Final answer:
The alpha star in a constellation is generally the brightest within that constellation, as designated by the Bayer system, using Greek letters such as Alpha Centauri or Alpha Orionis for Betelgeuse.
Explanation:
The alpha star in a constellation is named using a system introduced by Johann Bayer in 1603, which designates stars with Greek letters according to their brightness within that constellation. The alpha star is typically the brightest star in its constellation. For example, Alpha Centauri is the brightest star in the Centaurus constellation, visible from south of the equator. Similarly, Alpha Orionis, or Betelgeuse, is the brightest star in the Orion constellation. Stars like Sirius, Vega, and Altair also fall under this naming system. Apparent brightness is subject to change over long periods due to stars' space velocity, making certain stars more prominent in our skies at different times.
The designation of stars within a constellation also serves astronomy and celestial navigation, highlighting important features of the celestial sphere. Not all stars within the vicinity of the Sun are equally visible or as bright, with only a few within 26 light-years appearing among the brightest in our sky. The alpha designation helps us identify and catalogue these celestial bodies systematically.
In the first-order spectrum, maxima for two different wavelengths are separated on the screen by 3.40 mm . what is the difference between these wavelengths?
The solution would be like this for this specific problem:
Given:
diffraction grating slits = 900 slits per centimeter
interference pattern that is observed on a screen from the grating = 2.38m
maxima for two different wavelengths = 3.40mm
slit separation .. d =
1/900cm = 1.11^-3cm = 1.111^-5 m
Whenas n = 1, maxima (grating equation) sinθ = λ/d
Grant distance of each maxima from centre = y ..
As sinθ ≈ y/D y/D =
λ/d λ = yd / D
∆λ = (λ2 - λ1) = y2.d/D - y1.d/D
∆λ = (d/D) [y2 -y1]
∆λ = 1.111^-5m x [3.40^-3m] / 2.38m .. .. ►∆λ = 1.587^-8 m
Telephone companies are replacing older, analog lines with digital lines because
A. wireless transmissions can be used only for short distances. B. computers can now be equipped with modems to translate transmissions. C. digital lines are less expensive. D. data is transmitted more quickly over digital lines.
A glass is half-full of water, with a layer of vegetable oil (n 5 1.47) fl oating on top. a ray of light traveling downward through the oil is incident on the water at an angle of 71.48. determine the critical angle for the oil–water interface and decide whether the ray will penetrate into the water.
What is the definition of a point object?
A car slow down at -5.00 m/s2 until it comes to a stop after traveling 15.0 m. What was the initial speed of the car? (Unit=m/s)
Answer:
12.25 m/s
Explanation:
If a car slows down at -5 m/s2 and it comes to a stop after traveling 15 m we just have to use the next formula:
[tex]Vf^{2} =Vo^{2} +2ad[/tex]
Now we know that the final velocity is 0, so by inserting our data into the formula it would look like this:
[tex]Vf^{2} =Vo^{2} +2ad[/tex]
[tex]0 =Vo^{2} +2(-5m/s^{2})(15m)[/tex]
[tex]-Vo^{2}= -150m^{2}/s^{2}[/tex]
[tex]Vo^{2}= 150m^{2}/s^{2}[/tex]
[tex]Vo= \sqrt{150m^{2}/s^{2}}[/tex]
[tex]Vo= 12.25m/s[/tex]
It is ethical to use deceptive methods in research when the scientific goals of the project can be achieved by non-deceptive methods. nih
What evidence suggests that Earth attracts or pulls on objects?
Scientists have determined that light is made up of electromagnetic waves light is made up of particles called photons light is both a longitudinal wave and a particle both a and b
When you set something down on the ground what kind of work is your arm doing
When set something is set down on the ground, negative work is said to be done by the body.
What is Negative work?This is the type of work which is characterized by the force and displacement being in opposite direction.
This type of work occurs when the arm set down something on the ground which makes it the most appropriate choice.
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which is an organic compound?
What is the range of wavelengths for fm radio (88 mhz to 108 mhz)?
The range of wavelengths for FM radio waves is approximately 2.78 meters to 3.41 meters.
What is wavelength?Wavelength is a physical property of a wave that refers to the distance between two consecutive points on a wave that are in phase, i.e., they have the same position in their cycle of motion. It is the distance over which the wave's shape repeats itself.
In other words, the wavelength is the distance between two successive peaks or troughs of a wave. It is usually denoted by the Greek letter lambda (λ) and is measured in units of length, such as meters or nanometers.
The wavelength of a wave is determined by its frequency and the speed at which it travels through a medium. In general, waves with higher frequencies have shorter wavelengths, while waves with lower frequencies have longer wavelengths.
Wavelength is an important property of many types of waves, including light waves, sound waves, and radio waves. Understanding the properties of wavelength is crucial in fields such as physics, engineering, and telecommunications, as it affects how waves interact with materials, how they can be detected and measured, and how they can be transmitted over long distances.
Here in the Question,
The ranges of wavelengths for FM (frequency modulation) radio waves can be calculated using the formula:
wavelength (in meters) = speed of light (in meters per second) / frequency (in hertz)
The frequency range for FM radio is 88 MHz to 108 MHz. To calculate the corresponding wavelength range, we can use the speed of light, which is approximately 299,792,458 meters per second:
For the lower end of the FM radio frequency range (88 MHz), the wavelength is:
wavelength = 299,792,458 m/s / 88,000,000 Hz ≈ 3.41 meters
For the upper end of the FM radio frequency range (108 MHz), the wavelength is:
wavelength = 299,792,458 m/s / 108,000,000 Hz ≈ 2.78 meters
Therefore, the range of wavelengths for FM radio waves is approximately 2.78 meters to 3.41 meters.
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After using a thermometer where should it be placed
If white light illuminates a diffraction grating having 790 lines/mm , over what range of angles does the visible m = 1 spectrum extend?
Final answer:
The range of angles over which the visible m = 1 spectrum extends can be calculated using the equation θ = sin^(-1)(mλ/d), where θ is the angle, m is the order of the spectrum, λ is the wavelength of light, and d is the grating spacing. For a diffraction grating with 790 lines/mm spacing, the range of angles for the visible m = 1 spectrum is approximately 18.42° to 33.57°.
Explanation:
We are given the property of the illuminating light:
790 lines/mm
Which is also equivalent to:
790,000 lines/m
Taking the reciprocal of this value will give us the distance per line:
d = 1 m / 790,000 lines
d = 1.2658 * 10^-6 m
Now we can solve for the range of angles using the formula
λ = d * sin θ
sin θ = λ / d
where λ is the wavelength of light and θ is the angle
Now we know that visible light ranges from 400 to 700 nm, therefore we use these values to find the range.
when λ = 400 nm = 400 * 10^-9 m
sin θ = 400 * 10^-9 m / 1.2658 * 10^-6 m
θ = 18.42°
when λ = 700 nm = 700 * 10^-9 m
sin θ = 700 * 10^-9 m / 1.2658 * 10^-6 m
θ = 33.57°
Therefore the range of angles is 18.42° to 33.57°.
Traffic officials indicate, it takes longer to ______ when you drive fast.
Answer:
Stop
Explanation:
when we drive fast it will be take longer time to stop.
As car is moving fast the acceleration will be to decelerate we have to apply brake.
By applying brake the car decelerates very fast as deceleration is the change in velocity per unit time. change in velocity is very high so deceleration will be high.
when the brake is applied the distance travel by the high speed vehicle will be more than the vehicle moving at slow speed.
If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as _____.
If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as Melting.
What is the thickness of the mantle in km?
The mantle of the Earth is approximately 2900 kilometers thick. It is the largest part of the solid Earth, extending from the base of the crust to the top of the core. It is mainly solid, but can deform and flow under extreme conditions.
Explanation:The Earth's mantle is the largest part of the solid Earth, stretching from the base of the crust downward to a depth of 2900 kilometers. This part of the Earth is largely solid, but due to the extreme temperatures and pressures found in the mantle, the rock can deform and flow slowly. The density in the mantle increases from about 3.5 g/cm³ at the top to more than 5 g/cm³ at the bottom due to the compression produced by the weight of the overlying material.
Samples of upper mantle material are occasionally ejected from volcanoes, allowing scientists to conduct a detailed analysis of its chemical composition. After the mantle, at a depth of 2900 kilometers, we encounter the Earth's core, which is dense and metallic. The core has a larger diameter of 7000 kilometers and is made up of a liquid outer layer and a solid inner layer.
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A body is placed on a rough inclined plane. Why does the frictional force decrease with the increase of angle of inclination
Kepler's second law implies what about planetary motion?
When a bus moves forward after stopping to pick up passengers, why do the passengers feel as though they are being pushed back against their seats?
A. The passengers' bodies tend to remain still relative to the ground while the bus is moving.
B. The forward force caused by the inertia of the bus pushes back on the passengers' bodies.
C. The force of gravity tries to hold the bodies of the passengers in place.
D. The body of the bus moves faster than the seats on the bus due to inertial forces.
A steel cylinder with a moveable piston on top is filled with helium (He) gas. The force that the piston exerts on the gas is constant, but the volume inside the cylinder doubles, pushing the piston up.
Which of the following answers correctly states the cause for the change described in the scenario?
The temperature increased.
The density of the helium atoms decreased.
The pressure decreased.
The helium atoms increased in size.
Determine the rate of a reaction that follows the rate law:rate = k[A]m[B]n, where:k = 1 × 10-2[A] = 2 M[B] = 3 Mm = 2n = 1
Final answer:
The rate of the reaction is calculated by substituting the given values into the rate law, resulting in a rate of 0.12 M/s, with the rate constant k having units of mol² L²/s for this reaction.
Explanation:
To calculate the rate of a reaction with the given rate law, we insert the provided values into the rate equation: rate = k[A]m[B]n. With the values k = 1 × 10-2, [A] = 2 M, [B] = 3 M, m = 2, and n = 1, the rate is calculated as follows:
rate = (1 × 10-2 M-1s-1)(2 M)2(3 M)1
rate = 1 × 10-2 M-1s-1 × 4 M2 × 3 M
rate = 0.12 M/s
The rate constant k has the units necessary to provide the rate in terms of mol/L/s, which for this second-order reaction in [A] and first-order in [B] (total order: 3), is mol-2 L2/s.
Electrical shock is more likely to be fatal when the path of current is through the
An object has a mass of 15 kg. on planet x, the object weighs 126 n. the force of gravity on planet x is _____. 0.12 m/s2 8.4 m/s2 1875 m/s2
The force of gravity on planet x is equal to 8.4 m/s². Therefore, option (B) is correct.
What is the weight of the object?The weight of a body can be defined as the force acting on the body due to the gravity of the earth or any planet. Weight can be described as a vector parameter if the gravitational force is exerted on the object.
The measurement unit for weight is similar to that of force, which (SI) is the newton (N). A body with a mass of 1 Kg has a weight of 9.8 N on Earth's surface, and about 1/6th as much on the Moon.
The mathematical expression to determine the weight of an object is written as follows:
W = mg
Given the mass of the given object, m = 15 Kg
The weight of the object, W = 126N
The force of gravity on planet x will be equal to:
126 N = 15 Kg × g
g = 126/15
g = 8.4 m/s²
Therefore, the force of gravity on planet x is equal to 8.4 m/s².
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A 25 N force at 60° is required to set a crate into motion on a floor. What is the value of the static friction?
In a scientific experiment, the variable manipulated or controlled by the experimenter is called the
Independent.
The independent variable is manipulated and the effects are noted.
The work done in pushing a tv set a distance of 2 m with an average force of 20 n is
What do astronomers mean by light pollution?
Final answer:
Light pollution is the excessive or misdirected artificial light that brightens the night sky, making it difficult to see celestial objects. It is a concern for astronomers, environmentalists, and those worried about global warming.
Explanation:
Light pollution refers to the excessive or misdirected artificial light that brightens the night sky, making it difficult to see celestial objects such as planets and stars. This phenomenon is of concern not just to astronomers, but also to environmentalists and those who are worried about global warming. It can disrupt the natural life cycle of animals and lead to unnecessary expenses and energy consumption. Light pollution can be measured and compared using citizen science projects like Globe at Night, and organizations like the International Dark-Sky Association work to address this issue.
A bird experiences an acceleration of -1.80 m/s^2 for 3.81 s, and ends up 26.5 m to the left of its starting point. What is its final velocity?
To solve this problem, we can assume that the motion is linear so that we can use the equations:
Xf = Xi + v0 t + 0.5 a t^2 ---> 1
vf = v0 + a t ---> 2
where Xi = initial distance = 0, v0 = initial velocity, Xf = final distance = 26.5 m, a = acceleration = - 1.80 m/s^2, t = time = 3.81 s, vf = final velocity
Substituting the given values into equation 1 to find for v0:
26.5 = v0 (3.81) + 0.5 (-1.80 m/s^2) (3.81)^2
3.81 v0 = 39.56449
v0 = 10.38 m/s
Using equation 2 to find for vf:
vf = 10.38 + (-1.80) (3.81)
vf = 3.53 m/s
What is the name of the concave depression in the central retina for gathering light?
under what conditions would a scale record a weight for an object which is equal to the magnitude of the gravitational force on the object?
answer:if there are no external forces acting on the object
Explanation:
under what conditions would a scale record a weight for an object which is equal to the magnitude of the gravitational force on the object?
If gravity and the normal reaction force are the only forces acting on the body, and the body is at rest or moving at constant velocity, the normal force and the weight are equal and opposite. Also if there are no influence of external forces
and air resistance is negligible.
from newtons law of motion which states that the rate of change in momentum is directly proportional to the force applied
f=km(v-u)/t
f=kma
where k is the constant and equal to 1
f=ma