

For every 50th cartons, 1 are examined

For every 100th cartons, 2 are examined

then;

For 1000 cartons , we have 20 are examined.

Examined per shipment  = 20 cartons

We have to find how large is the sample.

Since, there are total 10 shipment

then;

For 10 shipment, we have

[tex]20 \times 10 = 200[/tex] cartons

Therefore, 200 cartons  is the sample size

Answer:

[tex]1+\sqrt{2}[/tex]

Step-by-step explanation:

We have been given a radical expression [tex]\sqrt{3+2\sqrt{2}}[/tex]. We are asked to simplify the given expression.

We will add [tex](\sqrt{2})^2-2[/tex] to our given expression as after adding and subtracting same quantity the value of our expression will be same.

[tex]\sqrt{3+2\sqrt{2}+(\sqrt{2})^2-2}[/tex]

[tex]\sqrt{3-2+2\sqrt{2}+(\sqrt{2})^2}[/tex]

[tex]\sqrt{1+2\sqrt{2}+(\sqrt{2})^2}[/tex]

Using perfect square formula [tex](a+b)^2=a^2+2ab+b^2[/tex] we can rewrite our expression as:

[tex]\sqrt{1^2+2\sqrt{2}\cdot 1+(\sqrt{2})^2}[/tex]

[tex]\sqrt{(1+\sqrt{2})^2}[/tex]

Applying radical rule [tex]\sqrt[n]{x^n} =x[/tex], we will get,

[tex](1+\sqrt{2})^{\frac{2}{2}}=1+\sqrt{2}[/tex]

Therefore, the simplified form of our given expression would be [tex]1+\sqrt{2}[/tex].

Answer:

Ryan use 4. 50 yards of cloth to make 6 backpack.

Step-by-step explanation:

Given : ryan makes 6 backpacks he uses 3/4 of cloth to make each backpack.

To find  : what is the total amount cloth ,in yards ryan use to make all 6 backpacks.

Solution : We have given that

Ryan make a backpack to use =  [tex]\frac{3}{4}[/tex] of a cloth.

Ryan make such 6 backpack = [tex]6*\frac{3}{4}[/tex]

                                                =   [tex]\frac{18}{4}[/tex] .

                                               = 4. 50 yards.

Therefore, Ryan use 4. 50 yards of cloth to make 6 backpack.

Answer:

Linear equation is V(t) = 1500 - 290t

Step-by-step explanation:

To find the linear equation representing the value of the robot we will calculate per year depreciation in the cost of the robot.

Rate of depreciation = [tex]\frac{\text{(Manufacturing cost in 2005-selling price in 2010)}}{5}[/tex]

                                 = [tex]\frac{[(1.5)(10^{6})-50000]}{5}[/tex]

                                 = [tex]\frac{(1500000-50000)}{5}[/tex]

                                 = [tex]\frac{1450000}{5}=290000[/tex]

If depreciation is represented by V(t) (in $000) then equation will be

V(t) = 1500 - 290t

Answer:

Graph of line going through (0, 8) with a slope of 1.5  represents Ariel's remaining entries

Step-by-step explanation:

Ariel wants to write 8 entries for her blog.

After 2 hours, she has 5 entries left. [tex](x_1,y_1)=(2,5)[/tex]

After 4 hours, she has 2 entries left. [tex](x_2,y_2)=(4,2)[/tex]

So, now using two point slope form:

[tex]y-y_1=m(x-x_1)[/tex] ---1

where [tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]

So , substituting the given points we get the equation that represents the given situation .

[tex]m = \frac{2-5}{4-2}[/tex]

[tex]m = \frac{-3}{2}[/tex]

[tex]m = -1.5[/tex]

Now,

[tex]y-5 = -1.5(x-2)[/tex]

[tex]y-5 = -1.5x+3[/tex]

Thus the slope of the given situation is 1.5

Now at x = 0

[tex]y-5 = -1.5*0+3[/tex]

[tex]y=8[/tex]

So, at 0 hour 8 entries left .

So, graph of line going through (0, 8) with a slope of 1.5  represents Ariel's remaining entries

Answer:

it 2 units

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

When performing certain statistical calculations, finding roots, or working with powers, calculators or computers are necessary for the calculations; otherwise, more traditional methods will be sufficient.