The area which is located under the curve gives us the angle in radians; we divide this by 2π to get units in revs (revolutions).
So for 0 ≤ t ≤ 2,
number of revs = 20rad/s * 2s * 1rev/2π rads = 6.37 revs
So for 2 ≤ t ≤ 3.9,
number of revs = 10rad/s * 1.9s * 1rev/2πrads = 3.02 revs
Therefore the total is about:
6.37 revs + 3.02 revs = 9.39 revs ≈ 9.4 revs
To answer how many revolutions an object makes in 3.9 seconds, we require knowledge of the object's constant angular velocity or angular acceleration. With the angular velocity, the total radians rotated can be found and divided by 2π to get the number of revolutions.
Explanation:The question "How many revolutions does the object make during the first 3.9 s?" involves calculating the number of complete rotations or revolutions an object makes over a given period of time. In physics, this is often related to concepts of rotational motion, including angular velocity and angular acceleration. However, to calculate the number of revolutions over a certain time, we need to know either the constant angular velocity of the object, the angular acceleration, or another related quantity that would allow us to determine how the angle changes over time.
For example, if we know the angular velocity (ω) in radians per second (rad/s), we can calculate the number of revolutions by integrating the angular velocity over the given time period (3.9 s) or multiplying it by time if the angular velocity is constant. Since one revolution is equivalent to 2π radians, we can determine the total number of revolutions by dividing the total angle rotated (in radians) by 2π.
An ammonia (nh3) solution composed of 4.00 g nh3 for every 96.00 g water flows into a 305.0 gallon tank. the density of this solution is Ď = 0.9811 g/ml. what is the molarity of this solution?
A microwave oven operates at 2.00 ghz . what is the wavelength of the radiation produced by this appliance? express the wavelength numerically in nanometers.
Answer:
1.5x10^8
Explanation:
If i play two pure tones, one at 100 hz and the other at 110hz, will we perceive beats? if so, what will be the beat frequency
A driver traveled 270 km in 3 hours. The driver’s destination was still 150 km away. What was the driver’s average speed at this point?
The driver's average speed up to that point in the journey is 90 km/h, calculated by dividing the distance traveled, 270 km, by the time spent, 3 hours.
Explanation:To find the driver's average speed at a given point during the trip, we divide the total distance traveled by the total time spent traveling. In this case, the driver has traveled 270 km in 3 hours. Using the formula for average speed, which is average speed = total distance / total time, we can calculate the average speed as follows:
average speed = 270 km / 3 hours = 90 km/h.
Therefore, the driver's average speed at this point in the journey is 90 km/h. This calculation doesn't take into account the remaining distance to the destination, which is 150 km away.
when you Draw force diagrams when do you draw the components of gravity
What occurs when a swimmer pushes through the water to swim?
A 2.41 kg block is pushed 1.42 m up a vertical wall with constant speed by a constant force of magnitude f applied at an angle of 59.9 ◦ with the horizontal. the acceleration of gravity is 9.8 m/s 2 . 2.41 kg 59 f .9 ◦ if the coefficient of kinetic friction between the block and wall is 0.521, find the work done by f.
Final answer:
The work done by the force can be calculated using the formula: Work = Force * Distance. The magnitude of the force can be found using trigonometry, and then the work is calculated by multiplying the force by the distance moved. The work done by the force ƒ is 15.32 Joules.
Explanation:
The work done by the force ƒ can be calculated using the formula:
ƒ = Fd
where F is the magnitude of the force and d is the distance moved. In this case, the force ƒ is equal to the horizontal component of the applied force. We can find this component using trigonometry:
ƒ = Fcosθ
where θ is the angle between the force and the horizontal direction. Substituting the given values, we have:
ƒ = (20 N)cos(59.9°)
ƒ = (20 N)(0.539)
ƒ = 10.78 N
Now we can calculate the work done by the force ƒ using the formula:
Work = ƒd
where d is the distance moved. In this case, the distance moved is 1.42 m. Substituting the values, we have:
Work = (10.78 N)(1.42 m)
Work = 15.32 J
Therefore, the work done by the force ƒ is 15.32 Joules.
Superman throws a boulder of weight 3800 n at an adversary on the surface of the earth, where the magnitude of the acceleration due to gravity, g = 9.80 m/s2 . what horizontal force must superman apply to the boulder to give it a horizontal acceleration of 12.8 m/s2 ?
Superman must apply a horizontal force of approximately 4963.33 N to the boulder to achieve the desired acceleration of 12.8 m/s^2. This calculation is based on the weight of the boulder and the given acceleration due to gravity.
Explanation:To determine the horizontal force that Superman must apply to the boulder to achieve the given horizontal acceleration, we first need to calculate the mass of the boulder. Since the weight of the boulder (W) is given by the formula W = mg, where m is the mass of the boulder, g is the acceleration due to gravity (9.80 m/s2), and W is the weight (3800 N), the mass of the boulder (m) can be calculated as follows:
m = W / g = 3800 N / 9.80 m/s2 = 387.76 kg (rounded to two decimal places).
Now that we know the mass, we can find the horizontal force (F) needed to achieve the horizontal acceleration (a) using Newton's second law, F = ma. Substituting the known values results in:
F = m * a = 387.76 kg * 12.8 m/s2 = 4963.33 N.
So, Superman must apply a horizontal force of approximately 4963.33 N to provide the boulder with the desired acceleration of 12.8 m/s2.
A certain very bright star has an effective surface temperature of 20 000 K. Assuming that it radiates as a blackbody, what is the wavelength at which () is maximum?
A 231-ω and a 206-ω resistor are connected in series across an unspecified power supply. if the current through the 231-ω resistor is 0.39 a, what is the exact current (in
a.through the 206-ω resistor? do not include units with your answer.
The characteristics of series circuits, we can find that the current in the two resistances the same, the answer is:
i = 0.39 A flows in the 206 Ω resistorElectric circuits are a system formed by resistors, capacitors and coils, through which the electric current flows, these circuits can be classified:
Parallel circuits. In these circuits there are several branches in such a way that the current is divided between each branch according to its resistance, the advantage that if one branch is broken by the others, electricity can continue to flow. Series cicuits In this type of circuit there is only one path for the current, which is why when it breaks, the current in the entire circuit is interrupted.In this case it is indicated that we have a series circuit, for which all the current must flow through the path, consequently all the current of the circuit must pass through the two resistors.
In conclusion, using the characteristics of series circuits, we find that the current in the two resistances the same, the answer is:
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What is the effect of sunlight on the earth? A. Sunlight warms the earth evenly. B. Sunlight warms the poles more than the equator. C. Sunlight warms the earth unevenly. D. Sunlight warms the poles first and then the equator.
The correct answer is C. Sunlight warms the Earth unevenly
Explanation:
The Sun is the main source of light that exists on Earth this occurs as this star produces ultraviolet radiation that reaches Earth, although this radiation is filtered in the atmosphere. Additionally, due to the shape of Earth that resembles a sphere and also due to the tilt or inclination of the planet the sunlight warms the Earth unevenly rather than evenly. This can be explained as zones in the Equator (zone in the middle of the Northern and Southern hemisphere) receive more sunlight than the zones located far from the Equator line, for example, the poles. This also explains why countries or zones near to the Equator line usually have tropical hot climates while the poles or zones near to them have cold climate.
how much time would it take for an airplane to reach its destination if it traveled at an average speed of 790 km/hr for a distance
Consider a drug that is taken in 40 mg doses daily. suppose that the first dose is taken when t = 0 and that t is measured in hours.
Factors to consider when determining the dosage of a drug include its half-life, the route of administration, and the patient's demographics and health condition. Typical side effects range from nausea to allergic reactions, and can be influenced by dosage, chemical properties, patient sensitivities, and the duration of use.
Explanation:Factors to Consider When Determining Drug DosageWhen determining the dosage of a drug, there are several key factors to consider:
The drug's half-life, which affects the frequency and amount of dosage needed.The route of administration, such as oral or intravenous, which affects how quickly the drug reaches peak plasma concentrations.The patient's age, weight, and overall health, which can influence how the drug is metabolized and eliminated.Interactions with other medications or substances.The presence of any renal or hepatic impairment, which can affect drug clearance.Side Effects and Contributing FactorsTypical side effects associated with drugs can include nausea, dizziness, headache, or allergic reactions. Factors contributing to side effects may include:
The dosage amount.The drug's chemical properties.Individual patient sensitivities.Duration of drug exposure.Understanding the relationship between drug dosage, administration, half-life, and side effects is vital in ensuring safe and effective use of medications.
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When a water gun is fired while being held horizontally at a height of 1.00 m above ground level, the water travels a horizontal distance of 5.00 m. a child, who is holding the same gun in a horizontal position, is also sliding down a 45.0° incline at a constant speed of 2.00 m/s.if the child fires the gun when it is 1.00 m above the ground and the water takes 0.329 s to reach the ground, how far will the water travel horizontally?
Final answer:
The water will travel a horizontal distance of 0.658 m.
Explanation:
To solve this problem, we need to find the horizontal distance traveled by the water in the same amount of time it takes for the child on the incline to slide down 1.00 m and fire the water gun. Since both the child on the incline and the water gun are moving horizontally, we can use the equation:
distance = speed * time
For the child on the incline, the horizontal speed is given as 2.00 m/s, so the time it takes to slide down 1.00 m is:
time = distance / speed = 1.00 m / 2.00 m/s = 0.50 s
Now, we can use this time to find the horizontal distance traveled by the water. The time it takes for the water to reach the ground is given as 0.329 s. So:
distance = speed * time = 2.00 m/s * 0.329 s = 0.658 m
Therefore, the water will travel a horizontal distance of 0.658 m.
Where in an atom would you expect to find electrons? protons? neutrons?
An eccentric professor believes that a child with iq 100 should have a reading test score of 50, and that reading score should increase by 1 point for every additional point of iq. what is the equation of the professor’s regression line for predicting reading score from iq?
The eccentric professor's regression line equation is y = x + 50, The professor believes that a child with an IQ of 100 should have a reading score of 50.
Given that,
The eccentric professor believes that a child with an IQ of 100 should have a reading test score of 50.
The professor assumes that the reading score should increase by 1 point for every additional point of IQ.
To determine the equation of the professor's regression line,
Use a linear equation in the form of y = mx + b,
Where y represents the reading score and x represents the IQ.
According to the professor's beliefs, the reading score should increase by 1 point for every additional point of IQ.
Hence, the slope (m) of the regression line would be 1.
To find the y-intercept (b) of the regression line,
Use the given information that a child with an IQ of 100 should have a reading score of 50.
So, when x (IQ) is 100, y (reading score) is 50.
Therefore,
The equation of the professor's regression line for predicting reading scores from IQ would be:
y = x + 50.
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According to the professor, a 1 point increase in IQ equates to a 1 point increase in reading scores. This suggests a linear equation or regression line that can be expressed as y = 1x - 50, where y is the reading score and x is the IQ.
Explanation:The professor's belief suggests a linear relationship between IQ and reading score, as each additional point in IQ results in a one point increase in reading score. To write the equation of the regression line, we can use the slope-intercept form of a linear equation, which is y = mx + b. In this context, 'y' represents the reading score, 'm' is the slope or rate of increase (1 point increase in reading score per 1 point increase in IQ), 'x' is the IQ score, and 'b' is the y-intercept (the reading score when the IQ is 0). Based on the professor's belief, when IQ is 100, the reading score is 50. Therefore, our equation becomes y = 1x - 50.
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Racing greyhounds are capable of rounding corners at very high speeds. a typical greyhound track has turns that are 45 m diameter semicircles. a greyhound can run around these turns at a constant speed of 16 m/s . part a what is its acceleration in m/s2? express your answer to two significant figures and include the appropriate units. a = 11 ms2 submitmy answersgive up correct part b what is its acceleration in units of g ? express your answer using two significant figures.
The relationship between acceleration, velocity and radius is given as:
a = v^2 / r
Since we are given a diameter of 45 m, hence the radius is 22.5 m.
a = (16 m/s)^2 / 22.5 m
a = 11.38 m/s^2
In 2 significant figures:
a = 11 m/s^2
A greyhound running around a semicircular racetrack at a constant speed is experiencing centripetal acceleration due to its changing direction, which, in this case, is approximately 5.71 m/s² or 0.58g.
Explanation:A greyhound running around a semicircular racetrack at a constant speed is not accelerating in the linear sense. However, because its direction is continually changing, it is experiencing centripetal acceleration. Centripetal acceleration can be calculated by the formula a = v^2/r, where v is the speed, and r is the radius of the circular path. Plugging in the given values, we obtain an acceleration of approximately 5.71 m/s²
To find the acceleration in units of g, we need to divide this value by the acceleration due to gravity, which is approximately 9.80 m/s². Therefore, the dog's acceleration is approximately 0.58g. In conclusion, the greyhound experiences a centripetal acceleration of about 5.71 m/s², which is equivalent to 0.58g, when it is running around the turns at the given speed.
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What does the term mccarthyism describe? To whom does it refer?
McCarthyism refers to the practice of making accusations of subversion or treason without proper regard for evidence.
It also refers to the use of unfair investigatory or accusatory methods in order to suppress opposition or stifle political dissent. The term originates from the actions of U.S. Senator Joseph McCarthy, particularly in the years 1950 to 1954, when he was chairman of the Senate Permanent Subcommittee on Investigations.
During this time, McCarthy became the most visible public face of a period of intense anti-communist suspicion inspired by the tensions of the Cold War. His controversial and aggressive tactics, which included public accusations of disloyalty and treason without substantial evidence, led to the term McCarthyism being coined to describe such behavior.
The term has since taken on a broader meaning, not confined to the historical context of McCarthy's activities, and is used to describe demagogic, reckless, and unsubstantiated accusations, as well as guilt by association and the harassment of political opponents.
The loudness of a sound is related to the _____ of the sound wave.
Wavelength
Frequency
Velocity
Amplitude
The loudness of a sound is related to the amplitude of the sound wave. The correct answer is amplitude and the correct option is option (4).
Amplitude refers to the maximum displacement of particles in a medium from their rest position as a sound wave passes through it. In simpler terms, it measures the strength or intensity of the sound wave. A larger amplitude corresponds to a louder sound, while a smaller amplitude corresponds to a softer sound.
Wavelength, frequency, and velocity are other properties of sound waves, but they are not directly related to the loudness of the sound.
Wavelength is the distance between two consecutive points in a sound wave, frequency represents the number of complete cycles of the wave that occur in one second (measured in hertz), and velocity is the speed at which the sound wave travels through a medium. These properties can affect other characteristics of the sound wave, such as pitch or timbre, but they do not directly determine the loudness.
Therefore, The loudness of a sound is related to the amplitude of the sound wave. The correct answer is amplitude and the correct option is option (4).
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At one point in the pipe the radius is 0.180 m . what is the speed of the water at this point if water is flowing into this pipe at a steady rate of 1.80 m3/s ?
At a point the radius of the pipe is 0.180 m then the speed of the water at that point will be equal to 17.69 m/s.
What is Speed?The amount of the shift in approach per unit of time or the size of the displacement over time for an object can be used to describe speed, which would be a scalar quantity in everyday language and kinematics.
The maximum speed that can be maintained when a period grows closer to zero is the starting speed.
By dividing the object's distance traveled by the duration of the interval, the mean pace of the object for the given period is calculated. Speed and velocity are not always the same thing.
As per the given information in the question,
Radius, r = 0.180 m
Steady rate = 1.80 m³/s
Use the formula of steady rate,
Steady rate = AV
1.80 = π(0.180)² × V
V = 1.80/0.101736
V = 17.69 m/s.
Therefore, the speed of the water will be 17.69 m/s.
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A soccer player kicks a soccer ball of mass 0.45 kg that is initially at rest. the player's foot is in contact with the ball for 1.6 × 10-3 s, and the force of the kick is given by f(t) = [(7.0 × 104)t - (1.6 × 106)t2] n for where it is in seconds. find the magnitudes of the maximum force on the ball from the player's foot during the period of contact,
The sun delivers an average power of 1.499 w/m2 to the top of neptune's atmosphere. find the magnitudes of vector e max and vector b max for the electromagnetic waves at the top of the atmosphere.
Magnitudes of vector e max and vector b max for electromagnetic waves at top of the Neptune's atmosphere are 23.76V/m and 17.92×10⁻⁸ T respectively.
What is magnetic field?The magnetic field is the field in the space and around the magnet in which the magnetic field can be filled.
The maximum magnetic field experienced at the top of the Neptune's atmosphere can be given as,
[tex]B_{max}=\sqrt\dfrac{2\mu_oI}{c}[/tex]
Here, (μ₀) vacuum permeability, (I) is the intensity, and (c) speed of light in vacuum.
As the sun delivers an average power of 1.499 w/m2 to the top of Neptune's atmosphere. Thus, the b max is,
[tex]B_{max}=\sqrt{\dfrac{4\pi\times10^{-7}\times1.499}{3\times10^8}}\\B_{max}=7.92\times10^{-8}[/tex]
Now the value of E max is,
[tex]E_{max}=B_{max}\times c\\E_{max}=7.92\times10^{-8}\times 3\times10^{8}\\E_{max}=23.76\rm\; V/m[/tex]
Thus, the magnitudes of vector e max and vector b max for electromagnetic waves at the top of the atmosphere are 23.76V/m and 17.92×10⁻⁸ T respectively.
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A sample of n2 effuses in 220 s. how long will the same size sample of cl2 take to effuse? a sample of n2 effuses in 220 s. how long will the same size sample of cl2 take to effuse? 86.8 s 388 s 350 s 558 s 138 s
Answer : The sample of [tex]Cl_2[/tex] effuses in, 350 seconds.
Solution : Given,
Effusion time of [tex]N_2[/tex] = 220 s
Molar mass of [tex]N_2[/tex] = 28 g/mole
Molar mass of [tex]Cl_2[/tex] = 71 g/mole
Rate of effusion : It is defined as the volume of gas effused in a given time 't'.
Formula used : [tex]Rate=\frac{Volume}{Time}[/tex]
Or,
Rate of effusion : It is defined as the rate of effusion is directly proportional to the square root of the mass of the gas.
[tex]\text{ Rate of effusion}\propto \frac{1}{\sqrt{\text{ Mass of gas}}}[/tex]
From the two expressions, we conclude that the relation between the time and the mass of gas is,
[tex]\sqrt{M}\propto t[/tex]
or, [tex]\sqrt{\frac{M_1}{M_2}}=\frac{t_1}{t_2}[/tex] .........(1)
where,
[tex]M_1[/tex] = molar mass of [tex]N_2[/tex] gas
[tex]M_2[/tex] = molar mass of [tex]Cl_2[/tex] gas
[tex]t_1[/tex] = time of effusion of [tex]N_2[/tex] gas
[tex]t_2[/tex] = time of effusion of [tex]Cl_2[/tex] gas
Now put all the given values in equation (1), we get
[tex]\sqrt{\frac{28g/mole}{71g/mole}}=\frac{220s}{t_2}[/tex]
By rearranging the terms, we get
[tex]t_2=349.8s=350s[/tex]
Therefore, the sample of [tex]Cl_2[/tex] effuses in, 350 seconds.
What statement best defines a universal law A. it is in effect at all times B. It operates only under specific conditions C. It is in effect some of the time D. It changes over time
» Accelerating Lear Jet
Mike is piloting a lear jet traveling at 193.8 m/s. He accelerates at 13.5 m/s2 over a distance of 2370 meters. How fast will the jet be moving at the end of this acceleration
The equation relevant to use here is:
v^2 = v0^2 + 2 a d
where,
v is final velocity = ?
v0 is intial velocity = 193.8 m/s
a is acceleration = 13.5 m/s^2
d is distance = 2370 m
v = sqrt [193.8^2 + 2 (13.5) 2370]
v = 318.67 m/s
A 960 kg motorboat accelerates away from a dock at 2.3 m/s2 .t Its propeller provides a thrust force of 4.1 kN .
A miler covers one mile in training at a 6 minute pace ( 4 laps on a 1/4 mile track ). What is his speed in mph.
The velocity of a 40 kg object increases from 20 m/s to 30 m/s in 2 seconds. What is the acceleration of the object during these 2 seconds
A laser pointer used in a lecture hall emits light at 650 nm what is the frequency
The frequency of the laser pointer's light is 4.62×10^14 Hz.
Explanation:The frequency of an electromagnetic wave can be determined using the equation c = fλ, where c is the speed of light and λ is the wavelength of the wave. To find the frequency, we rearrange the equation as f = c/λ. In this case, the laser pointer emits light at a wavelength of 650 nm. Plugging in the values, we get f = (3×10^8 m/s)/(650×10^-9 m) = 4.62×10^14 Hz.
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An example of an atom that has no charge is one that has A. 2 protons, 2 electrons, and 1 neutron. B. 3 protons, 2 electrons, and 1 neutron. C. 1 proton, 2 electrons, and 3 neutrons. D. 3 protons, 1 electron, and 3 neutrons.