If 11 pens weigh 53.43 grams how many grams will 2 pens weigh

Answers

Answer 1

Answer:

11 pens weigh 53.43 grams.

2 pens weigh X grams.

We have:

11/53.43 = 2/X

=> X = 2 x 53.43/11 = 9.72 grams

Hope this helps!

:)


Related Questions

Y=200(.6)x decay or growth

Answers

decay because the b value is less than 1

Which statements about the figure are true? Select two options.

The perimeter of the triangle is 19 units.
TU ≅ TS
PU ≅ TU
The length of line segment PR is 13 units.
The length of line segment TR is 10 units.

Answers

Complete Question

The circle is inscribed in triangle PRT. A circle is inscribed in triangle P R T. Points Q, S, and U of the circle are on the sides of the triangle. Point Q is on side P R, point S is on side R T, and point U is on side P T. The length of R S is 5, the length of P U is 8, and the length of U T is 6. Which statements about the figure are true?

Answer:

(B)TU ≅ TS

(D)The length of line segment PR is 13 units.

Step-by-step explanation:

The diagram of the question is drawn for more understanding,

The theorem applied to this problem is that of tangents. All tangents drawn to a circle from the same point are equal.

Therefore:

|PQ|=|PU|=8 Units

|ST|=|UT| =6 Units

|RS|=|RQ|=5 Units

(b)From the above, TU ≅ TS

(d)Line Segment |PR|=|PQ|+|QR|=8+5=`13 Units

Answer:

b & d

Step-by-step explanation:

i took the edge test !

x2 + 2x = 2x + x2
associative property
closure property
commutative property

Answers

Final answer:

The equation x2 + 2x = 2x + x2 demonstrates the Commutative Property, showing that the order of addition does not change the result.

Explanation:

The equation x2 + 2x = 2x + x2 demonstrates the Commutative Property of addition. The Commutative Property states that for any numbers a and b, a + b = b + a. This property applies to both addition and multiplication, indicating that the order in which two numbers are added or multiplied does not change the result. In the given equation, the terms on both sides can be rearranged without changing the equality, showing that x2 + 2x is equal to 2x + x2 due to the commutative property.

Lana is creating a video.Her computer shoes that the video is 184.026 second long. She writes the length of the video in expanded form. Which expression represents the value of one of the digits in the length of Lana video

Answers

Answer: 6 × 1/1000

Step-by-step explanation:

Lana is creating a video. Her computer shoes that the video is 184.026 second long. From the figures, 184.026

1 represents 100

8 represents 80

4 represents 4

0 represents 0 tenths

2 represents 2 hundredths

6 represents 6 thousandths

Therefore, 6 × 1/1000 is the right answer.

The correct expanded form expression for one of the digits in Lana's video length is D. 6 * [tex]\frac{1}{1000}[/tex] which matches the digit 6 in the thousandths place correctly.

Lana's video length is 184.026 seconds. To write it in extended form, we separate each digit by its place value:

1 * 1008 * 104 * 10 * [tex]\frac{1}{10}[/tex]2 * [tex]\frac{1}{100}[/tex]6 * [tex]\frac{1}{1000}[/tex]

Now, let's match the given options to this expanded form:

A. 1 * 1000: This is incorrect because 1 is multiplied by 100, not 1000.B. 2 * [tex]\frac{1}{10}[/tex] : This is incorrect because 2 is multiplied by [tex]\frac{1}{100}[/tex]C. 4 * 10: This is incorrect because 4 is multiplied by 1.D. 6 * [tex]\frac{1}{1000}[/tex] : This is correct because 6 is indeed multiplied by 1/1000.

Therefore, the correct answer is D. 6 * [tex]\frac{1}{1000}[/tex]

Complete question:

Lana is creating a video. Her computer shows that the video is 184.026 seconds long. She writes the length of the video in expanded form. Which expression represents the value of one of the digits in the length of Lana’s video?

A. 1* 1000

B. 2* [tex]\frac{1}{10}[/tex]

C. 4* 10

D. 6* [tex]\frac{1}{1000}[/tex]

determine the slop of the line passing through (-3,7) and (9,-2)

Answers

the slope is 3/4. you need to find the change of y over the change of x.

cos(-35°) = _____.

cos 55°
cos 35°
-cos35°
-cos 325°

Answers

Answer:

Cos 35

Step-by-step explanation:

They have the same answer when typed in a calculator

Tracey ran 1,000 meters in 5 minutes. How many meters/minutes did she run?

Answers

Answer:

200/1

Step-by-step explanation:

1000/5  = 200/1

can anyone help
3c+5=23

Answers

Answer: c = 6

To solve for c in the equation you see here,

our goal is to get c by itself.

Our first step will be to isolate the term

containing c which in this problem is 3c.

To isolate 3c, we have to get rid of the +5 by

subtracting 5 from both sides of the equation.

On the left, the +5 and -5 cancel out

and we are simply left with 3c.

On the right, 23 - 5 simplifies to 18.

Now we have 3c = 18.

To get c by itself, since it's being multiplied by 3,

we just divide both sides of the equation by 3.

On the left, the 3's cancel and we are left with c.

On the right, 18/3 simplifies to 6.

So our answer is c = 6.

2. 5 − 1/2 x = y m= _______ b=_________

Answers

Answer:

m = -1/2 and b = 2.5

Step-by-step explanation:

The slope intercept form of the equation of a line is

y = mx+b  where m is the slope and b is the y intercept

2.5 - 1/2x = y

Rewriting

y = -1/2x +2.5

The slope is -1/2 and the y intercept is 2.5

m = -1/2 and b = 2.5

Next 3 sequences for 3,-15,75,-375

Answers

Answer:

1,875

-9,375

46,875

Step-by-step explanation:

You're multiplying by -5 every time, so your next three numbers would be 1,875 -9,375 and 46,875

Manny observed a Northern Gannet, a deep diving seabird, hovering at a height of 10 meters above the ocean surface. The bird then dove into the water, diving to a depth of 16 meters before coming to the surface. The dive can be modeled by a quadratic function, y = x2 – 10.3x + 10, where x represents the time the dive lasted in seconds and y represents the height of the bird in meters. Use the graphing calculator to graph the equation. After how many seconds did the bird surface? Round your answer to the nearest tenth. seconds

Answers

Answer:

9.2 seconds

Step-by-step explanation:

got it right on edg 2020

URGENT, NEED ANSWERS ASAP

1) Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p
n = 110, x=55, 88% confidence
a. 0.426 < p < 0.574
b. 0.422 < p < 0.578
c. 0.425 < p < 0.575
d. 0.421 < p < 0.579

2) Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p
A study involves 669 randomly selected deaths, with 31 of them caused by accidents. Construct a 98% confidence interval for the true percentage of all deaths that are caused by accidents.
a. 3.29% < p < 5.97%
b. 3.04% < p < 6.23%
c. 2.74% < p < 6.53%
d. 2.54% < p < 6.73%

3) Use the confidence level and sample data to find a confidence interval for estimating the population μ. Round your answer to the same number of decimal places as the sample mean.
A random sample of 130 full-grown lobsters had a mean weight of 21 ounces and a standard deviation of 3.0 ounces. Construct a 98% confidence interval for the population mean μ.
a. 20 oz < μ < 22 oz
b. 21 oz < μ < 23 oz
c. 19 oz < μ < 21 oz
d. 20 oz < μ < 23 oz

4) Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution.
n = 30, x = 83.1, s = 6.4, 90% confidence
a. 80.71 < μ < 85.49
b. 79.88 < μ < 86.32
c. 81.11 < μ < 85.09
d. 81.13 < μ < 85.07

5) Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution.
Thirty randomly selected students took the calculus final. If the sample mean was 83 and the standard deviation was 13.5, construct a 99% confidence interval for the mean score of all the students.
a. 76.93 < μ < 89.07
b. 76.21 < μ < 89.79
c. 78.81 < μ < 87.19
d. 76.23 < μ < 89.77

6) Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution.
A savings and loan association needs information concerning the checking account balances of its local customers. A random sample of 14 accounts was checked and yielded a mean balance of $664.14 and a standard deviation of $297.29. Find a 98% confidence interval for the true mean checking account balance for local customers.
a. $455.65 < μ < $872.63
b. $492.52 < μ < $835.76
c. $493.71 < μ < $834.57
d. $453.59 < μ < $874.69

7) Use the given degree of confidence and sample data to construct a confidence interval for the population standard deviation σ. Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal places as the sample standard deviation.
College students' annual earnings: 98% confidence interval; n = 9, x = $3959, s = $886
a. $539 < σ < $1734
b. $598 < σ < $1697
c. $697 < σ < $1156
d. $559 < σ < $1953

8) 41 random samples of monthly electric bill amounts are selected form a normally distributed population. The samples have a mean of $108 and a standard deviation of $5. Construct a 98% confidence interval for the population standard deviation.
a. $1.89 < σ < $2.75
b. $3.14 < σ < $9.02
c. $3.96 < σ < $6.72
d. $4.23 < σ < $6.14

9) Use the given degree of confidence and sample data to construct a confidence interval for the population standard deviation σ. Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal places as the sample standard deviation.
Heights of mature White Pine trees: 99% confidence; n = 29, x = 65 ft, s = 8.4 ft
a. 8.27 ft < σ < 8.53 ft
b. 4.23 ft < σ < 10.47 ft
c. 6.22 ft < σ < 12.59 ft
d. 5.73 ft < σ < 10.07 ft

10) Use the given degree of confidence and sample data to construct a confidence interval for the population standard deviation σ. Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal places as the sample standard deviation.
The amounts (in ounces) of juice in eight randomly selected juice bottles are:
15.9 15.2 15.3 15.2
15.3 15.8 15.1 15.2
Find a 98% confidence interval for the population standard deviation σ.
a. 0.18 oz < σ < 0.62 oz
b. 0.19 oz < σ < 0.62 oz
c. 0.21 oz < σ < 0.80 oz
d. 0.19 oz < σ < 0.72 oz

Answers

Answer:

1) a. CI = 0.426 < p < 0.574

2) c. CI = 2.74% < p < 6.524%

3) a. CI = 20 < μ < 22

4) c. CI = 81.11 < μ < 85.09

5) b. CI = 76.21 < μ < 89.79

6) d. $453.59 < μ < $874.69

7) d. CI = $559 < σ < $1953.3

8) c. CI = $3.96 < σ < $6.72

9) c. 6.22 ft < σ < 12.59 ft

10) d. 0.19 oz < σ < 0.72 oz

Step-by-step explanation:

The Confidence Interval, CI are given as follows

For the population proportion

[tex]CI=\hat{p}\pm z\times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}[/tex]

1)  [tex]\hat p[/tex] = 55/110 = 0.5

z at 88% = ±1.56

a. CI = 0.426 < p < 0.574

2)  [tex]\hat p[/tex] = 31/669 = 0.5

z at 98% = ±2.326

c. CI = 2.74% < p < 6.524%

3) Here we have unknown population standard deviation, so we find the t interval

[tex]\bar x[/tex] = 21

n = 130

s = 3.0

Confidence level = 98%

[tex]CI=\bar{x}\pm t_{\alpha/2} \frac{s}{\sqrt{n}}[/tex]

[tex]t_{\alpha /2}[/tex] = ±2.356

CI = 20.380 < μ < 21.62

Rounding up gives;

a. CI = 20 < μ < 22

4) Similarly here we have;

[tex]t_{\alpha /2}[/tex] = ±1.699 and

c. CI = 81.11 < μ < 85.09

5) Here

[tex]\bar x[/tex] = 83

s = 13.5

n = 30

Confidence level = 99%

[tex]t_{\alpha /2}[/tex] = ±2.76 and

b. CI = 76.21 < μ < 89.79

6) In the question, we have

[tex]\bar x[/tex] = $664.14

s = $297.29

n = 14

Confidence level = 98%

[tex]t_{\alpha /2}[/tex] = ±2.65 and

CI = $453.56 < μ < $874.72

d. $453.59 < μ < $874.69

7) The confidence interval for a population standard deviation is given by the following relation;

[tex]\sqrt{\frac{\left (n-1 \right )s^{2}}{\chi _{1-\alpha /2}^{}}}< \sigma < \sqrt{\frac{\left (n-1 \right )s^{2}}{\chi _{\alpha /2}^{}}}[/tex]

Here

n = 9

x = $3959

s = $886

Therefore we have

d. CI = $559 < σ < $1953.3

8) Here we have;

n = 41

x = $108

s = $5

Therefore;

c. CI = $3.96 < σ < $6.72

9) Here we have;

n = 29

x = 65 ft

s = 8.5 ft

Therefore we have

CI = 6.3 ft < σ < 12.73 ft

c. 6.22 ft < σ < 12.59 ft

10) Here we have

n = 8

s = 0.301188123

d. 0.19 oz < σ < 0.72 oz.

A worker at a mill is loading 5 pound bags of flour into boxes to deliver to a local warehouse. Each box holds 16 bags of flour. If the warehouse orders 4 tons of flour how many boxes are needed to fulfill the order ?

Answers

Answer:

100 boxes are needed to fulfill the order

Step-by-step explanation:

In this question, we are concerned with calculating the number of boxes that are needed to fulfill an order.

Each of the boxes contain 16 bags of flour and each of these bags weigh 5 pounds. What this means is that each of the boxes will have a net weight of 5 * 16 = 80 pounds

Mathematically, 1 ton is the equivalent of 2,000 pounds. Hence, 4 tons is the equivalent of 4 * 2000 = 8,000 pounds

Thus, the number of boxes needed will be 8,000/80 = 100 boxes

The function F(x) is described below.
Fx) = 3x + 2
What is the value of F(5)?
O A. 10
B. 15
C. 17
D. 21

Answers

Answer:

C. 17

Step-by-step explanation:

f(x)= 3x+2

f(5)= 3(5) + 2

f(5)= 15+2

f(5) = 17

A right rectangular prism has edges measuring 3/4 inch, 1 inch, and 1/4 inch. How many cubes with side lengths of 1/4 would be needed to fill the prism.

Answers

Answer:

The number of cubes needed = 12

Step-by-step explanation:

To know the number of cubes that will be needed to fill the prism, we need to divide the the volume of the right rectangular prism by the volume of the cube.

Mathematically, the volume of the right rectangular prism can be calculated using the formula;

V = whl

where w is the width, h is the height and l is the length.

Plugging the values we have in the question for the right rectangular prism, we have;

V = 3/4 * 1 * 1/4 = 3/16 inch^3

The volume of the cube can be calculated using the formula L^3 where L is the side length

V = 1/4 * 1/4 * 1/4 = 1/64 inch^3

The number of cubes needed to fill the prism is thus;

(3/16) ÷ (1/64) = 3/16 * 64/1 = 3 * 4 = 12

12 small cubes with side lengths of 1/4 inch each are needed to fill the given right rectangular prism.

To find out how many small cubes with side lengths of 1/4 inch are needed to fill a right rectangular prism with edges measuring 3/4 inch, 1 inch, and 1/4 inch, we need to calculate the volume of the prism and divide it by the volume of one small cube.

The volume of the prism is found by multiplying the lengths of its sides:
Volume of prism = (3/4 inch) * (1 inch) * (1/4 inch) = 3/16 cubic inches.

The volume of a small cube with a side length of 1/4 inch is:
Volume of small cube = [tex](1/4 inch)^3[/tex] = 1/64 cubic inches.

To find the number of small cubes needed to fill the prism, we divide the prism's volume by the small cube's volume:
Number of small cubes = Volume of prism / Volume of small cube
Number of small cubes = (3/16) / (1/64)

By simplifying this division, we get:
Number of small cubes = 3/16 * 64 = 12

Therefore, 12 small cubes with side lengths of 1/4 inch each are needed to fill the right rectangular prism.

The sum of Emma’s age and her sisters age is 41 years. Emma is 11 years older than her sister. What is Emma’s age and what is her sisters age

Answers

Emma’s age is 26 and her sister is 15 because 26 - 15 = 11 (The age that Emma is older by) and once you add 26 and 15, it equals 41

Write an exponential function in the form y=ab^xy=ab x that goes through points (0, 5) and (8, 1280)

Answers

Answer:

[tex] a =5[/tex]

Now we can use the info from the second point and we have:

[tex] 1280 = 5 b^8 [/tex]

We can divide 5 in both sides and we got:

[tex] 256 = b^8[/tex]

And using an exponent 1/8 in both sides we got:

[tex] (256)^{1/8} = b[/tex]

[tex] b = 2[/tex]

And then our model would be given:

[tex] y= 5 (2)^x [/tex]

Step-by-step explanation:

For this case we have two points given (0,5) and (8,1280). And we want to find a function given by this general expression:

[tex] y= ab^x [/tex]

And using the first point given we have:

[tex] 5 = a b^0 [/tex]

[tex] a =5[/tex]

Now we can use the info from the second point and we have:

[tex] 1280 = 5 b^8 [/tex]

We can divide 5 in both sides and we got:

[tex] 256 = b^8[/tex]

And using an exponent 1/8 in both sides we got:

[tex] (256)^{1/8} = b[/tex]

[tex] b = 2[/tex]

And then our model would be given:

[tex] y= 5 (2)^x [/tex]

Final answer:

To write an exponential function that passes through (0, 5) and (8, 1280), we first use the point (0, 5) to find that a = 5. Then, using the point (8, 1280), we solve for b, finding b = 2. Thus, the required exponential function is[tex]y = 5.2^x.[/tex]

Explanation:

To write an exponential function in the form y=ab^x that goes through the points (0, 5) and (8, 1280), we need to solve for a and b.

Step 1: Use the First Point (0, 5)

Substitute x = 0 and y = 5 into the equation:
5 = a · [tex]b^0[/tex]
Since any number raised to the power of 0 is 1, we find:
a = 5

Step 2: Use the Second Point (8, 1280)

Substitute x = 8, y = 1280, and a = 5 into the equation:
1280 = 5 ·[tex]b^8[/tex]
To solve for b, divide both sides by 5:
256 = [tex]b^8[/tex]

Finding the 8th root of both sides gives:
b = 2

Step 3: Write the Exponential Function

Now that we have a = 5 and b = 2, the exponential function is:
y = 5·[tex]2^x[/tex]

9. A. if 23n=11112, find n​

Answers

Answer:

23n=11112

n=11112÷23

...n=483.13

The value of n in the equation ( 23n = 11112 ) rounded to the nearest tenth is 483.1.

What is an Equation?

An equation is simply a mathematical formula that expresses the equality of two expressions, using the equals sign as a connection between them.

Given the data in the question;

23n = 11112n = ?

We simply divide both sides by 23

23n = 11112

23n/23 = 11112/23

n = 11112/23

n = 483.1

Therefore, the value of n in the equation ( 23n = 11112 ) rounded to the nearest tenth is 483.1.

Learn more about equations here: brainly.com/question/14686792

#SPJ2

find the mean and median of the data.

12, 15, 16, 18, 20, 90

please help!!!

Answers

The median is 17. The mean is 28.5. Hope this helps!

i will mark brainliest to whoever will aswer this

2+2=_______?????

Answers

Answer:

4

Step-by-step explanation:

It because when you count on your hands from 2 go up 2 more you get 4

The length of a football field is 300 feet (excluding the end zones). The diagonal is about 316.2 feet. What is the width of the football field, rounded to the nearest foot?

Answers

Answer:

w = 100 ft

Step-by-step explanation:

A football fields is of rectangular shape, and for that shape, we know the length (300 ft) and one diagonal (316,2 ft). To determine the width we have to understand that diagonal, length and a width form a right triangle, and in a right triangle we can apply Pytagoras theorem. Therefore:

d(diagonal)²  =  l²  +  w²    where l is the length and w the width

d²  =  l² + w²    ⇒    d²  -  l²  = w²

w²  =  ( 316,2)² - (300)²   ⇒   w²  =  99982,44 - 90000

w² = 9982,44

w = √9982,44

w = 99,91 ft

Rounded to the nearest foot

w = 100 ft

simplify the complex fraction 2 3/4 divided by 1 1/8

Answers

Answer:

2 3/4 divided by 11/8 would be 2.

Factor the numerator and denominator and cancel the common factors.

I hope that this was helpful :3

STAY SAFE!! :)

Just listen to him/her . kk bye now ! :)

What volume of water is needed to dilute 10.0 mL of 2.0 M HCl to make a 0.25 M HCl solution?
A. Enough to make 50. ml of solution
B. Enough to make 60. mL of solution
C. Enough to make 70. mL of solution
D. Enough to make 80. mL of solution

Answers

Answer:

D. 80 mL

Step-by-step explanation:

Given:

- 10.0 mL of HCL

- 2.0 M HCl

- .25 M HCl

1) Convert mL to L

10 mL/1000 mL = .01 L

2) Find # of moles of HCl

2.0 M HCl = (x/.01 L)

x = .02 mol HCl

3) Find volume needed to make .25 M HCl

.25 M = .02 mol HCl/ y

y = .08 Liters

4) Convert Liters to mL

.08 L * 1000 mL = 80 mL

Answer: 80 mL (D)

The answer for that would be D. 80 mL

A scientist took this picture and concluded that ________.


all stars have the same brightness
all stars show a pattern
not all stars show a pattern
stars are not always visible

Answers

all stars show a pattern

Which type of statement had the form If A, then B
A. Deductive
B. False
C. Conditional
D. True

Answers

The answer is conditional. I had this question and got it right have a great day

Complementary angles mean all 3 angles equal how many degrees?​

Answers

Answer:

Two Angles are Complementary when they add up to 90 degrees (a Right Angle)

Step-by-step explanation:

Please mark Brainliest :)

Write this in standard form. Six hundred twenty-nine and eleven hundredths

Answers

Answer:

629.11

Step-by-step explanation:

Six hundred twenty-nine and eleven hundredths

Hundreds | Tens | Ones | Tenths | Hundredths  

Fill in the above place value chart

Hundreds (100) | Tens (10) | Ones (1) | Tenths (0.1)  | Hundredths  (0.01)

       6                          2               9        .         1                        1

Multiply each value in the chart by their respective number above it.

6 (100) + 2 (10) + 9 (1) + 1 (0.1) + 1(0.01)

600 + 20 + 9 + 0.1 + 0.01

Add

629.11

Hope this helps :)

The cost of 24 bottles of water cost $6. Which expression shows how to find the cost 10 bottles of water.

Answers

Answer:

2.5

Step-by-step explanation:

Okay so this is just unit pricing I believe.  First we take a look at the info we have.

24 bottles cost $6

We want 10

So what is 24 divided by 6?

Once you have that, it is the unit price.

Since 4 x 6 is 24, what would you use to find 10?

And thats how you find your answer!  Hope this helped.

Have a great day ad stay healthy.

A tabletop in the shape of a trapezoid has an area of 5,106 square centimeters. Its longer base measures 119 centimeters, and the shorter base is 65 centimeters. What is the height?

Answers

A\9

Step-by-step explanation:

Answer:

[tex]55.5cm[/tex]

Step-by-step explanation:

[tex]area \\ 5106= \frac{1}{2} (a + b) \times h \\ 5106= \frac{1}{2} \times (119 + 65) \times h \\ 5106= \frac{1}{2} \times 184 \times h \\ 5106 = \frac{184}{2} \times h \\ 5106 = 92h \\ \frac{5106}{92} = \frac{92h}{92} \\ \\ h = 55.5cm[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

In 1970, the population of a small town was 4,200. The population is decreasing at a rate of 2.4% per year. Which of the following shows an exponential decay function to find the quarterly decay rate?The population is decreasing by how much percent per quarter?

Answers

Answer:

a. y = 4,200 [tex]0.976^{4t}[/tex]

b. 9.2%

Step-by-step explanation:

Given the information:

The intinital value: 4,200 The population is decreasing at a rate of 2.4% per year

=> the base number of the exponential function is:

100% - 2.4% = 97.6% = 0.976

Let t is quarter

Let y is the population

=>  the following shows an exponential decay function to find the quarterly decay rate is:

y (t)= 4,200 [tex]0.976^{4t}[/tex]

b. The population is decreasing by how much percent per quarter?

Let t = 0 we have: y(0) = 4,200 [tex]0.976^{4*0} = 4200[/tex]

Let t = 1 we have:  y(1) = 4,200 [tex]0.976^{4*1} = 3811[/tex]

=> the decreasing percentage is:

= (y(0) - y(1)) / y(0)*100%

= (4200 - 3811) / 4200 *100%

= 389/4200*100%

= 9.2%

The expoenetial function that represents the quarterly decay is y = 4200(0.994)^4t.

The  population is decreasing by 0.4% every quarter.

What is the exponential function that determines the rate of decrease every quarter?

The formula that can be used to determine the rate of decrease every quarter is:

FV = P(1 - r/m)^tm

FV = Future value P = Present value of the population = 4,200R = rate of decrease = 2.4%m = number of compoundingt = number of years

y = 4200( 1 - 0.024/4)^4t

y = 4200(1 - 0.006)^4t

y = 4200(0.994)^4t

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