Answers
4(4)-1 (4)+ 2 4 can not be the answer
16-1 =6
=15
4x-1 x + 2
4(5)-1 (5)+ 2 5 can not be the answer
20-1 =7
=19
4x-1 x + 2
4(1)-1 (1)+ 2 X= 1 is the answer!!!
4 - 1 1 + 2
=3 =3
Answer:
Option D. x = 1
Step-by-step explanation:
If the two triangles Δ ABC and ΔDEC are similar then there corresponding sides will be in the same ratio.
Now using this theorem in these triangles
[tex]\frac{AB}{DE}=\frac{BC}{EC}[/tex]
Now it has been given
AB = (4x - 1)
BC = 4
EC = 4
DE = x + 2
By putting these values in the formula
[tex]\frac{4x-1}{x+2}=\frac{4}{4}=1[/tex]
We cross multiply on both the sides
(4x - 1) = (x + 2)
4x - x = 1 + 2
3x = 3
x = 1
Option D. x = 1 is the answer.
Related Questions
The table below represents ordered pairs of a function. Which change could be made so that the relation in the table is no longer a function
Answers
State a true conclusion. 1) If a ● b = 0, then a = 0 or b = 0 2) 3x = 0
Answers
Proposition 2) 3x = 0
=> 3 = 0 or x = 0
Given that 3 ≠ 0, x must be equal to 0.
Conclusion: x = 0
Answer:
x=0
Step-by-step explanation:
Proposition 1) If a ● b = 0, then a = 0 or b = 0
Proposition 2) 3x = 0
=> 3 = 0 or x = 0
Given that 3 ≠ 0, x must be equal to 0.
Conclusion: x = 0
Let p: The shape is a rhombus. Let q: The diagonals are perpendicular. Let r: The sides are congruent. Which represents "The shape is a rhombus if and only if the diagonals are perpendicular and the sides are congruent”?
Answers
"if and only if" is represented using the biconditional logic operator (↔) and "and" is represented using the logical conjuction operator (∧).
Therefore, "The shape is a rhombus if and only if the diagonals are perpendicular and the sides are congruent” is represented by "p ↔ (q ∧ r)"
Answer:
C.)p ↔ (q ∧ r)
Step-by-step explanation:
I scored a 100 on my quiz
a line that passes through two sides of triangles divides the sides proportionally
A. always
B. sometimes
C. never
Answers
If $5000 is invested at 7.8% interest compounded monthly, how much would you have after 54 months?
Answers
5000 x (1+0.078/12)^54
5000 x (1.0065)^54
$7094.37
How do I simplify ((3x^2+12x+12)/(2x^2+x-6))/((4x^2-9)/(3x^3+x^2-10))
Answers
[tex]= \dfrac{3(x + 2)^2}{(2x - 3)(x + 2)} \times \dfrac {3x^3+x^2-10} {(2x + 3)(2x - 3)} } [/tex]
[tex]= \dfrac{3(x + 2)}{2x - 3} \times \dfrac {3x^3+x^2-10} {(2x + 3)(2x - 3)} } [/tex]
[tex]= \dfrac{3(x + 2)(3x^3+x^2-10) }{(2x - 3)^2(2x + 3)} [/tex]
A triangle has base 6 cm and area 42 cm^2 what is the height of the triangle
Answers
A=bh/2
42=6h/2
Divide both sides by 6 giving you
h/2=7
Then, multiply by 2 on both sides giving you
h=14
The height then is 14 cm.
The height of the triangle is 14 cm.
Explanation:To find the height of the triangle, we can use the formula for the area of a triangle: Area = 1/2 * base * height. In this case, the base is 6 cm and the area is 42 cm^2. By rearranging the formula, we can solve for the height: Height = 2 * Area / Base. Plugging in the values, we get Height = 2 * 42 cm^2 / 6 cm = 14 cm.
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Which is harder linear algebra or abstract algebra?
Answers
Linear algebra
I've always had trouble with graphs and it's much better if the algebra is similar to arthemetic
Which pair of triangles are congruent by ASA ?
Answers
The pair of triangles that are congruent by ASA is figure C
The ASA theoremTwo triangles can be judged to be congruent using the ASA (Angle-Side-Angle) criterion. For triangles to satisfy ASA congruency:
Angle: The triangles' two matching angles have to coincide.Side: There must also be congruence on the included side that lies between the congruent angles.Put otherwise, the ASA criterion determines that two triangles are congruent if two of their angles and the included side are congruent, respectively. For this criterion, the angles and sides' order matters.
Based on the explanations, hence the pair of triangles that are congruent by ASA is figure C
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What theorem or postulate can prove a triangle to be an isosceles?
Answers
Final answer:
The Converse of the Base Angles Theorem states that if two angles of a triangle are congruent, then the triangle is isosceles.
Explanation:
In geometry, the theorem that can prove a triangle to be isosceles is the Converse of the Base Angles Theorem. It states that if two angles of a triangle are congruent, then the triangle is isosceles. In other words, if the two base angles of a triangle are equal, then the triangle is isosceles. For example, if angles A and B in triangle ABC are congruent (angle A = angle B), then triangle ABC is isosceles.
The vertex of the graph of a quadratic function is (–2, –9) and the y-intercept is (0, –5). Which of the following is the equation of the function? A. y = x2 +10x + 2 B. y = x2 +10x – 2 C. y = x2 – 2x – 5 D. y = x2 + 4x – 5
Answers
Find the quotient of 3 2/5 and 3 2/6. Express your answer in simplest form.
Answers
What is the equation of the line shown in this graph?
pls help
Answers
the line of the graph is vertical since both x coordinates are the same ( both are -2)
so the equation would be x = -2
Please help thank you.
30 points.
Answers
The sum of all angles with a polygon with n sides is
180(n-2)
We have 20 sides.
180(20 -2) = 180 * 18
= 3240
Thus, the sum of all angles is 3240 degrees.
The second choice is your answer.
Question 2:
First, let's calculate the sum of all the angles.
180(12 - 2) = 1800
Now, divide that by the number of sides to get the measure of one angle.
1800/12 = 150
Your answer is the last choice.
Question 3:
Do the same as we did in question 2, but instead of 12 sides, there are 6 sides.
A regular hexagon has an interior angle measure of 120 degrees.
(Note: you should remember that for future reference).
Now, let's form the following equation
3x = 120
Divide both sides by 3
x = 40
The first choice is your answer.
Have an awesome day! :)
1. 3240. 20 gon is called an isogon
2.150 because the formula for the interior angle or regular polynomials is [tex] \frac{180(n-2)}{n}[/tex]
3.3x = 120
Divide both sides by 3
x = 40
Difference of two numbers is 8. find the smallest possible product.
Answers
Can someone how to get the answer? Thanks! PLEASE HELPpppppppppppppppppppppppp
Answers
[tex]\mathrm{Apply\:log\:rule}:\ \log _a\left(x^b\right)=b\cdot \log _a\left(x\right) \ \textgreater \ \ln \left(6^x\right)=x\ln \left(6\right) [/tex]
[tex]x\ln \left(6\right)=\ln \left(21\right) \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}\ln \left(6\right) \ \textgreater \ \frac{x\ln \left(6\right)}{\ln \left(6\right)}=\frac{\ln \left(21\right)}{\ln \left(6\right)} [/tex]
[tex]Therefore \: x=\frac{\ln \left(21\right)}{\ln \left(6\right)}[/tex]
In your case ln means [tex] \frac{log 21}{log 6} [/tex]
after that you press (ALPHA) (L) which iOS the button for the parenthesis (. ). )
find LOG and then plug in the number you want.
repeat this until you get the equation you want.
Use the graph shown to fill in the blank.
When x = -3, then y = a0.
Answers
you will find that:
y= -6 at x= -3
slope = (-3+4)/(0+1) = 1 and b = -3
so y = 7x - 3
when x= -3 then
y = 1(-3) -3
y = -3 - 3
y = -6
answer
When x = -3, then y = -6
Which graph represents the solution set of the system of inequalities?
Answers
(see image)
bottom right image
Explanation:
First try the origin (0,0) to rule out two of the graphs.
3y ≥ x - 9
3(0) ≥ (0) - 9
3 ≥ - 9 yes
3x + y > - 3
3(0) + (0) > - 3
3 > - 3 yes
so the origin should be in the shaded area of the graph, which rules out the top right and bottom left graphs.
Now try a coordinate that is in the shaded area of one of the remaining graphs, but not in the other one. If it works, the graph is the one that has that point in the shaded region, and vice versa.
Try point (4, 2)
3y ≥ x - 9
3(2) ≥ (4) - 9
6 ≥ - 5 yes
3x + y > - 3
3(4) + (2) > - 3
12 + 2 > - 3
14 > - 3 yes
So the graph is the bottom right one since (4, 2) is included in that shaded region.
What is the probability of throwing a number greater than 4 when rolling a number cube that has sides labeled 1, 2, 3, 4, 5, 6?
Answers
The only numbers there are is 5 and 6.
That means that there are 2 outcomes out of 6 total outcomes.
That would be 2/6.
Divide the the top and bottom by 2.
In simplest form it would be 1/3.
2/6=1/3
The answer is 1/3. The probability of throwing a number greater than 4 is 1/3.
The probability of rolling a number greater than 4 on a six-sided die is 1/3 or 0.33 or 33%. This is obtained by dividing the number of favourable outcomes (2, i.e., 5 and 6) by the total number of outcomes (6).
Explanation:The subject of the question is the probability in mathematics, specifically related to an experiment involving rolling a six-sided die. To answer your question, a six-sided die has numbers from 1 to 6. But you are asking about throwing a number greater than 4. There are only two outcomes that are greater than 4, the numbers 5 and 6. Therefore, the possible favorable outcomes are 2.
The total outcomes (since it's a six-sided standard die) are 6. Probability is calculated by dividing the number of favorable outcomes by the total number of outcomes. In this case, it will be 2/6 = 1/3 which is approximately 0.33 or 33%.
This means, if you roll the die, on an average, you can expect to roll a number greater than 4 about 33 times if you roll it 100 times.
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What is the value of cos 45 degrees?
(answers in picture)
Answers
which graph shows the inequality y>-2
Answers
For what values of x and y must each figure be a parallelogram?
Answers
(6x - 180)° = 180°
6x = 360°
x = 60°
5(60)-180= 300-180=120°
I have a graphing question
Answers
[tex](y-y_1)=m(x-x_1)[/tex]
where [tex](x_1,\ y_1)[/tex] is a point on the line.
Given
[tex]y-3=\frac{3}{4}(x+2) \\ \\ y-3=\frac{3}{4}(x-(-2))[/tex]
Thus the line has a slope of 3/4 and passes through the point (-2, 3), we can obtain another point on the line by substituting an arbitrary value for x.
Consider x = 2, then
[tex]y-3= \frac{3}{4} (2+2)= \frac{3}{4} (4)=3 \\ \\ \Rightarrow y=3+3=6[/tex]
Thus another point on the line is (2, 6).
The line can then be graphed by joining the two points.
Help please! I need to show my work
Answers
a.
PC is 2/3 of PY, and CY is 1/3 of PY.
If CY = 10, then PC = 20, and PY = 30
b.
If QC = 10, then ZC = 5, a nd ZQ = 15.
c.
X is the midpoint of side PQ.
PX = XQ = 1/2(PQ)
If PX = 20, PQ = 40
[02.05]
Solve for x: 4 − (x + 2) < −3(x + 4) (1 point)
x < −7
x > −7
x < −9
x > −9
Answers
4-x-2<-3x-12 => 2-x<-3x-12
next, eliminate x on one side. here I'll eliminate -3x by adding 3x on both side:
2+2x<-12
2x<-14
x<-7
Option A
x<-7
Given :
[tex]4 - (x + 2) < -3(x + 4)[/tex]
Explanation :
Solve the given inequality for x by applying algebraic properties
We use order of operation to simplify the left and right side of inequality
[tex]4- (x + 2) < -3(x + 4)\\4-x-2<-3x-12\\-x+2 < -3x -12\\Add\; 3x \; on \; both \; sides\\2x+2<-12\\Subtract\; 2\; from \; both \; sides\\2x<-14\\Divide \; both \; sides \; by 2\\x<-7[/tex]
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The sum of two integers is 28, and their product is 192. what are the two integers?
Answers
The product of 12 and 16 is 192, and the sum is 28.
What is the value of x in the parallelogram?
Answers
Extra information:
In a parallelogram, the consecutive angles are supplementary (so in this case, that means that because the line from corner x to the corner of 67 degrees is 180 degrees in total, the value of x has to be 180-67 = 113 degrees).
Find the area of the shaded region. Thanks!
Answers
now, let's rationalize the denominator for "r" first.
also notice, that section is just 1/4 of the area of that circle, so, let's just find the area of the whole circle with that "r", get one-quarter of it, and subtract it from the half of the area of the square.
[tex]\bf r=\cfrac{8}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies r=\cfrac{8\sqrt{2}}{2}\implies \boxed{r=4\sqrt{2}} \\\\\\ \stackrel{\textit{area of that circle}}{A=\pi (4\sqrt{2})^2}\implies A=\pi (16\cdot 2)\implies A=32\pi \\\\\\ \textit{how much is one-quarter of that?}\quad \cfrac{32\pi }{4}\implies \boxed{8\pi }\\\\ -------------------------------\\\\[/tex]
[tex]\bf \stackrel{\textit{area of the square}}{A=8\cdot 8}\implies A=64\qquad \stackrel{\textit{half of that square's area}}{32}\\\\ -------------------------------\\\\ \textit{shaded region}\implies \stackrel{\stackrel{\textit{half of that square}}{area}}{32}~~-~~\stackrel{\stackrel{\textit{one-quarter of the circle}}{area}}{8\pi }[/tex]
Answer:
-8π + 32
6.8675
Step-by-step explanation:
So we know that the are of the square is 64, and we know that the equation for the are of the shaded region is Area of square - 1/4 area of circle with a radius of 4√2 - area of 90/45/45 triangle with side lengths of 8 and 8.
s = square area
c = circle area
t = triangle area
∆ = shaded region area
∆ = s - 1/4c - t
input the numbers that we have for those variables:
∆ = 64 - 1/4(100.53) - 32
∆ = 64 - 25.1325 - 32
∆ = 32 - 25.1325
shade region approximate ≈ 6.8675
or to get an exact answer in terms of pi
∆ = 64 - 1/4(32π) - 32
∆ = 32 - 8π
shaded region = -8π + 32
just added this because it is hard to pick out the actual answer in the other person's answer.
The table below represents the atmospheric temperature at a location as a function of the altitude:
Altitude
(in thousand feet)
x
15
20
25
30
Temperature
(in °C)
f (x)
4
−6
−16
−26
The average rate of change of the function between x = 15 to x = 25 is ___degrees Celsius per thousand feet and represents the rate of change of temperature per thousand feet.
Answers
from x15 to x 25 is 4 - -16 = -20 degree change
25 -15 = 10000 feet
-20/10 = -2 degrees every 1000 feet
Answer: The average rate of change of the function between x = 15 to x = 25 is -2 degrees Celsius per thousand feet and represents the rate of change of temperature per thousand feet.
Step-by-step explanation:
The average rate of change of a function y=f(x) from [tex]x_1\ to\ x_2[/tex]is given by :-
[tex]k=\frac{f(x_2)-f(x_1)}{x_2-x_1}=\frac{-6-4}{20-15}[/tex]
Now, by the given table the average rate of change of the function between x = 15 to x = 25 will be :_
[tex]k=\frac{-16-4}{25-15}=\frac{-20}{10}=-2[/tex]
Hence, the average rate of change of the function between x = 15 to x = 25 is -2 degrees Celsius per thousand feet and represents the rate of change of temperature per thousand feet.
Important state labor laws and safety regulations came about as a result of the 1911 __________.
a. labor relations act
b. triangle shirtwaist factory fire
c. homestead strike
d. massachusetts child safety campaign
Answers
Answer:
Option B is correct.
Step-by-step explanation:
Important state labor laws and safety regulations came about as a result of the 1911 - Triangle shirtwaist factory fire
The Triangle shirtwaist factory fire was one of the worst industrial disasters during that time. Many people died due to a fire breakout in the factory. They could not escape the building and died due to smoke inhalation or burns.
After this incident, a Committee on Public Safety was formed that led to a legislation requiring labor laws and improved factory safety standards.