Answer:
0.
Step-by-step explanation:
We can do this by substitution of -2 The numerator will tend to 0.
The denominator will always be positive so the limit is 0.
what is the function, domain and range of {(1,1) (2,2) (3,5) (4,10) (5,15)}?
Step-by-step explanation: To determine whether the relation shown here is a function, it's important to understand that a function is a relation in which each x-term corresponds to exactly one y-term.
Each of the x-terms shown here 1, 2, 3, 4, and 5 appears only once so each x-term corresponds to only one y-term. So yes, this relation is a function.
The domain of a relation is the set of all the x-terms of the relation. So here, the domain will be the set of all the x-terms or {1, 2, 3, 4, 5}.
The range of a relation is the set of all the y-terms of the relation. SO here, the range will be the set of all the y-terms or {1, 2, 5, 10, 15}.
what is the correct answer to the question
Answer:
4.37%
Step-by-step explanation:
Given: Value of object in 1997 is $5000
Value of object in 2012 is $4500.
Number of years (2012-1997)= 15 years
∵We know that there is growth in value of object over multiple years.
∴Compound annual growth rate (CAGR)= [tex][(\frac{end\ value}{initial\ value} )^{\frac{1}{n} } ] -1[/tex]
Remember, n = number of years
∴ Growth rate= [tex][(\frac{9500}{5000} )^{\frac{1}{15} } ]-1[/tex]
⇒Growth rate= [tex][(1.9)^{\frac{1}{15} } -1][/tex]
⇒Growth rate= [tex](1.9)^{0.0667} -1= 1.0437-1[/tex]
⇒ Growth rate= 0.0437
Now, finding percentage of growth rate
∴ [tex]0.0437\times 100= 4.37\%[/tex]
∴ Annual growth percent over the period of time is 4.37%
Find the product of 400 and 9.460730473 times 10/15
Final answer:
To find the product, multiply 400 by 9.460730473, then multiply the result by 2/3.
Explanation:
To find the product of 400 and 9.460730473 times 10/15, we need to multiply the three numbers together. First, let's simplify 10/15 to 2/3. Then, multiply 400 by 9.460730473 to get the product. Finally, multiply the result by 2/3 to find the final answer.
400 x 9.460730473 = 3784.2921892
3784.2921892 x 2/3 = 2522.8614595
The product of 400, 9.460730473, and 10/15 is approximately 2522.8614595.
Which system of equations has no solutions
A. 3x + 4y = 5
6x + 8y = 10
B. 7x - 2y = 9
7x - 2y = 13
C. 2x - y = -11
-2x + y = 11
D. 3x + 6y = 1
x + y = 0
Answer:
Step-by-step explanation:
3x+4y=5
6x+8y=10
---------------
-2(3x+4y)=-2(5)
6x+8y=10
----------------
-6x-8y=-10
6x+8y=10
------------------
0=0
Answer: Infinitely many solutions.
------------------------------------------------------
7x-2y=9
7x-2y=13
--------------
-1(7x-2y)=-1(9)
7x-2y=13
---------------------
-7x+2y=-9
7x-2y=13
-------------
0=4
Answer: NO Solution.
-------------------------------------
2x-y=-11
-2x+y=11
-----------------
0=0
Answer: Infinitely many solutions.
-----------------------
3x+6y=1
x+y=0
x=0-y=-y
3(-y)+6y=1
-3y+6y=1
3y=1
y=1/3
x=-y=-1/3
Answer: x=-1/3, y=1/3. (-1/3, 1/3).
Answer:69
Step-by-step explanation:
69
What is 9 divided by 883
choose the abbreviation of the postulate or theorem that supports the conclusion that the triangles are congruent. Given: C, F are rt. (angles) ; AB = DE ; BC = EF
HL
LL
HA
LA
Answer:
The abbreviation of the postulate or theorem that supports the conclusion that the triangles are congruent.
HL.
Step-by-step explanation:
The Figure is attached below
Given:
AB = DE ; BC = EF
∠C = ∠F = 90°
To Prove:
ΔACB ≅ ΔDFE
Proof:
Hypotenuse Leg Theorem:
The hypotenuse leg theorem states that any two right triangles that have a congruent hypotenuse and a corresponding, congruent leg are congruent triangles.
The abbreviation is HL
In ΔACB and ΔDFE
AB ≅ DE ……….{Hypotenuse congruent Given}
BC ≅ EF ……….{Given}
∠C ≅ ∠F = 90° …………..{Measure of each angle is 90° given}
ΔACB ≅ ΔDFE ….{Hypotenuse Leg ( HL ) Theorem}
Answer:
HLStep-by-step explanation:
ODYSSEY
What is the domain of the rational function, f of x equals quantity x minus 5 over quantity 2 times x minus 3
The domain of the function f(x) = (x - 5) / (2x - 3) is all real numbers except for x = 3/2 because this value would cause the denominator of the function to be zero, which is undefined.
Explanation:The domain of a function refers to all possible values that can be inputted into the function, or 'x' values. For a rational function, such as f(x) = (x - 5) / (2x - 3), it is important to note that the function is undefined for values of x that would make the denominator equal zero. Because functions cannot have a denominator of zero, these values should be excluded from the domain.
To find these values, you would set the denominator equal to zero and solve. Thus, 2x - 3 = 0. Solving this, x = 3/2. Therefore, all real numbers except for x=3/2 are in the domain for this rational function.
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Use the figure below.
Which best describes the pair of angles:
24 and 25?
A. vertical
B. adjacent
C. linear pair
D. complementary
Answer: B. Adjacent
Step-by-step explanation: They share a common side and vertex
A 5 pairs of jeans and 2 sweatshirts costs $233, while 3 pairs of jeans and 4 sweatshirts costs $193. Find the cost of one sweatshirt.
The cost of one sweatshirt is $19.
Step-by-step explanation:
Let,
Cost of one pair of jeans = x
Cost of one sweatshirt = y
According to given statement;
5x+2y=233 Eqn 1
3x+4y=193 Eqn 2
Multiplying Eqn 1 by 2
[tex]2(5x+2y=233)\\10x+4y=466\ \ \ Eqn\ 3[/tex]
Subtracting Eqn 2 from Eqn 3
[tex](10x+4y)-(3x+4y)=466-193\\10x+4y-3x-4y=273\\7x=273[/tex]
Dividing both sides by 7
[tex]\frac{7x}{7}=\frac{273}{7}\\x=39[/tex]
Putting x=39 in Eqn 2
[tex]3(39)+4y=193\\117+4y=193\\4y=193-117\\4y=76[/tex]
Dividing both sides by 4
[tex]\frac{4y}{4}=\frac{76}{4}\\y=19[/tex]
The cost of one sweatshirt is $19.
Keywords: linear equation, subtraction
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There are 110 students in the 6th grade band and 120 students in the 7th grade band. Of the students, 60% of the 6th grade band members and 85% of the 7th grade band members went on a trip Disney World trip. How many more 7th graders went on the trip than 6th graders?
Answer:
36 more students of grade 7 went on a trip than students of grade 6
Step-by-step explanation:
60 % of 110 students= 60/100*110= 66 students
85 % of 120 students= 85/100 * 120= 102 students
No of students of grade 7th more than 6th grade students= 102-66= 36
60% of the 6th grade band members and 85% of the 7th grade band members went on a trip Disney World trip. Then 36 more 7th graders went on the trip than 6th graders
What is Percentage?percentage, a relative value indicating hundredth parts of any quantity.
Given,
The number of students in 6th grade=100
The number of students in 7th grade=120
60% of the 6th grade band members
60%×110
60/100×110=0.6×110=66
85% of the 7th grade band members
85%×120=85/100×120
=0.85×120=102
We need to find how many more 7th graders went on the trip than 6th graders
For this we need to find difference of 7th and 6th grade
102-66=36
Hence 36 more 7th graders went on the trip than 6th graders
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geometry thanks if you help!
Answer:
D
Step-by-step explanation:
For a function to be true, there cannot be the same x used for two different ys. D is the only table that follows this rule.
solving eqations
4c=16
Answer:
c=4
Step-by-step explanation:
Answer:
C=4
Step-by-step explanation:
when solving these equations you have to get the letter by itself and in this case the 4 is being multiplied by the c so you have to do the opposite and divide the 4 from the c and divide 16 by 4 because what you do to one side of the equal sign you have to do to the other side.
If you awnser this question please include work
Answer:
3/2
Step-by-step explanation:
2+1=3
3*3/2=4.5
it would not make sense if it was 2/3 cuz look what u get.......
3*2/3=2
Answer:
When x increases by 1, y increases by 3/2 = 1.5Step-by-step explanation:
If x and y are proporttional then
[tex]\dfrac{y}{x}=costant\to\dfrac{y}{x}=a\to y=ax[/tex]
From the table we have x = 2 and y = 3.
Substitute:
[tex]3=2a[/tex] divide both sides by 2
[tex]\dfrac{3}{2}=\dfrac{2a}{2}\\\\\dfrac{3}{2}=a\to a=\dfrac{3}{2}[/tex]
Therefore we have:
[tex]y=\dfrac{3}{2}x[/tex]
We increase x by 1:
[tex]y_1=\dfrac{3}{2}(x+1)[/tex] use the distributive property
[tex]y_1=\underbrace{\dfrac{3}{2}x}_{y}+\dfrac{3}{2}\Rightarrow y_1=y+\dfrac{3}{2}[/tex]
help pleaseeeeeeeee
Answer:
No, we can't.
Step-by-step explanation:
Let x be the amount of time it takes each machine to make 1 cockpit, and y be the amount of time it takes each machine to make 1 propulsion system.
For machine A: 22 hours to produce 3 cockpits and 5 propulsion system.
For machine B: 44 hours to produce 6 cockpits and 10 propulsion system.
So, this will produce the following system of equations:
3x + 5y = 22 ⇒(1)
6x + 10y = 44 ⇒(2)
We can note that the second equation is two times the first equation.
So, the two equation are actually represent one equation.
OR, by another way the two equation have the same slope and y-intercept
So, the two equation are identical, therefore, we can't solve one equation with two variables.
Also, see the attached figure.
equation (1) with blue color and the second equation with red color.
In Exercise #13 above, how many different combinations would be possible if the three numbers do not have to be different (for example, 20-20-20 could be a combination)?
Answer:
116 280
Step-by-step explanation:
number of combination = 20 x 19 x 18 x 17 = 116 280
HOPE THIS HELPED ;3
The number of different combinations are there if the numbers must be all different is 19380.
What is a combination?Combinations are selections made by taking some or all of a number of objects, irrespective of their arrangements. The number of combinations of n different things taken r at a time, denoted by nCr and it is given by, nCr=n!/r!(n−r)!,where 0 ≤ r ≤ n.
Given that, a combination lock has 20 numbers on it.
Different three-number combinations
= 20!/3!(20-3)!
= 20×19×18×17!/3!×17!
= 20×19×18×17/(3×2×1)
= 10×19×6×17
= 19380
Therefore, the number of different combinations are there if the numbers must be all different is 19380.
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"Your question is incomplete, probably the complete question/missing part is:"
A combination lock has 20 numbers on it. How many different three-number combinations can be made? How many different combinations are there if the numbers must be all different?
Order from least to greatest.
5
12
,
2
3
,
1
2
,
5
6
,
3
4
A)
3
4
,
5
6
,
2
3
,
1
2
,
5
12
B)
5
12
,
1
2
,
2
3
,
3
4
,
5
6
C)
1
2
,
2
3
,
3
4
,
5
6
,
5
12
D)
1
2
,
2
3
,
5
6
,
3
4
,
5
12
the answer is c
Step-by-step explanation:
12
23
34
56
512
the answer is c
Step-by-step explanation:
12
23
34
56
Ben saved $66 and spent $30. What percentage of his money did he spend? Round your answer to the nearest whole percent
Answer: 50%
Step-by-step explanation:
Answer: Nope it's 55%
Step-by-step explanation:
A students cost for last semester at her community college was $2800. She spent $504 of that on books. What percent of last semesters college cost was spent on books
Answer: 18%
Step-by-step explanation:
The percentage spent on book = cost of books / total cost x 100
% spent on book = 504/2800 x 100
= 18
Therefore , the percentage spent on book is 18
If g(x) is the inverse of f(x) and S(x) = 4x+12, what is g(x)?
g(x) = 12x + 4
g(x) = 4x12
g(x) = x= 3
8(t) = 1x-3
Answer:
[tex]g(x)=\frac{1}{4}x-3[/tex]
Step-by-step explanation:
we have
[tex]f(x)=4x+12[/tex]
Find the inverse
step 1
Let
y=f(x)
[tex]y=4x+12[/tex]
step 2
Exchange the variables (x for y and y for x)
[tex]x=4y+12[/tex]
step 3
Isolate the variable y
we have
[tex]x=4y+12[/tex]
Subtract 12 both sides
[tex]x-12=4y[/tex]
Divide by 4 both sides
[tex]y=\frac{x-12}{4}[/tex]
simplify
[tex]y=\frac{1}{4}x-3[/tex]
step 4
Let
[tex]f^{-1}(x)=y[/tex]
[tex]f^{-1}(x)=\frac{1}{4}x-3[/tex]
we have that
[tex]g(x)=f^{-1}(x)[/tex]
therefore
[tex]g(x)=\frac{1}{4}x-3[/tex]
Matt and Ming are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges. Matt sold 3 small boxes of oranges and 14 large boxes of oranges for a total of $203. Ming sold 11 small boxes of oranges and 11 large boxes of oranges for a total of $220. Find the cost each of one small box of oranges and one large box of oranges
Answer: One small box of oranges costs $7 and one large box of oranges costs $13.
Step-by-step explanation:
Let be "s" the cost in dollars of one small box of oranges and "l" the cost in dollars of one small box of oranges.
Based on the data given in the exercise, you can set up the following System of equations:
[tex]\left \{ {{3s+14l=203} \atop {11s+11l=220}} \right.[/tex]
Use the Elimination Method to solve it:
- Multiply the first equation by 11 and the second one by -3.
- Add the equations.
- Solve for "l".
Then:
[tex]\left \{ {{33s+154l=2233} \atop {-33s-33l=-660}} \right.\\...............................\\\\121l=1573\\\\l=13[/tex]
- Substitute the value of "l" into any original equation and solve for "s":
[tex]3s+14(13)=203\\\\3s=203-182\\\\s=\frac{21}{3}\\\\s=7[/tex]
how do i figure out 9 1/6 - 8 5/6
and 10 3/4 - 6 4/4?
Answer:
1) [tex]9\frac{1}{6}-8\frac{5}{6}=\frac{1}{3}[/tex]
2) [tex]10\frac{3}{4}-6\frac{4}{4}=3\frac{3}{4}[/tex]
Step-by-step explanation:
You can convert he mixed numbers to improper fractions:
1. Multiply the whole number part by the denominator of the fraction.
2. Add the product obtained to the numerator.
3. The denominator does not change.
Then:
[tex]9\frac{1}{6}=\frac{54+1}{6}=\frac{55}{6}\\\\8\frac{5}{6}=\frac{48+5}{6}=\frac{53}{6}\\\\10\frac{3}{4}=\frac{40+3}{4}=\frac{43}{4}\\\\6\frac{4}{4}=\frac{24+4}{4}=\frac{28}{4}[/tex]
Observe that, in each subtraction, the denominators are equal, then you can rewrite the denominator and subtract the numerators:
[tex]1)\ \frac{55}{6}-\frac{53}{6}=\frac{55-53}{6}= \frac{2}{6}=\frac{1}{3} \\\\2)\ \frac{43}{4}-\frac{28}{4}=\frac{43-28}{4}= \frac{15}{4}[/tex]
Divide 15 by 4. The quotient will be 3 and the remainder 3.
Then:
[tex]\frac{15}{4}=3\frac{3}{4}[/tex]
Approximately how many times greater is 2.3x10^-4 than 1.15x10^-8 ?
A: 115
B:200
C:11,500
D:20,000
Answer:
2.3 × [tex]10^{-4}[/tex] is 20,000 times greater than 1.15 × [tex]10^{-8}[/tex]
Step-by-step explanation:
Given as :
The first number= x = 2.3 × [tex]10^{-4}[/tex]
The second number= y = 1.15 × [tex]10^{-8}[/tex]
Let The first number is z times greater than second number
i.e x = z × y
Or, z = [tex]\dfrac{x}{y}[/tex]
Or, z = [tex]\dfrac{2.3\times 10^{-4}}{1.15\times 10^{-8}}[/tex]
Or, z = 2 × [tex]10^{4}[/tex]
∴ z = 20,000
So,The first number is 20,000 times greater than second number
Hence, 2.3 × [tex]10^{-4}[/tex] is 20,000 times greater than 1.15 × [tex]10^{-8}[/tex] . Answer
Four speed skaters, Marco
Answer:
???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
Step-by-step explanation:
starting in 2000 what is estimated population and annual growth rate of 19,169,000 at 0.6% for 2025 not sure how to do this
Answer:
The estimated population in 2025 will be 22261221.
Step-by-step explanation:
Let us assume that the annual growth rate is compounded annually on the population.
Now, in 2000, the population was 19169000 and the annual growth rate is 0.6%, the the population in the year 2025 will be given by
[tex] 19169000(1 + \frac{0.6}{100} )^{25} = 22261220.7[/tex] ≈ 22261221
Therefore, the estimated population in 2025 will be 22261221. ( Answer )
An equation is given
2Vx+ 7 = 8
Enter the value of x for this equation.
Answer:
x = 1
----------
82V
Step-by-step explanation:
Make a conjecture about the diagram below. Do you think you can conclude that △JKL ≅ △XYZ? Explain your reasoning.
Answer:
△JKL ≅ △XYZ by HL congruency for right triangles
Step-by-step explanation:
If only given two sides and an uncontained angle, the triangles may not necessarily be congruent. However, since the given angle is a right angle, they are congruent.
When given that the hypotenuse and any "leg" of the right triangles are equal, the triangles are congruent.
Since one angle is 90°, the other two angles must be acute. This is unlike the ambiguous case when given an uncontained acute angle, where two possible triangles can be made by making another angle obtuse.
Imagine an isosceles triangle cut in half at the altitude, creating two right triangles (JKL and XYZ). They have the same angle measures. Each with a right angle, the angle that had an equal measure in the isosceles, and the unequal angle bisected. For the triangles' sides, the isosceles base was bisected by the altitude, and they have the same altitude.
Solve for x.
2х2-4х = 0
Step-by-step explanation:
2x²-4x=0
2x²=4x
[tex] \frac{2x {}^{2} }{x} = 4[/tex]
2x=4
x=2
Rena evaluated 3/4 ÷ 2/5 and got an answer of 1 7/8. Which statement is true about her answer
Rena's answer is correct.
To evaluate whether Rena's answer is correct, we need to perform the division of the two fractions 3/4 and 2/5. To divide one fraction by another, you multiply the first fraction by the reciprocal of the second fraction. The reciprocal of a fraction is obtained by flipping its numerator and denominator.
Here is a step-by-step solution:
Step 1: Write down the problem.
\[ \frac{3}{4} \div \frac{2}{5} \]
Step 2: Find the reciprocal of the second fraction.
The reciprocal of \( \frac{2}{5} \) is \( \frac{5}{2} \).
Step 3: Multiply the first fraction by the reciprocal of the second.
\[ \frac{3}{4} \times \frac{5}{2} \]
Step 4: Multiply the numerators together and the denominators together.
\[ \frac{3 \times 5}{4 \times 2} \]
\[ \frac{15}{8} \]
Step 5: Simplify the fraction if necessary.
In this case, \( \frac{15}{8} \) is an improper fraction because the numerator is larger than the denominator. We can convert it into a mixed number.
The whole number part of the mixed number is obtained by dividing the numerator by the denominator:
\[ 15 \div 8 = 1 \text{ with a remainder of } 7 \]
So, the mixed number is \( 1 \frac{7}{8} \).
Conclusion:
Rena's answer of \( 1 \frac{7}{8} \) is correct. The statement about her answer is true; she correctly evaluated the division of \( \frac{3}{4} \) by \( \frac{2}{5} \).
Mai biked 7 and 1/4 miles today, and Noah biked 3 5/8 miles. How many times the length of Noah's bike ride was Mai's bike ride?
answer choices
2/3
2
1/2
3/2
Answer:
2 times
Step-by-step explanation:
Mai biked [tex]7\frac{1}{4} = \frac{29}{4}[/tex] miles today and Noah biked [tex]3\frac{5}{8} = \frac{29}{8}[/tex] miles today.
We are asked how many times the length of Noah's bike ride was Mai's bike ride.
Therefore, the length of Mai's bike ride was [tex](\frac{29}{4} \div \frac{29}{8}) = 2[/tex] times the length of Noah's bike ride.
Therefore, we will take option B will be correct. ( Answer )
1. What is the total cost of a $95.00 item with a sales tax of 6%?
Since the sales tax is 6%, the object will cost 1.06 (100% + 6%) times the original value.
1.06 × $95.00 = $100.70
The object will cost $100.70.
Let me know if you need any clarifications, thanks!