If i play two pure tones, one at 100 hz and the other at 110hz, will we perceive beats? if so, what will be the beat frequency

Answer: v1o/v2o=0.8518777161

Explanation:

using the equation from an answer in part A (https://brainly.com/question/14482074)

cancel out L and g and input the other variables in the ratio

((10kg+0.006kg)/0.006kg)sqrt(2(1-cos(4.3))) = 125.1276088 m/s = v1o

((10kg+0.012kg)/0.012kg)sqrt(2(1-cos(10.1))) = 146.8844723 m/s = v2o

v1o/v2o=0.8518777161

The direction of the resultant displacement of the dog is determined as 58.2⁰.

How to calculate the direction of the resultant displacement?

The direction of the resultant displacement of the dog is calculated by applying the following formula as shown below.

The sum of the x - component of the displacement;

Dx = 11 m  - 30 m x cos(55)

Dx = - 6.21 m

If the dog must end the run 10 m south of her original starting point, then the resultant displacement in y - direction is 10 m.

Dy = - 10 m

The direction of the resultant displacement of the dog is;

tan θ = Dy / Dx

tan θ = -10 / -6.21

tan θ = 1.61

θ = arc tan (1.61)

θ = 58.2⁰

The correct answer is option d. Electromagnetism can repel which is why the electromagnetic force can be used to demonstrate how like charges behave when they come together.

Electromagnetic force, one of the fundamental forces in nature, governs the interactions between electrically charged particles. Like charges (charges of the same sign) experience a repulsive force when they come together, according to Coulomb's law.

This repulsion is a characteristic behavior of electromagnetic interactions, where positively charged particles repel other positively charged particles, and similarly for negatively charged particles.

Why other options are not correct:

Option a is incorrect because electromagnetic force is actually known for having an infinite range, meaning it acts over any distance, although its strength decreases with distance according to the inverse-square law.

Option b is not entirely accurate because while the range is effectively infinite, it does not explain why like charges behave a certain way.

Option c is incorrect because like charges do not attract; they repel each other.

The complete question:

Which best explains why the electromagnetic force can be used to demonstrate how like charges behave when they come together?

a. Electromagnetism has a very small range.

b. Electromagnetism has a infinite range.

c. Electromagnetism can attract.

d. Electromagnetism can repel.

Cell size negatively affects the efficiency of waste elimination due to the surface area to volume ratio. Diffusion, which is vital for nutrient intake and waste removal, is less effective in larger cells, leading to potential accumulation of toxic waste and free radicals. Therefore, cell size and shape are crucial for effective waste elimination and overall cell health.

The size of a cell can have a significant impact on its ability to remove wastes and therefore on its survival. Cells require a balance between their surface area and volume to efficiently exchange substances with their environment. The surface area to volume ratio decreases as a cell grows, making it more difficult for substances to diffuse across the cell membrane at a rate necessary to maintain cell function. Diffusion is the primary mechanism through which cells take in nutrients and expel waste products. However, diffusion is only effective over short distances, hence the size of a cell is limited as large cells can potentially accumulate toxins or fail to acquire enough nutrients. Smaller cells, or cells with elongated or flattened shapes, have a higher surface area relative to their volume, allowing for more efficient waste removal and nutrient uptake.

Additionally, the build-up of waste products can be lethal to a cell, as these can interfere with cellular metabolism and lead to the production of harmful substances such as free radicals. These reactive chemicals can damage important molecules like DNA and contribute to diseases. Overall, the efficiency of waste elimination is crucial for the health and viability of a cell, and thus cell size and shape are critical to these processes.

The removal of waste from cells is less efficient in larger cells due to the increased distance substances must travel. This can result in toxic waste accumulation and impact cell survival. Cells adapt by maintaining a small size or a flattened shape to facilitate a more effective exchange of substances.

The process of waste removal in cells is closely related to the size and shape of the cell. Larger cells have a bigger problem with waste accumulation because the distance travelled by waste products to the cell membrane is greater, leading to an inefficient removal process. This inefficiency can cause the accumulation of waste products, including toxic substances like free radicals, which can interfere with normal cellular metabolism and even lead to cell death. These toxic substances may contribute to diseases such as cancer and cardiovascular disease if not efficiently removed from the cell.

In contrast, smaller cells or those with a flattened shape have a larger surface area relative to their volume, which allows for easier and quicker exchange of nutrients and waste with their environment. This is because substances have a shorter distance to travel to reach or leave any part of the cell. Diffusion is more effective in these cells, facilitating timely nutrient uptake and waste elimination, crucial for the cell's survival.

Ultimately, if a cell grows too large, its ability to intake nutrients and expel waste effectively is compromised. Cells have adapted to this limitation by remaining small, flattening, or developing structures like microvilli that increase surface area. Furthermore, multicellular organisms have evolved complex systems like the circulatory and lymphatic systems to help transport substances to and from individual cells, thereby overcoming the limitations of diffusion over larger distances.

Answer:

P.E=1/2k((-L – x)^2 + (L – x)^2 + 2(-y)^2)

Explanation:

What is the potential energy of the two-spring system after the point of connection has been moved to position (x, y)? keep in mind that the unstretched length of each spring ℓ is much less than l and can be ignored (i.e., ℓ≪l). express the potential in terms of k, x, y, and l?

potential energy is equal to the kinetic energy

potential energy is energy at rest while kinetic energy is energy due to motion

P=U

P=1/2k((-L – x)^2 + (L – x)^2 + 2(-y)^2)

k=elastic constant of the pring system

x,y are the position

Stage 1 sleep is characterized by the transition from alpha waves to theta waves, indicating a light sleep state from which individuals can be easily awakened.

The wave characteristic of stage 1 sleep is predominantly marked by the presence of theta waves. Initially, as a person transitions from wakefulness to sleep, alpha waves are prevalent, characterized by their lower frequency (8-13 Hz) and higher amplitude. As stage 1 sleep progresses, theta waves, which have an even lower frequency (4-7 Hz) and higher amplitude, become more dominant.

These brain waves indicate that the individual is in a light sleep state, as it is quite easy to wake someone during this stage.

The minimum coefficient of static friction needed for the deli owner to set up her display board with an angle of 30° between the two sides is 0.577.

The problem asks for the minimum coefficient of static friction needed for the board to remain stable in a 'V' position. The forces acting on the board in this scenario would be gravity, which acts downward, and the force of static friction, which acts to prevent the board from sliding. The weight of the board acts at the center of gravity, which is at the midpoint of the height of the 'V'.

We need to consider the forces acting horizontally and vertically. Vertically, the total force must be zero, so the gravitational force (weight of the board) equals twice the vertical component of the force of friction. Horizontally, the net force must be zero as well, so the two horizontal forces of friction (one on each board) must balance each other.

Using the formula for the force of friction (friction = normal force x coefficient of friction), and knowing that for each side the normal force equals half the weight of the board, we can establish an equation and solve for the coefficient of friction.

Setting up these relationships, solving for the coefficient of friction gives us a value of tan(30°), which is 0.577. Thus, the minimum coefficient of static friction needed would be 0.577 to keep the board stable at an angle of 30°.

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Answer:

C

Explanation:

Gotta trust me fam

The minimum distance the truck can stop in without the box sliding into the cab is equal to 77m.

The equations of motion can represent the relation between the initial and final velocity, acceleration, displacement, and time of a moving object.

The equations of motions are usually represented as shown below:

[tex]v = u +at\\S = ut +\frac{1}{2}at^2\\v^2 -u^2 = 2aS[/tex]

Given, the final velocity of the truck, v = 100 Km/h

The third equation of motion: v²- u² = 2ad

v² - 0 = 2 × a × d

a = v²/2d

The coefficient of static friction between the box and the truck = 0.54

We know that, F = ma = [tex]\mu_{s}m g[/tex]

[tex]a = \mu_{s} g[/tex]

[tex]{\displaystyle \frac{v^2}{2d} = \mu_s g[/tex]

(100)²/2d = 0.54 × 9.8

d = 73 m

Therefore, the minimum distance the truck can stop is equal to 73m.

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The answer is False, not two factors there are many factors that affect our environment.

The surrounding where we live with all the needs, nature, food, air and our life needed things can be said to be environment. In this environment human were causing many unwanted and environment affecting things.

Factors affecting environment are as follows:

So, there are not only two factors that affect our environment.

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Answer:

I TOOK THE TEST! the answer is INCREASES AND ENERGY INCREASES!

To find the rate at which the man and woman are moving apart, calculate the distance each has traveled and add their speeds since they are moving in opposite directions. The man traveled 2400 ft and the woman 3600 ft in their respective times, and the rate at which they are moving apart 15 minutes after the woman starts walking is 6 ft/s.

The student's question involves determining the rate at which two people are moving apart after a certain amount of time has passed, with one walking north and the other south from different starting points. To solve this, we can use the concept of relative velocity in one dimension, as the paths of the man and the woman are perpendicular to each other.

Firstly, we calculate the distance the man has walked in 20 minutes (since he started 5 minutes before the woman). At 2 ft/s, he would have walked 2 ft/s × 1200 s = 2400 ft north of point P. The woman, having started 5 minutes later, would have walked for 15 minutes at 4 ft/s, so she would have walked 4 ft/s × 900 s = 3600 ft south of her starting point.

When calculating the rate at which they are moving apart, we need to consider the sum of their speeds as they are moving in opposite directions. The man's speed is 2 ft/s and the woman's speed is 4 ft/s, so the rate at which they are moving apart is 2 ft/s + 4 ft/s = 6 ft/s.

Answer:true

Explanation:

As shocking as it might be your nose and tongue some what function the same but for a question like this the answer would be true.

it is known that a shark can travel at a speed of 15 meters/second then the shark can go 150 meters in 10 seconds.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second.

average speed = total distance /Total time

As given in the problem it is known that a shark can travel at a speed of 15 meters/second,

speed of the shark = 15 meters/second

time taken by the shark = 10 seconds

The total distance covered by the shark in 10 seconds = speed ×time

The total distance covered by the shark in 10 seconds  = 15×10

                                                                                            = 150 metes

Thus, the shark can go 150 meters in 10 seconds.

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Refraction is when the light is changes speed and bends as it travels from medium to another. The water slows down the light, and the image appears to bend.

The term that describes this property of light is Refraction. The correct option is D.

When a light ray falls on the interface of two medium like air and water, then the portion of light is reflected and another portion of the light is refracted into the water medium. The angle of incidence is equal to the angle of reflection but the angle of incidence is larger then the angle of refraction.

So, If you put a straw into a glass of water, the straw looks to be bent because of refraction of light into the water medium.

Refraction is when the light is changes speed and bends as it travels from medium to another. The water slows down the light, and the image appears to bend.

Thus, the correct option is D.

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a) In this case the forces are the centrifugal force Fcp, which is directed horizontally toward the wall; the force of static friction Ff with the wall, directed upward; the normal force Fn by the wall, which is directed away the wall; the force of gravity Fg, directed downwards. Then we have that the horizontal forces are all equal in magnitude; similarly the vertical forces are also all equal in magnitude.

b) The minimum coefficient s occurs when force of gravity is equals the max friction force, that is

Fg = Ff,max

m g = s Fn

Also, the normal force has equal magnitude to the centrifugal force:

m g = s Fcp

m g = s m w^2 r

g = s w^2 r

s = g / (r w^2)

With values: g = 9.81 m/s^2; r = 2.5 m; and w = 2pi * 0.60 = 3.77 rad/s; we find

s = 9.81 / (2.5 * 3.77^2) = 0.276

The minimum value of coefficient of static friction for which the person does not slide is [tex]\boxed{0.276}[/tex].

Further Explanation:

As the cylinder start to rotate, the people standing against the wall remain stick to the wall. So if we draw the free body diagram of the person, then we can see the balanced forces acting on person's body.

Given:

The rate of rotation of the cylinder is [tex]0.60\text{ rev}/\text{s}[/tex].

The radius of the cylinder is [tex]2.50\text{ m}[/tex].

Concept:

The friction force between the person’s body and the inner surface is balanced by the gravitational firce acting on the person's body.

[tex]\boxed{f_\text{friction}=f_\tect{gravity}}[/tex]                                                   ...... (1)

The force of friction acting on the person's body is:

[tex]f_\text{friction}=\mu N[/tex]

Here, [tex]N[/tex] is the normal reaction,  [tex]\mu[/tex] is coefficient of static friction.

The gravitational force acting on the person's body is:

[tex]f_\text{gravity}=mg[/tex]

Here, [tex]m[/tex] is mass of the body, and [tex]g[/tex] is the acceleration due to gravity.

Substitute [tex]\mu N[/tex] for [tex]f_\text{friction}[/tex] and [tex]mg[/tex] for [tex]f_\text{gravity}[/tex] in equation (1).

[tex]{\begin{aligned}\mu N&=mg\\\mu&=\dfrac{mg}{N}\end{aligned}[/tex]

The Normal force acting on the person's body is balanced by the centrifugal force acting on the persion due to the rotation of the cylinder.

[tex]\boxed{f_\text{normal}=f_\text{centrifugal}}[/tex]                                                  ...... (2)

The centrifugal force acting on the person's body is:

[tex]f_\text{centrifugal}=m\omega^2r[/tex]

Here, [tex]\omega[/tex] is the angular speed of the cylinder, [tex]r[/tex] is the radius of the cylinder.

Substitute [tex]m\omega^2r[/tex] for [tex]f_\text{centrifugal}[/tex] in equation (2).

[tex]N=m\omega^2r[/tex]

Substitute the value of [tex]N[/tex] in equation of static friction coefficient.

[tex]\begin{aligned}\mu&=\dfrac{mg}{m\omega^2r}\\&=\dfrac{g}{\omega^2r}\end{aligned}[/tex]

The acceleration due to gravity on the surface of Earth is [tex]9.81\text{ m}/\text{s}^2[/tex].

The angular speed of rotation of the cylinder is given as:

[tex]\begin{aligned}\omega&=2\pi\times\text{Revolutions per second}\\&=2\pi\times0.6\\&=3.77\text{ rad}/\text{s}\end{aligned}[/tex]

Substitute the values of [tex]\omega[/tex], [tex]g[/tex] and [tex]r[/tex] in above expression.

[tex]\begin{aligned}\mu&=\dfrac{9.81}{(3.77)^2\times2.5}\\&=\dfrac{9.81}{35.53}\\&=0.276\end{aligned}[/tex]

Thus, the minimum value of coefficient of static friction for which the person does not slide is [tex]\boxed{0.276}[/tex].

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Answer Details:

Grade: Senior school

Subject: Physics

Chapter: Circular motion

Keywords:

Amusement park, ride, spindle top, six flags, texas, vertical cylinder, hollow, 2.5m, 0.60 rev/s, dropped about, minimum static friction coefficient, rotation rate 0.60.

The nurse's push must equate to the frictional force for the cart to move at a constant velocity. Since the push is at an angle, its horizontal component, which opposes friction, is calculated and set equal to the friction. Solving for the force exerted by the nurse yields the answer.

This is a physics problem related to force, friction, and motion. To keep the cart at a constant velocity, the net force exerted on it must be zero, as per Newton's second law. This means that the frictional force, which opposes the direction of motion, should be equal to the applied force, which is the nurse's push.

The nurse's push is exerted at an angle, so we have to decompose it into horizontal and vertical components. The horizontal component is the one that actively works against the friction and it can be calculated using the formula: F_Horizontal = F_Nurse cos θ, where 'F_Nurse' is the force applied by the nurse and 'θ' is the angle of the push. Since this component must equal the frictional force, we can rearrange the equation and solve for 'F_Nurse': F_Nurse = Friction / cos θ. Plugging in the known values for friction (65 N) and angle (36 degrees), we can find the magnitude of force the nurse must exert to move the cart at a constant velocity in newtons.

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To move the cart at a constant velocity, the nurse must exert a force of approximately 79.3 Newtons at a downward angle of 35 degrees below the horizontal. The force of friction and the horizontal component of the nurse's force must be equal for the cart to move at a constant velocity.

To calculate the force the nurse must exert to move the cart at a constant velocity, we need to consider the forces acting on the cart. In this case, the force of friction and the force exerted by the nurse are the main forces. The force exerted by the nurse can be broken down into horizontal and vertical components. The horizontal component of the force is responsible for overcoming the force of friction. Since the cart is moving at a constant velocity, the net force in the horizontal direction is zero. To find the magnitude of the force the nurse must exert, we can use trigonometry to find the horizontal component of the force.

The horizontal component of the force can be found using the equation:

F_h = F_n * cos(theta)

Where F_h is the horizontal component of the force, F_n is the total force exerted by the nurse, and theta is the angle of the force below the horizontal. Substituting the values into the equation, we get:

F_h = F_n * cos(35 degrees) = F_n * 0.819

Since the net force in the horizontal direction is zero, the horizontal component of the force must be equal to the force of friction. Therefore, we can write the equation:

F_h = F_f = 65 N

Substituting the value of the force of friction and the expression for the horizontal component of the force, we can solve for the magnitude of the force the nurse must exert:

F_n * 0.819 = 65 N

F_n = 65 N / 0.819 = 79.3 N

The nurse must exert a force of approximately 79.3 Newtons to move the cart at a constant velocity.

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Final answer:

To find the height from which the ball was thrown, we can use the equations of motion for projectile motion. The ball was thrown from a height of 44.1 meters.

Explanation:

To find the height from which the ball was thrown, we can use the equations of motion for projectile motion. Since the ball is thrown horizontally, the initial vertical velocity is 0. We can use the equation h = (1/2) g t^2, where h is the height, g is the acceleration due to gravity, and t is the total time the ball is in the air.

Using the given values, we can substitute g = 9.8 m/s^2 and t = 3 s into the equation to solve for h: h = (1/2) * 9.8 m/s^2 * (3 s)^2 = 44.1 m.

Therefore, the ball was thrown from a height of 44.1 meters.

Hello!

A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result? A) law of differential mass B) law of conservation of momentum C) law of unequal forces D) law of accelerated collision

We have the following data¹:

ΔP (momentum before impact) = ?  

mA (mass) = 10 kg

vA (velocity) = 5 m/s

mB (mass) = 5 kg

vB (velocity) = 0 m/s

Solving:

ΔP = mA*vA + mB*vB

ΔP = 10 kg*5 m/s + 5 kg*0 m/s

ΔP = 50 kg*m/s + 0 kg*m/s

Δp = 50 kg*m/s ← (momentum before impact)

We have the following data²:

ΔP (momentum after impact) = ?  

mA (mass) = 10 kg

vA (velocity) = 0 m/s

mB (mass) = 5 kg

vB (velocity) = 10 m/s

Solving:

Δp = mA*vA + mB*vB

Δp = 10 kg*0 m/s + 5 kg*10 m/s

Δp = 0 kg*m/s + 50 kg*m/s

Δp = 50 kg*m/s ← (momentum after impact)

*** Then, which principle explains the result ?

Law of conservation of momentum, since the total momentum of body A and B before impact is equal to the total momentum of body A and B after impact.

Note:  Bodies of different masses and velocities may have the same kinetic energy, if proportionality between the units is maintained it can occur that they have the same kinetic energy.

Answer:

B) law of conservation of momentum

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The wavelength of a radio photon from an AM radio station that broadcasts at 1080 kilohertz is approximately 27.8 centimeters.

The wavelength of a radio photon from an AM radio station can be calculated using the formula:

wavelength = speed of light/frequency

Given that the frequency is 1080 kilohertz (or 1080,000 hertz), we need to convert it to megahertz (MHz) by dividing it by 1000. So the frequency is 1080 MHz.

Now, we can substitute the values into the formula:

wavelength = 3 x 10^8 meters per second / 1080 x 10^6 hertz

Performing the calculation, we get:

wavelength = 0.278 meters, or approximately 27.8 centimeters.

The upward force exerted by the floor exists equivalent to the downward force that the toes apply to the floor.

The overall force acting on an item vertically is measured by an upward force. Usually, this is calculated by deducting the total upward force from the total force caused by gravity.

The upward force applied to an object that is fully or partially submerged in a fluid is known as the buoyant force. A body submerged partially or completely in a fluid appears to shed weight or to be lighter, due to the buoyant force.

Every action contains a corresponding and opposite response, according to Newton's Third Law of Motion. The forces of action and response do not affect the same body. This law can be utilized to define if the floor exerts any force on a person's feet.

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