I need help with this Physics problem. I've been stuck forever:

Two packages at UPS start sliding down the 18° ramp. Package A has a mass of 5.08 kg and a coefficient of friction of 0.18. Package B has a mass of 10.74 kg and a coefficient of friction of 0.13. How long does it take package A to reach the bottom? (s=2.08 m)

Thanks!

Answers

Answer 1
Final answer:

To find the time it takes for Package A to reach the bottom, we need to consider the forces acting on it. The main forces are the gravitational force and the frictional force. By calculating these forces and using Newton's second law and the equation for displacement, we can find the time it takes for Package A to reach the bottom of the ramp.

Explanation:

To find the time it takes for Package A to reach the bottom of the ramp, we need to consider the forces acting on it. The two main forces are the gravitational force pulling it down the ramp and the frictional force opposing its motion.

First, let's calculate the gravitational force acting on Package A. The gravitational force is given by the formula Fg = m × g, where m is the mass of the object and g is the acceleration due to gravity. Given that the mass of Package A is 5.08 kg and the acceleration due to gravity is 9.8 m/s², we can calculate Fg = 5.08 kg × 9.8 m/s² = 49.784 N.

The frictional force can be calculated using the formula Ff = μ × Fn, where μ is the coefficient of friction and Fn is the normal force. The normal force can be calculated using the formula Fn = mg × cos(θ), where θ is the angle of the ramp. Given that θ is 18° and g is 9.8 m/s², we can calculate Fn = 5.08 kg × 9.8 m/s² × cos(18°) = 48.583 N. Now we can calculate the frictional force Ff = 0.18 × 48.583 N = 8.745 N.

The net force acting on Package A is the difference between the gravitational force and the frictional force. Fnet = Fg - Ff = 49.784 N - 8.745 N = 41.039 N. We can use Newton's second law, Fnet = ma, to find the acceleration of Package A. Given that the mass of Package A is 5.08 kg, we have 41.039 N = 5.08 kg × a. Solving for a, we find a = 8.08 m/s².

Finally, we can use the equation s = ut + (1/2)at² to find the time it takes for Package A to reach the bottom, where u is the initial velocity (which is 0 in this case) and s is the distance traveled. Given that s = 2.08 m and a = 8.08 m/s², we have 2.08 m = 0 + (1/2) × 8.08 m/s² × t². Solving for t, we find t ≈ 0.32 s.

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Related Questions

A gas is cooled from 365 K to 285 K while its volume changes from 12.8 L to 9.9 L. The initial pressure of the gas is 1.9 atm.

Answers

Assuming you want the new pressure, PV/T = PV/T , so by extension you'd have (1.9 atm)(12.8 L)/ 365 K = x atm (9.9L)/ 285 K  x= 1.918 atm

This igneous rock contains flattened pieces of pumice and small crystals of quartz and feldspar. what type of eruption probably formed this rock?

Answers

Final answer:

The igneous rock in question, characterized by the presence of flattened pumice and small quartz and feldspar crystals, was likely formed by an explosive volcanic eruption. This is evidenced by the extrusive nature of pumice and the rapid cooling inferred from the small crystal sizes.

Explanation:

The igneous rock described contains flattened pieces of pumice and small crystals of quartz and feldspar. The presence of pumice, which is a vesicular felsic igneous extrusive rock with a very low density such that it can float on water, indicates that the rock was formed during an explosive volcanic eruption. This type of eruption releases lava that cools very quickly on the surface of the Earth, trapping gases within the rock and creating the vesicles or holes that define pumice. Hence, the rock exhibits characteristics of an extrusive igneous rock.

Moreover, the small crystal sizes of quartz and feldspar suggest rapid cooling as well. Large crystals are typically indicative of slow cooling within the Earth's crust, a feature of intrusive igneous rocks like granite. Given these characteristics, it is evident that the rock formed from an explosive eruption, which would have caused the rapid cooling and trapping of gas that are evident in the presence of pumice.

According to a newspaper account, a paratrooper survived a training jump from 1200 ft when his parachute failed to open but provided some air resistance by ï¬apping unopen in the wind. allegedly he hit the ground at 100 mi/h after falling 8 seconds. test the accuracy of this account.

Answers

Final answer:

Determining the plausibility of a paratrooper hitting the ground at 100 mi/h after an 8-second fall involves examining the concept of terminal velocity and the effects of air resistance on falling objects.

Explanation:

The question concerns a paratrooper's descent with a malfunctioning parachute and whether it's plausible for him to hit the ground at 100 mi/h after falling for 8 seconds. To test the accuracy of this account, we must look at the forces involved and the terminal velocity a parachutist can reach. For example, a skydiver with a mass of 75 kg can achieve a terminal velocity of about 350 km/h in a headfirst position, which corresponds to minimizing the area and therefore the drag. Transitioning to a spread-eagle position can decrease this velocity to about 200 km/h, increasing air resistance due to a larger cross-sectional area. However, after a parachute opens, the terminal velocity becomes much smaller. This means that if the parachute provided any air resistance, it's unlikely the paratrooper would be traveling at 100 mi/h (which is approximately 160 km/h) after just 8 seconds.

The paratrooper's reported fall seems plausible as the calculated average acceleration, considering air resistance, is 5.59 m/s².

A paratrooper is reported to have survived a fall from 1200 ft after his parachute failed to open. To verify this account, let's calculate the following:

1. Terminal Velocity Calculation

The paratrooper fell for 8 seconds and allegedly hit the ground at 100 mi/h.

First, convert the velocity and time:

Velocity, v = 100 mi/h = 44.7 m/s

Time, t = 8 s

2. Average Acceleration

We can use the equation of motion, v = u + at where:

u = initial velocity (0, since he started from rest)

v = final velocity (44.7 m/s)

a = acceleration

t = time (8 s)

Rearranging for acceleration, we get:

a = (v - u) / t = 44.7 m/s / 8 s = 5.59 m/s2

3. Free Fall and Air Resistance

In a vacuum, the paratrooper would fall under a gravitational acceleration of 9.8 m/s². Given our acceleration is 5.59 m/s², air resistance played a significant role, slowing his acceleration.

Conclusion

The report's accuracy seems plausible given the average acceleration calculated. However, other factors like the angle of impact and ground conditions would also have contributed to his survival.

Each of the three plates has a mass of 10 kg. if the coefficients of static and kinetic friction at each surface of contact are μs = 0.3 and μk = 0.2 , respectively, determine the acceleration of each plate when the three horizontal forces are applied.

Answers

Even though you forgot to include the diagram of the problem, I found a similar problem as shown in the top of the picture. The diagrams at the bottom are force diagrams of each plate.

For plate D, the forces acting on it are the horizontal force 18 N, and the opposite frictional force which is equal to uk*W = 0.2(10 kg)(9.81 m/s²) = 19.62 N.
F = ma
19.62 N - 18 N = 10 kg(a)
a = 0.162 m/s²

For plate C, the forces acting on it are: horizontal 100 N, and the two opposite frictional forces from the top and bottom plates D and B.
F = ma
100 N - 2(19.62 N) = (10 kg)(a)
a = 6.076 m/s²

For plate B, because A is not moving, we use us instead of uk.
F = ma
0.3(10 kg)(9.81 m/s²) - 15 N = (10 kg)(a)
a = 2.943 m/s²

Final answer:

To calculate the acceleration of each plate, first find the force of kinetic friction using the mass of the plates and coefficients of friction. The acceleration can then be found by applying Newton's second law, considering the net force on each plate after friction is taken into account.

Explanation:

To determine the acceleration of each plate when three horizontal forces are applied, we first need to understand the role of static and kinetic friction. Given each plate has a mass of 10 kg, we can calculate the normal force (N) exerted by each plate, which is necessary for finding frictional forces. The normal force is equal to the weight of the plate, calculated as N = mg, where m is the mass and g is the acceleration due to gravity (9.8 m/s2). Thus, for a 10 kg plate, N = 10 kg × 9.8 m/s2 = 98 N.

The maximum static friction force that must be overcome to start moving the plate is calculated using Fₛ(max) = μsN, where μs is the coefficient of static friction (0.3). Therefore, Fₛ(max) = 0.3 × 98 N = 29.4 N. Once motion begins, the kinetic friction force applies, calculated using Fₘ = μkN, where μk is the coefficient of kinetic friction (0.2). Therefore, Fₘ = 0.2 × 98 N = 19.6 N. To find the acceleration of each plate, we apply Newton's second law of motion (F = ma), subtracting the kinetic friction force from the applied force, and solving for a.

Without specific values for the applied forces in the question, we've laid out the framework to calculate the acceleration. It's important to subtract the kinetic friction force from the applied force to find the net force before applying Newton's second law.

A 2​-liter ​[l] soda​ bottle, made of​ pet, will fail at approximately 207 ​pound-force per square inch​ [psi] of pressure. if you were to dive straight down into the ocean with a 2​-liter bottle, at what depth in units of feet​ [ft] would the bottle​ fail? assume the specific gravity of ocean water is 1.0251

Answers

I like to solve first in SI units. So convert pressure into Pascal.

P = 207 psi = 1.427x10^6 Pa

 

The formula for hydrostatic pressure is:

P = ρ g h

where ρ is density of ocean water = 1025.1 kg/m^3, g is gravity = 9.81 m/s^2, h is height or depth

1.427x10^6 = 1025.1 * 9.81 * h

h = 141.92 m

Convert meters to inches:

h = 141.92 m = 5587.4 inches

If for 1.00 inch there are 2.54 cm, then how many centimeters are in 4.00 ft

Answers

121.92 is the answer I believe

To convert 4.00 feet to centimeters, multiply 4.00 feet by 12 inches per foot to get inches, then multiply the result by 2.54 to convert inches to centimeters. The result is 121.92 centimeters.

To convert 4.00 feet to centimeters, you can use the conversion factors and the chain link method. First, you need to know the basic conversion factors, which are 2.54 cm in 1 inch and 12 inches in 1 foot. Using these conversions:

Convert feet to inches: 4.00 ft ×12 in/ft = 48.00 in

Then convert inches to centimeters: 48.00 in ×2.54 cm/in = 121.92 cm

Therefore, there are 121.92 centimeters in 4.00 feet.

Consider a box sitting in the back of a pickup. The pickup accelerates to the right, and because the bed of the pickup is sticky, the box does not slide around the truck when this happens.What direction is the force acting on the box due to the truck?

Answers

Final answer:

The force acting on a box in the back of a pickup truck, which accelerates forward, is due to static friction and is directed forward. This force ensures the box accelerates at the same rate as the truck, preventing it from sliding.

Explanation:

When a pickup truck accelerates forward, the force acting on a box due to the truck is directed forward. This force is the result of static friction between the box and the bed of the truck. The static friction force prevents the box from slipping by providing the necessary force to accelerate the box at the same rate as the truck. If the truck accelerates to the right, the frictional force acting on the box is also to the right. This force is a reaction to the box's tendency to remain in its state of rest, according to Newton's first law of motion, which says that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

The calculation of the maximum distance the truck can travel without the box sliding involves determining the static frictional force and using it to find the acceleration of the box. Given the coefficient of static friction (μ) is 0.24, and assuming the acceleration of gravity (g) is approximately 9.8 m/s², we use the equation for static friction F_s = μ N, where N is the normal force, equivalent to the weight of the box if we assume a horizontal surface and neglect air resistance.

The key to understanding this problem lies in recognizing the role of static friction in causing the box to accelerate together with the truck, rather than sliding. If the bed of the truck provides sufficient friction, it enables the box to move as one with the vehicle, demonstrating the practical application of Newton's laws of motion.

The force acting on the box due to the truck is directed to the right.

When the pickup truck accelerates to the right, a force is exerted on the box due to the truck bed's friction. Since the bed of the truck is sticky, the box does not slide. The direction of the frictional force acting on the box is also to the right, in the same direction as the truck's acceleration.

Here's a step-by-step explanation:

The truck accelerates to the right.The surface of the truck bed exerts a frictional force on the bottom of the box to prevent it from sliding.This frictional force acts to the right, matching the truck's acceleration direction.According to Newton's third law of motion, every action has an equal and opposite reaction, so the box exerts a force back on the truck bed, but this doesn’t change the direction of the frictional force acting on the box.

Therefore, the force acting on the box due to the truck is to the right.

If earth had no landmasses, then the idealized zonal precipitation pattern would have _______.

Answers

If the planet earth has no land masses, the idealized zonal precipitation pattern would likely have regions that are wet in the equator and there will be more of mid-latitudes if the earth has no land masses at all and it does not exist.

Four 8.5 kg spheres are located at the corners of a square of side 0.52 m. calculate the magnitude and direction of the gravitational force exerted on one sphere by the other three. magnitude

Answers

3.4x10^-8 N of force directly towards the sphere in the opposite corner of the square. The gravitational attraction of two masses towards each other is F = G(m1m2/r^2) where G = gravitational constant m1,m2 = masses r = distance between the centers of the masses. So the force being exerted by the masses alone an edge of the square would be F = 6.674x10^-11 N(m/kg)^2 * ((8.5 kg)^2)/((0.52m)^2) F = 6.674x10^-11 N(m/kg)^2 * (72.25 kg^2)/(0.2704 m^2) F = 6.674x10^-11 N(m/kg)^2 * 267.1967 (kg/m)^2 F = 1.78327x10^-8 N There are 2 masses that affect a mass on a corner so that the sum of their vectors will result in a 3rd vector aiming towards the mass in the diagonal corner. So sqrt(2(1.78327x10^-8 N)^2) = 2.52193x10^-8 N The mass in the diagonal corner will also be attracting. The distance to that mass is sqrt(2*(0.52m)^2) = 0.735391052 m F = 6.674x10^-11 N(m/kg)^2 * ((8.5 kg)^2)/(2*(0.52m)^2) F = 6.674x10^-11 N(m/kg)^2 * (72.25 kg^2)/(0.5408 m^2) F = 6.674x10^-11 N(m/kg)^2 * 133.5984 (kg/m)^2 F = 8.916355x10^-9 N This vector will be along the same line as the combined vector from the other 2 masses, so they'll add directly. F = 8.916355x10^-9 N + 2.52193x10^-8 N = 3.4136x10^-8 N Since we have 2 significant figures in our data, the result rounded to 2 significant figures is 3.4x10^-8 N
Final answer:

The magnitude of the gravitational force exerted on one sphere by the other three can be calculated using Newton's Law of Universal Gravitation. Using the given information, the magnitude of the gravitational force is approximately 2.97 x 10^-8 N.

Explanation:

The magnitude of the gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation:



Fg = (G * m1 * m2) / r2



Where Fg is the gravitational force, G is the gravitational constant (approximately 6.67 x 10-11 Nm2/kg2), m1 and m2 are the masses of the objects, and r is the distance between the centers of the objects.



In this case, the mass of each sphere is 8.5 kg and the distance between their centers is 0.52 m.



Calculating the gravitational force between one of the spheres and the three others, we use the formula and plug in the values:



Fg = (6.67 x 10-11 * 8.5 kg * 8.5 kg) / (0.52 m)2



Calculating the result, the magnitude of the gravitational force exerted on one sphere by the other three is approximately 2.97 x 10-8 N.

What's the steady state theory

Answers

Answer:

A theory explaining the model of the Universe.

Explanation:

Steady State theory, proposed in 1948 by Sir Hermann Bondi, Thomas Gold, and Sir Fred Hoyle, suggests that the universe is always expanding while maintaining a constant average density. This is achieved as matter is continuously created to form new stars and galaxies at the same rate as that of old ones becoming non-observable. This occurs as a consequence of increasing distance and velocity of recession of old stars and galaxies.

As per this theory, Universe has no beginning and no end in time. If looked at it from a grand scale, the arrangement of galaxies and average density remain same.

Later observation of the Universe gave results contradictory to Steady State Theory. This has led to increase in support of Big Bang Model of the Universe.

The steady state theory in systems theory means state variables do not change over time, and in chemical kinetics, it refers to the steady-state approximation where an intermediate's concentration is assumed constant, aiding in the analysis of complex reactions.

The steady state theory refers to a concept in systems theory where a system or process is said to be in a steady state if its state variables, which define the behavior of the system, are not changing over time. In the context of chemical kinetics, this often pertains to the steady-state approximation, where the concentration of an intermediate in a reaction is assumed to be constant over time because its formation rate is equal to its consumption rate. This approximation simplifies the mathematical analysis of complex reactions and is particularly useful in enzyme kinetics, as proposed by Briggs & Haldane in 1925.

The steady-state assumption does not imply that the system is static or that there is an absence of reaction fluxes. Rather, it means that even though reactions are occurring and products are being formed, the internal metabolite concentrations and the fluxes (input and output fluxes) are maintained constant over time. This is a critical simplification that aids in metabolic modeling and the analysis of enzymatic reactions.

What wave phenomenon is responsible for the sunlight shown in this diagram? A.)Diffraction, because light is bent around the clouds B.)Refraction, because the light bends through the clouds C.)Absorption, because the sunlight is absorbed by the clouds D.)Transmission, because the sunlight travels through the clouds

Answers

A) DIFFRACTION, because light is bent around the clouds" is the correct answer.

A.)Diffraction, because light is bent around the clouds

The current in a hair dryer measures 17 amps. The resistance of the hair dryer is 14 ohms. What is the voltage?

Answers

voltage is 238 volts

An increase in wind speed will cause the temperature of a leaf to ______. assume all other parameters of the leaf environment remain unchanged.

Answers

decrease. as the temperature is effected by 1. air humidity 2. air movement 3. light and so on

The level of water in an olympic size swimming pool (50.0 meters long, 25.0 meters wide, and about 2.00 meters deep) needs to be lowered 6.50 cm. if water is pumped out at a rate of 4.20 liters per second, how long will it take to lower the water level 6.50 cm

Answers

We need to start by finding the surface area of the pool.
50 meters multiplied by 25 meters gives us 1250 square meters.
1250 square meters multiplied by .065 (6.5 cm in meters) gives us a volume of 81.25 cubic meters of water that needs to be pumped out of the pool.

There are 1000 liters in a cubic meter so this is 81250 liters. Divide by 4.2 to find the number of seconds required to pump out this much water and we get 19345.2 seconds. This equals approximately 5.37 hours.
Final answer:

First, the cubic volume of water to be removed is calculated by multiplying length, width, and reduced depth of the pool. This equates to 81.25 cubic meters, which is 81250 liters. The time is then calculated by dividing total volume by pump rate, equating to 19345 seconds or approximately 5.40 hours.

Explanation:

The subject of this question is related to applied mathematics, specifically about volume and rates.

In order to determine how long it will take to lower the water level in the pool, first, we need to calculate the volume of the water to be removed. The volume can be calculated by multiplying the length, width, and height of the swimming pool. However, since we want the height to be 6.50 cm or 0.065 m, we use that as our height.

Volume = length x width x height = 50.0 m x 25.0 m x 0.065 m = 81.25 cubic meters. Since 1 cubic meter is equivalent to 1000 liters, the volume of water to be removed is 81250 liters.

Given that the pump removes water at a rate of 4.20 liters per second, we can determine the time by dividing the total volume by the rate of the pump.

Time = volume / rate = 81250 liters / 4.20 liters/sec = 19345 seconds or approximately 5.40 hours.

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A ball rolls 6.0 meters as its speed changes from 15 meters per second to 10 meters per second. What is the average speed of the ball as it rolls the 10 meters? 1) 2.5m/s 2) 10m/s 3) 12.5m/s 4) 15m/s (Please show calculation)

Answers

Initial speed, u = 15 m/s
Final speed, v = 10 m/s
Distance traveled, s = 6.0 m

The acceleration, a, is determined from
u² + 2as = v²
(15 m/s)² + 2*(a m/s²)*(6.0 m) = (10 m/s)²
225 + 12a = 100
12a = -125
a = -10.4167 m/s²

The time, t, for the velocity to change from 15 m/s to 10 m/s is given by
(10 m/s) = (15 m/s) - (10.4167 m/s²)*(t s)
10 = 15 - 10.4167t
t = 0.48 s

The average speed is
(6.0 m)/(0.48 s) = 12.5 m/s

Answer: 12.5 m/s

The average speed of the ball cannot be accurately determined without the total time or rate of deceleration. However, if we are simply looking for the average of the initial and final speeds, it would be 12.5 m/s.

The question involves calculating the average speed of a ball given its initial and final speeds. However, there is a discrepancy in the question as it initially mentions the ball rolls 6.0 meters but then asks for the average speed over 10 meters. Assuming the correct distance is 6.0 meters, the calculation of average speed requires us to know the total distance traveled and the total time taken.

To find the average speed, we use the formula:

Average Speed = Total Distance ÷ Total Time

The total distance traveled by the ball is given as 6.0 meters. Since we do not have the total time, we cannot calculate the average speed directly. Additionally, it's said that the ball's speed changes from 15 m/s to 10 m/s, which means that it is decelerating. However, with the information provided, we cannot accurately determine the ball's average speed without additional details such as the rate of deceleration or the time taken.

Assuming a typo in the question and that it's asking for the average of the initial and final speeds instead, we could simply calculate it by:

Average Speed = (Initial Speed + Final Speed) ÷ 2

In this case:

Average Speed = (15 m/s + 10 m/s) ÷ 2 = 12.5 m/s

However, this calculation assumes a linear change of speed, which might not be the case in a real-world scenario.

Category 5e twisted pair can run farther than 100 meters from its source to its final destination, as long as the signal is regenerated at least every ____ meters.

Answers

Cat 5e must be regerated every 100 meters to stay within specification.

Matter's resistance to a change in motion is called _____ and is directly proportional to the mass of an object. For an object to change its state of motion, a force must be applied to it?

Answers

Inertia

A bowling ball has a higher inertia than bowling pins, as it weighs significantly more than the pins.
Inertia is your answer that goes in the blank space

did a reaction happen in the erlenmeyer flask? how can you tell?

Answers

cause i saw it and i know it

Final answer:

To determine if a reaction happened in an Erlenmeyer flask, you can observe indicators such as color change, formation of a precipitate, and gas evolution.

Explanation:

In order to determine if a reaction happened in the Erlenmeyer flask, you can observe several indicators:

Change in color: If the original reactants and the product have different colors, it suggests that a reaction took place.Formation of a precipitate: If a solid substance appears in the solution, it indicates the formation of a new compound.Gas evolution: If bubbles or a gas is produced, it signifies that a reaction occurred.

Additionally, other observations such as the release of energy (exothermic reaction) or absorption of energy (endothermic reaction) can provide further evidence of a reaction.

Your skeleton. It is there for support, protection, and movement. But you could not move your bones without the help of your ______________ system. A) digestive B) gland C) immune D) muscular\

Answers

I believe the answer is D.) the muscular system
The answer would be 
D) muscular

Henry takes a boat ride for 15 minutes to reach his destination. If the boat was traveling at 6 meters/second, how far did the boat travel?

Answers

Do 6 * 60 * 15
The answer is 5,400
The boat traveled 5,400 meters or 5.4 km (3.355 mi)

Answer: The distance traveled by boat is 5400 meters.

Explanation:

Speed is defined as the ratio of distance traveled to the time taken.

To calculate the distance traveled by boat, we use the equation:

[tex]\text{Spped of the boat}=\frac{\text{Distance traveled}}{\text{Time taken}}[/tex]

We are given:

Speed of the boat = 6 m/s

Time taken = 15 mins = 900 s     (Conversion factor:   1 min = 60 s)

Putting values in above equation, we get:

[tex]6m/s=\frac{\text{Distance traveled by boat}}{900s}\\\\\text{Distance traveled by boat}=(6m/s\times 900s)=5400m[/tex]

Hence, the distance traveled by boat is 5400 meters.

A rocket car is traveling at a constant speed of 250 km/h on a salt flat. the driver gives the car a reverse thrust, and the car experiences a continuous and constant deceleration of 8.25 m/s2. how much time elapses until the car is 175 m from the point where the reverse thrust is applied?

Answers

3.086 seconds.

First, convert 250 km/h into m/s by multiplying by 1000 (to convert km to m) and dividing by 3600 to convert per hour to per second. Doing 250 * 1000 / 3600 gives you a speed of 69.4444 m/s.

Now under constant acceleration, the formula for distance is:

1/2 A T^2

Since A = -8.25 (negative since it's deceleration) we get

1/2 * (-8.25) * T^2

giving

-4.125 T^2

The total distance traveled then becomes the original velocity multiplied by the time plus the distance for the acceleration, giving

69.4444 T - 4.125 T^2 = 175

Doing a bit of reordering, we get a standard looking quadratic equation

-4.125 T^2 + 69.4444 T - 175 = 0

Plugging the values of A = -4.125, B = 69.4444, C=-175 into the quadratic formula gives you two solutions.

First solution is 3.086 seconds

and the second solution is 13.750 seconds.

The physical interpretation of those 2 answers is that 3.086 seconds after the reverse thrust is applied, the vehicle is 175 meters from the spot where the thrust was applied. The vehicle continues to decelerate until it comes to a complete stop. Then the vehicle goes into reverse and after a total of 13.75 seconds, once again is at a point 175 meters from where it had applied the reverse thrust. We can use that information to double check our answer. Namely at the mid point between 3.086 seconds and 13.75 seconds, the rocket car should be motionless. Let's check if that's correct.

(3.086 + 13.75) / 2 = 8.418 seconds

Given a velocity of 69.44444 m/s and a deceleration of 8.25 m/s^2, the vehicle should stop after

69.44444 / 8.25 = 8.418 seconds

Since those two independent calculations of when the vehicle would stop the match, it's a good check that the math is correct.

A ball is thrown upward from the ground with an initial speed of 22.0 m/s; at the same instant, another ball is dropped from a building 16 m high. after how long will the balls be at the same height

Answers

they will  be together in 8 minutes

Atoms that are alike combine to form the next stage of matter, which is a(n) ____

Answers

Molecule. The answer is molecule. Alike atoms combine to form molecules. An example is Hydrogen molecule which is H₂. Another example is O₂ which is an oxygen molecule. Hope I helped. Good luck

a ball is thrown straight up it passes a 2.00 m high window 7.5 meters off the ground on its path up it takes 1.3 s to go past the window. what was the balls initial velocity?

Answers

Let's say the velocity at the bottom of the window was "v."
s = v*t + ½at²
2 m = v * 1.3s - 4.9m/s² * (1.3s)² = v * 1.3s - 8.3 m
v = 10.3m / 1.3s = 7.9 m/s

Then the initial speed was
V = √(v² + 2as) = √(7.9m/s² + 2 * 9.8m/s² * 7.5m) = 14 m/s ◄ initial velocity
(after rounding to 2 digits from 14.5 m/s).

Final answer:

The initial velocity of the ball is approximately 14.9 m/s, found using kinematic equations considering the ball's upward motion against gravity over 1.3 seconds to pass a 2.00 m high window.

Explanation:

To determine the initial velocity of a ball thrown straight up, we can use the kinematic equations for uniformly accelerated motion. The ball passes a 2.00 m high window that starts 7.5 meters above the ground, and it takes 1.3 seconds to pass by the window. We'll use the following kinematic equation:

s = ut + 1/2at²

where s is the displacement (the height of the window), u is the initial velocity we want to find, t is the time (1.3 seconds), and a is the acceleration due to gravity (approximately -9.81 m/s², since it's upwards).

Plugging in the values, we have:

2.00 m = u(1.3 s) + 1/2(-9.81 m/s²)(1.3 s)²

Solving for u, the initial velocity of the ball is calculated to be the positive root of the resulting quadratic equation. After performing the algebraic manipulation, we find that the initial velocity is approximately 14.9 m/s.

What volume of .2500 m cobalt iii chloride is required to react completely with 25 ml of .0315 m calcium hydroxide?

Answers

f 0.0315 M calcium hydroxide?Co2(SO4)3 + 3Ca(OH)2---> 2Co(OH)3+ 3CaSO4 Co Sulfate and Ca hydroxide react

could you mark as brailiest

What is the acceleration of a ball rolling down a ramp that starts from rest and travels 0.9 m in 3 s?

Answers

Given:
u = 0, initial velocity
s 0.9 m, distance traveled.
t = 3 s, the time taken.

Let a =  the acceleration. Then
s = ut + (1/2)*a*t²
(0.9 m) = 0.5*(a m/s²)*(3 s)²
0.9 = 4.5a
a = 0.2 m/s²

Answer: 0.2 m/s²

Final answer:

The acceleration of the ball rolling down the ramp is 0.2 m/s^2, calculated using the equation of motion for uniformly accelerated movement without initial velocity.

Explanation:

To calculate the acceleration of a ball that starts from rest and travels a certain distance down a ramp over a known time period, we can use the equations of motion for uniformly accelerated motion. It is given that the ball travels 0.9 meters in 3 seconds from rest.

The equation that relates distance (s), initial velocity (u), time (t), and acceleration (a) is:


s = ut + \frac{1}{2}at^2

Since the initial velocity u is 0 m/s (because the ball starts from rest), the equation simplifies to:


s = \frac{1}{2}at^2

Rearranging this equation to solve for acceleration yields:


a = \frac{2s}{t^2}

Plugging in the given values:


a = \frac{2 * 0.9 m}{(3 s)^2} = \frac{1.8 m}{9 s^2} = 0.2 m/s^2

Therefore, the acceleration of the ball is 0.2 m/s2.

The peripheral nervous system consists of __________ that link the central nervous system with all parts of the body.

Answers

Answer- Communication Lines

What is the weight in newtons of an object that has a mass of 610 mg?

Answers

To answer this question, you need to know the gravity power used for this equation. Let assume the gravity is 9.8N/kg. Then to find the mass, you need to multiply the weight with gravitational acceleration. The equation would be:

mass= weight x gravity
mass= 610mg x 10^-6 kg/mg x 9.8N/kg= 5978 x 10^-6= 5.978 x 10^-3

85) List and discuss the structures of a long bone. 86) Discuss the organization of the five regions of the spine. 87) Explain how atlas and axis are different from other vertebrae. Discuss the roles they play in the body. 88) Differentiate among the three types of joints based on structural and functional classification. Provide examples of each type of joint.

Answers

85)
The bone structure from outside would be periosteum, cortical, cancellous then medulla. Periosteum is the area outside the bone that will supply nutrition into the outer part of the bone. Cortical is the layer where bone mineral deposition is intense. In this part, the bone is compact and hard. This is the part of the bone that has great strength.
Cancellous is part of the bone where it is not too hard but not too soft. Mineralization is not so dense like cortical layer. That makes this part looks spongy. 
In the medulla, most part is made from connective tissue and blood vessels. This part is responsible for the bone vascularization, which means the supply of mineral to the outer part is coming from the medulla. Mineralization is not much in the medulla, makes it not strong. Medulla or marrow also makes blood cells.

86)
The region of the spine would be cervical(neck), thoracal(chest), lumbar(back), sacrum then coccyx. The vertebrae in the neck are smaller since it did not need much strength but need more mobility. Lower part on the thoracal and lumbar is bigger and have a bigger process that will further stabilize the vertebrae. Thoracal vertebrae have a part on their side where the ribs attached. Sacrum shape was a kinda weird because it needs to be able to connect with the pelvis to make buttock. Coccyx the tailbone look like just a small remnant and doesn't seem to have a function in human.

87)
Axis is the name of cervical 2nd vertebral which was located below the atlas, 1st cervical vertebrae. Both of them doesn't have spinal processes that were stabilizing the side of vertebrae Axis also has an odontoid peg which will make the joint with atlas more flexible.
This effect makes the neck can turn to side easily. It also makes neck more mobile vertically, make a nodding movement is possible.
88)
Thre kind of joints would be: Synarthrosis, amphiarthrosis, and diarthrosis.
In synarthrosis, the joint mostly made by fibrous so that it can move. The example of this joint would be suture in the skull. In children, the skull joint is not closed to permit the head to grow but in the adult, it is closed. 
Amphiarthrosis joint permits a small movement. This included the intervertebral disc.
Diarthrosis permit a wide degree of movement. This joint is more complex because it has the synovial membrane. The complex structure makes the joints more durable to shock. This was vital because organ with this join used frequently. The example of this joints would be femur and pelvic(hip) joints. Joints in arm and leg mostly diarthrosis joint.

In what way do acids affect your body?

Answers

everyway, if it touch your skin it can damage it
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