Physics College

In an isochoric process, the internal (thermal) energy of a gas decreases by 50 j. how much work is done by the gas during this process

Answers

Answer 1
the amount of work done by the gas during this process is: 0
The isochoric process is a thermodynamic process in which the volume will always remain contant.

work could be calculated = P x dV

since dV = 0, there wore the amount of work done by this process is also 0
Answer 2
Final answer:

In an isochoric process where the gas's internal energy decreases by 50 J, no work is done by the gas because the volume is constant. The work done is 0 J.

Explanation:

In an isochoric process (also known as an isovolumetric process), the volume of a gas remains constant. According to the first law of thermodynamics, the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W): ΔU = Q - W. In an isochoric process, because the volume does not change, no work is done by the gas (W = 0). Therefore, if the internal energy of the gas decreases by 50 Joules, and no work is done, the amount of heat removed from the gas would be equivalent to the decrease in internal energy, which is -50 Joules.

The answer to the student's question is that in an isochoric process where the internal energy decreases by 50 Joules, no work is done by the gas since the volume is constant; the work done is 0 Joules.

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