Answers
"Evaluate: -7/3-1 2/9."...
First, we must convert the mixed number into an improper fraction. This is done by multiply to whole number of the fraction (1 2/9) by the denominator. Then add this number to the numerator.
1*9=9
9+2=11
11/9
-7/3-11/9
Now we must find a common denominator for both fractions.
-21/9-11/9
=-32/9
The answer is -32/9.
Hope this helps.
Related Questions
What is the distance in km between two cites that are 7.5 cm apart on a 1:24 000 scale
Answers
7.5 cm on the map represents 7.5 x 24000 = 180000 cm on the ground.
180000 cm = 1800 m (dividing by 100 cm per m)
1800 m = 1.8 km (dividing by 1000 m per km)
Those "cities" are really close together!
What's the principal square root of 169
Answers
The principal square root of 169 is 13.
The principal square root of a number is the non-negative square root.
The principal square root of 169 is the non-negative number that, when multiplied by itself, equals 169.
We are looking for a number such that when it is squared (multiplied by itself), it equals 169.
This can be expressed mathematically as:
x² = 169
The solution to this equation is
x = √169.
169 is a perfect square, and its square root is 13 because:
13 × 13 = 169.
Therefore, the principal square root of 169 is 13.
Suppose that receiving stations X, Y, and Z are located on a coordinate plane at the points (3,3), (-13, −5), and (-5,3), respectively. The epicenter of an earthquake is determined to be 5 units from X, 13 units from Y, and 5 units from Z. Where on the coordinate plane is the epicenter located?
Answers
The epicenter is located at (-5, 1) on the coordinate plane.
Explanation:To find the coordinates of the epicenter, we need to find the average of the coordinates of the three receiving stations. The x-coordinate of the epicenter is (3 - 13 - 5)/3 = -5, and the y-coordinate is (3 - 5 + 3)/3 = 1. Therefore, the epicenter is located at (-5, 1) on the coordinate plane.
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The coordinates of the epicenter of earthquake are (-1, 0).
The epicenter of the earthquake is the point that is equidistant from stations X, Y, and Z. This is essentially the solution to a system of three equations representing the distances from the epicenter to each of the three stations.
The equations are derived from the distance formula, [tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex] ,
where [tex](x_1,y_1)[/tex] and [tex](x_2, y_2)[/tex] are the coordinates of the two points and d is the distance between them.
For station X at (3,3), the distance to the epicenter (x,y) is 5 units. So, the equation is:
[tex](x - 3)^2 + (y - 3)^2 = 5^2 = 25 \text{ ....(1)}[/tex]
For station Y at (-13,-5), the distance to the epicenter is 13 units. So, the equation is:
[tex](x + 13)^2 + (y + 5)^2 = 13^2 = 169\text{ ....(2)}[/tex]
For station Z at (-5,3), the distance to the epicenter is 5 units. So, the equation is:
[tex](x + 5)^2 + (y - 3)^2 = 5^2=25 \text{ ....(3)}[/tex]
Solving this system of equations will give the coordinates of the epicenter.
Subtract equation (1) from equation (2), we get:
[tex](x^2+26x+169+y^2+10y+25)-(x^2-6x+9+y^2-6y+9) = 144\\\\\text{Simplifying, we get:}\\32x+16y+176=144\\32x+16y = -32\\\text{Divide by 16 on both sides of the equation, we get:}\\2x + y = -2[/tex]
Subtract equation (1) from equation (3), we get:
[tex](x+5)^2+(y-3)^2-(x-3)^2-(y-3)^2 = 0\\x^2+10x+25-(x^2-6x+9)=0\\16x + 16 = 0\\\text{Dividing by 1 on both sides, we get}\\x + 1 =0\\\text{We get:}\\x = -1[/tex]
Putting x = -1 in the equation 2x + y = -2, we get:
2(-1) + y = -2
We get,
y = 0
So, the coordinates of the epicenter of earthquake are (-1, 0).
A worker can assemble 3 shelf units each hour. the same worker can assemble 6 tv stands each hour. if x = hours assembling shelf units, y = hours assembling tv stands, and 24 = total number of furniture pieces made, write a function in standard form modeling the situation.
Answers
Five cans of tomatoes cost $6.50. At this rate, how much will nine cans of tomatoes cost?
Answers
The cost of one can of tomatoes is $1.30, so nine cans at this rate would cost $11.70.
If five cans of tomatoes cost $6.50, to find the cost of nine cans, we first need to find the cost of one can of tomatoes. We do this by dividing the total cost by the number of cans.
Cost per can = Total cost / Number of cans
Cost per can = $6.50 / 5
Cost per can = $1.30
Now that we know how much one can costs, we can find out how much nine cans will cost by multiplying the cost per can by nine.
Total cost for nine cans = Cost per can × Number of cans
Total cost for nine cans = $1.30 × 9
Total cost for nine cans = $11.70
Therefore, nine cans of tomatoes will cost $11.70.
Find the lowest common denominator of and . A. x3y4 B. x2y3 C. xy4 D. x4y5
Answers
For the 'x' term, the highest power is x⁴ and for the 'y' term, the highest power is y⁵
Common denominator of A, B, C, and D: x⁴y⁵
Answer:15 2 3
Step-by-step explanation:
How many ounces of gold are in anan 18-karat gold chain that weighs 2.7 ounces?
Answers
A karat is a measure of the amount of gold in the gold chain. The karat has a maximum value of 24 karats. This means that an 18 karat of gold chain contains 18 parts of pure gold for every 24 parts of gold chain. Therefore:
gold = (18 / 24) * 2.7 ounces
gold = 2.025 ounces
What is the result of dividing x^3-4 by x+2
A. x^2-2x+4+12/x+12
B. x^2-2x+4+4/x+2
C. x^2-2x+4-4/x+2
D. x^2-2x+4-12/x+2
What is the result of dividing 2x^3+x^2-2x+8 by x+2
A. 2x^2+5x+8
B. 2x^2-3x+16
C. 2x^2-3x+4
D. 2x^2+5x-8
What is the remainder when the polynomial 6x^2+11x-3 is divided by 2x-1
Jorge wasnt to divide 3x^2-x-2 by x+4 using synthetic division. (has picture)
Which answer shows the correct process?
What is the remainder when the polynomial 6x^2+11x-3 is divided by x+2
Answers
Write x^3-4 as 1x^3 + 0x^2 + 0x + (-4)x^0
The coefficients here are 1, 0, 0, and -4
note how the exponents step down one at a time (3, 2, 1, 0)
Write the coefficients 1, 0, 0, -4 in that order along a single row. Write the test root x = -2 in a box off to the left of the row of coefficients. See Figure1A (attached) to see how the set up is done so far.
-------------------------
Now we will follow the steps to perform synthetic division. The first step is to drop the first coefficient (which is 1) down below the horizontal line. This is shown by the letter A in red. See Figure1B (attached).
We then multiply that dropped value (1) by the test root (-2) to get 1 times -2 = -2. This result of -2 is placed where you see the red letter B (Figure1B)
Now add straight down: 0 plus -2 = -2
The result -2 is placed just below the previous result. It is placed where you see the red letter C
-------------------------
Repeat these steps over and over until the bottom row is filled out. By that, I mean we have the bottom row terms line up with the right most value in the top row. See figure1C to have a look at what I mean. We stop once we get to -12 in the bottom row as there are no more terms to fill out.
The last term in the bottom row (-12) is the remainder. The other terms help construct the quotient.
In this case, the quotient is 1x^2 + (-2)x + 4x^0 which simplifies to x^2 - 2x + 4
The remainder is -12
Put this all together and we have the final answer of [tex]x^2 - 2x + 4 - \frac{12}{x+2}[/tex]
So the final answer is choice D
===================================================================================================
Problem 2)
Follow the same kind of steps shown in problem 1. This time we'll have the synthetic division table you see in the image Figure2 (attached)
The last value in the bottom row is the remainder. The remainder of 0 indicates (x+2) is a factor of 2x^3+x^2-2x+8
The quotient is the other values in the bottom row. The other values in that bottom row are (in order) 2, -3, 4 so the quotient is 2x^2 - 3x + 4
This makes the final answer to be choice C
===================================================================================================
Problem 3)
We can use the remainder theorem and skip synthetic division
2x-1 = 0 leads to x = 1/2 = 0.5
Plug x = 0.5 into the function f(x) = 6x^2 + 11x - 3 to get
f(x) = 6x^2 + 11x - 3
f(0.5) = 6(0.5)^2 + 11(0.5) - 3
f(0.5) = 4
So the remainder is 4
Answer: 4
Side Note: if you wish to use synthetic division, then check out "Figure3" in the attachments
===================================================================================================
Problem 4)
The answer is choice with the bottom row of 3, -13, and -54. This looks to be choice C. The same steps are followed as done in problems 1 through 3.
===================================================================================================
Problem 5)
Plug x = -2 into f(x) = 6x^2 + 11x - 3
f(x) = 6x^2 + 11x - 3
f(-2) = 6(-2)^2 + 11(-2) - 3
f(-2) = -1
Final Answer: -1
The two numbers with a product of 30 and a sum of 17 are
Answers
_____________________________________________
15 * 2 = 30 .
15 + 2 = 17 .
______________________________________________
The required numbers are "15" and "2".
What is the number system?A number system is defined as a way to represent numbers on the number line using a set of symbols and approaches. These symbols, which are known as digits, are numbered 0 through 9.
Let the first number would be x and the second number would be y
We have been given that the two numbers with a product of 30,
So, x × y = 30
x = 1/y .....(i)
And the sum of 17, then x + y = 17 .....(ii)
Take both equations, then solves them and we get the values that are:
x = 15 and y = 2
So, 15 × 2 = 30 and 15 + 2 = 17
Thus, the required numbers are "15" and "2".
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The number of minutes taken for a chemical reaction if f(t,x). it depends on the temperature t degrees celcius, and the quantity, x grams, of a catalyst present. when the temperature is 30 degrees celcius and there are 5 grams of catalyst, the reaction takes 50 minutes. increasing the temperature by 3 degrees reduces the time taken by 5 minutes. increasing the amount of catalyst by 2 grams decreases the time taken by 3 minutes. use this information to find the partial derivatives fx(30,5) and ft(30,5). use the tangent plane approximation to find f(33,4).
Answers
The partial derivatives fx(30,5) and ft(30,5) can be calculated using the given information, and the tangent plane approximation can be used to estimate f(33,4).
Explanation:The chemical reaction time is represented by the function f(t,x), where t is the temperature in degrees Celsius and x is the quantity of a catalyst present in grams. We are given that when the temperature is 30 degrees Celsius and there are 5 grams of catalyst, the reaction takes 50 minutes. Additionally, increasing the temperature by 3 degrees reduces the time taken by 5 minutes, and increasing the amount of catalyst by 2 grams decreases the time taken by 3 minutes.
To find the partial derivative fx(30,5), we need to find the rate of change of the reaction time with respect to the quantity of catalyst, while holding the temperature constant. Using the given information, we can calculate:
fx(30,5) = (f(30,5+2)-f(30,5))/2 = (-3)/2 = -1.5
To find the partial derivative ft(30,5), we need to find the rate of change of the reaction time with respect to the temperature, while holding the quantity of catalyst constant. Using the given information, we can calculate:
ft(30,5) = (f(30+3,5)-f(30,5))/3 = (-5)/3 = -1.67
Using the tangent plane approximation, we can estimate f(33,4) by calculating the change in reaction time by adjusting the temperature to 33 degrees Celsius and the quantity of catalyst to 4 grams.
f(33,4) = f(30,5) + ft(30,5) * (33-30) + fx(30,5) * (4-5)
f(33, 4) = 50 + (-1.67) * 3 + (-1.5) * -1 = 50 - 5.01 + 1.5 = 46.49
[tex]\( f_t(30,5) = -\frac{5}{3} \)[/tex], [tex]\( f_x(30,5) = -1.5 \)[/tex], [tex]\( f(33,4) \approx 46.5 \)[/tex] minutes.
ft (30, 5) =_[tex]\(-\frac{5}{3} \)[/tex]_ fx (30,5) =_-1.5_ f (33,4)=__46.5 minutes__
To find the partial derivatives [tex]\( f_t(30,5) \)[/tex] and [tex]\( f_x(30,5) \)[/tex], we'll use the given information about how changes in [tex]\( t \) and \( x \)[/tex] affect the time [tex]\( f(t,x) \)[/tex].
Given:
- [tex]\( f(30,5) = 50 \)[/tex] minutes
- Increasing [tex]\( t \)[/tex] by 3 degrees Celsius reduces [tex]\( f \)[/tex] by 5 minutes.
- Increasing [tex]\( x \)[/tex] by 2 grams decreases [tex]\( f \)[/tex] by 3 minutes.
1. Partial derivative with respect to [tex]\( t \) at \( (30,5) \)[/tex]:
- Change in [tex]\( t \): \( \Delta t = 3 \)[/tex] degrees Celsius
- Change in [tex]\( f \): \( \Delta f = -5 \)[/tex] minutes
- Using the definition of partial derivative:
[tex]\[ f_t(30,5) = \frac{\Delta f}{\Delta t} = \frac{-5}{3} = -\frac{5}{3} \text{ minutes/degree Celsius} \][/tex]
2. Partial derivative with respect to [tex]\( x \) at \( (30,5) \)[/tex]:
- Change in [tex]\( x \): \( \Delta x = 2 \)[/tex] grams
- Change in [tex]\( f \): \( \Delta f = -3 \)[/tex] minutes
- Using the definition of partial derivative:
[tex]\[ f_x(30,5) = \frac{\Delta f}{\Delta x} = \frac{-3}{2} = -1.5 \text{ minutes/gram} \][/tex]
Now, to find [tex]\( f(33,4) \)[/tex] using the tangent plane approximation, we'll use the partial derivatives we found and the point [tex]\( (30,5) \)[/tex] as a reference:
The tangent plane approximation formula is:
[tex]\[ f(t,x) \approx f(30,5) + f_t(30,5)(t-30) + f_x(30,5)(x-5) \][/tex]
Substituting the values:
[tex]\[ f(33,4) \approx 50 + \left(-\frac{5}{3}\right)(33-30) + (-1.5)(4-5) \][/tex]
[tex]\[ f(33,4) \approx 50 - 5 + 1.5 \][/tex]
[tex]\[ f(33,4) \approx 46.5 \text{ minutes} \][/tex]
So, [tex]\( f(33,4) \approx 46.5 \)[/tex] minutes.
Thus:
- [tex]\( f_t(30,5) = -\frac{5}{3} \)[/tex] minutes/degree Celsius
- [tex]\( f_x(30,5) = -1.5 \)[/tex] minutes/gram
- [tex]\( f(33,4) \approx 46.5 \)[/tex] minutes
The correct question is:
The number of minutes taken for a chemical reaction if f(t,x). It depends on the temperature t degrees Celsius, and the quantity, x grams, of a catalyst present. When the temperature is 30 degrees Celsius and there are 5 grams of catalyst, the reaction takes 50 minutes. Increasing the temperature by 3 degrees reduces the time taken by 5 minutes. Increasing the amount of catalyst by 2 grams decreases the time taken by 3 minutes. Use this information to find the partial derivatives fx(30,5) and ft(30,5). Use the tangent plane approximation to find f(33,4). ft (30, 5) =__________ fx (30,5) =__________ f (33,4)=__________
Expressions to Radical Form
I always have a hard time with radicals...
Answers
The cube root of -64 is -4
The cr of x^6 is x^2
The cr of y^9 is y^3
Now put these all together:
-4x^2y^3
Hope this helped!
In the number 12,005,999 what is the value of the 2
Answers
a model car is 4inhes long actual car is 15ft long what is the reduced ratio of the model to the actual
Answers
15 ft = 15*12 = 180 inches
180/4 = 45
so the scale is 1/45
What is the r (common ratio) for the geometric sequence: -3, -15, -75, -375, -1875...
Answers
hope this helps
3 x 5 = 15
15 x 5 = 75
75 x 5 = 375
etc
Solve the following equation, answer as a reduced, mixed number.
4(7x - 1) = 3(2x + 1) - 4(x + 6)
Answers
28x-4= 6x+3-4x-24
then we combine like terms and move like terms to the different sided
28x-4=2x-21
26x=-17
x= -17/26
:)
The ratio of boy to girls in a class is 3 : 2. There are 15 boys in the class. How many total boys and girls are in the class?
Answers
E bisects DF, DE=2y, and EF=8y-3. Find DE, EF, and DF
Answers
DF=2
EF=1
DE=1
Evaluate ƒ(x) = 3x + 8 for x = 1.
Answers
Answer: The required value of f(x) for x = 1 is 11.
Step-by-step explanation: We are given to evaluate f(x) for x = 1, where
[tex]f(x)=3x+8~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
To evaluate the required value, we need to substitute x = 1 in expression (i).
So, putting x = 1 in (i), we get
[tex]f(1)=3\times1+8=3+8=11.[/tex]
Thus, the required value of f(x) for x = 1 is 11.
What is the value of the expression 5x+2y y-x2 when x=2 and y =3
Answers
There is a box full of toys. There are four Lego sets, six video games, and five remote control cars. You randomly choose a toy. Find the probability of choosing a remote control car. A. 1/7 B. 7/24 C. 1/3 D. 11/24
Answers
There is a box full of toys. There are four Lego sets, six video games, and five remote control cars. You randomly choose a toy. Find the probability of choosing a remote control car.
Probability means occurrence of chance.
Step 1) Add all the toys
[tex]4+6++5=15[/tex]
There are 5 control cars
[tex]5/15[/tex]
The simplified form would be [tex]1/3[/tex]
Thus, your answer is option C.
Hope I helped (:
Have a great day!
The probability of choosing a remote control car from the box is 1/3, which is calculated by dividing the number of remote control cars (5) by the total number of toys (15).
Explanation:To find the probability of choosing a control car from the box, we use the formula for probability, which is:
Probability = Number of favorable outcomes / Total number of possible outcomes
The number of favorable outcomes is the quantity of remote control cars which is 5. The total number of toys is the sum of all the toys, which are 4 Lego sets + 6 video games + 5 remote control cars = 15 toys in total.
The probability is therefore calculated as:
Probability of choosing a remote control car = 5 (number of remote control cars) / 15 (total number of toys) = 1/3
Hence, the correct answer is C. 1/3.
How is the parent function y=x2 related to the given function Y=3(x+1)2?
Answers
given function: y = g(x) = 3 (x+1)^2
=> g(x) = 3 * f(x + 1)^2
So, from the point of view of graphs, the given function, g(x), is the parent function, f(x) = x^2, shifted one unit to the left and amplified by a factor of 3.
To solve the literal equation 5x = 7t + 6, what is the first step that you must do?
Can anyone help me?
Answers
Find the distance between the points 6 + 5i and 1 – 2i.
Answers
let : z = 6+5i z' = 1-2i
the distance between the points 6 + 5i and 1 – 2i is : |z - z' |
|z - z' | = |6+5i -1+2i| = |5+7i | =√(5²+7²) =√74
Answer:
Approximately 8.6
Step-by-step explanation:
How many solutions are there in the equation below 8x+11=8x+8
Answers
Help please algebra
Answers
hope this helps
A wire is first bent into the shape of a triangle. Each side of the triangle is
12cm long. Then the wire is unbent and reshaped into a square. What is the length of a side of the square?
Answers
The length of a side is 9 square root of 3 or approximately 15.588 cm
Final answer:
By dividing the total length of the wire (36 cm) by the number of sides of a square (4), we find that the length of one side of the square is 9 cm.
Explanation:
We start by calculating the total length of the wire when it was bent into an equilateral triangle. Since each side is 12 cm long and there are three sides, the total wire length is 3 × 12 cm = 36 cm. When the wire is unbent and reshaped into a square, the total wire length remains the same; thus, the perimeter of the square is also 36 cm. A square has four equal sides, so the length of each side of the square is the perimeter divided by four.
Length of one side of the square = Total wire length ÷ 4
Length of one side of the square = 36 cm ÷ 4
Length of one side of the square = 9 cm
Tony ran laps around a track to raise money for a hospital. Tony raised $15 plus $1.50 per lap that he ran. He raised a total of $255.
Let x represent the number of laps Tony ran.
What expression completes the equation to determine the total number of laps Tony ran?
How many laps did Tony run?
Answers
15 + 1.5x = 255
1.5x = 240
x = 160
Tony ran 160 laps.
15 + 1.5x = 255
and 160 laps
ann took a taxi home from the airport. the taxi fare was $2.10 per mile and she gave the driver a $5 tip. Ann paid a total of $49.10. What is an equation to determine the distance in miles from Anns home to the airport?
Answers
(49.1/5)/2.1 = amount of miles it takes to reach Ann's home
Hope this helps!
two parallel lines are coplanar (always,sometimes, or never true)
Answers
Hope this helps! If you have any questions just ask!
Mei draws three pairs of parallel lines that are each intersected by a third line. In each figure, she measures a pair of angles. What is a reasonable conjecture for Mei to make by recognizing a pattern and using inductive reasoning? A. When a pair of parallel lines are intersected by a third line, the alternate interior angles are congruent. B. When a pair of parallel lines are intersected by a third line, the alternate interior angles are acute. C. When a pair of parallel lines are intersected by a third line, all of the angles formed are obtuse. D. When a pair of parallel lines are intersected by a third line, all of the angles formed are congruent.
Answers
The only correct statement among the choices is:
A. When a pair of parallel lines are intersected by a third line, the alternate interior angles are congruent.
This statement can actually be proven by measuring the angles of the alternate interior angles. We can actually see that they have equal measurements. While the adjacent interior angles are supplementary angles.