In an American Sign Language​ (A.S.L) class of 26 ​students, 15 are hearing impaired. What fraction of the students are hearing​ impaired?

Answers

Answer 1
The best way to get this answer would be to divide 15 by 26, getting 0.576923077, then multiplying that number by 100, getting 57.6923077, then you round it to the nearest whole number if needed. The answer to the nearest whole number is 58%.
Answer 2

The 15/26 fraction of the students is hearing​ impaired if in an American Sign Language​ (A.S.L) class of 26 ​students, 15 are hearing impaired.

What is a fraction?

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

It is given that:

In an American Sign Language​ (A.S.L) class of 26 ​students, 15 are hearing impaired.

The fraction:

= 15/26

We can convert the above value in the percentage as follows:

The best method for obtaining this answer is to divide 15 by 26 to obtain the number 0.5769, multiply that number by 100 to obtain the number 57.69; and then round it to the closest full number if necessary.

15/26 in percentage will be 57.69

Thus, the 15/26 fraction of the students is hearing​ impaired if in an American Sign Language​ (A.S.L) class of 26 ​students, 15 are hearing impaired.

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Related Questions

Students were surveyed about their favorite colors one fourth of the students perfered red , one eighth of the students perferred blue, and three fifth of the remaining students perferred green . if 15 students perferred green , how many students were surveyed

Answers

Since 1/4 said red, and 1/8 said blue, that leaves 5/8 of the students remaining. 3/5 of those students said green, so we need to multiply 5/8 by 3/5, achieving a product of 3/8. If 3/8 of the students is 15 students, then we must divide 15 by 3 to get 1/8 of the students. 15 divided by 3 is 5, so if we multiply by 8, we get the total amount of students, being 40 students.

Convert 604,800 seconds to weeks using Dimensional analysis

Answers

I think it would be 1 week.

You are planning a party and want to know how many cans of soda to buy. a genie offers to tell you either the mean number of cans guests will drink

Answers

Is there more to this question??

For a fixed loan amount, what happens to the monthly payment as the annual rate increases? a. as the annual rate increases, the monthly payment increases c. as the annual rate increases, the monthly payment stays the same b. as the annual rate increases, the monthly payment decreases d. no correlation

Answers

 If the annual rate increases nothing will happen to the monthly payment, so the answer is C as the annual rate increases, the monthly payment stays the same. Once the fixed-rate payment (loan) is processed there is no chance for any changes as this procedure means that lender is under a fixed-rate loan each payment period.

Suppose you buy a piece of office equipment for $9,000.00. After 5 years you sell it for a scrap value of $2,000.00. The equipment is depreciated linearly over 5 years. The value of the piece of equipment after 2 years is (rounded to the nearest whole dollar)

Answers

Residual value = $2000

$7000/5 = $1400

Yearly depreciation = $1400

So in 2 years total depreciation = $2800.

Value = Purchase Price - Total Depreciation
Value = $9000               -    $2800
Value after 2 years = $6200

The value of the piece of equipment after 2 years is $6,200.00.

What is a Linear equation?

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. Sometimes, the aforementioned is referred to as a "linear equation of two variables," with y and x serving as the variables.

The equipment is depreciated linearly, which means that its value decreases at a constant rate each year. We can find the rate of depreciation by subtracting the scrap value from the purchase price, and then dividing by the number of years of useful life:

Rate of depreciation = (Purchase price - Scrap value) / Useful life

Rate of depreciation = (9000 - 2000) / 5

Rate of depreciation = 1400

This means that the equipment loses $1,400 of value each year. After 2 years, the value of the equipment will be:

Value after 2 years = Purchase price - (Rate of depreciation x Number of years)

Value after 2 years = 9000 - (1400 x 2)

Value after 2 years = 6200

Therefore, the value of the piece of equipment after 2 years is $6,200.00.

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The volume of a rectangular prism is given by the formula V = lwh, where l is the length of the prism, w is the width, and h is the height. Suppose a box in the shape of a rectangular prism has length (2a + 11), width (5a – 12), and height (a + 6). Which expression represents the volume of the box? v=(2a+11)(5a-12)(a+6) v=(10a^2-24a+55a-132)(a+6) v=(10a^3+60a^2-24a^2-144a+55a^2+330a-132a-792 v=10a^3+60a^2-24a^2+55a^2-144a+330a-132a-792 v=10^3+91a^2+54a-792

Answers

All of the given expressions for v are various stages in the process of "simplifying" the product of length, width, and height. Each and every one of them represents the volume of the box.

Is 25/99 a terminating or repeating decimal

Answers

25/99 = 0.2525252525

Do you see that 25 repeats?

Repeating decimal for sure.

The price of 6 pretzels is $5.10. Simon and Sofia bought 8 pretzels and shared the cost equally. How much did each person pay?

Answers

$4.68 because each pretzel is $1.17 so 8 pretzels are 9.36 ÷ by 2 = $4.68

a square has the side measurment of s = 2 3 over 2 using the formula 1= s^2 find the area of the square

Answers

check the picture below.

[tex]\bf A=s^2\qquad s=2\frac{3}{2}\qquad A=\left( 2\frac{3}{2} \right)^2\implies A=\left( \frac{2\cdot 2+3}{2} \right)^2 \\\\\\ A=\left( \frac{7}{2} \right)^2\implies A=\cfrac{7^2}{2^2}\implies A=\cfrac{49}{4}\implies A=12\frac{1}{4}[/tex]

Earth is about 4.5 billion years old and written human history extends back about​ 10,000 years. Suppose the entire history of Earth is represented with a 1000​-meter-long ​timeline, with the birth of Earth on one end and today at the other end.
2 billion years is represented by how many meters of the timeline?

Answers

444.44 meters.

Hope that helps

Given that the points (-1, 10), (2, 10), (2, -2), and (-1, -2) are vertices of a rectangle, what is the ratio of the rectangle's length to its width?

Answers

check the picture below.

Each side of a square is lengthened by 2 inches. the area of the new, larger square is 121 square inches. find the length of a side of the original square.

Answers

Let the original side length be x.  Then (x+2)^(in)^2 = 121 sq in.

Thus, x^2 + 4x + 4 = 121;
          x^2 + 4x - 117 = 0   =   (x-13)(x+9) = 0.  Then x = 13 and x = -9.

We need to discard the negative result (-9).

The side of the original square is 9 inches.            (answer)

Check:  does (9+2)^2 = 121?  Does 11^2 = 121?  YES.

The length of the original square is 9 inches

What is a square?

A square is defined as a polygon that has four sides and is a closed, two-dimensional (2D) object. A square has equal and parallel sides on all four sides.

Area of square  =  x * x

where x is the side of the square

According to the question,

The area of the new square is 121 square inches.

Let the side of the original square is = x  inches

Then the side of the new  square is =  x + 2 inches

Area of the new square = ( x + 2 )²

                                   121    =  ( x + 2 )²

                                      11   = x + 2

                                        x  = 9 inches

Therefore, The length of the original square is 9 inches.

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Two negative integers are five minutes apart on the number line, and their product is 126. What is the sum of the two integers?

Answers

First I will assume that this problem can be reworded as follows:  "Two negative integers are five units apart on the number line."

Let the first (the smaller) negative integer be x and the second y.  Note that y, being bigger than x, can be represented by y=x+5.

First find the 2 integers.  Their product is 126, so x(x+5)=126.
Expanding, x^2 + 5x - 126 = 0.  Using the quadratic formula to solve this, 

          -5 plus or minus sqrt(529)        -5 plus or minus 23
x = --------------------------------------- = -----------------------------
                           2                                              2
                                                                                          -5 -23
We are interested only in negative integers, so take x = ------------
                                                                                               2

Then x = -28/2, or x = -14.  Then y is x+5, or -14+5 = -9.

Check:  does the product of -9 and -14 equal 126, as it must?   YES.

About 11/12 of a golf course is in the fairways, 1/11 in the greens, and the rest in the trees. What part of the golf course is in the trees?

Answers

I believe that your question is wrong because 11/12+1/11>1

[tex]\frac{1}{132}[/tex] part of the golf course is in the trees.

To find out what part of the golf course is in the trees, we need to add the fractions of the golf course that are in the fairways and the greens, and then subtract that sum from 1 (which represents the whole golf course).

First, we add the fractions of the golf course that are in the fairways and greens:

Fairways: [tex]\frac{11}{12}[/tex]Greens: [tex]\frac{1}{11}[/tex]

To add these fractions, we must first find a common denominator. The denominators are 12 and 11, so the common denominator is 12 x 11 = 132.

Convert each fraction to have this common denominator:

[tex]\frac{11}{12}[/tex] = [tex]\frac{121}{132}[/tex][tex]\frac{1}{11}[/tex] = [tex]\frac{12}{132}[/tex]

Now, add these converted fractions together:

[tex]\frac{121}{132}[/tex] + [tex]\frac{12}{132}[/tex] = [tex]\frac{133}{132}[/tex]

Since the sum [tex]\frac{133}{132}[/tex] is greater than 1, we convert it to a whole number plus a fraction. [tex]\frac{133}{132}[/tex] = 1 + [tex]\frac{1}{132}[/tex].

Now, to find the part of the golf course in the trees, subtract this sum from the whole golf course:

1 - 1 + [tex]\frac{1}{132}[/tex] = [tex]\frac{1}{132}[/tex]

So, [tex]\frac{1}{132}[/tex] of the golf course is in the trees.

Complete question:

About [tex]\frac{11}{12}[/tex] of a golf course is in the fairways, [tex]\frac{1}{11}[/tex] in the greens, and the rest in the trees. What part of the golf course is in the trees?

"sam's furniture was destroyed by a fire. the furniture cost $1200 when it was purchased, but similar new furniture now costs $1800. assuming the furniture was 50 percent depreciated, what is the actual cash value of sam's loss?"

Answers

deprecated means the price is decreased, so if something is deprecated by 50% (which just means 1/2 is taken away) its original price is just cut in half. so half of 1200 (1200 divided by 2) is 600. i think the answer is 600 :-)

The actual cash value of Sam's furniture loss is $600.

To calculate the actual cash value of Sam's furniture loss, we first determine the amount of depreciation applied to the original purchase price. Since the furniture was 50 percent depreciated, we calculate this amount to be 50% of $1200, which is $600. This means the depreciated value of the furniture is $1200 - $600 = $600. However, because the replacement cost of new, similar furniture is now $1800, this does not affect the actual cash value of the lost furniture, which remains at the depreciated value of $600. So the actual cash value of Sam's loss is $600.

Find two numbers with a sum of 20 and a difference of 14.

Answers

17 and 3 is your answer

17 + 3 = 20

17 - 3 = 14

hope this helps

30 + (.0825 x 30) + (15% x 30) =

Answers

Your answer is gonna be 36.975
30+(.0825 times 30) +(15% times30)
30+2.475 +(0.15 times 30)
32.475+ 4.5=36.975

1. 3/5x -7 = 23

A. x = 40
B. x = 45
C. x = 50
D. x = 55

2.When Patrick and Cameron went bowling at Victory Lanes, they spent a total of $42. This included rental of shoes at $3.50 per pair. Patrick bowled 2 games, and Cameron bowled 3 games.
How much did each game cost?
A. $6.00
B. $7.00
C. $7.70
D. $8.75
3.A local movie theater offers a special deal for birthday parties. The price, which covers the cost of the tickets and a box lunch, includes a flat fee of $75 plus $5 per ticket. Sarah’s parents spent $150 altogether at the theater to celebrate her birthday.

Which equation can be used to determine how many children, x, were in the group?
A. 75/150=5x
B. 150/75=5x
C. 150 = 5x – 75
D. 150 = 5x + 75

4. 35 + 0.25x = 53.75
A. x = 75
B. x = 140
C. x = 215
D. x = 250

5.T he perimeter of this isosceles triangle is 47 cm.
top point. (B) left bottom point (A) right bottom point (C) in between 12cm
What is the length of each of its legs (it doesn't have legs)?
A. 15 cm
B. 17.5 cm
C. 19.5 cm
D. 35 cm

Answers

3/5x - 7 = 23
3/5x = 23 + 7
3/5x = 30
x = 30/(3/5)
x = 30 * 5/3
x = 150/3
x = 50 <==
=====================
3.50(2) + 5g = 42
7 + 5g = 42
5g = 42 - 7
5g = 35
g = 35/5
g = 7 <== each game costs $ 7
===================
150 = 5x + 75
===================
35 + 0.25x = 53.75
0.25x = 53.75 - 35
0.25x = 18.75
x = 18.75 / 0.25
x = 75 <===
===================
if one leg is 12.....and an isosceles triangle has 2 equal sides....(47 - 12) / 2 = 35/2 = 17.5 <==


10 11/12 + 7 1/4 =

A. 3 8/12
B. 3 2/3
C. 17 1/4
D. 18 1/6

Answers

It's D if you  need an explanation let me know
10 11/12 + 7 1/4 
= 10 11/12 + 7 1/4 
= 10 11/12 + 7 3/12
= 17 14/12
= 18 2/12
= 18 1/6
answer
D. 18 1/6

You purchase three packs of batteries at $11.99/pack. You have a coupon for 10% off and the sale tax is 7% how much is the total cost of your purchase?

Answers

The answer is 34.64. C.

The entire purchase of the three items cost about $34.

How to determine the total cost?

The given parameters are:

The cost of one packs of batteries is $11.99/pack.

Coupon = 10% off

The total cost is then calculated using:

Total = (three packs of batteries) * (1 - Coupon)

So, we have:

Total = (11.99 + 11.99 + 11.99 ) * (1 - 10%)

Evaluate,

Total = 34.47

Approximate

Total = 34

Hence, the entire purchase of the three items cost about $34.

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What is the image of G for a dilation with center (0,0) and a scale factor of 1?

Answers

When the dilation scale factor is 1, the image is the same as the original, G.

The length of a rectangle is 4 centimeters more than twice its width. If the perimeter of the rectangle is 86 centimeters , find the dimensions of the rectangle

Answers

P = perimeter = 2L + 2W = 86 cm.  Also, L = W + 4.  Subst. W + 4 for L, 

P = 2(W + 4) + 2W = 86 cm.  Then 2W + 8 + 2W = 86 cm, and 4W = 78 cm.

Finally solving for W, W = (78 cm)/4, or 19.5 cm.

If W = 19.5 cm, then L = W + 4 cm = 19.5 cm + 4 cm = 23.5 cm

The rectangle's dimensions are 19.5 cm by 23.5 cm.

Celine's Cereal Company is launching a new brand of cereal and she is considering two different sizes for the base of the boxes. Box 1: The length is 3 times the width. Box 2: The length is 1 less than 4 times the width. The dimensions of the base of Box 1 are: width: x; length: 3 width: x; length: x + 3 width: x; length: x – 3 width: x; length: 3x

Answers

Answer:

D. Width = x and Length = 3x

Step-by-step explanation:

We are given that,

The length of Box 1 is 3 times the width of Box 1.    ..................(1)

Let the width of Box 1 = x

So, from (1), we have,

Length of Box 1 = 3 × Width of Box 1

i.e. Length of Box 1 = 3x

Thus, the dimensions of Box 1 are : Width = x and Length = 3x

Hence, option D is correct.

In this exercise we have to identify which of the alternatives best represents the equation, like this:

Letter D

So we have that it is the area of ​​a box, where we have:

The length of box is 3 times widthThe width of the box is  X

So is the same as:

[tex]L= 3W\\W=X\\L=3X[/tex]

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Last year, Amanda had
$10,000
to invest. She invested some of it in an account that paid
6%
simple interest per year, and she invested the rest in an account that paid
10%
simple interest per year. After one year, she received a total of
$760
in interest. How much did she invest in each account?

Answers

Let $x be invested in the account that paid 5% simple interest.
Let $y be invested in the account that paid 10% simple interest.

The total invested is $10,000, therefore
x + y = 10000            (1)

The interest amounts earned are respectively
x*1*0.06 = 0.06x
y*1*0.10 = 0.10y

The total interest earned is $760, therefore
0.06x + 0.10y = 760     
Multiply through by 10 to obtain
0.6x + y = 7600              (2)

Subtract (2) from (1).
x + y - (0.6x + y) = 10000 - 7600
0.4x = 2400
x = $6,000
From )1), obtain
y = 10000 - 6000 = $4,000

Answer:
$6,000 in the account paying 6% simple interest, and
$4,000 in the account paying 10% simple interest.

Each side of a square is increasing at a rate of 5 cm/s. at what rate is the area of the square increasing when the area of the square is 49 cm2? 70 cm2/s

Answers

This problem is solved using the chain rule. the area of the square is f(t) and the length of the side is g(t) f(t)=g(t)^2 g'(t)=5 Using the chain rule f'(t)=2*g(t)*g'(t) The value of g(t) is sqrt(49) which is 7. g'(t) is given as 5 cm/s f'(t)=2*7*5=14*5=70cm^2/s

At full power, how long would it take for the car to accelerate from 0 to 64.0 mph ? neglect friction and air resistance. express your answer in seconds.

Answers

The amount of time it would take for a car to accelerate from 0 to 64.0 mph can vary based on the vehicle. Basic vehicles generally can accelerate in under 6 seconds to 64 mph, while exotic cars can reach that speed somewhere in between 3 and 4 seconds.

Sections of pre-fabricated fencing are each 4 1/3feet long how long are 6 1/2 sections placed end to end

Answers

first off, let's convert the mixed fractions to "improper fractions".

6 and 1/2 sections, each of 4 and 1/3 feet? is just their product.

[tex]\bf \stackrel{mixed}{4\frac{1}{3}}\implies \cfrac{4\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{13}{3}} \\\\\\ \stackrel{mixed}{6\frac{1}{2}}\implies \cfrac{6\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{13}{2}}\\\\ -------------------------------\\\\ \cfrac{13}{3}\cdot \cfrac{13}{2}\implies \cfrac{13\cdot 13}{3\cdot 2}\implies \cfrac{169}{6}\implies 28\frac{1}{6}[/tex]

What is the place value of the 4 in the number 5,679.04

Answers

the 4 is in the hundreth place
Hi. The 4 is in the hundredths place. When dealing with place value that has a decimal just remember that everything to the left of the decimal starts as ones, tens, hundreds, etc. Starting with the first number on the right we have tenths, hundredths, thousandths, etc. So for your numbers, we have the following:

5 = thousands
6 = hundreds
7 = tens
9 = ones
0 = tenths
4 = hundredths

Hope this helps.

Take care,
Diana

-3.1 * (- 2.9) Please help! Math.

Answers

8.99 would be your answer

The answer is

(-3.1)(-2.9)

=8.99

Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8)=2

Answers

[tex]w(s,t)=f(u(s,t),v(s,t))[/tex]

From the given set of conditions, it's likely that you are asked to find the values of [tex]\dfrac{\partial w}{\partial s}[/tex] and [tex]\dfrac{\partial w}{\partial t}[/tex] at the point [tex](s,t)=(1,0)[/tex].

By the chain rule, the partial derivative with respect to [tex]s[/tex] is

[tex]\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}[/tex]

and so at the point [tex](1,0)[/tex], we have

[tex]\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}[/tex]
[tex]\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21[/tex]

Similarly, the partial derivative with respect to [tex]t[/tex] would be found via

[tex]\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}[/tex]
[tex]\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5[/tex]
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