Answer:
360 kJ
Explanation:
Energy = power × time
E = 600 J/s × (10 min × 60 s/min)
E = 360,000 J
E = 360 kJ
Using a 600 watt stove and oven for 10 minutes results in an energy consumption of 0.1 kilowatt-hours (kWh),
Using the formula:
Energy (in watt-minutes) = Power (in watts)× Time (in minutes)
For a 600 watt stove:
Power = 600 wattsTime = 10 minutesEnergy = 600 watts× 10 minutes
= 6000 watt-minutes
However, energy consumption is usually expressed in kilowatt-hours (kWh). To convert watt-minutes to kilowatt-hours, use the following conversion:
1 watt-minute = 1/60,000 kilowatt-hour
Therefore:
Energy = 6000 watt-minutes× (1/60,000) kWh/watt-minute
= 0.1 kWh
The 600 watt stove and oven can do 0.1 kWh of work in 10 minutes.
Which of the following is an example of matter?
(A) materials that make up the stars
(B) air
(C) metals, gems and minerals
(D) all of the above
Answer:
(D) all of the above
Explanation:
All of the choices describe matter.
an object travels a distance of 6 m in 2 seconds if average speed is found using the equation distance traveled/ elapsed time what is the average speed of the object be sure to include units in your answer
Answer:
3 m/s
Explanation:
average speed = distance traveled / total time taken
= 6m/ 2s
= 3 m/s
Scientists measure the time between the arrival of an earthquake's _______ and _______ waves to help determine the distance between the recording seismograph and the earthquake epicenter.
Scientists measure the time between the arrival of an earthquake's __P____ and ___S____ waves to help determine the distance between the recording seismograph and the earthquake epicenter.
Explanation:
P- (compressional) and S- (shear) waves produced in earthquakes travel at different speeds. P waves are faster than S waves and hence will be detected first by a seismograph after an earthquake. The further away a seismograph is from the epicenter of an earthquake, the longer the time difference between the two (2) waves will be.
Using several, at least 3, seismographs located at different geoghraphical locations and detecting earthquakes, geologists can extrapolate the epicenter of an earthquake using the time differences in arrivals of the two waves in each of the seismographs, using the mathematics of triangulation.
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The time between the arrival of P waves and S waves, recorded by seismographs, is used to determine the distance to an earthquake's epicenter, with the precision being affected by the accuracy of wave speed and arrival time measurements.
Explanation:Scientists gauge the distance to an earthquake's epicenter by measuring the time between the arrival of an earthquake's P waves and S waves. Seismographs can record these waves with a precision of 0.100 seconds. Given that P waves travel at 7.20 km/s and S waves travel at 4.00 km/s, the time difference recorded on seismograms allows scientists to calculate the distance to an epicenter with considerable accuracy. However, the precision of this distance measurement can be limited by the exactitude of the wave speed measurements and the timing of their arrivals.
Furthermore, the tracking of seismic waves can also be significant for monitoring underground nuclear tests. If there is uncertainty in the speeds of S and P waves, or in the measurement of their arrival times, this poses a limitation in accurately determining the source of seismic energy, which could hinder detection capabilities for such underground activities.
You apply a horizontal force of 200N against a 50kg couch. The force of friction between the couch and the floor is 180N. If the couch is pushed 2 metres, the kinetic energy gained by the couch is: a) 0 b) 40 J c) 100 J d) 360 J e) 400 J
Answer:
The kinetic energy gained is 40[J]
Explanation:
This is a problem that applies the work and energy conservation. We must analyze the initial and final positions as well as the forces that act on the couch during displacement.
The working and energy conservation theorem says:
[tex]E_{k1} + W_{1-2}= E_{k2}[/tex]
The above equation tells us that kinetic energy plus the work done to move an object from one position to another will be equal to kinetic energy in the last position.
The kinetic energy in the initial position is zero since the couch is at rest, Ek1=0
The work will be given by the force that drives the couch multiplied by the distance, and the friction force that acts in the opposite direction to the displacement.
[tex]0+(200-180)*2= Ek2\\Ek2=20*2= 40 [J][/tex]
A green dot in the middle of 4 concentric circles. The first away from the green dot is labeled n = 1. The second circle away from the green dot is labeled n = 2. The third circle away from the green dot is labeled n = 3 and the last is labeled n = 4. There is an arrow from n = 4 to n = 1 labeled A. There is an arrow from n = 3 to n = 2 labeled B. There is an arrow from n = 3 to n = 1 labeled C. There is an arrow from n = 2 to n = 1 labeled D.
Which transition by an electron will release the greatest amount of energy?
A
B
C
D
Answer:a??
Explanation:
Transition (A) from n=4 to n=1 by an electron will release the greatest amount of energy.
What is energy levels of energy?The fixed distances from an atom's nucleus where electrons may be found are referred to as energy levels (also known as electron shells). In an atom, the small, positively charged nucleus is surrounded by smaller, negatively charged electrons.
Energy levels resemble the rungs of a ladder in several ways. You cannot stand between the steps, only on one or the other. In the same way, electrons. They are able to occupy energy levels, but not the area between them.
In the given question there have four transitions of electron:
from n = 4 to n = 1 labeled A. from n = 3 to n = 2 labeled B. from n = 3 to n = 1 labeled Cfrom n = 2 to n = 1 labeled D.As for transition A; Δn = 4 -1 = 3 is the highest among the four transitions of electron, transition from n=4 to n=1 by an electron will release the greatest amount of energy.
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I got part c right but idk why the other parts are wrong HELP!
a) The impulse is 76.5 Ns
b) The average force is 546.4 N
c) The final speed is 31.5 m/s
Explanation:
a)
The impulse exerted on an object is defined as
[tex]J=\int F\Delta t[/tex]
where
F is the magnitude of the force exerted on the object
[tex]\Delta t[/tex] is the time interval during which the force is applied
If we consider a graph of the force applied vs time, it follows that the impulse exerted is equal to the area under the graph.
Therefore, in this problem, we can calculate the impulse by computing the area under the graph. We have a trapezium, whose bases are
[tex]B=0.14-0 = 0.14s\\b=8-5=3s[/tex]
and whose height is
[tex]h=900 N[/tex]
Therefore, the area (and the impulse) is
[tex]J=\frac{(B+b)h}{2}=\frac{(0.14+0.03)(900)}{2}=76.5 Ns[/tex]
b)
In this problem, the force applied is not constant. However, we can rewrite the impulse also as
[tex]J=F_{avg} \Delta t[/tex]
where
[tex]F_{avg}[/tex] is the average force exerted during the whole time [tex]\Delta t[/tex]
In this problem we have
J = 76.5 Ns is the impulse (calculated in part a)
[tex]\Delta t = 0.14 s[/tex] is the time interval
Solving for the average force, we find
[tex]\Delta t = \frac{J}{F_{avg}}=\frac{76.5}{0.14}=546.4 N[/tex]
c)
According to the impulse theorem, the impulse exerted on an object is equal to the change in momentum of the object:
[tex]J=\Delta p = m(v-u)[/tex]
where
m is the mass of the object
v is the final velocity
u is the initial velocity
In this problem, we have
J = 76.5 Ns
m = 3.0 kg is the mass
u = 6.0 m/s is the initial velocity
Solving for v, we find the final velocity (and speed):
[tex]v=u+\frac{J}{m}=6.0+\frac{76.5}{3}=31.5 m/s[/tex]
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If for every 2 atoms of Chlorine-35 there are 5 atoms of Chlorine-38. What is the average mass?
Answer:
37.1
Explanation:
mass of 2 atoms of chlorine-35 = 2× 35 = 70
mass of 5 atoms of chlorine-38 = 5 × 38 = 190
average mass = total mass / total number of atoms
= (70 +190) / (2 +5)
= 260 / 7
= 37.143
= 37.1
Final answer:
The average mass of chlorine-35 and chlorine-38 can be calculated using their respective atomic masses and percent abundances. The average mass of chlorine is 35.46 amu.
Explanation:
The average mass of chlorine can be calculated using the information provided. Chlorine-35 has an atomic mass of 34.969 amu and a percent abundance of 75.77%. Chlorine-38 has an atomic mass of 36.966 amu and a percent abundance of 24.23%. To calculate the average mass, we multiply the fraction of chlorine-35 (0.7577) by its mass, and add it to the fraction of chlorine-38 (0.2423) multiplied by its mass.
Therefore, the average mass of chlorine is: (0.7577 * 34.969) + (0.2423 * 36.966) = 35.46 amu.
Match the vocabulary terms to their definitions.
1. distance a measurement that has both magnitude and direction
2. velocity the net change in position of an object
3. displacement the rate and direction at which an object moves
4. vector the length along a path between two points
5. speed measure of the rate at which an object changes position
6. momentum the mass of an object multiplied by its veloci
Answer:
Distance- The length along a path between two points .
Velocity- The rate and direction at which an object moves .
Displacement- The net change in position of an object .
Vector- A measurement that has both magnitude and direction .
Speed- Measure of the rate at which an object changes position .
Momentum- The mass of an object multiplied by its velocity.
Explanation:
Vector: A physical quantity having both magnitude and direction is called Vector quantity. Example: Displacement, Velocity, Acceleration, Force etc.
On the other hand , quantity having only magnitude is called Scalar. Example: Distance, Speed, Time, Current etc.
Distance: The totle length of path traversed by a body in certain time is called distance. It is scalar quantity as it has only magnitude. SI unit of distance is meter.
Displacement: It is defined as change in position of a body in given period of time. Actually it is the distance between initial and final position along with given direction. So it is vector quantity. SI unit is meter.
Speed: The rate at which distance is traveled with respect to time is called speed.It is scalar quantity. SI unit is meter/second.
[tex]Speed=\frac{Distance}{Time}[/tex]
Velocity: It can be defined as rate of change in position or displacement with respect to time.It is vector quantity. SI unit is meter/second.
[tex]Velocity=\frac{Displacement}{Time}[/tex]
Momentum: The amount of motion contain in a body is the momentum. It is defined as product of mass and velocity. It is vector quantity. SI unit is kg.meter/second
Momentum=Mass×Velocity
Answer: The answer above is correct! I got 100% :))
Explanation:
Two objects gravitationally attract with a force of 10N. If the distance between the two objects center is doubled, then the new force is
Answer:
20N
Explanation:
10×2
Answer:
Answer:
20N
Explanation:
10×2
Add these measurements, using significant digit rules:
1.0090 cm + 0.02 cm = cm
Answer: " 1.03 " .
____________________________________
Explanation:
_____________________________________
When we add "measured" or "obtained values" ; the rules for "signficant digits" (also known as "significant figures" ; or "sig figs") are different from the rules we use when we multiply "measured or obtained values".
We are given 2 (two) "measured or obtained values" ; and we are asked to add these values together using the "significant digit rules.
In this case, we add up the "sum total value" of all the values—Not taking into account the number of significant figures. Then, we take that "sum value" ; and we round that value to the number of "decimal places" that corresponds to the the number of decimals places in the "measured/obtained valued" that occurs in the value using to calculate the sum —the one that also happens to have the least number of significant digits among all the values used to calculate the "sum total".
As such:
_____________________________________
1.0090 cm
+ 0.02 cm
________________
1.0290 cm.
→ Now, there were two (2) values used to calculate the "sum total" ;
1) 1.0090 cm ; which has 5 (five) significant digits.
2) 0.02 cm ; which as 1 (one) significant digits.
_____________________________________
So, " 1" is less than "5" ; so: " 0.02" is the value within the calculations used to find the sum total — that has the "least" number of significant digits.
→ " 0.02 " ; happens to have 2 (two) decimal spaces.
_____________________________________
So, we take the "sum total" :
→ " 1.0290 cm " ;
→ And round this number to: " 2 (two) decimal places:
→ 1.029... ;
→ If the number after the second decimal place is from "1 to 4" ; we round down. If the number after the second decimal place is
from "5 and 9" ; to round up. Since the third decimal place is: "9" ;
[Note: " 1.029.." ; is between "5 to 9" } ; we round up:
→ The answer is: " 1.03 " .
_____________________________________
Hope this is helpful to you!
Wishing you the best!
_____________________________________
Object A attracts object B with a gravitational force of 10 newtons from a given distance. If the distance between the two objects is doubled,
what is the new force of attraction between them?
A. 2.5 newtons
B. 5newtons
C. 20 newtons
D. 100 newtons
Answer:
20N option C
Explanation:
10× 2
7. Mildred was driving 12 m/s and slowed
to 8 m/s in three seconds. Mildred's
acceleration can be calculated as:
0 0
ID 111111
0 0
1223
33
Answer:
The acceleration of Mildred is, 1.33 m/s²
Explanation:
Given data,
The initial velocity of Mildred, u = 12 m/s
The final velocity of Mildred, v = 8 m/s
The time period of travel, t = 3 s
The acceleration of Mildred,
a = (v-u)/t
a = (8 - 12) /3
= -4/3
= -1.33 m/s²
The negative sign indicates that the Mildred is decelerating.
Hence, the acceleration of Mildred is, 1.33 m/s²
23. Imagine a ball on a track where no energy is transferred between the ball and the track
or between the ball and the air around it. The ball starts from rest at the position labeled B
and moves along the track toward Positions D, E, F, and G. Place a dot on the highest
position the ball will reach before stopping and going back down the track. Explain why the
ball stop at that position? (Remember that no energy is transferred between the ball and the
track or between the ball and the air around it.)
In the given physics problem, the ball comes to a stop at the highest point. This is because it has transformed all of its kinetic energy into potential energy, and has no more energy to continue moving upwards, as there is no energy transfer with either the track or the air.
Explanation:In this physics problem, the ball on the track is an example of a system that conserves energy. Since there is no energy transfer with either the track or the surrounding air, the total mechanical energy of the ball, which comprises potential and kinetic energy, remains constant throughout its motion. Potential energy is energy due to height, and kinetic energy is energy due to motion.
To place the dot at the highest point the ball will reach, you identify where the ball has maximum potential energy and minimum kinetic energy because at the highest point, the ball momentarily stops and hence, kinetic energy is zero.
Therefore, the ball will stop at the highest point because it has converted all its kinetic energy (energy of motion) into potential energy (energy stored due to its position) and has no more energy left to continue moving upwards. At this point, it starts converting its potential energy back into kinetic energy as it moves downwards, hence it starts moving back down the track.
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The ball will reach the highest position at the same height as position B because of the conservation of mechanical energy. At this point, all kinetic energy converts back to potential energy, causing the ball to momentarily stop before reversing direction. This principle assumes no energy losses in the system.
To determine the highest position the ball will reach on the track before stopping and reversing direction, we need to consider the conservation of energy principle. In this scenario, the total mechanical energy (sum of potential and kinetic energy) remains constant because no energy is transferred between the ball and the track or the air.
When the ball starts from rest at position B, it possesses only potential energy and no kinetic energy. As the ball moves downward, it loses potential energy but gains kinetic energy, and as it moves upward, it loses kinetic energy and gains potential energy. The ball will reach the same height on the opposite side of the track as it started, assuming no energy losses. Therefore, the highest position the ball will reach will be the same height as position B.
The ball stops at this highest position because all of its kinetic energy is converted back to potential energy at that point, making its speed momentarily zero before it reverses direction. This illustrates the conservation of mechanical energy where the initial and final heights are the same when no external forces are acting on the system.
A punter kicks a football from the ground with a velocity of 19 m/s at an angle 32 degrees from the horizontal the football travels a horizontal distance of 33m before it hits the ground what is the maximum height the football reaches
Answer: 5.17 m
Explanation:
The football reaches its maximum height when the vertical component of the velocity is zero:
[tex]V_{y}=0 m/s[/tex]
This is exactly at the point where the football stops and then begins to fall thanks to the acceleration due gravity.
So, we can use the following equation:
[tex](V_{y})^{2}=(V_{oy})^{2}-2gy_{max}[/tex]
Where:
[tex]V_{y}=0[/tex] is the final velocity
[tex]V_{oy}=V_{o} sin(32\°)[/tex] is the vertical component of the initial velocity
[tex]V_{o}=19 m/s[/tex] is the initial velocity
[tex]g=9.8 m/s^{2}[/tex] is the acceleration due gravity
[tex]y_{max}[/tex] is the football's maximum height
Isolating [tex]y_{max}[/tex]:
[tex]y_{max}=\frac{(V_{o} sin(32\°))^{2}}{2g}[/tex]
[tex]y_{max}=\frac{(19 m/s sin(32\°))^{2}}{2(9.8 m/s^{2})}[/tex]
Finally:
[tex]y_{max}=5.17 m[/tex] This is the football's maximum height
What is the name and symbol of the element in the second row and fourteenth column of the periodic table? Hint: Review your periodic table. cobalt (Co) silicon (Si) carbon (C) aluminum (Al)
Which of the following statements about earthquakes is true?
A)Earthquakes and volcanic eruptions always occur at the same time.
B)Earthquakes can only occur on dry land or under water at depths less than 100 meters.
C)Earthquakes occur at regular intervals, usually every five years.
D)The date of future earthquakes cannot be precisely predicted.
Answer:
Option D)The date of future earthquakes cannot be precisely predicted.
Explanation:
Natural disasters take place without being able to be precisely predicted at times. For example, the volcanoes can more or less likely to be predicted due to the plate tectonics and profiling the history of the volcano.
However, earthquakes cannot be predicted. For example, the massive earthquake in Lisbon in Portugal hit unexpectedly. In addition, Japan was hit by an earthquake which could not be predicted. Thus, an earthquake's future is unpredictable.
D) The correct statement is that the date of future earthquakes cannot be precisely predicted. This is due to the complexity of the geological processes involved, which also explains why the other statements are false.
Explanation:Among the given statements, it is true that the date of future earthquakes cannot be precisely predicted (Option D). This is due to the complex nature of geological processes. Volcanic eruptions and earthquakes do not always coincide (Option A).
Earthquakes can occur not only on dry land but also under water, at much greater depths than 100 meters (Option B). Earthquakes also do not occur at regular, predictable intervals (Option C).
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how much pressure is exerted by an 100n man with a shoe area of O.05cm square
Answer:
Pressure = 20 MPa
Explanation:
Given:
Force acting on the shoe is, [tex]F=100\ N[/tex]
Area of shoe on which the force acts is, [tex]A= 0.05\ cm^2[/tex]
Now, first we convert the area into its standard unit of m².
We have the conversion factor as:
1 cm² = [tex]10^{-4}\ m^2[/tex]
Therefore, the area of shoe in square meters is given as:
[tex]A=0.05\times 10^{-4}\ m^2\\A=5\times 10^{-6}\ m^2[/tex]
Now, pressure on the shoe is given as:
[tex]P=\frac{Force}{Area}\\P=\frac{F}{A}[/tex]
Plug in 100 N for 'F', [tex]5\times 10^{-6}[/tex] for 'A' and solve for 'P'. This gives,
[tex]P=\frac{100\ N}{5\times 10^{-6}\ m^2}\\P=20\times 10^{6}\ N/m^2[/tex]
Now, we know that,
[tex]10^{6}\ N/m^2=1\ MPa\\\therefore 20\times 10^{6}\ N/m^2=20\times 1\ MPa=20\ MPa[/tex]
Therefore, the pressure acting on the shoe is 20 MPa.
8. What are the two types of friction and what is the difference?
Answer:
There are more than 2 but you are probably thinking of kinetic and static friction. Kinetic friction is the friction between objects as they are moving. Static friction keeps something in place and resists the movement. Static friction can be overcome by force to move the object.
Explanation:
Pls help ASAP this questions are science questions ( biology chemistry physics)
46 I think a
47 I think d
49 I think a
50 I think a
51 idk
54 I think d
55 idk
56 idk
57 idk
58 I think d
59 idk
61 idk
62 I think a
Answer:
It would be A.
Explanation:
The scale goes from 0 to 14, With 0 being acidic and 14 being basic.
So if 7 is neutral, then anything less than 7 is moving more towards being more acidic. Anything higher than 7 is moving towards being more basic.
Answer:
100, 50, 40, 30, 20, 10 butter
Explanation:
1. Complete the table with the appropriate equivalences
Scientific notation
Order of magnitude
Look the picture there’s a example
Answer:
The different values are in the located in the word document
Explanation:
In the attached document in word, we can find each of the conversion for each one of the quantities.
If we increase the distance traveled when doing work, and keep all other factors the same, what will happen?
A) The amount of force will go down
B) The amount of force will increase.
C) The amount of work will decrease
D) The amount of work will increase
Answer: D
Explanation:
A -amount of work
F-force
s-distance
If you keep same Force(F) and increase distance(s), amount of work will increase, according to:
A=F*s
Answer:
D) The amount of work will increase
Explanation:
Took test
The apparent shift in measurement is called accurate meniscus parallax precision
The apparent shift in measurement is called Parallax.
What is Parallax in physics?Parallax is a displacement or difference in the apparent position of an object viewed along two different lines of sight, and is measured by the angle or semi-angle of inclination between those two lines.
Parallax is the apparent shift of an object's position relative to more distant background objects caused by a change in the observer's position.
In other words, parallax is a perspective effect of geometry.
The apparent shift of an observed object's position resulting from a change of perspective is called "parallax." With the previous demonstration, we've established an inverse relationship.
The closer the object, the greater the parallax angle. We can apply the same principle to the stars.
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What is the horizontal acceleration of a ball taht is launched horizontally with a velocity of 5.6 m/s?
Answer:
Horizontal acceleration=0
Explanation:
Horizontal Launching
When an object is launched horizontally at a certain speed [tex]v_o[/tex], only one force will be acting throughout the whole duration of the motion: the force of gravity. If no effect of the wind is to be considered, then the horizontal speed will not change over time. It means the horizontal acceleration is zero. Please note the vertical acceleration is not zero, it is in fact, the acceleration of gravity (0.8 m/sec^2)
What is the shortest possible time for a sprinter moving at 4 m/s to finish a 100 meter race?
The time needed is 25 s
Explanation:
Assuming that the sprinter is moving by uniform motion, then we can use the following equation that relates distance, time and speed:
[tex]v=\frac{d}{t}[/tex]
where
v is the speed of the sprinter
d is the distance covered
t is the time elapsed
In this problem, we know that
v = 4 m/s is the speed of the sprinter
d = 100 m is the distance that must be covered
Solving for t, we find the minimum time needed:
[tex]t=\frac{d}{v}=\frac{100}{4}=25 s[/tex]
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will mark as brainliest if correct!!!!!!!!!!!!!!!!!!!!!!!!!
When light is reflected, the "incoming" ray is also called the _____ ray.
A. incident
B. reflected
C. bouncing
D. electromagnetic
Answer: A (Incident ray).
Explanation:
what is the work done by a force equivalent to the weight of 100kg that moves an object in 7 minutes?
7000 Joules
Explanation:We are given;
The mass of an object = 100 kgBut, Force = mass × g (taking g as 10 N/kg)
Then, Force = 1000 NAssuming we are given the distance moved by the object as 7 m
We can calculate the work done by the force
We need to know that;
Work done = Force × distance
Therefore;
Work done = 1000 N × 7 m
= 7000 Joules
Therefore, the work done by the force is 7000 Joules
• Most of the galaxies in the universe are moving away from
Earth. Suppose a particular galaxy emits orange light with
a frequency of 5.00 * 1014 Hz. If the galaxy is receding
from Earth with a speed of 3325 km/s, what is the
frequency of the light when it reaches Earth?
• A) 4.945 x 1014 Hz
• B) 5.542 1012 Hz
• C) 5.055 1014 Hz
The frequency of light changes when it is emitted from a moving source. When a galaxy is moving away from Earth, the light it emits becomes redshifted, meaning the frequency decreases. In this case, the observed frequency when the light reaches Earth is approximately 4.945 * 10^14 Hz. Option a is correct.
Explanation:The frequency of light changes when it is emitted from a moving source. This change in frequency is known as the Doppler effect. When a galaxy is moving away from Earth, the light it emits becomes redshifted, meaning the frequency decreases. To calculate the new frequency, we can use the formula f' = f/(1+v/c), where f' is the observed frequency, f is the emitted frequency, v is the speed of the galaxy, and c is the speed of light.
In this case, the galaxy is moving away from Earth with a speed of 3325 km/s. The emitted frequency is 5.00 * 10^14 Hz. Plugging these values into the formula, we get f' = 5.00 * 10^14 Hz / (1 + 3325 km/s / 3 * 10^5 km/s). Simplifying this expression, we find that the observed frequency when the light reaches Earth is approximately 4.945 * 10^14 Hz.
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A) 4.945 x [tex]10^{14}[/tex] Hz is correct option. Using the Doppler effect formula, we calculate the observed frequency of the light from a galaxy receding at 3325 km/s.
To determine the frequency of light from a receding galaxy as observed on Earth, we use the Doppler effect formula for light:
[tex]f_{obs}[/tex] = [tex]f_{em}[/tex] x (1 - v/c)
Where:
[tex]f_{obs}[/tex] is the observed frequency[tex]f_{em}[/tex] is the emitted frequency (5.00 x [tex]10^{14}[/tex] Hz)v is the recession speed of the galaxy (3325 km/s or 3325000 m/s)c is the speed of light (3.00 * 108 m/s)Let’s substitute the values into the formula:
[tex]f_{obs}[/tex] = 5.00 x [tex]10^{14}[/tex] Hz x (1 - 3325000 m/s / 3.00 x [tex]10^{8}[/tex] m/s)
[tex]f_{obs}[/tex] = 5.00 x [tex]10^{14}[/tex] Hz x (1 - 0.01108333)
[tex]f_{obs}[/tex] ≈ 4.945 x [tex]10^{14}[/tex] Hz
Therefore, the frequency of the light observed on Earth is 4.945 x [tex]10^{14}[/tex] Hz.
The law of inertia states that an object
a. will continue moving at the same velocity unless an outside force acts on it.
b. will continue moving in a straight line unless an outside force acts on it.
c. that is not moving will never move unless a force acts on it.
d. at rest will remain at rest unless acted on by an outside force.
2. will do all of the above.
The law of inertia states that an object:
e. Will do all of the above.
Why?
Newton's First Law or the Law of inertia, states that an object at rest will always remain at rest if a force does not act on/upon it. Also, when an object is moving describing a straight line, if a force does not act upon it, it will keep the motion forever.
According to the Law, if an object is moving at constant velocity (same speed and same direction) it will keep the motion unless an outside force acts on it.
So, the correct option will be:
e. The object will do all of the above options.
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The law of inertia states that an object at rest will remain at rest unless acted on by an outside force, while an object in motion will continue moving in a straight line at a constant speed unless acted on by an outside force.
Explanation:The law of inertia, also known as Newton's first law of motion, states that an object at rest will remain at rest unless acted on by an outside force. Similarly, an object in motion will continue moving in a straight line at a constant speed unless acted on by an outside force. This law applies to all objects and is a fundamental principle in physics.
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in which type of wave are vibrations at right angles to the direction in which the wave is travelling
Answer:
longitudinal waves have those properties
I need help with my physics work quickly please!!! I only need help with the circled questions!
Answer:
E11. 0.6 N
E12. 1.61×10⁻⁴ N
E13. 1.12 N
E14. 45 lb
Explanation:
The force due to gravity between two objects is:
F = Gm₁m₂ / r²
where G is the gravitational constant,
m₁ and m₂ are the masses of the objects,
and r is the distance between them.
E11. At a distance r, the force is 9.6 N.
9.6 = Gm₁m₂ / r²
At quadruple the distance (4r), the force is:
F = Gm₁m₂ / (4r)²
F = Gm₁m₂ / (16r²)
F = 9.6 / 16
F = 0.6
E12. Given m₁ = m₂ = 700 kg, and r = 0.45 m:
F = Gm₁m₂ / r²
F = (6.67×10⁻¹¹ m³/kg/s²) (700 kg) (700 kg) / (0.45 m)²
F = 1.61×10⁻⁴ N
E13. At a distance r, the force is 0.28 N.
0.28 = Gm₁m₂ / r²
At half the distance (r/2), the force is:
F = Gm₁m₂ / (r/2)²
F = 4 Gm₁m₂ / r²
F = 4 (0.28)
F = 1.12
E14. The acceleration due to gravity on the Moon is 1/6 that of Earth's. So an astronaut weighs 1/6 as much on the Moon.
W = 270 lb / 6
W = 45 lb