I REALY NEED HELP!
In kite ABCD, m∠ACD=82°. What is m∠DCE?
1.)41°
2.)82°
3.)90°
4.)98°

The expected amount of money in the bag if 90 coins are in the bag is [tex]\(\$5.78\)[/tex].

We need to determine the total value of the coins in the bag based on the given handful and then extrapolate that to the total number of coins in the bag.

First, let's calculate the value of the coins in the handful:

The value of five nickels is [tex]\(5 \times 5\)[/tex] cents = 25 cents.

The value of three quarters is [tex]\(3 \times 25\)[/tex] cents = 75 cents.

The value of nine pennies is [tex]\(9 \times 1\)[/tex] cent = 9 cents.

Adding these values together gives us the total value of the handful:

[tex]\[25 + 75 + 9 = 109 \text{ cents}\][/tex]

Next, we need to find out the ratio of each type of coin in the handful. We have a total of [tex]\(5 + 3 + 9 = 17\)[/tex] coins in the handful.

The ratios for each type of coin are as follows:

Nickels: [tex]\(\frac{5}{17}\)[/tex]

Quarters: [tex]\(\frac{3}{17}\)[/tex]

Pennies: [tex]\(\frac{9}{17}\)[/tex]

Now, let's calculate the expected number of each type of coin in the bag, given that there are 90 coins in total:

Expected nickels: [tex]\(90 \times \frac{5}{17}\)[/tex]

Expected quarters: [tex]\(90 \times \frac{3}{17}\)[/tex]

Expected pennies: [tex]\(90 \times \frac{9}{17}\)[/tex]

Using these ratios, we can calculate the expected number of each coin type:

Expected nickels: [tex]\(90 \times \frac{5}{17} \approx 26.47\)[/tex], but since we can't have a fraction of a coin, we'll consider 26 nickels.

Expected quarters: [tex]\(90 \times \frac{3}{17} \approx 15.88\)[/tex], rounding to 16 quarters.

Expected pennies: [tex]\(90 \times \frac{9}{17} \approx 47.65\)[/tex], rounding to 48 pennies.

Finally calculate the total expected value in the bag by multiplying the number of each type of coin by its value:

Value of expected nickels: [tex]\(26 \times 5\)[/tex] cents = 130 cents

Value of expected quarters: [tex]\(16 \times 25\)[/tex] cents = 400 cents

Value of expected pennies: [tex]\(48 \times 1\)[/tex] cent = 48 cents

Adding these values together gives us the total expected value in the bag:

[tex]\[130 + 400 + 48 = 578 \text{ cents}\][/tex]

To convert the total value from cents to dollars, we divide by 100:

[tex]\[578 \text{ cents} \div 100 = \$5.78\][/tex]

Answer: Answer is 2

Step-by-step explanation:

Answer:

The value of 8 cos 30° rounded to four decimal places = 6.9282

Step-by-step explanation:

Here we need to find the value of 8 cos 30° rounded to four decimal places.

Using the calculator to find the value

          8 cos 30° = 6.9282032302755

Rounding the number to   four decimal places, we will get

         8 cos 30° = 6.9282

The value of 8 cos 30° rounded to four decimal places = 6.9282

Answer:

1,260

Step-by-step explanation:

Because it seemed right and I'm pretty sure it is

To find the height at which the center of a railroad rail would rise due to expansion, convert all measurements to meters and use the formula h ≈ ΔL / 8. For expansion of 50 cm, the rail would rise approximately 6.25 cm.

The student has asked how high the center of a 2 km long railroad rail would rise when it expands by 50 cm on a hot day. First, we need to convert all measurements to meters: the railroad is 2000 m long, and it expands by 0.50 m. To find the height that the rail would rise, we can consider the rail as forming an arc of a circle after expansion.
We have the original length of the rail as the diameter of the circle and the expanded length as a slightly longer arc of the same circle. As the increase in length due to expansion is very small compared to the original length, we can use the approximation that the height of the rise is equal to the arc's excess length divided by 8 (h ≈ ΔL / 8).

Applying this formula: h ≈ 0.50 m / 8 = 0.0625 m or 6.25 cm. This approximation works under the assumption that the bend in the rail is mild, as it would be in reality due to the small degree of expansion.

The values where cos(x) is equal to 0 are excluded from the domain of the function y=sec(x)=1cos(x), or the values 2+n for all integers n. The function's range is either y<=1 or y>=1.

The domain of a function is the set of values that we are allowed to plug into our function. This set is the x values in a function such as f(x).

here, we have,

we know that  "secant function" mean:

Its root is the Latin verb secare, which means "to cut." Any line that intersects a circle twice is referred to as a secant line, and you can conceive of this line as slicing the circle in half. The distance from the origin to the point where the tangent line intersects the x-axis is the secant function.

now,  the identity of the sec is:

1/cos(x) = sec(x) Cot (x) = 1/Tan (x)

To know more about domain visit:-

brainly.com/question/28135761

#SPJ7

Answer:

The answer is 1.

Im sorry I forgot the step by step explanation, but I had this in a quuiz a while ago and the answer is 1.

Answer:

6

Step-by-step explanation:

60x 6 =360

Plz give me 5 stars and a THANK YOU!

Mr. Rif-kin initially had 181 digital cameras.

Let's denote:

- [tex]\( x \)[/tex] as the initial number of digital cameras.

- [tex]\( y \)[/tex] as the initial number of manual cameras.

According to the given information:

1. Mr. Rif-kin had a total of 240 digital and manual cameras initially:

[tex]\[ x + y = 240 \][/tex]

2. After donating 82 digital cameras and 26 manual cameras, he had 3 times as many digital cameras as manual cameras left:

[tex]\[ (x - 82) = 3(y - 26) \][/tex]

We can set up a system of equations with these two equations and solve for [tex]\( x \)[/tex] and [tex]\( y \)[/tex].

1. From Equation 1:

[tex]\[ y = 240 - x \][/tex]

2. Substituting [tex]\( y \)[/tex] from Equation 1 into Equation 2:

[tex]$\begin{aligned} & x-82=3((240-x)-26) \\ & x-82=3(214-x) \\ & x-82=642-3 x \\ & 4 x=724 \\ & x=181\end{aligned}$[/tex]

Now that we have found [tex]\( x \)[/tex], we can find [tex]\( y \)[/tex] using Equation 1:

[tex]$\begin{aligned} & y=240-x \\ & y=240-181 \\ & y=59\end{aligned}$[/tex]

So, Mr. Rif-kin initially had [tex]\( 181 \)[/tex] digital cameras and [tex]\( 59 \)[/tex] manual cameras.

The complete question is here:

Mr. Rif-kin had 240 digital and manual cameras. After donating 82 digital cameras and 26 manual cameras, he had 3 times as many digital cameras as manual cameras left. How many digital cameras did he have at first?

Answer: Simplified version of the answer above: (x = 9) is the correct answer.

Step-by-step explanation:

Answer: [tex]f(x) = 80 ( 1.1 ) ^x[/tex]

Step-by-step explanation:

Let the function that shows the average annual salary after x years since 2005 is,

[tex]f(x) = ab^x[/tex] ----- (1)

Where a and b are any unknown numbers.

For x = 0,

[tex]f(0) = ab^0= a[/tex]

But According to the question,

The average annual salary of the employees of a company in the year 2005 was $80,000.

Therefore, f(0)=80000 dollars.

⇒ a = 80000

From equation (1),

[tex]f(x) = 80000 b^x[/tex]  ------- (2)

Now again according to the question,

In 2006, the average annual salary was $88,000

But the average annual salary in 2006 is [tex]f(1) = 80000 b^1[/tex]

⇒ [tex] 80000 b^1=88000[/tex]

⇒ b = 1.1

Putting the value of b in equation (2),

The average annual salary after x years since 2005 is,

[tex]f(x) = 80000 (1.1)^x[/tex] dollars

Or  [tex]f(x) = 80 (1.1)^x[/tex] thousand dollars

Thus, Fourth Option is correct.

25/10 = 7.5/x

75/25x

x=75/25 = 3

diameter of smaller jar = 3 cm

Answer:

Step-by-step explanation:

Since f(x) = (x^2 + 5x + 6) / (2x + 16)

For discontinuities, they can be found at where the slope does NOT exist

Take the derivative of f(x):

f'(x) = (x^2 + 16x + 34) / 2(x+8)^2

Apparently, when x= -8, f'(x) is NOT defined

Therefore, the discontinuity is uniquely located at x = -8