Answer: [tex]\dfrac{1}{90}[/tex]
Step-by-step explanation:
Given : The total number of companies = 720
The number of companies won = 8
Now, the probability of a company winning is given by ;-
[tex]\text{P(winning)}=\dfrac{\text{Number of company wins}}{\text{ Total companies}}\\\\\Rightarrow\ \text{P(winning)}=\dfrac{8}{720}\\\\\Rightarrow\ \text{P(winning)}=\dfrac{1}{90}[/tex]
Hence, the probability of a company winning is [tex]\dfrac{1}{90}[/tex].
Lake eyre in australia is approxinatley 50 feet below sea level. Which of the following best describes the location of lake Eyre as it relates to sea level?
+100
+50
0
-50
Plz help
The following best describes the location of lake Eyre as it relates to sea level is -50. Therefore, option D is the correct answer.
Given that, Lake Eyre in Australia is approximately 50 feet below sea level.
What is the sea level?Mean sea level is an average surface level of one or more among Earth's coastal bodies of water from which heights such as elevation may be measured.
Now, if the surface sea level is 0.
50 feet below sea level = 0-50=-50
The following best describes the location of lake Eyre as it relates to sea level is -50. Therefore, option D is the correct answer.
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Which expression correctly represents "eight times the difference of four and a number"
String a is 35 centimeters long. String b is 5 times long as string a. Both are necessary to create a decorative bottle. Find the total length of string needed for 17 identical decorative bottles.
The total length of string needed to decorate 17 identical decorative bottle is 3570 cm or 35.7 m
Further ExplanationGiven:
String A is 35 cm longString B is 5 x string AQuestion
Total length of string needed for 17 identical decorative bottle?
String A = 35
String B = 5 x string A
= 5 x 35
= 175 cm
String B = 175 cm
We need to calculate total string needed for 1 decorative bottle
= String A + String B
= 35 cm + 175 cm
= 210 cm
The total length to decorate one bottle is 210 cm
To decorate 17 identical bottles, it would need:
= 210 x 17
= 3570 cm
Here is to solve the multiplication in standard algorithm method:
21
17 x
147
21 +
357
then adding the zero = 3570
To simplify the multiplication we just do the two digit numbers and then adding the zero later in the answer,
So, the total string needed for 17 identical decorative bottle is 3570 cm or 35.7 m
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What is the factorization of 3x2 – 8x + 5?
Answer:
[tex](x-1)(3x-5)[/tex]
Step-by-step explanation:
[tex]3x^2 - 8x + 5[/tex]
To factor it we use AC or splitting the middle term method
product is 3 times 5 is 15
Sum is -8
-3 times -5 is 15
-3 plus -5 is -8
Factors are -3 and -5
[tex]3x^2 -5x-3x+ 5[/tex]
Group first two terms and last two terms
[tex](3x^2 -5x)+(-3x+ 5)[/tex]
[tex]x(3x-5)-1(3x- 5)[/tex]
Factor out 3x-5
[tex](x-1)(3x-5)[/tex]
The Zoo offers 5 boat tours and 8 train tours every day. How many tours will the train have made when the boat has made 35 tours? Make a table.
When the boat has made 35 tours, the train will have made 56 tours, based on the ratio 8 train tours for every 5 boat tours.
The question involves calculating the number of train tours when a given number of boat tours is reached, utilising basic multiplication and ratios. Since there are 5 boat tours and 8 train tours per day, for every boat tour, there are 8/5 train tours. To find out the number of train tours when there have been 35 boat tours, we multiply 35 by 8/5 which equals 56.
Here is the table showing the boat to train tour ratios:
Boat Tours 5,10,15,20,25,30,35
Train Tours 8,16,24,32,40,48,56
Therefore, when the boat has made 35 tours, the train will have made 56 tours.
32 divided by 258.24
Helpppp meeeeeee eeeeeee
Answer:
no
Step-by-step explanation:
Solve for x. y=7x−7z−9
Answer:
The value of x is [tex]x=\frac{y+7z+9}{7}[/tex]
Step-by-step explanation:
Consider the provided equation.
[tex]y=7x-7z-9[/tex]
We need to solve the equation for x.
Add 7z to both the sides.
[tex]y+7z=7x-7z+7z-9[/tex]
[tex]y+7z=7x-9[/tex]
Add 9 to both the sides.
[tex]y+7z+9=7x-9+9[/tex]
[tex]y+7z+9=7x[/tex]
Divide both sides by 7.
[tex]x=\frac{y+7z+9}{7}[/tex]
Hence the value of x is [tex]x=\frac{y+7z+9}{7}[/tex].
How do I solve this problem
The price changes from $450 to $396 what is the percent change?
A. 13.6% increase
B. 13.6% decrease
C. 12% increase
D. 12% decrease
Doug is twice Anne's age. Doug is 34 years old. How old is Anne
What is the product in simplest form? −5/12 ⋅ 8/13 Please answer
([20-2+(46-15)+2]-(9+4)
What is the value of x?
vertical angles equal each other
so you have
9x+12 = 3x +24
subtract 12 from each side:
9x = 3x+12
subtract 3x from each side:
6x = 12
divide both sides by 6
x = 12/6
x = 2
Jerry has 2 1\2 pounds of peanuts to share equally. He plans to share the peanuts amoung 5 people. How many pounds of peanuts will each person get? Express your answer in simplest form.
Gerry spends $1.25 each day on lunch at school. On Friday's, she buys an extra snack for $0.55. How much money will she spend in two weeks
Gerry will spend $13.6 in two weeks
Further ExplanationFrom the problem given:
Gerry spend $1.25/day on lunch
Fridays spend extra $0.55
How much Gerry will spend in two weeks?
In one week, there are 5 school days
4 days (Monday to Thursday) Gerry spend $1.25/day
1 day, Fridays, Gerry spends $1.25+$0.55 = $1.80
So, in one week Gerry will spend :
= [tex]\boxed {(1.25 \times4) + 1.80\ }\\ =\boxed {5+1.80\ }\\ =\boxed {6.8\ }[/tex]
In two weeks, Gerry will spend :
[tex]=\boxed {2 \times 6.8\ }\\ =\boxed {13.6\ }[/tex]
When we are multiplying decimal numbers, the process the same as multiplying whole numbers except for the placement of the decimal point in the answer. In multiplying we don't need to line up the decimal point.
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In a school, there are 150 students. Out of these 80 students enrolled for mathematics class, 50
enrolled for English class, 60 enrolled for physics class. The student enrolled for English cannot
attend any other class , but student of mathematics and physics can take two courses at a
time. Find the number of students who have taken both physics and mathematics.
a. 40
b. 30
c. 50
d. 20
By applying set theory, we calculate that 40 students are enrolled in both mathematics and physics classes after excluding the 50 English students who cannot attend any other classes.
Explanation:To find the number of students who have taken both physics and mathematics, we can subtract the number of English class students from the total because they cannot be in the group that takes both of the other two classes.
So, we have a total number of students who can take math or physics, which is 150 - 50 = 100 students.
Since there are 80 students in mathematics and 60 in physics, the maximum number could be 80 if every physics student also took mathematics.
But because we only have 100 students to distribute between the two subjects (excluding the English students).
The actual number of students who took both courses will be the total number for math and physics classes (80 + 60) minus the number of students who can take these classes, which gives us ;
140 - 100 = 40 students.
Therefore, the answer is 40 students have taken both physics and mathematics classes. This corresponds to choice a.
A patrol unit has 13-gallon fuel tank and averages 15 miles per gallon of fuel used. If the officer assigned to the unit works four 10-hour shifts per week and typically drives 100 miles per shift. How much fuel will the officer's unit use in one week?
The officer's unit will use approximately 26.67 gallons of fuel in one week.
Explanation:To calculate the amount of fuel the officer's unit will use in one week, we need to determine the total distance driven in a week and then calculate the amount of fuel needed for that distance.
Since the officer works four 10-hour shifts per week, the total driving time in a week is 40 hours (4 shifts x 10 hours per shift). If the officer typically drives 100 miles per shift, then the total distance driven in a week is 400 miles (100 miles per shift x 4 shifts).
Now, let's calculate the amount of fuel needed for 400 miles at an average fuel economy of 15 miles per gallon.
Fuel used = Total distance driven / Fuel economy = 400 miles / 15 miles per gallon
Fuel used = 26.67 gallons
Therefore, the officer's unit will use approximately 26.67 gallons of fuel in one week.
An investment is currently worth 1.035×108 dollars . Thirty years ago, the investment was worth 2.3×105 dollars. How many times greater is the value of the investment today than the value of the investment thirty years ago? A. 0.45 B.450 C.4500 D. 45,000
The correct option is: B. 450
Explanation
Current value of the investment is [tex]1.035\times 10^8[/tex] dollars and 30 years ago, the value of the investment was [tex]2.3\times 10^5[/tex] dollars.
Suppose, the value of investment today is [tex]n[/tex] times greater than the value of the investment thirty years ago.
So, the equation will be........
[tex]n(2.3\times 10^5)=1.035\times 10^8\\ \\ n= \frac{1.035\times 10^8}{2.3\times 10^5}=0.45\times 10^3 = 450[/tex]
Thus, the value of the investment today is 450 times greater than the value of the investment thirty years ago.
Answer: B. 450
Step-by-step explanation:
Given: An investment is currently worth =[tex]1.035\times10^8[/tex] dollars .
Thirty years ago, the investment was worth =[tex] 2.3\times10^5[/tex] dollars.
Now, the number of times the value of the investment today than the value of the investment thirty years ago is given by :-
[tex]n=\frac{1.035\times10^8}{2.3\times10^5}\\\\=0.45\times10^{8-5}........\text{Since }a^na^m=a^{m+n}\\\\=0.45\times10^3\\\\=0.45\times1000=450[/tex]
Hence, the value of the investment today is 450 times greater than the value of the investment thirty years ago.
36 divided by 21312 awnser
4.5w=5.1w-30, how do I solve it
Jeremiah is saving money from a tutoring job.After the first three weeks,he saved $135.Assume the situation is proportional.Use the unit rate to write an equation relating the amount saved s to the number of weeks w worked.At this rate,how much will Jeremiah save after eight weeks?
What is the simplified value of the expression below?
3(8-4)+2x5.5
A.23
B.31
C.47
D.77
Answer:
its a
Step-by-step explanation:
find the value of X. (x + 90) 4x°
Can someone please help me :)
if (93 x p) + 84 = 85 then please equals:
0
1/93
1/85
1/84
1
Using the principle of solving algebraic expressions, the value of p in the equation is 1/93
Given the expression :
(93 × p) + 84 = 85Solving the expression in bracket :
93p + 84 = 85
Subtract 84 from both sides to isolate 93p
93p + 84 - 84 = 85 - 84
93p = 1
Divide both sides by 93 to isolate p
93p/93 = 1/93
p = 1/93
Therefore, the value of p in the expression is 1/93.
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which behavior is important for keeping your skeletal system healthy ?
A. Avoiding medical checkups
B. Eating Well
C. Playing with an injury
D. Playing the same sport all year long
Ernesto's bus arrived 51 minutes after he got to the bus stop. Determine what fraction of an hour Ernesto spent waiting for the bus. Write the fraction in the simplest form.
17/20 is the fraction of an hour Ernesto spent waiting for the bus
What is Fraction?A fraction represents a part of a whole.
Given that Ernesto's bus arrived 51 minutes after he got to the bus stop
We need to find the fraction of an hour Ernesto spent waiting for the bus
We know that 1 hour has 60 minutes.
Ernesto's waited 51 minutes out of 60 minutes or an hour.
So 51 minutes is the part and 60 minutes is the whole part
Then the fraction will be 51/60
51 and 60 are the multiples of 3.
Let us divide numerator and denominator by 3
17/20
Hence, 17/20 is the fraction of an hour Ernesto spent waiting for the bus
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Which term is defined as a fee charged for the use of money? a. interest b. down payment c. principal d. default
what is the smallest number
2.31
2.3
2.33
2.301
Solve for w.
2w−5(w+1)=3w+1
Answer:
[tex]w=-1[/tex].
Step-by-step explanation:
We have been given an equation [tex]2w-5(w+1)=3w+1[/tex]. We are asked the equation for w.
Using distributive property [tex]a(b+c)=ab+ac[/tex], we will get:
[tex]2w-5w-5=3w+1[/tex]
[tex]-3w-5=3w+1[/tex]
Subtract 3w from both sides:
[tex]-3w-3w-5=3w-3w+1[/tex]
[tex]-3w-3w-5=1[/tex]
Combine like terms:
[tex]-6w-5=1[/tex]
Add 5 on both sides:
[tex]-6w-5+5=1+5[/tex]
[tex]-6w=6[/tex]
Divide both sides by -6:
[tex]\frac{-6w}{-6}=\frac{6}{-6}[/tex]
[tex]w=-1[/tex]
Therefore, our required equation would be [tex]w=-1[/tex].