Identify the species oxidized. 2 al3+(aq) + 2 fe(s) → 2 al(s) + 3 fe2+(aq)

Answers

Answer 1
To know the answer, compare the oxidation number of the element in the reactant and the product side. The oxidation number of Al was originally +3, then became 0 after the reaction. On the other hand, Fe was originally 0, then became +2 after the reaction. When the element is oxidized, it oxidation number increases. Thus, the element oxidized is Fe.
Answer 2

The species oxidized in the reaction is Iron Fe.

The oxidation number assigned to Al is +3

The  oxidation number assigned to Fe is +2

Here, in the reaction the oxidation number of iron Fe is increased to +3

Hence, we can conclude that the species oxidized in the reaction is Iron Fe.

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Related Questions

What is the most striking part of this simulation?

Answers

None of the alpha particles fired at the foil are being repelled back, like they were in the Rutherford atom simulation.I hope this correct.

"according to the modern theory of the atom, where may an atom’s electrons be found?"

Answers

Because it is only possible to find the location OR velocity of an electron, we have to assume the location of the electron(s) is somewhere around the atom. 

Final answer:

Electrons in an atom, according to modern quantum mechanics, can be found in an electron cloud, occupying regions of space around the nucleus with probabilistically determined densities.

Explanation:

According to the modern theory of the atom, known as quantum mechanics, an atom's electrons can be found within specific regions of space around the nucleus, often referred to as the electron cloud.

Unlike the earlier Bohr model which suggested electrons travel in discrete orbits, quantum mechanics proposes that electrons exist in probabilistic distributions - the regions where electrons are most likely to be found.

These distributions are characterized by four quantum numbers, much like a home address, with the first three providing an approximation of the electron's location in the atom and the fourth describing the electron's spin direction.

The electron cloud has variable densities, indicating the likelihood of finding an electron at a given location; the closer to the nucleus, the higher the density. This concept is crucial for understanding how atoms interact and react with one another, as chemical reactions are typically a result of interactions between the valence electrons of different atoms.

In summary, electrons occupy shells and subshells that define an atom's electron configuration, which in turn influences the atom's chemical behavior.

If an electron gains energy what may happen to it

Answers

It could get bigger or it could have something a lot different to it than anything else
Final answer:

When an electron gains energy, it can move to a higher energy level (excited state). The energy was provided by an external source like a photon. When the electron returns to its initial state (ground state), it releases this acquired energy, usually in the form of a photon.

Explanation:

When an electron gains energy, it can move to an orbit with a higher energy level, a state referred to as an excited electronic state. This transition happens when an atom absorbs sufficient energy from an external source, such as a photon. According to the law of conservation of energy, the same amount of energy absorbed to excite the electron will be emitted when the electron returns to its initial state, usually in the form of a photon.

For instance, in Bohr's model of the atom, if the electron absorbs enough energy, it may move to an orbit farther from the nucleus, which requires additional energy. This energy can be obtained by absorbing electromagnetic radiation coming in contact with the atom.

When an electron transitions back to a less excited state or ground state, it emits energy in the form of electromagnetic radiation, like light or a photon, depending on the energy difference between the high and low energy state.

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A handbook gives the density of calcium as 1.54 g/cm3. based on lab measurements, what is the percentage error of a density calculation of 1.25 g/cm3? 37. what is the percentage error of a length measurement of 0.229 cm if the correct value is 0.225 cm?

Answers

Percentage error is a measure of the accuracy of a measurement or calculation, expressed as a percentage relative to the true or accepted value.

Percentage error = ( Experimental value  − True value / True value ) × 100 %

a) Percentage Error of Density Calculation:

Experimental Density = 1.25 g/cm³

True Density = 1.54 g/cm³

Percentage Error= ∣ 1.25−1.54 / 1.54 ∣  × 100 %

                            ≈ 18.83 %

b) Percentage Error of Length Measurement:

Given:

Experimental Length = 0.229 cm

True Length = 0.225 cm

Percentage Error=  ∣ 0.229  − 0.225 cm / 0.225 cm  ∣   × 100 %  

                             = 1.78 %

Therefore, The percentage error in density is 18.83 % and percentage error in length measurement is 1.78 %

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What does pure substance mean in chemistry?

Answers

The substances made up of only one atom or molecule is defined as pure substance.
I hope this helps.
Have a great day.

Describe how functional groups affect an organic molecule's' chemical reactivity

Answers

Functional groups are set of commonly found groups of atoms covalently bonded to carbon in organic molecules.The unique functional groups present on a bio molecule determine reactivity solubility and other physical properties that lead to its biological role in living organisms.

Gaseous vapor observed when handling dry ice (solid co_2 ​2 ​​ ) physical or chemical

Answers

Final answer:

Handling dry ice (solid CO₂) and observing gaseous vapor is a physical change called sublimation, where the substance directly transitions from the solid state to the gaseous state without passing through the liquid phase.

Explanation:

The observation of gaseous vapor when handling dry ice (solid CO₂) is a physical change. This is because when dry ice is handled, it bypasses the liquid phase and directly transitions from the solid state to the gaseous state through a process called sublimation. Sublimation is a physical change where a substance converts from a solid to a gas without going through the liquid phase. This is similar to how snow and ice can sublime into water vapor without melting into liquid water.

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What effect does a solute have on the freezing and boiling points of the solution?

Answers

it lowers the freezing point and raises the boiling points.

A dissolved solute raises the boiling point of a solvent.


How many moles of carbon monoxide are there in 36.55 g of carbon monoxide?

Answers

You can find moles of a substance by dividing mass by the molecules molar mass.

Explanation:

Carbon Monoxides Molar mass is 12.0111 (Carbon) + 16.0000 (Oxygen) = 28.0111g/mol. Divide grams by molar mass:

36.55g28.0111=1.305mols




Final answer:

The number of moles of carbon monoxide in 36.55 g can be calculated using the formula of number of moles = mass / molar mass. Applying this formula with the molar mass of carbon monoxide, you will find that there are approximately 1.305 moles of carbon monoxide in 36.55 g.

Explanation:

To find the number of moles in a given mass of a substance, we can use the formula: number of moles = mass of the substance / molar mass of the substance. The molar mass of carbon monoxide (CO) is approximately 28.01 g/mol, which is the sum of the atomic masses of carbon (12.01 g/mol) and oxygen (16.00 g/mol).

Now, plug the given mass of carbon monoxide into the formula: number of moles = 36.55 g / 28.01 g/mol. Solving this calculation, you will find that there is approximately 1.305 moles of carbon monoxide in 36.55 g.

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Explain how a skateboard resting on the ground contains energy. If the skateboard were moving , would it have more energy than it did at rest? Explain.

Answers

When the skate board is resting, it has potential energy, if it started to move the energy would increase and become kinetic energy.
A resting skateboard has potential energy, meaning that it's being stored.
If it starts moving, it now has kinetic energy, meaning it has more energy.

Which electron dot diagram shows the bonding between 2 chlorine atoms?

Answers

Chlorine has 7 valence electrons, but in the diagram, there are 2 chlorine atom making there a total of 14 valence electrons. There are 2 valence electrons in between the two atoms. There are 6 valence electrons around the outside of each individual chlorine atom. The electrons are arranged in groups of two around the outside of each atom.
Chlorine has 7 valence electrons, but in the diagram, there are 2 chlorine atom making there a total of 14 valence electrons. There are 2 valence

What can the vast majority of elements in the periodic table be classified?

Answers

I may need a bit more information to answer your question, but try these out:
 
The vast majority of elements in the periodic table are metals, meaning they have some degree of ductility and malleability, if you are being asked about physical properties.

The vast majority of elements in the periodic table are also solids at room temperature, if you are being asked about phase.

One useful way is by metals, nonmetals, and metalloids. (See also The Periodic Table: Families and Periods.) Most of the elements on the periodic table are classified as metals.

What is the molar mass of iron (III) oxide (Fe2O3)

Answers

should be 159.6822g/mol

159.7 is the correct answer.

Tartaric acid is the white, powdery substance that coats sour candies such as sour patch kids. combustion analysis of a 12.01-g sample of tartaric acid-which contains only carbon, hydrogen, and oxygen-produced 14.08 g co2 and 4.32 g h2o. empirical formula

Answers

First we calculate the mass of carbon, hydrogen and oxygen.

Mass of Carbon;
Molar mass of CO₂ is 44.009g/mol  and molar mass of C = 12.011 g/mol 

Mass of Carbon in 14.08g CO2₂ = 12.011/44.009 x 14.08 = 3.84

Mass Hydrogen;
Molar mass H₂O is 18.0015g/mol and molar mass of H is 1.008and  H₂ = 2.016 

Mass Hydrogen in 4.32g of H₂O = 2.016/18.0015 x 4.32 = 0.48

Mass of  Oxygen = total mas of tartaric acid – (mass of carbon + mass of hydrogen) = 12.01 - (3.84+0.48) = 7.69
Now divide carbon, hydrogen and oxygen through their respective atomic masses: 
C = 3.84/12.011 = 0.32
H = 0.48/1.008 = 0.48
O = 7.69/15.999 = 0.48
Now divide by smallest: 
C = 0.32/0.32 = 1 
H = 0.48/0.32 = 1.5 
O = 0.48/0.32 = 1.5 
multiply by 2 to get whole integers: 
C = 1 x 2 = 2 
H= 1.5 x 2 = 3 
O= 1.5 x 2 = 3
Thus, the Empirical formula of tartaric acid = C₂H₃O₃

The empirical formula for tartaric acid is C₂H₃O₃.

First, let's summarize the problem: A 12.01-g sample of tartaric acid produces 14.08 g of CO₂ and 4.32 g of H₂O upon combustion.

1. Calculate the moles of carbon in CO₂.

Mass of CO₂ produced: 14.08 g.

Molar mass of CO₂: 44.01 g/mol.

Moles of CO₂: 14.08 g / 44.01 g/mol = 0.320 mol CO₂.

Moles of C in CO₂: 0.320 mol × 1 mol C / 1 mol CO₂ = 0.320 mol C.

2. Calculate the moles of hydrogen in H₂O.

Mass of H₂O produced: 4.32 g.

Molar mass of H₂O: 18.02 g/mol.

Moles of H₂O: 4.32 g / 18.02 g/mol = 0.240 mol H₂O.

Moles of H in H₂O: 0.240 mol × 2 mol H / 1 mol H₂O = 0.480 mol H.

3. Calculate the mass of carbon and hydrogen in the original sample.

Mass of C: 0.320 mol × 12.01 g/mol = 3.84 g.

Mass of H: 0.480 mol × 1.008 g/mol = 0.48 g.

4. Determine the mass and moles of oxygen in the original sample.

Mass of O: Total mass - (mass of C + mass of H) = 12.01 g - (3.84 g + 0.48 g) = 7.69 g.

Moles of O: 7.69 g / 16.00 g/mol = 0.481 mol O.

5. Determine the empirical formula by finding the simplest whole number ratio.

Ratio of atoms: C = 0.320 mol, H = 0.480 mol, O = 0.481 mol.

Simplest ratio: Divide by the smallest number of moles (0.320).

C: 0.320 / 0.320 = 1, H: 0.480 / 0.320 = 1.5, O: 0.481 / 0.320 = 1.5.

Multiply by 2 to get whole numbers: C₂H₃O₃. This is the empirical formula.

Thus, the empirical formula of tartaric acid is C₂H₃O₃.

Complete question:

Tartaric acid is the white, powdery substance that coats sour candies such as sour patch kids. combustion analysis of a 12.01-g sample of tartaric acid-which contains only carbon, hydrogen, and oxygen-produced 14.08 g co2 and 4.32 g h2o. Find the empirical formula for tartaric acid.

Four most common oxyanions of Iodine

Answers

HIO= Hypoiodous acid; IO-=Hypoiodite
HIO2= Iodous acid; IO2= iodite
HIO3=Iodic acid; IO3-= iodate
HIO4=Periodic acid; IO4-=Periodate

Answer:

[tex]IO_4^-= Periodate\ ion[/tex]

[tex]IO_3^-= Iodate\ ion[/tex]

[tex]IO_2^-= Iodite\ ion[/tex]

[tex]IO^-= Hypoiodite\ ion[/tex]

Explanation:

Oxyanions:

Oxyanions are anions that have one or more oxygen atoms bonded to another elements is called oxyanions.

General formula of oxyanions are : [tex]A_xO_y^{z-}[/tex]

Where, A represents an element and O represents oxygen atom.

Four most common oxyanions of Iodine are:

[tex]IO_4^-= Periodate\ ion[/tex]

[tex]IO_3^-= Iodate\ ion[/tex]

[tex]IO_2^-= Iodite\ ion[/tex]

[tex]IO^-= Hypoiodite\ ion[/tex]

When the salinity of a seawater sample changes, the ratio of the major salt ions does not change?

Answers

The Answer is that the statement is true.
Salinity of a seawater sample changes, the ratio of the major salt ions does not change because we can define salinity as it is equal to the salts that are dissolved in seawater and we can expresses salinity as grams of salt per kg of seawater, so the major salt ions concentration in water does not change with the salinity of seawater. We can also determine the salinity by measuring the concentration of chloride ions in seawater.

You carefully weigh out 11.00 g of caco3 powder and add it to 44.55 g of hcl solution. you notice bubbles as a reaction takes place. you then weigh the resulting solution and find that it has a mass of 51.04 g . the relevant equation is caco3(s)+2hcl(aq)âh2o(l)+co2(g)+cacl2(aq) assuming no other reactions take place, what mass of co2 was produced in this reaction?

Answers

The bubbles that were observed after the mixing of the two substances is one of the products of the reaction. It is the carbon dioxide that is produced. To determine the mass of this gas produced, we need to remember the Law of conservation of mass where mass cannot be created or destroyed. With this, we can say that the total mass that goes in a process should be equal to the mass that is goes out of the process no matter what the reaction is. We do as follows:

Mass of reactants = mass of products
11.00 + 44.55 = 51.04 + mass of carbon dioxide
mass of carbon dioxide = 4.51 g
Final answer:

The mass of CO2 produced in the reaction is 17.596 g

Explanation:

The balanced equation for the reaction is:

CaCO3(s) + 2HCl(aq) → H2O(l) + CO2(g) + CaCl2(aq)

To find the mass of CO2 produced, we need to determine the mass of CaCO3 that reacted.

Given that the initial mass of CaCO3 is 11.00 g and the final mass of the solution is 51.04 g, the mass of CaCO3 that reacted is:

Final mass - Initial mass = 51.04 g - 11.00 g = 40.04 g

Since the molar mass of CaCO3 is 100.09 g/mol, we can calculate the moles of CaCO3 that reacted:

Moles = Mass / Molar mass = 40.04 g / 100.09 g/mol = 0.3998 mol

From the balanced equation, we can see that 1 mole of CaCO3 produces 1 mole of CO2. Therefore, the mass of CO2 produced is:

Mass = Moles × Molar mass = 0.3998 mol × 44.01 g/mol = 17.596 g

So, 17.596 g of CO2 was produced in this reaction.

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Identify the mixture of powdered charcoal and powdered sugar and suggest a technique for separating their components

Answers

To separate powdered charcoal from powdered sugar, add water to dissolve the sugar, use gravity filtration to remove charcoal, and evaporate the water to recrystallize the sugar.

The mixture described containing powdered charcoal and powdered sugar is a heterogeneous mixture. A technique to separate these components would be filtration. Since charcoal is insoluble in water and sugar is soluble, we can add water to the mixture to dissolve the sugar.

After the sugar has dissolved, we can use gravity filtration to separate the charcoal from the sugar solution. The charcoal will stay in the filter paper while the sugar solution passes through.

To recover the sugar from the solution, we could then evaporate the water, leaving behind solid sugar. It's important to break up any clumps and use hot water to ensure efficient dissolving and filtration. If the charcoal passes through the filter paper, it might be necessary to refilter or use a filter aid like Celite.

If a weak acid is 25% deprotonated at ph 4, what is the pka?if a weak acid is 25% deprotonated at ph 4, what is the pka?

Answers

Answer:

pKa = 4.5

Explanation:

The weak acid can be represented by the general formula, HA and the dissociation equilibrium given as:

[tex]HA \rightleftharpoons H^{+}+A^{-}[/tex]

where HA = protonated form

A- = deprotonated form

The Henderson-Hasselbalch equation relates the pH of a solution to the ratio of the concentrations of HA and A- as;

[tex]pH = pKa + log\frac{[A-]]}{[HA]]}-----(1)[/tex]

It is given that:

% deprotonated i.e. A- = 25%

Therefore, %protonated i.e. HA = 100 -25 = 75%

pH = 4

Based on equation (1)

[tex]4 = pKa + log\frac{[25]]}{[75]]} = pKa-0.477[/tex]

pKa = 4.477 i.e. around 4.5

The pKa of the weak acid is 5.07

Data;

pH = 4α = 25% = 0.25

For Weak Acids

The dissociation constant is given as

[tex]K_a = \frac{c\alpha ^2}{1-\alpha }\\[/tex]

The concentration of the acid can be calculated as

[tex]pH = -log [H^+]\\\\H^+ = 10^-^4\\H^+ = 1*10^-4M[/tex]

substitute the values into the equation above

[tex]Ka = \frac{1.0*10^-^4*0.25^2}{1-0.25}\\Ka = 8.33*10^-^6\\[/tex]

The pKa is calculated as

[tex]pKa = -logKa \\pKa = -log(8.33*10^-6)\\pKa = 5.07[/tex]

From the calculation above, the pKa of the weak acid is 5.07

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Calculate the mass percentages of carbon hydrogen and oxygen in sucrose

Answers

the formula for sucrose is C12H22O11 with a molecular mass of approx 342g/mol
% mass of C = 12(12) / 342 × 100% = 42.1%
% mass of H = 22(1) / 342 × 100% = 6.43%
% mass of O = 11(16) / 342 ×100% = 51.5%

Final answer:

The mass percentages of carbon, hydrogen, and oxygen in sucrose (C12H22O11) are approximately 42.11%, 6.48%, and 51.41%, respectively, calculated by determining the molar mass of sucrose and using the molar masses of the individual elements.

Explanation:

To calculate the mass percentages of carbon (C), hydrogen (H), and oxygen (O) in sucrose (C12H22O11), we first need to determine the molar mass of sucrose by summing the molar masses of its constituent elements. The molar masses are 12.01 g/mol for carbon, 1.008 g/mol for hydrogen, and 16.00 g/mol for oxygen.

The molar mass of sucrose is calculated as follows:

Carbon: 12 atoms × 12.01 g/mol = 144.12 g/molHydrogen: 22 atoms × 1.008 g/mol = 22.176 g/molOxygen: 11 atoms × 16.00 g/mol = 176.00 g/mol

Total molar mass = 144.12 g/mol + 22.176 g/mol + 176.00 g/mol = 342.296 g/mol

Next, we calculate the mass percentage for each element:

Carbon: (144.12 g/mol / 342.296 g/mol) × 100% = 42.11%Hydrogen: (22.176 g/mol / 342.296 g/mol) × 100% = 6.48%Oxygen: (176.00 g/mol / 342.296 g/mol) × 100% = 51.41%

Therefore, the mass percentages in sucrose are approximately 42.11% carbon, 6.48% hydrogen, and 51.41% oxygen.

An atom containing 47 protons, 47 electrons, and 60 neutrons has a mass number of

Answers

Final answer:

An atom containing 47 protons, 47 electrons, and 60 neutrons has a mass number of 107, calculated by summing the number of protons and neutrons.

Explanation:

The mass number of an atom is defined as the sum of the number of protons and the number of neutrons within the atom's nucleus. Given an atom with 47 protons, 47 electrons, and 60 neutrons, we can calculate its mass number by adding the number of protons and the number of neutrons:

Mass number = Number of protons + Number of neutrons = 47 + 60 = 107.

Therefore, the atom with 47 protons, 47 electrons, and 60 neutrons has a mass number of 107.

Under certain conditions, neon (Ne) gas diffuses at a rate of 4.5 centimeters per second. Under the same conditions, an unknown gas diffuses at a rate of 10.1 centimeters per second. What is the approximate molar mass of the unknown gas?

Answers

mv^2 = const 
m ~ 1/v^2 

(4.5/10.1)^2 = 0.198 

20.2 * 0.198 = 4.0 g/mol (Helium)

Answer: 4 g/mol

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

[tex]\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}[/tex]

Molar mass of neon =  20 g/mol

Molar mass of unknown gas = ?g/mol

For the rate of diffusion of neon to unknown gas (X), we write the expression:

[tex]\frac{Rate_{Ne}}{Rate_{X}}=\sqrt{\frac{M_{X}}{M_{Ne}}}[/tex]

[tex]\frac{4.5}{10.1}=\sqrt{\frac{M_{X}}{20}[/tex]

[tex]{M_{X}}=4g/mol[/tex]

Hence, the approximate molar mass of the unknown gas is 4 g/mol

What are families of elements with similar chemical properties called?

Answers

It is called groups.
Final answer:

The families of elements with similar chemical properties are called groups in the periodic table.

Explanation:

The families of elements with similar chemical properties are called groups in the periodic table. Elements in the same group have the same number of valence electrons and therefore exhibit similar chemical behaviors. For example, the alkali metals in Group 1 and the halogens in Group 17 both have similar reactivity due to their respective valence electron configurations.

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If you have a substance, would it have the same density no matter what mass of the substance you have?

Answers

Assuming all other conditions equal, then, yes, the density would not change regardless of the mass of the substance. This is because the density is a ratio of the mass substance to its volume. If you increase the mass, the volume displaced would also be greater. So, it would just adjust making the density constant. This is applicable if it is at the same temperature and pressure conditions.

You have three molecules of glucose (3C^6H^12O^6). How many carbon atoms do you have?

Answers

You have 6 carbon atoms in glucose. Multiply by 3 and you get 18.
Each molecule of glucose has 6 Carbon atoms, so 3 molecules would be 3*6 Carbon atoms, or 18 in total.

Which electron configuration exhibits the ground-state electron configuration for molybdenum (element 42)?

Answers

Molybdernum, Mo has atomic number 42. Hence 42 electron.


...in shorthand: [Kr] 5s2, 4d4 
...or in full: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d4

Which of the following is NOT made up of atoms

Answers

What is it?
You didn't put up the questions

Answer:

i think the answer choices is

A-Heat

B-A Gas

C-A cell

D-A solid

Explanation:

This type of fatty acid contains more than one double bond in its hydrocarbon chain.

Answers

Polyunsaturated fatty acids contain more than one double bond in its hydrocarbon chain.

the elements that contain electrons in an F sublevel near the highest occupied energy level are referred to as?

A. Alkali metals

B. Alkali earth metals

C. transition metals

D. inner transmission levels

Answers

inner transition metals is your answer

The elements that contain electrons in an F sublevel near the highest occupied energy level are referred to as inner transition elements. Thus option D is correct.

What are orbitals?

Orbitals are energy levels or regions in an atom where, there is a possibility of finding electrons.  Electrons are filled in various orbitals from lower energy levels to higher energy levels.

There are 4 different orbitals namely s, p , d and f. Based on the energy level they can 1s, 2s, 2p, 3p and so on. The elements in periodic table are classified into 4 different blocks based on the orbitals of valence electrons.

If the valence electrons are filled in s orbital they are s-block elements containing metals and if they are filled in p orbital are p-block elements containing non metals.

Elements whose valence electrons fall in d-orbital are called d-block elements or transition metals and those having valence electrons in f orbital are f-block elements and they are called as inner transition elements.

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Which quantity of heat is equal to 200. joules?
(1) 20.0 kJ (3) 0.200 kJ

Answers

the answer is (3) 0.200 kJ
Hope I helped!
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