How to simplify equations with fractional exponents?

Answers

Answer 1
The general form for a term with fractional exponents is given as :

[tex]a^{ \frac{m}{n} }[/tex] which can be rewritten as [tex] (\sqrt[n]{a} )^m[/tex]

for example: [tex](x + 3)^ \frac{2}{3} =( \sqrt[3]{x+3})^2 [/tex]
Answer 2

Final answer:

To simplify equations with fractional exponents, divide the digit term of the numerator by the digit term of the denominator and subtract the exponents of the exponential terms. Then multiply the numerators and denominators together and simplify by common factors if needed.

Explanation:

When simplifying equations with fractional exponents, we can follow these steps:

Divide the digit term of the numerator by the digit term of the denominator.Subtract the exponents of the exponential terms.Multiply the numerators and denominators together and simplify by common factors if needed.

For example, let's simplify the equation √(x³ / y²). We divide x³ by y², which gives us x/y. Then we subtract the exponents, resulting in √(x/y). Finally, we can simplify the fractional exponent by taking the square root of x/y, which gives us √(x/y).


Related Questions

How many lines of symmetry are
found in a regular polygon with 40

Answers

This is assuming that 40 refers to sides.

Since 40 is an even number, you can have lines of symmetry going from any vertex to the opposite one. Since there can be two identical lines, we just cut in half 40 to 20 so there are no repeats. We can do this for halfway between two vertices as well, so that's another 20. Twenty  + 20 = 40 and thus, your answer is 40 lines of symmetry.
Final answer:

A regular polygon has the same number of lines of symmetry as it has sides. Therefore, a regular polygon with 40 sides will have 40 lines of symmetry.

Explanation:

In Mathematics, symmetry is a significant aspect when dealing with geometric figures, such as polygons. In a regular polygon, the number of lines of symmetry is equal to the number of sides. Therefore, a regular polygon with 40 sides will have 40 lines of symmetry.

This is because, in a regular polygon, all sides and angles are equal, meaning it can be reflected or folded over each of its sides and still remain the same shape. So, you can draw a line from each vertex to the opposite side (or vertex in some cases) and get a perfect fold or reflection.

Remember, this is only true for regular polygons, as irregular polygons won't have the same number of lines of symmetry because their sides and angles may not be equal.

Learn more about Symmetry in Regular Polygons here:

https://brainly.com/question/33820017

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Can someone please help?
thanks :)

Answers

This is one way to solve it.

(6-3)^2

breakdown: (6-3) (6-3)

Now using the distributive property you can further solve this problem. This means you multiply everything by each other.

6*6, 6*-3, -3*6, -3*-3

36 -18 -18 +9

Now solve what's above.
You should find 9 as your final answer.

Please vote my answer brainliest. thanks!


All real numbers that are less than -3 or greater than it equal to 5

Answers

is that the question?

Your answer would be
<-3 or x > 5

Solve this Multi-Step Equation

7p - (3p + 4) = -2(2p - 1) + 10

Answers

p=2 in the question above
I hope this was helpful!!!

4x-8y=24 find the x-intercept and y- intercept on the graph

Answers

the x intercept is the value of x when y=0
the y intercept is the value of y when x=0
when y=0: 4x-0=24 => x=4
when x=0: 0-8y=24 => y=-3
so the x intercept is 4, and the y intercept is -3

4x-8y=24
move variables to the right side and change its sign 
4x=24+8y
divide both sides by 4 
x=6+2y 


4x-8y=24
move variable to the right and change the sign 
-8y=24-4x
divide both sides by -8
y=-3+1/2x

In a class of 20 students ,40% are boys.25% of theboys and 50% of the girls were glasses.how many students were glassses. show work

Answers

40% of 20 is 8 Boys
60% of 20 is 12 Girls
50% of the Girls is 6
25% of the Boys is 2
6 + 2 = 8 Students wore glasses

Hope this helps!

Graph y-5 = -2/3 (x+9)

Answers

when you put the equation into y=mx+b form, it is:
y=-2/3x-1
not sure how to graph this on here, but I guess I can describe the graph to ya:
~the line intersects the y-axis at -1 and the x intersect at -1.5
~draw your line

Three consecutive integers have a sum of 114. what are the three integers

Answers

let the smallest one be x, the second one is then x+1, the third one is x+2
x+(x+1)+(x+2)=114
3x+3=114
3x=111
x=37
the three consecutive integers are: 37,38,39

Our three consecutive integers are 37, 38, and 39.

Work is provided in the image attached.

Mrs. Reid is going on a trip. She has 9 books that she hasn't read yet, but she wants to bring only 3 on the trip. In how many ways can she choose 3 books to bring on the trip?
♦27
♦84
♦504
♦60,480

Answers

Answer:

Option B is right.

Step-by-step explanation:

Given that there are totally 9 books unread by Mrs. Reid.  OUt of these she wants to take only 3 books on the trip.

For books order does not count.

Hence combinations would be appropriate to calculate.

3 books out of 9 can be selected in

9C 3 ways

No of ways of selecting 3 books for the trip out of 9 = [tex]\frac{9(8)(7)}{1(2)(3)} =84[/tex]

There are just 84 ways of choosing 3 books to bring on the trip out of 9 unread books.

Option B is right.

The correct answer is 84.

To solve this problem, we can use the concept of combinations from combinatorics. A combination is a way of selecting items from a collection, such that the order of selection does not matter. In this case, Mrs. Reid wants to select 3 books out of 9 without regard to the order in which they are chosen.

The number of ways to choose 3 books from 9 is given by the combination formula:

[tex]\[ C(n, k) = \frac{n!}{k!(n-k)!} \][/tex]

where[tex]\( n \)[/tex] is the total number of items to choose from, [tex]\( k \)[/tex]is the number of items  to choose, and [tex]\( ! \)[/tex] denotes factorial, which is the product of all positive integers up to that number.

For Mrs. Reid's situation:

[tex]\[ n = 9 \] \[ k = 3 \][/tex]

So we plug these values into the formula:

[tex]\[ C(9, 3) = \frac{9!}{3!(9-3)!} \][/tex]

Calculating the factorials:

[tex]\[ 9! = 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \] \[ 3! = 3 \times 2 \times 1 \] \[ (9-3)! = 6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 \][/tex]

Now we simplify the expression by canceling out the common terms in the numerator and the denominator:

[tex]\[ C(9, 3) = \frac{9 \times 8 \times 7 \times 6!}{3! \times 6!} \] \[ C(9, 3) = \frac{9 \times 8 \times 7}{3 \times 2 \times 1} \][/tex]

Divide out the common factors:

[tex]\[ C(9, 3) = \frac{9}{3} \times \frac{8}{2} \times \frac{7}{1} \] \[ C(9, 3) = 3 \times 4 \times 7 \][/tex]

Now we multiply the remaining numbers [tex]\[ C(9, 3) = 3 \times 4 \times 7 = 84 \][/tex]

Therefore, Mrs. Reid can choose 3 books to bring on the trip in 84 different ways.

What is the length of each side of a cube if its surface area is 486 in2?

Answers

The surface area of a cube = side * side *6 =
area = side^2 * 6
486 = side^2 * 6
side^2 = 486 / 6
side^2 = 81
side length = 9 inches



Jill bought items costing $3.45 , $ 1.99, $6.59 , and $ 12.98 . she used a coupon worth $2. 50. if jill had $ 50.00 when she went into the store , how much did she have when she left

Answers

What you do is add 
$3.45
$1.99
$6.59
$2.50
$12.98
which the sum of that is $27.51 then you subtract the coupon with the total which is $25.01 and then you take $25.01 and subrtact $50.00 thn your answer is $24.99

Does this figure have rotational symmetry?
A) No, pentagons cannot be rotated.
B) No, it has five lines of symmetry.
C) Yes, it has five lines of symmetry.
D) No, it only looks the same if it is rotated 360°.

Answers

D) No, it only looks the same if it is rotated 360

More than half of which climate type averages between 40 and 59 inches of precipitation a year?

Answers

A range between 40 and 59 inches of precipitation a year would not correspond to a dry climate or a very cold climate.
The Cfa climate is the humid subtropical climate. This climate has hot muggy summers and frequent thunderstorms. Winters are mild and precipitation during this season comes from mid-latitude cyclones. The southeastern USA good example for Cfa climate . The Cfa climate receives precipitation throughout the year. 

Simplify the expression, if possible. (if the expression cannot be simplified, enter the given expression.) (k − 5)13 (k − 5)

Answers

2 ( k-5) 13 you don't need two k-5 you can simplify it so you just know to do it twice

Is the probability of contamination more than twice the mean of 14.4 unusual, or can it be considered typical variation? explain?

Answers

More than the twice of the mean is 28.8 and I don't understand the meaning of typical. Seeing this porblem statement said that 3 brands had been contaminated more than twice the average, We would assume it's typical, then again it depends on what you define typical as. I think the mean is like "find the probability that a tested bar has at least twice as many insect fragments as the mean, and see if that number is really really small". 
The probability is 0.000463 and this is really small, but I really don't understand what is the meaning of typical in this problem. 

To determine if a probability of contamination more than twice the mean of 14.4 is unusual, the standard deviation must be considered. In a normal distribution, occurrences more than two standard deviations from the mean are typically unusual.

Whether a probability of contamination more than twice the mean of 14.4 is unusual or not depends on the standard deviation of the data. In a typical normal distribution, values more than two standard deviations away from the mean could be considered unusual. Considering a mean of 14.4, if the standard deviation is small, then a value twice as large would likely be an outlier. However, if the standard deviation is large, such a value could fall within the realm of normal variation.

To ascertain if a value is unusual, one would compare it to the range defined by a certain number of standard deviations from the mean. A common rule of thumb is the empirical rule, which states that for a normally distributed dataset, roughly 68% of data falls within one standard deviation of the mean, 95% within two standard deviations, and 99.7% within three standard deviations.

In this context, if a probability of contamination is more than twice the mean (greater than 28.8), and assuming a normal distribution, it would be considered unusual if it falls outside of two standard deviations from the mean.

Find the slope of the line.

Answers

do rise over run  and it would be rise 1 run 4, 1/4

We can use the points (-4, -1) and (0, -2) to solve.

Slope formula: y2-y1/x2-x1

= -2-(-1)/0-(-4)

= -1/4

Best Regards,

Wolfyy :)

What is the reciprocal of each mixed number? Drag and drop the answer into the box to match each number.
10 1/3
2 2/3
5 1/3.

Answers

Hi there!! 

First, we are going to find the improper fraction of each mixed number. 

10 1/3 >>>>> 10*3+1=31 31/3

2 2/3 >>>>> 2*3+2=8.      8/3 

5 1/3 >>>>>> 5*3+1 = 16.  16/3 

TO find the reciprocal, we switch the numerator with the denominator. 

31/3 changes to 3/31, 8/3 changes to 3/8, and finally 16/3 changes to 3/16. 


Your answer is: 

3/31
3/8
3/16

Hope this helps! Let me know if you have any questions:)

Answer:

10 1/3 = 3 /31.      2 2/3 = 3/8.          5 1/3 = 3/16.

Step-by-step explanation:

i took the k12 test and got 100 percent hope this helps!!

Hey Yo I needs some Help

Answers

12?) [tex]5.15(8)=41.2[/tex], [tex]5.15(4)=20.6[/tex], [tex]5.15(3)=15.45[/tex], [tex]5.15(7)= 36.05 [/tex], [tex]5.15(4)=20.6[/tex], [tex]5.15(2)=10.3[/tex]
[tex]41.2+20.6+15.45+36.05+20.6+10.3=144.2[/tex] There is a remainder of 30 mins that why i choose to to up 144.2 to 146.78

13) works 7 hours plus 43mins and 28 mins which adds another hours [tex]6.75(8)=54[/tex] yet there is still 11 mins left so i divided 6.75 by 4 to get as close  and got 1.6875 which i rounded to 69 cents theresore it is 55.69



     

Answer:

wow

Step-by-step explanation:

THE FUNCTION ARCSINE CAN ALSO BE DEFINED AS?

Answers

The arcsine, [tex]\sin^{-1}[/tex], is the inverse of the [tex]\sin[/tex] function. This means that it takes as inputs what would usually be outputs for the [tex]\sin[/tex] function and produces as outputs what would usually be inputs for the [tex]\sin[/tex] function.

This can be particularly useful when you're trying to find an angle on a right triangle, but you've only been given the lengths of the sides. To find any angle [tex]\theta[/tex] in a right triangle, just take [tex]\sin^{-1} \frac{o}{h} [/tex], where o is the side opposite [tex]\theta[/tex] and h is the hypotenuse of the right triangle.

If the top of a set of characters is chopped off, then line spacing may be set to ____.

Answers

may be set to exactly.

Erica sells magazine subscriptions and makes a flat rate of $5.35 for each subscription see cells if Erica man $42.80 on Monday $64.20 on Tuesday and $74.90 on Wednesday how many subscriptions did she sell in three days

Answers

Erica would have sold 121 subscriptions in 3 days.

C—34. Subscriptions


evaluate the expression if a=3 and b=5
4(a+2b)

Answers

4(3+2(5))
4(3+10)
4(13)
52

I think it would be 52 hoped this helped!

30 POINTS!!

Find the measure of angle B in isosceles triangle ABC.

Answers

C. 65 degrees.

Triangles must equal 180 degrees. The given 50 means the rest of the triangle is equal to 130. I believe because of the Side-Angle-Side theorem of triangles (if my knowledge of proofs from 3 years ago is still with me), the two remaining angles are equal to each other. Let's call them X. 2x = 130. Divide both sides by 2. 130/2 = 65. So x=65

3 angles inside a triangle = 180 degrees

 since the 2 sides are equal

 angle B  and C are the same

180 - 50 = 130 degrees

130 / 2 =65

 Angle B is 65 degrees

Force equals mass times acceleration. If m represents mass and a represents acceleration, Which function f represents Force?

A. F=ma
B. F=m+a
C. F= m exponent a
D. F=m/a

Answers

The answer is F=ma
In this type of equation, By followng, the rules that learned through aljabar ,
ab = ab
-ab = -ab
putting two letter representations will equal to multiplying it.Beside this,  Putting a dot between each the two-letter representations will also indicate multiplication.

Calculus: Help ASAP
Evaluate the integral of the quotient of the secant squared of x and the square root of the quantity 1 plus tangent x, dx.

Answers

[tex]\bf \displaystyle \int~\cfrac{sec^2(x)}{\sqrt{1+tan(x)}}\cdot dx\\\\ -------------------------------\\\\ u=1+tan(x)\implies \cfrac{du}{dx}=sec^2(x)\implies \cfrac{du}{sec^2(x)}=dx\\\\ -------------------------------\\\\ \displaystyle \int~\cfrac{\underline{sec^2(x)}}{\sqrt{u}}\cdot\cfrac{du}{\underline{sec^2(x)}}\implies \int~\cfrac{1}{\sqrt{u}}\cdot du\implies \int~u^{-\frac{1}{2}}\cdot du \\\\\\ 2u^{\frac{1}{2}}\implies 2\sqrt{1+tan(x)}+C[/tex]

Answer:

[tex]2\sqrt{1+tan(x)} +C[/tex]

Step-by-step explanation:

To start solving this you need to use substitution. I let u = 1+tan(x). Next you need to find du/dx, which is sec^2(x) using trigonometric properties. Solve for dx and get dx = du / sec^2(x). Next put the new dx back in. This gives you integral sec^2(x) / sqrt u * du / sec^2(x). The sec^2(x) cancels and the new expression is integral 1/sqrt u * du, which can be simplified to integral u^-1/2 * du. You then take the integral and get 2u^1/2. Lastly, substitute the original u back in and get 2 sqrt 1+tan(x) + C.

A certain mutual fund has net assets of $1,359,600. One share of this fund has a net asset value of $11.33. How many shares make up the fund?

Answers

You would have to divide $1,359,600 by $11.33 which comes out to 120,000
So the answer is 120,000 shares

Answer:

B

Step-by-step explanation:

5(1+4m)=2(3+10m)
Please help. Show work please

Answers

5 times 1 which is 6+4m
6+10m
Combine light terms
12+14m
Distribute first...
5(1)=5
5(4m)=20m
So for the left side it's 5+20m
Now u have to do the same thing for the right side
2(3)=6
2(10m)=20m
So for the right side it's 6+20m
Now that u have solved both sides u have to isolate the m
5+20m=6+20m
-5 -5
----------------------
20m=1+20m
-20m -20m
------------------------
0=1
Therefore there is no solution

ALGEBRAAA

1. What is the average rate of change? How do you find it?
2. Whats the difference between recursive and explicit formulas?

Answers

1. The average rate of change is the slope of a line to find it divide the vertical change by the horizontal change


2. recursive is a formula to calculate the next term, depending on what the previous term was

 Explicit is a formula to calculate any term depending on the term number

A function is given. Determine the average rate of change of the function between the given values of the variable.
h(t) = t2^2+ 2t; t = −1, t = 4

Answers

Formula for "average rate of change:"
              h(b) - h(a)
ARC = --------------------
                  b - a
                       [h(4)\ - [h(1)]
Here, ARC = --------------------
                            4 - 1

Please double check that you have copied down the function h(t) correctly.  What does t2^2 mean?

in a experiment investigating the growth of spores in varying soil conditions a certain spore colony grew an average of 3 times larger during each 24 hours period.if the colony contained 50 spores at the beginning of the experiment how many spores were there at the end of the 4th day?

Answers

Given that the certain type of spore colony having 50 spores and a rate of growth of 3 times in 24 hour or one day period, it would grow to (3 times 50) 150 spores at the end of the first day, (3 times 150) 450 in the 2nd day, (3 times 450) 1350 in the third day, and (3 times 1350) 4050 spores at the end of the fourth day.

The spore colony, which triples in size each day, will contain 4050 spores at the end of the 4th day starting from an initial count of 50 spores.

This question involves exponential growth, where the size of the spore colony triples every day.

To solve this, we will calculate the number of spores at the end of each day:

Initial spores= 50

End of Day 1,
50 * 3 = 150

End of Day 2,
150 * 3 = 450

End of Day 3,
450 * 3 = 1350

End of Day 4,
1350 * 3 = 4050

Therefore, at the end of the 4th day, the spore colony would contain 4050 spores.

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