If 3x² -6=y for all real numbers x, then x² - 2 =

Answers

Answer 1
3x² - 6 = 3(x² - 2)

If 3(x² - 2) = y, then
[tex] \frac{3(x^2-2)}{3}= \frac{y}{3} \\ \\ x^2-2 = \frac{y}{3} [/tex]

Answer:
x² - 2 = y/3

Related Questions

Opposite angles of a parallelogram are congruent.
a. True
b. False

Answers

Correct answer is true

Tell which equation you would use to isolate a variable in order to solve the system using substitution. Explain your reasoning.

2x + y=-10
3x-y=0

Answers

2x+y=-10
Multiply both side by 3
2x*3+y*3=-10*3
6x+3y=-30

3x-y=0
Multiply both side by 2
3x*2-y*2=0*2
6x-2y=0
Next, use substitute property
6x+3y=-30
    -
6x-2y=0
    =
y=-30
3x-y=0
Substitute y with -30
3x-30=0
Add 30 to each side
3x-30+30=0+30
3x=30
Divided both side by 3
3x/3=30/3
x=10, so the solution pair is (10,-30). In this case, there is the first way to solve these two equation.
Then, I would use equation 3x+1.5y=-15 in this question by multiply 2x+y=-10 by multiplying both side by 3/2 to eliminate x and to solve variables for y. Hope it help!

Which function below is the inverse of f(x) = The quantity of four x minus three, over two.?

Answers

[tex]\bf f(x)=y=\cfrac{4x-3}{2}\qquad inverse\implies x=\cfrac{4y-3}{2}\impliedby \begin{array}{llll} first\ switch\\ the\ variables\\ then\ solve\\ for\ "y" \end{array} \\\\\\ 2x=4y-3\implies 2x+3=4y\implies \cfrac{2x+3}{4}=y=f^{-1}(x)[/tex]

The linear equation when b = 5 and m = –2 is

Answers

mx+b=y is a linear equation formula
So the answer would be y=-2x+5 so the answer would be D

Answer:

y=-2x+5

Step-by-step explanation:

[tex] \frac{x}{5}+\frac{3x}{15}=\frac{2x}{3} } [/tex]+2 Answer plz math help

Answers

Multiply all terms by 15
3x+3x= 10x+30

Combine like terms
6x=10x+30

Subtract 10x from both sides
-4x=30

Divide both sides by -4
x= -7.5

Final answer: -7.5

75% of our 1000 products are shipped on time each month the remainder have defects that take two weeks to fix and ship our clients complain about 10% of the anti-products are defective and 5% of the product shipped late or defective what is the overall percentage of defective products

Answers

The number of products shipped on time is 75% of 1000 = 750
The number of products shipped late is 25% of 1000 = 250

The number of defective product from the products that shipped on-time is 10% of 750 = 75

The number of defective product from the products that shipped late is 5% of 250 = 12.5

The total number of defective products is 75+12.5 = 87.5.

This is 87.5 out of 1000 products and as percentage it's [tex] \frac{87.5}{1000}=0.0875 [/tex]×100 = 8.75%

Final answer:

Calculating the overall percentage of defective products from the given data, we find that 150 out of 1000 products are defective, leading to an overall defect rate of 15%.

Explanation:

The question asks us to calculate the overall percentage of defective products based on the given scenarios. Firstly, it's mentioned that 75% of 1000 products are shipped on time, which means 750 are shipped on time and 250 are initially defective.

Since clients complain that 10% of the products are defective and 5% of the products are shipped late or are defective, we need to consider these percentages in our calculations.

To find the number of defective products, we can assume the 10% complaint rate on the entire batch of products which would lead to 100 out of 1000 products being defective. This is the initial estimated number of defective products.

To address the 5% of the products that are both shipped late and are defective, we consider this as an additional defect rate on top of the existing one, which would be another 50 products.

Total defects would then be the sum of defects from the complaints about defects and the defects because of shipping delay, which amounts to 100 + 50 = 150 defective products. To find the overall percentage, we divide 150 by 1000 and multiply by 100, giving us an overall defect rate of 15%.

Find the base of a parallelogram with an area (
a. of 60 square inches and height (h) of 4 inches. Use the formula for the area of a parallelogram

Answers

area of parallelogram = base x height
base = area of parallelogram/ height
= 60/4
= 15 inches

The base of parallelogram is 15 inches.

What is parallelogram?

A parallelogram is a two-pair quadrilateral with parallel sides. A parallelogram has opposite sides that are the same length and have opposite angles that are the same size. Additionally, the interior angles on the same transversal side are supplemental. 360 degrees is the sum of all the interior angles.

Given area  of a parallelogram is 60  square inches

area of parallelogram is given by product of base and height,

Area = b × h

where b = base and  h = height

height = 4 inches

Area = b × h

60 = b × 4

b = 60/4 = 15 inches

Hence the base is 15 inches.

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Assume that y varies inversely with x. If y=7 when x=2/3, find y when x=7/3

Answers

Inverse variation is of the form:

y=k/x, which we can express as:

yx=k  we are given the point (2/3, 7) so we can solve for k

7(2/3)=k

14/3=k

y=14/(3x), so when x=7/3

y=(14/3)/(7/3)

y=(14/3)(3/7)

y=2

PLEASE HELP!!!!! The velocity of sound in air is given by the equation , where v is the velocity in meters per second and t is the temperature in degrees Celsius. Find the temperature when the velocity is 329 meters per second by graphing the equation. Round the answer to the nearest degree. Show your work.

Answers

The equation of velocity of sound in air is v = 20 √(273 + t). In this problem, we need to find the temperature when the velocity is 329 meters/s. You need to measure the time it takes a sound to travel a measured distance in order to measure its speed in air.

 

Given:

Velocity of sound in air equation = v = 20 √(273 + t)

Velocity = 329 m/s

 

To solve:

V = 20 √(273 + t)


329 = 20 * sqrt(273 + t)


16.45 = sqrt(273 + t)


273 + t = 16.45^2


t- 16.45^2-273


t = -2.4 degrees Celsius

 

So, the temperature when the velocity is 329 meters per second is -2.4 degrees Celsius.

What is the exact value of x in the exponential equation 15.5 + e10x = 85.5?

Answers

hello : 
15.5 + e10x = 85.5
 e10x = 85.5 - 15.5 
e10x = 70
10x = ln(70)
x = ln70/10
x = 0.424

PLEASE HELP precal!

Answers

check the picture below

so.. .hmmm the vertex is at the origin... and we know the parabola passes through those two points... let's use either.. say hmmm 100,-50, to get the coefficient "a"

keep in mind that, the parabolic dome is vertical, thus we use the y = a(x-h)²+k  version for parabolas, which is a vertical parabola

as opposed to x = (y-k)²+h, anyway, let's find "a"

[tex]\bf y=a(x-0)^2+0\implies y=ax^2\qquad \begin{cases} x=100\\ y=-50 \end{cases}\implies -50=a100^2 \\\\\\ \cfrac{-50}{100^2}=a\implies -\cfrac{1}{200}=a \\\\\\ thus\qquad \qquad y=-\cfrac{1}{200}x^2\implies \boxed{y=-\cfrac{x^2}{200}}[/tex]

now.. .your choices, show.... a constant on the end.... a constant at the end, is just a vertical shift from the parent equation, the equation we've got above.. is just the parent equation, since we used the origin as the vertex, it has a vertical shift of 0, and thus no constant, but is basically, the same parabola, the one in the choices is just a shifted version, is all.


The length of a rectangle is 2 yd longer than its width. if the perimeter of the rectangle is 40 yd , find its area.

Answers

perimeter = 2L+2W

L=2+w

40 = 2L+2W

40= 2(2+w)+2W

40=4+2w+2w

36=4w

w=9

L=9+2=11

2(9) = 18, 2(11) = 22, 22+18 = 40

L=11

W=9

 Area = L x w

area = 11x9= 99 square yards

A drawer contains five pairs of socks that are brown, black, white, red, and blue. Claude takes the red socks out of the drawer. What is the probability of Claude choosing the red socks on his first pick?

Answers

A drawer contains five pairs of socks that are brown, black, white, red, and blue. Claude takes the red socks out of the drawer. What is the probability of Claude choosing the red socks on his first pick?

Answer: 1/25

Answer:

The answer would be 1/25 Hopefully this any T4L students!

Determine whether the equation represents y as a function of x 16x-y^4=0

Answers

Given
[tex]16x-y^4=0 \\ \\ \Rightarrow y^4=16x \\ \\ \Rightarrow y= \sqrt[4]{16x} =2 \sqrt[4]{x} [/tex]

For any value of x, there are two possible values of y, thus the equation does not represent y as a function of x.

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output.

Identify intervals on which the function is increasing, decreasing, or constant. g(x) = 4 - (x - 6)^2 ??

Answers

Taking the derivative will give you the velocity at any time.

g(x)=4-(x-6)^2

g(x)=4-(x^2-12x+36)

g(x)=4-x^2+12x-36

g(x)=-x^2+12x-32

dg/dx=-2x+12

So g(x) will be increasing when dg/dx>0

-2x+12>0

-2x>-12

x<6

So g(x) is increasing on the interval (-oo, 6)

g(x) will be decreasing when dg/dx<0

-2x+12<0

-2x<-12

x>6

So g(x) will be decreasing on the interval (6, +oo)

P, Q, and R are three different points. PQ = 3x + 2, QR = x, RP = x + 2, and . List the angles of PQR in order from largest to smallest and justify your response.

Answers

PQR is a triangle
QR = x  ⇒ x>0
If x>0 then:
QR is the smallest side
PQ is the largest side

In the triangle, the largest angle lies opposite the largest side.
The angles of ΔPQR in order from largest to smallest:
∠R is largest    [opposite to PQ]
∠Q is middle    [opposite to RP]
∠P is smallest   [opposite to QR] 
Final answer:

The angles of triangle PQR are ordered from largest to smallest as <>R,

Explanation:

The question involves applying the principles of geometry to compare lengths of sides in a triangle, and thereby determine the relative magnitude of angles in triangle PQR. According to the triangle inequality theorem, the largest angle in a triangle is opposite the longest side, and the smallest angle is opposite the shortest side. Given that the side lengths are represented as PQ = 3x + 2, QR = x, and RP = x + 2, we can compare the expressions to conclude which side is longest and which is shortest, assuming all values of x are positive since they represent lengths.

Firstly, it is obvious that QR (x) is the shortest side since it is just x without any additional positive value. Secondly, between RP (x + 2) and PQ (3x + 2), PQ will always be longer than RP for all positive x because it has a larger coefficient in front of x. Hence, the angle opposite PQ (angle R) will be the largest angle, and the angle opposite QR (angle P) will be the smallest. The angle at Q will be between the other two angles in terms of their measurements since PQ is longer than RP but both are longer than QR.

To summarize, the angles of Triangle PQR ordered from largest to smallest are: ∠R, ∠Q, and ∠P.

An object is thrown upward with an initial velocity of 32 feet per second. The objects height is modeled by the function h(t) = - 16t2 + 32t where t is the time of the at height, h(t). What is the maximum height of the object?
32 ft
60 ft
72 ft
104 ft

Answers

check the picture below.

[tex]\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\ \begin{array}{lccclll} y = &{{ -16}}x^2&{{ +32}}x&{{ +0}}\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array}\qquad \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)[/tex]

so, the object reaches at maximum height of  [tex]\bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\ feet[/tex]

HONORS PROJECT GEOMETRY HELP

Maurice and Johanna have appreciated the help you have provided them and their company Pythgo-grass. They have decided to let you consult on a big project.

1, A triangular section of a lawn will be converted to river rock instead of grass. Maurice insists that the only way to find a missing side length is to use the Law of Cosines. Johanna exclaims that only the Law of Sines will be useful. Describe a scenario where Maurice is correct, a scenario where Johanna is correct, and a scenario where both laws are able to be used. Use complete sentences and example measurements when necessary.


2, An archway will be constructed over a walkway. A piece of wood will need to be curved to match a parabola. Explain to Maurice how to find the equation of the parabola given the focal point and the directrix.


3, There are two fruit trees located at (3,0) and (−3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the y-axis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane.
4, A pipe needs to run from a water main, tangent to a circular fish pond. On a coordinate plane, construct the circular fishpond, the point to represent the location of the water main connection, and all other pieces needed to construct the tangent pipe. Submit your graph. You may do this by hand, using a compass and straight edge, or by using a graphing software program.


5, Two pillars have been delivered for the support of a shade structure in the backyard. They are both ten feet tall and the cross sections of each pillar have the same area. Explain how you know these pillars have the same volume without knowing whether the pillars are the same shape.

Answers

1. Maurice would be correct if the triangular section (ex. sides labeled ABC) had a missing opposite side length, specifically from the angle where the adjacent and the hypotenuse of the triangle meet. Johanna's suggestion would work if the side is adjacent from the opposite and hypotenuse needed to be found. A scenario in which both laws could be used is if the opposite angle and hypotenuse are known and needs to find the missing side lengths and adjacent of the the triangular section.

Three cities lie along a perfectly linear route: Springfield, Clarksville, and Allentown. Molly lives in Springfield and works in Allentown. She makes it to work using two gallons of gas in her car. Her friend Edgar lives in Allentown and works in Clarksville. It takes Edgar one gallon of gas to get to work. If Molly's car averages 26 miles per gallon, and Edgar's car averages 17 miles per gallon, about how far apart are Springfield and Clarksville?

Answers

When it says that the cities are routed linearly, it means that these cities are located right next to each other. From the left, the order is Springfield, Clarksville, then Allentown. You have details on the number of gallons and the mileage. To get the distance travelled, just multiply the mileage with the gallons, to cancel out gallons leaving you with the distance in miles.

Now, since Molly travelled from Springfield to Allentown, the total distance she covered is the distance Edward travelled and the unknown distance between Springfield and Clarksville, denoted as x in the picture. So, the equation is then

Molly's distance = x + Edgar's distance
26 miles/gal(2 gal) = x + 17 miles/gal(1 gal)
x = 35 miles

Which of the following points lie in the solution set to the following system of inequalities?

y ≤ x − 5
y ≥ −x − 4

(−5, 2)
(5, −2)
(−5, −2)
(5, 2)

Answers

The answer is (5,-2) because when you plug it into the first problem you would get 0 which is greater than or equal to -2 and for the second you would get -9 which is less than or equal to -2

Answer: Second option : (5, −2)


Step-by-step explanation: Given system of inequalities

y ≤ x − 5

y ≥ −x − 4

Plugging x=5 and y=-2 in first inequality

-2  ≤ 5 − 5

-2 ≤  0 : True.

Plugging x=5 and y=-2 in second inequality

-2 ≥ −5 − 4

-2 ≥ -9 : Also true.

Point  (5, −2) satisfied both of the given inequalities in the system.

Therefore, (5,-2) is correct option.

Which geometric series converges?
A. 2+0.2+0.02+0.002+...
B. 2+4+8+16+...
C. 2-20+200-2000+...
D. 2+2+2+2+...

Answers

Answer:  The correct option is (A) 2 + 0.2 + 0.02 + 0.002 +  .  .  .

Step-by-step explanation:  We are given to select the correct geometric series that converges.

We know that

a geometric series converges if the modulus of its common ratio is less than 1.

Option (A) : 2 + 0.2 + 0.02 + 0.002 +  .  .  .

Here, first term, a= 2  and the common ratio is given by

[tex]r=\dfrac{0.2}{2}=\dfrac{0.02}{0.2}=\dfrac{0.002}{0.02}=~.~.~.~=0.1\\\\\Rightarrow |r|=|0.1|=0.1<1[/tex]

So, this geometric series will converge.

Option (A) is correct.

Option (B) : 2 + 4 + 8 + 16 +  .  .  .

Here, first term, a= 2  and the common ratio is given by

[tex]r=\dfrac{4}{2}=\dfrac{8}{4}=\dfrac{16}{8}=~.~.~.~=2\\\\\Rightarrow |r|=|2|=2>1.[/tex]

So, this geometric series will not converge.

Option (B) is incorrect.

Option (C) : 2 - 20 + 200 - 2000 +  .  .  .

Here, first term, a= 2  and the common ratio is given by

[tex]r=\dfrac{-20}{2}=\dfrac{200}{-20}=\dfrac{-2000}{200}=~.~.~.~=-10\\\\\Rightarrow |r|=|-10|=10>1.[/tex]

So, this geometric series will not converge.

Option (C) is incorrect.

Option (D) : 2 +2 + 2 + 2 +  .  .  .

Here, first term, a= 2  and the common ratio is given by

[tex]r=\dfrac{2}{2}=\dfrac{2}{2}=\dfrac{2}{2}=~.~.~.~=1\\\\\Rightarrow |r|=|1|=1.[/tex]

So, this geometric series will not converge.

Option (D) is incorrect.

Thus, the correct option is (A).

The geometric series that converges is 2+0.2+0.02+0.002+ ...:

Thus, option (A) is correct.

In a geometric series, the terms are multiplied by a constant ratio to obtain the next term.

If the absolute value of the common ratio is less than 1, the series converges.

A. 2 + 0.2 + 0.02 + 0.002 + ...:

In this series, the common ratio is 0.1 (each term is divided by 10).

Since the absolute value of the common ratio is less than 1, this series converges.

B. 2 + 4 + 8 + 16 + ...:

In this series, the common ratio is 2 (each term is multiplied by 2).

Since the common ratio is greater than 1, this series diverges.

C. 2 - 20 + 200 - 2000 + ...:

In this series, the terms alternate in sign, but the absolute value of the common ratio is 10.

Since the absolute value of the common ratio is greater than 1, this series diverges.

D. 2 + 2 + 2 + 2 + ...:

In this series, the common ratio is 1 (each term is the same).

Since the common ratio is equal to 1, this series neither converges nor diverges. It is a divergent series.

Therefore, the geometric series that converges is 2 + 0.2 + 0.02 + 0.002 + ...

Thus, option (A) is correct.

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If a fair coin is tossed 9 ​times, in how many different ways can the sequence of heads and tails​ appear

Answers


10 different sequences
all tails, 1 head 8 tails,2 heads 7 tails,3 heads 6 tails,4 heads 5 tails,5 heads 4 tails,6 heads 3 tails,7 heads 2 tails,8 heads 1 tail and All heads. 

An angle is 15 degrees less than twice its complement. find the angles

Answers

The measure of an angle = 2 * the compliment of the angle - 15
Angle = 2 * (180 - angle) - 15
x = 2 * 180 - 2 * x - 15
x = 345 - 2x
3x = 345

x = 115 degrees.

99 POINTS!!! Find the equation for an ellipse with vertices at (-6, 0) and (6, 0) and foci at (-4, 0) and (4, 0).

Answers

(x^2)/a^2+(y^2)/b^2=1
a>b
a=6, a^2=36
foci=(a^2-b^2)^(1/2)
4=(36-b^2)^(1/2)
16=36-b^2
b^2=36-16
b^2=20
b=2(5)^(1/2) or (20)^(1/2)
1=(x^2/36)+(y^2/20)

(x^2)/a^2+(y^2)/b^2=1

a>b

a=6, a^2=36

foci=(a^2-b^2)^(1/2)

4=(36-b^2)^(1/2)

16=36-b^2

b^2=36-16

b^2=20

b=2(5)^(1/2) or (20)^(1/2)

1=(x^2/36)+(y^2/20)

Which of the following is a solution of x2 + 4x + 10?

2 + i times the square root of 6
−2 + i times the square root of 24
−2 + i times the square root of 6
2 + i times the square root of 24

Answers

x^2+4x+10=0

x^2+4x=-10

x^2+4x+4=-6

(x+2)^2=-6

x+2=±i√6

x=-2±i√6

So the correct answer is the third one down from the top.

Answer:

[tex]x=2+-i \sqrt{6}[/tex]

Step-by-step explanation:

[tex]x^2 + 4x + 10[/tex]

To find out the solution we set the expression =0 and solve for x

[tex]x^2 + 4x + 10=0[/tex]

Apply quadratic formula to solve for x

[tex]x=\frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]

a=1, b=4, c=10 plug in the values in the formula

[tex]x=\frac{-4+-\sqrt{4^2-4(1)(10)}}{2a}[/tex]

[tex]x=\frac{-4+-\sqrt{-24}}{2(1)}[/tex]

The value of square root (-1) is 'i'

[tex]x=\frac{-4+-2i\sqrt{6}}{2}[/tex]

Divide each term by 2

[tex]x=2+-i\sqrt{6}[/tex]

The expression 9n is also considered a _____.
constant
variable
term

Answers

Answer:

Term

Step-by-step explanation:

hope this helps

Given the arithmetic sequence A1, A2, A3, A4, 58,69,80,91
What is the Value of A21?


***PLEASE HELP******

Answers

an arithmetic sequence, means that there is an equal difference between each number of the sequence. 

i.e. a, a+d, a+2d, a+3d...

where a is the first term, and d is the difference

in your case, a (first term) = 58

to find the difference, subtract 58 (a) from 69 (a+d) to get d. 

d = 69 - 58 = 11

(you can always check your calculation on another two consecutive terms: 91 - 80 also equals 11)

the general formula for any term in an arithmetic sequence is: 

T(n) = a + (n-1)d ...(or A(n))

in your case, n = 21

subbing into the formula: 

A21 = a + (21-1)d = 58 + 20(11) = 278

hope that helps :)

Barry’s Bagel Emporium sells a dozen bagels for $5.00. This price is no longer high enough to create a profit. The owner decides to raise the price. He does not want to alarm his customers with too large of an increase. He is considering four different plans. Plan A: Raise the price by $0.05 each week until the price reaches $8.00. Plan B: Raise the price by 10 percent each week until the price reaches $8.00. Plan C: Raise the price by the same amount each week for 6 weeks, so that in the sixth week the price is $8.00. Plan D: Raise the price by $0.25 each week until the price reaches $8.00. Which plan will result in the price of the bagels reaching $8.00 fastest? plan A plan B plan C

Answers

Plan C. He already has $5, so to get to $8 it needs to be raised $3. In Plan C, he wants to raise it the same amount for 6 weeks. $3.00 / 6 = .50... 6 weeks would give him the fastest Plan out of all the Plans.... Making your answer Plan C

Hope This Helps
Correct If I'm Wrong

Answer:

Plan B is correct answer.

Step-by-step explanation:

Raise the price by 10 percent each week until the price reaches $8.00.

Week 1. Starting price $5

[tex]0.1\times5=0.5[/tex]

price becomes = [tex]5+0.5=5.5[/tex]

Week 2.

[tex]0.1\times5.5=0.55[/tex]

Price becomes = [tex]5.5+0.55=6.05[/tex]

Week 3.

[tex]0.1\times6.05=0.605[/tex]

Price become = [tex]6.05+0.605=6.655[/tex]

Week 4.

[tex]0.1\times6.655=0.6655[/tex]

Price becomes = [tex]6.655+0.6655=7.320[/tex]

Week 5.

[tex]0.1\times7.320=0.732[/tex]

Price becomes = [tex]7.320+0.732=8.052[/tex]

So, we can see that in 5 weeks the price becomes $8 from $5. Therefore, plan B is the best plan.

A certain drug dosage calls for 25 mg per kg per day and is divided into two doses (1 every 12 hours). if a person weighs 80 pounds, how much of the drug should be administered each time?

Answers

kg = 2.20462 lb 
kg(2.20462)  = 80 lb
36.2874 kg = 80 lbs
25 mg (36.2874 kg) = 907.185 mg
907.185 / 2 = 453.5925 mg per 12 hours

The required amount of drug for each time a day is given as 425 mg.

What is a Measurement unit?

A measurement unit is a unit to measure certain quantities.

For example, the mass can be measured in kilograms, length can be measured in meter and time can be measured in seconds.

To find the measurement of a new quantity known units can be used in operation. As to find the unit for speed we use m/s as a unit, where, m is the unit of distance and s is the unit of time.

Given that,

The weight of the person is 80 pounds.

The amount of dose of drug per day is 25 mg/kg

Then, the amount of drug for each time a day is 12.5 mg/kg.

The weight of the person in kilogram can be calculated as follows,

1 pound = 0.45 kg

Then, 80 pounds = 0.45 × 80

                             = 34 kg

Now, the amount of drug to be taken each time is 34 × 12.5 = 425mg.

Hence, the amount of drug that should be administered to the person each time is 425 mg.

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what is the inverse of the function f(x)=1/9x+2

Answers

Inverse works in this way:

y = 1/9x + 2,

you should swap the places of x and y and find y again, in this case it will be

x = 1/9y + 2    =>     x-2 = 1/9y    =>   (x-2) * 9y = 1   =>    9y = 1/(x-2)

and finally we got y = [tex] \frac{1}{(x-2)*9} [/tex]
Other Questions
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