How much would $125 invested at 8% interest compounded continuously be worth after 16 years? Round your answer to the nearest cent. Do not include units in your answer.

Answers

Answer 1
The formula is
A=p e^rt
A future value?
P present value 125
E constant
R interest rate 0.08
T time 16 years
A=125×e^(0.08×16)
A=449.58 round your answer to get
A=450

Related Questions

3x+2y+4z=12
X+y+2z=6
(X=0,y=4,z=1)
Determine if the given 2 lines intersect at the given point. Explain your reasoning.
-2x-4y+z=8
4x+2y=-5
(x=-2,y=0,z=3) same as up above

Answers

Substitute the given points into each equation and if the answer is as intended for both equation, then it means the given points are the intersection point

Given points x = 0, y = 4, and z = 1
Equation 1:
3x + 2y + 4z = 3(0) + 2(4) + 4(1) = 0 + 8 + 4 = 12
Equation 2: 
x + y + 2z = 0 + 4 + 2(1) = 6

Both equation 1 and equation 2 give the intended answer; 12 and 6 respectively, hence the given point is the intersection point
---------------------------------------------------------------------------------------------------------------

Given point : x = -2, y = 0, and z = 3

Equation 1:
-2x - 4y + z = -2(-2) - 4(0) + 3 = 4 - 0 + 3 = 7
Equation 2:
4x + 2y = 4(-2) + 2(0) = -8

The answers are not as intended, hence the given point is not the intersection point

In a certain? country, the true probability of a baby being a boy is 0.534. among the next six randomly selected births in the? country, what is the probability that at least one of them is a girl??

Answers

The probability that at least one of them is a girl is about 0.977

Further explanation

The probability of an event is defined as the possibility of an event occurring against sample space.

[tex]\large { \boxed {P(A) = \frac{\text{Number of Favorable Outcomes to A}}{\text {Total Number of Outcomes}} } }[/tex]

Permutation ( Arrangement )

Permutation is the number of ways to arrange objects.

[tex]\large {\boxed {^nP_r = \frac{n!}{(n - r)!} } }[/tex]

Combination ( Selection )

Combination is the number of ways to select objects.

[tex]\large {\boxed {^nC_r = \frac{n!}{r! (n - r)!} } }[/tex]

Let us tackle the problem.

This problem is about Probability.

Given:

The true probability of a baby being a boy P(B) = 0.534

The true probability that all of six randomly selected births in the country are boys is :

[tex]P(6B) = P(B) \times P(B) \times P(B) \times P(B) \times P(B) \times P(B)[/tex]

[tex]P(6B) = \boxed {(P(B))^6}[/tex]

The true probability that at least one of them is a girl is:

[tex]P(G\geq 1) = 1 - P(6B)[/tex]

[tex]P(G\geq 1) = 1 - (P(B))^6[/tex]

[tex]P(G\geq 1) = 1 - (0.534)^6[/tex]

[tex]P(G\geq 1) \approx \boxed {0.977}[/tex]

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Answer details

Grade: High School

Subject: Mathematics

Chapter: Probability

Keywords: Probability , Sample , Space , Six , Dice , Die , Binomial , Distribution , Mean , Variance , Standard Deviation

The probability that out of the next six randomly selected births, at least one of them is a girl is 0.98.

What is Probability in Mathematics?

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur. Mathematically -

P (Event A) = n(A)/n(S)

where -

n(A) → Number of outcomes favorable to event A.

n(B) → Total number of possible outcomes.

Given is the true probability of a baby being a boy. Its value is -

P(A) = 0.534

Assume that for the next six randomely selected births, the probability that it will be a baby boy is P(B). In one of the six randomely selected births, the probability that it will be a boy is 0.534. Therefore, the probability of being a boy in all the six cases will be -

P(B) = [P(A)]⁶

P(B) = 0.023

Now, for at least one of them to be girl, the probability of the event will be -

P(C) = P(B)' = 1 - 0.023 = 0.98

Therefore, the probability that out of the next six randomly selected births, at least one of them is a girl is 0.98.

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Which expression is equivalent to (x^27y)^1/3?

A) x^3 (3√y)

B) x^9 (3√y)

C) x^27 (3√y)

D) x^24 (3√y)

Answers

Remember that (xᵃ. yᵇ)ⁿ = xᵃⁿ.yᵇⁿ

(x²⁷.y)¹/³ = x⁽²⁷ˣ¹/³⁾. y¹/³

x⁽²⁷ˣ¹/³⁾. y¹/³ =x⁸. y¹/³ = x⁹. ∛y. NONE OF THE ANSWERS, UNLESS YOU HAVE OMITTED SOMETHING, JUST AS 27 IS THE EXPONENT OF X AND ALSO ANOTHER 27 THAT MULTIPLIES Y??, In this case, it will be b

Answer:

Option B).[tex]x^{9}.(\sqrt[3]{y} )[/tex].

Step-by-step explanation:

The given expression is [tex](x^{27}y)^{\frac{1}{3} }[/tex].

We have to further simplify so that we can get the answer as shown in the options.

[tex](x^{27}y)^{\frac{1}{3} }=(x^{27})^{\frac{1}{3}}(y)^{\frac{1}{3}}[/tex]

[ As [tex](x^{a}.y^{b})^{m}=(x^{a})^{m}.(y^{b})^{m}[/tex] ]

Now ([tex](x^{27})^{\frac{1}{3}}(y)^{\frac{1}{3}}=(x^{\frac{27}{3} }).(y^{\frac{1}{3} } )=x^{9}.(\sqrt[3]{y} )[/tex]

Therefore Option B. is the answer.

The area of a triangular flag is 4242 square centimeters. its altitude is 2 centimeters longer than twice its base. find the lengths of the altitude and the base.

Answers

A = (h * b) / 2
h = 2b + 2
A = 42

42 = (b(2b + 2)) / 2
42 = (2b^2 + 2b) / 2
42 = b^2 + b
b^2 + b - 42 = 0
(b + 7)(b - 6) = 0

b + 7 = 0
b = -7...nope..extraneous solution

b - 6 = 0
b = 6 <== base

h = 2b + 2
h = 2(6) + 2
h = 12 + 2
h = 14 <=== height (altitude)

ABC is similar to pqr. Ab corresponds to pq and bc corresponds to qr. if the length of ab is 9 units the length of bc is12units the length of ca is 6units and the length of pq is 3 units then the length of qr is ? Units and the length of rp is ? Units

Answers

QR would equal 4, and PR would equal 2.
if you multiply QP which equals 3, by 3, then you would get 9.
So you would divide BC by 3. 12/3= 4
Then divide AC by 3. 6/3=2.

Answer:

[tex]QR=4\ units[/tex]

[tex]RP=2\ units[/tex]

Step-by-step explanation:

we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal

In this problem

triangle ABC is similar triangle PQR -------> given problem

so

[tex]\frac{AB}{PQ}=\frac{CA}{RP}=\frac{BC}{QR}[/tex]

we have

[tex]AB=9\ units, PQ=3\ units,CA=6\ units,BC=12\ units[/tex]

Find the length of side QR

[tex]\frac{AB}{PQ}=\frac{BC}{QR}[/tex]

substitute the values and solve for QR

[tex]\frac{9}{3}=\frac{12}{QR}[/tex]

[tex]QR=12*3/9=4\ units[/tex]

Find the length of side RP

[tex]\frac{AB}{PQ}=\frac{CA}{RP}[/tex]

substitute the values and solve for RP

[tex]\frac{9}{3}=\frac{6}{RP}[/tex]

[tex]RP=6*3/9=2\ units[/tex]



The perimeter of a scalene triangle is 14.5 cm. The longest side is twice that of the shortest side. Which equation can be used to find the side lengths if the longest side measures 6.2 cm?



Choose the correct answer.
6.2 + b = 14.5
9.3 + b = 14.5
12.4 + b = 14.5
18.6 + b = 14.5

Answers

i believe it is a hope it helps

6,2/2=3,1 cm (the shortest side)
6,3+ 3,1+b=14.5 cm  
The correct anwser is  9,3+b=14,5






if the average (arithmetic mean) of two, seven, and X is 12, what is the value of X?

Answers

The average is always the sum of values divided by the number of values.

(2+7+x)/3=12

Multiply both sides by 3
2+7+x=36

Combine like terms
9+x=36

Subtract 9 from both sides
x=27

Final answer: x=27

Do the ratios 1/12 and 8/96 form a proportion? Explain.

Answers

1/12 = 8/96
cross multiply
(1)(96) = (8)(12)
96 = 96

yes, this is a true proportion...keep in mind, proportions are nothing but equivalent fractions
The following is a type of proportion ==> a : b = c : d; and in this case we have: 
1 : 12 = 8 : 96 
It's not all that hard, all you need to know is the ''cross-multiplication'' methods for testing this kind of stuff. 

1 : 12 = 8 : 96 ? 
1 * 96 = 12 * 8 ? 
96 = 96 ? 
96 = 96 ==> CORRECT 

Paul planted 20 onion bulbs. Three-fourths of the bulbs sprouted. How many onion plants did Paul have?

Answers

3/4 of 20...." of " means multiply

3/4(20) = 60/4 = 15 onion plants <=

Paul had 15 onion plants.

To solve the problem, we need to calculate three-fourths of the 20 onion bulbs that Paul planted, as this represents the number of bulbs that sprouted.

First, we find three-fourths of 20 by multiplying 20 by the fraction [tex]\(\frac{3}{4}\)[/tex]:

[tex]\[ \frac{3}{4} \times 20 = \frac{3 \times 20}{4} \][/tex]

[tex]\[ \frac{3 \times 20}{4} = \frac{60}{4} \][/tex]

[tex]\[ \frac{60}{4} = 15 \][/tex]

Therefore, 15 onion bulbs sprouted, which means Paul had 15 onion plants.

In the diagram below, an and bc are tangent to o. What is the measure of adc

Answers

Look at the attached graphic.

40° = ½ (ADC -140°)
40° = ½ ADC  -70°
110° = ½ ADC
ADC = 220°


Answer:

mADC = 220°

Step-by-step explanation:

In the given diagram AB and BC are tangents to the given circle O. We have to find the measure of arc ADC.

By theorem of tangents and arcs.

m∠ABC = [tex]\frac{1}{2}[/tex] [m ADC- m AC ]

Since it is given in the question

∠ABC = 40 & AC = 140°

Therefore, 40 = [tex]\frac{1}{2}[/tex] [ m ADC - 140 ]

40 × 2 = m ADC - 140

80 + 140 = m ADC

mADC = 220°

Are 60 meters equal to, greater than, or less than 6 km?

Answers

1 km is equal to 1000 meters, so 60 meters would be less than 6 kilometers (km).

Final answer:

60 meters is significantly less than 6 kilometers, as 6 kilometers is equal to 6,000 meters.

Explanation:

To answer this, we need to compare the two measurements in the same unit. We know that 1 kilometer is equivalent to 1,000 meters, so to convert 6 kilometers to meters, we multiply by 1,000:

6 km  imes 1,000 = 6,000 m

Now we can compare the two measurements:

60 m

6,000 m

Since 60 is less than 6,000, we can conclude that 60 meters is less than 6 kilometers.

Which of the numbers listed below are solutions to the equation? Check all that apply. x2 = 81 A. 18 B. 40.5 C. -9 D. 162 E. 9 F. 6561

Answers

x^2 = 81...take the square root of both sides, eliminating the ^2
x = (+-) sqrt 81
x = (+-) 9

answers are : -9 and 9
If 81 equals to x² (so the unknown number is 81 when x is squared), the to find x you do the square root of 81.

x = ±√81

x = ±9

Answers are either C and E

the area of the cross section of a sphere at the largest point is 100 Pi square miles. What is the total surface area of the sphere?

Answers

1.
The cross-section of largest area is obtained when the cross-sectional plane, contains the center of the sphere.

That is, when this plane divides the sphere into 2 semi (half) spheres.

2.
This cross sectional region is a circle with surface area = 100 Pi square miles.

The area of a circle is [tex] \pi R^{2} [/tex], where R is the radius.

So

[tex]\pi R^{2}=100 \pi [/tex] square miles,

3.

The surface area of a sphere is given by the formula [tex]4\pi R^{2}[/tex]

So the surface area of this sphere is [tex]4\pi R^{2}=4*100 \pi =400 \pi [/tex] square miles.


Answer: [tex]400 \pi[/tex] square miles

Find the 6th term of a geometric sequence t3 = 444 and t7 = 7104.

Answers

Given the value of t3 and t7, and t7 = t3 * r^4, where r represents the geometric quotient. 

So 7104 = 444 * r^4 -> solve for r, you will get r = 2 or -2

So, for r = 2, t6 = t7 / r = 7104 / 2 = 3552

For r = -2, t6 = -3552

The 6th term of the geometric sequence is 3552

How to determine the 6th term of the geometric sequence

To find the 6th term of a geometric sequence, we need to determine the common ratio (r) first.

Given that t3 = 444 and t7 = 7104, we can use these two terms to find the common ratio.

t3 = t1 * r^(3-1)

444 = t1 * r^2

t7 = t1 * r^(7-1)

7104 = t1 * r^6

Dividing the two equations, we get:

7104/444 = (t1 * r^6) / (t1 * r^2)

16 = r^4

Taking the fourth root of both sides, we find:

r = ∛16 = 2

Now that we have the common ratio (r = 2), we can find the first term (t1) by substituting the values of t3 and r into the equation t3 = t1 * r^(3-1):

444 = t1 * 2^2

444 = 4t1

t1 = 111

To find the 6th term (t6), we substitute the values of t1 and r into the general formula for the nth term of a geometric sequence:

t6 = t1 * r^(6-1)

t6 = 111 * 2^5

t6 = 111 * 32

t6 = 3552

Therefore, the 6th term of the geometric sequence is 3552.

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A school did a survey among 100 students to find their sports preferences. The students were asked about their preferences for football or baseball. Out of the total 77 people who liked football, 48 also liked baseball. There were 65 people who liked baseball. Part A: Summarize the data by writing the values that the letters A to I in the table below represent. (5 points)A school did a survey among 100 students to find their sports preferences. The students were asked about their preferences for football or baseball. Out of the total 77 people who liked football, 48 also liked baseball. There were 65 people who liked baseball. Part A: Summarize the data by writing the values that the letters A to I in the table below represent. (5 points) Like football Do not like football Total Like baseball A D G Do not like baseball B E H Total C F I Part B: What percentage of the survey respondents did not like either football or baseball? (3 points) Part C: Do the survey results reveal a greater dislike for football or baseball? Justify your answer. (2 points)

Answers

                                  like football            dont like football        total
like baseball                   48                            17                          65
dont like it                       29                              6                          35
total                                77                             23                        100

percent that did not like football or baseball : 6/100 = 0.06 = 6% <=
there is a greater dislike for baseball....because out of the 100 people, 35% dont like baseball, and 23% dont like football <=

Answer:

Part A: A=48  B=29 C=77  D=17  E=6   F=23  G=65  H=35  I=100

Part B: 6% of the survey respondents did not like either football or baseball.

Part C:  The survey results reveal a great dislike for baseball this is because 35% of the survey respondents dislike baseball while only 23% of the survey respondents dislike football.

Find the area of the regular polygon.
pentagon with a radius of 4 ft

Answers

In this problem we need to find the apothem and the length of the side before we can find the area of the entire polygon. Each central angle for a regular pentagon is 360∘5=72∘. So, half of that, to make a right triangle with the apothem, is 36∘. We need to use sine and cosine. 
sin36∘4sin36∘8sin36∘n=.5n4=12n=n≈4.7 cos36∘=a44cos36∘=aa≈3.24
Using these two pieces of information, we can now find the area. 
A=12(3.24)(5)(4.7)≈38.07 units^2.

Translate the sentence into an equation. Twice the difference of a number and 2 equals 9 . Use the variable y for the unknown number.

Answers

Since difference is subtraction, that means that y-2=9 and by adding 2 to both sides we get y=11

The value of variable y in the equation,

2y + 2 = 9 is y = 7/2.

What is an equation?

An equation is a pair of algebraic equations with the equal sign (=) in the middle and the same value.

Given:

A phrase: Twice the difference of a number and 2 equals 9.

Let the number be y.

Then according to the question,

twice the difference of a number means,

2 x y

= 2y.

And the 2y and 2 equals 9.

That means,

we have an equation,

2y + 2 = 9

Subtract 2 from both sides,

we get,

2y = 7

y = 7/2.

Therefore, the value of y is 7/2.

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If you flip a coin twice, what is the probability that you flip tails both times?

Answers

Probability of one coin: 1/2

1/2(1/2)= 1/4

The probability of flipping tails both times is 1/4.

Hope this helps!

Answer: 1/4

Step-by-step explanation: In this problem, we are tossing two coins and we want to find the probability of tossing a tails and a tails. Tossing two coins are independent events because the outcome of tossing one coin does not affect the outcome of tossing the other coin.

We can find the probability of independent events by multiplying the probability of the first event by the probability of the second event. Note that we are talking about the theoretical probability because we aren't going to actually toss the coins.

If we want to find the probability of tossing a tails and a tails, we multiply the probability of tossing a tails by the probability of tossing a tails.

Now, let's find the probability of tossing a tails on the first coin. Remember that a coin has two sides which are heads and tails. Tails is one of these sides so the probability of tossing a heads is 1 out of 2 or 1/2. On the second coin the same is true so the probability is 1 out of 2 or 1/2.

Finally, we can simply multiply 1/2 by 1/2 which gives us 1/4. Therefore, the probability of tossing tails and tails is 1/4.

What is the average of three checks, one for $16.00, one for $40.00 and one for $130?

Answers

add them then divide by 3

16.00 + 40.00 + 130 = 186.00

186.00/3 = 62.00

 the average is 62.00

Candida bought 334 yards of fabric. If she uses 23 of the fabric to make a dress, how much fabric will she have left?

Answers

334-23 = 311
just minus 23 from 334
334 yards are 12,024 inches
23 yards are 828 inches
She has 11,196 inches or 311 yards left

Substituting x-4=y and -5y+8x=29

Answers

The answer is x=3. Work shown in the photo above!
-5(x-4) +8x=29
-5x+20+8x=29
3x+20=29
3x=9
X=3

The width of a rectangle is 7 inches less than its length. The area of the rectangle is 120 square inches. Solve for the dimensions of the rectangle. Length: inches Width: inches

Answers

area = L x W

W=L-7

120 = L x L-7

120 = L^2-7L

L^2-7L+120 =0

(L-15) (L+8)

L=15, L=-8. It can't be a negative number so L=15

W=15-7 = 8

15*8 =120

 length = 15 inches

width = 8 inches


Answer:

The dimensions of the rectangle. Length= 15 inches and Width= 8 inches

Step-by-step explanation:

Let width of rectangle be W and length be L then

L=W+7 ---- (A)

Also given that area of rectangle = 120 square inches

=> WxL=120   -----(B)

From equation (A) and (B)

Wx(W+7) = 120

=> [tex]W^{2}+7W-120=0[/tex]

=>[tex]W^{2}+15W-8W-120=0 =>(W+15)(W-8)=0[/tex]

=> [tex]W=-15 or 8[/tex]

Since the width can not be a negative quantity , so W= 8 inches

=> L= W+7= (8+7) inches =  15 inches

Thus the dimensions of the rectangle. Length= 15 inches and Width= 8 inches

Conjecture for interior angles of complex polygons

Answers

The best way to do this is to draw out a few polygons and divide them into triangles, then add up the angles. If you start with a square, then a pentagon, then a hexagon, then a heptagon, by the time you get to an octagon, you will see a pattern and can make your inference. Remember that to make an inference is to come to a conclusion based on your observation. So grab a piece of paper and a pencil and start drawing!! You will probably find that they actually did you for this in the Geometry textbook:)

Final answer:

The conjecture for interior angles of complex polygons involves using the formula (n-2)×180 degrees for regular polygons and more complex considerations for 3D shapes like pentagonal bipyramids or square antiprisms. As the number of sides increases, calculations become more intricate and the interior angles can approach 180 degrees in very large polygons.

Explanation:

The question involves making a conjecture for the interior angles of complex polygons. A commonly used theorem related to this is that the sum of the interior angles of a polygon can be found using the formula (n-2)×180 degrees, where n is the number of sides in the polygon. For instance, to find the sum of the interior angles of a pentagon (a polygon with five sides), we calculate (5-2)×180 degrees = 540 degrees. As the number of sides increases, our calculations can become more complex, especially when dealing with non-regular polygons (where the sides and angles don't all have the same length/measure).

When considering the interior angles of complex geometries like a pentagonal bipyramid or a square antiprism, it's essential to recognize that their interior angles may involve multiple planes and hence cannot be calculated using the simple 2D polygon interior angle sum formula. These shapes involve three-dimensional calculations and often require advanced geometry or trigonometry to dissect into understandable components.

Considering large numbers of sides and complex figures, the interior angle measures can approach different limits. For example, as the number of sides I becomes very large, the interior angle measures can become very close to 180 degrees, which is suggested by the idea that for a polygon with infinitely many sides (approaching a circle), each interior angle would be 180 degrees.

What is the shape of the graph of any geometric sequence?

Answers

It is an exponential curve   which will either  quickly get very steep or decrease  very quickly according to the value of the common ratio.

Final answer:

The graph of a geometric sequence forms either an exponential decay or growth curve, depending on the common ratio, with the sequence appearing as a straight line on a semi-logarithmic scale.

Explanation:

The graph of any geometric sequence takes on a distinctive shape. If the common ratio of the geometric sequence is between -1 and 1 (excluding 0), the points of the graph will form a curve that approaches the x-axis as the number of terms increases, which is known as an exponential decay if the common ratio is positive, and an oscillating decay if it is negative. Similarly, if the common ratio is greater than 1 or less than -1, the sequence will exhibit exponential growth with each subsequent term becoming larger, and the points will diverge away from the x-axis forming an upward curve if the common ratio is positive or oscillating upward if it is negative. The graph may have a y-intercept, where it crosses the y-axis, and when graphed on a semi-logarithmic scale, the sequence with a positive common ratio will appear as a straight line.

The proof that MNG ≅ KJG is shown.

Given: angle N and angle J are right angles; NG ≅ JG
Prove: MNG ≅ KJG

What is the missing reason in the proof?

the reflexive property
ASA
AAS
the third angle theorem

Answers

ASA theorem is the missing proof

The line [tex]\mathbf{\overline{MK}}[/tex] is a bisector of the line [tex]\mathbf{\overline{JN}}[/tex], and both lines form part of

ΔMNG and ΔKJG.

Correct response:

The missing reason in the proof is; ASA

Method used to prove ΔMNG ≅ ΔKJG, and find the missing reason

A two column proof is presented as follows;

Statement [tex]{}[/tex]                                     Reasons

1. [tex]\overline{NG}[/tex] ≅ [tex]\overline{JG}[/tex]                       1. Given (hash marks representing equal length)

2. ∠N and ∠J are right angles      2. Given (symbol for right angle)

3. ∠MGN ≅ ∠KGJ                       3. Vertical angle are congruent (theorem)

4. ∠N ≅ ∠J                                   4. Right angles are (all) congruent

5. ΔMNG ≅ ΔKJG                    5. Angle-Side-Angle, ASA, congruency rule

The missing reason in the proof is; ASA

According to the ASA congruency rule, if two angles and the included

side of one triangle are the same to two angles and the included side of

another triangle, the two triangles are congruent.

∠N, side [tex]\mathbf{\overline{NG}}[/tex]∠MGN in ΔMNG are congruent to ∠J, side [tex]\mathbf{\overline{JG}}[/tex]∠KGJ in ΔKJG

Therefore;

ΔMNG ≅ ΔKJG by ASA congruency rule

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What is something that multipys to 72 and adds -27?

Answers

24 if you look at a factor tree, -24 x -3 = 72 and -24 + -3 = -27
You want xy=72 and x+y=-27. Now solve for either x or y in one of the equations and then substitute it into the other equation. For instance, x=-27-y so you can substitute to get (-27-y)y=72. Distribute so -27y-y^2=72. let's move everything to one side so 0=y^2+27y+72. Now use quadratic formula to solve. 

Gary earns $12 an hour plus $16 an hour for every hour of overtime. Overtime hours are any hours more than 30 hours for the week. Part A: Create an equation that shows the amount of money earned, M, for working x hours in a week when there is no overtime. (3 points) Part B: Create an equation that shows the amount of wages earned, T, for working y hours of overtime. Hint: Remember to include in the equation the amount earned from working 30 hours. (3 points) Part C: Gary earned $408 in 1 week. How many hours (regular plus overtime) did he work? Show your work. (4 points)

Answers

Part A.

Amount of money earned = Regular rate per hour * Number of working hours

M = 12 x

 

Part B.

Amount of wages earned = Regular rate per hour * Maximum number of regular working hours + Overtime rate per hour * Excess working hours

T = 12 * 30 + 16 * y

T = 360 + 16 y

or

T = 16 y + 360

 

Part C.

Given T = 408, find y:

408 = 16 y + 360

y = 3 hrs

Therefore the total hours Gary worked that week is,

x + y = 30 + 3 = 33 hrs        

(x = 30 since that is the maximum limit for regular working hours)

A quadratic equation is shown below:

25x2 + 10x + 1 = 0

Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (5 points)

Part B: Solve 4x2 − 4x + 1 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used. (5 points)

Answers

hello : 

help :
the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 )  Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions

Choose the equation below whose axis of symmetry is x = 2.

y = x^2 + 4x + 2
y = x^2 - 4
y = x^2 - 2
y =x^2 - 4x + 2

Answers

the answer would be the first one

Answer:

Hi!

The correct answer is y =x^2 - 4x + 2

Step-by-step explanation:

The axis of symmetry is the x-coordinate vertex of the parabola.

The general form to find the axis of symmetry is:

[tex]x=-\frac{-b}{2*a} [/tex]

For y =x^2 - 4x + 2, a=1, b=−4 and c=2:

[tex]x=-\frac{-4}{2*1} = - \frac{-4}{2} = -(-2) = 2[/tex]

[tex]x = 2[/tex]

The distance between two cities on a map is 3 1/2 inches. The actual distance between the two cities is 28 miles.
a. What is the scale used on the map?
b. If the scale on a different map of the same area is inch = 1 mile, how separate the same two cities?

Answers

part A= 3.5 inches is equal to 8 miles

Part B= if 1 inch is 1 miles then on this map the cities are 28 inches apart.

hope this helps!!! if so please help me out by marking as brainliest
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