In a neutralization reaction, equivalent volumes of solutions with equal normality will neutralize each other. Thus, 53 mL of 0.0050 N KOH will neutralize 53 mL of 0.0050 N H2SO4.
Explanation:To answer the question 'How many milliliters of 0.0050 N KOH are required to neutralize 53 mL of 0.0050 N H2SO4 ?', we must understand the concept of neutralization in the context of acid-base reactions. Neutralization occurs when an acid reacts with a base to produce water and a salt, with no excess of hydrogen or hydroxide ions left in the solution.
In this case, the reaction is between KOH (Potassium Hydroxide, a base) and H2SO4 (Sulfuric Acid, an acid). As both solutions are of the same normality (0.0050 N), they will neutralize each other in equal volumes. Hence, 53 mL of 0.0050 N KOH are required to neutralize 53 mL of 0.0050 N H2SO4.
This concept ties into titration, a technique where a solution of known concentration (in this case, KOH) is used to determine the concentration of an unknown solution (H2SO4). It's important to note that this is a simplified example as it assumes 1:1 stoichiometry. For other reactions, it might be necessary to take into account the stoichiometric coefficients in the balanced chemical equation.
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How to determine the amount of electrons transferred in a redox reaction
The amount of electrons transferred depends on how many electrons an element gains/loses. Metals normally lose electrons and nonmetals gain electrons to attain a total of 8 electrons.
How many moles are equal to 89.23 g of calcium oxide
the molecular formula of calcium oxide - CaO
The molar mass of CaO - 40 + 16 = 56 g/mol
Which means that 1 mol weighs 56 g
Therefore 56 g of CaO is - 1 mol
Then 89.23 g is equivalent to - 1/56 x 89.23 = 1.6 mol of CaO.
Final answer:
To find the number of moles in 89.23 g of calcium oxide, divide the mass by the molar mass of CaO, which is 56.0 g/mol, resulting in approximately 1.5934 moles.
Explanation:
To calculate the number of moles equivalent to 89.23 grams of calcium oxide (CaO), one must use the molar mass of CaO as a conversion factor. The molar mass of CaO, where calcium (Ca) has an atomic mass of 40.0 u and oxygen (O) has an atomic mass of 16.0 u, is 40.0 g/mol + 16.0 g/mol = 56.0 g/mol.
The number of moles of CaO can be determined by dividing the given mass by the molar mass:
Number of moles of CaO = (mass of CaO) / (molar mass of CaO)
= 89.23 g / 56.0 g/mol
= 1.5934 moles
Therefore, 89.23 grams of calcium oxide are equal to approximately 1.5934 moles of CaO.
Which of the following statements about Dalton’s atomic theory is true?
Dalton’s theory recognized that all matter is composed of atoms.
Dalton’s theory recognized the existence of smaller particles within atoms.
Dalton’s theory did not account for the similarities of atoms of the same element.
Dalton’s theory stated that atoms could not combine with each other.
We have to get the true statement about Dalton's atomic theory.
The true statement is: Dalton’s theory recognized that all matter is composed of atoms.
According to Dalton's atomic theory, all matter is made of atoms and atoms are indivisible and not destructible. So, the statement -Dalton’s theory recognized that all matter is composed of atoms- is true whereas the statement - Dalton’s theory recognized the existence of smaller particles within atoms is false.
As per Dalton's theory, all atoms of a given elements are identical in mass and properties, so the statement -Dalton’s theory did not account for the similarities of atoms of the same element is false.
Also, compounds are formed by a combination of two or more different kinds of atoms hence the statement - Dalton’s theory stated that atoms could not combine with each other is false.
Answer:
evidence that some kinds of matter are made up of waves instead of particles
observations that cannot be explained by the theory
Explanation: these ones are right trust